Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Balbharti Maharashtra State Board Class 10 Science Solutions Part 1 Chapter 5 Heat Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 1.
Fill in the blanks and rewrite the sentences:
a. The amount of water vapour in air is determined in terms of its………..
Answer:
The amount of water vapour in air is determined in terms of its absolute humidity.

b. If objects of equal masses are given equal heat, their final temperature will be different. This is due to difference in their………….
Answer:
If objects of equal masses are given equal heat, their final temperature will be different. This is due to difference in their specific heat capacities.

c. When a liquid is getting converted into solid, the latent heat is……….  (Practical Activity Sheet – 1 and 2)
Answer:
When a liquid is getting converted into solid, the latent heat is released.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 2.
Observe the following graph. Considering the change in volume of water as its temperature is raised from 0 °C, discuss the difference in the behaviour of water and other substances. What is this behaviour of water called?
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat 1
Answer:
If the temperature of water is raised from 0 °C to 10 °C, its volume goes on decreasing in the range 0 °C to 4 °C. It is minimum at 4 °C. The volume of water goes on increasing in the range 4 °C to 10 °C.

In general, when a substance is heated, its volume goes on increasing with temperature. Thus, in the range 0 °C to 4 °C, behaviour of water is different from other substances. It is called anomalous behaviour of water.

Question 3.
What is meant by specific heat capacity?
How will you prove experimentally that different substances have different specific heat capacities?
Answer:
The amount of heat energy required to raise the temperature of a unit mass of an object by 1 °C is called the specific heat capacity of that object.

Question 4.
While deciding the unit for heat, which temperatures interval is chosen? why?
Answer:
While deciding the unit for heat, the temperature interval chosen is 14.5 °C to 15.5 °C. For the reason, see the information given in the following box.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 5.
Explain the following temperature vs time graph:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat 2
(Practice Activity Sheet – 1 and 4; March 2019)
Answer:
The graph shows what happens when a mixture of ice and water is heated continuously. The temperature of the mixture remains constant (0 °C) till all the ice melts as shown by the line AB. This temperature is the melting point of ice. On further heating, the temperature rises steadily from 0 °C to 100 °C as shown by the line BC, At 100 °C water starts converting into steam. This temperature is the boiling point of water. Further heating does not change the temperature and the conversion waters steam continues as shown by the line CD.

Question 6.
Explain the following:
a. the role of anomalous behaviour of water in preserving aquatic life in regions of cold climate?
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat 3
In cold regions, during winter, the temperature of the atmosphere falls well below 0 °C. As the temperature decreases, the water at the surfaces of lakes and ponds starts contracting. Hence, its density increases and it sinks to the bottom. This process continues till the temperature of all the water in a lake falls to 4 °C. As the water at the surface cools further, i.e., its temperature falls below 4 °C, it starts expanding instead of contracting. Therefore, its density decreases and it remains at the surface.

The temperature of the water at the surface continues to fall to 0 °C. Finally, the water at the surface is converted into ice, but the water below the layer of ice is at 4 °C. Ice is a bad conductor of heat. Hence, the layer of the ice at the surface does not allow transfer of heat from the water to the atmosphere. As the water below the layer of ice remains at 4 °C, fish and other aquatic animals and plants can survive in it.

b. How can you relate the formation of water droplets on the outer surface of a bottle taken out of a refrigerator with formation of dew?
Answer:
At a given temperature, there is a limit on how much water vapour the given volume of air can hold. The lower the temperature, the lower is the capacity of air to hold water vapour.

The temperature of a bottle kept in a refrigerator is lower than room temperature. Hence, when the bottle is taken out of the refrigerator, the temperature of the air surrounding the bottle is lowered. Therefore, the capacity of the air to hold water vapour becomes less. Hence, the excess water vapour condenses to form water droplets (like dew) on the outer surface of the bottle.

c. In cold regions in winter, the rocks crack due to anomalous expansion of water.
Answer:
Sometimes water enters into crevices of the rocks. When the temperature of the atmosphere falls below 4 °C, water expands. Even when water freezes to form ice, there is increase in its volume. As there is no room for expansion, it exerts a tremendous pressure on the rocks which crack and break up into small pieces.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 7.
a. What is meant by latent heat? How will the state of matter transform if latent heat is given off?
Answer:
When a solid is heated, initially, its temperature increases. Here, the heat absorbed by the body (substance) is used in increasing the kinetic energy of the particles (atomic, molecules, etc.) of the body as well as for doing work against the forces of attraction between them. As the heating is continued, at a certain temperature (melting point), solid is converted into liquid. In this case, the temperature remains constant and the heat absorbed is used for weakening the bonds and conversion into liquid phase (liquid state). This heat is called the latent heat of fusion.

When a liquid is converted into the gaseous phase (gaseous state), at the boiling point, the heat absorbed is used for breaking the bonds between the atoms or molecules. This heat is called the latent heat of vaporization. Some solids, under certain conditions, are directly transformed into the gaseous phase. Here the heat is absorbed but the temperature remains constant. The absorbed heat is used for breaking the bonds between atoms or molecules. This heat is called the latent heat of sublimation.

In general, latent heat is the heat absorbed or given out by a substance during a change of state at constant temperature.
In transformations from liquid to solid, gas to liquid and gas to solid, latent heat is given out by the body (substance).
(Note: change of state = change of phase)

b. Which principle is used to measure the specific heat capacity of a substance?
Answer:
The principle of heat exchange is used to measure the specific heat capacity of a substance. This principle is as follows: If a system of two objects is isolated from the environment by keeping it inside a heat resistant box, then no energy can leave the box or enter the box. In this situation, heat energy lost by the hot object = heat energy gained by the cold object.

c. Explain the role of latent heat in the change of state of a substance.
Answer:
When a solid is heated, initially, its temperature increases. Here, the heat absorbed by the body (substance) is used in increasing the kinetic energy of the particles (atomic, molecules, etc.) of the body as well as for doing work against the forces of attraction between them. As the heating is continued, at a certain temperature (melting point), solid is converted into liquid. In this case, the temperature remains constant and the heat absorbed is used for weakening the bonds and conversion into liquid phase (liquid state). This heat is called the latent heat of fusion.

When a liquid is converted into the gaseous phase (gaseous state), at the boiling point, the heat absorbed is used for breaking the bonds between the atoms or molecules. This heat is called the latent heat of vaporization. Some solids, under certain conditions, are directly transformed into the gaseous phase. Here the heat is absorbed but the temperature remains constant. The absorbed heat is used for breaking the bonds between atoms or molecules. This heat is called the latent heat of sublimation.

In general, latent heat is the heat absorbed or given out by a substance during a change of state at constant temperature.
In transformations from liquid to solid, gas to liquid and gas to solid, latent heat is given out by the body (substance).
(Note: change of state = change of phase)

d. what basis and how will you determine whether air is saturated with vapour or not?
Answer:
Whether the air is saturated with water vapour or not is determined on the basis of the extent of water vapour present in the air. If the relative humidity is 100%, the air is saturated with water vapour. In that case, we can see the formation of water droplets on the leaves of plants/grass.
If the relative humidity is less than 100%, the air is not saturated with water vapour.

Question 8.
Read the following paragraph and answer the questions:
If heat is exchanged between a hot and cold object, the temperature of the cold object goes on increasing due to gain of energy and the temperature of the hot object goes on decreasing due to loss of energy.

The change in temperature continues till the temperatures of both the objects attain the same value. In this process, the cold object gains heat energy and the hot object loses’ heat energy. If the system of both the objects is isolated from the environment by keeping it inside a heat resistant box (meaning that the energy exchange takes place between the two objects only), then no energy can flow from inside the box or come into the box.
(1) Heat is transferred from where to where?
(2) Which principle do we learn about from this process?
(3) How will you state the principle briefly?
(4) Which property of the substance is measured using this principle?
Answer:
(1) Heat is transferred from a hot object to a cold object.
(2) This process shows the principle of heat exchange.
(3) In this process, the cold object gains heat energy and the hot object loses energy. If a system of two objects is isolated from the surroundings, heat energy lost by the hot object = heat energy gained by the cold object.
(4) This principle is used to measure the specific heat capacity of a substance.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 9.
Solve the following problems:
a. Equal heat is given to two objects A and B of mass 1 g. The temperature of A increases by 3 °C and B by 5°C. Which object has more specific heat? And by what factor?
Solution:
Data: m = 1 g, Δ T1 = 3 °C, Δ T2 = 5 °C,
Q same
Here, Q = mc1 ΔT1 = mc2 ΔT2
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat 4
Thus, c1 > c2
The specific heat of A is more than that of B and
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat 5

b. Liquid ammonia is used in ice factory for making ice from water. If water at 20 °C is to be converted into 2 kg, ice at 0 °C, how many grams of ammonia is to be evaporated?
(Given: The latent heat of vaporization of 1 ammonia = 341 cal/g)
Solution:
Data : m1 = 2kg, ΔT1=20 °C – 0 °C
= 20 °C, c1 = 1 kcal/kg·°C, L1 (ice) = 80 kcal/kg,
L2 (vaporization of ammonia) = 341 cal/g = 341 kcal/kg, m2 =?
Q1 (heat lost by water) = m1c1 ΔT1 + m1L1
= 2kg × 1 kcal/kg·°C × 20 °C + 2 kg × 80 kcal/kg
=40 kcal + 160 kcal = 200 kcal
Q2 (heat absorbed by ammonia) = m2L2
= m2 × 34l kcal/kg
According to the principle of heat exchange, Q1 = Q2
∴ 200 kcal = m2 × 341 kcal/kg
∴ m2 = \(\frac{200}{341}\) kg = 0.5864 kg = 586.4 g
586.4 g of ammonia are to be evaporated.

c. A thermally insulated pot has 150 g ice at temperature 0 °C. How much steam of 100 °C has to he mixed to it, so that water of temperature 50 °C will be obtained?
(Given: Latent heat of melting of ice = 80 cal/g, latent heat of vaporization of water = 540 cal/g, specific heat of water = 1 cal/g °C)
Solution:
Data: m1 = 150 g, ΔT1 = 50 °C – 0 °C
= 50 °C, cw = 1 cal/g.°C, L1 = 80 cal/g, L2 = 540 cal/g,
Δ T2 = 100°C – 50 °C = 50 °C, m2 = ?
Q1 (heat absorbed by ice) = m1L1
= 150 g × 80 cal/g = 12000 cal
Q2 (heat absorbed by water formed on melting of ice) =m1 cw ΔT1
= 150 g × 1 cal/g·°C × 50 °C = 7500 cal
Q3 (heat given out by steam) = m2L2
= m2 × 540 cal/g
Q4 (heat given out by water formed on condensation of steam)
= m2 cw ΔT2 = m2 × 1 cal/g·°C × 50 °C
According to the principle of heat exchange,
Q1 + Q2 = Q3 + Q4
∴ 12000 cal + 7500 cal = m2 × 540 cal/g + m2 × 50 cal/g
∴ 19500 cal = m2 (540 + 50) cal/g
∴ m2 = \(\frac{19500}{590}\) g
33.5 g of steam is to be mixed.

d. A calorimeter has mass 100 g and specific heat 0.1 kcal/kg ·°C. It contains 250 g of liquid at 30 °C having specific heat of 0.4 kcal/kg·°C. If we drop a piece of ice of mass 10 g at 0 °C into the liquid, what will be the temperature of the mixture?
Solution:
Data: m1 = 100 g, c1 = 0.1 kcal/kg·°C,
= 0.1 cal/g·°C, T1 = 30 °C, m2 = 250 g,
c2 = 0.4 kcal/kg·°C = 0.4 cal/g·°C, T2 = 30 °C,
m3 = 10 g, T3 = 0 °C, L = 80 cal/g,
c (water) = 1 cal/g·°C, T = ?
Q1 (heat lost by calorimeter) = m1c1 (T- T1),
Q2 (heat lost by liquid) = m2c2 (T – T2),
Q3 (heat absorbed by ice) = m3 L,
Q4 (heat absorbed by water formed on melting of ice) = m3c (T – 0 °C)
According to the principle of heat exchange,
Q1 + Q2 = Q3 + Q4
∴ m1c1 (T1 – T) + m2c2 (T2 – T) = m3L + m3c (T – 0 °C)
∴ m1c1T1 – m1c1T + m2c2T2 – m2c2T = m3L + m3c (T – 0°C)
∴ m1c1T1 + m2c2T2 = m3L + (m1c1 + m2c2 + m3c)T
∴ 100g × 0.1 cal/g°C × 30 °C + 250g × 0.4 cal/g.°C × 30 °C J
= 10 g x× 80 cal/g + (100 g × 0.1 cal/g.°C + 250 g × 0.4 cal/g.°C + 10 g × 1 cal/g.°C) T
∴ (10 + 100 + 10) T = (300 + 3000 – 800)°C
∴ 120 T = 2500 °C
∴ T = \(\frac{2500}{120}\) °C = \(\frac{125}{6}\) °C = 20.83 °C
This is the temperature of the mixture.

Project:
Take help of your teachers to make a working model of Hope’s apparatus and perform the experiment. Verify the results you obtain. [Do it your self]

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Can you recall? (Text Book Page No. 62)

Question 1.
What is the difference between heat and temperature?
Answer:
Heat is a form of energy. Particles of matter (atoms, molecules, etc.) possess potential energy and kinetic energy. Total energy (potential energy + kinetic energy) of all particles of matter in a given sample is called it’s thermal energy. When two bodies at different temperatures are in thermal contact with each other, there is transfer of thermal energy from a body at higher temperature to a body at lower temperature. This energy in transfer is called heat. It is expressed in joule, calorie and erg.

Temperature is a quantitative measure of degree of hotness or coldness of a body. It is expressed in °C, °F or K (kelvin). Temperature determines the direction of energy transfer.

Question 2.
What are the different ways of heat transfer?
Answer:
Ways of heat transfer: conduction, convection and radiation.
[Note: heat ≡ heat energy. In the textbook, both the terms are used.]

Use your brain power! (Text Book Page No. 63)

Question 1.
Is the concept of latent heat applicable during transformation of gaseous phase to liquid phase and from liquid phase to solid phase?
Answer:
Yes.

Question 2.
Where does the latent heat go during these transformations?
Answer:
During these transformations, the latent heat is given out by the substance to the surroundings.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Use your brain power! (Text Book Page No. 64)

Question 1.
In the above experiment, the wire moves through the ice slab. However, the ice slab does not break. Why?
Answer:
When the thin wire with two equal weights attached to its ends is hung over the block of ice, it exerts pressure on the ice below it. Due to this, the melting point of the ice below the wire is lowered and some ice melts. The wire passes through the water so formed.

The water above the wire is no longer under pressure and, therefore, refreezes. Once again the ice below the wire melts, and the wire passes through it, and the process continues. In this way, due to alternate melting of ice and refreezing of water, the wire cuts right through the block of ice leaving the block intact.

Question 2.
Is there any relationship of latent heat with regelation?
Answer:
Yes. when the ice melts, heat is absorbed, but the temperature does not change. Also, when water refreezes, heat is given out, but the temperature does not change. This heat absorbed or given out is the latent heat.

Question 3.
You know that as we go higher than the sea level, the boiling point of water decreases. What would be the effect on the melting point of a solid?
Answer:
As we go higher than the sea level, the melting point of solids (i) that expand on melting is lowered due to a decrease in pressure (ii) that contract on melting is raised due to a decrease in pressure.

[The wire used in the experiment is made of a metal (usually copper). Metals are good conductors of heat. Hence, exchange of heat between the portion of the ice above the wire and that below the wire takes place readily.]

Can you tell? (Text Book Page No. 64)

Question 1.
We feel that some objects are cold, and some are hot. Is this feeling related in some way to our body temperature?
Answer:
Yes. If the temperature of the object is lower than our body temperature, e.g., ice, we feel the object is cold. If the temperature of the object is higher than our body temperature, e.g., hot water, we feel the object is hot.

Use your brain power! (Text Book Page No. 66)

Question 1.
How will you explain the following statements with the help of the anomalous behaviour of water?
(1) In regions with cold climate, the aquatic plants and animals can survive even when the atmospheric temperature goes below 0 °C.
(2) In cold regions in winter the pipes for water supply break and even rocks crack.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat 6
In cold regions, during winter, the temperature of the atmosphere falls well below 0 °C. As the temperature decreases, the water at the surfaces of lakes and ponds starts contraeting. Hence, its density increases and it sinks to the bottom. This process continues till the temperature of all the water in a lake falls to 4 °C. As the water at the surface cools further, i.e., its temperature falls below 4 °C, it starts expanding instead of contracting. Therefore, its density decreases and it remains at the surface.

The temperature or the water at the surface continues to fall to 0 °c. Finally, the water at the surface is converted Into ice, but the water below the layer of ice is at 4 °C. Ice is a bad conductor of heat. Hence, the layer of the ice at the surface does not allow transfer of heat from the water to the atmosphere. As the water below the layer of ice remains at 4 °C, fish and other aquatic animals and plants can survive in it.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

(2) Sometimes water enters into crevices of the rocks. when the temperature of the atmosphere falls below 4 °C, water expands. Even when water freezes to form ice, there is increase in its volume. As there is no room for expansion, it exerts tremendous pressure on the rocks which crack and break up Into small pieces.

In cold countries, in winter, the temperature of the atmosphere falls below 0 °C. when the temperature of water falls below 4 °C, it expands. Hence, the water in pipes expands. Even if ice is rormed, there is an increase in the volume.

As there is no room for expansion, water (or ice) exerts a large pressure on the pipes. Hence, the pipelines carrying water burst.

Fill in the blanks and rewrite the sentences:

Question 1.
The amount of water vapour in air is determined in terms of its…………..
Answer:
The amount of water vapour in air is determined in terms of its absolute humidity.

Question 2.
If objects of equal masses are given equal heat, their final temperature will be different. This is due to difference in their……………
Answer:
If objects of equal masses are given equal heat, their final temperature will be different. This is due to difference in their specific heat capacities.

Question 3.
When a liquid is getting converted into solid, the latent heat is…………. (Practical Activity Sheet – 1 and 2)
Answer:
When a liquid is getting converted into solid, the latent heat is released.

Rewrite the following statements by selecting the correct options:

Question 1.
……….is used to study the anomalous behaviour of water.
(a) Calorimeter
(b) Joule’s apparatus
(c) Hope’s apparatus
(d) Thermos flask
Answer:
(c) Hope’s apparatus

Question 2.
When water boils and is converted into steam, then………..
(a) heat is taken in and temperature remains constant
(b) heat is taken in and temperatures rises
(c) heat is given out and temperature lowers
(d) heat is given out and temperature remains constant
Answer:
(a) heat is taken in and temperature remains constant

Question 3.
When steam condenses to form water,………..
(a) heat is absorbed and temperature increases
(b) heat is absorbed and temperature remains the same
(c) heat is given out and temperature decreases
(d) heat is given out and temperature remains the same
Answer:
(d) heat is given out and temperature remains the same

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 4.
The temperature of ice can be decreased below 0 °C by mixing………..in it. (Practice Activity Sheet – 3)
(a) saw dust
(b) sand
(c) salt
(d) coal
Answer:
(c) salt

Question 5.
Ice/water is a substance that………..
(a) expands on melting and contracts on freezing
(b) contracts on melting and does not undergo change in volume on freezing
(c) contracts on melting and expands on freezing
(d) does not undergo any change in volume on melting or freezing
Answer:
(c) contracts on melting and expands on freezing

Question 6.
Heat absorbed when 1 g of ice melts at 0 °C to form 1 g of water at the same temperature is………..cal.
(a) 80
(b) 800
(c) 540
(d) 54
Answer:
(a) 80

Question 7.
The latent heat of vaporization of water is………..
(a) 540 cal/g
(b) 800 cal/g
(c) 80 cal/g
(d) 54 cal/g
Answer:
(a) 540 cal/g

Question 8.
The latent heat of fusion of ice is………..
(a) 540 cal/g
(b) 80 cal/g
(c) 800 cal/g
(d) 4cal/g
Answer:
(b) 80 cal/g

Question 9.
If the temperature of water is decreased from 4 °C to 10 °C, then its………..
(a) volume decreases and density increases
(b) volume increases and density decreases
(c) volume decreases and density decreases
(d) volume increases and density increases
Answer:
(b) volume increases and density decreases

Question 10.
At 4 °C, the density of water is………..
(a) 10 g/cm3
(b) 4g/cm3
(c) 4 × 103 kg/m3
(d) 1 × 103 kg/m3
Answer:
(d) 1 × 103 kg/m3

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 11.
The density of water is maximum at………..
(a) 0 °C
(b) – 4 °C
(c) 100 °C
(d) 4 °C
Answer:
(d) 4 °C

Question 12.
………..heat is needed to raise the temperature of 1 kg of water from 14.5 °C to 15.5 °C.
(a) 4180 J
(b) 103 J
(c) 1 cal
(d) 4180 cal
Answer:
(a) 4180 J

Question 13.
………..heat is needed to convert 1 g of water at 0 °C and at a pressure of one atmosphere into 1 g of steam under the same conditions.
(a) 80 cal
(b) 540 cal
(c) 89 J
(d) 540 J
Answer:
(b) 540 cal

Question 14.
Water expands on reducing its temperature below………..°C. (March 2019)
(a) 0
(b) 4
(c) 8
(d) 12
Answer:
(b) 4

State whether the following statements are true or false. (If a statement is false, correct it and rewrite it.):

Question 1.
Specific latent heat of fusion is expressed in g/cal.
Answer:
False. (Specific latent heat of fusion is expressed in cal/g.)

Question 2.
If the temperature of water is raised from 0 °C to 10 °C, its volume goes on increasing.
Answer:
False. (If the temperature of water is raised from 0 °C to 10 °C, its volume goes on decreasing in the range 0 °C to 4 °C and then goes on increasing in the range 4 °C to 10 °C.)

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 3.
At dew point relative humidity is 100%.
Answer:
True.

Question 4.
1 kcal = 4.18 joules.
Answer:
False. (1 kcal = 4180 joules.)

Question 5.
Specific heat capacity is expressed in cal/g·°C
Answer:
True.

Question 6.
Latent heat of fusion, Q = mL.
Answer:
True.

Question 7.
If the relative humidity is more than 60%, we feel that the air is humid.
Answer:
True.

Question 8.
If the relative humidity is less than 60%, we feel that the air is dry.
Answer:
True.

Question 9.
Relative humidity has no unit.
Answer:
True.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 10.
Absolute humidity is expressed in kg/m3.
Answer:
True.

Identify the odd one and give the reason:

Question 1.
Temperature, conduction, convection, radiation.
Answer:
Temperature. It is a physical quantity. Others are modes of transfer of heat.

Question 2.
The joule, The erg, The calorie, The newton.
Answer:
The newton. It is a unit of force. Others are units of energy (as well as work.)

Question 3.
cal/g, cal/g·°C, k cal/kg·°C, erg/g·°C.
Answer:
cal/g. It is a unit of specific latent heat. Others are units of specific heat capacity.

Match the columns:

Column A Column B
1. Latent heat a. Q = mc ΔT
2. Specific heat capacity b. Q = mL
3. Heat absorbed or given out by a body when its temperature changes. c. kcal
d. cal/g·°C

Answer:
(1) Latent heat – Q = mL
(2) Specific heat capacity – cal/g·°C
(3) Heat absorbed or given out by a body when its temperature changes – Q = mc ΔT.

Answer the following questions in one sentence each:

Question 1.
State units of temperature.
Answer:
Units of temperature: °C, °F and K (kelvin).

Question 2.
State units of energy.
Answer:
Units of energy: the erg, the joule, the calorie.

Question 3.
State the relation between the joule and the calorie.
Answer:
1 calorie = 4.18 joules.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 4.
State the relation between the erg and the joule.
Answer:
1 joule = 107 ergs.

Question 5.
State the relation between the erg and the kilocalorie.
Answer:
1 kilocalorie = 4.18 × 1010 ergs.

Question 6.
State the relation between the joule and the kilocalorie.
Answer:
1 kilocalorie = 4.18 × 103 joules.

Question 7.
When heat energy is absorbed by an object, ΔT represents the rise in temperature. What would ΔT represent if the object loses heat energy? (Practice Activity Sheet – 4)
Answer:
If the object loses heat energy, ΔT would represent the decrease in temperature.

Answer the following questions:

Question 1.
Define latent heat of fusion.
(OR)
What is latent heat of fusion? State its units.
Answer:
When a solid is converted into liquid at constant temperature (melting point of the substance) the amount of heat absorbed by it is called the latent heat of fusion.
Heat is a form of energy. Hence, latent heat is expressed in units joule, erg, calorie or kilocalorie.

Question 2.
Define specific latent heat of fusion.
(OR)
What is specific latent heat of fusion? State its units.
Answer:
The amount of heat energy absorbed at constant temperature by unit mass of a solid to convert into liquid phase is called the specific latent heat of fusion.
It is expressed in units J/kg, erg/g, cal/g, kJ/ kg and kcal/kg.

[Note: Specific latent heat (L) = \(\frac{\text { latent heat }(Q)}{\text { mass of the substance }(m)}\)
:. SI unit of specific latent heat = SI unit of energy / SI unit of mass = J/kg]

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 3.
Explain the term latent heat of vaporization.
Answer:
When a liquid is heated continuously, initially, its temperature increases. Later, at a certain stage, its temperature does not increase even when heat is supplied to it. At this temperature, heat absorbed by the liquid is used for breaking the bonds between its atoms or molecules, i.e., for doing work against the forces of attraction between the atoms or molecules and conversion into gaseous phase.

This heat is called the latent heat of vaporization and the constant temperature at which this change of state occurs is called the boiling point of the liquid.

Question 4.
Define boiling point of a liquid.
(OR)
What is boiling point of a liquid?
Answer:
The constant temperature at which a liquid transforms into gaseous state is called the boiling point of the liquid.
[Note: On application of pressure, the boiling point of a liquid is raised. On reducting the pressure, the boiling point is lowered.]

Question 5.
Define specific latent heat of vaporization.
OR
What is specific latent heat of vaporization?
Answer:
The amount of heat energy absorbed at constant temperature by unit mass of a liquid to convert into gaseous phase is called the specific latent heat of vaporization.

Question 6.
The specific latent heat of fusion of ice is 80 cal/g. Explain this statement.
Answer:
When 1 g of ice at a pressure of one atmosphere and at a temperature 0 °C is converted into 1 g of water, heat absorbed by the ice is 80 cal.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 7.
The specific latent heat of fusion of silver is 88.2 kJ/kg. Explain this statement.
Answer:
When 1 kg of silver at a pressure of one atmosphere and at a temperature of 962 °C (melting point of silver) is converted into 1 kg of silver in liquid phase, heat absorbed by the silver is 88.2 kJ.

Question 8.
The specific latent heat of vaporization of water is 540 cal/g. Explain this statement.
Answer:
When 1 g of water at a pressure of one atmosphere and at a temperature of 100 °C is converted into 1 g of steam, heat absorbed by the water is 540 cal.

Question 9.
Define regelation.
(OR)
What is regelation?
Answer:
The phenomenon in which the ice converts to liquid due to applied pressure and then re-converts to ice once the pressure is removed is called regelation.

Question 10.
The terms hot and cold are used in relative context. Explain.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat 7
(1) Take three large bowls, P, Q and R. Fill bowl P with cold water, bowl Q with lukewarm water, and bowl R with hot water.
(2) Immerse your right hand in bowl P, and left hand in bowl R for about five seconds.
(3) Now, immerse both the hands in bowl Q at the same time.
(4) You will find that the water in bowl Q appears warm to your right hand, and cold to your left hand. Thus, the hand immersed in cold water for some time finds the lukewarm water hot while the one immersed in hot water finds the same lukewarm water cold. This experiment shows that the terms hot and cold are relative.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 11.
Draw a neat labelled diagram of Hope’s apparatus. Explain how this apparatus can be used to demonstrate anomalous behaviour of water. Draw a graph of temperature of water against time.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat 8
The figure shows Hope’s apparatus. Initially, the cylindrical container in Hope’s apparatus is filled with water at about 12 °C and the flat bowl is filled with a freezing mixture of ice and salt.

The temperature of water in the upper part of the container (T2) is recorded by thermometer T2 and that of water in the lower part of the container (T1) is recorded by thermometer T1. Figure shows variation of temperature of water with time.

Initially, both the thermometers show the same temperature (say, 12 °C). In a short time, the temperature shown by the lower thermometer starts decreasing, while the temperature shown by the upper thermometer does not change very much.

This process continues till the temperature shown by the lower thermometer falls to 4 °C and remains constant thereafter. This shows that in the temperature range 12 °C to 4 °C, the density of the water in the central part of the container goes on increasing and hence the water sinks to the bottom. It means that water contracts, i.e., its volume decreases as its temperature falls from 12 °C to 4 °C.

As the temperature of the water in the central part of the container becomes less than 4 °C, the temperature shown by the upper thermometer begins to fall rapidly to 0 °C. But the temperature shown by the lower thermometer remains constant (4 °C). Later, the heading shown by the lower thermometer decreases to 0 °C.

In the temperature range 4 °C to 0 °C, the water moves upward. This shows that the density of water goes on decreasing in this range. It means that water expands, i.e. its volume increases as its temperature falls from 4 °C to 0 °C.

Thus, the volume of a given mass of water is minimum at 4 °C, i.e., the density of water is maximum at 4 °C.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat 9
In the above figure, the point of intersection of the two curves shows the temperature at which the density of water is maximum. This temperature is 4 °C.

Question 12.
A mountaineer climbing on the Everest, experienced the following facts. Explain each fact with the scientific reason : (1) He found j fishes alive below the ice (2) Time required for cooking was more as he went higher (3) He saw many times cliffs falling suddenly (4) He saw tubes carrying water broken.
Answer:
Explanation:
(1) Water expands as its temperature decreases from 4 °C to 0 °C. Water is converted into ice at 0 °C. The density of water is more than that of ice. Fishes can remain alive in the water (at 4 °C) below the ice.
(2) At high altitudes, atmospheric pressure is low and hence water boils at a temperature lower than its normal boiling point. Therefore, the time required for cooking food is more at higher altitudes.
(3) Water expands while freezing. Hence, the water present in the crevices of the rocks exerts a tremendous pressure on the rocks, while freezing. Therefore, the cliffs fall.
(4) Water expands while freezing. Hence, the water in the tube exerts a large pressure on the tube, while freezing. Therefore, the tube carrying water breaks.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 13.
What is humidity?
Answer:
The moisture, i.e., the presence of water vapour, in the atmosphere is called humidity.

Question 14.
When is air said to be saturated with water vapour?
Answer:
When air contains maximum possible water vapour, it is said to be saturated with water vapour at that temperature.

Question 15.
What does the amount of water vapour needed to saturate air depend on?
Answer:
The extent of water vapour needed to saturate air depends on the temperature. The greater the temperature, the greater is the amount of water vapour needed to saturate air.

Question 16.
When is air said to be unsaturated with water vapour?
Answer:
When air contains water vapour less than its capacity to hold water vapour at that temperature, it is said to be unsaturated with water’vapour.

Question 17.
What is dew point temperature?
(OR)
Define dew point temperature.
Answer:
If the temperature of unsaturated air is decreased, a temperature is reached at which the air becomes saturated with water vapour. This temperature is called the dew point temperature.

Question 18.
Name the physical quantity used to express the amount of water vapour present in air.
Answer:
Absolute humidity.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 19.
Define absolute humidity.
(OR)
What is absolute humidity? State its unit.
Answer:
The mass of water vapour present in a unit volume of air is called absolute humidity. Generally it is expressed in kg/m3.

Question 20.
Define relative humidity.
(OR)
What is relative humidity? Write the formula for % relative humidity.
Answer:
The ratio of the actual mass of water vapour content in the air for a given volume and temperature to that required to make the same volume of air saturated with water vapour at the same temperature is called the relative humidity.

% Relative humidity = [the actual mass of water vapour content in the air for a given volume and temperature ÷ the mass of water vapour required to make the same volume of air saturated with water vapour at the same temperature] × 100%.

Question 21.
What is the value of relative humidity at the dew point temperature?
Answer:
At the dew point temperature, relative humidity is 100%.

Question 22.
The mass of water vapour in air enclosed in a certain space is 60 g and the mass of water vapour needed to saturate the same air with water vapour under the same conditions is 100 g. What is the corresponding % relative humidity?
Answer:
Here, % relative humidity = (\(\frac{60 \mathrm{g}}{100 \mathrm{g}}\)) × 100% = 60%

Question 23.
During winter, sometimes we see a white trail at the back of a flying aeroplane in a clear sky. Explain why.
Answer:
In winter, air temperature is low. Hence, when an aeroplane flies, the vapour released by its engine condenses and forms white clouds. If the relative humidity of the air surrounding the plane is high, we see this white trail at the back of the plane for a long time before it disappears. If.the relative humidity is low, the white trail is short and disappears quickly. If the relative humidity is very low, there is no formation of the white trail.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 24.
State two effects of humidity present in atmosphere.
Answer:
Effects of humidity present in atmosphere: When the temperature of air falls below the dew point, dew and fog are formed.

Question 25.
Explain how dew and fog are formed.
(OR)
Write a short note on formation of dew and fog.
Answer:
At a particular temperature, a given volume of air can contain a certain maximum amount of water vapour. Normally, the temperature of air during the day is such that air is not saturated with water vapour present in it.

As the temperature falls, the capacity of air to hold water vapour becomes less. During a cold night, the temperature of air may fall to the dew point, or even below the dew point. If the temperature falls below the dew point, the excess of water vapour in air condenses on the surfaces of cold bodies and dew is formed. If the water vapour condenses on the fine dust particles present in the atmosphere, mist or fog is formed.

Question 26.
State the units of heat.
Answer:
Units of heat: joule, erg, calorie, kilocalorie.

Question 27.
Define the kilocalorie.
Answer:
The amount of heat necessary to raise the temperature of 1 kg of water by 1 °C from 14.5 °C to 15.5 °C is called one kilocalorie.

Question 28.
Define the calorie.
Answer:
The amount of heat necessary to raise the temperature of 1 g of water by 1 °C from 14.5 °C to 15.5 °C is called one calorie.

Question 29.
State the relation between the kilocalorie and the calorie.
Answer:
1 kilocalorie = 103 calories.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 30.
Study the following procedure and answer the questions below:  (Practice Activity Sheet – 2)
1. Take 3 spheres of iron, copper and lead of equal mass.
2. Put all the 3 spheres in boiling water in a beaker for some time.
3. Take 3 spheres out of the water. Put them immediately on a thick slab of wax.
4. Note the depth that each sphere goes into the wax.
(i) Which property of a substance can be studied with this procedure?
(ii) Describe that property in minimum words.
(iii) Explain the rule of heat exchange with this property.
Answer:
(i) Specific heat.
(ii) Specific heat: The amount of heat energy required to raise the temperature of a unit mass of an object by 1 °C.
(iii) According to the rule/principle of heat exchange, heat energy lost by the hot object = heat energy gained by the cold object.

In this activity, heat absorbed by the iron sphere is transmitted more in the wax, hence the sphere goes deepest into the wax, while the lead sphere absorbs less heat, resulting in less transmission of heat in the wax, hence, the sphere goes the least depth into the wax.

Question 31.
Write the symbol for specific heat capacity. State the units of specific heat capacity.
Answer:
Symbol for specific heat capacity: c.
Units of specific heat capacity: J/kg·°C,
erg/g·°C, cal/g·°C, kcal/kg·°C.
[ Notes: (1) Specific heat capacity
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat 10
In SI, heat is expressed in joule (J), mass in kg and temperature in kelvin(K).
∴ SI unit of specific heat capacity = \(\frac{\mathrm{J}}{\mathrm{kg} \cdot \mathrm{K}}\). (2) The specific heat capacity of a substance depends upon its constituent particles (atoms, molecules, etc.), interaction between them, structure of the substance (atomic/molecular arrangement), temperature of the substance, etc.]

Question 32.
Explain the principle of heat exchange. Ans. Suppose two objects A and B at different temperature T1 and T2 respectively are enclosed in a box of heat resistant material as shown in figure.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat 11
Let m1 = mass of A, m2 = mass of B, c1 = specific heat capacity of A, c2 = specific heat capacity of B and T = common temperature attained by A and B after the heat exchange between A and B. Here, no heat leaves the box or enters the box from outside. Hence, if T1 > T2, heat energy lost by A (Q1) = heat energy gained by B (Q2).
∴ m1c1 (T1 – T) = m2c2 (T – T2)
[Note: If m1, c1, T1, T, m2 and T2 are known, c2 can be determined.]

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 33.
The specific heat capacity of silver is 0.056 kcal/kg·°C. Explain this statement.
Answer:
The amount of heat needed to raise the temperature of 1 kg of silver by 1 °C is 0.056 kcal.

Question 34.
Explain how the specific heat capacity of a solid can be determined (measured) by the method of mixture.
Answer:
A hot solid is put in water in a calorimeter. The mixture is stirred continuously and the maximum temperature of the mixture is measured with a thermometer. Heat exchange between the hot solid, water and calorimeter results in sill bodies attaining the same temperature after some time. Hence, according to the principle of heat exchange, heat lost by the solid = heat gained by the water in the calorimeter + heat gained by the calorimeter.

Now, heat lost by the solid (Q) = mass of the solid × its specific heat capacity × decrease in its temperature, heat gained by the water (Q1) = mass of the water × its specific heat capacity × increase in its temperature and heat gained by the calorimeter (Q2) = mass of the calorimeter × its specific heat capacity × increase in its temperature.

Heat lost by the hot object = heat gained by the calorimeter + heat gained by the water. Q = Q2 + Q1
Using this equation, the specific heat capacity of the solid can be determined (measured) when the other quantities are known.

Give scientific reasons:

Question 1.
Even though heat is supplied to boiling water, there is no increase in its temperature.
Answer:
Once water starts boiling, all the heat supplied to it is used in conversion of water into steam at the boiling point of water. Hence, there is no rise in its temperature.

Question 2.
Burns from steam are worse those from boiling water at the same temperature.
Answer:
1. A given quantity of steam contains more heat than the same quantity of boiling water at the same temperature.
2. When steam comes in contact with one’s body, it releases extra heat of 540 calories per gram and causes a more serious burn than that caused by boiling water.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 3.
In winter, the pipelines carrying water burst in cold countries.
Answer:
1. In cold countries, in winter, the temperature of the atmosphere falls below 0 °C. When the temperature of water falls below 4 °C, it expands. Hence, the water in pipes expands. Even if ice is formed, there is an increase in the volume.

2. As there is no room for expansion, water (or ice) exerts a large pressure on the pipes. Hence, the pipelines carrying water burst.

Question 4.
If crushed ice is pressed and then the pressure is released, a lump of ice is formed.
Answer:
1. When crushed ice is pressed, its melting point is lowered and some ice melts to form water.
2. When pressure is released, the melting point becomes normal and the water freezes to form ice forming a lump.

Question 5.
In cold countries, in winter, even when the water of lakes freezes, aquatic animals and plants can survive.
Answer:
1. In cold countries, in winter, a layer of ice is formed on the surface of lakes when the atmospheric temperature falls below 0 °C. However, below this layer, there is water at 4 °C.
2. Ice, being a bad conductor of heat, does not allow transfer of heat from this water to the atmosphere. Hence, aquatic animals and plants can survive in this water.

Question 6.
Water droplets are seen on’ the outer surface of a cold drink bottle.
Answer:
1. The temperature of the outer surface of a cold drink bottle is less than that of the atmosphere.
2. Therefore, the excess of water vapour from the air condenses to form droplets on the outer surface of the cold drink bottle.

Question 7.
During cold nights, sometimes dew is formed.
Answer:
1. During a cold night, the temperature of air may fall to the dew point, or even below the dew point. 2. If the temperature falls below the dew point, the excess of water vapour in air condenses on the surfaces of cold bodies and dew is formed.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Question 8.
When you enter a warm room after being outside on a frosty early morning, your spectacles ‘steam up’.
Answer:
1. On a frosty early morning, the temperature of air outside a warm room is lower than the dew point.
2. Hence, when you enter the room from outside, some water vapour in the room condenses on the glass of your spectacles, i.e., the spectacles ‘steam up’.

Question 9.
A plastic bottle, completely filled with water, when kept in a freezer, is likely to break.
Answer:
The temperature of air in the freezer (deep freeze) compartment of a refrigerator is less than 0 °C. 2. When a plastic bottle, completely filled with water, is kept in this compartment, the temperature of water falls below 4 °C and the water expands. Even when water freezes and ice is formed, there is an increase in the volume. It exerts a large pressure on the sides of the bottle and hence the bottle is likely to break.

Question 10.
The outer surface of a beaker containing ice cubes becomes wet in a short while.
Answer:
1. When ice cubes are placed in a beaker, ice starts melting. The heat required for melting is absorbed from the surrounding air and also from the beaker to some extent.
Hence, the temperature of the air and beaker falls.

2. The capacity of air to hold water vapour depends upon the temperature of the air, and this capacity decreases as the temperature decreases. At a certain low temperature, the surrounding air becomes saturated with water vapour present in it. As the temperature falls further, the air is unable to hold all the water vapour.

Hence, the extra water vapour starts condensing on the cold outer surface of the beaker in the form of minute drops. Therefore, the outer surface of the beaker containing ice cubes becomes wet in a short while.

Distinguish between the following:

Question 1.
Absolute humidity and Relative humidity.
Answer:
Absolute humidity:

  1. Absolute humidity is the mass of water vapour present in a unit volume of air.
  2. It is commonly expressed in kg/m3.

Relative humidity:

  1. Relative humidity is the ratio of the mass of water vapour in a given volume of air at a given temperature to the mass of water vapour required to saturate the same volume of air at the same temperature.
  2. It does not have unit.

Solve the following examples/Numerical problems:
[Use the data given in the Tables on pages 130 and 131.]

Problem 1.
Calculate the amount of heat required to convert 5 g of ice of 0 °C into water at 0 °C. (Specific latent heat of fusion of ice = 80 cal/g)
Solution: Here, m = 5 g, L = 80 cal/g; Q = ?
Amount of heat required, Q = mL
= 5 g × 80 cal/g
= 400 calories.

Problem 2.
Find the amount of heat required to convert 10 g of water at 100 °C into steam. (Specific latent heat of vaporization of water = 540 cal/g)
Solution: Here, m = 10 g, L = 540 cal/g; Q = ?
Amount of heat required, Q = mL
= 10 g × 540 cal/g
= 5400 calories.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Problem 3.
Calculate the amount of heat required to convert 15 g of water at 100 °C into steam. (Specific latent heat of vaporization of water = 540 cal/g)
Solution:
m = 15 g, L = 540 cal/g; Q = ?
Amount of heat required, Q = mL
= 15 g × 540 cal/g
= 8100 calories.

Problem 4.
How many calories of heat will be absorbed when 3 kg of ice at 0 °C melts?
Solution:
m = 3 kg = 3000 g; L = 80 cal/g; Q = ?
Quantity of heat absorbed, Q = mL
= 3000 g × 80 cal/g
∴ Q = 240000 calories.

Problem 5.
Calculate the amount of heat required to convert 10 g of water at 30 °C into steam at 100 °C. (Specific latent heat of vaporization of water = 540 cal/g)
Solution:
Here, m = 10 g; c = 1 cal/g·°C
T2 – T1 = 100 °C – 30 °C = 70 °C; L = 540 cal/g; Q = ?
Amount of heat required, Q = mc (T2 – T1) + mL
= 10 g × 1 cal/g·°C × 70 °C + 10 g × 540 cal/g
= 700 cal + 5400 cal
∴ Q = 6100 calories.

Problem 6.
If water of mass 80 g and temperature 45 °C is mixed with water of mass 20 g and temperature 30 °C, what will be the maximum temperature of the mixture?
Solution:
Data : m1 = 80 g, T1 = 45 °C, m2 = 20 g,
T2 = 30 °C, T = ?
According to the principle of heat exchange, heat lost by hot water = heat gained by cold water
∴ m1c (T1 – T) = m2c (T – T2)
∴ m1T1 – m1T = m2T – m2T2
∴ m1T1 + m2T2 = (m1 + m2)T
∴ Maximum temperature of the mixture,
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat 12
= (36 + 6) °C
= 42°C.

Problem 7.
When water of mass 70 g and temperature 50 °C is added to water of mass 30 g, the maximum temperature of the mixture is found to be 41 °C. Find the temperature of water of mass 30 g before hot water was added to it.
Solution:
Data : m1 = 70 g, T1 = 50 °C, m2 = 30 g, T = 41 °C, T2 = ?
According to the principle of heat exchange, heat lost by hot water = heat gained by cold water
∴ m1c (T1 – T) = m2c (T – T2)
∴ m1T1 – m1T = m2T – m2T2
∴ m2T2 = (m1 + m2) T – m1T1
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat 13
This is the required temperature.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Problem 8.
Find the heat needed to raise the temperature of a silver container of mass 100 g by 10 °C. (c = 0.056 cal/g.°C)
Solution:
Data: m = 100 g, ΔT = 10 °C, c = 0.056 cal/g·°C
Heat needed to raise the temperature of the container = mc ΔT
= 100 g × 0.056 cal/g·°C × 10 °C .
= 56 calories.

Problem 9.
If steam of mass 100 g and temperature 100 °C is released on an ice slab of temperature 0 °C, how much ice will melt?
Solution:
Data: m1 = 100 g, L1 = 540 cal/g,
T1 = 100 °C, mass of ice, m = ?, L2 = 80 cal/g, c (water) = 1 cal/g·°C
According to the principle of heat exchange, heat lost by hot body = heat gained by cold body. Conversion of steam into water:
Q1 = m1L1 = 100 g × 540 cal/g = 54000 cal
Decrease in the temperature of this water to 0 °C:
Q2 = m1c × (T1 – 0 °C) = 100 g × 1 cal/g·°C × (100 °C – 0 °C) = 10000 Cal
Melting of ice: Q3 = mL2
= m × 80 cal/g
Now, Q1 + Q2 = Q3
∴ (54000 + 10000) cal = m × 80 cal/g
∴ m = \(\frac{64000}{80}\) = 800 g
800 g of ice will melt.

Numerical problems for practice:

Problem 1.
Calculate the amount of heat required to convert 80 g of ice at 0 °C into water at the same temperature. (Specific latent heat of fusion of ice = 80 cal/g)
Solution:
6400 cal

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Problem 2.
Find the heat required to convert 20 g of ice at 0 °C into water at the same temperature. (Specific latent heat of fusion of ice = 80 cal/g)
Solution:
1600 cal

Problem 3.
Calculate the quantity of heat released during the conversion of 10 g of ice cold water (temperature 0 °C) into ice at the same temperature. (Specific latent heat of freezing of water = 80 cal/g)
Solution:
800 cal

Problem 4.
How many calories of heat will be absorbed when 2 kg of ice at 0 °C melts? (Specific latent heat of fusion of ice = 80 cal/g)
Solution:
160000 cal

Problem 5.
How much heat will be required to convert 20 g of water at 100 °C into steam at 100 °C? (Specific latent heat of vaporization of water = 540 cal/g)
Solution:
10800 cal

Problem 6.
Find the heat absorbed by 25 g of water at 100 °C to convert into steam at the same temperature. (Specific latent heat of vaporization of water = 540 cal/g.)
Solution:
13500 cal

Problem 7.
If water of mass 60 g and temperature 50 °C is mixed with water of mass 40 g and temperature 30 °C, what will be the maximum temperature of the mixture?
Solution:
42 °C

Problem 8.
If water of mass 60 g and temperature 60 °C is mixed with water of mass 60 g and temperature 40 °C, what will be the maximum temperature of the mixture?
Solution:
50 °C

Problem 9.
Find the heat needed to raise the temperature of a piece of iron of mass 500 g by 20 °C. (c = 0.110 cal/g·°C)
Solution:
1100 cal

Problem 10.
Water of mass 200 g and temperature 30 °C is taken in a copper calorimeter of mass 50 g and temperature 30 °C. A copper sphere of mass 100 g and temperature 100 °C is released into it. What will be the maximum temperature of the mixture? [c (water) = 1 cal/g·°C, c (copper) =0.1 cal/g·°C]
Solution:
33.26 °C

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 5 Heat

Problem 11.
A copper calorimeter of mass 100 g and temperature 30 °C contains water of mass 200 g and temperature 30 °C. If a piece of ice of mass 40 g and temperature 0 °C is added to it, what will be the maximum temperature of the mixture? [c (copper) = 0.1 cal/g·°C, c (water) = 1 cal/g·°C, L = 80 cal/g]
Solution:
12.4 °C

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Balbharti Maharashtra State Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 1.
Match the pairs.

Group A Group B
a. C2H6 1. Unsaturated hydrocarbon
b. C2H2 2. Molecular formula of an alcohol
c. CH4O 3. Saturated hydrocarbon
d. C3H6 4. Triple bond

Question 2.
Draw an electron dot structure of the following molecules. (Without showing the circles)
a. Methane.
Answer:
Molecular formula: CH4
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 1

b. Ethene.
Answer:
Molecular formula: H2C = CH2
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 2

c. Methanol.
Answer:
Molecular formula: H3C – OH
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 3

d. Water.
Answer:
Molecular formula: H2O
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 4

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 3.
Draw all possible structural formulae of compounds from their molecular formula given below.
a. C3H8
b. C4H10
c. C3H4
Answer:
a. C3H8 Propane:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 5

b. C4H10 Butane:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 6

c. C3H4 Propyne:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 7

Question 4.
Explain the following terms with example.
a. Structural isomerism.
Answer:
The phenomenon in which compounds having different structural formulae have the same molecular formula is called structural isomerism. Butane is represented by two different compounds as their structural formulae are different. The first compound is a straight chain compound and the second compound is a branched chain compound. These two different structural formulae have the same molecular formula i.e. C4H10.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 8

b. Covalent bond.
Answer:
The chemical bond formed by sharing of two valence electrons between the two atoms is called covalent bond.
Example:
1. Hydrogen molecule formation: The atomic number of hydrogen is 1, its atom contains 1 electron in K shell. It requires one more electron to complete the K shell and attain the configuration of helium (He). To meet this requirement two hydrogen atoms share their electrons with each other to form H2 molecule. One covalent bond, i.e. a single bond is formed between two hydrogen atoms by sharing of two electrons.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 9

2. Formation of oxygen molecule:
(1) The atomic number of oxygen is 8. The electronic configuration of oxygen is (2, 6). Oxygen has 6 electrons in the outermost shell.
(2) It requires 2 electrons to complete the L shell and attain the configuration of neon (Ne).
(3) Each oxygen atom shares its valence electron with the valence electron of another oxygen atom to give two shared pairs of electrons which results in the formation of oxygen molecule.
(4) Thus, two electron pairs are shared between two oxygen atoms, forming double covalent bond (=).
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 10

c. Hetero atom in a carbon compound.
Answer:
Carbon compounds are formed by formation of bonds of carbon with other elements such as halogens, oxygen, nitrogen, sulfur. The atoms of these elements substitute one or more hydrogen atoms in the hydrocarbon chain and thereby the tetravalency of carbon is satisfied. The atom of the element which is substitute for hydrogen is referred to as a heteroatom. Sometimes hetero atoms are not alone but exist in the form of certain groups of atoms.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 11

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

d. Functional group.
Answer:
The compound acquire specific chemical properties due to these hetero atoms or the groups of atoms that contain hetero atoms, irrespective of length and nature of the carbon chain in that compound. Therefore these hetero atoms or groups of atoms containing hetero atoms are called the functional groups.

e. Alkane.
Answer:
In hydrocarbon, the four valencies of carbon atom are satisfied only by the single bonds, such compounds are called alkane.
Example: In methane, four hydrogen atoms are bonded to carbon atom by four single covalent bonds.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 12

f. Unsaturated hydrocarbons.
Answer:
The carbon compounds having a double bond or triple bond between two carbon atoms are called unsaturated hydrocarbons. The unsaturated hydrocarbons containing a carbon-carbon double bond are called alkenes.
e.g. Ethene (CH2 = CH2), Propene (CH3 – CH = CH2).
The unsaturated hydrocarbons containing a carbon-carbon triple bond are called alkynes e.g. Ethyne (CH ≡ CH).

g. Homopolymer.
Answer:
The polymers formed by repetition of single monomer are called homopolymer. e.g. polyethylene (CH2 – CH2)n.

h. Monomer.
Answer:
The small unit that repeats regularly to form a polymer is called monomer.
Example: Ethylene.

i. Reduction.
Answer:
In a chemical reaction, removal of oxygen from a compound or addition of hydrogen to a compound is called a reduction.

j. Oxidant.
Answer:
An oxidant is a reactant that oxidizes or removes electrons from other reactants during a redox reaction. An oxidant may also be called an oxidizer or oxidizing agent. When the oxidant includes oxygen, it may be called an oxygenation reagent or oxygen-atom transfer (OT) agent.
Examples of oxidants include:

  1. Hydrogen peroxide
  2. Ozone
  3. Nitric acid
  4. Sulfuric acid

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 5.
Write the IUPAC names of the following structural formulae.
a. CH3 – CH2 – CH2 – CH3
Answer:
The number of carbon atopic in the longest chain: 4
Parent alkane: Butane IUPAC name: n-Butane

b. CH3 – CHOH – CH3 (Practice Activity Sheet – 3)
Answer:
The number of carbon atoms in the longest chain: 3
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 13
Parent alkane: Propane
Functional group: -OH (ol)
Assign the number: 2
The carbon atom to which the -OH group is attached is numbered as C2. If the carbon chain of the compound contains a -OH group then change the ending of the parent name, i.e., ‘e’ of propane is replaced by ‘ol’. (ol stands for alcohol)
Parent suffix: Propan-2-ol
IUPAC name: Propan-2-ol

c. CH3 – CH2 – COOH (Practice Activity Sheet – 3)
Answer:
The number of carbon atoms in the longest chain: 3
Parent alkane: Propane
Functional group: -COOH (-oic acid)
If the carbon chain of the compound contains a -COOH group then change the ending of the parent name, i.e., ‘e’ of propane is replaced by ‘oic acid’.
Parent suffix: Propanoic acid
IUPAC name: Propanoic acid

d. CH3 – CH2 – NH2
Answer:
Number of carbon atoms: 2
Parent alkane: Ethane
Functional group: -NH2 (amine)
If the carbon chain of the compound contains a -NH2 group, then change the ending of the parent name, i.e., ‘e’ of ethane is replaced by ‘amine’.
Parent suffix: Ethanamine
IUPAC name: Ethanamine.

e. CH3 – CHO
Answer:
Number of carbon atoms: 2
Parent alkane: Ethane
Functional group: -CHO (al)
If the carbon chain of the compound contains a -CHO group, then change the ending of the parent name, i.e., ‘e’ of ethane is replaced by ‘al’.
Parent suffix: Ethanal
IUPAC name: Ethanal

f. CH3 – CO – CH2 – CH3
Answer:
Number of carbon atoms in the longest chain: 4
Parent alkane: Butane Functional group: -CO- (one)
Assign the number:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 14
In the longest chain, the numbering of carbon atom starts from the carbon atom nearest to the function group.
If the carbon chain of the compound contains a (-CO-) group, then change the ending of the parent name, i.e., ‘e’ of butane is replaced by ‘one’.
Parent suffix: Butan-2-one
IUPAC name: Butan-2-one

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 6.
Identify the type of the following reaction of carbon compounds.
1. CH3 – CH2 – CH2 – OH + (O) → CH3 – CH2 – COOH
2. CH3 – CH2 – CH3 + O2 → 3CO2 + 4H2O
3. CH3 – CH = CH – CH3 + Br2 → CH3 – CHBr – CHBr – CH3
4. CH3 – CH3 + Cl2 → CH3 – CH2 – Cl + HCl
5. CH3 – CH2 – CH2 – CH2 – OH → CH3 – CH2 – CH = CH2 + H2O
6. CH3 – CH2 – COOH + NaOH → CH3 – CH2 – COONa+ + H2O
7. CH3 – COOH + CH3 – OH → CH3 – COO – CH3 + H2O
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 15
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 16

Question 7.
Write the structural formulae for the following IUPAC names:
a. Pent-2-one
Answer:
Pent-2-one.
(1) Pent stands for 5 carbon atoms in a chain.
Number the carbon atoms in a chain as 1, 2, 3,…..
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 17
(2) ‘one’ stands for functional group
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 18
ketone. The number assigned for the ketone group is 2. Show the ketone group at C2.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 19
(3) Now satisfy the valencies of each carbon atom
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 20

b. 2-Chlorobutane
Answer:
(1) In 2-chlorobutane, butane is parent alkane stands for 4 carbon atoms and number the carbon atoms in a chain as 1, 2, 3,….
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 21
(2) Chloro (Halo) is the prefix and the number assigned for prefix (chloro) is 2. Show the chloro atom at C2
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 22
(3) Now satisfy the valencies of each carbon atom
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 23

c. Propan-2-ol
Answer:
(1) Propan stands for 3 carbon atoms in a chain. Number the carbon atom in a chain as 1, 2, 3.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 24
(2) ‘-ol’ stands for (-OH) hydroxyl group. The number assigned for the hydroxyl group is 2. Show the -OH group at C2.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 25
(3) Now satisfy the valencies of each carbon atom
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 26

d. Methanal
Answer:
(1) Meth – stands for one carbon atom and assigned the number ‘1’ to carbon in the functional group -CHO.
(2) ‘-al’ stands for functional group (-CHO) aldehyde.
(3) Now satisfy the valencies of carbon in -CHO.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 27

e. Butanoic acid
Answer:
(1) But stands for 4 carbon atoms in a chain. Number the carbon atoms in a chain as 1, 2, 3,….
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 28
‘-oic acid’ stands for functional group -COOH. Assign the number 1 to carbon in the functional group -COOH.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 29
Now satisfy the valencies of each carbon atom
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 30

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

f. 1-Bromopropane.
Answer:
(1) In 1-bromopropane, propane is parent alkane stands for 3 carbon atoms and number the carbon atoms in a chain as 1, 2, 3…….
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 31
(2) Bromo (Halo) is the prefix and the number assigned for prefix (bromo) is 1, show the bromine atom at C1.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 32
(3) Now satisfy the valencies of each carbon atom
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 33

g. Ethanamine
Answer:
(1) Eth stands for 2 carbon atoms in a chain and the parent alkane is ethane.
– C – C –
(2) ‘amine’ stands for (- NH2) amino group. Show the amino (-NH2) at any carbon atom.
– C – C – NH2
(3) Now satisfy the valencies of each carbon atom
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 34

h. Butanone.
Answer:
(1) But stands for 4 carbon atoms in a chain and the parent alkane is butane. Number the carbon atoms in a chain 1, 2, 3,….
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 35
(2) ‘one’ stands for functional group
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 36
ketone. The number assigned for the ketone group is 2. Show the ketone group at C2.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 37
(3) Now satisfy the valencies of each carbon atom
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 38

Question 8.
a. What causes the existance of very large number of carbon compound?
Answer:
(1) Carbon has a unique ability to form strong covalent bonds with other carbon atoms; this results in formation of big molecules. This property of carbon is called catenation power. The carbon compounds contain open chains or closed chains of carbon atoms. An open chain can be a straight chain or a branched chain. A closed chain is a ring structure. The covalent bond between two carbon atoms is strong and therefore stable. Carbon is bestowed with catenation power due to the strong and stable covalent bonds.

(2) One, two or three covalent bonds can bond together two carbon atoms. These bonds are called single covalent bond, double covalent bond and triple covalent bond respectively. Due to the ability of carbon atoms to form multiple bonds as well as single bonds, the number of carbon compounds increases. For example, there are three compounds, namely, ethane (CH3 – CH3), ethene (CH2 = CH2) and ethyne (CH = CH) which contain two carbon atoms.

(3) Carbon being tetravalent, one carbon atom can form bonds with four other atoms (carbon or any other). This results in formation of many compounds. These compounds possess different properties as per the atoms to which carbon is bonded. For example, five different compounds are formed using one carbon atom and two monovalent elements hydrogen and chlorine: CH4, CH3Cl, CH2Cl2, CHCl3, CCl4. Similarly carbon atoms form covalent bonds with atoms of elements like O, N, S, halogen and P to form different types of carbon compounds in large number.

(4) Isomerism is one more characteristic of carbon compound which is responsible for large number of carbon compounds.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

b. Saturated hydrocarbons are classified into three types. Write these names giving one example each.
Answer:
In hydrocarbon, the four valencies of carbon atom are satisfied only by the single bonds, such compounds are called saturated hydrocarbons. Methane molecule contains only one carbon atom. In methane, four hydrogen atoms are bonded to carbon atom by four covalent bonds.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 39

c. Give any four functional groups containing oxygen as the heteroatom in it. write name and structural formula of one example each.
Answer:

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 40

d. Give names of three functional groups containing three different heteroatoms. Write name and structural formula of one example each.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 41

e. Give names of three natural polymers. write the place of their occurance and names of monomers from which they are formed.
Answer:

  1. Poly saccharide is a natural polymer. It occurs in starch/carbohydrates. It is formed from monomer glucose.
  2. Protein is a natural polymer. It occurs in muscles, hair, enzymes, skin, egg. It is formed from alpha amino acids.
  3. Rubber is a natural polymer. It occurs in latex of rubber tree. It is formed from monomer isoprene.

f. What is meant by vinegar and gasohol? What are their uses?
Answer:
(1) Vinegar is a 5 – 8% aqueous solution of acetic acid. It is used as preservative in pickles. It is used to cook meat. 1t is used as a salad dressing.
(2) To increase the efficiency of petrol, it is mixed with 10% anhydrous ethanol, such a fuel is called gasohol. It is used as a fuel in cars and other vehicles.

g. what is a catalyst ? write any one reaction which is brought about by use of catalyst?
Answer:
Catalyst is a substance, which changes the rate of reaction, without causing any disturbance to it. Vegetable oil (unsaturated compound) undergoes addition reaction with hydrogen in the presence of nickel catalyst to form vanaspati ghee (saturated compound).

Project:
Prepare a chart giving detailed information of carbon compounds in everyday use. Display it in the cluss and discuss.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Can you recall? (Text Book Page No. 110)

Question 1.
What are the types of compounds?
Answer:
Organic and inorganic compounds are the two important types of compounds.

Question 2.
Objects in everyday use such as foodstuff, fibres, paper, medicines, wood, fuels are made of various compounds. Which constituent elements are common in these compounds?
Answer:
The constituent elements common in these compounds are carbon (C), hydrogen (H) and oxygen (O).

Question 3.
To which group in the periodic table does the element carbon belongs? Write down the electronic configuration of carbon and deduce the valency of carbon.
Answer:
The element carbon belongs to group 14 and its electronic configuration is 2, 4. The valency of carbon is 4.

Use your brain Power! (Text Book Page No. 115)

Question 1.
The molecular formula of ethyne is C2H2. From this draw its structural formula and electron-dot structure.
Answer:
Ethyne: Molecular formula: C2H2
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 42

Question 2.
How many bonds have to be there in between the carbon atoms in ethyne so as to satisfy their tetra valency?
Answer:
To satisfy their tetravalency, three double bonds have to be there in between two carbon atoms in ethyne.

Use your brain power! (Text Book Page No. 116)

Question 1.
Draw the electron-dot structure of cyclohexane.
Answer:
Cyclohexane: Molecular formula: C6H12
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 43

Use your brain power! (Text Book Page No. 112)

Question 1.
Atomic number of chlorine is 17. What is the number of electrons in the valence shell of the chlorine?
Answer:
There are seven electrons in the valence shell of the chlorine.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 2.
Molecular formula of chlorine is Cl2. Draw electron-dot and line structure of a chlorine molecule.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 44

Question 3.
The molecular formula of water is H2O. Draw electron-dot and line structures for triatomic molecule. (Use dots for electron of oxygen atom and crosses for electrons of hydrogen atoms.)
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 45

Question 4.
The molecular formula of ammonia is NH3. Draw electron-dot and line structures for ammonia molecule.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 46

Question 5.
The molecular formula of carbon dioxide is CO2. Draw the electron-dot structure (without showing circle) and line structure for CO2.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 47

Question 6.
With which bond C atom in CO2 is bonded to each of the O atoms ?
Answer:
In CO2, carbon atom is bonded to each of the O atoms by double bond.

Question 7.
The molecular formula of sulfur is S8 in which eight sulphur atoms are bonded to each other to form one ring. Draw electron-dot structure for S8 without showing the circles.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 48
The above S8 molecule of sulphur has crown shaped structure. One molecule of sulpur is made up of eight atoms of sulphur.

Use your brain power! (Text Book Page No. 113)

Question 1.
Hydrogen peroxide decomposes of its own by the following reaction:
2H – O – O – H → 2H – O – H + O2
From this, what will be your inference about the strength O – O covalent bond ?
Tell from the above example whether oxygen has catenation power or not.
Answer:
In hydrogen peroxide (H2O2), the O – O covalent bond is not strong as oxygen has no catenation power.

Name Molecular
formula
Condensed Structural formula Number of carbon atoms Number of
-CH2– units
Boiling point ° C
Ethene C2H4 CH2 = CH2 2 0 -102
Propone C3H6 CH3 – CH = CH2 3 1 -48
1-Butene C4H8 CH3 – CH2 – CH = CH2 -6.5
1-Pentene C5H10 CH3 – CH2 – CH2 – CH = CH2 30

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Use your brain power! (Text Book Page No. 120)

Question 1.
The above table shows the homologous series of alkenes. Inspect the molecular formulae of the members of this series. Do you find any relationship, in the number of carbon atoms and the number of hydrogen atoms in the molecular formulae?
Answer:
In the above homologous series, if we observe the molecular formulae of alkenes then the number of carbon atoms are half the number of hydrogen atoms.

Question 2.
If the number of carbon atoms in the molecular formulae of alkenes is denoted by ‘n’ what will be the number of hydrogen atoms?
Answer:
If the number of carbon atoms in the molecular formulae of alkenes is denoted by ‘n’ then the number of hydrogen atoms would be 2n.

Question 3.
What would be the general formula for the molecular formulae of the members of the homologous series of alkanes? What would be the value of ‘n’ for the first member of this series?
Answer:
The general formula for the homologous series of alkane is CnH2n + 2. The value of ‘n’ for the first member of homologous series is 1.
CnH2n+2 = C1H2 × 1 + 2 = CH4

Question 4.
The general molecular formula for the homologous series of alkynes is CnH2n – 2. Write down the individual molecular formulae of the first, second and third members by substituting the values 2, 3 and 4 respectively for ‘n’ in this formula.
Answer:
The general molecular formula for the homologous series of alkynes is CnH2n – 2
n = 2 C2H2 × 2 – 2 = C2H2 Ethyne
n = 3 C3H2 × 3 – 2 = C3H4 Propyne
n = 4 C4H2 × 4 – 2 = C4H6 Butyne

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 5.
Write down structural formulae of the first four members of the various homologous series formed by making use of the functional groups.
Answer:

Functional group Halo – X (Cl, Br, -I) Functional group
Aldehyde – CHO
Functional group
Carboxylic acid – COOH
Functional group
Amine -NH2
CH3Cl
Chloromethane
HCHO
Methanal
HCOOH
Methanoic acid
CH3NH2
Methenamine
CH3 – CH2 – Cl
Chloroethane
CH3CHO
Ethanal
CH3COOH
Ethanoic acid
CH3CH2NH2
Ethanamine
CH3 – CH2 – CH2 – Cl
1-Chloropropane
CH3CH2CHO
Propanal
CH3CH2COOH
Propanoic acid
CH3CH2CH2NH2
Propanamine
CH3 – CH2 – CH2 CH2 – Cl
1-Chlorobutane
CH3CH2CH2 CHO
Butanal
CH3CH2CH2COOH
Butanoic acid
CH3CH2CH2CH2NH2
Butanamine

Question 6.
General formula of the homologous series of alkanes is CnH2n + 2. Write down the molecular formula of the 8th and 12th member using this.
Answer:
General formula of alkanes is CnH2n + 2
n = 8 C8H2 × 8 + 2 = C6H18 Octane
n = 12 C12H2 × 12 + 2 = C12H26 Dodecane

Use your brain power! (Text Book Page No. 121)

Question 1.
Draw three structural formulae having molecular formula C5H12. Give the names n-pentane, i-pentane and neo-pentane to the above structural formulae.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 49

Question 2.
Draw all possible structural formulae having molecular formula C6H14. Give names to all the isomers.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 50
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 51

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Try This! (Text Book Page No. 124)

Question 1.
Light a bunsen burner. Open and close the air hole at the bottom of the burner by means of the movable ring around it. When do you get yellow sooty flame? When do you get blue flame?
Answer:
When the air hole at the bottom of the burner is open, sufficient oxygen is mixed gaseous fuel for complete combustion and a clean blue flame is obtained. When the air hole is partially blocked by means of the movable ring around it, the air supply is limited which results in incomplete combustion. Hence, yellow sooty flame is produced.

(Text Book Page No. 126)

Question 1.
The names of four fatty acids separated from vegetable oils are given in the table. Identify the number of carbon – carbon double bonds from their structure and molecular formula from the below fatty acids which one when reacts with iodine will make the colour of iodine disappear.
Answer:

Name Molecular Formula Number of C = C double bonds Will it decolorise I2?
Stearic acid C17H35COOH ———————– yes/no
Oleic acid C17H33COOH One double bond yes/no
Plamitic acid C15H31COOH ———————– yes/no
Linoleic acid C17H31COOH Two double bonds yes/no

Use your brain power! (Text Book Page No. 128)

Question 1.
Explain by writing a reaction, what will happen when pieces of sodium metal are put in n-propyl alcohol.
Answer:
n-Propyl alcohol reacts with pieces of sodium metal, sodium propoxide and hydrogen gas are obtained.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 52

Question 2.
Explain by writing a reaction, which product will be formed on heating n-butyl alcohol with concentrated sulphuric acid.
Answer:
When n-butyl alcohol is heated with concentrated sulphuric acid, one molecule of water is removed from its molecule to form 1-butene.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 53

Use your brain power! (Text Book Page No. 129)

Question 1.
Which one of ethanoic acid and hydrochloric acid is stronger?
Answer:
Hydrochloric acid is stronger acid.

Question 2.
Which indicator paper out of blue litmus paper and pH paper is useful to distinguish between ethanoic acid and hydrochloric acid ?
Answer:
pH paper is useful to distinguish between ethanoic acid and hydrochloric acid.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Use your brain power! (Text Book Page No. 130)

Question 1.
Explain why does the lime water turns milky in the reaction of acetic acid with sodium carbonate.
Answer:
In the reaction of acetic acid with sodium carbonate, carbon dioxide gas is evolved which turns lime water milky resulting in the formation of insoluble calcium carbonate.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 54

Question 2.
Explain the reaction that would take place when a piece of sodium metal is dropped in ethanoic acid.
Answer:
When a piece of sodium metal is dropped in ethanoic acid, sodium acetate and hydrogen gas is formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 55

Question 3.
Two test tubes contain two colourless liquids ethanol and ethanoic acid. Explain by writing reaction which chemical test you would perform to tell which substance is present in which test tube.
Answer:
Ethanol does not react with sodium bicarbonate, while ethanoic acid reacts with sodium bicarbonate to form carbon dioxide gas.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 56

Use your brain power! (Text Book Page No. 131)

Question 1.
When fat is heated with sodium hydroxide solution, soap and glycerin are formed. Which functional groups might be present in fat and glycerin? What do you think?
Answer:
The functional group carboxylic acid (-COOH) is present in fat whereas the functioned group hydroxyl group (-OH) is present in glycerin.

Can you tell? (Text Book Page No. 131)

Question 1.
What are the chemical names of the nutrients that we get from the foodstuff, namely, cereals, pulses and meat?
Answer:
The nutrients that we get from the foodstuff, namely cereals, pulses and meat are alpha amino acids.

Question 2.
What are the chemical substances that make cloth, furniture and elastic objects?
Answer:
The chemical substances that make cloth, furniture and elastic objects are cellulose and rubber.

Use your brain power! (Text Book Page No. 133)

Question 1.
Structural formulae of some monomers are given below. Write the structural formula of the homopolymer formed from them.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 57
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 58

Question 2.
From the given structural formula of polyvinyl acetate, that is used in paints and glues, deduce the name and structural formula of the corresponding monomer.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 59
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 60

(Text Book Page No. 133)

Question 1.
Complete the following table by writing their Structural formulae and Molecular formulae.
Answer:
(Answer is given directly in bold letters.)
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 61
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 62

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Fill in the gaps in the table: (Text Book Page No. 119)
(Answer is given directly in bold letters.)
a. Homologous series of alkanes.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 63

b. Homologous series of alcohol.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 64

c. Homologous series of alkenes.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 65

(Text Book Page No. 123)

Question 1.
Complete the table by writing the IUPAC names in the third column.
(Answer is directly given with underline.)
Answer:

Common name Structural formula IUPAC name
Ethylene CH2 = CH2 Ethene
Acetylene HC = CH Ethyne
Acetic acid CH3 -COOH Ethanoic acid
Methyl alcohol CH3 – OH Methanol
Ethyl alcohol CH3 – CH2 – OH Ethanol

Use your brain power! (Text Book Page No. 119)

Question 1.
By how many -CH2– (methylene) units do the formulae of the first two members of homologous series of alkanes, methane (CH4) and ethane (C2H6) differ? Similarly, by how many -CH2– units do the neighbouring members ethane (C2H6) and propane (C3H8) differ from each other?
Answer:
The first two members of homologous series of alkanes, methane (CH4) and ethane (C2H6) differed by one -CH2– unit. Similarly, ethane (C2H6) and propane (C3H8) differed by -CH2– unit.

Question 2.
How many methylene units are extra in the formula of the fourth member than the third member of the homologous series of alcohols?
Answer:
There is only one, methylene unit extra in the formula of the fourth member and the third member of the homologous series of alcohols.

Question 3.
How many methylene units are less in the formula of the second member than the third member of the homologous series of alkenes?
Answer:
There is only one methylene unit less in the formula of the second member of and the third member of the homologous series of alkenes.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Fill in the blanks and rewrite the completed statements:

Question 1.
The organic compounds having double or triple bonds in them are termed as …………
Answer:
The organic compounds having double or triple bonds in them are termed as unsaturated hydrocarbons.

Question 2.
The general formula of alkane is ……………
Answer:
The general formula of alkane is CnH2n + 2.

Question 3.
The compounds of homologous series have the same ………….. group.
Answer:
The compounds of homologous series have the same functional group.

Question 4.
A double bond is formed between carbon atoms by ………… pairs of electrons.
Answer:
A double bond is formed between carbon atoms by two pairs of electrons.

Question 5.
The compounds having different structural formulae having the same molecular formula is called ……….
Answer:
The compounds having different structural formulae having the same molecular formula is called structural isomerism.

Question 6.
The functional group of ether is …………..
Answer:
The functional group of ether is -O-.

Question 7.
The general formula of alkene is …………
Answer:
The general formula of alkene is CnH2n.

Question 8.
The bond between two atoms of nitrogen is a ………… bond.
Answer:
The bond between two atoms of nitrogen is a triple bond.

Question 9.
Benzene ring is made up of ………….. carbon atoms.
Answer:
Benzene ring is made up of six carbon atoms.

Question 10.
Due to …………., vegetable oil is converted into vanaspati ghee.
Answer:
Due to hydrogenation, vegetable oil is converted into vanatspati ghee.

Question 11.
………….. control the heredity at molecular level.
Answer:
Nucleic acids control the heredity at molecular level.

Question 12.
The regular repetition of a small unit is called …………..
Answer:
The regular repetition of a small unit is called polymer.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 13.
The structural formula of polypropylene is ……………….
Answer:
The structural formula of polypropylene is
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 66

Question 14.
The monomers of proteins are ……………..
Answer:
The monomers of proteins are alpha amino acids.

Question 15.
The monomer of cellulose is …………
Answer:
The monomer of cellulose is glucose.

Question 16.
…………. have sweet odour.
Answer:
Esters have sweet odour.

Choose the correct alternative and rewrite the statement:

Question 1.
The property of direct bonding between atoms of the same element to form a chain is called ………..
(a) catenation
(b) isomerism
(c) dehydration
(d) polymerization
Answer:
The property of direct bonding between atoms of the same element to form a chain is called catenation.

Question 2.
The molecular weight of two adjacent members in homologous series of an alkane differ by ………. units.
(a) 16
(b) 20
(c) 14
(d) 12
Answer:
The molecular weight of two adjacent members in homologous series of an alkane differ by 14 units.

Question 3.
Consecutive members of a homologous series differ by ………. group.
(a) -CH
(b) -CH2
(C) -CH3
(d) -CH4
Answer:
Consecutive members of a homologous series differ by CH2 group.

Question 4.
……….. is used to prepare carbon black.
(a) Methane
(b) Ethene
(c) Propane
(d) Butane
Answer:
Methane is used to prepare carbon black.

Question 5.
……….. is the general formula of alkene.
(a) CnH2n
(b) CnH2n + 2
(c) CnH2n – 2
(d) CnHn – 2
Answer:
CnH2n is the general formula of alkene.

Question 6.
The reaction of methane with chlorine in the presence of sunlight is called ………..
(a) pyrolysis
(b) an elimination reaction
(c) a substitution reaction
(d) an addition reaction
Answer:
The reaction of methane with chlorine in the presence of sunlight is called a substitution reaction.

Question 7.
The general formula for alkynes is ………….
(a) CnH2n
(b) CnH2n + 2
(c) CnH2n – 2
(d) CnH2n – 1
Answer:
The general formula for alkynes is CnH2n – 2

Question 8.
The reaction of ………… with ethanol is a fast reaction.
(a) calcium
(b) magnesium
(c) sodium
(d) aluminum
Answer:
The reaction of sodium with ethanol is a fast reaction.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 9.
Ethylene has …………. bond between two carbon atoms.
(a) a single
(b) a double
(c) a triple
(d) an ionic
Answer:
Ethylene has a double bond between two carbon atoms.

Question 10.
The saturated hydrocarbons are those in which carbon atom are linked by ………….
(a) a single bond
(b) a double bond
(c) a triple bond
(d) an ionic bond
Answer:
The saturated hydrocarbons are those in which carbon atom are linked by a single bond.

Question 11.
C7H16 is ………….
(a) hexane
(b) octane
(c) methane
(d) heptane
Answer:
C7H16 is heptane.

Question 12.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 67
(a) carboxylic acid group
(b) aldehyde group
(c) ketonic group
(d) alcohol group
Answer:
(a) carboxylic acid group

Question 13.
The possible isomers for C5H12 are ……………
(a) 2
(b) 4
(c) 1
(d) 3
Answer:
The possible isomers for C5H12 are 3.

Question 14.
………. contains alcoholic functional group.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 68
Answer:
(d) all of these

Question 15.
Oxygen molecule has ………… bond between two oxygen atoms.
(a) a double
(b) a single
(c) a triple
(d) an ionic
Answer:
Oxygen molecule has a double bond between two oxygen atoms.

Question 16.
Some acetic acid is treated with solid NaHCO3. The resulting solution will be ………..
(a) colourless
(b) blue
(c) green
(d) yellow
Answer:
Some acetic acid is treated with solid NaHCO3. The resulting solution will be colourless.

Question 17.
Ethanoic acid has a ……… odour.
(a) rotten eggs
(b) pungent
(c) mild
(d) vinegar-like
Answer:
Ethanoic acid has a vinegar-like odour.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 18.
Acetic acid ………..
(a) turns red litmus blue
(b) has pungent odour
(c) is red in colour
(d) is odourless
Answer:
Acetic acid has pungent odour.

Question 19.
When acetic acid reacts with sodium metal ……….. gas is formed.
(a) oxygen
(b) hydrogen
(c) chlorine
(d) nitrogen
Answer:
When acetic acid reacts with sodium metal hydrogen gas is formed.

Question 20.
The molecular formula of acetic acid (ethanoic acid) is …………
(a) HCOOH
(b) CH3COOH
(c) C2H5COOH
(d) C3H7COOH
Answer:
The molecular formula of acetic acid (ethanoic acid) is CH3COOH.

Question 21.
When sodium bicarbonate solution is added to dilute acetic acid …………
(a) a gas is evolved
(b) a solid settles at the bottom
(c) the mixture becomes warm
(d) the colour of the mixture becomes yellow
Answer:
When sodium bicarbonate solution is added to dilute acetic acid a gas-is evolved.

Question 22.
2 ml of ethanoic acid was taken in each of test tubes A, B, C and 2 ml, 4 ml, 6 ml of water was added respectively to them. A clear solution is obtained in ………..
(a) test tube A
(b) test tube B
(c) test tube C
(d) all the test tubes
Answer:
2 ml of ethanoic acid was taken in each of test tubes A, B, C and 2 ml, 4 ml, 6 ml of water was added respectively to them. A clear solution is obtained in all the test tubes.

Question 23.
In the presence of acid catalyst, ethanoic acid reacts with ethanol and ……….. ester is produced.
(a) ethanol
(b) ethanoic
(c) ethyl ethanoate
(d) ethyl ethanol (Practice Activity Sheet – 1)
Answer:
In the presence of acid catalyst, ethanoic acid reacts with ethanol and ethyl ethanoate ester is produced.

Question 24.
The following structural formula belongs to which carbon compound?
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 69
(a) Camphor
(b) Benzene
(c) Starch
(d) Glucose (Practical activity sheet- 2)
Answer:
(b) Benzene

Question 25.
What type of reaction is shown below?
\(\mathrm{CH}_{4}+\mathrm{Cl}_{2} \stackrel{\text { Sunlight }}{\longrightarrow} \mathrm{CH}_{3}-\mathrm{Cl}+\mathrm{HCl}\)
(a) Addition
(b) Substitution
(c) Decomposition
(d) Reduction (Practice Activity Sheet – 3)
Answer:
(b) substitution

Question 26.
The carbon compound is used in daily life is ………..
(a) edible oil
(b) salt
(c) carbon dioxide
(d) baking soda (March 2019)
Answer:
The carbon compound is used in daily life is edible oil

State whether the following statements are true or false. (If a statement is false, correct it and rewrite it.):

Question 1.
Generally the melting and boiling points of carbon compounds are high.
Answer:
False. (Generally the melting and boiling points of carbon compounds are low.)

Question 2.
Till now the number of known carbon compounds is about 10 million.
Answer:
True.

Question 3.
Unsaturated hydrocarbons are less reactive than saturated hydrocarbons.
Answer:
False. (Unsatured hydrocarbons are more reactive than saturated hydrocarbons.)

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 4.
Benzene is an aromatic compound.
Answer:
True.

Question 5.
The carbon-carbon double and triple bonds are also recognised as functional groups.
Answer:
True.

Question 6.
The general formula of alkyne is CnH2n.
Answer:
False. (The general formula of alkyne is CnH2n – 2)

Question 7.
Naphthalene burns with a yellow flame.
Answer:
True.

Question 8.
When vegetable oil and tincture iodine react, the color of iodine does not change.
Answer:
False. (When vegetable oil and tincture iodine react, the colour of iodine changes.)

Question 9.
Saturated fats are healthy.
Answer:
False. (Saturated fats are harmful to health.)

Question 10.
Aqueous solution of ethanol is found to be neutral.
Answer:
True.

Question 11.
Denatured ethanol is used as industrial solvent.
Answer:
True.

Question 12.
Vinegar is a 12-15 % aqueous solution of acetic acid.
Answer:
False. (Vinegar is a 5-8 % aqueous solution of acetic acid.)

Question 13.
The functional group of ethanoic acid is a carboxylic group.
Answer:
True.

Question 14.
Sodium hydroxide is used in the preparation of soap from fats and oils.
Answer:
True.

Question 15.
Rubber is a manmade macromolecule.
Answer:
False. (Rubber is a natural macromolecule.)

Question 16.
Polyvinyl chloride is used in the manufacture of P.V.C. pipes and bags.
Answer:
True.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 17.
Polyethylene is a homopolymer.
Answer:
True.

Question 18.
The chemical bonds in carbon compounds do not produce ions.
Answer:
True.

Find the odd one out:

Question 1.
Propane, methane, ethene, pentane
Answer:
Ethene. (Others are saturated hydrocarbons.)

Question 2.
Methane, butane, benzene, sodium chloride
Answer:
Sodium chloride. (Others are organic compounds.)

Question 3.
CH4, C2H6, C3H8, CaCO3
Answer:
CaCO3. (Others are organic compounds.)

Question 4.
C2H2, C3H8, C2H6, CH4
Answer:
C2H2. (Others are saturated hydrocarbons.)

Question 5.
C2H4, C4H10, C3H8, CH4
Answer:
C2H4. (Others are saturated hydrocarbons.)

Question 6.
Polyethylene, Polysaccharide, Polystyrene, Polypropylene
Answer:
Polysaccharide (Others are manmade polymers.)

Question 7.
-NH2, -COOH,-SO4, -Br
Answer:
-SO4 (Others are functional groups.)

Question 8.
Methane, Ethane, Propene, Propane, Butane
Answer:
Propene (Others are members of homologous series of alkanes.)

Match the columns:

Question 1.

Column I Column II
(1) CH4 (a) CH2 = CH2
(2) Ethane (b) CnH2n – 2
(3) Alkene (c) Methane
(4) Alkyne (d) C2H6
(e) C3H8

Answer:
(1) CH4 – Methane
(2) Ethane – C2H6
(3) Alkene – CH2 = CH2
(4) Alkyne – CnH2n – 2.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 2.

Column I Column II
(1) Aromatic hydrocarbon (a) Propyne
(2) Alkane (b) Benzene
(3) Alkyne (c) Saturated hydrocarbon
(4) Alkene (d) CnH2n
(e) C n H2n – 1 OH

Answer:
(1) Aromatic hydrocarbon – Benzene
(2) Alkane – Saturated hydrocarbon
(3) Alkyne – Propyne
(4) Alkene – CnH2n.

Question 3.

Column I Column II
(1) Cyclohexane (a) CH3COOH
(2) Methanol (b) CH3Cl
(3) Acetaldehyde (c) CH2Cl2
(4) Ethanoic acid (d) CH3OH
(e) C6H12
(f) CH3CHO

Answer:
(1) Cyclohexane – C6H12
(2) Methanol – CH3OH
(3) Acetaldehyde – CH3CHO
(4) Ethanoic acid – CH3COOH.

Question 4.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 70
Answer:
(1) (-OH) – Alcohol
(2) (-COOH) – Carboxylic acid
(3) (-CHO) – Aldehyde
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 71

Question 5.

Column I Column II
(1) Ethyne (a) C2H6
(2) Ethene (b) C2H2
(3) Ethane (c) C3H6
(4) Propyne (d) C2H4
(e) C3H4

Answer:
(1) Ethyne – C2H2
(2) Ethene – C2H4
(3) Ethane – C2H6
(4) Propyne – C3H4.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 6.

Column I Column II
(1) Cellulose (a) P.V.C. pipes, bags
(2) R.N.A (b) Blankets
(3) Polyacrylonitrile (c) Wood
(4) Polyvinyl chloride (d) Chromosomes of plants

Answer:
(1) Cellulose – Wood
(2) R.N.A. – Chromosomes of plants
(3) Polyacrylonitrile – Blankets
(4) Polyvinyl chloride – P.V.C. pipes, bags.

Consider the relation between Column I and II. Fill in Column IV to match Column III.

Column I Column II Column III Column IV
(1) Ethylene Polyethylene Tetrafluoroethylene —————–
(2) Poly­propylene Propylene Polystyrene —————–
(3) Poly­saccharide Glucose Proteins —————–
(4) Rubber Isoprene D.N.A. —————–
(5) Wood Cellulose Chromosomes of plants —————–

Answer:
(1) Teflon
(2) Styrene
(3) Alpha aminoacid
(4) Nucleotide
(5) R.N.A.

Define the following:

Question 1.
Define Alkane
Answer:
Alkane: In hydrocarbon, the four valencies of carbon atom are satisfied only by the single bonds, such compounds are called alkane.
Example: Methane (CH4), Ethane (C2H6)

Question 2.
Define Alkene.
Answer:
Alkene: The unsaturated hydrocarbons containing a carbon-carbon double bond are called alkenes.
Example : Ethene (CH2 = CH2)

Question 3.
Define Alkyne.
Answer:
Alkyne: The unsaturated hydrocarbons containing a carbon-carbon triple bond are called alkynes.
Example: Ethyne C2H2 (CH ≡ CH).

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 4.
Define Addition reaction.
Answer:
Addition reaction: When a carbon compound combines with another compound to form a product that contains all the atoms in both the reactants; it is called an addition reaction.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 72

Question 5.
Define Substitution reaction.
Answer:
Substitution reaction: The reaction in which the place of one type of atom/group in a reactant is taken by another atom/group of atoms, is called substitution reaction.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 73

Question 6.
Define Esterification.
Answer:
Esterification: A carboxylic acid reacts with an alcohol in presence of an acid catalyst, an ester is formed. The reaction is known as esterification.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 74

Question 7.
Define Saponification.
Answer:
Saponification: When an ester reacts with the alkali, i.e. sodium hydroxide, the corresponding alcohol and sodium salt of carboxylic acid are obtained. This reaction is called saponification reaction. It is used in the preparation of soap.
Ester + Sodium hydroxide → Sodium salt of carboxylic acid + Alcohol.

Question 8.
Define Polymerization.
Answer:
Polymerization: The reaction by which monomer molecules are converted into a polymer is called polymerization.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 75

Name the following:

Question 1.
The higher homologue of hexane.
Answer:
Keptane.

Question 2.
The number of double bonds in benzene.
Answer:
Three.

Question 3.
The functional group in ether and halogen.
Answer:
Functional groups:
Ether: – O –
Halogen: – X (-Cl, -Br, -I).

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 4.
Polymer of tetrafluoroethylene.
Answer:
Teflon.

Question 5.
The monomer of polysaccharide.
Answer:
Glucose.

Question 6.
The Polymer of nucleotide.
Answer:
D.N.A./R.N.A.

Question 7.
The Monomer of rubber.
Answer:
Isoprene.

Question 8.
Two oxidising compounds.
Answer:
Potassium permanganate, Potassium dichromate.

Question 9.
IUPAC name of sodium acetate.
Answer:
Sodium ethanoate.

Question 10.
The main component of natural gas.
Answer:
Methane.

Question 11.
Two isomers of butane.
Answer:
n-butane and i-butane.

Question 12.
A nomenclature system based on the structure of the compounds and it was accepted all over the world.
Answer:
International Union of Pure and Applied Chemistry (IUPAC).

Answer the following questions in one sentence each:

Question 1.
State the atomic number and electronic configuration of carbon.
Answer:
The atomic number of carbon is 6 and the electronic configuration of carbon is (2, 4).

Question 2.
State number of electrons in the outermost orbit of carbon and valency of carbon.
Answer:
Four electrons are present in the outermost orbit of carbon and the valency of carbon is 4.

Question 3.
What are hydrocarbons? Give one example.
Answer:
The compounds containing only carbon and hydrogen are called hydrocarbons. These compounds are known as organic compounds. E.g. Methane, Ethane.

Question 4.
What is the molecular formula and structural of methane?
Answer:
The molecular formula of methane is CH4.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 76

Question 5.
How many atoms of carbon and hydrogen are present in methane?
Answer:
The molecule of methane has one carbon atom and four hydrogen atoms.

Question 6.
State the general formula of alkane.
Answer:
The general formula of an alkane is CnH2n + 2.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 7.
Give two examples of alkanes.
Answer:
Methane (CH4) and ethane (C2H6) are alkanes.

Question 8.
Give two examples of alkenes.
Answer:
Ethene (CH2 = CH2) and propene (CH3 – CH = CH2) are alkenes.

Question 9.
Give two examples of alkynes.
Answer:
Ethyne (HC ≡ CH) and propyne (CH3 – C ≡ CH) are alkynes.

Question 10.
Write the name and molecular formula of a higher homologue of propane.
Answer:
Butane (C4H10) is a higher homologue of propane.

Question 11.
Write the structure and molecular formula of ethane.
Answer:
Structure of ethane:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 77
Molecular formula of ethane: C2H6

Question 12.
What is meant by catenation power?
Answer:
Carbon has a unique ability to form strong covalent bonds with other carbon atoms, this result in formation of big molecules. This property of carbon is called catenation power.

Question 13.
State the structural and molecular formula of benzene.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 78

Question 14.
Which functional groups are present in aldehyde and ketone?
Answer:
The functional group -CHO is present in aldehyde and the functional group
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 79
is present in ketone.

Question 15.
Which functional group is present in
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 80
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 81

Question 16.
Compare: The proportions of carbon atoms in ethanol (C2H5OH) and naphthalene (C10H8).
Answer:
Ethanol contains two carbon atoms while naphthalene contains 10 carbon atoms. Ethanol is a saturated hydrocarbon and naphthalene is an unsaturated hydrocarbon.

Question 17.
What are the products of combustion of methane?
Answer:
Carbon dioxide (CO2) and water (H2O) are the products of combustion of methane.

Question 18.
Which gas is evolved when ethanol reacts with sodium?
Answer:
Hydrogen gas (H2) is evolved when ethanol reacts with sodium.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 19.
Compare: How is the transformation of ethanol into ethanoic acid on oxidation reaction?
Answer:
The transformation of ethanol into ethanoic acid is an oxidation process, in which ethanol accepts oxygen.

Question 20.
Complete the following:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 82
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 83

Question 21.
Which of the following hydrocarbons undergo addition reactions:
C2H6, C3H8, C2H4, C3H8?
Answer:
C2H4 (ethene) and C3H6 (propene) undergo addition reactions.

Question 22.
How many covalent bonds are there in a molecule of cyclohexane?
Answer:
A molecule of cyclohexane contains 18 covalent bonds.

Question 23.
Give the IUPAC name for CH3COOH.
Answer:
The IUPAC name for CH3COOH is ethanoic acid.

Question 24.
Write the IUPAC name of CH3COONa.
Answer:
IUPAC name of CH3COONa is sodium ethanoate.

Question 25.
What is meant by denatured alcohol?
Answer:
Ethanol is the important commercial solvent. To prevent the misuse of this solvent, it is mixed with the poisonous methanol. Such ethanol is called denatured spirit.

Question 26.
What is meant by glacial acetic acid ?
Answer:
The melting point of pure acetic acid is 17 °C. Therefore, during winter in old countries acetic acid freezes at room temperature itself and looks like ice. Therefore it is named glacial acetic acid.

Question 26.
Which useful components of hydro¬carbon are obtained by fractional distillation of crude oil?
Answer:
Various useful components of hydrocarbon such as CNG, LPG, petrol (gasoline), rockel, diesel, engine oil, lubricant, etc. are obtained by separation of crude oil using fractional distillation.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 28.
Which functional groups are present in ester and amine?
Answer:
Ester: -COO-
Amine: -NH2

Question 29.
Give two examples of natural macromolecules.
Answer:
Examples: Polysaccharide, protein and nucleic acid.

Question 30.
Write the structure of polystyrene and give its uses.
Answer:
Structure:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 84
Polystyrene is used to make thermocoal articles.

Question 31.
Write the name and the structure of monomer of polyacrylonitrile.
Answer:
The name and structure of monomer: Acrylonitrile CH2 = CH – CN

Question 32.
Write the name and the structure of monomer of teflon and its uses.
Answer:
The name and structure of monomer: Tetrafluro ethylene CF2 = CF2
Teflon is used to make nonstick cookware.

Question 33.
What is meant by copolymers?
Answer:
The polymers formed from two or more monomers are called copolymers.
Examples: Poly ethylene terephthalate.

Answer the following questions:

Question 1.
How is hydrogen molecule formed?
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 85
The atomic number of hydrogen is 1, its atom contains 1 electron in K shell. It requires one more electron to complete the K shell and attain the configuration of helium (He). To meet this requirement two hydrogen atoms share their electrons with each other to form H2 molecule. One covalent bond, i.e. a single bond is formed between two hydrogen atoms by sharing of two electrons.

Question 2.
Describe the formation of oxygen molecule (O2).
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 86
(1) The atomic number of oxygen is 8. The electronic configuration of oxygen is (2, 6). Oxygen has 6 electrons in the outermost shell.
(2) It requires 2 electrons to complete the L shell and attain the configuration of neon (Ne).
(3) Each oxygen atom shares its valence electron with the valence electron of another oxygen atom to give two shared pairs of electrons which results in the formation of oxygen molecule.
(4) Thus, two electron pairs are shared between two oxygen atoms, forming double covalent bond (=).

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 3.
Describe the formation of nitrogen molecule.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 87
(1) The atomic number of nitrogen is 7. The electronic configuration of nitrogen is (2, 5). Nitrogen has 5 electrons in the outermost shell.
(2) It requires three more electrons to complete the L shell and attain the configuration of neon (Ne).
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 88
(3) Two nitrogen atoms come close together and share three pairs of electrons with each other, resulting in the formation of a triple bond.
(4) Thus, two nitrogen atoms are bound with a triple bond (=) to form a nitrogen molecule.

Question 4.
How is the methane molecule formed?
Answer:
(1) The electronic configuration of carbon is (2, 4). Carbon has four electrons in the outermost shell, hence it is tetravalent.
(2) The electronic configuration of hydrogen is 1, hence it is monovalent.
(3) Carbon needs four electrons to complete the L shell and attain the configuration of neon (Ne).
(4) Four atoms of hydrogen share 1 electron each with 4 electrons of carbon.
(5) A single covalent bond is formed by sharing of two electrons.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 89
Thus, the methane molecule contains four single bonds between the carbon and hydrogen atoms.

Question 5.
State the various compounds and its formulae formed by a single atom of carbon with monovalent hydrogen and chlorine.
Answer:

Compounds Names
CH4 Methane
CH3Cl Methyl chloride
CH2Cl2 Methylene dichloride
CHCl3 Methylene trichloride
CCl4 Carbon tetrachloride

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 6.
Observe the straight chain hydrocarbons given below and answer the following questions:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 90
(i) Which of the straight chain compounds from A and B is saturated and unsaturated straight chains?
(ii) Name these straight chains.
(iii) Write their chemical formulae and number of -CH2 units. (Practice Activity Sheet – 2)
Answer:
(i) A is a saturated hydrocarbon, B is an unsaturated hydrocarbon.
(ii) A = Propane, B = Propene
(iii) The chemical formula of A = C3H8 and number of -CH2 units are 3.
The chemical formula of B = C3H6 and number of -CH2 unit is 1.

Question 7.
Draw electron-dot and line structure of an ethane molecule.
Answer:
The molecular formula of ethane is C2H6.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 91

Question 8.
The molecular formula of propane is C3H8. From this draw its structural formula. (Practice Activity Sheet – 3)
Answer:
The structural formula of propane:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 92

Question 9.
Draw the structure and carbon skeleton for cyclohexane.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 93

Question 10.
Classify into saturated and unsaturated hydrocarbons: (1) Methane (2) Ethene (3) Ethane (4) Ethyne (5) Propene (6) Propyne (7) Butane (8) Cyclohexene (9) Cyclopentane (10) Heptane.
Answer:
(i) Saturated hydrocarbons: (1) Methane (2) Ethane (3) Butane (4) Cyclopentane (5) Heptane.
(ii) Unsaturated hydrocarbons: (1) Ethene (2) Ethyne (3) Propene (4) Propyne (5) Cyclohexene.

Question 11.
Classify into alkanes, alkenes and alkynes: (1) Ethane (2) Ethene (3) Methane (4) Propene (5) Ethyne (6) Propyne (7) Butane (8) Pentane.
Answer:
Alkanes: (1) Ethane (2) Methane (3) Butane. (4) Pentane
Alkenes: (1) Ethene (2) Propene
Alkynes: (1) Ethyne (2) Propyne

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 12.
Classify into straight chain carbon compounds, branched chain carbon compounds and ring carbon compounds:
(1) Propene (2) Butane (3) Iso-butane (4) Cyclopentane (5) Benzene (6) Isobutylene.
Answer:
Straight chain carbon compounds:

  1. Propene
  2. Butane.

Branched chain carbon compounds:

  1. Iso-butane
  2. Isobutylene.

Ring carbon compounds:

  1. Cyclopentane
  2. Benzene.

Question 13.
Draw chain and ring structures of organic compound having six carbon atoms in it.
Answer:
Chain structures of an organic compound having six carbon atoms:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 94
Ring structures of an organic compound having six carbon atoms:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 95

Question 14.
Explain the structure of benzene.
Answer:
The molecular formula of benzene is C6H6. It is a cyclic unsaturated hydrocarbon. Benzene ring is made of six carbon atoms. In benzene, each carbon atom is linked to two other carbon atoms, on one side by a single bond and on the other side by a double bond, i.e. three alternate single bonds and double bonds in the six membered ring structure of benzene. The compound having this characteristic unit in their structure are called aromatic compounds.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 96

Question 15.
Draw the structures of isomers of pentane (C5H12).
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 97

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 16.
Recognize the carbon chain type for each of the following:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 98
(Practice Activity Sheet – 1)
Answer:
In the reaction of acetic acid with sodium carbonate, carbon dioxide gas is evolved which turns lime water milky resulting in the formation of insoluble calcium carbonate.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 99

Question 17.
What is meant by functional group? Give examples.
(OR)
Explain the term functional group with example.
Answer:
The compound acquire specific chemical properties due to these hetero atoms or the groups of atoms that contain hetero atoms, irrespective of length and nature of the carbon chain in that compound. Therefore these hetero atoms or groups of atoms containing hetero atoms are called the functional groups.
Example: Methyl alcohol, acetic acid.

In methane (CH4), when one hydrogen atom is replaced by an -OH group, methyl alcohol (CH3OH), is formed. The -OH is known as the alcoholic functional group.
Similarly, from methane (CH4) when one hydrogen atom is replaced by -COOH group, acetic acid (CH3COOH) is formed. The -COOH group is known as the carboxylic acid functional group.

Question 18.
Define functional group and complete the following table:

Functional group Compound Formula
——————– Ethyl alcohol ——————–
——————– Acetaldehyde ——————–

Answer:
The compound acquire specific chemical properties due to these hetero atoms or the groups of atoms that contain hetero atoms, irrespective of length and nature of the carbon chain in that compound. Therefore these hetero atoms or groups of atoms containing hetero atoms are called the
functional groups.

Functional group Compound Formula
-OH Ethyl alcohol C2H5OH
-CHO Acetaldehyde CH3CHO

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 19.
What is meant by homologous series?
Answer:
The length of the carbon chains in carbon compounds is different their chemical properties are very much similar due to the presence of the same functional group in them. The series of compounds formed by joining the same functional group in place of a particular hydrogen atom on the chains having sequentially increasing length is called homologous series. Two adjacent members of the series differ by only one -CH2– (methylene) unit and their mass differ by 14 units.

The homologous series of straight chain alkanes can be represented by the general formula CnH2n + 2. The members of this series are as follows:

Methane – CH4
Ethane – C2H6
– These differ by – CH2 units
Ethane – C2H6
Propane – C3H8
– These differ by – CH2 units
Butane – C4H10
Pentane – C5H12
– These differ by – CH2 units

Question 20.
State the four characteristics of homologous series.
Answer:
Characteristics of Homologous series:
(1) In homologous series while going in an increasing order of the length of carbon chain
(a) one methylene unit ( -CH2– ) gets added
(b) molecular mass increases by 14 u (c) number of carbon atoms increases by one.
(2) Chemical properties of members of a homologous series show similarity due to the presence of the same functional group in them.
(3) Each member of the homologous series can be represented by the same general molecular formula.
(4) While going in an increasing order of the length there is gradation in the physical properties i.e. the boiling and melting points.

Question 21.
Write names of first four homologous series of alcohols: (March 2019)
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 100
Answer:
First four homologous series of alcohols are

  1. Methanol CH3 – OH
  2. Ethanol C2H5 – OH
  3. Propanol C3H7 – OH
  4. Butanol C4H9 – OH

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 22.
Describe the IUPAC rules of naming organic compounds.
Answer:
IUPAC nomenclature system: International Union for Pure and Applied Chemistry (IUPAC) put forth a nomenclature system based on the structure of the compounds and it was accepted all over the world. There are three units in the IUPAC name of any carbon compound: parent, suffix and prefix. These are arranged in the name as follows:

Prefix-parent-suffix:
An IUPAC name is given to a compound on the basis of the name of its parent alkane. The name of the compound is constructed by attaching appropriate suffix and prefix to the name of the parent-alkane. The steps in the IUPAC nomenclature of straight chain compounds are as follows:

Step 1: Draw the structural formula of the straight chain compound and count the number of carbon atoms in it. The alkane with the same number of carbon atoms is the parent alkane of the concerned compound. Write the name of this alkane.

In case the carbon chain of concerned compound contains a double bond, change the ending of the parent name from ‘ane’ to ‘ene’. If the carbon chain in the concerned compound contains a triple bond, change the ending of the parent name from ‘ane’ to ‘yne’.

Sr. No.

Structural formula Straight chain

Parent name

1. CH3 – CH2 – CH3 C – C – C propane
2. CH3 – CH2 – OH C – C ethane
3. CH3 – CH2 – COOH C – C – C propane
4. CH3 – CH2 – CH2 – CHO C – C – C – C butane
5. CH3 – CH = CH2 C – C = C propene
6. CH3 – C ≡ CH C – C ≡ C propyne

Step 2: If the structural formula contains a functional group, replace the last letter ‘e’ from the parent name by the condensed name of the functional group as the suffix. (Exception: The condensed name of the functional group ‘halogen’ is always attached as the prefix.)

Step 3: Number the carbon atoms in the carbon chain from one end to the other. Assign the number T to carbon in the functional group -CHO or -COOH, if present. Otherwise, the chain can be numbered in two directions. Accept that numbering which gives smaller number to the carbon carrying the functional group. In the final name, a digit (number) and a character (letter) should be separated by a small horizontal line.

Question 23.
Write the IUPAC names of the following structural formulae.
a. CH3 – CH2 – CH = CH2
Answer:
Number of carbon atoms in the longest chain: 4
Parent alkane: Butene
Functional group: double bond
Assign the number:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 101

In the longest chain, the numbering of carbon atom starts from the carbon atom nearest to the double bond and the other c-atoms are numbered accordingly.
Parent suffix: But-1-ene
IUPAC name: But-1-ene

b. CH3 – C ≡ C – H
Answer:
Number of carbon atoms in the longest chain: 3
Parent alkane: Propyne
Functional group: triple bond
Parent suffix: Propyne
IUPAC name: Propyne

c.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 102
Answer:
The number of carbon atoms in the longest chain: 5
Parent alkane: Pentane
Prefix functional group: Chloro
Assign the number: 2
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 103
The carbon atom to which the -Cl atom is attached is numbered as C2 and the other C atoms are numbered accordingly.
Prefix parent: 2-Chloropentane
IUPAC name: 2-Chloropentane

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

d. CH3 – CH2 – CH2 – Br
Answer:
The number of carbon atoms in the longest chain: 3
Parent alkane : Propane Prefix functional group: Bromo
Assign the number:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 104
The carbon atom to which the -Br atom is attached is numbered as C1 and the other C atoms are numbered accordingly.
Prefix parent: 1-Bromopropane
IUPAC name: 1-Bromopropane

e.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 105
Answer:
The number of carbon atoms in the longest chain: 4
Parent alkane: Butane Functional group: -OH (ol)
Assign the number:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 106
The carbon atom to which the -OH group is attached is numbered as C2.
If the carbon chain of the compound contains a -OH group, then change the ending ‘e’ of the parent name, i.e. ,‘e’ of butane is replaced by ‘ol’ (ol for alcohol).
Parent suffix: Butan-2-ol
IUPAC name: Butan-2-ol

f.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 107
The number of carbon atoms: 3
Parent alkane: Propane
Functional group: -NH2 (amine)
Assign the number:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 108
If the carbon chain of the compound contains a -NH2 group then change the ending of the parent name, i.e. ‘e’ of propane is replaced by ‘amine’.
Parent suffix: 2-Propanamine
IUPAC name: 2-Propanamine

g. HCOOH
Answer:
The number of carbon atoms: 1
Parent alkane: Methane
Functional group: -COOH (-oic cid)
If the carbon chain of the compound contains a -COOH group, then change the ending of the parent name, i.e. ‘e’ of methane is replaced by ‘-oic acid’.
Parent suffix: Methanoic acid
IUPAC name: Methanoic acid

h. CH3 – CH2 – CH2 – CHO
Answer:
The number of carbon atoms in the longest chain: 4
Parent alkane : Butane Functional group: -CHO (al)
Assign the number: 1
Assign the number ‘1’ to carbon in the functional group
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 109
If the carbon chain of the compound contains a -CHO group then change the ending of the parent name, i.e. ‘e’ of the butane is replaced by ‘al’.
Parent suffix: Butanal
IUPAC name: Butanal

i.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 110
Answer:
The number of carbon atoms in the longest chain: 5
Parent alkane: Pentane
Functional group:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 111
Assign the numbering:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 112
In the longest chain, the numbering of carbon atom starts from the carbon nearest to the functional group (both the numbering equivalent).
If the carbon chain of compound contains a
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 113
group, then change the ending of the parent name i.e. ‘e’ of pentane is replaced by ‘one’.
Parent suffix: Pentan-3-one
IUPAC name: Pentan-3-one.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 24.
What happens when methane is burnt in air? Write the balanced chemical equation for the same.
Answer:
When methane burns in air, carbon dioxide and water are formed. The reaction is exothermic with release of large amount of heat and light.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 114

Question 25.
What happens when ethanol is burnt in air?
Answer:
When ethanol is burnt in air, it burns with a clean blue flame, carbon dioxide and water are formed. In this reaction, release of large amount of heat and light takes place.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 115

Question 26.
What happens when ethanol is treated with alkaline potassium permanganate? Write the balanced chemical equation for the same.
Answer:
When ethanol is treated with alkaline potassium permanganate, ethanol gets oxidised by alkaline potassium permanganate to’ form ethanoic acid.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 116

Question 27.
What happens when vegetable oil is hydrogenated? Write the balanced chemical equation.
Answer:
When vegetable oil (unsaturated compound) is hydrogenated in the presence of nickel catalyst, vanaspati ghee (saturated) compound is formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 117

Question 28.
What happens when chlorine is treated with methane?
(OR)
Describe the action of chlorine on methane.
(OR)
Write a note on chlorination of methane.
Answer:
Methane reacts rapidly with chlorine in the presence of sunlight to form four products. In this reaction, chlorine atoms replace, one by one, all the hydrogen atoms in the methane.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 118
The reaction in which the place of one type of atom/group in a reactant is taken by another atom/group of atoms is called substitution reaction. Chlorination of methane is a substitution reaction.

Question 29.
What happens when ethanol is reacted with sodium?
Answer:
When ethanol is reacted with sodium at room temperature, sodium ethoxide is formed and hydrogen gas is liberated.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 119

Question 30.
What happens when ethanol is heated at 170 °C with excess of conc. sulphuric acid?
Answer:
When ethanol is heated at 170 °C with excess of conc. sulphuric acid, one molecule of water is removed from its molecule to form ethene (unsaturated compound).
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 120

Question 31.
What happens when ethanoic acid is treated with sodium hydroxide? Write the balanced equation for the same.
Answer:
When ethanoic acid is treated with sodium hydroxide, neutralization takes place to form sodium acetate (sodium ethanoate) and water.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 121

Question 32.
What happens when ethanoic acid is treated with sodium carbonate?
Answer:
When ethanoic acid is treated with sodium carbonate, sodium ethanoate, carbon dioxide and water is formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 112

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 33.
What happens when ethanoic acid is treated with sodium bicarbonate?
Answer:
When ethanoic acid is treated with sodium bicarbonate, sodium ethanoate, water and carbon dioxide is formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 123

Question 34.
What happens when ethanoic acid is treated with ethanol? Write the balanced equation for the same.
Answer:
When ethanoic acid is treated with ethanol in the presence of an acid catalyst, an ester, i.e., ethyl ethanoate is formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 124

Question 35.
What happens when ethylene gas is heated at high pressure and high temperature in the presence of suitable catalyst?
Ans. When ethylene gas is heated at high pressure and high temperature in the presence of suitable catalyst, it polymerizes to form polyethylene or polythene (plastic).
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 125

Question 36.
State the physical properties of ethyl alcohol ethanol.
Answer:

  1. Ethanol is a colourless liquid and it is soluble in water in all proportions and has pleasant odour.
  2. The boiling point of ethanol is 78 °C and the freezing point is -114 °C.
  3. It is combustible and burns with a blue flame.
  4. An aqueous solution of ethanol is neutral to litmus paper.

Question 37.
State the properties of ethanoic acid.
Answer:

  1. Ethanoic acid is a colourless liquid with boiling point 118 °C and melting point 17 °C. It has a pungent odour.
  2. Its aqueous solution is acidic and turns blue litmus red.
  3. A 5-8% aqueous solution of acetic acid is used as vinegar.
  4. It is a weak acid.

Write short notes:

Question 1.
Catenation power.
Answer:
(1) Carbon has a unique ability to form strong covalent bonds with other carbon atoms; this results in formation of big molecules. This property of carbon is called catenation power.

(2) Carbon shows catenation. Two or more carbon atoms can share their valence electrons and bond with each other. Thus, carbon chains can be straight or branched or closed chain ring structure forming large molecules. The covalent bond between two carbon atoms is strong and therefore stable. Carbon is bestowed with catenation power due to the strong and stable covalent bonds.

(3) Hence, carbon atoms can form an unlimited number of compounds.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 126

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 2.
Characteristics of Carbon.
Answer:
(1) Carbon has a unique ability to form strong covalent bonds with other carbon atoms: this results in formation of big molecules. This property of carbon is called catenation power. The carbon compounds contain open chains or closed chains of carbon atoms. An open chain can be a straight chain or a branched chain. A closed chain is a ring structure. The covalent bond between two carbon atoms is strong and therefore stable. Carbon is bestowed with catenation power due to the strong and stable covalent bonds.

Question 3.
Functional group.
Answer:
(1) The compound acquire specific chemical properties due to these hetero atoms or the groups of atoms that contain hetero atoms, irrespective of the length and nature of the carbon chain in that compound. Therefore these hetero atoms or the groups of atoms containing hetero atoms are called functional groups.

All organic compounds are derivatives of hydrocarbons. The derivatives are formed by replacing one or more H-atom/atoms of hydrocarbon by some other hetero atom or groups of atoms containing hetero atoms. After replacement, a new compound is formed which has properties different from the parent hydrocarbon.

Examples: For methane, if one hydrogen atom is replaced by an – OH group, then a compound is methyl alcohol (CH3OH). The -OH group is known as the alcoholic functional group.
Functional group is organic compound:
1. Alcohol: – OH (hydroxy group)
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 127
4. Carboxylic acid : -COOH

Question 4.
Homologous series.
Answer:
The length of the carbon chains in carbon compounds is different their chemical properties are very much similar due to the presence of the same functional group in them. The series of compounds formed by joining the same functional group in place of a particular hydrogen atom on the chains having sequentially increasing length is called homologous series. Two adjacent members of the series differ by only one -CH2– (methylene) unit and their mass differ by 14 units.

The homologous series of straight chain alkanes can be represented by the general formula CnH2n + 2
The members of this series are as follows:

Methane – CH4
Ethane – C2H6
– These differ by – CH2 units
Ethane – C2H6
Propane – C3H8
– These differ by – CH2 units
Butane – C4H10
Pentane – C5H12
– These differ by – CH2 units

Characteristics:
(1) In homologous series while going in an increasing order of the length of carbon chain
(a) one methylene unit (-CH2-) gets added
(b) molecular mass increases by 14 u
(c) number of carbon atoms increases by one.
(2) Chemical properties of members of a homologous series show similarity due to the presence of the same functional group in them.
(3) Each member of the homologous series can be represented by the same general molecular formula.
(4) while going in an increasing order of the length there is gradation in the physical properties i.e., the boiling and melting points.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Question 5.
Polymerization.
Answer:
(1) The reaction by which monomer molecules are converted into a polymer is called polymerization. A macromolecule formed by regular repetition of a small unit is called polymer. The small unit that repeats regularly to form a polymer is called monomer. The important method of polymerization is to make a polymer by joining alkene type of monomers.

(2) When ethylene gas is heated at high pressure and high temperature in the presence of suitable catalyst, it polymerizes to form polyethylene or polythene (plastic).
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds 128

(3) The polymer polystyrene is used to make thermocoal articles. The polymer polyvinyl chloride is used to make P.V.C. pipes, doormats, etc. The polymer teflon is used to make nonstick cookware. The polymer polypropylene is used to make injection syringe, furniture, etc.

Give scientific reasons:

Question 1.
Carbon atoms are capable of forming an unlimited number of compounds.
Answer:

  1. Carbon has the property of catenation. Two or more carbon atoms can share some of their valence electrons to form (single, double and triple) bonds.
  2. The straight chains or branched chains or rings may have different shapes and sizes. This results in formation of many compounds. Hence, carbon atoms are capable of forming an unlimited number of compounds.

Question 2.
Ethylene is an unsaturated hydrocarbon.
Answer:
(1) Ethylene (CH2 = CH2) contains a double bond between carbon atoms.
(2) Thus, the valencies of the two carbon atoms are not fully satisfied by single covalent bonds. Hence, ethylene is an unsaturated hydrocarbon.

Question 3.
Naphthalene burns with a yellow flame.
Answer:
(1) Naphthalene is an unsaturated compound. In unsaturated hydrocarbon the proportion of carbon is larger than that of saturated hydrocarbon. As a result, some unburnt carbon particles are also formed during combustion of unsaturated compounds.

(2) In the flame. these unburnt hot carbon particles emit yellow light and therefore the flame appears yellow. Hence, naphthalene burns with a yellow flame.

Question 4.
The colour of iodine disappears in the reaction between vegetable oil and iodine.
Answer:
(1) Vegetable oils (unsaturated compound) contains a multiple bond as their functional group. They undergo addition reaction to form a saturated compound as the product.
(2) The addition reaction of vegetable oil with iodine takes place instantaneously at room temperature. The colour of iodine disappears in this reaction. This iodine test indicates the presence of a multiple bond in vegetable oil.

Question 5.
The hydrogenation of vegetable oil in the presence of nickel catalyst forms vanaspati ghee.
Answer:
(1) The molecules of vegetable oil contain long and unsaturated carbon chains. These unsaturated hydrocarbons contain a multiple bond as their functional group. They undergo addition reaction to form a saturated compound as the product.

(2) When vegetable oil (unsaturated compound) is hydrogenated in the presence of nickel catalyst, the addition reaction takes place, vanaspati ghee (saturated compound) is formed.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Distinguish between the following:

Question 1.
Saturated hydrocarbons and Unsaturated hydrocarbons.
Answer:
Saturated hydrocarbons:

  1. In saturated hydrocarbons, the carbon atoms are linked to each other only by single covalent bonds.
  2. They contain only a single bond.
  3. They are chemically less reactive.
  4. Substitution reaction is a characteristic property of these hydrocarbons.
  5. Their general formula is CnH2n + 2.

Unsaturated hydrocarbons:

  1. In unsaturated hydrocarbons, the valencies of carbon atoms are not fully satisfied by single covalent bonds.
  2. They contain carbon to carbon double or triple bonds.
  3. They are chemically more reactive.
  4. Addition reaction is a characteristic property of these hydrocarbons.
  5. Their general formula is CnH2n or CnH2n – 2

Question 2.
Open chain hydrocarbons and closed chain hydrocarbons.
Answer:
Open chain hydrocarbons:

  1. A hydrocarbon in which the chain of carbon atoms is not cyclic is called an open chain hydrocarbon.
  2. All aliphatic hydrocarbons contain open chains.

Closed chain hydrocarbons:

  1. A hydrocarbon in which the chain of carbon atoms is present in a cyclic form or ring form is called a closed chain hydrocarbon.
  2. All aromatic hydrocarbons contain closed chains.

Question 3.
Alkane and Alkene.
Answer:
Alkane

  1. Alkanes in which the carbon atoms are linked to each other only by single bonds.
  2. The general formula of an alkane is CnH2n + 2
  3. They are chemically less reactive.

Alkene:

  1. Alkenes in which carbon atoms are linked to each other by double bonds.
  2. The general formula of an alkene is CnH2n.
  3. They are chemically more reactive.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 9 Carbon Compounds

Project:

Question 1.
Prepare a list of carbon compounds which occur in nature and discuss their uses in daily life.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology

Balbharti Maharashtra State Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology

Question 1.
Fill in the blanks and complete the statements.
a. Methods like artificial insemination and embryo transplant are mainly used for ………..
(a) animal husbandry
(b) wild life
(c) pet animals
(d) for infertile women
Answer:
(a) animal husbandry

b. ……….. is the revolutionary event in biotechnology after cloning.
(a) Human genome project
(b) DNA discovery
(c) Stem cell research
(d) All the above
Answer:
(c) Stem cell research

c. The disease related with the synthesis of insulin is …………..
(a) cancer
(b) arthritis
(c) cardiac problems
(d) diabetes
Answer:
(d) diabetes

d. Government of India has encouraged the ……….. for improving the productivity by launching NKM-16.
(a) aquaculture
(b) poultry
(c) piggery
(d) apiculture
Answer:
(a) aquaculture

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology

Question 2.
Match the pairs.

Column ‘A’ Column ‘B’
(1) Interferon (a) Diabetes
(2) Factor VIII * (b) Dwarfness
(3) Somatostatin (c) Viral infection
(4) Interleukin (d) Cancer
(e) Haemophilia

[Note: In examination match the column question will have 2 components in Column A’ with 4 alternatives in Column B’.]
Answer:
(1) Interferon – Viral infection
(2) Factor VIII – Haemophilia
(3) Somatostatin – Dwarfness
(4) Interleukin – Cancer
[Note: Factor VIII* is an important protein factor and it should not be just factor as given in the textbook.]

Question 3.
Rewrite the following wrong statements after corrections:
a. Changes in genes of the cells are brought about in non-genetic technique.
Answer:
Non-genetic biotechnology involves use of either cell or tissue.

b. Gene from Bacillus thuringiensis is introduced into soyabean.
Answer:
Gene from Bacillus thuringiensis is introduced with gene of cotton.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology

Question 4.
Write short notes.
a. Biotechnology: Professional uses. (Commercial uses)
Answer:
(1) Biotechnology can be used in the following professional fields, viz. crop biotechnology, animal husbandry, human health, etc.

(2) In crop biotechnology, improvement in the yield and variety of agricultural field is done. The hybrid seeds, genetically modified crops, herbicide tolerant plants are some of the areas in which lot of biotechnological research is being done. By such research, high yielding and disease resistant varieties and varieties which can tolerate stresses such as alkalinity, weeds, cold and drought etc. are produced. BT cotton, BT Brinjal and golden rice are some GMO plants which have become popular in India.

Due to herbicide tolerant plants, the weeds are now selectively destroyed. By using biofertilizers, the use of chemical fertilizers is reduced. Use of bacteria such as Rhizobium, Azotobacter, Nostoc, Anaixiena and plants like Azolla the nitrogen fixation and phosphate solubilization abilities of the plants are improved.

(3) Animal husbandry is now using the methods of artificial insemination and embryo transfer by which the breeds of cattle are improved.

(4) To improve and to manage the human health, diagnosis ahd treatment of diseases have to be focussed. Diagnosis of diabetes, heart diseases and infectious diseases such as AIDS and dengue can be done rapidly due to biotechnology.

(5) The treatment and prevention of diseases need hormones, interferons, antibiotics and different vaccine which are now manufactured through biotechnology. Gene therapy is also used to treat hereditary disorders.

(6) Industrial products and clean technology to combat environmental pollution uses biotechnology practices.

(7) DNA fingerprinting has revolutionized the profession of forensic science.

b. Importance of medicinal plants.
Answer:

  • In Ayurveda practices, the natural remedies were used. Since India had great biodiversity and traditional knowledge of herbal medicinal uses, therefore, people depended on such medicinal plants.
  • In olden days, such herbs were collected by roaming in the jungles.
  • Such important medicinal herbs are now cultivated with care.
  • In entire world people have understood the importance of holy basil (tulsi), Adulsa, Jyesthmadh, etc.
  • In some of the allopathy medicines too, the plant extracts are used.
  • Medicines made from harmful chemicals have side effects and are not safe to be used unless there is medical supervision. Therefore, world-wide herbal remedies are gaining more popularity.

Question 5.
Answer the following questions in your own words.
a. Which products produced through biotechnology do you use in your daily life?
Answer:

  • The simplest use of biotechnology that we practice at home is making curd and buttermilk.
  • The primary type of biotechnology is used in the process of fermentation while making food stuffs, like bread, idli-dosa, dhokla, etc.
  • Nowadays, different types of cheese, paneer, yoghurt, energy drinks, etc. are produced with the help of biotechnology. We are consuming these in our daily life.
  • Seedless grapes, papaya, and watermelons are available in the market these days.
  • Violet cabbage, yellow capsicum and exotic vegetables used for salad are also biotechnology products.
  • The vaccines, antibiotics and the injections of human insulin are in regular use in many house-holds.

b. Which precautions will you take during spraying of pesticides?
Answer:

  • Pesticides are toxic chemicals. By using them indiscriminately, they contaminate the water, soil and also crops.
  • The D.D.T., chloropyriphos and malathion are very dangerous. They spread through the food chain causing biomagnification.
  • Therefore, we shall not use such insecticides and pesticides. We shall use organic pesticides. Excessive use will be avoided.
  • At the time of spraying, nose, eyes and skin will be covered and protected.
  • Care will be taken not to allow children or domestic animals to come in, contact with a pesticide.

c. Why some of the organs in human body are most valuable?
Answer:

  • The body can be in best health,if all the vital organs of the body are also in the best condition.
  • Brain, kidney, heart, liver, etc. are some such vital organs which are most essential for proper metabolism and functioning of the body. The sense organs of the body are also of utmost importance, especially eyes.
  • One cannot survive if any of these vital organs are not functioning properly. Some of the organs like brain will never regenerate too.
  • Some of the organs can be brought back to functionality by performing surgeries. However, any problem with these vital organs make life miserable, therefore, they are said to be valuable.

d. Explain the importance of fruit processing in human life?
Answer:
(1) Fruits are perishable food stuff. They are spoilt soon if not consumed immediately. Hence for storage and usage for a long term, their preservation is absolutely essential.
(2) For year-long use of the fruits they are dried, salted, packed in air tight containers, used for preparing jams and jellies or condensed into pulps or syrups. Beverages, pickles, sauce, and various other products made from the fruits are largely used by us.
(3) The preserved products also fetch financial benefits.
(4) In national and international markets, Indian fruits like mangoes are in great demand. We can get foreign currency through exports of fruits and fruit products. The local horticulturists get good benefit from their orchards.
(5) Processed fruit products also give vitamins and minerals that help in maintaining good health. Thus fruit processing is important for human life.

e. Explain the meaning of vaccination.
Answer:

  • Vaccination is the administering of vaccine. Vaccine is the ‘antigen’, given to a person or even to animals for acquiring immunity against particular pathogens or diseases.
  • In olden days, vaccipes were prepared with the help of completely or partially killed pathogens. But this method causes some inconvenience. Some persons were allergic to such raw vaccines or they contracted the same disease through such vaccines.
  • Hence in recent times the vaccines are produced by using biotechnology. These vaccines are artificial which are synthesised in the laboratories.
  • The antigen is produced with the help of gene of the pathogen. Such vaccine becomes safe for administering.
  • These antigenic proteins are injected to people to make their immune systems strong. This process of vaccination is absolutely safe. The vaccines are more thermostable and active for a long period of time.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology

Question 6.
Complete the following chart.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology 1
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology 2

Question 7.
Write the correct answer in blank boxes.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology 3
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology 4

Question 8.
Identify and complete the following correlations:
a. Insulin : Diabetes : : Interleukin : …………….
Answer:
Insulin : Diabetes : : Interleukin : Cancer

b. Interferon : ………. : : Erythropoietin : Anaemia.
Answer:
Interferon : Viral infection : : Erythropoietin : Anaemia.

c. ……….. : Dwarfness : : Factor VIII : Haemophilia.
Answer:
Somatostatin : Dwarfness : : Factor VIII : Haemophilia.

d. White revolution : Dairy : : Blue revolution : ………
Answer:
White revolution : Dairy : : Blue revolution : Fishery

Question 9.
Write a comparative note on usefulness and harmfulness of biotechnology.
(OR)
“Biotechnology is not only beneficial but it has some harmful effects too”. Express your opinion about this statement.
Answer:
(1) Biotechnology has proved to be useful in the field of agriculture, medicine, clean technology and industrial products.
(2) Due to various biotechnological experiments, the food production is increased substantially. The milk and milk products are now freely available. People no longer die of hunger due to abundant food supply.
(3) The sophisticated vaccines have stopped the spread of epidemics.
(4) The diseases like diabetes can be controlled due to human insulin injections that can be manufactured by biotechnology.
(5) The problems of pollution control, solid waste management and fuels are partially tackled by biotechnological alternatives.
(6) Though all such positive aspects are there, the biotechnology also poses some problems. The genetic changes are breaking the principles of nature. By inserting human genes in bacteria or virus, the products that are needed only for humans are produced.
(7) Human cloning is also a debatable issue. It will cause social and ethical problems. The new generations formed by cloning will have mothers but no fathers. If man tries to manipulate the genomes of other living organisms, it will cause disturbances in the natural balance. The long ternT effects of all such genetic manipulations can be disastrous. Thus, according to some views, biotechnology can be dangerous too.

Projects: (Do it your self)

Project 1.
Visit the organic manuring projects nearby your place and collect more information.

Project 2.
What will you do to increase public awareness about organ donation in your area?

Project 3.
Collect information about ‘green corridor’. Make a news-collection about it.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology

Can you recall? (Text Book Page No. 88)

Question 1.
What is cell?
Answer:
The structural and functional unit of the body is called a cell.

Question 2.
What is tissue? What are the functions of tissue?
Answer:
Tissue is a group of cells that performs a similar and definite function. E.g. The muscular tissues in the body perform contraction and extensions thereby helping in locomotion. The conducting tissues of the plants like xylem and phloem transport the water and food respectively.

Question 3.
Which technique in relation to tissues have you studied in earlier classes?
Answer:
The technique of tissue culture and genetic engineering has been studied last year. Tissue culture is ‘Ex vivo growth of cells or tissues in an aseptic and nutrient-rich medium’. Genetic engineering and its use has also been studied under, ‘Introduction to biotechnology’.

Question 4.
Which are the various processes in tissue culture?
Answer:
Various step-wise processes are done while performing the-tissue culture. These processes are primary treatment, reproduction/cell division/multiplication, shooting or rooting, primary hardening, secondary hardening, etc.

Observe: (Text Book Page No. 88)

Question 1.
Assign names in the figure given below. Explain the various stages those are kept blank:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology 5
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology 6
Tissue Culture: Tissue culture is the technique in which ‘ex vivo growth of cells or tissues in an aseptic and nutrient-rich medium’ is done. While performing experiments of tissue culture, a liquid, solid or gel-like ” medium prepared from agar, is used. Such medium supplies nutrients and energy necessary for tissue culture technique. Different processes are to be done while performing tissue culture, viz. primary treatment, reproduction or multiplication, shooting and rooting, primary hardening, secondary hardening, etc. From the source plant, required tissues are taken out and all the processes are carried in an aseptic medium in laboratory.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology

(Use your brain power. (Text Book Page No. 89)

Question 1.
Just like the grafting in plants, is the organ transplantation possible in humans?
Answer:
The grafting as done in case of plants, cannot be done in human beings. But the transplantation of certain organs can be done. Liver, kidney, heart, eyes, etc. can be transplanted. But for these transplantations the donor and the recipient should match with each other in respect of their bloodr groups, age, disease condition, etc. In future, the stem cell research can bring about certain changes in the field of transplantations.

(Text Book Page No. 94)

Question 1.
What will happen if the transgenic potatoes are cooked before consumption?
Answer:
Some types of transgenic potatotes that contain edible vaccine against Hepatitis can be cooked. The cooking does not destroy the antigen incorporated into these transgenic potatoes. But according to some scientists, transgenic potatoes with enterotoxin vaccine, if cooked shows denaturation of vaccine.

Choose the correct alternative and write its alphabet against the sub-question number:

Question 1.
The property of stem cells is called ………….
(a) diversity
(b) equality
(c) differentiation
(d) pluripotency
Answer:
(d) pluripotency

Question 2.
Cell ……….. starts from 14th day of conception.
(a) development
(b) specialization
(c) growth
(d) differentiation
Answer:
(d) differentiation

Question 3.
Availability of ………… is an important requirement in organ transplantation.
(a) doctor
(b) clinic
(c) donor
(d) ambulance
Answer:
(c) donor

Question 4.
The toxin which is lethal for ……….. was produced in leaves and bolls of BT cotton.
(a) bollworm
(b) locust
(c) birds
(d) frogs
Answer:
(a) bollworm

Question 5.
Transgenic raw potatoes generate the immunity against ………… disease.
(a) plague
(b) cholera
(c) leprosy
(d) TB
Answer:
(b) cholera

Rewrite the following wrong statements after corrections:

Question 1.
High-class varieties of crops have been developed through the technique of transplantation.
Answer:
High-class varieties of crops have been developed through the technique of tissue-culture.

Question 2.
Earlier, insulin was being collected from, the pancreas of pigs.
Answer:
Earlier, insulin was being collected from the- pancreas of horses.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology

Question 3.
Malaria arises due to genetic changes in hepatocytes.
Answer:
Phenylketonuria (PKT) arises due to genetic changes in hepatocytes.

Question 4.
The E.coli bacteria are useful for cleaning the hydrocarbon and oil pollutants from soil and water.
Answer:
The Pseudomonas bacteria are useful for cleaning the hydrocarbon and oil pollutants from soil and water.

Question 5.
Various essential elements like N, P, K are removed and hence become unavailable to the crops due to earthworms and fungi.
Answer:
Various essential elements like N, P, K become available to crops due to earthworms and fungi.

Question 6.
We do not have any tradition that cures the diseases with the help of natural resources.
Answer:
We have a great tradition of ayurveda that cures the diseases with the help of natural resources.

Match the pairs:

Question 1.

Scientist Contribution
(1) Dr. Anand Mohan Chakravarti (a) Wheat production in America
(2) Dr. M. S. Swaminathan (b) White revolution
(c) Green revolution in India
(d) Cleaning the oil spill

Answer:
(1) Dr. Anand Mohan Chakravarti – Cleaning the oil spill
(2) Dr. M.S. Swaminathan – Green revolution in India

Question 2.

Organism Substance that is absorbed
(1) Pseudomonas (a) Uranium and arsenic
(2) Pteris vitata (b) Selenium
(c) Arsenic
(d) Hydrocarbons

Answer:
(1) Pseudomonas – Hydrocarbons
(2) Pteris vitata – Arsenic

Find the odd man out:

Question 1.
Green revolution, Industrial revolution, White revolution, Blue revolution
Answer:
Industrial revolution. (All others are concerned with food.)

Question 2.
DDT, malathion, chloropyriphos, Humus
Answer:
Humus. (All others are insecticides.)

Question 3.
Sodium, Aluminium, Potassium, Phosphorus
Answer:
Aluminium. (All others are essential elements for plant growth.)

Question 4.
Diabetes, Anaemia, Leukaemia, Thalassemia
Answer:
Diabetes. (All other diseases involve reduction in the number of blood cells.)

Question 5.
Drying, Salting, Cooking, Soaking with sugar
Answer:
Cooking. (All others are food preservative methods.)

Identify and complete the following correlations:

Question 1.
White revolution : Increase in dairy production : : Green revolution : ………. (March 2019)
Answer:
White revolution : Increase in dairy production : : Green revolution : Increase in agricultural production or crop yield

Question 2.
Nostoc, Anabaena : Biofertilizers : : Alfalfa : ………..
Answer:
Nostoc, Anabaena : Biofertilizers : : Alfalfa : Phytoremediation.

Give definition/Give meanings:

Question 1.
Stem cell or what are stem cells?
Answer:
The special cells having pluripotency and ability to divide and differentiate into new cells are called stem cells. They are present in multicellular living beings.

Question 2.
Biotechnology.
Answer:
Technology that brings about artificial genetic changes and hybridization in organisms for human welfare is called biotechnology.

Question 3.
Genetically modified crops.
Answer:
Crops having desired characters are developed by integrating foreign gene with their genome, such crops have modified genome and are known as genetically modified crops.

Question 4.
Golden rice.
Answer:
Biotechnologically developed variety of rice in which gene synthesizing the vitamin A (Beta carotene) has been incorporated and which contains 23 times more amount of beta carotene than that of the normal variety is called golden rice. It was developed in 2005.

Question 5.
Vaccine.
Answer:
The ‘antigen’ containing material given to a person or animal to acquire either permanent or temporary immunity against a specific pathogen or disease is called a vaccine.

Question 6.
Cloning.
Answer:
Production of replica of any cell or organ or entire organism through biotechnological process is called cloning.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology

Question 7.
DNA fingerprint.
Answer:
The nucleotide sequence present on the DNA of each person is unique just like the fingerprint, thus for establishing the identity of any person DNA can be analysed, this technique is known as DNA fingerprinting.

Question 8.
Green revolution.
Answer:
All the methods applied for harvesting maximum yield from minimum land are collectively referred to as green revolution.

Question 9.
White revolution.
Answer:
Achieving the self-sufficiency in dairy business, by performing various experiments for quality control, bringing about newer dairy products and their preservation and thus raising economic standards is called white revolution.

Question 10.
Blue revolution.
Answer:
The aquaculture practices to increase the yield of edible aquatic organisms is called blue revolution.

Name the following:

Question 1.
Research institutes involved with cell science.
Answer:

  • National Centre of Cell Science, Pune
  • Instem, Bengaluru.

Question 2.
Sources of stem cells.
Answer:

  • Umbilical cord
  • Embryonic cells
  • Redbone marrow
  • Adipose connective tissue and blood of adult human being.

Question 3.
Types of Stem cells.
Answer:

  • Embryonic stem cells
  • Adult stem cells.

Question 4.
Organs that can be donated.
Answer:
Eyes, heart, pancreas, liver, kidneys, skin, J bones, lungs.

Question 5.
Organisms used as biofertilizers.
Answer:
Rhizobium, Azotobacter, Nostoc, Anabaena, Azolla.

Question 6.
Two main methods used in animal husbandry.
Answer:

  1. Artificial insemination
  2. Embryo transfer.

Question 7.
Two important aspects of human health management.
Answer:

  1. Diagnosis
  2. Treatment of diseases.

Question 8.
Place where DNA fingerprinting research is done in India.
Answer:
Centre of DNA fingerprinting and Diagnostics, Hyderabad.

Question 9.
One benefit of biotechnology to the agriculture.
Answer:
Expenses on the pesticides are reduced.

scientific reasons:

Question 1.
Nowadays, safer vaccines are being produced.
Answer:

  • Before the advent of biotechnology, the vaccines were made from inactive or dead pathogens of that disease.
  • But now the vaccine is made artificially using biotechnological processes.
  • Such vaccines produced some disease symptoms in some cases.
  • The antigen of the disease is researched upon and its genetic code is found out.
  • A similar antigen is made in the laboratories which is used as a vaccine.
  • Such vaccines are more thermostable and remain active for longer duration. Therefore, the vaccines are now safer.

Question 2.
Awareness about organ donation after death is increasing.
Answer:

  • Due to accidents or illness, some of the vital organs may get damaged and may not work to fullest capacity.
  • In such cases, if organ transplantation is done, it will be very helpful for that needy patient.
  • The dead person’s organs can be used for organ transplantation and a life can be saved.
  • Many government and social organizations are spreading awareness about such donations. Therefore, gradually the awareness about organ transplantation is increasing.

Answer the following questions:

Question 1.
Write two uses of biotechnology related to human health. (Board’s Model Activity Sheet)
Answer:

  1. Biotechnology is used to manufacture vaccines for controlling diseases.
  2. Different hormones such as insulin, somatotropin and somatostatin can be prepared in laboratories by using new biotechnological processes. The clotting factors are also manufactured through such techniques.

Question 2.
Answer the following questions:
(a) What is biotechnology?
(b) Explain any two commercial applications of it. (March 2019)
Answer:
(a) Biotechnology: Technology that brings about artificial genetic changes and hybridization in organisms for human welfare is called biotechnology.

(b)

  • The treatment and prevention of diseases need hormones, interferons, antibiotics and different vaccine which are now manufactured through biotechnology. Gene therapy is also used to treat hereditary disorders.
  • Industrial products and clean technology to combat environmental pollution uses biotechnology practices.
  • DNA fingerprinting has revolutionized the profession of forensic science.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology

Question 3.
What is mainly included under biotechnology?
Answer:
Biotechnology includes the following main areas:

  • Abilities of microbes are used in producing yoghurt from milk and making alcohol from molasses.
  • Production of antibiotics and vaccines, etc. is carried out by with the help of specific cells using their productivity.
  • Bio-molecules like DNA and proteins are used for human welfare.
  • By performing gene manipulation, plants, animals and products of desired quality are produced. Genetically modified bacteria are used to produce human hormones such as Human Growth Hormone and insulin.
  • Tissue culture is a non-genetic technique which is used for production of new cells or tissues. Hybrid seeds are also produced in a similar way.

Question 4.
What are edible vaccines?
Answer:

  • Edible vaccines are those which are given as a food by incorporating them into the food-stuff.
  • Such edible vaccines are produced through biotechnology.
  • Transgenic potatoes are produced with the help of biotechnology which contain vaccine that act against bacteria like Vibrio cholera, Escherichiatoli.
  • If raw potatoes are consumed, then the immunity is generated in the body of a person. However, eating only raw potatoes generates the immunity against cholera and the disease caused due to E. coli.

Question 5.
What is DNA fingerprinting? Explain it in brief. Where is this technique used? Give any two examples. (Board’s Model Activity Sheet)
Answer:

  • As the fingerprints are unique for every individual, similarly the nucleotide sequence in the DNA molecule is also unique.
  • By knowing this sequence, one can find out the identity of any person. Such technique to establish the identity of a person by taking into consideration the nucleotide sequence is called DNA fingerprinting.
  • Its main use is in forensic sciences to confirm the identity of the criminal.
  • Similarly, identity of parents in case of disputed parentage for any child can be understood by taking DNA fingerprints of both the parents and a child.

Write short notes on:

Question 1.
Uses of stem cells.
Answer:
Stem cells are used for following purposes:

  • In regenerative therapy stem cells are used.
  • In case of diseased conditions like diabetes, myocardial infarction, Alzheimer’s disease, Parkinson’s disease, etc., stem cells can be used to replace the damaged or functionless cells.
  • In conditions such as anaemia, thalassaemia, leukaemia, etc. there is always the need of newer blood cells. Here, stem cells can be used to restore the number of blood cells.
  • In techniques of organ transplantation stem cells can be used and they can help in the transplantation of new organs such as kidney and liver The defective organs can be replaced by those that are produced with the help of stem cells and transplanted.

Question 2.
Cloning.
Answer:

  • Cloning is the modern technique in which there is production of replica of any cell or organ or entire organism is done.
  • There are two types of cloning, viz. (i) Reproductive cloning and (ii) Therapeutic cloning.
  • Reproductive cloning: In reproductive cloning, a clone is produced by fusion of a nucleus of diploid somatic cell with the enucleated ovum of anybody. In the process, the sperm or male gamete is not needed.
  • Therapeutic cloning: This technique is largely used for treatment purpose. Stem cells are derived from the cell formed in laboratory by the union of somatic cell nucleus with the enucleated egg cell.
  • This technique is used for therapy of various diseases.
  • Gene cloning can also be done to form millions of copies of same gene. Such genes are used for gene therapy and other purposes.
  • Due to cloning technique, the inheritance of hereditary diseases can be controlled, continuation of generations can be achieved and certain characteristic genes can be enhanced.
  • However, for human cloning, there is world-wide opposition due to ethical reasons.

Question 3.
Dolly.
Answer:

  • Dolly was the first mammalian cloned sheep.
  • Dolly was born on 5th July 1996 in Scotland by the process of cloning.
  • The Finn Dorset sheep was chosen and her diploid nucleus from the udder cell was introduced into the ovum whose haploid nucleus was removed. This enucleated ovum was of Scottish sheep.
  • The egg was then introduced into uterus of another Scottish sheep and it grew into Dolly.
  • Dolly resembled exactly like Finn Dorset sheep whose diploid nucleus was used. None of the characters of Scottish sheep were seen in Dolly.
  • In this way, Dolly had three mothers but no father.
  • Dolly gave birth to many young ones. She died on 14th February 2003 due to cancer of the lungs.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology

Question 4.
Green revolution.
Answer:

  • In agriculture, different methods used to harvest maximum yield from minimum land, these methods are collectively called green revolution.
  • Dr. M.S. Swaminathan is called father of Green Revolution in India while Dr. Norman Borlaug has done the similar efforts in the U.S.
  • Before the Green Revolution in India, there was always the dearth of the food grains. The overflowing Indian population was badly affected due to poor quality and quantity of food.
  • But due to the Green Revolution in India, attention was focussed on the agricultural research.
  • Improvised dwarf varieties of wheat and rice, proper use of fertilizers and pesticides and water management were the proper methods that increased production of food grains.
  • This created abundance of the grains for Indian population.

Question 5.
White revolution.
Answer:

  • Few years back, there was scarcity of milk in various parts of India. At some places, milk and milk products were abundant but they did not reach all the consumers.
  • Dr. Verghese Kurien ^ho was then the founder director of Anand Milk Union Limited (AMUL) started thecooperative movement in the direction to produce “operation flood”, i.e. abundance of milk everywhere.
  • The use of biotechnology was also done to increase the milk production.
  • Dr. Kurien’s efforts have reached all-time high status as India is now self-sufficient in dairy business.
  • This is popularly known as White Revolution. Different experiments were performed for quality control, newer dairy products were thought off and preservation methods were improved.
  • This created White Revolution. AMUL from Anand has now reached international standards.

Question 6.
Blue Revolution.
Answer:

  • Utilization of aquaculture practices for obtaining edible and commercial aquatic organisms is called blue revolution.
  • In East Asian countries where water bodies and fish population is abundant, the aquaculture was started.
  • On similar lines, in India, the aquaculture of different fresh water and marine organisms is being done with the help of fishery scientists.
  • Government of India has vowed to increase the aquaculture production by encouraging the people for aquaculture by launching the program ‘Nil- Kranti Mission-2016’ (NKM-16).
  • Pisciculutre is culturing of fish, mariculture is culture of marine organisms such as prawns/shrimps and lobsters. Sea weeds, oysters, clams are also cultured.
  • For carrying out aquaculture, 50% to 100% subsidies are offered by the Government.
  • Fresh water fishes like rohu, catla and other edible varieties like shrimp and lobsters are being cultured on a large scale which can bring about Blue Revolution.

Complete the paragraph by choosing the appropriate words given in the bracket:

Question 1.
(degenerated, red bone marrow, adipose connective tissue, blastocyst, umbilical cord, Differentiation)
………… of stem cells form can form various tissues, in the body. Stem cells are present in the ………….. by which the foetus is joined to the uterus of the mother. Stem cells are also present in the ……….. stage of embryonic development. Stem cells are present in ……….. and ………… of adult human beings. It has become possible to produce different types of tissues and the ……… part of any organ with the help of these stem cells.
Answer:
Differentiation of stem cells form can form various tissues in the body. Stem cells are present in the umbilical cord by which the foetus is joined to the uterus of the mother. Stem cells are also present in the blastocyst stage of embryonic development. Stem cells are present in red bone marrow and adipose connective tissue of adult human beings. It has become possible to produce different types of tissues and the degenerated part of any organ with the help of these stem cells.

Paragraph-based questions :

1. Green corridor refers to a special road route that enables harvested organs meant for transplants to reach the destined hospital. A 45-year-old woman, a victim of a railway accident, was declared brain dead, her husband and children agreed to donate her kidneys, liver and heart. One of her kidneys was transplanted to a patient in MGM Hospital and the second kidney helped a patient in Jaslok hospital. Her liver helped the transplant of a patient in Wockhardt Hospital. And her heart was sent to Fortis to the patient on a super urgent priority list, transported via a green corridor covering 18km in less than 16 minutes. This was possible due to Green corridor.
Questions and Answers :

Question 1.
What is Green corridor?
Answer:
Green corridor is a special road route that enables harvested organs meant for transplants to reach the destined hospital

Question 2.
Which organs of brain-dead lady were transplanted?
Answer:
Two kidneys, liver and heart of the brain- dead lady were transplanted.

Question 3.
How many lives were saved from organs of one lady?
Answer:
Four patients lives were saved due to organ donation of one lady.

Question 4.
How was distance of 18km covered in 16 minutes? Why?
Answer:
The distance was covered because the concept of Green corridor was applied. The heart was sent from one hospital to another, where the recipient was kept ready. The quick transportation is necessary to keep heart in living condition.

Question 5.
Who takes the decision to donate the organs?
Answer:
The close relatives of deceased person take the decision to donate the organs.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology

2. Read the following extract and answer the questions that follow: (March 2019)
A liberal view behind the concept of organ and body donation is that after death our body should be useful to other needful persons so that their miserable life would become comfortable. Awareness about these concepts is. increasing in our country and people are voluntarily donating their bodies.

Life of many people can be saved by organ and body donation. Blinds can regain their vision. Life of many people can be rendered comfortable by donation of organs like liver, kidneys, heart, heart valves, skin, etc. Similarly, body can be made available for research in medical studies. Many government and social organizations are working towards increasing the awareness about body donation.
Questions and Answers :

Question 1.
What is the liberal view behind the organ and body donation?
Answer:
By body donation, research in medical studies is possible. The needy persons can get vital organs which can save their lives.

Question 2.
Name any four organs that can be donated.
Answer:
Liver, Kidneys, heart, eyes, skin, etc. can be donated.

Complete the following table:

Question 1.

Plant/Microbes Functions
(1) Pteris vitata ______________________________
(2) Pseudomonas ______________________________
(3) ______________________________ Absorption of uranium and arsenic
(4) ______________________________ Absorption of radiations of nuclear waste

Answer:

Plant/Microbes Functions
(1) Pteris vitata Absorbs arsenic from soil.
(2) Pseudomonas Separates hydrocarbon and oil from water and soil
(3) Sunflower Absorption of uranium and arsenic
(4) Deinococcus radiodurans Absorption of radiations of nuclear waste

Diagram/chart based questions:

Question 1.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology 7
(A) Which process is shown in the above figure? *
Answer:
The figure shows process to make transgenic

(B) Describe in brief the steps I, II, III and IV.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology 8

Question 2.
Draw well labelled diagram of Stem cell therapy.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology 9

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology

Question 3.
Label the following diagram :
(i) Stem cells and organ transplantation,
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology 10

(ii) Organs that can be donated:
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology 11

Question 4.
(i) Which therapy is shown in the Fig. 8.5?
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology 12
(ii) Which will be possible benefits of this therapy in organ transplantation ?
Answer:
(i) The figure 8.5 shows the ‘regenerative therapy’ using stem cells. Also called stem cell therapy.
(ii) With the help of above therapy organs like liver, kidney from stem cells can be redeveloped to replace the failed ones.

Activity based questions:

Question 1.
Bring a packet of ‘Balghuti’ from ayurveda shop. Learn the information about each component in it. Collect information about various other medicines and prepare the chart as shown below. (Try this: Textbook page no. 99)
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology 13

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology

Question 2.
Give five examples of each of the fruiting and flowering plants developed through tissue culture and mention their benefits. (Make a list and discuss: Textbook page no. 93)
Answer:
I. Fruiting trees: Banana, Chikoo (Sapota), Tomato, Fig, Pineapple.

II. Flowering trees: Orchids, Roses, Chrysanthemum, Gerbera, Begonia, Carnation, Lili. Benefits of such plants may be varied. Mostly fruits developed are made seedless and tastier.

III. Benefits of plants produced through technique of tissue culture:

  • Techniques of tissue culture can produce more copies of same plant with better characters. ’ The plant grower likes to have bigger and more fruits from fruit trees. On the flowering trees, colourful flowers with good fragrance are favoured.
  • Plants which do not depend on particular climate and local seasonal changes are produced by tissue culture methods. This helps to rise the yield in an area which otherwise may not produce a specific crop.
  • For tissue culture, saplings and seedlings are made available throughout the year through laboratory. The limitations of getting natural seeds are not there thus planting can be done throughout the year.
  • Tissue culture techniques create the plants of uniform size, shape and yield. Since they are exactly alike, it becomes beneficial.
  • In lesser time period, the crops reach maturity.
  • The crops are pest and disease resistant.
  • Tissue culture techniques are cost effective and easy to carry out.

Question 3.
Which new species of the rice have been developed in India? (Collect Information: Textbook page no. 97)
Answer:

  1. Species in 2015-16: High zinc species (DRR Dhan 45), Pusa 1592, Punjab basmati 3, Pusa 1609, Telangana Sona.
  2. Species in 2014: CR Dhan 205, CR Dhan 306, CRR, 451.

Question 4.
Discuss about stem cells and organ transplantation in the class with the help of figures given on textbook page no. 90. (Observe: Textbook page no. 90)
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology 14
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology 15
Organ transplantation:
Various organs in the human body either become less efficient or completely functionless due to various reasons like aging, accidents, infections, disorders, etc. Life of such person becomes difficult or even fatality may occur under such conditions. However, if a person gets the necessary organ under such conditions, its life can be saved.

Availability of donor is an important requirement in organ transplantation. Each person has a pair of kidneys. As the process of excretion can occur with the help of single kidney, person can donate another one. Similarly, skin from certain parts of the body can also be donated.

Various factors like blood group, diseases, disorders, age, etc. of the donor and recipient need to be paid attention during transplantation.

However, other organs cannot be donated during life time. Organs like liver, heart, eyes can be donated after death only. This has lead to the emergence of concepts like posthumous (after death) donation of body and organs.

Organ and Body Donation: human bodies are disposed off after death as per traditional customs. However due to progress in science, it has been realized that many organs remain functional for certain period even after death occurs under specific conditions. Concepts like organ donation and body donation have emerged recently after realization that such organs can be used to save the life of other needful persons. A liberal view behind the concept of organ and body donation is that after death, our body should be useful to other needful persons so that their miserable life would become comfortable. Awareness about these concepts is increasing in our country and people are voluntarily donating their bodies.

Life of many people can be saved by organ and body donation. Blinds can regain the vision. Life of many people can be rendered comfortable by donation of organs like liver, kidneys, heart, heart valves, skin. etc. Similarly, body can be made available for research in medical studies. Many government and social organizations are working towards increasing the awareness about body donation.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology

Question 5.
Which fruits processing industries you observe in your surrounding? What is their effect? (Make a list and discuss: Textbook page no. 99)
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology 16
Fruit Processing:
we are daily using various products prepared from fruits. All are consuming the products like chocolates, juices, jams and jellies. All these products can be produced by processing on fruits. Fruits are perishable agro-produce. It needs the processing in such a way that it can be used throughout the year. Fruit processing includes various methods ranging from storage in cold storage to drying, salting, air tight pucking, preparing murabba, evaporating, etc.

Projects: (Do it your self)

Project 1.
Collect information about various hybrid varieties of animals. What are their benefits? Make a presentation of various pictures and videos. (Use of ICT: Textbook page no. 93)

Project 2.
Visit the websites: http://www.who.int/transplantation/organ/en/ and www.organindia.org / approaching-the- transplant/and collect more information about ‘brain dead’, organ donation and body donation (Internet is my friend: Textbook page no. 90)

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 8 Cell Biology and Biotechnology

Project 3.
Collect more information about the Human Genome Project, one of the important projects in the world.
(Internet is my friend: Textbook page no. 95)

Project 4.
Collect the information and make the chart about the work of various state and national-level institutes related with biotechnology. (Internet is my friend: Textbook page no. 97)

Maharashtra Board Class 10 Political Science Solutions Chapter 4 Social and Political Movements

Balbharti Maharashtra State Board Class 10 Political Science Solutions Chapter 4 Social and Political Movements Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 10 Political Science Solutions Chapter 4 Social and Political Movements

Question 1.
Choose the correct option from the given options and complete the sentences.
(1) ………………………….. is the main demand of farmers movement.
(a) Right to cultivate on the forest land
(b) To get the right price for agricultural product
(c) Protection of consumers
(d) Building of dams
Answer:
(b) To get the right price for agricultural products

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(2) To increase agricultural production and become self-sufficient with regard to food grains ………………………….. was initiated.
(a) Water revolution
(b) Green revolution
(c) Industrial revolution
(d) White revolution
Answer:
(b) Green revolution

Question 2.
Explain the concepts.
(1) Tribal movement
Answer:

  • Tribal community was always dependent on forest wealth for their living.
  • The British had prohibited the tribals from making use of forest wealth to earn their livelihõod
  • Kolam, Gond, Santhal, Koli, Bhilla, Munda Tribals of different parts of India revolted against the British.
  • Even after independence their problem to earn a livelihood is not solved. Their right on the forest land, to gather forest products and to cultivate on forest land is not yet recognised.

Therefore, for these demands, Tribal Movement is active in many parts.

(2) Labour movement
Answer:

  • Industries in public and private sector like textile mills, railway companies started in India in the latter part of the nineteenth century.
  • Due to industrialisction, a large number’ of labour force came into existence.
  • Thiš led to lot of labour issues. In 1920, All India Trade Union. Congress was established to solve their problems.
  • Many unions were formed after independence. The Trade Union Movement was very effective from 1960 tifi 1980s.
  • After 1980s trade union movement lost its momentum and slowly disintegrated. Globalization gave a final blow to the movement.

Question 3.
Answer the following questions in brief.
(1) Explain the activities/role/functions of environmental movement.
Answer:
(i) Role : The environment movement rias played a key role in –

  • Creating public awareness about the importance of balance in environment through television, newspapers, and other mediums.
  • Opposing developmental projects with environmental concerns.

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(ii) Functions : The function of the environment movement is to make efforts silently or rigorously to protect natural areas through afforestation, recycling or pollution control. Forest department and the pollution board are actively involved and extend support by making stringent laws to book the culprits.

(iii) Activities : Different activities are conducted to promote the environment movement:

  • Environmental degradation has become a serious issue not only in India but also in the world.
  • The issues of degradation was discussed at. Rio-de-Janeiro, Paris and Kyoto Conferences.
  • Even in India many movements are active for conservation of the environment like the Chipko movement, Appiko movement ana Vanmahatsov.

(2) Explain the nature of farmers movement in India.
Answer:

  1. The Indian farmers organised themselves in pre-independence era to fight against the anti-agricultural policies of the colonial British rulers.
  2. The farmers were inspired by the thoughts of Mahatma Phule, Justice Ranade and Mahatma Gandhi. They organised satyagraha against revenue collection in Bardoli and Champaranya.
  3. Farmers’ movement slowed down because of tenancy laws under land reforms. Green revolution failed to improve conditions of the poor farmers.
  4. Farmers’ movement gained momentum with demands like, appropriate price for agricultural products, debt relief and debt cancellation after recommendations from Swaminathan Commission.

(3) For which reforms were the women’s movement in the pre-independence period fighting?
Answer:
In the pre-independence period women’s movement were working for the following reforms :

  • Eliminating injustice against women.
  • To put an end to the exploitation of women and help them lead a respectful and dignified life.
  • They should be able to participate actively in social life.
  • To end the practices like Sati, child marriage, polygamy and bring about reforms such as widow remarriage and women’s education.

Question 4.
State wheather the following statements are true or false. Give reasons for your answer.
(1) Movements are important in a democracy.
Answer:
The above statement is True.

  • People organise themselves and start a movement to solve social issues.
  • Leaders and activists provide all the information regarding those issues to the government.
  • The government takes, notice of the problems because of the movement.
  • Some movements aim at opposing some policies of the government and certain decisions. This is the most recognised method of protest in democracy.

Hence, movements have great importance in democracy

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(2) Movements do not need a strong leadership.
Answer:
The above statement is False.

  • The success of any movement depends on leadership. The movement remains active because of the strong leader.
  • The decisions regarding the objective of the movement, programme of action, strategy of agitation are decided and taken by the leader.
  • Firm leadership has a wide reach. They can get public support making the movement very effective. So, the need of a strong leadership is utmost essential.

(3) Consumer movement came into existence.
Answer:
The above statement is True.

  • The consumers faced different problems because of changing economy and social system.
  • Adulteration increased the cost of products and faulty weights and measures are some of the problems faced by the consumers.
  • To protect the consumers from such frauds the Consumer Protection Act was passed in 1986.
  • The Consumer Protection movement was started to create awareness among the consumers about their rights and their safety.

Project
(1) Collect the news in the newspapers about various activities of social movements.
(2) Write a report on movements in your area which are working to resolve general problems.
(3) Prepare a format of a complaint you will submit under consumer protection act if you are cheated in purchase of vegetables or grains
Answer:

Memory Map
Maharashtra Board Class 10 Political Science Solutions Chapter 4 Social and Political Movements 1

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Question 5.
Choose the correct option from the given options and complete the sentences :
(a) In …………………., movements have more importance.
(a) socialist rule
(b) dictatorship
(c) democracy
(d) communist rule
Answer:
(c) democracy

(b) In democracy, Right to …………………. is considered an important right.
(a) rehabilitate
(b) pursue questions
(c) behave with control and responsibility
(d) protest
Answer:
(d) protest

(c) is the objective of Green Revolution.
(a) To stop degradation of environment
(b) Protection of the forests
(c) Increase in agricultural output
(d) To stop the felling of trees.
Answer:
(c) Increase in agricultural output.

(d) The trade union movement in India has background of ………………… .
(a) freedom struggle
(b) globalisation
(c) prestigious past
(d) industrialisation
Answer:
(d) industrialisation

(e) In 1899, …………………. workers called for a strike.
(a) railway
(b) mill
(c) handloom
(d) rice mill
Answer:
(a) railway

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(f) Dr. Rajendrasinh Rana had brought about …………………. in Rajasthan.
(a) White Revolution
(b) Water Revolution
(c) Green Revolution
(d) Consumer Revolution
Answer:
(b) Water Revolution

(g) Dr. Rajendrasinh Rana is known as the …………………. of India.
(a) Farmer man
(b) environment affectionate
(c) Man of the Millennium
(d) Waterman
Answer:
(d) Waterman

(h) Tribals in Bihar revolted against the British under the leadership of ………………… .
(a) Rajendrasinh Rana
(b) Birsa Munda
(c) Umaji Naik
(d) Kajarsingh
Answer:
(b) Birsa Munda.

(i) Swadeshi movement is an important …………………. movement.
(a) political
(b) social
(c) economic
(d) cultural
Answer:
(c) economic

(j) …………………. is one of the problems faced by consumers.
(a) Cancellation
(b) Malnutrition
(c) Adulteration
(d) Transportation
Answer:
(c) Adulteration

(k) The main demand of the farmer’s movement was to accept suggestions of the …………………. Commission.
(a) Sunderlal Bahuguna
(b) Verghese Kurien
(c) Swaminathan
(d) Kothari
Answer:
(c) Swaminathan

(l) In 1986, …………………. Act came into force.
(a) Consumer Protection
(b) Women Empowerment
(c) Child Marriage
(d) Environment Protection
Answer:
(a) Consumer Protection

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(m) The post-1980 movements are called ………………… .
(a) New
(b) Neo-social
(c) Broad
(d) Globalisation
Answer:
(b) Neo-social

(n) …………………. was established in 1920.
(a) Farmer’s Organization
(b) Bhartiya Kisan Union
(c) All India Trade Union Congress
(d) All India Kisan Sabha
Answer:
(d) All India Trade Union Congress.

Question 6.
Explain the following statements by giving reasons :
(a) Political parties can concentrate on one particular issue.
Answer:
The above statement is False.

  • Political parties contest elections to solve problems of common people.
  • Parties have to take into consideration all matters from public cleanliness to roads to space research. They have to have a national perspective and take decisions.
  • Political parties should have programmes for the development of all the sections of society like youth, senior citizens, businessmen, women, farmers and labourers.
  • This – means that political parties cannot concentrate on just one particular issue.

(b) People’s active participation is expected in the movement.
Answer:
The above statement is True.

  • A. movement is started to solve issues of public interest.
  • People offer support to the movements which are related to their cause or a particular issue.
  • Deciding upon the issues of the people a programme is decided and a group is formed.

(c) Dr. Rajendrasinh Rana is called the Waterman of India.
Answer:
The above statement is True.

  • Dr. Rajendrashinh Rana built thousands of ‘Johads’ in Rajasthan.
  • He revived many rivers in the desert region of Rajasthan.
  • He formed an organisation – “Tarun Bharat Sangh” which built eleven thousand Johads to harvest water. .
  • He started a campaign for Water conservation, revival of rivers, forest conservation and wildlife conservation.
  • He worked continuously for this cause for 31 years building 11 thousand johads bringing about water revolution in Rajasthan. Therefore, is called the Waterman of India.

Question 7.
Explain the concept :
(a) Movement:
Answer:

  1. When people organise themselves to resolve a certain issue it is called a movement.
  2. Movements increase the participation of people in social life.
  3. Movements are for public welfare and to solve issues. The aim of any movement is not only to pressurize the government but also to oppose its decision or policies.
  4. A movement is started for different reasons like religious, social, cúltural, protection of the environment, ill practices and traditions.

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(b) Public Interest Litigation:
Answer:

  1. A litigation is filed if an individual or group feels that fundamental rights which are enshrined in the Constitution are undermined by the government.
  2. To safeguard human rights, citizens can file a litigation in High Court or Supreme Court. Such a litigation is known as Public Interest Litigation.
  3. Public Interest Litigation is filed for problems such as pollution, government avoiding public works and for social problems such as violence, discrimination and ostracising someone.
  4. It is the most effective way of seeking justice.

(c) Environment Movement :
Answer:

  • Different activities are conducted to promote the environment movement in India.
  • Environment degradation has become a serious issue not only in India but also all over the world.
  • The issues of degradation were discussed at Rio-de-Janeiro, Paris and Kyoto Conferences.
  • Even in India many movements are active for conservation of the environment like the Chipko movement, Appika movement and Vanmahatsov.

Question 8.
(A) Complete the graphical representation :

(1)
Maharashtra Board Class 10 Political Science Solutions Chapter 4 Social and Political Movements 2
Answer:
Maharashtra Board Class 10 Political Science Solutions Chapter 4 Social and Political Movements 3

(2)
Maharashtra Board Class 10 Political Science Solutions Chapter 4 Social and Political Movements 4
Answer:
Maharashtra Board Class 10 Political Science Solutions Chapter 4 Social and Political Movements 5

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(3)
Maharashtra Board Class 10 Political Science Solutions Chapter 4 Social and Political Movements 6
Answer:
Maharashtra Board Class 10 Political Science Solutions Chapter 4 Social and Political Movements 7

(4)
Maharashtra Board Class 10 Political Science Solutions Chapter 4 Social and Political Movements 8
Answer:
Maharashtra Board Class 10 Political Science Solutions Chapter 4 Social and Political Movements 9

(B) Explain the events in Trade Union Movement:

Maharashtra Board Class 10 Political Science Solutions Chapter 4 Social and Political Movements 10
Answer:
Maharashtra Board Class 10 Political Science Solutions Chapter 4 Social and Political Movements 11

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Question 9.
Answer the following questions in brief:
(a) Explain the features of a movement.
Answer:

  • A movement is a collective action which has active participation or support of the people.
  • People take up a particular issue and organise themselves.
  • A movement requires strong leadership. A strong leader makes the movement effective.
  • If people feel connected to the issue, then they extend their support to the movement.

(b) What are the demands of Trade Union Movement?
Answer:
The Trade Uniin Movement makes demands regarding following issues :

  • Contract labour and unstable employment..
  • financial insecurity and unfavourable conditions at workplace.
  • Unlimited working hours and health hazards.
  • No protection of labour laws.

(c) How did the objectives of women’s movement change after independence?
Answer:

  1. In the pre-independence era the aim of the women’s movement was to put an end to the unjust practices against women and end their exploitation.
  2. After independence, the aim of their movement changed because they realised that though the Constitution had given equal rights both to men and women in practice they were never considered equal.
  3. The objective of the women’s movement was to achieve freedom in real sense, i.e. they should be treated as human beings and should get equal rights and to live a dignified life.

(d) Which issues were taken up by the women’s movement after independence?
Answer:
Many issues were taken up by the women’s movement for welfare of the women after independence. Some are:

  • Health and education of women
  • financial independence
  • Social security
  • To be treated as human beings and have a status and prestige.

(e) Which issues are handled through movements?
Answer:
Movements arise out of public issues, which could be social, political, economic and religious.

  1. To protect the rights of the citizens like voting, freedom and for similar issues, political movements are organised.
  2. financial security, minimum wages, employment, insistence on an indigenous product are the reasons for economic movement.
  3. Social and religious movements are organized to eliminate ill practices like untouchability, entry of women in temples,’ discrimination and social issues.
  4. Movements are organised to raise voice against injustice done to a particular region, language and for issues like cleanliness, environment and movements for development like Green revolution and White resolution.

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(f) Which movements started in India are actively working for rehabilitation of the displaced and to secure their livelihood?
Answer:
People who got displaced started this movement for different reasons. Some movements lasted for short time while some lasted long.

  • “Narmada Bachao Andolan” was a popular movement.
  • People living in Maharashtra and Gujarat continued it for 28 years.
  • People in the Sindhudurg district who got displaced due to the Talamba dam started movement for rehabilitation. It lasted for 32 years.
  • Farmers who got displaced because of Pune-Nagpur highway or for the planned Purandar airport launched movements on a large scale. Such movements are going on all over India.

(g) Name the policies started by the government for the welfare of farmers and landless labourers?
Answer:
The government has started the following policies for the welfare of the farmers and landless labourers :

  • National agriculture policy
  • Crop insurance scheme (FASAL Bima Yojana)
  • Jalyukt Shivar
  • Indira Gandhi Niradhar (old), landless, destitute women farm labour scheme.
  • Neem Coated Urea.
  • Name the policies started by the government for the welfare of farmers and landless labourers.

(h) Name the movements started by Mahatma Gandhi, Mahatma Phule, Sant Gadge Maharaj and Dr. Babasaheb Ambedkar.
Answer:

  • Mahatma Phule laid the foundation of the movement for education of women and social equality.
  • To stop the practice of widow tonsure he called for a strike of barbers in Mumbai.
  • Mahatma Gandhi adopted the technique of satyagraha and started the movement for farmers in Champaranya and Kheda.
  • He also started the Non-cooperation Movement and Civil Disobedience Movement..
  • Sant Gadge Maharaj started the cleanliness campaign.
  • Dr. Babashaeb Ambedkar launched satyagraha to allow untouchables to use water from a public tank in Mahad..
  • He also led the movement in Nashik for Dalits so that they could get entry into the Kalaram temple.

(i) All movements have ideologies. (Discuss : Textbook page 92)
Answer:

  • Even though movements are launched for social welfare there is always an ideology behind every movement.
  • The scope of movements against child marriage or dowry prohibition is not limited to oppose the social evil practice but have wider aim of social reformation.
  • The movements started against female foeticide ‘Beti Bachao Beti Padhav’, violence against women and to empower women had objectives to achieve equal social status for women and their protection.
  • Movements like cleanliness campaign, Chipko Andolan, Save Trees aim not only at environment protection but also aim at saving humanity.
  • These movements have faith in democratic values like equality and brotherhood and humanity. This shows all movements have ideologies.
  • Generally the movements are devoted to one particular issue but have an ideology behind them.
  • For example movements against child marriage, dowry believe in values of democracy, women empowerment and social equality.
  • Sometimes some movements gradually get transformed into political parties.

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Question 10.
Give your opinion :
(a) Do you think, if all the movements co-ordinate with each other, the result will be more effective?
Answer:

  • Our society has witnessed many movements from pre-independence times.
  • If all these movements co-ordinate with each other they will be definitely, effective.
  • With each other’s cooperation they can work together to find the root cause of the problem and also find a solution.
  • The manpower will not get divided. The work will get divided and that would save time and energy to a great extent.
  • The movement will be more effective.

(a) On which issues does the ‘Sons of the Soil’ movement in India insist? (Discuss : Textbook page 93)
Answer:
People migrate for various reasons within the country. They create lot of problems in their newly adopted homeland which give rise to the ‘Sons of the Soil’ movement. The main reasons for the movement are :

  • Sons of the Soil, i.e. local people lose out on employment opportunities.
  • They are deprived of their jobs.
  • Their land is confiscated.
  • Housing becomes expensive.
  • The migrants pose a threat to the language and culture of local people.
  • Sons of the Soil lose economic monopoly as well as political influence.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Balbharti Maharashtra State Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 1.
Complete the table.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 1
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 2
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 3
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 4
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 5

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 2.
Write notes.
a. Disaster Management Authority.
Answer:
Disaster Management Authority is the body that works at the level of government from national level to village level. This work is basically about management of any disaster and tackling the problems of the affected people. At National level there is National Disaster Management Authority for which the Prime Minister is the chairman. For every state there is State Disaster Management Authority, where the chief minister of every state is the chairman. Under the state level, there are district level units where district collector is responsible for disaster management and implementation of rehabilitation schemes. Below district level authority there are Taluka and then Village Disaster Management Committees.

The Tahsildar is the chairman for Taluka level while the Sarpanch of the village is responsible for management of disasters at village level. Collector of each district helps in planning, coordinating and controlling the implementation of rehabilitation programme and also gives essential instructions and reviews the entire system.

b. Nature of disaster management.
Answer:
Disaster management involves either prevention of disasters (Pre-disaster management) or creating preparedness to face them (Post-disaster management). The action plans are prepared for managing disasters. This is done after studying the different aspects such as preventive measures, rehabilitation and reconstruction plans. The disasters are tackled by executing action plans in the following steps: Preparation, redemption, preparedness, action during actual disaster, response, resurgence and restoration. At every level there are other voluntary organizations and Government meteorological institutions for their help.

c. Mock drill.
Answer:

  • Mock drill is the practice to check whether there is preparedness for dealing with the sudden attack of disaster.
  • For this purpose, virtual or apparent situations that simulate the disaster are created.
  • The reaction time for any type of disaster is checked by such activity. In the presence of trained personnel, the execution of the rescue plans are observed.
  • People also understand their responsibilities at the time of actual disaster.
  • The experts also check execution of plan designed for disaster redressal.
  • By such mock drills, the efficacy of the system can be understood. In future, when actual calamity strikes, there is already preparation for disaster redressal. Therefore, mock drill is useful.

d. Disaster Management Act, 2005.
Answer:
Government of India has made Disaster Management Act in 2005. The affected people are given all necessary help as per this act. With the humanitarian view, people are rehabilitated and helped them to come back to normalcy after the disaster.

As per this Act, National Disaster Response Force has been established. This force consists of 12 divisions in entire India which are attached with Indian Army. The headquarter is located in Delhi, but the action is taken all over the country with the help of army. As per the Act, in Maharashtra National Disaster Response Force is in action through State Reserve Polioe Force. The personnel of this force are trained accordingly, and they take part in the rescue work during different disasters.

Question 3.
Answer the following questions.
a. Explain the role of district disaster control unit after occurrence of any disaster.
Answer:
(1) District control unit looks after the ; disaster management of the district.
(2) It is immediately formed either after the impact of disaster or if warning is given about some upcoming disaster.

District-wise Disaster Control Unit performs following role:

  • The review of various aspects of disasters is done.
  • Through the disaster control unit there is continuous contact established with various agencies like army, air force, navy, telecommunication department, paramilitary forces, etc. for obtaining help.
  • The unit also coordinates with various voluntary organizations for their help in disaster management.

b. Give the reasons for increase in human disasters after the World War-II.
Answer:

  • After Second World War, the feelings of peace and brotherhood among the global citizens were lost. The geographic, religious, racial and ethnic differences sprang up tremendously.
  • Atrocities that Nazi has performed made deep impact on the minds of people. Terrorism, abduction, robberies and social unrest increased in almost all the countries.
  • The financial losses had incurred in the World War II. The misuse of science and technology was done to retrieve these deficits.
  • At the end of World War II, the atomic bombs were dropped in Japan. This has created health problems in the entire world.
  • Social inequality, economic disparity, racial and religious differences were some adversaries that created unrest in the country.
  • Later, the neighbouring nations kept on fighting. The geographical boundaries were changed. People always had feelings of insecurity. The terrorism flourished. All such instances gave rise to man-made disasters.

c. What are the objectives of disaster management?
(OR)
State any four objectives of disaster management. (March ’19)
Answer:
Objectives of disaster management:

  • To save human life from disasters. To help them for moving away from the place of disasters by rapid action.
  • To supply essential commodities to the affected people. This helps to reduce the gravity of disaster. People are given grains, water and clothes and other basic necessities under this objective.
  • To bring back the conditions of affected people to normalcy.
  • To rehabilitate the affected and displaced victims.
  • To think and execute the protective measures in order to develop capability to face the disasters in future.

d. Why is it essential to get the training of first aid? (July ’19)
Answer:
When there is a disaster, we need to immediately help the victim. Till the medical help arrives, one should be in position to treat the injured and save his or her life. In such cases; knowing first- aid is essential. Such kind of a need may arise in case of our parents, our siblings at home or with friends in school. Those who are injured should be treated at once. If we know about techniques of first aid, we can save such person before the medical help arrives. Therefore, it is essential to get the training of the first aid.

e. Which different methods are used for transportation of patients? Why?
Answer:
For the transportation of patients following methods are used:

  • Cradle method: This method is used for children and persons with less weight.
  • Carrying piggy back: This method is useful in carrying the unconscious persons.
  • Human crutch method: If one leg of the person is injured, then the victim is supported with minimum load on the other leg. This is called human crutch method.
  • Pulling or lifting method: For carrying an unconscious person for a short distance this method is used.
  • Carrying on four-hand chair: This method is used when the support is needed for a part below waist region.
  • Carrying on two-hand chair: Patients that cannot use their hands but can hold their body upright, are carried by such method.
  • Stretcher: By making temporary stretcher in case of emergency, the unconscious patient can be moved. Such temporary stretchers are made by using bamboos, blanket, etc.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 4.
On the basis of the structure of disaster management authority, form the same for your school.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 6

Question 5.
Write down the reasons, effects and remedial measures taken for any two disasters experienced by you.
Answer:
Students are expected to write the answer based on their own experiences.

Question 6.
Which different aspects of disaster management would you check for your school? Why?
Answer:
For the pre-disaster management at school following aspects would be inspected.

  • Are the telephones 6f the school working properly?
  • Is there a first-aid box in each class?
  • Are there any basic medicines in the school?
  • Is the team ready for rescue of smaller children from lower classes?
  • Has monitor or prefect participated in a mock drill? Does he/she know about first aid?
  • Is the contact of parent representative available in emergency situations?
  • Is the Medical Officer/Doctor present on the school campus?
  • Is there enough drinking water and some dry snacks available in the school?
  • Are the staircases and corridors suitable for quick evacuation of the children?

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 7.
Identify the type of disaster.
a. Terrorism.
Answer:
Man-made, intentional.
Due to the activities of terrorism, many innocent lives are lost. Many are seriously injured. Some become crippled for their entire life. Buildings, monuments, vehicles everything is completely destroyed. There is rift between different religions or sects. The peaceful atmosphere is disturbed. The entire society is under the constant fear of insecurity.

b. Soil erosion.
Answer:
Natural, geophysical, geological.
When the upper fertile layer of soil is lost, it becomes barren. The trees are uprooted. The fertility of the area is lost. The land becomes unsuitable for cultivation or farming. Due to wind, flowing water or grazing animals the naturally occurring soil erosion becomes hazardous for the environment.

c. Hepatitis.
Answer:
Natural, biological, animal-origin.
Hepatitis is a viral disease which spreads through the contaminated food and water. The outburst of epidemic of hepatitis is difficult to control. As in big cities the quality of road side food is often consumed, the spread of hepatitis is. fast. People suffer due to hepatitis.

d. Forest fire.
Answer:
Natural, biological, plant-origin.
Due to heat and wind, the dry grass and the shrubs catch fire in the forests, resulting in forest fires. Such rapidly spreading forest fire can finish the biodiversity within a very short span of time. It is difficult to extinguish the naturally lit forest fires. Many trees and other vegetation, animals and birds along with their habitats are destroyed due to forest fire. The smoke emanating causes the air pollution.

e. Famine.
Answer:
Natural, climatic.
Due to famine there is severe water scarcity. In absence of water, the fields and farms become barren as the crops cannot grow without water. There is shortage of food grains. The cattle dies due to want of water and grass. Local people have to migrate in search of food, water and shelter.

f. Theft.
Answer:
Man-made, intentional.
Theft causes economic loss for the one whose money or valuables are looted. The person who suffers the loss also undergo mental and emotional shock. Sometimes the thief may also cause physical harm. It may cost on life too.

Question 8.
Some symbols are given below. Explain those symbols. Which disasters may occur if those symbols are ignored?
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 7
Answer:
The above signs are warning symbols which should never be ignored.
The meaning of each is given below. They are giving warnings about explosive, inflammable, oxidizing, compressed gas, corrosive, toxic, irritant, environmentally hazardous and health hazard.

(1) Explosive: Some materials are explosive. While handling such materials care should be taken. We should not take anything that would cause fire leading to explosion. If explosion occurs, there would be a major disaster causing great loss of life and property. Thus if this sign is seen, great care has to be taken.

(2) Inflammable: Similar to explosive substances, the inflammable materials can also catch fire easily. Therefore, to warn people such sign is given on materials that can cause hazard by burning.

(3) Oxidizing: Some chemical substances are oxidizing. They carry out chemical reactions with a rapid speed. E.g. If potassium permanganate falls on the cloth, it starts the reaction on its C-C bonds. Due to such property of carrying out reactions, the cloths may catch fire. Therefore, oxidizing substances should be handled with care.

(4) Compressed: Compressed substances are filled under pressure in some container. If mishandled, they can come out of the container by bursting it open. This can cause some injuries.

(5) Corrosive: The corrosive substances are very reactive. The mere touch of corrosive substances can cause destruction of skin, eyes, respiratory passages, digestive organs, etc. rapidly. Just touching or smelling of such substances can cause major injury and thus warning sign of corrosive substance should never be ignored.

(6) Toxic: To taste a toxic substance or even to smell it, can lead to death. The packing of these substances are therefore marked as dangerous. They should be avoided as far as possible.

(7) Irritant: When skin or any delicate part of the body comes in contact with the irritant substance, it can cause harmful reaction. Especially, eyes, nasal mucosa and skin are affected by contact with corrosive substances.

(8) Environmentally hazardous: Many sub¬stances cause harm to the environment due to their toxicity. Air, water or soil can be polluted due to such pollutants. When environment is affected, ultimately these hazardous effects come back to human species. Therefore, such substances should be carefully used. Their use should be judicious and controlled.

(9) Health hazard: The substances that can cause hazard to our health should always be distanced from us. Such substances should not be kept in proximity. As far as possible they should be kept away and handled with great care if needed for any work. Materials marked with health hazard can cause severe toxicity.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 9.
Explain that why is it said like that?
a. Mock drill is useful.
Answer:

  • Mock drill is the practice to check whether there is preparedness for dealing with the sudden attack of disaster.
  • For this purpose, virtual or apparent situations that simulate the disaster are created.
  • The reaction time for any type of disaster is checked by such activity. In the presence of trained personnel, the execution of the rescue plans are observed.
  • People also understand their responsibilities at the time of actual disaster.
  • The experts also check execution of plan designed for disaster redressal.
  • By such mock drills, the efficacy of the system can be understood. In future, when actual calamity strikes, there is already preparation for disaster redressal. Therefore, mock drill is useful.

b. Effective disaster management makes us well prepared for future.
Answer:

  • Disaster can strike any time. The sudden disasters can be man-made with some bad intentions or may be accidental.
  • When natural calamity strikes suddenly with a huge impact, large scale devastation of property and general environment degradation occurs along with substantial mortality of people and animals.
  • Therefore, it is most appropriate to have the preparedness to reduce the impact of any future disasters.
  • We cannot control the onset of the natural disaster, but we can definitely reduce the harsh effects of the disaster by following disaster management plan.

Question 10.
Complete the following chart.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 8
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 9

Question 11.
Following are the pictures of some disasters. How will be your pre and post-disaster management in case you face any of those disasters?
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 10
Answer:
In the pictures given, following disasters are shown:
(1) Two groups of children are fighting with each other.
(2) There is gas leakage from the LPG cylinder.
(3) There is heavy downpour due to cloud bursting which has led to waterlogging in the town.
(4) There is cyclone causing a tornado. (Commonly called a twister)
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 11
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 12

Projects:

Project 1.
Demonstrate the activities shown on page no. 106 of Std. IX Science and Technology textbook in front of the students of other classes. Make a video clip and send it to others.

Project 2.
Form a group of students from your school to demonstrate the mock drill and demonstrate it in the school

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Can you recall? (Text Book Page No. 109)

Question 1.
What is disaster?
Answer:
Disaster is the incidence that occurs suddenly causing heavy damage to life and property. The disaster can be man-made or due to natural reason.

Question 2.
Which disasters have you experienced in your area?
Answer:
On September 2019, there was a heavy downpour in Pune. This disaster has been experienced recently.
On 26th November 2008 there was attack at several places by the Pakistani terrorists. The stories about the deaths and damage caused by this disaster were seen in films and learnt about this from our elders.

Question 3.
What are the effects of that disaster on local and surrounding conditions?
Answer:
Due to a heavy downpour in Pune, there was waterlogging in all the shallow areas. All the transport systems collapsed on that day. Large trees fell down injuring the people. The water logging caused condition like floods. Schools, colleges and offices were shut down. People were caught in troublesome situation.

On 26th November 2008 many innocent people lost their lives. There was tremendous damage caused to some of the important places like Taj Palace Hotel and Chabad house.

Use your brain power: (Text Book Page No. 111)

Question 1.
Depending upon information given on page 111, explain the various effects of the disaster of railway accident.
Answer:
The effects of disastrous railway accident:
The effect will be dependent upon the nature of the accident that has occurred. Whether, it is a collapse of bridge or due to derailment of the train, or due to collision of two moving trains, whether it is due to failure in signaling system, due to land slide or due to obstacle in the tunnel, that has to be understood. The impact of such railway accident will be dependent on the way that accident has occurred. Based on this impact the effects will take place.

(1) Environmental The entire surroundings will show destruction.
(2) Administrative/ Managerial The railway department will have stress and the time table will collapse. The regular use of tracks will hamper, resulting into delay in railway traffic.
(3) Political Ministry of railways is considered to be responsible for the accident. Sometimes the Railway Minister resigns.
(4) Medical The passengers commuting in the train die or suffer from serious injuries.
(5) Economic The railways suffer huge financial loss.
(6) Social The railway traffic is disturbed. Passengers are troubled as they get held up at some place.

Observe/Discuss:
Let’s Discuss: (Text Book Page No. 110)
Question 1.
observe the images on textbook page no. 110. whether the places of disasters are known to you? Discuss the emfects of these disasters on public lire. How people could lave been saved from these disasters? Discuss with your friends in the classroom.
Answer:
Students should discuss the disasters given in the pictures by themselves after collecting the information.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Observe: (Text Book Page No. 114)

Question 1.
Observe the disaster cycle given below and explain each aspect of the disaster of earthquake.
Answer:
The main aspects of disaster cycle to tackle disaster of earthquake are as follows:
(1) Preparation : With the help of seismograph, the warning about forthcoming earthquake can be obtained these days. The intensity of the earthquake is also predicted with the help of technology. If the estimate of the Richter scale is on the higher sides, there would be more preparatory measures taken to tackle the forthcoming problem of earthquake.

(2) Redemption: Once this information is obtained the possible impact of the earthquake on the houses, buildings, people can be studied by the geological experts. The meetings of the Disaster Management Authority will be organized for same.

(3) Preparedness: What the general public should do and what action the reserved forces should take, will be decided in case of actual incidence of the earthquake. The schemes and plans will be made ready in this direction.

(4) Impact of Earthquake: In case of disaster of earthquake, people will be helped to safety. The trapped people will be rescued. First aid and other necessary help will be provided. The data about the losses and the intensity of this disaster will be noted and reported for the further process.

(5) Response: In this phase the response of the people as well as the action of Government can be well studied. The response should be quick and positive. The maximum lives and property should be saved by such responses. The disaster of earthquake should be managed with positivity and through help given to the sufferers.

(6) Resurgence: Earthquakes can destroy the entire households or even entire community. Such homeless people should be given the place to stay. Resurgence is important phase for the national welfare. If the citizens of India are cared for, the nation too will progress.

(7) Restoration: The earthquake victims should be settled by providing them with new settlements. Sometimes, entire village is to be settled. E.g. In Latur or Kutch, there twas very large scale devastation. But Government of India as well as some NGOs helped to reconstruct the houses. In such earthquake-prone areas, houses are built in specific pattern to withstand any possible future calamities.

Observe: (Text Book Page No. 117)

Question 1.
Give the reference of following pictures and explain importance of each of those in disaster management. Which are other such activities ?
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 13
Answer:
The actions shown in the above pictures are as follows:
(a) The patient is made to lie on the stretcher. He must be unconscious and injured to greater extent, so that he cannot move by himself.
(b) The patient is helped by giving artificial respiration. Probably the victim is suffocated and needs oxygen supply.
(c) and (d) The patient is being picked up. Most probably the patient is unconscious.
The unconscious person who cannot move by himself is carried by these two methods. In method ‘c’, the weight of the patient is less and hence he can be lifted as shown in the picture. In picture ‘d’ the victim has to be lifted in other way, may be due to his greater body weight.
(e) The patient is carried on the back as in ‘carrying piggy back’ position. He too is unconscious and needs to be shifted for medical treatment.
(f) The patient in this picture is carried by ‘human crutch method’. When victim’s one leg is injured, he cannot walk without support. Hence, he needs to be carried in such a way.

In all the above methods, the injured person at the time of disaster is transported to hospital or dispensary for further medical help. The primary first-aid is given to the victim. Now the volunteer is taking him for further treatment. Such rescue activities depend upon the type of disaster and the extent of the injury. Hence the methods will be of different nature.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Let’s Think: (Text Book Page No. 111)

Question 1.
What will be the effect on yourself and surrounding, if any accident-like disaster occurs during the sports on playground or in school?
Answer:
When in school, there is an accident, first of all we get scared. But with caring help of the teacher, we will give the first aid to the injured friends by using first aid kit. If the injury is serious, we will take him to the medical centre of the school. While playing or during sports event, children flock around and make unnecessary crowding. In case of such accident, first of all the crowd will have to be dispersed. If there is major disaster, one should not fumble but manage the disaster in a wise way with the help of teachers.

Let’s Think: (Text Book Page No. 112)

Question 1.
Explain the nature and scope of the disaster of flood with the help of six points given on text book page no. 112.
Answer:
The nature and the scope of the disaster of flood can be described according to the six points:
(1) Pre-disaster phase: Due to Indian Meteorological Department the warning predictions are received before any climatic disaster strikes. If the scope of the flood is predicted to be high, then the people who may be affected by the calamity are relocated to a safer area.

(2) Warning phase: In the warning phase the Government warns the general public about the forthcoming disaster of floods through mass media like radio, television, newspapers, etc. In recent times, even the cellphone messages are sent to people for warning them. The people living in coastal areas will be worst affected and hence such people are given greater care and they are immediately made to leave their houses. They are taken to the safe places.

(3) Emergency phase: When the flood waters actually start rising up, the low-lying areas are submerged. Houses, roads and shops everything goes under water. The rescue operations are carried out by army men from National Disaster Rescue Force. They take every possible effort to rescue the trapped people. The emergency continues till the water does not recede. Later after the water starts receding, people who had been taken to places on heights, start coming back. During this phase, search, rescue operations, medical treatment, and first aid are all the aspects on which the attention is focussed.

(4) Rehabilitation phase: The people affected due to floods are given emotional and financial support. The fields, farms, houses or cattle-shed are under water. Such people are given transient accommodations. Many cattle and other animals die by drowning. Their rotting carcasses have to be disposed as soon as possible because the decaying process spreads epidemics of diseases. People are given vaccinations to protect them from diseases of such kind. Special care of young children and senior citizens is taken during this period. Supply of food and drinking water is also very important task during this time.

(5) Recovery phase: During recovery phase, the life comes gradually back to normalcy. The removal of dead, decaying material and the debris is the first priority. The water connections and electricity is restored back. Various NGOs or Government organizations provide help of various kind to the affected people. This help is to be distributed to those who are in real need. This work is also done by Disaster Management Department.

(6) Reconstruction phase: The houses and building that collapse due to floods are built back. Agricultural activities start again. Roads and water supply is once again normalized. Schools and colleges start once again. Thus, the once flood affected area comes back to routine functioning again.

Let’s Think: (Text Book Page No. 117)

Question 1.
Following are some pictures of disasters. Which precautions would you take during those disasters?
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 14
Answer:
The pictures shown above are showing earthquake, fire and snake bite respectively.
In the above disasters, the initial precautions to be taken are as follows:
(1) Earthquake: In case of earthquake, one should immediately come out of house and stand in the open ground. If this is not possible, one has to go below table or any other cover. During collapse of the building, there should not be a head injury. This precaution is basically for prevention of dangerous injuries and saving our life. Switch off the power supply. If in journey, stay inside the vehicle.

(2) Fire: First and foremost is to save ourselves from fire. Then one can help others in rescue operations. Help others to extinguish fire. Call the fire department for immediate action.

(3) Snake bite: Many a times the biting snake can be non-venomous too. But the victim is psychologically affected too. The tourniquet should be tied in the region above the snake bite. The rope, piece of cloth or even handkerchief can be used for this purpose, so that the venom, if any should not rise and reach vital organs. The wound should be made near the bite-wound so that the blood will ooze out and some venom can automatically flow out. Though these are first-aid measures, the victim should be rushed to a qualified doctor for an injection of antivenin.

Choose the correct alternative and write its alphabet against the sub-question number:

Question 1.
Disasters definitely affect the ………… of the nation.
(a) people
(b) economy
(c) security
(d) employment
Answer:
(b) economy

Question 2.
If local ………… is not strong enough, citizens become confused.
(a) leadership
(b) women
(c) politicians
(d) cattle
Answer:
(a) leadership

Question 3.
…………… problems arise diming the disaster.
(a) Local
(b) Global
(c) Administrative
(d) Private
Answer:
(c) Administrative

Question 4.
Stinking pollution caused due to decomposing corpses of humans and other animal is ………… disaster.
(a) environmental
(b) health
(c) necessary
(d) effective
Answer:
(a) environmental

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 5.
After the subsidence of any type of disaster, rehabilitation work is started in ………… phase.
(a) later
(b) transitional
(c) terminal
(d) ultimate
Answer:
(b) transitional

Question 6.
…………. phase is highly complicated phase.
(a) Reconstruction
(b) Recycling
(c) Reuse
(d) Redevelopment
Answer:
(a) Reconstruction

Question 7.
There had been a huge ……….. in the village Malin, Tal. Ambegaon in 2014.
(a) earthquake
(b) storm
(c) landslide
(d) change
Answer:
(c) landslide

Question 8.
The atomic energy plant at Chernobyl was used only for generating ………….
(a) electricity
(b) solar power
(c) atomic energy
(d) agriculture
Answer:
(a) electricity

Question 9.
Supply of essential ………….. to the affected people can reduce the effect of the disaster.
(a) food
(b) water
(c) commodities
(d) money
Answer:
(c) commodities

Question 10.
Keeping …………. ready is a practice to check the preparedness of facing the disaster.
(a) First aid
(b) Mock drill
(c) Ambulance
(d) Fire brigade
Answer:
(b) Mock drill

Question 11.
Which of the following is man-made disaster. (March, July ’19)
(a) Earthquake
(b) Flood
(c) Meteor
(d) Leakage of toxic gases
Answer:
(d) Leakage of toxic gases

Question 12.
What should be done if gas cylinder at your house catches fire?
(a) Water should be sprinkled
(b) Sand, soil should be put on it
(c) Cylinder should be covered with wet blanket
(d) one should run away
Answer:
(c) Cylinder should be covered with wet blanket

Which type of disaster is described in the following statements:

Question 1.
On 26th July 2005, entire suburban Mumbai was waterlogged.
Answer:
Cloudbursting and severe downpour

Question 2.
Elephants in the Bandipur forest started running helter and skelter due to smoke.
Answer:
Forest fires

Question 3.
Many innocent people died in the bomb blast that occurred on 11th July 2006 in local trains.
Answer:
Bomb explosion-Terrorism

Question 4.
In Kutch, suddenly many school children were buried under the rubble.
Answer:
Earthquake

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 5.
Because of lack of crops, people from Vidarbha are migrating to other regions.
Answer:
Dry famine

Question 6.
The huge waves in Chennai engulfed many human lives in December 2004.
Answer:
Tsunami.

Find the correlation:

Question 1.
Earthquake in recent times : Gujarat, Latur : : Devastating floods in 2018 : ………….
Answer:
Earthquake in recent times : Gujarat, Latur : : Devastating floods in 2018 : Kerala/Assam

Question 2.
Toxic gas leakage: Accidental disaster : : war : …………..
Answer:
Toxic gas leakage: Accidental disaster : : war : Intentional

Question 3.
Sun spots : Atmospheric type of disaster : : Salinization : …………..
Answer:
Sun spots : Atmospheric type of disaster : : Salinization : Geological type of disaster

Question 4.
Pre-disaster management : Preparation and warning : : Post-disaster management : ………..
Answer:
Pre-disaster management : Preparation and warning : : Post-disaster management : Resurgence and restoration.

Match the columns:

Question 1.

Column A: Disaster Column B: Type
(1) Earthquake and volcano (a) Animal origin
(2) Snowfall and snowstorms (b) Geological
(c) Climatic
(d) Terrorism

Answer:
(1) Earthquake and volcano – Geological.
(2) Snowfall and snowstorms – Climatic.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 2.

Column A: Disaster Column B: Type
(1) Aquatic weeds (a) Animal origin
(2) Attack by locusts (insects) (b) Plant origin
(c) Geological
(d) Climatic

Answer:
(1) Aquatic weeds – Plant origin
(2) Attack by locusts (insects) – Animal origin.

Question 3.

Column A: Disaster Column B: Type
(1) Atomic tests (a) Intentional
(2) Terrorism (b) Unintentional
(c) Geological
(d) Animal origin

Answer:
(1) Atomic tests – Unintentional
(2) Terrorism – Intentional.

Question 4.

Column A: Effect Column B: Effect
(1) Contamination of water (a) Economical
(2) Collapsing of transport system (b) Environmental
(c) Administrative
(d) Geological

Answer:
(1) Contamination of water – Environmental
(2) Collapsing of transport system – Administrative.

Question 5.

Column A: Effect Column B: Problem
(1) Spread of epidemics (a) Economical
(2) Shortage of funds (b) Administrative
(c) Medical
(d) Physical

Answer:
(1) Spread of epidemics – Medical
(2) Shortage of funds – Economical.

Question 6.

Column A: Effect Column B: Problem
(1) Rift due to religions (a) Economical
(2) Citizens getting confused (b) Social
(c) Political
(d) Environmental

Answer:
(1) Rift due to religions – Social
(2) Citizens getting confused – Political.

Identify the type of disaster and describe the effects of the same in brief:

Question 1.
Accident at Chernobyl.
Answer:
Man-made, unintentional. At Chernobyl in Russia there was the atomic energy plant, where disastrous accident took place. The radiations emitted through the reactors caused tremendous radiation pollution. These hazardous effects are even seen today.

Give reasons:

Question 1.
When there are riots, the cities, towns or villages show signs of tense atmosphere.
Answer:

  • During riots, there is financial loss for all the rioting groups.
  • The belongings, houses, shops, etc. are destroyed or damaged.
  • Property is looted. There is no guarantee of safety and security for anyone.
  • Women and children suffer the most as they are easily victimized. Therefore, when there are riots, the cities, towns or villages show signs of tense atmosphere.

Answer the following questions in detail:

Question 1.
which are the disaters that make Impact for longer duration? Give examples.
Answer:
Those disasters that make the impact for long duration and those disasters, whose after-elfbcts are either severe are long term disasters. Their severity increases with thme. Such disasters are famine, various problems of growth of crop, strikes of workers, rising levels of oceans, desertification, etc.

Question 2.
What types of disaster are the following? Explain their impacts.
(a) Floods (b) War. (Board’s Model Activity Sheet)
Answer:
(a) Flood is geophysical climatic disaster.
(b) War is man-made intentional disaster.

Impact of flood : The low-lying and the coastal areas are seen to be submerged. The entire region is waterlogged.
Impact of war: Tremendous destruction causing loss. Many lives are lost. The costs of all the items rise due to war conditions. Entire nation faces insecurity.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 3.
Explain in brief the sensitive issues of general public about disaster.
(OR)
Which are the three aspects of disaster tjiat are important for common citizens?
Answer:
The phase of emergency, transitional phase and reconstruction phase are the three phases of disaster that are important for common citizens.

(1) Phase of emergency: If timely and rapid action is taken during this phase, maximum lives can be saved. Search and rescue operations, medical help, first aid, restoring communication services, removing the people from affected area are done during this phase. The gravity of disaster can be estimated during this phase.

(2) Transitional Phase: The disaster subsides and then the work of transitional phase starts. The main concern is rehabilitation work for the affected and displaced people. This work includes clearing of debris, restoring water supply, repairing roads, etc. to bring normalcy in public life. Help from different voluntary and Government institute is taken to offer the monetary provision and essential commodities to affected victims. Permanent means of livelihood is given to the people to reduce their mental and emotional stress. The victims are truly rehabilitated.

(3) Reconstruction Phase: Reconstruction phase is a highly complicated phase which actually overlaps with transition stage. Help is offered to people to reconstruct their buildings. Other facilities like roads and water supply are restored. Farming practices are restarted. It is a very gradual phase that makes the victims to completely rehabilitate.

Question 4.
What are the objectives of mock drill?
Answer:
Objectives of Mock Drill:

  • To evaluate the response of the people to the disaster.
  • To improve the coordination between various departments of disaster control.
  • To identify one’s own abilities if disaster approaches.
  • To improve the ability to quick response to disaster and taking rapid action.
  • To check the competency of the planned actions.
  • To identify the possible errors and risks while dealing with disasters.

Question 5.
Write down the names of international organizations that work for disaster management.
Answer:
Following international organizations work for disaster management.

  • United Nations Disaster Relief Organization
  • United Nations Centre for Human Settlements
  • Asian Disaster Reduction Centre.
  • Asian Disaster Preparedness Centre.
  • World Health Organization.
  • United Nations Educational, Scientific and Cultural Organization.

Question 6.
The building in which you are residing ( has caught fire on the ground floor. What necessary rescue steps will you take? (July ’19)
Answer:

  • We shall call out for help.
  • We shall immediately call fire brigade.
  • We shall try to extinguish fire with the help of other people.
  • We will give first aid to people who are injured, fill the medical help arrives.
  • We will cover our nose and mouth with moist cloth to prevent suffocation.

Write short notes:

Question 1.
Pre-disaster management.
Answer:
The management measures taken before onset of a disaster is called pre-disaster management.
In pre-disaster management, complete preparation and planning to face any type of disaster is done. For this purpose, following steps are taken.

  • Identifying the areas where the disaster can strike. Such disaster-prone areas are to be thoroughly studied.
  • Through predictive intensity maps and hazard maps, the information is collected about the intensity of disaster and probable sites of disasters respectively.
  • Special training for disaster management is given to the concerned people.
  • The mass awareness is created about disaster management through training programmes, mass media and internet, etc.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 2.
Post-disaster management.
Answer:
The management measures taken after the striking of a disaster is called post-disaster management.
Following steps are taken during post-disaster management:

  • Helping the victims of disasters by giving all possible help needed for their survival.
  • Local people are trained to take part in the disaster management so that affected people can be saved rapidly.
  • Establishing the help centres that could provide all the necessary help. Such centres will be different in case of different disasters.
  • Collection and categorization of the material received from control centre for helping the victims. Distributing the same and reviewing the measures continuously.
  • Disaster rescue programmes are mainly focused.

Some symbols are given below. Explain those symbols. Which disasters may occur if those symbols are ignored?

Question 1.
Write what the signs indicate:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 15
Answer:

  • Figure A indicates inflammable substances. They can catch fire if they come in contact with oxygen-rich air.
  • Figure B indicates corrosive substances which can cause damage to tissues of skin, eyes and other delicate organs etc.
  • Both the symbols are warning signs for people to keep away or handle carefully such substances.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 2.
What does the symbols below indicate? Write in brief. (Board’s Model Activity Sheet)
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 16
Answer:
(1) Symbol ‘A’ indicates Irritant. When skin or any delicate part of the body comes in contact with the irritant substance, it can cause harmful reaction. Especially, eyes, nasal mucosa and skin are affected by contact with corrosive substances.
(2) Symbol ‘B’ indicates toxic substance. To taste a toxic substance or even to smell it, can lead to death. The packing of these substances are therefore marked as dangerous. They should be avoided as far as possible.

Complete the paragraph by choosing the appropriate words given in the brackets:

(Capability, Rehabilitation, Commodities, Human, objectives, normalcy, amusements)
The ………. of disaster management comprise of the following aspects …………. life is saved from the disasters. People are helped to move away from the place of disasters. They are given essential ……….. by the government so that the gravity of disaster is reduced. The disaster conditions are brought back to ………… of the affected and displaced victims is done. Moreover, protective measures for future are also planned to develop ………… among the people to face any possible disasters in future.
Answer:
The objectives of disaster management, comprise of the following aspects. Human life is saved from the disasters. People are helped to move away from the place of disasters. They are given essential commodities by the government so that the gravity of disaster is reduced. The disaster conditions are brought back to normalcy. Rehabilitation of the affected and displaced victims is done. Moreover, protective measures for future are also planned to develop capability among the people to face any possible disasters in future.

Paragraph based questions:

1. Read the paragraph and answer the questions given below:
Disasters can be properly classified into three categories, viz. natural disasters, technological disasters and man-made disasters. The forces that cause natural disasters cannot be controlled. Moreover, they are becoming more frequent in the current years due to phenomena of climate change. On and off incidences of cyclones, cloud bursting, floods, etc. am creating havoc in the lives of people. Technological disasters are due to improper and callous behaviour at the different processes carried out in technical establishments. Man-made disasters are conflicts arising due to different religions, regions and-terrorism.

Questions and Answers:

Question 1.
What are three broad areas of disasters?
Answer:
Natural disasters, technological disasters and manmade disasters are three broad areas of disasters.

Question 2.
Which disasters cannot be controlled? Why?
Answer:
Natural disasters cannot be controlled as they are due to natural phenomena beyond the human power to stop them.

Question 3.
Which type of disasters were very common in Western Maharashtra in recent times? Why?
Answer:
Cloud bursting and floods were very common in Western Maharashtra caused due to climate change.

Question 4.
Give any one example of technological disaster that shook the entire India.
Answer:
Bhopal gas tragedy that occurred in 1984 was a worst disaster that shook the entire India.

Question 5.
Which types of disasters can be controlled in order to lead happy, peaceful and secured life? How?
Answer:
We have to control manmade disasters such as wars, riots, terrorism, etc. by having peaceful negotiations, respect for each human being and feeling of brotherhood among all.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Questions based on tables and charts:

Question 1.
Complete the chart: (Text Book Page No. 111)
Different problems occur with disasters. In the concept map different effects are mentioned. Read it and fill the blank places.
Answer:
(Answers are given directly in bold.)
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 17

Question 2.
Complete the chart: (Text Book Page No. 117)
Complete the chart as per the objectives of the first aidr:t
Answer:
(Answers are given directly in bold.)
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 18

Activity based questions:

Question 1.
Observe the images ‘A’ and ‘B’ and answer the following questions.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 19
(i) Which disasters are shown in the images ?
Answer:
Image A is showing damage due to earthquake. Image B is showing house on fire.

(ii) Which primary precautions will you take in case of disaster shown in ‘A’?
Answer:
In the above disasters, the initial precautions to be taken are as follows :
Earthquake: In case of earthquake, one should immediately come out of house and stand in the open ground. If this is not possible, one has to go below table or any other cover. During collapse of the building, there should not be a head injury. This precaution is basically for prevention of dangerous injuries and saving our life. Switch off the power supply. If in journey, stay inside the vehicle.

(iii) Which type of first-aid is offered to the injured people in disaster ‘B’?
Answer:
First aid given to burn victim:

  • The person who is injured by fire should be dotised with cold water on his/her body. This will extinguish fire and give some relief caused due to inflammation. Do not break the blisters. Give water to drink.
  • Cover the burnt part by wet and moist cloth. Wash the wounds with antiseptic solution.
  • If the person is severely burnt, transfer him/her immediately to hospital.

Question 2.
Correct the following diagram:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 20
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 21

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Projects:

Project 1.
Can you tell? ( Textbook page no. 118)
Whether there had been mock drill by fire fighters under the disaster management scheme in your school? Which techniques did you see during the drill?

Project 2.
Try this: (Textbook page no. 115)
Which factors will you consider while designing the pre-disaster management plan for your school/home? Prepare a survey report with the help of your teacher.

Project 3.
Get information:
(1) Visit the district collector or Taluka Tehasildar office and collect the information about disaster management. (Textbook page no. 115)
(2) Meet the medical officer/doctor from your village and collect information about providing the first aid. (Textbook page no. 118)

Project 4.
Internet is my friend:
(1) Search for the video clips of disasters. Discuss in your class about effects of disasters and remedies over it. (Textbook page no. 110)
(2) Find out more about the activities of international organizations that work for disaster management.
(Textbook page no. 116)
1. United Nations Disaster Relief Organization.
2. United Nations Centre for Human Settlements.
3. Asian Disaster Reduction Centre.
4. Asian Disaster Preparedness Centre.
5. World Health Organization.
6. United Nations Educational, Scientific and Cultural Organization.

Maharashtra Board Class 10 History Solutions Chapter 9 Heritage Management

Balbharti Maharashtra State Board Class 10 History Solutions Chapter 9 Heritage Management Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 10 History Solutions Chapter 9 Heritage Management

Question 1.
(A) Choose the correct option from the given options and complete the statement.
(1) Lovre Museum has in its collection the much-acclaimed painting of …………..…….. by Leonardo da Vinci.
(a) Napoleon
(b) Mona Lisa
(c) Hans Sloan
(d) George II
Answer:
(b) Mona Lisa

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(2) …………..…….. at Kolkata is the first museum in India.
(a) Government Museum
(b) National Museum
(c) Chhatrapati Shivaji Maharaj Vastusangrahalay
(d) Indian Museum
Answer:
(d) Indian Museum

(B) Identify and write the wrong pair in the following set.
(1) Maharaja Sayajirao University – Delhi
(2) Banaras Hindu University – Varanasi
(3) Aligarh Muslim University – Aligarh
(4) Jivaji University – Gwalior
Answer:
(1) Wrong Pair: Maharaja Sayajirao University – Delhi

Question 2.
Explain the following statements with reasons.
(1) Archives and libraries publish research journals, informative pamphlets, leaflets, posters, etc.
Answer:

  • Libraries preserve and conserve old’ books and artefacts discovered during excavation.
  • If these documents and artefacts are not exhibited then they are kept in archives.
  • All the historical sources are our assets and they should reach the people.
  • Libraries not only preserve these documents but also carry out research, to know the authenticity.

In order to make the historical events, personalities, and historical research known to the people, archives and libraries publish research journals, informative pamphlets and leaflets.

(2) Only trained persons, who are duly qualified can take up the tasks involved in the work of conservation and preservation.
Answer:

  1. While conducting historical research, one has to do the different tasks carefully like collecting sources, preserving, exhibiting, etc.
  2. The skill required for every task is different. The procedure followed for each task is different as well as the preliminary preparations.
  3. It is essential to know about precautions to be taken.
  4. Hence only trained persons who are duly qualified can take up the tasks involved in the work of conservation and preservation.

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Question 3.
Write notes:
(1) Sthalakosh
Answer:

  • History does not shape itself in oblivion. It takes place at some place.
  • Geographic information is essential to study history.
  • Chakradhar Swami, of Mahanubav sect, visited many villages and details of those villages were noted by Muni Vyas.
  • Siddheshwarshastri Chitrav wrote Prachin Bharatiya Sthalkosh. It gives us information on various places mentioned in Vedic literature, Kautiliya’s Arthashastra, Panini’s Grammar, Ramayana.
  • Mahabharata and also in Buddhist Jain Greek, Chinese and Persian literature.
  • Sthalakosh gives us information on ancient cities and history of those cities. It serves as an important written source of history.

(2) Vishwakosh
Answer:

  • The first Chief Minister of Maharashtra, Shri Yashwantrao Chavan, established the ‘Maharashtra Rajya Sahitya Samskruti Mandal.
  • The objective of making Vishwakosh was to develop and enhance Marathi language and literature.
  • Tarkteerth Lakshmanshastri Joshi was appointed as the chief editor. 20 volumes of Vishwakosh are published till date.
  • Marathi Vishwakosh contains knowledge about all possible subjects which exist in the world. It has important entries about history.

(3) Samdnya Kosh
Answer:

  1. While studying any subject we come across many new words. If their exact meaning is not understood, it can create a lot of confusion.
  2. Terms in history like colonialism, imperialism, liberalisation, globalisation, socialism, communism need explanation and clarity. In order to avoid such confusions, this kosh is prepared.
  3. In Samdnya Kosh, all subject related concepts are collected and explained. Information on what led to the development of concepts is provided.
  4. Samdnya Kosh is very helpful for research students, teachers of history as well as common people.

(4) Saraswati Mahal Granthalay
Answer:

  • The Saraswati Mahal Granthalay was built in 16-17th century in Tanjavur, Tamil Nadu during the reign of Nayak Dynasty.
  • In 1675, Maharaj Vyankojiraje Bhosale conquered ‘ Thanjavur and established his independent rule. He and his successors contributed to the expansion of this library. ‘
  • Sarfojiraje Bhosale contributed the most in expanding and enriching the library. Because of his contribution, to honour him, the library was renamed as ‘The Thanjavur Maharaj Sarfoji’s Saraswati Mahal Library’.

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Question 4.
Give elaborate answers to the following.
(1) Why is library management important?
Answer:
Library is not just about a collection of books but managing it is equally important.

  • Readers can easily get the books they want if the library is properly organised.
  • The location of the book should be easily traced. It saves the time and efforts of readers as well as the librarian.
  • Preservation and conservation of books is done effectively with proper management. It prolongs life of books and causes less damage.
  • If the management is well acquainted, they will have good collection that will make available good quality books to reader.
  • Instead of collecting books on one subject there should be variety in the collection so as to cater of different readers who are very selective in their choices.
  • Facilities like proper catalogues, indexes, computerised systems and modern facilities are provided by effective management of library.
  • If the management is creative it will organise exhibitions, advertise, have seasonal offers for vacations, conduct competitions to increase membership.

(2) Which tasks are important in archives management?
Answer:
The following tasks are important in archives’ management:

  • Important documents to be preserved and care should be taken that document with important contents are preserved in their original condition. Confidentiality of important papers should be maintained.
  • To classify the documents by preparing indexes and to create accurate systems of retrieval of documents.
  • Documents from the archives are supposed to be very reliable.
  • Therefore, it is important to safeguard the papers from humidity, fungus and other environmental factors.
  • It is important to remain updated with latest technology in archive management.
  • Computerise/Digitalse all systems. To make use of information technology in managing libraries and archives.
  • To establish regional and local archives*.
  • To preserve national, cultural and historical heritage.
  • To create a hasslefree system.

Question 5.
Complete the following Concept chart.
Maharashtra Board Class 10 History Solutions Chapter 9 Heritage Management 1
Answer:
Maharashtra Board Class 10 History Solutions Chapter 9 Heritage Management 2

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Project
Obtain information about the important libraries in Maharashtra. Visit the library in your vicinity and learn about its functioning.

Question 6.
Complete the sentences by choosing the correct option:
(a) Documents and artefacts which are not exhibited are kept in …………………… .
(a) Museum
(b) Library
(c) Archives
(d) Government office
Answer:
(c) Archives

(b) ……………………. was the 16th century artist who worked under the patronage of French King Francis I.
(a) Leonardo-da-Vinci
(b) Michaelangelo
(c) Raphael
(d) Dante
Answer:
(a) Leonardo-da-Vinci

(c) The collection in ……………………. increased to a great extent because of the antiquities brought by Napoleon Bonaparte.
(a) National Museum of Natural History
(b) British Museum
(c) Louvre Museum
(d) The Calico Museum
Answer:
(c) Louvre Museum.

(d) ……………………., a natural scientist handed over about 71 thousand objects in his collection to the British Museum.
(a) Sir Hans Sloan
(b) King George II
(c) Napoleon Bonaparte
(d) King Francis I
Answer:
(a) Sir Hans Sloan

(e) The Museum of Natural History which 8 houses more than 12 crore specimens of fossils is in ……………………. .
(a) England
(b) France
(c) Switzerland
(d) USA.
Answer:
(d) USA

(f) Chhatrapati Shivaji Maharaj Vastu-sangrahalay was built to commemorate the visit of ……………………. .
(a) King George I
(b) Queen Elizabeth
(c) Prince Charles
(d) Prince of Wales
Answer:
(c) Prince of Wales

(g) The building of Chhatrapati Shivaji Maharaj Vastusangrahalay is built in ……………………. style.
(a) Mughal
(b) Indo-Greek
(c) Indo-Gothic
(d) Indo-Persian
Answer:
(c) Indo-Gothic

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(h) ……………………. is given status of Grade I heritage building in Mumbai.
(a) Chhatrapati Shivaji Maharaj Railway Terminus
(b) Chhatrapati Shivaji Maharaj Vastusangrahalay
(c) Reserve Bank of India
(d) Jehangir Art Gallery
Answer:
(b) Chhatrapati Shivaji Maharaj Vastusangrahalay.

(i) The Royal Library of Ashurbanipal, the ……………………….. Emperor in Mesopotamia is one of the earliest libraries in the world.
(a) Hispanic
(b) Assyrian
(c) Mongol
(d) Akkadian
Answer:
(b) Assyrian

(j) The ……………………….. in Thanjavur, Tamil Nadu was built in 16th-17th century during the times of Nayak dynasty.
(a) Vyankojiraje Bhosale
(b) Sarfojiraje Bhosale
(c) Saraswati Mahal Granthalay
(d) Vidya Niketan
Answer:
(c) Saraswati Mahal Granthalay

(k) The first official archives of India, the ……………………….. was established in 1891 C.E. in Kolkata.
(a) National Archive
(b) Federal Record of Nation
(c) Archive National
(d) Imperial Record Department
Answer:
(d) Imperial Record Department

(l) There are about five crore Modi documents related to Maratha history in the Pune branch which are referred as ………………………. .
(a) Peshwa Daftar
(b) Bhosale Daftar
(c) British Daftar
(d) Maratha Daftar
Answer:
(a) Peshwa Daftar

(m) ……………………….. prepared during the reign of Chhatrapati Shivaji Maharaj is considered as an important encyclopaedia.
(a) Bharatiya Vyavahar Kosh
(b) Rajavyavaharkosh
(c) Vyavaharik Kosh
(d) Bharatiya Prachin Charitrakosh
Answer:
(b) Rajavyavaharkosh.

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Question 7.
Identify the wrong pair in the following and write it:
(1)

(1) Maharaj Sayajirao University Delhi
(2) Banaras Hindu University Varanasi
(3) Aligarh Muslim University Aligarh
(4) Jivaji University Gwalior

Answer:
Wrong Pair: Maharaj Sayajirao University – Delhi.

(2)

(1) Sangeetshastrakar va Kalavant Yancha Itiha£ Lakshman Dattatray Joshi
(2) Krantikarakancha Charitrakosh S. R. Date
(3) Svantantryasainik Charitrakosh N. R. Phatak
(4) Bharatvarshiya Prachin Aitihasik Kosh Shridhar Vyankatesh Ketkar

Answer:
Wrong Pair: Bharatvarshiya Prachin Aitihasik Kosh – Shridhar Vyankatesh Ketkar

(3)

(1) Bharatvarshiya Charitrakosh Siddeshwar Shastri Chitral
(2) Marathi Vishwakosh Raghunath Bhaskar Godbole
(3) Bharatiya Samskruti Kosh Pandit Mahadevshastri Joshi
(4) Maharashtriya Dnyankosh Shridhar Vyankatesh Ketkar

Answer:
Wrong Pair: Marathi Vishwakosh – Raghunath Bhaskar Godbole

(4)

(1) Sthanapothi Muni Vyas
(2) Index of Marathi Periodicals S. G. Date
(3) First Encyclopaedia of Natural History Denis Diderot
(4) Asiatic Society of Bengal First museum in India

Answer:
Wrong Pair: First Encyclopaedia of Natural History – Denis Diderot

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Question 8.
Complete the following concept chart:
(1)
Maharashtra Board Class 10 History Solutions Chapter 9 Heritage Management 3
Answer:
Maharashtra Board Class 10 History Solutions Chapter 9 Heritage Management 4

(2)
Maharashtra Board Class 10 History Solutions Chapter 9 Heritage Management 5
Answer:
Maharashtra Board Class 10 History Solutions Chapter 9 Heritage Management 7
(3)
Maharashtra Board Class 10 History Solutions Chapter 9 Heritage Management 8
Answer:
Maharashtra Board Class 10 History Solutions Chapter 9 Heritage Management 9

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Question 9.
Explain the concept :

(a) Archives:
Answer:

  1. An archive is a place where documents with important content in their original conditions are preserved in a scientific manner.
  2. Artefacts and documents which are not exhibited in museums or libraries but have historical importance are kept in archives.
  3. Archives provide documents to the § government, research students and local public when required. Technically, the management of archives is akin to library management.
  4. The documents in the archives are preserved in their original condition and hence no changes can be made to it. Documents from archives are very reliable.

(b) Encyclopaedia:
Answer:

  1. Encyclopaedia can be defined as a systematic compilation of words with meaning, information or knowledge on various topics.
  2. A specific method is adopted to compile the information or to organise the available knowledge. g
  3. Accuracy, meticulousness, objectivity, standardised format of presentation and updated information are the special features of good encyclopaedia.
  4. The objective of making an encyclopaedia is to make the available knowledge easily accessible to the readers.

(c) Dictionaries:
Answer:

  • A type of encyclopaedia giving word meaning arranged in alphabetical order is a Dictionary.
  • Dictionaries help the readers to know meaning of the words and enrich their vocabulary.
  • Dictionaries have word meanings, synonyms and etymology.
  • Dictionaries are of various type like comprehensive dictionaries, dictionaries of terminology, etymology, thesaurus and dictionaries of idioms and proverbs.

(d) Comprehensive Encyclopaedia (Vishwakosh):
Answer:

  • Comprehensive Encyclopaedia (Vishwakosh) means a book which has information on all subjects known, i.e. all subjects under the sun.
  • Vishwakosh is an important medium” of documenting and disseminating information.
  • The information is included in encyclopaedia after thorough research and study.
  • (a) There are two types of encydopaedias – one that includes all subjects like ‘Encyclopaedia Britannica’, Maharashtriya Dnyankosh, Marathi Vishvakosh.
    (b) The other type of encyclopaedia includes comprehensive information on one chosen subject, e.g. Bharatiya Samskruti Kosh, ‘Vyayam Dnyankosh1.

(e) Index:
Answer:

  • Index means a list.
  • Index is at the end of a book which includes alphabetical lists of individuals, subjects, key words, reference books, etc.
  • As the list is in alphabetical order, the reader finds it easy to access required information.
  • The index of Marathi periodicals prepared by S. G. Date and index of ‘Marathyancha Itihasachi Sadhane1 is well-known.

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(f) Charitrakosh (Encyclopaedia of Biographies):
Answer:

  1. Charitrakosh contained biographies of individuals who lived in a particular period and their work which inspired and motivated all the people in the society.
  2. Charitrakosh enables the researcher and scholars to know about the historic period, with regard to social structure and social life.
  3. Bharatvarshiya Prachin Aitihasik Kosh written by Raghunath Bhaskar Godbole is the earliest encyclopaedia of this kind.

(g) Bharatiya Samskruti Kosh:
Answer:

  • It contains the description of Indian history, geography, religions, sects, culture, traditions, beliefs, ethnic and lingual groups residing in our country.
  • Bharatiya Samskruti Kosh throws light on, people living in a particular region, festivals and their culture.
  • Mahadevshastri Joshi edited and published 10 volumes of this Kosh.
  • Chakradhar Swami, of Mahanubav sect, visited many villages and details of those villages were noted by Muni Vyas.

Question 10.
Write short notes:
(a) Louvre Museum:
Answer:

  • The Louvre Museum in Paris was established in the 18th century.
  • It has antiquities collected by the royal family of France.
  • The world famous painting of Mona Lisa by Leonardo-Da-Vinci is kept in this museum.
  • The antiquities brought back by Napoleon Bonaparte on his return from conquests are exhibited in this museum.
  • Presently, the museum has more than 3 lakh and 80 thousand artefacts.

(b) British Museum:
Answer:

  • The British Museum was established in the 18th century in London.
  • It has a collection of 71 thousand objects given by natural scientist Sir Hans Sloan to King George. II.
  • Several books, pictures, specimens of preserved plants are included in it.
  • The ancient objects and artefacts which the Britishers have collected from their colonies are exhibited in this museum.
  • At present, it has about 80 lakh objects in its collection.

(c) National Museum of Natural History:
Answer:

  • The National Museum of Natural History was established in Washington DC in 1846.
  • The Smithsonian Institute managed the museum from its inception. This is a museum of natural history.
  • Remains of animals, plants, organisms and thousands of specimens of fossils are kept in it.
  • It also has human fossils, minerals, rocks, shells, artefacts. All together it has a collection of more than 12 crore (120 million).

(d) Chhatrapati Shivaji Maharaj Vastusangrahalay:
Answer:

  1. Chhatrapati Shivaji Maharaj Vastusangrahalay was built to commemorate the visit of Prince of Wales to India. Some influential residents in Mumbai decided to establish a museum in 1904.
  2. The foundation of the building was laid on 2nd November 1905 and the construction was completed in 1922. The museum was named as ‘Prince of Wales of Western India’. In 1998 C.E. it was renamed as ‘Chhatrapati Shivaji Maharaj Vastusangrahalay.’
  3. The museum building is constructed in Indo-Gothic style and has been awarded the status of Grade I heritage building.
  4. The museum has about 50 thousand antiquities which are divided into three categories, viz.. Arts, Archaeology and Natural History.

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(e) Bharatvarshiya Prachin Aitihasik Kosh:
Answer:

  • Raghunath Bhaskar Godbole wrote Bharatvarshiya Prachin Aitihasik Kosh.
  • It is the first dictionary of Biography in Indian regional language.
  • We get information on Manu and many ancient personalities from Mahabharat.
  • We come to know about legendary people who lived in Bharatvarsha and were renowned.
  • Information about their women, their sons, religions, lands, capitals, mountains and rivers.
  • Which flowed in their land their entire history is given in this encyclopaedia.

(f) Bharatiya Samskruti Kosh:
Answer:

  • Pandit Mahadevshastri Joshi edited and published 10 volumes of Bharatiya Samskruti Kosh.
  • He wrote about Indian history, geography, about people speaking different languages and how they created history.
  • Detailed information on culture of India and festivals, geography, traditions, ideas, is taken into consideration.

Therefore these koshs are useful for readers and research scholars.

Question 11.
Explain the following statements with reasons:

(a) Encyclopaedias should be created in as many languages as possible.
Answer:
Encyclopaedias symbolise the richness and vast gamut of words a language has.

  • It fulfils the curiosity of readers and solves the confusion of a layman.
  • Encyclopaedias inspire to carry out more research as one gets information, knowledge and references.
  • Encyclopaedias provide complete information and knowledge to researchers and students which enriches their previous knowledge.
  • Encyclopaedias represent intellectual and cultural development of a society.
  • Many languages in India and the world are rich and resourceful and hence encyclopaedias should be created in as many languages as possible to raise intellectual level of society.

(b) Encyclopaedia and history are related.
Answer:

  • Encyclopaedias contain information about personalities, events and ancient cultures.
  • In order to gather information it is essential to take the help of history,
  • The common factors between an encyclopaedia and history are objectivity and authenticity.
  • Research scholars of history need to refer to encyclopaedias to find information on events, personalities, concept, places, etc. as encyclopaedias are created with the help of history. Hence encyclopaedia and history are related.

(c) Improved versions of Encyclopaedia or supplements to original editions need to be published.
Answer:

  1. Encyclopaedia is a systematic compilation of information or knowledge on various topics ranging from people, places and events to concepts, word meanings, etc.
  2. With the passage of time the spectrum of knowledge has widened.
  3. With the advent of new technology new words are added. Latest or updated information, knowledge, concepts enrich the language.
  4. The references of the past events change in context of the new research. If all these changes are not incorporated in the encyclopaedias, they will become outdated.

Therefore, encyclopaedia or supplements to original editions need to be published.

Question 12.
Answer the following questions in 25-30 words:
(a) What are the ways to preserve and conserve oral resources?
Answer:

  • Folk songs ancl folk tales are collected and compiled.
  • Collected material is classified. It is interpreted and analysed after compilation.
  • The result of research conducted is then published.

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(b) What steps are taken to preserve written sources?
Answer:
Written sources have great importance in the writing of history. To preserve written sources we need –

  • To collect old books, historical books, pictures, photographs, copper plates, manuscripts and official records and edit them.
  • To decide upon the historical values of collected documents.
  • To exhibit the selected documents.
  • To publish edited documents and research reports.
  • To complete necessary chemical and mechanical process of cleaning for conserving and preserving the documents.

(c) What methods should be followed while studying material source?
Answer:
The following methods should be followed by research scholars while studying material source:

  • To collect the artefacts and classify them according to their historical date and type and prepare indexes.
  • To arrange exhibitions of selected artefacts or their replicas.
  • To write and publish research articles about artefacts.
  • To complete required mechanical and chemical processes of cleaning for conservation and preservation of the collected documents.

(d) Write about the earliest libraries in the world.
Answer:
Libraries were established in different parts of the world in ancient times:

  • The Royal Library of Ashurbanipal is the earliest library dating back to the 7th century B.C.E. in Mesopotamia. The library was owned by the Assyrian emperor.
  • A library was discovered at Alexandria in Egypt which was built in 4th century C.E.
  • The library at Takshashila university in 5th century B.C.E. – 5th century C.E. as it was a noted centre of learning.

(e) Write about format of Encyclopaedias.
Answer:
Format of Encyclopaedias:

  • Encyclopaedias are made according to selected subjects; therefore encyclopaedias are classified according to the subjects.
  • Encyclopaedias are framed according to alphabetical order or as per the order of topics.
  • They provide the exact meaning of words and give information on concepts.
  • The type of order is kept according to the convenience of the readers. An index is provided at the end of the encyclopaedia for this purpose.

(f) Write about Encyclopaedic Literature.
Answer:

  • It appears similar to an encyclopaedia but differs in composition.
  • Information and scholarly articles on all possible aspects of a subject is covered.
  • Experts are called to write on different topics which are compiled to create encyclopaedia
  • ‘Maharashtra Jeevan’ Volume I and II; ‘Shahar Pune’ Volume I and II; Yearbook like Manorama, etc. are the examples of Encyclpaedic Literature.

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(g) Give information on early encyclopaedias made in the west.
Answer:

  • The process of making encyclopaedias started in before 1st century C.E. in the west. Pliny wrote the first encyclopaedia on natural history between 23 C.E.-79 C.E.
  • In the 8th and 9th century, encyclopaedias were written in England, France and in Arab countries.
  • French Philosopher Denis Diderot wrote Encyclopaedia in the 18th century C.E.
  • The important milestone in this process was ‘Encyclopaedia Britannica’ published in 1767 C.E.
  • Wikipedia is considered equivalent to encyclopaedia. The information given in this encyclopaedia is highly reliable and updated.

(h) Write about ancient Indian encyclopaedias.
Answer:

  • In the 7th century C.E., Nighantu, a dictionary (information on ancient medicine) in Sanskrit language was written. Dictionaries like Dhatupath were written.
  • In tjie medieval times, encyclopaedic text was composed by Mahanubhav sect.
  • Amarsimha wrote a thesaurus in Sanskrit ‘Amarkosha’.
  • Raghunath Pandit prepared Rajavyavaharkosh as directed by Chhatrapati Shivaji Maharaj.

Question 13.
Read the following passage and answer the following questions:
(a) Which factors influence Encyclopaedia?
Answer:
The influence of national policies, ethical values and ideals, philosophy and traditions is seen in an encyclopaedia.

(b) What is the common factor between history and encyclopaedia?
Answer:
History and encyclopaedia both are objective.

(c) Explain the statement: Encyclopaedias are looked upon as outstanding achievements of a society.
Answer:

  • The knowledge in all the spheres of society is made accessible to everyone is the major reason behind making an encyclopaedia.
  • What inspires people to create encyclopaedias is the instinct to gain knowledge and spread it.
  • Encyclopaedias reflect the collective intellect and creativity of society.
  • One develops a sense of pride after knowing about nation’s progress through it.

Hence encyclopaedias are looked upon as outstanding achievements of a society.

Question 14.
Give elaborate answers to the following: (3 marks each)

(a) What kind of training is required to study written sources?
Answer:
While studying and handling written sources the following training is required:

  • The students should have knowledge of scripts like Brahmi, Modi, Persian and their development.
  • They should know ways to obtain information about the social organisations and traditions.
  • They should know about the literature and writing style in past societies.
  • They should have basic knowledge about administrative systems, dynasties and cultures of the past.
  • They should study prevalent schools of painting and sculpture.
  • They should be able to collect information on types of paper, know about ink and colour of ancient document and ways to handle.
  • They should be well acquainted with properties of stones and metals used for inscriptions.
  • Articles published earlier on case study should be read.
  • They should know the chemicals and equipment used in various processes of cleaning and preserving the documents.
  • Modern know-how of approaches of managing exhibitions in museums, galleries and information technology.

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(b) What kind of training is required to study material sources?
Answer:
Student should have following knowledge to study material resource:

  • They should have basic knowledge of archaeological method and theory.
  • They should be acquainted with the history of ancient civilisations.
  • They should have knowledge of various techniques of excavation.
  • Stones, minerals and clay used to make artefacts and their characteristics to be studied.
  • They should be well-acquainted with the sources of the material used and their chemical properties.
  • They should also know about various styles of making artefacts and development in their making process.
  • They should have the knowledge and skills of making replicas of artefacts and fossils.
  • They should read research papers previously published on his case study.
  • They should acquire information about the approaches of arranging exhibitions and administrations.
  • They should know about the equipment and chemicals necessary for the cleaning of artefacts.
  • They should be able to write research reports and articles.

(c) Write information about museums in India.
Answer:

  • ‘Indian Museum’ established by the Asiatic Society of Bengal in Kolkata was the first museum in India in 1814.
  • The ‘Government Museum’ established in Chennai in 1851 C.E. was the second museum in India. The National Museum was established in Delhi in 1949.
  • The foundation of the Prince of Wales Museum was laid in Mumbai in 1905. Its construction was completed in 1922. It was renamed as Chhatrapati Shivaji Maharaj Vastusangrahalay in 1998 C.E.
  • At present, there are many museums in various states of India.
  • Many museums are connected to libraries and archives. Some are connected to Universities.
  • Such museums offer courses in Museology also.

(d) Give information on “National Archives of India.
Answer:

  • The first official archive of India was established m Kolkata in 1891 C.E. as the ‘Imperial Record Department’.
  • It was moved to Delhi in 1911 C.E.
  • In 1998 C.E. it was made accessible to the public by the then President of India K.R. Narayanan.
  • It was renamed as ‘National Archive’ (National Archive of India). Archives come under the Ministry of Culture of the Indian Government.
  • This archive has papers, maps, books and micro films preserved in chronological order since 1748.
  • Records in English, Arabic, Hindi, Persian, Sanskrit, Devanagari and Modi languages are preserved.
  • Papers kept in archives are classified into public, oriental, manuscripts and private papers.
  • The National Archives of India is the largest in Asia and technologically advanced.

(e) Explain the statement: A nation should have museums and libraries.
Answer:
Museums and libraries mirror the history of the country and that is the reason they are very valuable for a nation.

  • Museums and Libraries make it easy for the research scholar to write history.
  • Historical events and life stories of important people reach the masses.
  • People get an idea about past social, political and cultural conditions.
  • A visit to museums increases one’s interest.
  • A change in a prejudiced view about history is seen.
  • Information on animals, microorganisms, birds and elements of nature.
  • Museums contribute to the process of gaining and dissemination of knowledge.
  • Ancient historical sources are preserved.
  • Tourism is promoted.
  • It creates opportunities for employment.

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Hence it can be said that it is important for a nation to have museums and libraries as they both are symbols of nation’s progress and glory.

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Maharashtra Board Class 10 History Solutions Chapter 9 Heritage Management 9

Maharashtra Board Class 10 History Solutions Chapter 2 Historiography Indian Tradition

Balbharti Maharashtra State Board Class 10 History Solutions Chapter 2 Historiography Indian Tradition Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 10 History Solutions Chapter 2 Historiography Indian Tradition

Question 1.
(A) Choose the correct option from the given options and complete the statement.
(1) …………………..…….. was the first Director-General of the Archaeological Survey of India.
(a) Alexander Cunningham
(b) William Jones
(c) John Marshall
(d) Friedrich Max Muller
Answer:
(a) Sir Alexander Cunningham

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(2) …………………..…….. translated the Sanskrit text of ‘Hitopadesh’ in the German language.
(a) James Mill
(b) Friedrich Max Muller
(c) Mountstuart Elphinstone
(d) Sir John Marshall
Answer:
(b) Friedrich Max Muller

(B) Identify and write the wrong pair in the following set.
(1) ‘Who were the Shudras’ – subaltern History
(2) ‘Stri-Purush Tulana’ – Feminist writing
(3) ‘The Indian War of Independence 1857’ – Marxist History
(4) Grant Duff – Colonial History.
Answer:
(1) Right Pair: ‘Who were the Shudras’ – subaltern History
(2) Right Pair: ‘Stri-Purush Tulana’ – Feminist writing
(3) Wrong Pair: ‘The Indian War of Independence 1857’ – Marxist History
(4) Right Pair: Grant Duff – Colonial History.

Question 2.
Explain the following with its reason.
(1) Writing of the regional history received a momentum.
Answer:

  • Indian historians trained in the British educational system showed an inclination to restore the self-esteem of Indians They started writing Nationalistic historiography.
  • Historians from the different regions of India criticised the prejudiced history of India written by the British officers.
  • Their attention was drawn towards geographic conditions and history of different regions of India.
  • The nationalistic historiography helped in triggering the independence movement.
  • It provided a momentum to the writing of regional histories for e.g.
  • Nationalistic writings in Maharashtra were inspired by Vishnu Shastri Chiplunkar.

Hence, writing of the regional history received momentum.

(2) Bakhar is an important type of historical documents.
Answer:

  • Bakhars are important source of history like coins, inscriptions, texts, copper plates and travelogues.
  • Bakhars contain eulogies of the heroes, historic events, stories of lives of great men and description of battles.
  • It portrays a picture of prevalent society, religions and economic life.
  • Bakhars are of various types which contain biographies of kings, dynastic history, description of events, sects, autobiographies, mythologies, administration of kings, etc.
  • These descriptions are helpful for writing historiography.
  • Among well-known Marathi. Bakhars ‘Sabhasad Bakhar’ written by Krishnaji Anant Sabhasad requires a special mention Bhausahebanchi Bakhar and Panipatachi Bakhar describe the ‘Battle of Panipat’.

Hence, Bakhars are important type of historical document.

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Question 3.
Write detailed Answers the following questions in detail.
(1) What is Marxist History?
Answer:

  1. In the post-independence era, new trends emerged in writing Indian historiography. Marxist historiography is prominent among them.
  2. Historiography which is based on ideas of Karl Marx is known as Marxist Historiography. In Marxist Historiography, more importance was given to class struggles.
  3. Marxist Historiography reflects concerns for means and modes of production as well as the industrial relations. These became centre of writings of the Marxist historians.
  4. How every social event affects the life of people was analysed and it became the theme of Marxist historians Marxist historians studied the transitions that took place in the caste system.
  5. Notable Indian historians who adopted Marxist ideologies were Damodar Kosambi, Comrade Shripad Dange, Sharad Patil and Ram Sharan Sharma.
  6. Their writings reflected Marxist ideology. Comrade Dange was the founder member of the Indian Communist Party

(2) What is the contribution of Itihasacharya V.K. Rajwade to historiography?
Answer:

  1. V.K. Rajwade is well-known for his writings in Marathi on subjects like history, linguistics, etymology and grammar. His contributions are as follows:
  2. He compiled and edited 22 volumes of Marathyanchya Itihasachi Sadhane.
  3. He stated that history is the all-inclusive image of the past societies.
  4. V. K. Rajwade was of the view that history does not include only the stories of political images, conspiracies and Wars for seizing power.
  5. He was of the firm opinion that we should write our own history and insisted that history . should be written only using the authentic sources.
  6. He was of the opinion that description of any human event in historiography should have balanced combination of three factors namely – Time, Space and Personalities.

Question 4.
(a) Complete the following chart.

Historian Name of the Book
James Mill ‘The History of British India’
James Grant Duff ……………………………………………
…………………………………………… ‘The History of India’
S.A. Dange ……………………………………………
…………………………………………… ‘Who were the Shudras’

Answer:

Historian Name of the Book
James Mill The History of British India
James Grant Duff A History of Mahrattas
Mountstuart Elphinstone The History of India
S. A. Dange Primitive Communism to Slavery
Dr. Babasaheb Ambedkar Who Were the Shudras

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(b) Complete the following concept chart.
Maharashtra Board Class 10 History Solutions Chapter 2 Historiography Indian Tradition 1
Answer:
Maharashtra Board Class 10 History Solutions Chapter 2 Historiography Indian Tradition 2

Question 5.
Explain the following concepts.
(1) Orientalist historiography.
Answer:

  1. In the later part of the eighteenth century many European scholars felt curious to know about civilisations and countries of the East.
  2. These scholars who studied the Indian Civilization had respect and admiration for it. They were known as ‘Orientalists’.
  3. They studied similarities between Sanskrit and some of the European languages, focussing more on Vedic traditions and Sanskrit literature.
  4. It resulted in the notion that an ancient language could be the mother of all Indo-European languages.
  5. Notable Orientalist scholars are Friedrich Max Muller and William Jones.

(2) Nationalistic historiography.
Answer:

  1. English education started in India in the nineteenth century. The Indian historians who were trained in English education system realised the glory of their past.
  2. They showed an inclination to restore the pride in the ancient glory of India and the self-esteem of the Indian readers.
  3. They laid the foundation of Nationalistic writing. Nationalistic writings in Maharashtra were inspired by ‘Vishnushastri Chiplunkar’.
  4. Nationalistic historians opposed the prejudiced history written by the British officers.
  5. Mahadev Govind Ranade, Vinayak Damodar Savarkar, Ramesh Chandra Majumdar are renowned Nationalistic historians.
  6. Nationalistic historiography inspired freedom struggle against the Britishers and gave momentum to write about regional history. While glorifying the past, at times they are blamed for ignoring to critically analyse the truth.

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(3) Subaltern history.
Answer:

  • History of deprived classes or communities who were deprived of all rights is known as subaltern history.
  • The seeds of subaltern history can be traced in the Marxist history. Italian historian Antonio Gramsci has special importance in writing the subaltern history.
  • He presented the idea that history should be written starting from the bottommost ranks of people in the society.
  • Ranjit Guha, an Indian historian, has given prominence to subaltern history and played a major role in establishing it as an important academic school of historiography.
  • Similar thoughts were expressed by Mahatma Phule and Dr. Babasaheb Ambedkar which can be found in their writings.

Project
Prepare an illustrated manuscript with the help of the internet giving more information about the historians mentioned in this lesson.
Answer:

Memory Map
Maharashtra Board Class 10 History Solutions Chapter 2 Historiography Indian Tradition 3

Question 6.
Complete the sentences by choosing a correct option:
(a) The first written document found in India was inscribed during the rule of Emperor ……………….. .
(a) Akbar
(b) Harshavardhan
(c) Ashoka Maurya
(d) Aurangzeb
Answer:
(c) Ashoka Maurya

(b) Banabhatta wrote King Harsha’s biography titled ………………… in the 7th century CE.
(a) Meghdoot
(b) Rajtarangini
(c) Rasratnakar
(d) Harshacharit
Answer:
(d) Harshacharit

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(c) In the 12th century C.E., ………………… wrote a book ‘Rajtarangini’ about history of Kashmir.
(a) Banabhatta
(b) Kalhana
(c) Ziquddin Barani
(d) Patanjali
Answer:
(b) Kalhana.

(d) The historians in the courts of Muslim rulers were influenced by ………………… historiography.
(a) Greek and Roman
(b) Arabic and Persian
(c) English and French
(d) Arabic and Urdu
Answer:
(b) Arabic and Persian

(e) We get information about the rule of Chhatrapati Shivaji Maharaj from ……………….. .
(a) Bhausahebanchi Bakhar
(b) Panipatachi Bakhar
(c) Sabhasad Bakhar
(d) Holkaranchi Bakhar
Answer:
(c) Sabhasad Bakhar

(f) ‘Bhausahebanchi Bakhar’ describes Battle of ……………….. .
(a) Raigad
(b) Panipat
(c) Plassey
(d) Vasai
Answer:
(b) Panipat

(g) The first book written by a British historian on Indian history is ……………….. .
(a) The History of India
(b) The History of Maharaj
(c) The History of British India
(d) The Sacred Books of the East
Answer:
(c) The History of British India

(h) Nilkanth Janardan Kirtane and V.K. Rajwade exposed the limitations in writings of ……………….. .
(a) Friedrich Max Muller
(b) Colonel Todd
(c) Grant Duff
(d) William Wilson Hunter
Answer:
(c) Grant Duff

(i) …………………, an Indian historian played a major role in establishing subaltern history as an important academic school of historiography.
(a) Comrade Sharad Patil
(b) Ranjit Guha
(c) Dharmanand Kosambi
(d) Ram Sharan Sharma
Answer:
(b) Ranjit Guha.

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(j) The writings of British officials on India display strong influence of ……………….. .
(a) Marxism
(b) Colonalism
(c) Feminism
(d) Capitalism
Answer:
(b) Colonalism

(k) The Nationalistic Historiography in Maharashtra was inspired by works of ……………….. .
(a) Vinayak Damotfar Savarkar
(b) Ramkrishna Gopal Bhandarkar
(c) Vishnushastri Chiplunkar
(d) Justice Mahadev Govind Ranade
Answer:
(c) Vishnushastri Chiplunkar

(l) The two volumes written by ……………….. on Indian history show impartial treatment of the subject.
(a) Colonel Todd
(b) William Wilson Hunter
(c) Grant Duff
(d) James Mill
Answer:
(b) William Wilson Hunter

(m) ‘Primitive Communism to Slavery’, represents ……………….. the historiography.
(a) Colonial
(b) Orientalist
(c) Nationalistic
(d) Marxist
Answer:
(d) Marxist

(n) ‘Stripurush Tulana’ was written by ……………….. is acknowledged as first feminist book in India.
(a) Meera Kosambi
(b) Dr. Sharmila Rege
(c) Tarabai Shinde
(d) Pandita Ramabai
Answer:
(c) Tarabai Shinde.

Question 7.
Identify the wrong pair and write it:
(1)

Name of the Book Types of Historiography
(1) Who were the (a) Subaltern history
Shudras (July ’19)
(2) Stripurush Tulana (b) Feminist writing
(3) The Indian War of Independence (c) Marxist History
(4) Grant Duff (d) Colonial History

Answer:
Wrong pair: The Indian War of Independence – Marxist History.

(2)

Name of the Book Historian
(1) The Rise of the Maratha Power (a) Justice Mahadev Govind Ranade
(2) Marathyanchya Itihasachi Sadhane (b) Vishnushastri Chiplunkar
(3) Maratha Riyasat (c) Govind Sakharam Sardesai
(4) Gulamgiri (d) Mahatma Phule

Answer:
Wrong pair: Marathyanchya Itihasachi Sadhane- Vishnushastri Chiplunkar.

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(3)

Work Scholars
(1)  Bharat Itihas Samshodhak Manda (a)   V. K. Rajwade
(2)  Asiatic Society (b)   Sir William Jones
(3)  Inspiration for Nationalistic historiography (c)  Vishnushastri Chiplunkar
(4)  Discovery of Harappan Civilization (d)  James Mill

Answer:
Wrong pair: Discovery of Harappan CIvilization – James Mill.

(4)

Historiography Historian
(1) Nationalistic Historiography (a) V. D. Savarkar
(2) Marxist Historiography (b) Damodar Kosambi
(3) Subaltern Historiography (c) Ramchandra Guha
(4) Feminist Historiography (d) Sharmila Rege

Answer:
Wrong pair: Subaltern Historiography – Bamchandra Guha.

Question 8.
Do as directed:
(1)

Answer:

(2)

Answer:

(3) Prepare a flow chart on Literary work of Max Muller:
Answer:
Maharashtra Board Class 10 History Solutions Chapter 2 Historiography Indian Tradition 8

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Question 9.
Explain the concepts:
(a) Colonial Historiography:
Answer:

  • The history written by British officers and Christian missionaries in support of British rule and colonialism is known as Colonial historiography.
  • It reflected their prejudiced mindset about Indian culture. They ridiculed the Indian culture as being primitive.
  • Their writings justified the colonial British rule.
  • The distinct example of colonial historiography is ‘Cambridge History of India’ in five volumes published during 1922-1937.

Question 10.
Write short notes:
(a) Alexander Cunningham:
Answer:

  • British rulers started archaeological exploration and research in India in the 20th century.
  • They established the Archaeological Survey of India and appointed Sir Alexander Cunningham as its first Director General.
  • He mainly chose the sites mentioned in the Buddhist texts for excavations.
  • Many other ancient sites were excavated under his supervision.

(b) James Mill:
Answer:

  • James Mill, a‘British historian, had written the monumental book ‘The History of British India’. He published it in three volumes in 1817.
  • The book is important as it was the first book written by a British officer on Indian history.
  • The book: lacks objective perspective and is prejudiced about various aspects of the Indian culture.

(c) Grant Duff:
Answer:

  • Grant Duff, a British officer, wrote the book ‘A History of Mahrattas’, in three volumes.
  • His name stands out among the British officers who wrote about Maratha history.
  • The tendency of the British historians to condemn Indian culture and history is found in Grant Duff’s writing.
  • Historians Nilkanth Janardan Kirtane and Vishwanath Kashinath Rajwade exposed the limitations of Grant Duff’s writings.

(d) Indian Feminist Historiography:
Answer:

  1. Tarabai Shinde, Pandita Ramabai and Dr. Rukhamabai were feminist historians before independence.
  2. They wrote about employment of women, their right to political equality, treatment meted out to women at their workplace and gender discrimination.
  3. A lot of literature is available unfolding the viewpoint of Dalit women on problems like social class, caste, etc. In the post-independence era.
  4. Dr. Sharmila Rege included her essays on the autobiographies of Dalit women in her book, ‘Writing Caste, Writing Gender: Reading Dalit Women’s Testimonies.’
  5. Meera Kosambi’s book, ‘Crossing Thresholds: Feminist Essays in Social History’ contains essays on the life stories of women like Pandita Ramabai and Dr. Rukhamabai, the first practising lady Doctor of India.

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Question 11.
Explain the following with reasons:
(a) The history of Indian civilization dates back to 3rd millennium BCE.
Answer:

  • Indian civilisation is among the various ancient civilisations in the world.
  • Excavations at Harappa took place in 1920 under the supervision of Sir John Marshall, then Director General of Archaeological Survey of India (ASI). This led to the discovery of Harappan Civilization.
  • This discovery prqved helpful to trace the antiquity of Indian history which dates back 3rd millennium BCE or earlier.

(b) It became necessary to rethink of women’s position in history.
Answer:

  • For a considerable period of time, mainly male scholars were involved in the writing of Indian history.
  • It was obvious that the perspective was male-dominated.
  • The work of the women historians was neglected for long. So it became important to highlight this fact.
  • It was a huge challenge in front of the women: historians to compile the work and do research which would prove to be a medium to put forth their status in society.

Hence, it became necessary to rethink about the position of women in history.

(c) Govind Sakharam Sardesai was addressed as ‘Riyasatkar’.
Answer:

  • Govind Sakharam Sardesai had a momentous achievement to his credit by publishing ‘Maratha Riyasat’.
  • He published several volumes of Maratha history.
  • His work became so popular that people began to address him as ‘Riyasatkar’.

Question 12.
Answer the following in 25-30 words:
(a) Which things are included in the description by Emperor Babur in bis autobiography?
Answer:
Babur, the founder of the Mughal empire, in his autobiography entitled Tuzuk-i-Babari describes:

  • The battles fought by him.
  • Recordings of minute observations of various regions and cities visited by him noting minute observations.
  • Observation of the local customs, economy, fauna and flora of the region travelled by him.

(b) What is the contribution of Swatantryaveer Savarkar to nationalistic historiography?
Answer:

  1. The writings of Swatantryaveer Savarkar were infused with nationalistic ideas. He looked at the revolt of 1857 as the First War of Independence and wrote the ‘book ‘The Indian War of Independence, 1857’.
  2. His book gave inspiration to Nationalistic historiography which helped in triggering independence movement of the Indian people against the British. Even the writing of regional history got momentum.
  3. The attention of historians was drawn towards the history and geographic conditions and variations in the South Indian region.

(c) Write about the contribution of Banabhatta in writing historiographies.
Answer:

  • It was considered an important step in the Indian historiography to write biographies of kings and dynastic histories.
  • Banabhatta wrote Harshacharit, King Harsha’s biography, in the 7th century C.E.
  • It portrays a realistic picture of the social, economic, political, religious and cultural life during the period when King Harsha ruled.

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(d) Write information on ‘Rajtarangini’.
Answer:

  • Rajtarangini was written by Kalhana in the 12th century C.E. It traces the history of Kashmir.
  • These eight books contain records of dynasties which ruled Kashmir, local traditions, coins, remains of monuments and inscriptions. Kalhana wrote the text after critically examining the various sources.
  • The book is a good example to show how scientific technique is applied in writing history.

(e) Write about historiography in the post-independence period.
Answer:

  • In the post-independence period, along with dynastic history, cultural, social and economic histories were also written.
  • New schools of thought like Marxist, Subaltern and Feminist History were included in historiography.
  • The scholars in this era began to feel the need of writing histories of various communities, sciences, economic systems, political ideologies, cultural aspects, etc.
  • They presented the new schools of ideologies. These changes increased the scope of writing historiography.

(f) What are the objectives of writing history according to Ziauddin Barani?
Answer:

  • Ziauddin Barani explained the ’ objectives of historiography. According to him, the duty of a historian does not end with recording the ruler’s valour and welfare policies.
  • He should also write about the ruler’s failings and incorrect policies.
  • He further adds that a historian should also take into account the impact of the teachings of the wise, the learned and the saints on the cultural life of people.

Thus, Ziauddin Barani holds important place as he expanded the scope of historiography.

(g) What are the salient features of writings of historians in the courts of Mughal emperors?
Answer:
The salient features of writings of historians in the courts of Mughal emperors are:

  • Historians praised the Mughal emperors in their writings.
  • Their loyalty towards the rulers is exhibited.
  • The custom of adding suitable poetic quotes was introduced. The historians started to include beautiful pictures as well.

(h) Write about the importance of Tarabai Shinde in writing feminist historiography. *
Answer:

  • Tarabai Shinde has a prominent place among the feminist historians who wrote about women in the nineteenth century, i.e. pre-independence era.
  • She wrote a book Stripurush Tulana which was published in 1882. It is acknowledged as the first feminist book published in India.
  • Her writings attacked the male-dominated social system and the caste system.

Question 13.
Read the given passage and answer the questions given below:
(a) Complete the graphical presentation:

Answer:

(b) What was considered more important by the historians in the Mughal Court?
Answer:
Praising the Mughal emperor and exhibition of loyalty was considered more 8 important by the historians in the Mughal Court.

(c) Why is Abbul Fazl’s writing considered realistic?
Answer:

  • Abul Fazl’s Akbarnama reflects his critical viewpoint.
  • He collected authentic historical documents for this book.
  • He scrutinized these documents to affirm their reliability. Therefore, his method is looked upon as devoid of bias and hence realistic.

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Question 14.
Write detailed answers to the following questions:
(a) Write information about historiography in the ancient period of India.
Answer:

  • In the ancient period, stories of great deeds of ancestors, mythological lore, memories of social transitions were preserved through oral traditions.
  • The art of writing was mastered by Indians as early as 3rd millennium B.C.E. But Harappan script is not deciphered yet.
  • The earliest written documents found in India were in the form of inscriptions that are as old as 3rd century B.C.E. during the period of Emperor Ashok. His edicts are inscribed on natural rocks and stone pillars.
  • Inscriptions started to occur on coins, metal images and sculptures and also on copper plates from the 1st century B.C.E.
  • Epics like Ramayana, Mahabharat, Puranas, Jain and Buddhist texts are important sources of ancient Indian literature.
  • Historical accounts by Indian authors and travelogues by foreign travellers are also important sources of history.

(b) Explain the works of Dr. Babasaheb Ambedkar and Mahatma Phule in Subaltern History.
Answer:

  • History of the deprived classes expressed in folklore was known as ‘Subaltern History’.
  • Similar thoughts were expressed by Mahatma Jotirao Phule and Dr. Babasaheb Ambedkar.
  • Mahatma Phule unfolded the history of the Shudratishudra communities in his book ‘Gulamgiri’.
  • He drew attention to show how women, Shudras and Atishudras were exploited under the name of religion.
  • Dr. Ambedkar focused on the idea that in spite of having a significant role in shaping the cultural and political aspects of India, the role of Dalits was not duly acknowledged in colonial and nationalistic historiography.
  • Injustice done to the Dalits was mostly written by him. ‘Who Were the Shudras’ and ‘The Untouchables’ are his books which can be cited as examples of subaltern history.

Question 15.
Observe the given picture and answer the question given below:

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(a) Write a short note on Copper-plate inscriptions.
Maharashtra Board Class 10 History Solutions Chapter 2 Historiography Indian Tradition 11
Answer:

  • The copper-plate shown in the picture was found at Sohagaura in Gorakhpur district in Uttar Pradesh.
  • It is supposed to be from the Mauryan period and the inscription on it is in Brahmi script.
  • Many symbols are inscribed on it ‘Tree-in-railing’ and ‘Mountain’ at the beginning of inscription occur on punch marked coins.
  • A structure created on four pillars is indicative of a granary.
  • The inscriptions have a record of royal order that the grains stored in the granary should be distributed carefully.
  • This order is suggestive of precautionary measures taken during famine.

Maharashtra Board Class 10 Political Science Solutions Chapter 3 Political Parties

Balbharti Maharashtra State Board Class 10 Political Science Solutions Chapter 3 Political Parties Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 10 Political Science Solutions Chapter 3 Political Parties

Question 1.
Choose the correct option from the given options and complete the sentences.
(1) When people come together and participate in electoral process, to acquire political power, such organisations are called ………………………….. .
(a) Government
(b) Society
(c) Political parties
(d) Social organisations
Answer:
(c) Political parties

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(2) National Conference is a party in ………………………….. this region.
(a) Odisha
(b) Assam
(c) Bihar
(d) Jammu and Kashmir
Answer:
(d) Jammu and Kashmir

(3) Justice Party- a non-Brahmin movement was transformed into ………………………….. Political Party.
(a) Assam Gan Parishad
(b) Shivsena
(c) Dravid Munnetra Kazhagam
(d) Jammu and Kashmir National Conference
Answer:
(c) Dravid Munnetra Kazhagam

Question 2.
State whether the following statements are true or false. Give reasons for your answer.
(1) Political parties act as a link between government and people.
Answer:
The above statement is True.

  • The political parties convey the demands and complaints of the people to the government.
  • Information about various government policies and schemes are conveyed to the people by the political parties.
  • People’s reaction to the policies and their expectations are conveyed to the government too by the parties. In this way, political parties act as a link between government and the people.

(2) Political parties are social organisations.
Answer:
The above statement is True.

  • People who have similar views come together voluntarily and form a party, so it can be said that political parties are an integral part of our society.
  • The political parties try to solve the problems of the people.
  • Some political parties represent the role of a particular community in society, its ideology and work to achieve it. Hence it can be said that political parties are social organizations.

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(3) Coalition politics leads to instability.
Answer:
The above statement is False.

  • As no single party got majority after the elections held in 1989, coalition government came to power at the centre and many states.
  • Parties had to set aside their policies and programmes and concentrate on a common agenda to run the government.
  • Both Congress Party and the Bharatiya Janata Party made an experiment of establishing a coalition government.
  • The National Democratic Alliance formed by BJP and its partners and the Democratic Front government formed by Congress and its partners ruled at the centre and state level effectively.

Therefore, the belief that the coalition government brings instability was proved wrong.

(4) Shiromani Akali Dal is a national party.
Answer:
The above statement is False.
The Election Commission of India recognises a political party as National or Regional party on the basis of specific criteria namely:

  • The number of seats secured in Parliament and Legislative Assembly or percentage of votes secured.
  • Shiromani Akali Dal does not meet the criteria listed above.
  • As its influence is limited to the state of Punjab and not in any other state.
  • The Election Commission has given recognition to it as regional party.

Question 3.
Explain the following concepts.
(1) Regionalism
Answer:

  • India is a vast country with great physical diversity. People belonging to different regions have their own language, culture and traditions.
  • Along with the physical diversity, we find diversity in literature, education, history and movements.
  • Each one feels an affinity for his language, traditions and history of social reforms. This gives rise to linguistic identity.
  • This affinity towards all the above-mentioned aspects develops into identity consciousness and gives rise to excessive regional pride.
  • People start giving preference only to the development of their language and region.
  • This is known as Regionalism.

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(2) National Parties
Answer:
A party which functions at the national level is known as National Party.

  1. The Election Commission has laid certain criteria for a party to get recognised as a Political party. The political party should secure at least f 6% valid votes in four or more states in the earlier Lok Sabha. OR
  2. State Assembly elections and minimum four members should be elected in the Lok Sabha from any state or states in the earlier elections. OR
  3. The candidates of a party should be elected from a minimum three states or should be elected from a minimum 2% constituencies of the total Lok Sabha constituencies. OR
  4. It is important to get recognition as a state party in at least four states.

Question 4.
Answer the following questions in brief.
(1) What are the major characteristics of political parties?
Answer:
The main features of political parties are as follows:

  • Political parties aim at securing power by contesting elections.
  • Every political party has some ideology.
  • Every party has an agenda. It is based on the party’s ideology.
  • The party that gets majority seats in election forms the government and the one that does not secure the majority act as opposition parties.
  • Political parties are a link between the people and the government and work to gain the support of the people.

(2) What changes have taken place in the nature of political parties in India?
Answer:
The following changes were seen in the party system in India:

  • Indian- National Congress was the only dominant party in states and at the centre after independence.
  • All other parties came together and formed a coalition in 1977 and defeated the Congress.
  • For the first time in history, the two-party system got importance over one-party system.
  • The one-party system came to an end after the 1989 elections.
  • Regional parties got importance and the coalition government was formed at the centre and in the states.

Project
(1) In a map of Maharashtra, point out the Loksabha constituency that includes the names of your parents.
(2) In a map of India, point out the places where national political parties have their influence.
Answer:

Memory Map
Maharashtra Board Class 10 Political Science Solutions Chapter 3 Political Parties 1

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Question 5.
Choose the correct option from the given options and complete the sentences:
(a) The party which fails to secure majority is known as ………………………. party.
(a) Ruling
(b) Opposition
(c) Independent
(c) Coalition
Answer:
(b) Opposition

(b) ‘Bharatiya Janata Party’ which was formed in 1980 after a split with ………………………. a component of Janata Party.
(a) Jan Sangh
(b) Lok Dal
(c) Independent party
(b) Janata Dal
Answer:
(a) Jan Sangh.

(c) Social support received by a political party is called ………………………. .
(a) Democracy
(b) People’s rule
(c) Mass base
(d) Public relation
Answer:
(c) Mass base

(d) Promotion of the Marathi language is the objective of the ………………………. .
(a) Dravida Munnetra Kazhagam
(b) Shiromani Akali Dal
(c) Shiv Sena
(d) Assam Gana Parishad
Answer:
(c) Shiv Sena

(e) There are ………………………. recognised parties in India.
(a) five
(b) seven
(c) nine
(d) six
Answer:
(b) seven

(f) The main objective of the political party is to capture ………………………. and retain it.
(a) publicity
(b) victory
(c) power
(d) information
Answer:
(c) power

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(g) The ideology of the Communist Party of India is based on ………………………. Philosophy.
(a) Capitalist
(b) Marxist
(c) Democracy
(d) Imperialist
Answer:
(b) Marxist

(h) Shiromani Akali Dal is a prominent regional party in ………………………. state.
(a) Odisha
(b) Assam
(c) Punjab
(d) Jammu and Kashmir
Answer:
(c) Punjab

Question 6.
State whether the following statements are true or false. Give reasons for your answer:

(a) Political parties do not need support of the people.
Answer:
The above statement is False.

  • To secure power is the main aim of political parties.
  • Political parties have to implement various policies and programmes for the welfare of people and to gain the support of the people.
  • The party which solves the issues related to the welfare of the people get support.
  • Without the support of the people they can never get a mandate.

Hence, all political parties require support of the people.

(b) The Communist Party of India was split.
Answer:
The above statement is True.

  • The Communist Party of- India was established in 1925. The Communist Parties follow Marxist ideology.
  • In 1962, due to differences in the leadership a rift was created in the party.
  • The main reason for the split was about which political line to follow.

(c) Sometimes the sentiments of regionalism gets strengthened in the country.
Answer:
The above statement is True.

  1. A country like India has diversity of government language, region and culture. This diversity creates affinity towards a region.
  2. This affinity gives rise to excessive regional S pride and initiating movements to save it. The significance of such movements is claimed to be for preserving culture.
  3. Asserting to be rightful claimant of material resources, job opportunities and development of the region these movements strengthen the regional pride.
  4. Thus, this excessive regional pride turns morbid taking the form of regionalism.

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(d) Regional parties have no influence on National Politics.
Answer:
The above statement is False.

  • No single party got majority in the elections to Lok Sabha held in 1989.
  • The national parties formed coalition government at the centre taking help of regional parties.
  • As regional parties share power at the centre they have influence on national politics.

Question 7.
Explain the concept:
(a) Regional Parties:
Answer:

  1. The groups having a proud feeling about the different identity of their region and who compete to capture power to bring about regional development are ‘Regional Parties’.
  2. The influence of such parties are limited to their region. They give importance to regional problems. Development of one’s own region is the prime objective of these parties.
  3. Sometimes they demand for independent state or autonomy. They influence the national politics because of their dominance in the region.
  4. They have passed through various phases, from separatism to autonomy and have then merged with mainstream national politics.

(b) Political Party:
Answer:

  1. A Political Party is a kind of social organisation of like-minded people. The main aim of any political party is to contest election and secure power.
  2. The stand taken by various political parties on issues becomes their political ideology.
  3. In democracy, political parties are at the centre of all political activities. They are a link that connects common people, democracy, representation and elections.
  4. The party that secures a majority becomes the ruling party and the rest are known as the. opposition.

Question 8.
Write short note:
(a) Party System:
Answer:

  1. If one party remains in power in a country for a long period and no other party has any kind of influence the party system it is called ‘One- Party System’.
  2. When there are two equally strong parties which alternatively come to power. It is called ‘Two-Party System’.
  3. In a country where many political parties exist and compete with each other to capture power and have more or less influence in different states is called ‘Multi-Party System’.
  4. Democracy develops in Multi-Party System.

(b) Indian National Congress:
Answer:

  • The Indian National Congress was established in 1885.
  • The party represented the hopes and aspirations of Indians and led the freedom struggle.
  • Groups having diverse ideologies became part of the Congress to fight for freedom.
  • It believes in democratic socialism, social equality and international peace.
  • After independence, the Congress Party was a dominant party for almost four decades and ruled at the centre and in the states.

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(c) Communist Party of India:
Answer:

  • The Communist Party of India was established in 1925. The Communist Party follows the Marxist ideology.
  • The party aims at working to protect the interests of workers and labourers.
  • The main objective of this party is to oppose capitalism and protect the interests of workers.
  • The party split due to ideological differences in 1964. Those who walked out of the party formed Communist Party (Marxist).

(d) Nationalist Congress Party:
Answer:

  • Nationalist Congress Party (NCP) is the splinter or breakaway party from the Congress Party.
  • It considers the values like democracy, equality and secularism important.
  • It became part of United Progressive Alliance (UPA) and came to power in Maharashtra.
  • It was in power in Maharashtra from 1999 to 2014 and at the centre from 2004 to 2014.

(e) Trinamool Congress:
Answer:

  • All India Trinamool Congress was established in 1998.
  • The Election Commission of India gave it recognition in 2016.
  • Democracy, Secularism and protection of the weaker sections of the society are some of the policies of the party.
  • Presently (April 2019), this party is in power in the state of West Bengal.

(f) Shiv Sena:
Answer:

  1. The Shiv Sena was founded in 1966.
  2. The main objective of the party was to fight for the cause of Marathi-speaking people and preservation of Marathi language.
  3. They resisted the people from other regions.
  4. In 1995, it became the ruling party with BJP in Maharashtra and its strategic tie-up with BJP helped it to enter national politics.
  5. It was in power at the centre with BJP from 1998 to 2004. Again it has shared power with the BJP at the centre and state since 2014.

(g) Shiromani Akali Dal:
Answer:

  • Shiromani Akali Dal was formed in 1920.
  • It is a dominating party in Punjab.
  • It gives preference to nurture religious and for the regional pride.
  • The party has retained power in Punjab for many years.

(h) Dravid Munnetra Kazhagam:
Answer:

  • Justice party, a non-Brahmin movement, started in 1920. In 1944, it transformed into a political party called Dravid Kazhagam.
  • In 1949, a group within the party got split and formed Dravid Munnetra Kazhagam (DMK).
  • The party works for the protection of Tamil identity.
  • This party implemented many policies for welfare of the people and therefore has support from all the sections of society.
  • Another group separated from it in 1972 and formed All India Dravid Munnetra Kazhagham.
  • It remained in power for a long time in Tamil Nadu and for sometime at the centre.

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Question 9.
Do as directed
(a) Complete the concept map:
Maharashtra Board Class 10 Political Science Solutions Chapter 3 Political Parties 2
Answer:
Maharashtra Board Class 10 Political Science Solutions Chapter 3 Political Parties 3

Maharashtra Board Class 10 Political Science Solutions Chapter 3 Political Parties 4
Answer:
Maharashtra Board Class 10 Political Science Solutions Chapter 3 Political Parties 5

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(3)
Maharashtra Board Class 10 Political Science Solutions Chapter 3 Political Parties 6
Answer:
Maharashtra Board Class 10 Political Science Solutions Chapter 3 Political Parties 7

(b) Complete the Time-line writing the name of the party or the year of establishment:
Maharashtra Board Class 10 Political Science Solutions Chapter 3 Political Parties 8
Answer:
Maharashtra Board Class 10 Political Science Solutions Chapter 3 Political Parties 9

Question 10.
Answer the following questions in brief:

(a) What is called “mass base”?
Answer:

  • Every political party is formed with some ideology.
  • Political parties take a certain stand towards public issues.
  • Their ideology and their stand towards public issues are conveyed to the people through various programmes.
  • If the people agree with their role and ideology, they get the support of the people.
  • Such social support received by a political – party is called ‘mass base’.

(b) Write about the policies of Indian National Congress.
Answer:
The policies of the Indian National: Congress are as follows:

  • Equal rights for the minorities and weaker sections of society.
  • Secularism, all-round development and social welfare are its objectives.
  • Introduction of socialist democracy.
  • Belief in values like international peace and social equality.

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(c) Explain the role of Bharatiya Janata Party.
Answer:
Bharatiya Janata Party was formed in 1980 with the following objectives:

  • To preserve Indian culture and traditions.
  • To create a strong and rich India.
  • To give importance to economic reforms for development of India.

(d) Write about the policies of Communist Party of India (Marxist).
Answer:
Communist Party of India (Marxist) was formed in 1964 with the following objectives:

  • The party advocates socialism, secularism and democracy.
  • The main policy of the party is to work for the welfare of farmers, landless labourers and workers.
  • The party opposes imperialism.

(e) Why was Bahujan Samaj Party formed?
Answer:
The Bahujan Samaj Party was formed in 1984 to achieve the following objectives:

  • To bring socialist ideology into practice.
  • To secure power for ‘majority’ comprising of scheduled castes, scheduled tribes and other backward classes.
  • To give power in the hands of ‘majority’.

(f) What do the regional parties give preference for?
Answer:
The regional parties give preference to the following issues:

  • Importance should be given to regional issues and bring about development.
  • Regional issues should be handled* at regional level.
  • The power rests in the hands of regional people. ‘
  • People living in that region should get preference in administration and jobs. .

(g) What changes are seen in the nature and role of regional parties?
Answer:
The role of regional parties changed over period of time. The changes are as follows:

  • After independence, regional identity gave rise to separatists movements and demands were put up by regional parties for separate state.
  • They wanted to break away from the Indian union and form a separate state.
  • The demands of the regional parties changed gradually and these parties started asking for autonomy.
  • In the later period, for the development of their region and people the parties demanded representation of their people in the state and central government.
  • Regional parties in the north eastern region also started demanding more autonomy after split up.
  • The journey of the regional parties began with a split up and then a demand for autonomy going on to share power in federation and then entry into mainstream national politics.

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(h) What are the objectives of Assam Gana Parishad?
Answer:
Assam Gana Parishad was formed in 1985 with the following objectives:

  • To preserve the uniqueness of Assam’s culture, language and social identity.
  • To make efforts for economical development of Assam.
  • To resolve problems of displaced people.

(i) What are the criteria for a regional party to get recognition?
Answer:

  • In the last general .elections to the State Assembly, the party should not secure less than 6% of the total number of valid votes polled.
  • At least 2 members to be elected to the Legislative Assembly (Vidhan Sabha).
  • 3% seats of the total seats of Legislative Assembly or at least 3 seats in Legislative Assembly.

(j) What work is done by political parties?
Answer:
The following work is done by political parties:

  • To propagate policies and programmes of the party and contest elections.
  • They implement various policies when they come to power.
  • If they fail to secure power, they act as opposition party and try to gain support of the people.
  • They communicate the demands and complaints of the people to the government and the policies and programmes of the government to the people.

Question 11.
Give your opinion:

(a) Imagine you are opposition party leader and you have observed that the ruling party has not done good work in the field of health. What will you do as a leader of opposition?
Answer:
As opposition leader, I will do the following to make the government realise its negligence in the health field:

  • I will question the government in Parliament and point out their shortcomings and ask about the prolonged projects.
  • I will create awareness among the people by writing articles in newspapers.
  • I will give interviews,on radio and television and criticize the government.
  • I will organise rallies and meetings to sensitize among the people.

(b) Think and write
What has to be done to bring partyless democracy in modern times?
Answer:

  • The recognition of all the parties should be cancelled. ‘
  • People should be given the right to make decisions.
  • In order to improve the decision-making power, people should be educated on political issues.
  • To improve the moral character of the people who want to take the leadership.
  • To initiate direct democracy and prepare the people for the same.
  • Stress should be given for decentralization.
  • Mahatma Gandhi, Vinoba Bhave and Jayprakash Narayan put forth the idea of partyless democracy.
  • What has to be done to bring such democracy in modern times?

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Question 12.
What do you understand by the following news in newspapers? Explain in brief.

(a) Opposition parties held a meeting in Mumbai to resist the Ruling party. Will take up the issue of farmers?
Answer:

  • The ruling party did not undertake any work for the welfare of farmers. Therefore all the opposition parties decided to trap the government on this issue.
  • The opposition parties have kept aside their differences and come together for this cause.
  • It is the duty of the opposition party to question the negligence of the government.
  • This news makes us aware of the line of action taken by the opposition.
  • Opposition parties held a meeting in Mumbai to resist the Ruling party. Will take up the issue of farmers?
  • Ruling party organised ‘Samvad Yatra’ in rural areas.

(b) Ruling party has organised ‘Samvad Yatra’ in rural areas.
Answer:

  • Political parties adopt different ways to popularise their party and influence the people.
  • As the means of communication are limited in rural areas they organise the Yatra.
  • It shows the efforts of the government to understand problems of people in rural areas.
  • It is essential to have dialogue with people to know their problems and opinions.
  • As the initiative is taken by the government, people will develop faith in government.
  • The news conveys to us that the ruling party is carrying out its duties properly.
  • The faith in government becomes profound when people feel that government is sensitive towards them.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Balbharti Maharashtra State Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 1.
a. Alloy of sodium with mercury.
Answer:
Silver amalgam.

b.Molecular formula of common ore of aluminium.
Answer:
Al2O3.nH2O

c. The oxide that forms salt and water by reacting with both acid and base.
Answer:
Aluminium oxide (Al2O3).

d. device used for grinding an ore.
Answer:
The device used for grinding an ore is grinding mill.

e. The nonmetal having electrical conductivity.
Answer:
Graphite having electrical conductivity.

f. The reagent that dissolves noble metals.
Answer:
Aqua regia is the reagent that dissolves noble metals like gold and platinum.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 2.
Make pairs of substances and their properties.

Column I Column II
Substance Property
(1) Potassium bromide (a) Combustible
(2) Gold (b) Soluble in water
(3) Sulphur (c) No chemical reaction
(4) Neon (d) High ductility
(e) Magnetic ingredient

Answer:
(1) Potassium bromide – Soluble in water
(2) Gold – High ductility
(3) Sulphur – Combustible
(4) Neon – No chemical reaction

Question 3.
Identify the pairs of metals and their ores from the following.

Column I (ores) Column II (metals)
(1) Bauxite (a) Mercury
(2) Cassiterite (b) Aluminium
(3) Cinnabar (c) Tin
(d) Copper

Answer:
(1) Bauxite – Aluminium
(2) Cassiterite – Tin
(3) Cinnabar – Mercury

Question 4.
Explain the terms.
a. Metallurgy
Answer:
Metallurgy: The process used for extraction of metals in their pure form from their ores, then metals are further purified by different methods of purification. All the process is called metallurgy.

b. Ores.
Answer:
Ores: The minerals from which metals are extracted profitably and conveniently are called ores.
Examples: Bauxite (Al2O3.H2O), Cinnabar (HgS).

c. Minerals.
Answer:
Minerals: The naturally occurring compounds of metals along with other impurities are known as minerals.
Examples: Rocks are composed of mixtures of minerals. Talc and granite are minerals.

d. Gangue.
Answer:
Gangue: Ores contain metal compounds with some of the impurities like soil, sand, rocky material, etc. These impurities are called gangue.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 5.
Write scientific reasons.
a. Lemon or tamarind is used for cleaning copper vessels turned greenish.
Answer:

  • Copper undergoes oxidation in air to form black copper oxide. Copper oxide reacts slowly with carbon dioxide in air and gains a green coat. This green substance is copper carbonate.
  • Lemon and tamarind contain acid. The acid dissolves the green coating of basic copper carbonate present on the surface of a tarnished copper utensil and makes it shiny again.

b. Generally the ionic compounds have high melting points.
Answer:

  • The ionic compounds exist in solid state and are hard due to strong electrostatic force of attraction between oppositely charged ions.
  • The intermolecular force of attraction is high in ionic compounds and large energy is required to overcome it. Therefore, ionic compounds have high melting points.

c. Sodium is always kept in kerosene.
(OR)
Why is sodium stored in kerosene?
Answer:

  • Sodium reacts so vigorously with atmospheric oxygen that it catches fire if kept in the open.
  • It does not react with kerosene and sinks in it. Hence, to protect sodium and to prevent accidental fires it is always kept in kerosene.

d. Pine oil is used in the froth floatation process.
Answer:

  • In the concentration of an ore by froth floatation process, the ore is mixed with water and pine oil. When air is bubbled through the mixture a froth is formed.
  • The mineral particles in the ore are preferentially wetted by the oil and float on the top in the froth.
  • The gangue particles are wetted by water and settle down. Thus the mineral can be separated from the gangue and the ore is concentrated.

e. Anodes need to be replaced from time to time during the electrolysis of alumina.
Answer:

  • During electrolysis of alumina, the oxygen liberated at the carbon anode reacts with graphite rods (carbon anode) and forms carbon dioxide.
  • As the anodes get oxidised during electrolysis of alumina, they are continuously eroded. Hence, it is necessary to replace anodes from time to time.

Question 6.
When a copper coin is dipped in silver nitrate solution, a glitter appears on the coin after some time. Why does this happen? Write the chemical equation.
Answer:
When a copper coin is dipped in a silver nitrate solution, more reactive copper displaces silver from silver nitrate solution. The silver so liberated deposits on the copper coin. As a result, a shiny coat of silver is formed on the coin.
Cu(s) + 2AgNO3(aq) → Cu(NO3)2(aq) + 2Ag(s)

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 7.
The electronic configuration of metal ‘A’ is 2, 8, 1 and that of metal ‘B’ is 2, 8, 2. Which of the two metals is more reactive? Identify these metals. Write their reaction with dilute hydrochloric acid. (Practice Activity Sheet – 1)
Answer:
If the number of electrons in the outermost orbit is less, then the metal is more reactive. Metal A contains one electron in the outermost shell, while metal B contains two electrons. Hence, metal A is more reactive than metal B.

Metal A is sodium and metal B is magnesium. Reactions of Na and Mg with dil. HCl are,
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 1

Question 8.
Draw a neat labelled diagram.
a. Magnetic separation method.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 2

b. Forth floatation.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 3

c. Electrolytic reduction of alumina.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 4

d. Hydraulic separation method.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 5

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 9.
Write chemical equation for the following events.
a. Aluminium came in contact with air.
Answer:
When aluminium is exposed to air, it develops a thin oxide layer of aluminium.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 6

b. Iron filings are dropped in aqueous solution of copper sulphate.
Answer:
When iron filings are dropped in copper sulphate solution, more reactive iron displaces copper from copper sulphate solution. The iron filings get coated with reddish brown copper metal and the blue colour of copper sulphate fades gradually and ferrous sulphate is formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 7

c. A reaction was brought about between ferric oxide and aluminium.
Answer:
The reaction between ferric oxide and iron produces aluminium oxide and iron. It is a thermite reaction and is highly exothermic.
It produces a large amount of heat, which is released to melt oxygen and aluminium. This reaction is used in welding of machineries. It is also used in warfare to make grenades.

The chemical reaction for the above is as follows:
3Fe3O2 + 4Al → 2Al2O3 + 6Fe

d. Electrolysis of alumina is done.
Answer:
During electrolysis of alumina, aluminium is deposited at the cathode. Molten aluminium being heavier than the electrolyte, is collected at the bottom of the tank. Oxygen gas is liberated at the anode.
Anode reaction: 2O → O2 + 4e (Oxidation)
Cathode reaction: Al3+ + 3e → Al(l) (Reduction)

e. Zinc oxide is dissolved in dilute hydrochloric acid.
Answer:
Zinc oxide is dissolved in dilute hydrochloric acid, zinc chloride and water are formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 8

Question 10.
Complete the following statement using every given options.
During the extraction of aluminium
a. Ingredients and gangue in bauxite.
b. Use of leuching during the concentration of ore.
c. Chemical reaction of transformation of bauxite into alumina by Hall’s process.
d. Heating the aluminium ore with concentrated caustic soda.
Answer:
c. Chemical reaction of transformation of bauxite into alumina by Hall’s process.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 11.
Divide the metals Cu, Zn, Ca, Mg, Fe, Na, Li into three groups, namely, reactive metals, moderately reactive metals and less reactive metals.
Answer:
Reactive metals: Na, Li, Ca
Moderately reactive metals: Zn, Fe, Mg,
Less reactive metals: Cu

Project: (Do it your self)

Collect metal vessels and various metal articles. Write detailed informciton. write the steps in the procedure that can be done in the laboratory for giving glitter to these. Seek guidance from your teacher.

Can you recall? (Text Book Page No. 93)

Question 1.
what are the physical properties of metals and nonmetals?
Answer:
Properties of metals:

  1. Solid state (Exception: Mercury and gallium)
  2. Typical lustre
  3. Malleability and ductility
  4. Hardness (Exception: Lithium, sodium and potassium)
  5. Good conductors of heat and electricity
  6. High melting and boiling points (On the other hand, the melting and boiling points of the metals sodium, potassium, mercury and galium are very low.)
  7. Sonorous and produce sound on striking a hard surface.

Properties or nonmetals:

  1. Gaseous or solid state (Exception: Bromine in liquid state)
  2. Lack of any typical lustre (Exception: Iodine and Diamond)
  3. Brittleness in the solid state (Exception: Diamond is the hardest natural substance)
  4. Bad conductors of heat and electricity (Exception: Graphite) (Diamond is good conductor of heat)
  5. Low melting and boiling points.

Can you recall? (Text Book Page No. 102)

Question 1.
What is the electronic definition of oxidation and reduction?
Answer:
When a metal loses çlectrons the process is called an oxidation while when a nonmetal gains electrons, it is called a reduction,
Na → Na+ + e (oxidation)
Cl + e → Cl (reduction)

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Can you recall? (Text Book Page No. 106)

Question 1.
What is meant by corrosion?
Answer:
Corrosion is degradation of a material due toreaction with its environment.

Question 2.
Have you observed the following things?
(1) Old iron bars in the builthngs.
Answer:
When old iron bars in the buildings are exposed to moist air for a long time, they acquire a coating of browm nlaky substance called rust. (Fe2O3.H2O)

(2) Copper vessels not cleaned for a long time.
Answer:
If copper vessels are not cleaned for a long time, they react with moist carbon dioxide in the air, lose their shine and gain a green coat of copper carbonate. (CuCO3)

Question 3.
Silver ornaments or idols exposed to air for a long time.
Answer:
When silver ornaments or idols are kept exposed to air for a long time, silver reacts with sulphur in the air to form a coating of black silver sulphide. (Ag2S)

Question 4.
Old vehicles fit to be thrown away.
Answer:
The metallic parts of the body of old cars are corroded, eaten up and sometimes become perforated. The old cars also lose the original colour due to formation of flakes of rust.

Use your brain power! (Text Book Page No. 98)

Question 1.
In the reaction between chlorine and HBr a transformation or HBr into Br2 takes place. Can this transformation be called oxidation? What Is the oxidant that brings about this oxidation?
Answer:
The conversion of HBr to Br2 is an oxidation process. In the above reaction, Cl2 in the oxidant.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Can you tell? (Text Book Page No. 104)

Question 1.
what are the moderately reactive metals?
Answer:
In the middle of the reactivity series, metals such as iron. zinc, lead, copper are moderately reactive.

Question 2.
In which form to the moderately reactive metals occur in nature?
Answer:
The moderately reactive metals which occur in nature are in the form of their sulphide salts or carbonate salts.

Think about it (Text Book Page No. 106)

Question 1.
Why do silver articles turn blackish while copper vessels turn greenish on keeping in air for long time?
Answer:

  1. Silver articles turn blackish on exposure to air for a long time. This is because of silver sulphide (Ag2S) laver formed on the silver articles by the reaction of silver with hydrogen sulphide.
  2. Carbon dioxide in moist air reacts with copper vessel. Copper loses its lustre due to formation of greenish layer of copper carbonate (CuCO3) on its surface.

Question 2.
Why do pure gold and platinum always glitter?
Answer:
Gold and platinum are noble metals as they do not react with moisture, O2 and CO2 from air also acids and alkalis, therefore, pure gold and platinum always glitter.

Use your brain power! (Text Book Page No. 103)

Question 1.
Write the electrode reaction for electrolysis of molten magnesium chloride and calcium chloride.
Answer:
(1) Magnesium chloride (MgCl2):
MgCl2 → Mg2+ + 2Cl
At the cathode: Mg2+ + 2e → Mg
At the anode: 2Cl → Cl2 + 2e

(2) Calcium chloride (CaCl2):
At the cathode: Ca2+ + 2e → Ca
At the anode: 2Cl → Cl2 + 2e

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Can you tell? (Text Book Page No. 106)

Question 1.
Which measures would you suggest to stop the corrosion of metallic articles or not allow the corrosion to start?
Answer:
Various types of methods are used to protect metals from corrosion. Almost in all the methods, special attention is paid so that iron does not rust. It is possible to lower the rate of the process of rusting of iron. Corrosion of metals can be stopped by detaching the air from metals.

Some methods are as follows :

  1. To fix a layer of some substance on the metal surface so that the contact of the metal with moisture and oxygen in the air is prevented and no reaction would occur between them.
  2. To prevent corrosion of metals by applying a layer of paint, oil, grease or varnish on their surface. For example, corrosion of iron can be prevented by this method.

Question 2.
What is done so to prevent rusting of iron windows and iron doors of your house?
Answer:
To prevent rusting of iron windows and iron doors in the house, they are painted so that they do not rust.

Question 3.
What is done so to prevent rusting or iron windows and iron doors of your house?
Answer:
To prevent rusting of iron windows and iron doors in the house, they are painted so that they do not rust.

Use your brain power! (Text Book Page No. 107)

Question 1.
Can we permanently prevent the rusting of an iron article by applying a layer of paint on its surface?
Answer:
The method of painting is alright for some time. We cannot protect the articles permanently from rusting by painting them.

Question 2.
Why do new iron sheets appear shiny?
Answer:
The new iron sheets appear shiny because a layer of non-corrosionable metal is fixed on the surface of corrosionable metal.

Collect information. (Text Book Page No. 108)

Question 1.
What are the various alloys used in daily life? Where are those used?
Answer:

Various alloys Uses
1. Bronze It is used to prepare: Coins, utensils, medals, statues
2. Brass Pipes, condenser tubes, utensils worshipping God.
3. Stainless steel Utensils, tools, dairy equipment, boilers.
4. Steel Construction of bridges and buildings, cutting tools, blades.
5. Tungsten steel High speed cutting tools
6. Amalgam Silver amalgam used by dentists
7. Duralumin Bodies of aircraft, buses, kitchenwares
8. Aluminium bronze Pigment in ink and paint
9. German silver Electrical heaters, resistors
10. Gun metal Guns, boiler fittings
11. Magnelium Beams of scientific balances, aircraft parts.
12. Gold with copper or nickel or silver or platinum Jewellery

Question 2.
What are the properties that the alloy used for minting coins should have?
Answer:
The alloy used for minting coins should have excellent wear resistance and anti-corrosion properties.

Fill in the blanks:

Question 1.
……………has the highest melting point.
Answer:
Tungsten has the highest melting point.

Question 2.
Mercury and…………are two metals in the liquid state at room temperature.
Answer:
Mercury and galium are two metals in the liquid state at room temperature.

Question 3.
…………is the hardest natural substance.
Answer:
Diamond is the hardest natural substance.

Question 4.
The naturally occurring compounds of metals along with other impurities are known as………….
Answer:
The naturally occurring compounds of metals along with other impurities are known as minerals.

Question 5.
The minerals from which metals are extracted profitably and conveniently are called…………..
Answer:
The minerals from which metals are extracted profitably and conveniently are called ores.

Question 6.
An ore contains some of the impurities like soil, sand, etc. These impurities are called…………
Answer:
An ore contains some of the impurities like soil, sand, etc. These impurities are called gangue.

Question 7.
The process of extraction of a metal from its ore is called……….
Answer:
The process of extraction of a metal from its ore is called metallurgy.

Question 8.
Bauxite is a common ore of………..
Answer:
Bauxite is a common ore of aluminium.

Question 9.
…………. process is used for the purification of bauxite.
Answer:
Bayer’s process is used for the purification of bauxite.

Question 10.
During the electrolysis of alumina, ………..is liberated at the anode.
Answer:
During the electrolysis of alumina, oxygen is liberated at the anode.

Question 11.
The reaction of iron oxide with aluminium is known as…………..reaction.
Answer:
The reaction of iron oxide with aluminium is known as thermit reaction.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 12.
The process of coating a thin layer of zinc on iron is known as…………
Answer:
The process of coating a thin layer of zinc on iron is known as galvanising.

Question 13.
The metal that produces a sound on striking a hard surface is said to be………….
Answer:
The metal that produces a sound on striking a hard surface is said to be sonorous.

Question 14.
The process in which carbonate ores are changed into oxides by heating strongly in limited air is known as …………….
Answer:
The process in which carbonate ores are changed into oxides by heating strongly in limited air is known as calcination.

Question 15.
…………compounds are insoluble in solvents like kerosene and petrol.
Answer:
Ionic compounds are insoluble in solvents like kerosene and petrol.

Question 16.
…………… is used to obtain pure metals from impure metals.
Answer:
Electrolys is method is used to obtain pure metals from impure metals.

Question 17.
Corrosion can be prevented-by putting a layer of…………metal on corrosionable metal.
Answer:
Corrosion can be prevented by putting a layer of non-corrosionable metal on corrosionable metal.

Rewrite the following statements by selecting the correct options:

Question 1.
………… is a metal.
(a) Mg
(b) S
(c) P
(d) Br
Answer:
Mg is a metal.

Question 2.
………. is a nonmetal.
(a) Au
(b) Hg
(c) Br
(d) Cu
Answer:
Br is a nonmetal.

Question 3.
………… is a metalloid.
(a) Aluminium
(b) Antimony
(c) Zinc
(d) Mercury
Answer:
Antimony is a metalloid.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 4.
Metalloids have properties of ………..
(a) metals
(b) nonmetals
(c) both metals and nonmetals
(d) neither metals nor nonmetals
Answer:
Metalloids have properties of both metals and nonmetals.

Question 5.
…………. is a good conductor of electricity.
(a) Bromine
(b) Iodine
(c) Graphite
(d) Sulphur
Answer:
Graphite is a good conductor of electricity.

Question 6.
………. is a metal which is in liquid form at ordinary temperature and pressure.
(a) Magnesium
(b) Sodium
(c) Scandium
(d) Mercury
Answer:
Mercury is a metal which is in liquid form at ordinary temperature and pressure.

Question 7.
………. is an amphoteric oxide.
(a) Na2O
(b) MgO
(c) ZnO
(d) SO2
Answer:
ZnO is an amphoteric oxide.

Question 8.
……….. is an acidic oxide.
(a) Na2O
(b) CO2
(c) FeO3
(d) H2O
Answer:
CO2 is an acidic oxide.

Question 9.
………. is a basic oxide.
(a) CO2
(b) K2O
(C) SO2
(d) Al2O3
Answer:
K2O is a basic oxide.

Question 10.
………… is an ore of aluminium.
(a) Cryolite
(b) Bauxite
(c) Haematite
(d) Aluminium carbonate
Answer:
Bauxite is an ore of aluminium.

Question 11.
Bronze is an alloy of ………..
(a) copper and tin
(b) copper and zinc
(c) copper and iron
(d) iron and nickel
Answer:
Bronze is an alloy of copper and tin.

Question 12.
An alloy prepared from iron, nickel and chromium is known as …………
(a) brass
(b) bronze
(c) stainless steel
(d) amalgam
Answer:
An alloy prepared from iron, nickel and chromium is known as stainless steel.

Question 13.
…………. is an allotropic form of a nonmetal which conducts electricity.
(a) Sulphur
(b) Graphite
(c) Chlorine
(d) Iodine
Answer:
Graphite is an allotropic form of a nonmetal which conducts electricity.

Question 14.
………….. has an oxide which is soluble in sodium hydroxide.
(a) Calcium
(b) Magnesium
(c) Iron
(d) Zinc.
Answer:
Zinc has an oxide which is soluble in sodium hydroxide.

Question 15.
………… prevents the rusting of iron.
(a) Copper
(b) Zinc
(c) Aluminium
(d) Silver
Answer:
Zinc prevents the rusting of iron.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 16.
………….. is obtained by the reduction of its oxide by carbon.
(a) Zinc
(b) Aluminium
(c) Sodium
(d) Potassium
Answer:
Zinc is obtained by the reduction of its oxide by carbon.

Question 17.
………….. is used as an anode during the electrolytic reduction of bauxite.
(a) Sulphur
(b) Graphite
(c) Platinum
(d) Aluminium
Answer:
Graphite is used as an anode during the electrolytic reduction of bauxite.

Question 18.
Silver gets corroded due to ………… in air.
(a) oxygen
(b) hydrogen sulphide
(c) carbon dioxide
(d) nitrogen
Answer:
Silver gets corroded due to hydrogen sulphide in air.

Question 19.
…………. is the hardest substance and has the highest melting and boiling points.
(a) Iodine
(b) Sulphur
(c) Diamond
(d) Phosphorus
Answer:
Diamond is the hardest substance and has the highest melting and boiling points.

Question 20.
Jewellery articles are gold plated ………….
(a) to prevent corrosion
(b) to prevent rusting of the base metal
(c) to make articles attractive
(d) all of these
Answer:
(d) all of these

Question 21.
To show that zinc is more reactive than copper, the correct procedure is to ………..
(a) prepare copper sulphate solution and dip a zinc strip in it
(b) prepare zinc sulphate solution and dip a copper strip in it
(c) heat together zinc and copper strips
(d) add dil. nitric acid to both the strips
Answer:
To show that zinc is more reactive than copper, the correct procedure is to prepare copper sulphate solution and dip a zinc strip in it.

Question 22.
Iron is ………
(a) more reactive than zinc
(b) more reactive than aluminuium
(c) less reactive than copper
(d) less reactive than aluminium
Answer:
Iron is less reactive than aluminium.

Question 23.
A solution of Al2(SO4)3 in water is …………
(a) blue
(b) pink
(c) green
(d) colourless
Answer:
A solution of Al2(SO4)3 in water is colourless.

Question 24.
A solution of ………… in water is blue in colour.
(a) CuSO4
(b) FeSO4
(c) ZnSO4
(d) Al2(SO4)3
Answer:
A solution of CuSO4 in water is blue in colour.

Question 25.
A solution of …………. n water is green in colour.
(a) CuSO4
(b) FeSO4
(c) ZnSO4
(d) Al2(SO4)3
Answer:
A solution of FeSO4 in water is green in colour.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 26.
What would be the correct order if Zn, Fe, Al and Cu are arranged in increasing order of reactivity?
(a) Cu, Fe, Zn, Al
(b) Al, Cu, Fe, Zn
(c) Zn, Al, Cu, Fe
(d) Fe, Zn, Al, Cu (Practice Activity Sheet – 2)
Answer:
(a) Cu, Fe, Zn, Al

Question 27.
During the extraction of aluminium ……….
(a) Ingredients and gangue in bauxite
(b) Use of leaching during the concentration of ore
(c) Chemical reaction of transformation of bauxite into alumina by Hall’s process.
(d) Heating the aluminium ore with concentrated caustic soda.
Answer:
During the extraction of aluminium Chemical reaction of transformation of bauxite into alumina by Hall’s process.

Question 28.
A solution of CuSO4 in water is ………… in colour.
(a) pink
(b) blue
(c) colourless
(d) green
Answer:
A solution of CuSO4 in water is blue in colour.

Question 29.
Which of the following process is to be carried out to avoid the formation of greenish layer on brass vessels due to corrosion?
(a) Plating
(b) Anodization
(c) Tinning
(d) Alloying (Practice Activity Sheet – 3)
Answer:
(c) Tinning

State whether the following statements are True or False (If a statement is false, correct it and rewrite it.):

Question 1.
Metals are known as sonar metals.
Answer:
True.

Question 2.
Diamond is the softest natural substance.
Answer:
False. (Diamond is the hardest natural substance.)

Question 3.
Electrolysis method is used to obtain pure metals from impure metals.
Answer:
True.

Question 4.
Iodine and diamond are lustrous substances.
Answer:
True.

Question 5.
Aqua Regia is a mixture of conc. HCl and conc. HNO3 in the ratio of 1:3.
Answer:
False. (Aqua Regia is a mixture of conc. HCl and conc. HNO3 in the ratio of 3:1.)

Question 6.
Corrosion of metals can be stopped by detaching the air from metals.
Answer:
True.

Question 7.
Due to corrosion a greenish layer forms on the surface of copper or brass vessel.
Answer:
True.

Question 8.
Ionic compounds are soluble in kerosene.
Answer:
False. (Ionic compounds are soluble in water and insoluble in kerosene.)

Question 9.
Ionic compounds in the solid state conduct electricity.
Answer:
False. (Ionic compounds in the solid state do not conduct electricity.)

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 10.
Mercury, silver and gold are very reactive metals.
Answer:
False. (Mercury, silver and gold are least reactive metals.)

Question 11.
In electroplating a metal is coated with another metal using electrolysis.
Answer:
True.

Question 12.
In anodising method. the copper or aluminium article is used as anode.
Answer:
True.

Question 13.
Silver plated spoon, gold plated ornaments are the examples of alloying.
Answer:
False. (Silver plated spoon, gold plated ornaments are the examples of electroplating)

Question 14.
silver amalgam is mainly used by dentists.
Answer:
True.

Question 15.
Aluminium oxide is an acidic oxide.
Answer:
False. (Aluminium oxide is an amphoteric oxide.)

Question 16.
copper reacts with moist carbon form copper carbonate.
Answer:
True.

Question 17.
Corrosion is degradation of a reaction with its environment.
Answer:
True.

Find the correlation in the given pair and rewrite the answer:

Question 1.
Brass : Copper and Zinc :: Bronze :………….
Answer:
Brass : Copper and Zinc :: Bronze : Copper and tin

Question 2.
Tinning : Tin :: Galvanizing :…………….
Answer:
Tinning : Tin :: Galvanizing : Zinc

Question 3.
Pressure cooker : Anodizing :: Silver plated spoons :…………..
Answer:
Pressure cooker : Anodizing :: Silver plated spoons : Electro-plating

Question 4.
The sulphides ores are strongly heated in air : Roasting :: The carbonates ores are strongly heated in a limited supply of air :………….
Answer:
The sulphides ores are strongly heated in air : Roasting :: The carbonates ores are strongly heated in a limited supply of air : Calcination.

Question 5.
Sulphide ores : Froth floatation method : Cassiterite ore :………..
Answer:
Sulphide ores : Froth floatation method : Cassiterite ore : Magnetic separation method.

Find the odd one out:

Question 1.
Sodium, Potassium, Silver, Sulphur
Answer:
Sulphur. (All except sulphur, others are metals.)

Question 2.
Boron, Chlorine, Bromine, Fluorine
Answer:
Boron. (All except boron, others are nonmetals.)

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 3.
Copper, Iron, Mercury, Brass
Answer:
Brass. (All except brass, others are metals.)

Question 4.
Brass, Bronze, Phosphorus, Stainless steel
Answer:
Phosphorus. (All except phosphorus, others are alloys.)

Question 5.
Magnesium chloride, Sodium chloride, Water, Zinc chloride
Answer:
Water. (All except water, others are ionic compounds.)

Question 6.
Tinning, Anodization, Alloying, Froth floatation (March 2019)
Answer:
Froth floatation. (All except froth floatation, others are processes of coating a thin layer of metal on the surface of other metals.)

Match the following:

Question 1.

Column I Column II
(1) ZnS (a) Cuprous sulphide
(2) HgS (b) Bauxite
(3) Cu2S (c) Zinc blend
(4) Al2O3.H2O (d) Cinnabar
(e) Cryolite

Answer:
(1) ZnS – Zinc blend
(2) HgS – Cinnabar
(3) Cu4S – Cuprous sulphide
(4) Al2O3.H2O – Bauxite.

Question 2.

Column I Column II
(1) Copper and zinc (a) Stainless steel
(2) Copper and tin (b) Zinc amalgam
(3) Iron, nickel and chromium (c) Bronze
(4) Mercury and zinc (d) Brass
(e) Steel

Answer:
(1) Copper and zinc – Brass
(2) Copper and tin – Bronze
(3) Iron, nickel and chromium – Stainless steel
(4) Mercury and zinc – Zinc amalgam.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 3.

Column I Column II
(1) Galvanising (a) Pressure cooker
(2) Tinning (b) Silver plated spoons
(3) Electroplating (c) Coating of tin on copper
(4) Anodizing (d) Coating of Zn on iron

Answer:
(1) Galvanising – Coating of Zn on iron
(2) Tinning – Coating of tin on copper
(3) Electroplating – Silver plated spoons
(4) Anodizing – Pressure cooker.

Translate the following statements into chemical equations and then balance them:

Question 1.
steam is passed over aluminium.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 9

Question 2.
Extraction of copper from its sulphide ore.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 10
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 11

Question 3.
Thermit reaction.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 12

Question 4.
Magnesium reacts with hot water.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 13

Question 5.
what happens when aluminium oxide dissolves in aqueous sodium hydroxide?
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 14

Question 6.
Zinc reacts with sulphuric acid.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 15

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 7.
Iron reacts with sulphuric acid.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 16

Name the following:

Question 1.
A metal which forms an amphoteric oxide.
Answer:
Aluminium forms an amphoteric oxide.

Question 2.
An alloy of copper and zinc.
Answer:
An alloy of copper and zinc is termed as brass.

Question 3.
A compound which is added to lower the fusion temperature.
Answer:
Cryolite (AlF3, 3NaF) and fluorspar (CaF2) are added to lower the fusion temperature.

Question 4.
A metal which does not react with cold water but reacts with steam.
Answer:
Aluminium does not react With cold water but reacts with Steam.

Question 5.
A common ore of aluminium.
Answer:
Bauxite (Al2O3.H2O) is a common ore of aluminium.

Question 6.
A metal which is in liquid state at ordinary temperature.
Answer:
Mercury is in liquid state at ordinary temperature.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 7.
Two metals which are malleable.
Answer:
Iron and aluminium are malleable metals.

Question 8.
Two metals which are ductile.
Answer:
Gold and silver are ductile metals.

Question 9.
Two metals which are good conductors of heat.
Answer:
Silver and copper are good conductors of heat.

Question 10.
Two metals which are good conductors of electricity.
Answer:
Copper and aluminium are good conductors of electricity.

Question 11.
Two metals which are used for making cooking vessels.
Answer:
Copper and aluminium are used in making cooking vessels.

Question 12.
Two metals having low melting points.
Answer:
Sodium and potassium have low melting points.

Question 13.
Two highly reactive metals.
Answer:
Sodium and potassium are highly reactive metals.

Question 14.
A nonmetal which is in liquid state at room temperature.
Answer:
Bromine is in liquid state at room temperature.

Question 15.
Two ionic compounds.
Answer:
Sodium chloride (NaCl) and magnesium chloride (MgCl2) are ionic compounds.

Question 16.
The process of heating the sulphide ore to a high temperature in the excess of air.
Answer:
In roasting, sulphide ore is heated to a high temperature in the excess of air.

Question 17.
The process of heating the carbonate ore to a high temperature in limited air.
Answer:
In calcination, carbonated ore is heated to a high temperature in limited air.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 18.
The compound formed by the reaction between aluminium oxide and sodium hydroxide.
Answer:
Sodium aluminate is formed by the reaction between aluminium oxide and sodium hydroxide.

Question 19.
Two metals which are found in the free state in nature.
Answer:
Gold (Au) and silver (Ag) are found in the free state in nature.

Question 20.
A metal which has the highest melting point.
Answer:
Tungsten has the highest melting point.

Question 21.
Two nonmetals which are lustrous.
Answer:
Iodine and diamond are lustrous in nature.

Answer the following questions in one sentence each:

Question 1.
State the property of the metals due to which they can be drawn into wires.
Answer:
The property of the metal due to which they can be drawn into wires is called ductility.

Question 2.
State the property of the metals due to which they can be beaten into thin sheets.
Answer:
The property of the metals due to which they can be beaten into thin sheets is called malleability.

Question 3.
Which is the hardest substance?
Answer:
Diamond which is a form of carbon is the hardest substance.

Question 4.
What material is used to coat electrical wires?
Answer:
PVC (Polyvinyl chloride) is used to coat electrical wires.

Question 5.
State two metals which can be cut easily with a knife.
Answer:
Sodium and potassium are soft metals and can be cut easily with a knife.

Question 6.
Which of the following metals react with cold water?
Sodium, iron, copper, potassium.
Answer:
Sodium and potassium metals react with cold water.

Question 7.
Which of the following metals do not react with cold water or hot water?
Sodium, potassium, aluminium, iron.
Answer:
Aluminium and iron do not react with cold water or hot water.

Question 8.
State two metals which displace hydrogen from dilute acids and two metals which do not do so.
Answer:
Metals which displace hydrogen from dilute acids are: Magnesium and zinc.
Metals which do not displace hydrogen from dilute acids are: Copper and silver.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 9.
Arrange the following metals in the increasing order of their activity:
Copper, Silver, Aluminium, Iron. (Practice Activity Sheet – 1)
Answer:
The arrangement of metals in the increasing order of their activity:
Silver < Copper < Iron < Aluminium

Question 10.
Write the chemical equation for the reaction of hot iron with steam.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 17

Question 11.
Complete the following reactions:
(1) Zn(s) + H2O(g) → _____________
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 18
Answer:
(1) Zn(s) + H2O(g) → ZnO(s) + H2(g)
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 19

Question 12.
Complete the following reactions:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 20
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 21

Question 13.
3MnO2 + 4Al → 3Mn + 2Al2O3 + heat.
Identify the substances undergone oxidation and reduction reactions.
Answer:
MnO2 is reduced to Mn.
Al is oxidised to Al2O3

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 14.
State the impurities present in the bauxite ore.
Answer:
The main impurities present in the bauxite ore are silica (SiO2) and iron oxide (Fe2O3).

Question 15.
Write the formula of (i) bauxite (ii) cryolite.
Answer:
The formula of bauxite is Al2OH2O and that of cryolite is (Na3AlF6).

Question 16.
What is galvanization?
Answer:
The process of coating a thin layer of zinc on iron or steel is called galvanization.

Question 17.
Name the reaction in which aluminium is used as a reducing agent.
Answer:
The thermite reaction in which iron oxide is reduced by aluminium. Aluminium is used as a reducing agent in the thermit reaction.

Question 18.
What are the constituents of bronze?
Answer:
Copper and tin are the constituents of bronze.

Question 19.
State the term used to express the purity of gold.
Answer:
The purity of gold is expressed in carat.

Question 20.
What is meant by amalgam?
Answer:
The amalgam is an alloy in which one of the metals is mercury.

Question 21.
What is meant by electroplating?
Answer:
A process in which a less reactive metal is coated on a more reactive metal by electrolysis is called electroplating.

Question 22.
Why are metals called electropositive elements?
Answer:
Metals are reactive. They lose electrons and become positively charged ions. Therefore, metals are called electropositive elements.

Answer the following questions:

Question 1.
Distinguish between the physical properties of metals and nonmetals with respect to the following points:
(1) Physical state (2) Lustre (3) Ductility and malleability (4) Conduction of heat and electricity (5) Hardness (6) Melting and boiling points.
Answer:
(1) Physical state: Under ordinary conditions, metals are generally solids. Exceptions: mercury and gallium are liquids. Under ordinary conditions, nonmetals may be solids or gases. Exception: bromine is in liquid state.

(2) Lustre: Metals usually have a high lustre (called metallic lustre). They can be polished to give a highly reflective surface. With the exceptions of gold and copper, metals usually have silvery grey colour. Nonmetals lack lustre, exceptions: graphite and iodine. Some nonmetals are colourless and others possess a variety of colours.

(3) Ductility and malleability: Metals are ductile and malleable. Nonmetals are not ductile and mallfeable.

(4) Conduction of heat and electricity: Metals are good conductors of heat and electricity. Nonmetals are bad conductors of heat and electricity. Exception: Graphite is a good conductor of electricity.

(5) Hardness: Metals are usually hard, but not brittle, exceptions: sodium, potassium, lead, zinc. Nonmetals are brittle in the solid state, exception: diamond.

(6) Melting and boiling points: The melting and boiling points of metals are high, exceptions: sodium, potassium, mercury, gallium. The melting and boiling points of nonmetals are low, exceptions: carbon, silicon.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 2.
Write any three physical properties of nonmetals.
Answer:

  1. Nonmetals may be solid or gaseous.
  2. Nonmetals lack lustre. They are not ductile and malleable.
  3. The melting and boiling points of nonmetals are low.
  4. Nonmetals are bad conductors of heat and electricity.

Question 3.
Metals are good conductors of heat. Explain why.
Answer:
(1) The electrons in the outermost shells of atoms of a metal are free to move throughout the metal.
(2) When a metal is heated, these electrons start moving with higher velocity and conduct heat. Hence, metals are good conductors of heat.

Question 4.
Metals are good conductors of electricity. Explain why.
Answer:
(1) The electrons in the outermost shells of atoms of a metal are free to move throughout the metal.
(2) When a potential difference is applied between the ends of a metal wire, the net movement of the electrons in a particular direction, from a point at lower potential to a point at higher potential, constitutes an electric current. Hence, metals are good conductors of electricity.

Question 5.
A metal can be drawn into a wire. Explain why.
Answer:

  1. The property due to which a substance can be drawn into a thin wire without cracking or breaking is called ductility.
  2. Metals are ductile. Thus, a metal can be drawn into a wire.

Question 6.
A metal can be hammered into a thin sheet. Explain why.
Answer:

  1. The property due to which a substance can be hammered (or rolled) into a thin sheet without cracking is called malleability.
  2. Metals are malleable. Thus, a metal can be hammered to form a thin sheet.

Question 7.
How do metals react with oxygen?
Answer:
Metals combine with oxygen on heating in air and metal oxides are formed.
Metal + Oxygen → Metal oxide
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 22

Question 8.
How does a metal react with water?
Answer:
Sodium and potassium react vigorously with water to evolve hydrogen. Calcium reacts with water slowly and less vigorously to evolve hydrogen and the metal floats on water. Magnesium reacts with hot water to evolve hydrogen. Aluminium, iron and zinc do not react with cold or hot water but they react with steam to evolve their oxides and hydrogen.
2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g) + heat energy
2K(s) + 2H2O(l) → 2KOH(aq) + H2(g) + heat energy
2Ca(s) + 2H2O(l) → 2Ca(OH)2(aq) + H2(g)
Mg(s) + 2H2O(hot) → Mg(OH)2(aq) + H2(g)
2Al(s) + 3H2O steam → Al2O3(s) + 3H2(g)
3Fe(s) + 4H2O steam → Fe3O4 + 4H2(g)
Zn(s) + H2O steam → ZnO(s) + H2(g)

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 9.
(9) How does a metal react with an acid?
Answer:
Reaction of metals with acids: Metals react with dilute hydrochloric acid or dilute sulphuric acid to form metal chloride or metal sulphate and hydrogen gas. The rate of evolution of H2 is maximum in case of magnesium. The reactivity decreases in the order
Mg > Al > Zn > Fe.
Mg(s) + 2HCl(aq) → MgCl2(s) + H2(g)
2Al(s) + 6HCl(aq) → 2AlCl3(aq) + 3H2(g)
Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)
Fe(s) + 2HCl(aq) → FeCl2(aq) + H2(g)
Fe(s) + H2SO4(aq) → FeSO4 + H2(g)
Zn(s) + H2SO4(aq) → ZnSO4 + H2(g)
Mg(s) + H2SO4(aq) → MgSO4(aq) + H2(g)

Question 10.
How does a metal react with nitric acid?
Answer:
Metals react with nitric acid to form nitrate salts. Depending on the concentration of nitric acid, various oxides of nitrogen (NO, NO2) are formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 23

Question 11.
Arrange the following metals in the decreasing order of chemical reactivity:
Cu, Mg, Fe, Ca, Zn, Na.
Answer:
The reactivity of metal decreases in the following order:
Na > Mg > Ca > Zn > Fe > Cu.

Question 12.
What is meant by aqua regia?
Answer:
Aqua regia is a highly corrosive and fuming liquid. It is a freshly prepared mixture of conc. HCl and conc. HNO3 in the ratio of 3:1. Most of the substances dissolve in it. Aqua regia is a reagent which dissolves gold and platinum.

Question 13.
How does a metal react with salts of other metals?
Answer:
The reaction of metals with solutions of salts of other metals is the displacement reaction. If a metal A displaces other metal B from the solution of its salt, it means that the metal A is more reactive than the metal B.
Metal A + Salt solution of metal B → Salt solution of metal A + metal B
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 24
In this reaction Fe has displaced Cu from CuSO4. It means Fe is more reactive than Cu.

Question 14.
Explain the reactivity series of the metals.
Answer:
The arrangement of metals in decreasing order of their reactivity in the form of a series is called the reactivity or activity series of the metals.
The most reactive metal is placed at the top of the list and least reactive metal is placed at the bottom of the list.

On the basis of reactivity, we can classify metals into the following categories:

  1. High reactivity metals
  2. Moderately reactive metals
  3. Less reactive metals.

1. Extraction of High reactivity metals: The metals which are placed at the top of the reactivity series are very reactive. They are never found in nature as free elements, e.g., sodium, potassium, calcium and aluminium. These metals are obtained by electrolytic reduction.

2. Extraction of Moderately reactive metals: The metals in the middle of reactivity series such as iron, zinc, lead, copper are moderately reactive. These elements are present as sulphides or carbonates in nature. Generally metals are obtained from their oxide as compared to their sulphides and carbonates.

3. Extraction of Less reactive metals: The metals which are placed at the bottom of the reactivity series are least reactive. They occur in free state, e.g. gold, silver and copper. Copper and silver are also found in the combined state as sulphide and oxide ores. These metals are obtained from their ores by just heating the ores in air.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 15.
Atomic number of metal “A” is 11, while atomic number of metal “B” is 20. Which of them will be more reactive? Write the chemical reaction of dilute HCl with metal “A”. (Practice Activity Sheet – 2)
Answer:
Metal ‘A’ is more reactive than metal ‘B’.
Atomic number of metal ‘A’ is 11, hence it is Na.
2Na + 2HCl → 2NaCl(aq) + H2(g)

Question 16.
How does a metal react with a nonmetal?
Answer:
By oxidation of a metal, cations are formed, on the other hand by reduction of a nonmetal, anions are formed. The ionic compound is formed due to the metal losing electrons while the nonmetal accepts the electrons. The ionic compound of sodium chloride is formed as sodium loses one electron while chlorine accepts one electron.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 25
Similarly Mg and K form ionic compounds MgCl2 and KCl.

Question 17.
How do nonmetals react with oxygen?
Answer:
Nonmetals combine with oxygen to form acidic oxides. In some cases, neutral oxides are formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 26

Question 18.
How do nonmetals react with water?
Answer:
Nonmetals do not react with water, (exception : halogen). Chlorine dissolves in water giving hypochlorous acid.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 27

Question 19.
How do nonmetals react with dilute acids?
Answer:
Nonmetals do not react with dilute acid, (exception: halogen). Chlorine reacts with dil. hydrobromic acid to form bromine and HCl.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 28

Question 20.
How do nonmetals react with hydrogen?
Answer:
Nonmetals react with hydrogen under certain conditions (such as proper temperature, pressure, catalyst, etc.)
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 29

Question 21.
What is meant by an ionic compound?
Answer:
The compound formed from two units, namely cation and anion is called an ionic compound.

Question 22.
What is meant by an ionic bond?
Answer:
The cation and anion being oppositely charged, there is an electrostatic force of attraction between them, this force of attraction between cation and anion is called the ionic bond.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 23.
State the general properties of ionic compounds.
Answer:

  1. Ionic compounds are solids and hard due to strong electrostatic force of attraction between oppositely charged ions.
  2. They are generally brittle. When pressure is applied they break into pieces.
  3. They have high melting and boiling points, due to intermolecular force of attraction is high in ionic compounds.
  4. They are soluble in water and insoluble in solvents such as kerosene and petrol.
  5. Ionic compounds cannot conduct electricity when in solid state, they are electrically neutral. They conduct electricity in the molten state and also in an aqueous solution.

Question 24.
Explain the following terms:
1. Concentration of ores
2. Roasting
3. Calcination
4. Refining
Answer:
1. Concentration of ores: The process of separating gangue from the other ores is called concentration of ores.
2. Roasting: The process of heating an ore to a high temperature in excess of air and converting it into its oxide is called roasting.
Examples: ZnS (zinc blend), PbS (Galena)
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 30
3. Calcination: The process of heating an ore in a limited supply of air and converting it into its oxide is called calcination.
Example: Zinc carbonate (ZnCO3)
ZnCO3 → ZnO + CO2
4. Refining: The metal obtained by chemical reduction contains impurities. The process of electrolysis method is used to obtain pure metals from impure metals is known as refining.

Question 25.
State two methods of concentration of ores in which the heavy particles of ores can be separated from the light gangue particles by the gravitational method.
Answer:

  1. Wilfley table method
  2. Hydraulic separation method are two methods of concentration of ores in which the heavy particles of ores can be separated from the light, gangue particles by the gravitational method.

Question 26.
What are the different methods used for removing gangue from ores?
(OR)
Write the five methods of concentration of ores.
Answer:

  1. Wilfley table method
  2. Hydraulic separation method
  3. Magnetic separation method
  4. Froth floatation method
  5. Leaching method.

Question 27.
Write short notes on: (1) Wilfley table method (2) Hydraulic separation method (3) Magnetic separation method (4) Froth floatation method (5) Leaching method.
Answer:
(1) Wilfley table method : (Separation based on gravitation) This method of separation uses the Wilfley table, it is made by fixing narrow and thin wooden wedges/blocks on inclined surface with low slope. The table is kept continuously vibrating.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 31
Lumps of the ore is made powdered ore by using ball mill. This powdered ore is poured on the table and a stream of water is simultaneously released from the upper side. This result in the lighter gangue particles getting carried away along with the flowing water, while the heavier particles in which proportion of minerals is more and proportion of gangue particles is less, are blocked by the wooden wedges and is collected through the slits between them.

(2) Hydraulic separation method: The hydraulic separation method is based on the working of a mill. This is a tapering vessel similar to that used in a grinding mill. It opens in a tank like a container that is tapering on the lower side. The tank has an outlet for water on the upper side and a water inlet on the lower side.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 32
Finely ground ore is added to the tank. A fast stream of water is released in the tank from the lower side. The lighter gangue particles flow out along with the water stream from the outlet on the upper side of the tank and are collected separately, simultaneously the heavy particles of the ore are collected at the bottom from the lower side of the tank. This method is based on the law of gravitation, wherein particles of the same size are separated by their weight with the help of water.

(3) Magnetic separation method: Electro-magnetic machine is used in this method. The main parts of this machine are two types of iron rollers and the conveyor belt continuously moving around them. One of the rollers is nonmagnetic while the other is electromagnetic. The conveyor belt moving around the rollers is made up of leather or brass (nonmagnetic). The powdered ore is poured at that end of the conveyor belt which is on the side of the nonmagnetic roller. Two collector vessels are placed below the magnetic roller.

The particles of the nonmagnetic part in the ore are not attracted towards the magnetic roller. Therefore, they are carried out further along the belt and fall in the collector vessel which is away from the magnetic roller. Simultaneously the particles of the magnetic ingredients of the ore stick to the magnetic roller and therefore fall in the collector vessel near the belt.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 33
In this way the magnetic and nonmagnetic particles in the ore are separated because of their magnetic nature. For example, cassiterite is a tin ore. It contains mainly the nonmagnetic ingredient stannic oxide (SnO2) and the magnetic ingredient ferrous tungstate (FeWO4). These are separated by the electromagnetic method.

(4) Froth floatation method: The froth floatation method is based on the two opposite properties, hydrophilic and hydrophobic, of the particles. The metal sulphides particles get wet mainly with oil due to their hydrophobic property. The gangue particles get wet with water due to the hydrophilic property.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 34
In this method the finely ground mineral is put into a big tank containing a lot of water. The finely powdered ore and vegetable oil such as pine oil, eucalyptus oil are mixed with water for formation of froth. The pressurised air is blown through the mixture. There is an agitator rotating around its axis in the centre of the floatation tank. The agitator is used as per the requirement. Bubbles are formed due to the blown air.

A foam is formed from oil, water and air bubbles together, due to the agitating. This foam rises to the surface of the water and floats. Hence this method is called froth floatation. Sulphide minerals float with the foam on water as they get and can be removed. The gangue particles are wetted by water, settles down at the bottom. This method is used for concentration of zinc blend (ZnS) and copper pyrite (CuFeS2).

(5) Leaching: Leaching is the first step in the extraction of the metals like aluminium, gold and silver from their ores. In this method the ore is soaked in a particular solution for long time. The ore dissolves in that solution due to specific chemical reaction. The gangue, however, does not react and therefore does not dissolve in that solution. It can be separated easily.

For example, concentration of bauxite, the aluminium ore, is done by leaching method. Bauxite is soaked in aqueous NaOH or aqueous Na2CO3 which dissolves the main ingredient alumina in it. This means that bauxite is leached by sodium hydroxide.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 28.
Draw a neat labelled diagram of the arrangement of the equipment used in (1) Wilfley table method (2) Hydraulic separation method.
Answer:
1. Wilfley table method:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 35

2. Hydraulic separation method:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 36

Question 29.
Complete the following flow chart and answer the questions below:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 37
(i) In which method pine oil is used?
(ii) Explain that method of concentration in brief. (Practice Activity Sheet – 2)
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 38
(i) Pine oil is used in froth floatation method.

(ii) The finely powdered ore and vegetable oil such as pine oil, eucalyptus oil are mixed with water for formation of froth. The pressurised air is blown through the mixture. The agitator is used as per the requirement. Bubbles are formed due to the blown air. A foam is formed from oil, water and air bubbles together, due to the agitating. This foam rises to the surface of the water and floats. Hence this method is called froth floatation. Sulphide minerals float with the foam on water as they get and can be removed. The gangue particles are wetted by water, settles down at the bottom. This method is used for concentration of zinc blend (ZnS) and copper pyrite (CuFeS2).

Question 30.
A tapping vessel opens in a tank like container that is tapering on the lower side. The tank has an outlet for water on the upper side and a water inlet on the lower side. Finely ground ore is released in the tank. A forceful jet of water is introduced in the tank from lower side and gangue particles and pure ore are separated by this method.
(i) The above description is of which gravitation separation method?
(ii) Draw labelled diagram of this method. (March 2019)
Answer:
(i) Hydraulic separation method.
(ii)
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 39

Question 31.
How are sodium, magnesium and potassium obtained from their molten chloride salts?
Answer:
The metals sodium, calcium and magnesium are obtained by electrolysis of their molten chloride salts. In this process metal is deposited on the cathode while chlorine gas is liberated at the anode.

Question 32.
Name the main ore of aluminium.
Answer:
Bauxite (Al2O3·H2O) is the main ore of aluminium.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 33.
What is bauxite? What are the main impurities found in this ore?
Answer:
Bauxite (Al2O3·H2O) is hydrated aluminium oxide. It contains 30% to 70% Al2O3. The main impurities present in it are iron oxide (Fe2O3) and sand (SiO2).

Question 34.
From which ore is aluminium extracted? What are the stages in its extraction (give only names)?
Answer:
Aluminium is extracted from bauxite (Al2O3·nH2O). Stages id the extraction: (i) Concentration of ore, i.e., conversion of bauxite into alumina, (ii) Electrolytic reduction of alumina.

Question 35.
Describe Bayer’s process for concentration of bauxite.
Answer:
(1) Bayer’s process is used to obtain pure aluminium oxide from bauxite.
(2) Bauxite is then concentrated by chemical separation. Bauxite contains impurities like iron oxide (Fe2O3) and silica (SiO2).
(3) Bauxite ore is powdered and heated with sodium hydroxide under high pressure for 2 to 8 hours at 140 °C in the digester. The aluminium oxide being amphoteric in nature present in bauxite reacts with sodium hydroxide to form water soluble sodium aluminate. This means that bauxite leached by sodium hydroxide. Silica reacts with sodium hydroxide to form soluble sodium silicate. The basic iron oxide (Fe2O3) in the gangue remains unaffected. It is separated by filtration.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 40
(4) The filtrate containing sodium aluminate and sodium silicate is stirred with water and then cooling to 50° C. It is hydrolysed to give precipitate of aluminium hydroxide.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 41
(5) Aluminium hydroxide is then filtered, washed with water, dried and then calcinated by heating at 1000 °C to get pure aluminium oxide.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 42

Question 36.
Describe Hall’s process for concentration of bauxite.
Answer:
In Hall’s process the ore is powdered and then it is leached by heating with aqueous sodium carbonate in the digester to form water soluble sodium aluminate. Then the insoluble impurities are filtered opt. The filtrate is warmed and neutralised by passing carbon dioxide gas through it. This result in precipitation of aluminium hydroxide.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 43
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 44
The precipitate of Al(OH)3 obtained in this processes is filtered, washed, dried and then calcinated by heating at 1000 °C to obtain alumina.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 45

Question 37.
Describe the process of preparation of aluminium by the electrolysis of alumina.
(OR)
Draw and label the diagram of electrolysis of alumina and explain the electrolytic reduction of alumina.
Answer:
Electrolytic reduction of alumina:
(1) The electrolytic cell consists of a rectangular steel tank lined from inside with graphite.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 46
(2) The carbon lining (graphite) acts as a cathode. The anode consists of graphite rods suspended in the molten electrolyte.
(3) Alumina has very high melting point ( > 2000 °C). The electrolysis of alumina is carried out at a low temperature by dissolving it in molten cryolite (Na3AlF6). The solution of alumina in cryolite and small amount of fluorspar (CaF2) is added in the mixture to lower its melting point up to 1000 °C.
(4) On passing an electric current, alumina is electrolysed.
(5) Molten aluminium is collected at the cathode, while oxygen gas is evolved at the anode.
The electrode reactions are shown below:
Al2O3 → 2Al3+ + 3O2-
Anode reaction: 2O2- → O2(g) + 4e
Cathode reaction: Al3+ + 3e → Al
The molten aluminium is heavier than the electrolyte. Therefore, it sinks to the bottom of the electrolyte and is removed from time to time. About 99% pure aluminium is obtained by this process. The oxygen gas liberated reacts with carbon anode and forms carbon dioxide. As the anode gets oxidised during the electrolysis of alumina, it has to be replaced from time to time.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 38.
In the extraction of aluminium:
(i) Name the process of concentration of bauxite.
Answer:
The process of concentration of bauxite is known as Bayer’s process.

(ii) Write the cathode reaction in electrolytic reduction of alumina.
Answer:
At the cathode: Al3+ + 3e → Al.

(iii) Write the function and formula of cryolite in the extraction of aluminium.
Answer:
Cryolite is added to the molten mixture of alumina to reduce the melting point to about 1000 °C.
The formula of cryolite is (Na3AlF6) or AlF3, 3NaF.

(iv) write an equation for the action of heat on aluminium hydroxide.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 47

(v) Draw the diagram of extraction of aluminium.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 48

(vi) Write the anode reaction in electrolytic reduction of alumina.
Answer:
Al2O3 → 2Al3+ + 3O2-
At Anode: 2O2- → O2(g) + 4e

(vii) Write the cathode reaction in electrolytic reduction of alumina.
Answer:
Al2O3 → 2Al3+ + 3O2-
Cathode: Al3+ + 3e → Al(l)

Question 39.
What happens when aluminium ore is heated with caustic soda? Write the balanced chemical equation for the same.
Answer:
When aluminium ore is heated with caustic soda solution under high pressure for 2 to 8 hours and at 140 °C to 150 °C, aluminium oxide from aluminium ore, being amphoteric in nature, dissolves in caustic soda solution to form sodium aluminate.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 49

Question 40.
How is zinc extracted from its ore zinc sulphide or zinc carbonate?
Answer:
The crude zinc sulphide ore is heated strongly in excess of air. Zinc sulphide is converted into zinc oxide. This process is known as roasting.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 50
(OR)
The crude zinc carbonate ore is heated strongly in limited supply of air. Zinc carbonate is converted into zinc oxide. This process is known as calcination.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 51
The zinc oxide is reduced to zinc by using a reducing agent such as carbon.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 52

Question 41.
How is copper extracted from its sulphide ore?
Answer:
Copper is found as cuprous sulphide (Cu2S) in nature. When Cu2S is heated in air, copper is obtained.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 53

Question 42.
How is mercury extracted from cinnabar?
(OR)
Extraction of mercury from its ore cinnabar and write the corresponding chemical reaction.
Answer:
Cinnabar is an ore of mercury. When cinnabar is heated (roasted), it is converted into mercuric oxide (HgO). Mercuric oxide is then reduced to mercury on further heating.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 54

Question 43.
Show the steps involved in the extraction of moderately reactive metals from their sulphide ores.
Answer:
Moderately reactive elements are present as sulphides or carbonates in nature.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 55

Question 44.
In the reactivity series of metals, some metals are misplaced. Rearrange these metals in the decreasing order of their reactivity.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 56
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 57

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 45.
Complete the table, if a metal reacts with the reagent then mark ✓ and if not then ✗.

Metal Ferrous
sulphate
Silver
nitrate
Copper
sulphate
Zinc
sulphate
Cu
Al

Answer:

Metal Ferrous
sulphate
Silver
nitrate
Copper
sulphate
Zinc
sulphate
Cu
Al

Question 46.
Explain the term corrosion with a suitable example.
(OR)
What is corrosion ?
Answer:
The process in which a metal is destroyed gradually by the action of air, moisture or a chemical (like an acid) on its surface is called corrosion.
(OR)
Corrosion is degradation of a material due to reaction with its environment.
The major problem of corrosion occurs with iron, as it is used as a structural material in construction, bridges, shipbuilding.
Iron gets covered by reddish brown flakes when exposed to atmosphere. This is an example of corrosion.

Question 47.
Explain the different methods to prevent corrosion of metals.
Answer:
(1) Corrosion of a metal can be prevented if the contact between metal and air is cut off.
(2) Corrosion of a metal is prevented by coating with something which does not allow moisture and oxygen to react with it.
(3) A layer of oil or paint or grease is applied on the surface of a metal to prevent corrosion. The rusting or corrosion of iron can be prevented by this method.
(4) Corrosion is also prevented by coating a corrosive metal with a noncorrosive metal. Galvanising, tinning, electroplating, anodising and alloying are the different methods in which a metal is coated with a noncorrosive metal to prevent corrosion.

Question 48.
Write three methods of preventing rusting of iron.
Answer:

  1. The rusting of iron can be prevented by painting, oiling, greasing or varnishing its surface.
  2. Galvanisation is another method of protecting iron from rusting by coating iron with a thin layer of zinc.
  3. Corrosion of iron is prevented by coating iron with noncorrosive substance like carbon. This process is termed as alloying.

Question 49.
What is meant by an alloy? Give two examples with chemical composition.
Answer:
The homogeneous mixture formed by mixing a metal with other metals or nonmetals in certain proportion is called an alloy.
Examples:
1. Bronze: Bronze is an alloy formed from 90% copper and 10% tin. Bronze statues stay well in sun and rain.
2. Stainless steel: Stainless steel alloy is made from 74% iron, 18% chromium and 8% carbon. This alloy does not get stained with air or water and does not rust.

Write short notes on the following:

Question 1.
Galvanizing.
Answer:
(1) The process of coating a thin layer of zinc on iron or steel is called galvanization.
(2) In this method corrosion of zinc occurs first because zinc is more electropositive than iron. After a few years zinc layer goes away and the iron layer gets exposed and starts rusting.
(3) In galvanization an iron object is dipped into molten zinc. A thin layer of zinc is formed all over the iron object. Examples: Shiny iron nails, pin, iron pipes.

Question 2.
Tinning.
Answer:
The process of coating a thin layer of tin (molten tin) on copper or brass is called tinning. Cooking vessels made of copper and brass get a greenish coating due to corrosion. The greenish substance is copper carbonate and it is poisonous. If buttermilk or curry is placed in such a vessel it gets spoiled. Therefore, these vessels are coated with tin to prevent corrosion.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 3.
Electroplating.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 58
The process in which a less reactive metal is coated on a more reactive metal by electrolysis is called electroplating.
Examples: Silver-plated spoon, gold-plated jewellery.
(1) Which process will you study with the help of above material and solutions.
Answer:
With the help of above material and solutions, electroplating process is studied.

(2) Define the process.
Answer:
The process in which less reactive metal is coated on a more reactive metals by electrolysis is called electroplating.

(3) Write the anode and cathode reactions.
Answer:
At anode: Ag → Ag+ + e
At cathode: Ag+ + e → Ag

Question 4.
Anodizing.
(OR)
Identify the process shown in the above diagram and explain it in brief. (Practice Activity Sheet – 3)
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 59
Answer:
The anodizing technique is an application of electrolysis. In this method copper or aluminium article is used as anode and it is coated with a strong film of their oxides by means of electrolysis. This oxide layer is strong and uniform all over the surface. This thin film protects the metals from corrosion. The protection can be further increased by making the oxide layer thicker during the anodization.
Examples: Kitchen articles such as ; anodized pressure cooker and anodized pan.

Question 5.
Alloying.
Answer:
A homogenous mixture of two or more metals or a metal and a nonmetal in a definite proportion is called an alloy. The physical properties of an alloy are different from those of its constituents. Alloys are corrosion resistant. Alloy decreases the intensity of corrosion of metals.

Examples: Brass is made from copper and zinc, 90 % Copper and 10 % tin are used to make an alloy called bronze, Stainless steel is made from 74% iron, 8 % carbon and 18 % chromium.

Distinguish between: (Two points of distinction)

Question 1.
Metals and Nonmetals.
Answer:
Metals:

  1. Metals have a lustre.
  2. They are generally good conductors of heat and electricity.
  3. They are generally solids at room temperature.
    Exception: Mercury and gallium are liquids.
  4. Metals form basic oxides.

Nonmetals:

  1. Nonmetals have no lustre.
    Exception: Iodine and Diamond.
  2. They are bad conductors of heat and electricity.
    Exception: Graphite.
  3. They are generally gases and solids at room temperature.
    Exception: Bromine is a liquid.
  4. Nonmetals form acidic or neutral oxides.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 2.
Roasting and Calcination.
Answer:
Roasting:

  1. In this process, the ore is heated strongly in the presence of air.
  2. In this process, sulphide ore is converted into metal oxide.
  3. During this process SO2 is given out.

Calcination:

  1. In this process, the ore is heated strongly in the limited supply of air.
  2. In this process, carbonate ore is converted into metal oxide.
  3. During this process CO2 is given out.

Give scientific reasons for the following:

Question 1.
Calcium floats on water during the reaction with water.
Answer:

  1. Calcium reacts with water less vigorously hence the heat evolved is not sufficient for hydrogen to catch fire.
  2. Instead, calcium floats on water because the bubbles of hydrogen gas formed stick to the surface of the metal.

Question 2.
Common salt has high melting and boiling points.
Answer:

  • Common salt is an ionic compound. Common salt is solid and hard due to strong electrostatic attraction between oppositely charged Na+ and Cl- ions.
  • A large amount of energy is required to break the strong intermolecular attraction (strong ionic bond). Hence, common salt has high melting and boiling points.

Question 3.
Metals are good conductors, while non-metals are poor conductors of electricity.
Answer:

  • The electrons in the outermost orbit of atoms of a metal are free to move throughout the metal.
  • When a potential difference is applied between the ends of a metal wire, the movement of the electrons constitutes an electric current. Hence, metals are good conductors of electricity.
  • Nonmetals involve covalent bonding and do not have free electrons like metals. Hence, nonmetals are poor conductors of electricity.

Question 4.
Sodium is more reactive than aluminium.
Answer:

  • If the number of electrons in the outermost orbit of an atom of a metal is less, the metal is more reactive.
  • Sodium has electronic configuration (2, 8, 1) and aluminium has electronic configuration (2, 8, 3). The number of electrons in the outermost orbit of sodium and aluminium atoms are 1 and 3, respectively. Hence, sodium is more reactive than aluminium.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 5.
When zinc granules are added to copper sulphate solution, the blue coloured solution turns colourless.
Answer:

  • Zinc is more reactive than copper.
  • When zinc granules are added to copper sulphate solution, they displace copper from the copper sulphate solution to form zinc sulphate solution. As zinc sulphate is colourless, the blue coloured solution of copper sulphate disappears.

Question 6.
When an iron nail is dipped into a copper solution, a shiny coat of copper is formed on the nail.
Answer:

  • Iron is more reactive than copper.
  • When an iron nail is dipped into copper sulphate solution, iron displaces copper from the copper sulphate solution. The copper so liberated deposits on the iron nail. As a result, a shiny coat of copper is formed on the nail.

Question 7.
Cryolite (Na3AlF6) and fluorspar (CaF2) are added to the electrolytic mixture containing pure alumina.
Answer:
(1) Alumina has very high melting point ( > 2000 °C). Cryolite (Na3AlF6) and fluorspar (CaF2) lower the fusion temperature of the mixture containing alumina from 2000 ° C to 1000 ° C, thereby saving electrical energy.
(2) They increase the conductivity and the mobility of the fused mixture. Hence, cryolite and fluorspar are added to the electrolytic mixture containing pure alumina.

Question 8.
Air is bubbled through the mixture in Froth floatation process.
Answer:
(1) In the froth floatation process, in a tank water, ore and an oil are mixed. When air is bubbled through the mixture the oil forms froth.
(2) The mineral particles are wetted by the oil and float on the surface.
(3) The gangue particles are wetted by water and settle down. Hence, the ore can be concentrated. Hence, air is bubbled through the mixture in froth floatation process.

Question 9.
Silver amalgam is used for filling dental cavities.
Answer:
(1) Silver is a soft metal and wears off on constant usage particularly due to abrasion. Silver amalgam is an alloy of silver with mercury.
(2) It is a hard substance. It is nontoxic. Besides these properties it is a lustrous shining substance. It melts at a comparatively low temperature and can therefore conveniently fill in the cavities. Hence, silver amalgam is used for filling dental cavities.

Explain the following reactions with the help of balanced equations:

Question 1.
Out of sodium and sulphur which is a metal? Explain its reaction with oxygen. (March 2019)
Answer:
Sodium is a metal. Sodium reacts with oxygen in air at room temperature to form sodium oxide.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 60

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 2.
Magnesium burns in air.
Answer:
When magnesium bums in air, it combines with oxygen, emitting intense light and heat to form magnesium oxide.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 61

Question 3.
Copper reacts with air.
Answer:
Copper tarnishes in moist air and forms black coloured oxide when strongly heated.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 62

Question 4.
Sodium reacts with water.
Answer:
When sodium reacts with water, it evolves hydrogen which immediately catches fire producing a lot of heat.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 63

Question 5.
Calcium reacts with water.
Answer:
Calcium reacts with water less vigorously to form hydrogen gas and calcium hydroxide. In this reaction, the heat evolved is not sufficient for hydrogen to catch fire.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 64

Question 6.
Steam is passed over aluminium.
Answer:
When steam is passed over aluminium, hydrogen gas and aluminium oxide are formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 65

Question 7.
Steam is passed over iron.
Answer:
When steam is passed over iron, iron (III) oxide and hydrogen gas are formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 66

Question 8.
Magnesium reacts with dil. hydrochloric acid.
Answer:
When magnesium reacts with dil. hydrochloric acid, magnesium chloride is formed and hydrogen gas is evolved.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 67

Question 9.
Aluminium is treated with dil. hydrochloric acid.
Answer:
When aluminium is treated with dil. hydrochloric acid, aluminium chloride and hydrogen gas are formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 68

Question 10.
Zinc reacts with dil. hydrochloric acid.
Answer:
When zinc reacts with dil. hydrochloric acid, zinc chloride and hydrogen gas are formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 69

Question 11.
Iron is treated with dil. hydrochloric acid.
Answer:
When iron reacts with dil. hydrochloric acid, ferrous chloride and hydrogen gas is formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 70

Question 12.
Copper is reacted with cone, nitric acid.
Answer:
When copper is reacted with cone, nitric acid, copper nitrate and reddish brown nitrogen dioxide are formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 71

Question 13.
Copper is reacted with dil. nitric acid.
Answer:
When copper is reacted with dil. nitric acid, copper nitrate and nitric oxide are formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 72

Question 14.
Sodium metal is reacted chlorine gas.
Answer:
When sodium metal is reacted with chlorine, sodium chloride an ionic compound is formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 73

Question 15.
Sulphur burns in air.
Answer:
When sulphur burns in air, it combines with oxygen to form acidic sulphur dioxide.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 74

Question 16.
Chlorine dissolves in water.
Answer:
When chlorine dissolves in water, hypochlorous acid is formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 75

Question 17.
Chlorine is treated with hydrobromic acid.
Answer:
When chlorine is treated with hydrobromic acid, chlorine displaces bromine from hydrobromic acid.
Cl2(g) + 2HBr(aq) → 2HCl(aq) + Br2(aq)

Question 18.
Hydrogen gas is passed over boiling sulphur.
Answer:
When hydrogen gas is passed over boiling sulphur, sulphur combines with hydrogen to form hydrogen sulphide which has rotten egg smell.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 76

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 19.
Sodium aluminate is treated with water.
Answer:
When sodium aluminate is treated with water, it is hydrolysed to give a precipitate of aluminium hydroxide.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 77

Question 20.
Dry aluminium hydroxide is ignited at 1000 °C.
Answer:
When dry aluminium hydroxide is ignited at 1000 °C, alumina (Al2O3) formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 78

Question 21.
Zinc sulphide is heated strongly in excess of air.
Answer:
When zinc sulphide is heated strongly in excess of air, it forms zinc oxide and sulphur dioxide gas.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 79

Question 22.
Zinc carbonate is heated strongly in a limited supply of air.
Answer:
When zinc carbonate is heated strongly in a limited supply of air, it gives zinc oxide and carbon dioxide.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 80

Question 23.
Zinc oxide is treated with carbon.
Answer:
When zinc oxide is treated with carbon, it is reduced to zinc. In this reaction, carbon acts as reducing agent.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 81

Question 24.
Manganese dioxide is heated with aluminium.
Answer:
When manganese dioxide is heated with aluminium, manganese dioxide is reduced to manganese and large amount of heat is evolved.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 82

Question 25.
Cinnabar is heated in air.
Answer:
When cinnabar is heated in air, it forms mercuric oxide and sulphur dioxide.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 83

Question 26.
Cuprous sulphide is heated in air.
Answer:
When cuprous sulphide is heated in air, cuprous oxide is formed. Cuprous oxide is reduced to copper in the presence of ore.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 84

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Project: (Do it your self)

Project 1.
Which metals are used in day to day life? What are its uses?

Project 2.
Which nonmetals are used in day to day life? What are its uses?

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions

Balbharti Maharashtra State Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions

Question 1.
Fill in the blanks and explain the statements with reasoning:
a. If the height of the orbit of a satellite from the earth’s surface is increased, the tangential velocity of the satellite will ………………
Answer:
If the height of the orbit of a satellite from the earth’s surface, is increased, the tangential velocity of the satellite will decrease.
Explanation: The gravitational force (F) exerted by the earth on the satellite will decrease if the height of the orbit of the satellite from the earth’s surface is increased. Hence, the tangential velocity of the satellite will decrease.
The formula
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions 1
shows that υc decreases with increasing h.

b. The initial velocity (during launching) of the Mangalyaan must be greater than ………… from the earth.
Answer:
The initial velocity (during launching) of the Mangalyaan must be greater than the escape velocity from the earth.
Explanation: If a satellite is to travel beyond the gravitational pull of the earth, its velocity must be more than the escape velocity from the earth.
[Note: The velocity must be atleast equal to the escape velocity. Refer the definition of escape velocity.]

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions

Question 2.
State with reasons whether the following statements are true or false.
a. If a spacecraft has to be sent away from the influence of the earth’s gravitational field, its velocity must be less than the escape velocity.
Answer:
False.
Explanation: The escape velocity of a body is the minimum velocity with which it should be projected from the earth’s surface, so that it can escape the influence of the earth’s gravitational field. This clearly shows that the given statement is false.

b. The escape velocity on the moon is less than that on the earth.
Answer:
True.
Explanation: Escape velocity of an object from the earth,
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions 2

c. A satellite needs a specific velocity to revolve in a specific orbit.
Answer:
True.
Explanation:
Centripetal force on the satellite \(\frac{m v_{c}^{2}}{R+h}\) = gravitational force exerted by the earth on the satellite \(\frac{G M m}{(R+h)^{2}}\)
where,
m: mass of the satellite
υc: critical velocity of the satellite
h: height of the satellite from the surface of the earth
M: mass of the earth
R: radius of the earth
G: gravitational constant
∴ \(v_{\mathrm{c}}^{2}=\frac{G M}{R+h}\)
∴ \(v_{\mathrm{c}}=\sqrt{\frac{G M}{R+h}}\)
Thus, if the value of h changes, the value of υc also changes. It means a satellite needs to be given a specific velocity (in the tangential direction) to keep it revolving in a specific orbit.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions 3

d. If the height of the orbit of a satellite increases, its velocity must also increase.
Answer:
False.
Explanation:
Centripetal force on the satellite \(\frac{m v_{c}^{2}}{R+h}\) = gravitational force exerted by the earth on the satellite \(\frac{G M m}{(R+h)^{2}}\)
where,
m : mass of the satellite
υc : critical velocity of the satellite
h : height of the satellite from the surface of the earth
M : mass of the earth
R : radius of the earth
G : gravitational constant
∴ \(v_{\mathrm{c}}^{2}=\frac{G M}{R+h}\)
∴ \(v_{\mathrm{c}}=\sqrt{\frac{G M}{R+h}}\)
Thus, if the value of h changes, the value of υc also changes. It means a satellite needs to be given a specific velocity (in the tangential direction) to keep it revolving in a specific orbit.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions 4
As per the formula υc = \(\sqrt{\frac{G M}{R+h}}\) , if the value of h increases, the value of υc decreases. Hence, if the height of the satellite from the surface of the earth increases, its velocity decreases.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions

Question 3.
Answer the following questions:
a. What is meant by an artificial satellite? How are the satellites classified based on their functions?
(OR)
Write the importance of artificial satellites in your words. (Practice Activity Sheet – 3)
Answer:
A manmade object orbiting the earth or any other planet is called an artificial satellite. Satellites work on solar energy and hence photovoltaic panels are attached on both sides of the satellite, which look like wings. Satellites are also installed with various transmitters and other equipment to receive and transmit signals between the earth and the satellites.

Classification of satellites depending on their functions:
(1) Weather satellites: weather satellites collect the information regarding weather conditions of the region. It records temperature, air pressure, wind direction, humidity, cloud cover, etc. this information is sent to the space research station on the earth and then with this information weather forecast is made.

(2) Communication satellites: In order to establish communication between different places on the earth through mobile phones or computer assisted internet, communication satellites are used. Many artificial satellites placed at various locations in the earth’s orbit are well interconnected and help us to have communication with any place, from anywhere, at any time and in any form including voicemail, email, photographs, audio mail, etc.

(3) Broadcasting satellites: Broadcasting satel¬lites are used to transmit various radio and television programs and even live programs from any place on the earth to any other place. As a result, one can have access to information about current incidents, events, programs, sports and other events right from his drawing room with these satellites.

(4) Navigational satellites: Navigational satel¬lites assist the surface, water and air transportation and coordinate their busy schedule. These satellites also assist the user with current live maps as well as real time traffic conditions.

(5) Military satellites: Every sovereign nation needs to keep the real time information about the borders. Satellites help to monitor all movements of neighboring countries or enemy countries. Military satellites also help to guide the missiles effectively.

(6) Earth observation satellites: These satellites observe and provide the real time information about the earth. These satellites also help us to collect information about the resources, their management, continuous observation about a natural phenomenon and the changes within it.

(7) Other satellites: Apart from these various satellites, certain satellites for specific works or purposes are also sent in the space. E.g. India has sent EDUSAT for educational purpose; CARTOSAT for surveys and map making. Similarly, satellites with telescopes, like Hubble telescope or a satellite like International Space Station help to explore the universe. In fact, ISS (International Space Station) provides a temporary residence where astronauts can stay for a certain short or long period and can undertake the research and study space activities.
The various functions listed above show the importance of artificial satellites.

b. What is meant by the orbit of a satellite? On what basis and how are the orbits of artificial satellites classified?
Answer:
Orbit of a satellite is its path around the earth.
Orbits of artificial satellites can be classified on various basis.
(1) On the basis of the angle of the orbital plane: Orbital plane of a satellite can be the equatorial plane of the earth or it can be at an angle to it.
(2) On the basis of the nature of the orbit: Orbital plane can be circular or elliptical in shape.
(3) On the basis of the height of the satellite: Orbit of a satellite can be HEO, MEO or LEO.

(i) High Earth Orbit (HEO) satellite: A satellite orbiting at a height equal to or greater than 35780 km above the earth’s surface is called a High Earth Orbit satellite. The critical velocity (υc) of a satellite revolving in an orbit at 35780 km above the earth surface is 3.08 km/s. Such a satellite will take about 23 hours 54 minutes to complete one revolution around the earth. The earth completes one rotation about its axis in the same time. The orbital plane of such a satellite is the equatorial plane of the earth. The satellite’s relative position appears stationary with respect to a place on the earth. This satellite is, therefore, called a geostationary satellite or geosynchronous satellite.

(ii) Medium Earth Orbit (MEO) satellite: A satellite orbiting at a height between 2000 km and 35780 km above the earth’s surface is called a Medium Earth Orbit satellite. The orbital path of such a satellite is normally elliptical and passes through the North and the South polar regions. These satellites take about 12 hours to complete one revolution around the earth.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions 5

(iii) Low Earth Orbit (LEO) satellite:
A satellite orbiting at a height between 180 km and 2000 km above the earth’s surface is called a Low Earth Orbit satellite. Normally, these satellites take 90 minutes to complete one revolution around the earth. Weather satellites, space telescopes and International Space Station are Low Earth Orbit satellites.

c. Why are geostationary satellites not useful for studies of polar regions? (Practice Activity Sheet – 4)
(OR)
Explain the following statement. A geostationary satellite is not useful in the study of polar regions. (Practice Activity Sheet – 1)
Answer:
Geostationary satellites have two distinct characteristics:
(1) Geostationary satellites are HEO satellites and are placed at 35780 km above the earth’s surface.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions 6

(2) A geostationary satellite revolves in the equatorial plane of the earth, and thus, it can never fly above the polar regions.
Hence, geostationary satellites are not useful for studies of polar regions.

d. What is meant by a satellite launch vehicle? Explain the satellite launch vehicle developed by ISRO with the help of a schematic diagram.
Answer:
A rocket used to carry an artificial satellite to a desired height above the earth’s surface and then project it with a proper velocity so that the satellite orbits the earth in the desired orbit is called a launch vehicle. A satellite launch vehicle needs a specific velocity as well as a thrust to reach the desired height above the earth’s surface. The velocity and the thrust of a satellite launch vehicle depend on the weight and orbital height of the satellite.

Accordingly, the structure of the launch vehicle is decided and designed. The weight of the fuel also contributes a major portion in the total weight of the launch vehicle. This also influences the structure of the launch vehicle. In order to use the fuel optimally, multiple stage launch vehicles are now designed and used.

The Polar Satellite Launch Vehicle (PSLV) developed by ISRO is shown below in a schematic diagram.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions 7

e. Why is it beneficial to use a satellite j launch vehicle made up of more than one stage?
Answer:
Earlier Satellite Launch Vehicles (SLV) used to be of a single stage vehicles. Such SLVs used to be very heavy as well as expensive in terms of its fuel consumption. As a result, SLVs with multiple stages were developed.

In multistage SLVs, as the journey of the launch vehicle progresses and the vehicle achieves a specific velocity and a certain height, the fuel of the first stage is exhausted and the empty fuel tank gets detached from the main body of the launch vehicle and falls back into a sea or on unpopulated land. As the fuel in the first stage is exhausted, the engine in the second stage is Ignited. However, the weight of the launch vehicle is now less than what it was earlier and hence it can move with higher velocity, Thus, it saves fuel consumption. Hence, it is beneficial to use a multistage satellite launch vehicle.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions

Question 4.
Complete the following table:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions 8
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions 9

Question 5.
Solve the following problems:
a. If the mass of a planet is eight times the mass of the earth and its radius is twice the radius of the earth, what will be the escape velocity for that planet?
Answer:
Given:
(1) The mass of the planet (M) is eight times the mass of the earth, i.e., 8 × 6 × 1024 kg
(2) The radius of the planet (R) is twice the radius of the earth, i.e., 2 × 6.4 × 106 km
(3) G = 6.67 × 10-11 N·m2/kg2
Escape velocity for that planet
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions 10
= 2.237 × 104 m/s
= 22.37 km/s

b. How much time would a satellite in an orbit at a height of 35780 km above the earth’s surface take to complete one revolution around the earth, if the mass of the earth were four times its original mass?
Answer:
Given: R (Earth) = 6400 km = 6.4 × 106 m,
M (Earth) = 6 × 1024 kg
∴ M’ = 4M = 4 × 6 × 1024 kg
h = 35780 km = 3.578 × 107 m = 35.78 × 106 m,
G = 6.67 × 10-11 N·m2/kg2, T = ?
The time that the satellite would take to complete one revolution around the earth,
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions 11
= Approx 4.303 × 104 s
= Approx 11.95 h
or 11 hours 57 minutes 10 seconds.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions

c. If the height of a satellite completing one revolution around the earth in T seconds is h1 meters, then what would be the height of a satellite taking 2\(\sqrt{2}\) T seconds for one revolution?
Answer:
Given:
(1) Time: T seconds
(2) Height: h1
Let us assume the height of the satellite completing one revolution in 2\(\sqrt{2}\) T seconds as h2.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions 12
∴ R + h2 = 2R + 2h1
∴ h2 = R + 2h1

Project:

Project 1.
Collect information about the space missions undertaken by Sunita Williams.
Hints:
The following sources can be used to get the information on the above topic:
(1) Google Search Engine
(2) YouTube
(3) E-books on Sunita Williams
(4) English and other regional language books on Sunita Williams available in your library
(5) Newspaper clippings

Based on the information you have collected from the above sources, complete the project in about 5 pages. You can do value addition to your project with the help of suitable photos, clippings, charts, graphs and sketches.

Project 2.
Assume that you are interviewing Sunita Williams. Prepare a questionnaire and also the answers.
Answer:
Points to make a list of a questionnaire for the interview of Sunita Williams :
(1) Primary and higher education
(2) The source of inspiration to become an astronaut
(3) Information about her mentor
(4) General and specific training
(5) Initial experience of being an astronaut
(6) First space mission, its nature, duration and experience
(7) Natureofresearchcarriedoutinspace
(8) Some special memories
(9) Future plans
(10) Tips and guidance for the younger generation.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions

Can you recall? (Text Book Page No. 135)

Question 1.
What is the difference between space and sky?
Answer:

  1. The visible portion of the atmosphere and outer space seen by simple eyes, without any equipment from the earth, is known as the sky.
  2. The infinite three-dimensional expanse in which the Solar system, stars, celestial bodies, galaxies and the endless Universe exist is known as space.
  3. Both sky and space lack a definite boundary. However, the sky is a very tiny part of space.

Question 2.
What are different objects in the Solar system?
Answer:

  1. Our Solar system is a very tiny part of a huge Galaxy-Milky Way.
  2. The Sun is at the centre of the Solar system. Sun is a star.
  3. Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus and Neptune are planets in our Solar system. These planets revolve around the Sun. Some of these planets have their own natural satellites.
  4. Besides, there are asteroids, meteoroids, comets and meteors in the Solar system.

Question 3.
What is meant by a satellite?
Answer:

  1. An astronomical object orbiting any planet of our Solar system is called a satellite.
  2. Mercury and Venus have no satellites.
  3. Some planets have more than one satellite. E.g. Jupiter has 69 satellites.

Question 4.
How many natural satellites does the earth have?
Answer:
The earth has one natural satellite called the moon.

Question 5.
Which type of telescopes are orbiting around the earth? Why is it necessary to put them in space?
Answer:
(1) The following three types of telescopes are orbiting around the earth:

  • Optical Refracting Telescope.
  • Optical Reflecting Telescope.
  • Radio Telescope.

(2) Visible light and radio waves emitted by celestial bodies in space pass through the atmosphere before reaching the earth’s surface. During this journey, some light is absorbed by the atmosphere. Hence, the intensity of the light reaching the earth’s surface decreases. Besides, temperature and air pressure cause the atmospheric turbulence. Hence, light rays change their path, resulting in a change in the position of the image of a celestial body.

City lights during night, and bright sunlight during day also put limitations on usage of optical telescopes on the earth. To minimize these problems, optical telescopes are situated on mountain top, away from inhabited places. However, limitations caused by the atmosphere still persist.

To get rid of these problems scientists have successfully launched telescopes in space. Images obtained by these telescopes are brighter and clearer than those obtained by the telescopes located on the earth’s surface.

Can you recall? (Text Book Page No. 135)

Question 1.
Where does the signal in your cellphone come from?
Answer:
In nearby area of our residence, many mobile towers are installed at various places. Cellphones receive signals from one of these mobile towers.

Question 2.
Where from does it come to mobile towers?
Answer:
All mobile towers are connected to satellites. Cellphone signal reaching the nearest mobile tower in our vicinity is first transmitted to the satellite. The satellite transmits the signal to the mobile tower near the destination.

Question 3.
Where does the signal to your TV set come from?
Answer:
(1) Television Centre or Studio transmits the TV program which first reaches the satellite. The dish antenna of the cable operator in our area receives these signals. The TV programs reach our TV set through a cable connected between the cable operator’s receiving station and our TV set.

(2) Alternatively, a small portable dish antenna fixed on the rooftop is also used to receive the TV signals directly from the satellites. Finally, a cable connected to the dish antenna and TV set brings the programme to our TV set.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions

Question 4.
You may have seen photographs showing the position of monsoon clouds over the country in the newspaper. How are these images obtained?
Answer:
Weather satellites take photographs of the sky above the earth’s surface at regular intervals. Some satellites, capable of receiving radio signals, also collect the information of weather conditions and finally images of the sky are built with computers. Territorial boundaries of the states and the country are drawn later on these images. Such satellite images with imposed boundaries are printed in media or shown on the television.

Fill in the blanks:

Question 1.
A man-made object revolving around the earth in a fixed orbit is called …………..
Answer:
A man-made object revolving around the earth in a fixed orbit is called an artificial satellite.

Question 2.
Chandrayaan-I discovered the presence of ………….. on the moon.
Answer:
Chandrayaan-I discovered the presence of water on the moon.

Question 3.
Apart from launching a satellite around the earth, India has been able to launch a satellite around ……………
Answer:
Apart from launching a satellite around the earth, India has been able to launch a satellite around Mars.

Question 4.
All satellites work on …………… energy.
Answer:
All satellites work on solar energy.

Question 5.
……………. are used to carry and place a satellite in a specific orbit.
Answer:
Satellite launchers are used to carry and place a satellite in a specific orbit.

Question 6.
USA has developed ……………. as an alternative to space launch vehicles.
Answer:
USA has developed space shuttles as an alternative to space launch vehicles.

Question 7.
Hubble telescope is a ………….. satellite.
Answer:
Hubble telescope is a Low Earth Orbit (LEO) satellite.

Question 8.
……………. executed the first ever mission to the moon in the world.
Answer:
Russia executed the first ever mission to the moon in the world.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions

Question 9.
………… executed the first manned mission to the moon in the world.
Answer:
USA executed the first manned mission to the moon in the world.

Select the appropriate answer from given options:

Question 1.
Which one of the following is a Low Earth Orbit (LEO) satellite?
(a) Navigational satellite
(b) Geostationary satellite
(c) International Space Station
(d) All of the above
Answer:
(c) International Space Station

Question 2.
Which of the following satellite launchers is developed by India?
(a) INSAT
(b) IRNSS
(c) EDUSAT
(d) PSLV
Answer:
(d) PSLV

Question 3.
Which of the following astronauts travelled through space shuttle ‘Discovery’ first time? (Practice Activity Sheet – 4)
(a) Kalpana Chawla
(b) Rakesh Sharma
(c) Sunita Williams
(d) Neil Armstrong
Answer:
(c) Sunita Williams

Considering the correlation between the words of the first pair, pair the third word accordingly with proper answer. (OR) Considering the first correlation, complete the second.

Question 1.
IRNSS : Direction showing satellite :: INSAT :………… (Practice Activity Sheet – 1)
Answer:
IRNSS : Direction showing satellite :: INSAT : Weather satellite

Question 2.
Hubble telescope : 569 km high from the earth’s surface :: Revolving orbit of Hubble telescope :………. (Practice Activity Sheet – 2; March 2019)
Answer:
Hubble telescope : 569 km high from the earth’s surface :: Revolving orbit of Hubble telescope : Low Earth Orbit.

Match the column:

Question 1.

Column A Column B
(1) Clouds over India (a) Low Earth Orbit
(2) Global communication (b) PSLV
(3) Launch vehicle made by ISRO (c) Communication satellite
(4) International Space Station (d) EDUSAT
(5) Navigational satellite (e) Weather satellite
(f) Medium Earth Orbit

Answer:
(1) Clouds over India – Weather satellite
(2) Global communication – Communication satellite
(3) Launch vehicle made by ISRO – PSLV
(4) International Space Station – Low Earth Orbit
(5) Navigational satellite – Medium Earth Orbit.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions

Answer the following questions in one sentence each:

Question 1.
What do you mean by the orbit of a satellite?
Answer:
Orbit of a satellite is its path around the earth.

Question 2.
Which factor decides the orbit of a satellite?
Answer:
The function of a satellite decides the orbit of the satellite.

Question 3.
What is a High Earth Orbit satellite?
Answer:
A satellite orbiting at a height equal to or greater than 35780 km above the earth’s surface is called a High Earth Orbit satellite.

Question 4.
Give two examples of Low Earth Orbit satellites.
Answer:
Weather satellite and International Space Station are Low Earth Orbit satellites.

Question 5.
What is a launch vehicle?
Answer:
A rocket used to carry an artificial satellite to a desired height above the earth’s surface and then project it with a proper velocity so that the satellite orbits the earth in the desired orbit is called a launch vehicle.

Question 6.
Name the launch vehicle developed by India.
Answer:
The launch vehicle developed by India is known as PSLV, i.e., Polar Satellite Launch Vehicle.

Answer the following questions:

Question 1.
Write the proper name of the orbits of satellites shown in the following figure with their height from the earth’s surface. (Practice Activity Sheet – 4)
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions 13
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions 14
(a) Low earth orbits: height above the earth’s surface: 180 km to 2000 km
(b) Medium earth orbits: height above the earth’s surface: 2000 km to 35780 km
(c) High earth orbits: height from the earth’s surface > 35780 km

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions

Question 2.
Explain the need and importance of space missions.
Answer:
Man has always been curious about the sun, moon, stars and the world beyond the earth. Initially, man tried to observe space with the help of telescopes. However, later he dreamt to fly into space and finally succeeded to reach into space.

Space missions are now essential to understand the origin and evolution of our solar system as well as to study the Universe beyond the Solar system.

Space missions have given us many benefits and made our life simpler. It is because of space missions that the real-time immediate communication and exchange of information across the globe is now possible. We can receive the abundant information at the desk at our home or office. We also get information about any topic at any time and anywhere at fingertips through the Internet. Besides, the advanced alerts about some natural calamities like cyclones or storms are received through satellites sent as a part of space missions. Satellites have also helped us in entertainment. Programmes, sports events, etc., can be telecast live and can reach millions at a time throughout the world.

Satellite surveillance of the enemy, exploring the reserves of various minerals resources, access to various activities like trade, tourism and navigation, and easy global reach to make world a global village is all possible due to the space missions. Thus, space missions are extremely important in defence, communication, weather forecast, observation, direction determination, etc.

Question 3.
What are space expeditions? Explain their need and importance in your words. (Practice Activity Sheet – 2)
Answer:
A mission planned (i) for establishing artificial satellites in the earth’s orbit, using them for research or for the benefit of life, or (ii) for sending a spacecraft to the various components of the solar system or outside is called a space expedition.

Man has always been curious about the sun, moon, stars and the world beyond the earth. Initially, man tried to observe space with the help of telescopes. However, later he dreamt to fly into space and finally succeeded to reach into space. Space missions are now essential to understand the origin and evolution of our solar system as well as to study the Universe beyond the Solar system.

Space missions have given us many benefits and made our life simpler. It is because of space missions that the real-time immediate communication and exchange of information across the globe is now possible. We can receive the abundant information at the desk at our home or office. We also get information about any topic at any time and anywhere at fingertips through the Internet. Besides, the advanced alerts about some natural calamities like cyclones or storms are received through satellites sent as a part of space missions. Satellites have also helped us in entertainment. Programmes, sports events, etc., can be telecast live and can reach millions at a time throughout the world.

Satellite surveillance of the enemy, exploring the reserves of various minerals resources, access to various activities like trade, tourism and navigation, and easy global reach to make world a global village is all possible due to the space missions. Thus, space missions are extremely important in defence, communication, weather forecast, observation, direction determination, etc.

Question 4.
What are the objectives of the space mission?
Answer:
Man initially tried to satisfy his curiosity to know the world and universe beyond the earth with the help of telescopes. However, it has some obvious limitations and to overcome these limitations, man later ventured into space missions.

Space missions carried out by man were aimed at four specific objectives:

  1. To launch artificial satellites in the earth’s orbit for study and research.
  2. To launch artificial satellites in the earth’s orbit for various purposes like telecommunication, weather forecast, radio and TV programme transmission, etc.
  3. To send artificial satellites beyond the earth’s orbit to observe, study and collect the information from other planets, meteors, meteoroids, asteroids and comets.
  4. To sense and understand space beyond the solar system.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions

Question 5.
Write on significant space missions carried out by man.
Answer:
Man has carried out many space missions within and beyond the earth’s orbit. Significant space missions are as follows:
(1) Space missions within the earth’s orbit: Man has so far sent many artificial satellites of various types in the earth’s orbit. These satellites have made the life of man simpler. Besides, it has also helped us in resource management, communication, disaster management, etc.

(2) Moon missions : Moon is the natural satellite , of the earth and it is the nearest celestial body to us. Naturally, our initial space missions were directed to the moon. As of now, only Russia, USA, European Union, China, Japan and India have successfully undertaken . moon missions. Russia executed 15 moon missions between 1959 and 1976. Of these, last 4 missions brought the stone samples from the moon for study and analysis. However all these missions were unmanned. USA executed moon missions between 1962 and 1972. Some of these missions were unmanned.

However, the historic moon mission took place on 20th July, 1969, when American astronaut Neil Armstrong became the first human to step on the moon. India has undertaken the moon mission. Indian Space Research Organisation (ISRO) successfully launched Chandrayaan-I and placed it in orbit of the moon. It sent useful information to the earth for about a year. The most important discovery made during the mission was the presence of water on moon’s surface. India was the first country to discover this.

(3) Mars mission: The second nearest celestial object to the earth is Mars and many nations sent spacecraft towards it. But only few of them have been successful. However, the performance of Mangalyaan, the Indian spacecraft sent by ISRO towards Mars, was remarkable. Mangalyaan was launched in November 2013 and was placed in the orbit of Mars successfully in September 2014. It has obtained useful information about the surface and atmosphere of Mars.

(4) Space missions to other planets: Other than moon and Mars missions, many other space missions were undertaken for studying other planets. Some spacecraft orbited the planets, some landed on some planets, and some just observed the planets, passed near them and went further to study other celestial bodies. Some spacecraft were sent specifically to study asteroids and comets. Some spacecraft’s have brought dust and stone samples from asteroids for the study.

All these space missions are very useful in getting information and helping us in clarifying our concepts about the origin of the earth and the Solar system.

Question 6.
Bring out the contribution of India’s space missions.
Answer:
Successful space missions as well as scientific and technological accomplishments by India in space technology have made a significant contribution in the national and social development of our country.
India has indigenously built various launchers and these launchers can put the satellites having the mass up to 2500 kg in orbit.

Indian Space Research Organisation (ISRO) has designed and built two important launchers: Polar Satellite Launch Vehicle (PSLV) and Geosynchronous Satellite Launch Vehicle (GSLV).

Many satellites in INS AT and GSAT series are active in telecommunication, television broadcasting, meteorological services, disaster management and in monitoring and management of natural resources. EDUSAT is used specifically for education while satellites in IRNSS series are used for navigation. Thumba, Sriharikota and Chandipur are Indian satellite launch centers.

Vikram Sarabhai Space Centre at Thiruvananthapuram, Satish Dhawan Space Research Centre at Sriharikota and Space Application Centre at Ahmedabad are space research organizations of India.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions

Question 7.
What is meant by space debris? Why is there need to manage the debris? (March 2019)
Answer:
In a space nonessential objects such as the parts of launchers and satellites, revolving around the earth are called the debris in space.

The debris can be harmful to the artificial satellites. It can collide with the satellite or spacecrafts and damage them. Therefore the future of artificial satellites or spacecrafts are in danger.
Hence, it is necessary to manage the debris.

Solve the following examples/numerical problems:
[Note: See the textbook for the relevant data.]

Problem 1.
If the mass of a planet is 8 times that of the earth and its radius is twice the radius of the earth, what will be the escape velocity for that planet? (Escape velocity for the earth = 11.2 km/s) (Practice Activity Sheet – 2)
Answer:
Given:
Mass of the planet = 8ME radius of the planet, Rp = 2RE,
escape velocity for the earth, υescE = 11.2 km/s
escape velocity for the planet, υescP = ?
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions 15

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions

Problem 2.
Calculate the critical velocity (υc) of the satellite to be located at 35780 km above the surface of the earth.
Answer:
Given:
G: 6.67 × 10-11 N·m2/kg2,
M(Earth): 6 × 1024 kg,
R(Earth): 6.4 × 106 m,
h: 35780 km = 35780 × 103 m,
υc = ?
Critical velocity of the satellite
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions 16
= 3.08 × 103 m/s
= 3.08 Km/s.

Problem 3.
In the above example (2) how much time will the satellite take to complete one revolution around the earth?
Answer:
Given:
R: 6400mkm = 6.4 × 106 m
h: 35780 km = 3.5780 × 107 m
v: 3.08 km/s = 3.08 × 103 m/s
T = ?
The time required for the satellite to complete one revolution around the earth,
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions 17
= Approx 86060 s
= 23 hours 54 minutes 20 seconds

Problem 4.
Calculate the critical velocity (υc) of the satellite to be located at 2000 km above the surface of the earth.
Answer:
Refer to the example (2) above.
Here,h = 2 × 106 m
υc = 6902 m/s

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 10 Space Missions

Problem 5.
In the above example (4), how much time will the satellite take to complete one revolution around the earth?
Answer:
Refer to example (3) above.
Approx 7647 s
= 2 hours 7 minutes 27 seconds.
[Note: For more solved problems and problems for practice, refer Chapter 1 (Gravitation)]