Maharashtra Board Practice Set 31 Class 7 Maths Solutions Chapter 7 Joint Bar Graph

Balbharti Maharashtra State Board Class 7 Maths Solutions covers the 7th Std Maths Practice Set 31 Answers Solutions Chapter 7 Joint Bar Graph.

Joint Bar Graph Class 7 Practice Set 31 Answers Solutions Chapter 7

Question 1.
The number of saplings planted by schools on World Tree Day is given in the table below. Draw a joint bar graph to show these figures.

School Name\Name of Sapling Almond Karanj Neem Ashok Gulmohar
Nutan Vidyalaya 40 60 72 15 42
Bharat Vidyalaya 42 38 60 25 40

Solution:
Maharashtra Board Class 7 Maths Solutions Chapter 7 Joint Bar Graph Practice Set 31 1

Question 2.
The table below shows the number of people who had the different juices at a juice bar on a Saturday and a Sunday. Draw a joint bar graph for this data.

Days\Fruits Sweet Lime Orange Apple Pineapple
Saturday 43 30 56 40
Sunday 59 65 78 67

Solution:
Maharashtra Board Class 7 Maths Solutions Chapter 7 Joint Bar Graph Practice Set 31 2

Question 3.
The following numbers of votes were cast at 5 polling booths during the Gram Panchayat elections. Draw a joint bar graph for this data.

Persons\Booth No. 1 2 3 4 5
Men 200 270 560 820 850
Women 700 240 340 640 470

Solution:
Maharashtra Board Class 7 Maths Solutions Chapter 7 Joint Bar Graph Practice Set 31 3

Question 4.
The maximum and minimum temperatures of five Indian cities are given in °C. Draw a joint bar graph for this data.

City\Temperature Delhi Mumbai Kolkata Nagpur Kapurthala
Maximum temperature 35 32 37 41 37
Minimum temperature 26 25 26 29 26

Solution:
Maharashtra Board Class 7 Maths Solutions Chapter 7 Joint Bar Graph Practice Set 31 4

Question 5.
The numbers of children vaccinated in one day at the government hospitals in Solapur and Pune are given in the table. Draw a joint bar graph for this data:

City\Vaccine D.P.T. (Booster) Polio (Booster) Measles Hepatitis
Solapur 65 60 65 63
Pune 89 87 88 86

Solution:
Maharashtra Board Class 7 Maths Solutions Chapter 7 Joint Bar Graph Practice Set 31 5

Question 6.
The percentage of literate people in the states of Maharashtra and Gujarat are given below. Draw a joint bar graph for this data.

State\Year 1971 1981 1991 2001 2011
Maharashtra 46 57 65 77 83
Gujarat 40 45 61 69 79

Solution:
Maharashtra Board Class 7 Maths Solutions Chapter 7 Joint Bar Graph Practice Set 31 6

Maharashtra Board Class 7 Maths Chapter 7 Joint Bar Graph Practice Set 31 Intext Questions and Activities

Question 1.
Observe the graph shown below and answer the following questions. (Textbook pg. no. 51)

  1. In which year did Ajay and Vijay both produce equal quantities of wheat?
  2. In year 2014, who produced more wheat?
  3. In year 2013, how much wheat did Ajay and Vijay each produce?

Maharashtra Board Class 7 Maths Solutions Chapter 7 Joint Bar Graph Practice Set 31 7

Solution:

  1. Both produced equal quantities of wheat in the year 2011.
  2. Ajay produced more wheat in the year 2014.
  3. Ajay’s wheat production in 2013 = 40 quintal.
    Vijay’s wheat production in 2013 = 30 quintal.

Question 2.
The minimum and maximum temperature in Pune for five days is given. Read the joint bar graph and answer the questions below: (Textbook pg. no. 52)
Maharashtra Board Class 7 Maths Solutions Chapter 7 Joint Bar Graph Practice Set 31 8

  1. What data is shown on X- axis?
  2. What data is shown on Y- axis?
  3. Which day had the highest temperature?
  4. On which day is the minimum temperature the highest?
  5. On Thursday, what is the difference between the minimum and maximum temperature?
  6. On which day is the difference between the minimum and maximum temperature the greatest?

Solution:

  1. Five days of a week are shown on X – axis.
  2. Temperature in the city of Pune is shown on Y – axis.
  3. Monday had the highest temperature.
  4. The minimum temperature was highest on Wednesday.
  5. Maximum temperature = 29.5° C
    Minimum temperature = 15° C
    ∴ Difference in temperature = 29.5° C – 15° C = 14.5 ° C
  6. The difference in minimum and maximum temperature is greatest on Thursday.

Question 3.
Collect various kinds of graphs from newspapers and discuss them. (Textbook pg. no. 53)
i. Histogram
Maharashtra Board Class 7 Maths Solutions Chapter 7 Joint Bar Graph Practice Set 31 9
ii. Line graph
Maharashtra Board Class 7 Maths Solutions Chapter 7 Joint Bar Graph Practice Set 31 10
iii. Pie chart
Maharashtra Board Class 7 Maths Solutions Chapter 7 Joint Bar Graph Practice Set 31 11
Solution:
(Students should attempt the above activities on their own.)

Maharashtra Board Practice Set 22 Class 6 Maths Solutions Chapter 8 Divisibility

Balbharti Maharashtra State Board Class 6 Maths Solutions covers the Std 6 Maths Chapter 8 Divisibility Class 6 Practice Set 22 Answers Solutions.

6th Standard Maths Practice Set 22 Answers Chapter 8 Divisibility

Question 1.
There are some flowering trees in a garden. Each tree bears many flowers with the same number printed on it. Three children took a basket each to pick flowers. Each basket has one of the numbers, 3, 4 or 9 on it. Each child picks those flowers which have numbers divisible by the number on his or her basket. If He / She takes only 1 flower from each tree. Can you tell which numbers the flowers in each basket will have?
Maharashtra Board Class 6 Maths Solutions Chapter 8 Divisibility Practice Set 22 1
Solution:
Each child will have flowers bearing the following numbers:
Girl with basket number 3: 111, 369, 435, 249, 666, 450, 960, 432, 999, 72, 336, 90, 123, 108
Boy with basket number 4: 356, 220, 432, 960, 72, 336, 108
Girl with basket number 9: 369, 666, 450, 432, 999, 72, 90, 108

Maharashtra Board Class 6 Maths Chapter 8 Divisibility Practice Set 22 Intext Questions and Activities

Question 1.
Read the numbers given below. Which of these numbers are divisible by 2, by 5, or by 10? Write them in the empty boxes. 125,364,475,750,800,628,206,508,7009,5345,8710. (Textbook pg. no. 43)

Divisible by 2 Divisible by 5 Divisible by 10

Solution:

Divisible by 2 Divisible by 5 Divisible by 10
364,750, 800, 628, 206, 508, 8710 125,475, 750, 800, 5345, 8710 750, 800, 8710

Question 2.
Complete the following table: (Textbook pg. no. 43)

Number Sum of digits in the number Is the sum divisible by 3? Is the given number divisible by 3?
63 6 + 3 = 9
872 17 X X
91
552
9336
4527

Solution:

Number Sum of digits in the number Is the sum divisible by 3? Is the given number divisible by 3?
63 6 + 3 = 9
872 8 + 7 + 2 = 17 X X
91 9 + 1 = 10 X X
552 5 + 5 + 2 = 12
9336 9 + 3 + 3 + 6 = 21
4527 4 + 5 + 2 + 7 = 18

Question 3.
Complete the following table: (Textbook pg. no. 44)

Number Divide the number by 4. Is it completely divisible? The number formed by the digits in the tens and units places. Is this number divisible by 4?
992 92
7314
6448
8116
7773
3024

Solution:

Number Divide the number by 4. Is it completely divisible? The number formed by the digits in the tens and units places. Is this number divisible by 4?
992 92
7314 X 14 X
6448 48
8116 16
7773 X 73 X
3024 24

Question 4.
Complete the following table: (Textbook pg. no. 44)

Number Divide the number by 9. Is it completely divisible? Sum of the digits in the number. Is the sum divisible by 9?
1980 1 + 9 + 8 + 0 = 18
2999 X 2 + 9 + 9 + 9 = 29 X
5004
13389
7578
69993

Solution:

Number Divide the number by 9. Is it completely divisible? Sum of the digits in the number. Is the sum divisible by 9?
1980 1 + 9 + 8 + 0 = 18
2999 X 2 + 9 + 9 + 9 = 29 X
5004 5 + 0 + 0 + 4 = 9
13389 X 1 + 3 + 3 + 8 + 9 = 24 X
7578 7 + 5 + 7 + 8 = 27
69993 6 + 9 + 9 + 9 + 3 = 36

Maharashtra Board Practice Set 9 Class 6 Maths Solutions Chapter 4 Operations on Fractions

Balbharti Maharashtra State Board Class 6 Maths Solutions covers the Std 6 Maths Chapter 4 Operations on Fractions Class 6 Practice Set 9 Answers Solutions.

6th Standard Maths Practice Set 9 Answers Chapter 4 Operations on Fractions

Question 1.
Convert into improper fractions:
i. \(7 \frac{2}{5}\)
ii. \(5 \frac{1}{6}\)
iii. \(4 \frac{3}{4}\)
iv. \(2 \frac{5}{9}\)
v. \(1 \frac{5}{7}\)
Solution:
i. \(7 \frac{2}{5}\)
Maharashtra Board Class 6 Maths Solutions Chapter 4 Operations on Fractions Practice Set 9 1

ii. \(5 \frac{1}{6}\)
Maharashtra Board Class 6 Maths Solutions Chapter 4 Operations on Fractions Practice Set 9 2

iii. \(4 \frac{3}{4}\)
Maharashtra Board Class 6 Maths Solutions Chapter 4 Operations on Fractions Practice Set 9 3

iv. \(2 \frac{5}{9}\)
Maharashtra Board Class 6 Maths Solutions Chapter 4 Operations on Fractions Practice Set 9 4

v. \(1 \frac{5}{7}\)
Maharashtra Board Class 6 Maths Solutions Chapter 4 Operations on Fractions Practice Set 9 5

Question 2.
Convert into mixed numbers:
i. \(\frac { 30 }{ 7 }\)
ii. \(\frac { 7 }{ 4 }\)
iii. \(\frac { 15 }{ 12 }\)
iv. \(\frac { 11 }{ 8 }\)
v. \(\frac { 21 }{ 4 }\)
v. \(\frac { 20 }{ 7 }\)
Solution:
i. \(\frac { 30 }{ 7 }\)
Maharashtra Board Class 6 Maths Solutions Chapter 4 Operations on Fractions Practice Set 9 6

ii. \(\frac { 7 }{ 4 }\)
Maharashtra Board Class 6 Maths Solutions Chapter 4 Operations on Fractions Practice Set 9 7

iii. \(\frac { 15 }{ 12 }\)
Maharashtra Board Class 6 Maths Solutions Chapter 4 Operations on Fractions Practice Set 9 8

iv. \(\frac { 11 }{ 8 }\)
Maharashtra Board Class 6 Maths Solutions Chapter 4 Operations on Fractions Practice Set 9 9

v. \(\frac { 21 }{ 4 }\)
Maharashtra Board Class 6 Maths Solutions Chapter 4 Operations on Fractions Practice Set 9 10

v. \(\frac { 20 }{ 7 }\)
Maharashtra Board Class 6 Maths Solutions Chapter 4 Operations on Fractions Practice Set 9 11

Question 3.
Write the following examples using fraction:
i. If 9 kg rice is shared among 5 people, how many kilograms of rice does each person get?
ii. To make 5 shirts of the same size, 11 meters of cloth is needed. How much cloth is needed for one shirt?
Solution:
i. Total quantity of rice = 9 kg
Number of people = 5
∴ Kilograms of rice received by each person = \(\frac { 9 }{ 5 }\)
∴ Each person will get \(\frac { 9 }{ 5 }\) kg of rice.

ii. Total meters of cloth = 11 meters
Number of shirts to be made = 5
Meters of cloth needed to make 1 shirt = \(\frac { 11 }{ 5 }\)
∴ Cloth needed to make 1 shirt is \(\frac { 11 }{ 5 }\) meters.

Maharashtra Board Practice Set 21 Class 6 Maths Solutions Chapter 7 Symmetry

Balbharti Maharashtra State Board Class 6 Maths Solutions covers the Std 6 Maths Chapter 7 Symmetry Class 6 Practice Set 21 Answers Solutions.

6th Standard Maths Practice Set 21 Answers Chapter 7 Symmetry

Question 1.
Along each figure shown below, a line l has been drawn. Complete the symmetrical figures by drawing a figure on the other side such that the line l becomes the line of symmetry.
Maharashtra Board Class 6 Maths Solutions Chapter 7 Symmetry Practice Set 21 1
Solution:
Maharashtra Board Class 6 Maths Solutions Chapter 7 Symmetry Practice Set 21 2

Maharashtra Board Class 6 Maths Chapter 7 Symmetry Practice Set 21 Intext Questions and Activities

Question 1.
In the figures below, the line l divides the figure in two parts. Do these parts fall on each other? Verify? (Textbook pg. no. 42)
Maharashtra Board Class 6 Maths Solutions Chapter 7 Symmetry Practice Set 21 3
Solution:
Yes, the two parts of both the figures fall on each other on folding along the line l.

Maharashtra Board Practice Set 30 Class 6 Maths Solutions Chapter 12 Percentage

Balbharti Maharashtra State Board Class 6 Maths Solutions covers the Std 6 Maths Chapter 12 Percentage Class 6 Practice Set 30 Answers Solutions.

6th Standard Maths Practice Set 30 Answers Chapter 12 Percentage

Question 1.
Shabana scored 736 marks out of 800 in her exams. What was the percentage she scored?
Solution:
Total marks of the examination = 800
Marks scored by Shabana = 736
Suppose Shabana scored A% marks.
Maharashtra Board Class 6 Maths Solutions Chapter 12 Percentage Practice Set 30 1
∴ A = 92%
∴ Shabana scored 92% marks.

Question 2.
There are 500 students in the school in Dahihanda village. If 350 of them can swim, what percent of them can swim and what percent cannot?
Solution:
Total number of students in the school = 500
Number of students who can swim = 350
Suppose A% students can swim.
Maharashtra Board Class 6 Maths Solutions Chapter 12 Percentage Practice Set 30 2
∴ A = 70%
Percentage of students who cannot swim = 100% – Percentage of students who can swim .
= 100% – 70% = 30%
∴ 70% of the students can swim and 30% cannot swim.

Question 3.
If Prakash sowed jowar on 75% of the 19500 sq. m. of his land, on how many sq. m. did he actually plant jowar?
Solution:
Total area of the land = 19500 sq. m.
Percentage of area in which Prakash sowed jowar = 75%
Suppose Prakash planted jowar in A sq. m.
Maharashtra Board Class 6 Maths Solutions Chapter 12 Percentage Practice Set 30 3
∴ A = 14,625 sq. m.
∴ Prakash planted jowar in 14,625 sq.m.

Question 4.
Soham received 40 messages on his birthday. Of these, 90% were birthday greetings. How many other messages did he get besides the greetings?
Solution:
Total messages received by Soham on his birthday = 40
Percentage of messages received for birthday greetings = 90%
Suppose Soham got A number of birthday greetings.
Maharashtra Board Class 6 Maths Solutions Chapter 12 Percentage Practice Set 30 4
∴ A = 36
∴ Number of messages received other than birthday greetings
= total messages received – total number of birthday greetings
= 40 – 36 = 4
∴ The number of messages received other than birthday greetings is 4.

Question 5.
Of the 5675 people in a village 5448 are literate. What is the percentage of literacy in the village?
Solution:
Number of people in the village = 5675
Number of people who are literate = 5448
Suppose the percentage of literacy in the village is A%.
Maharashtra Board Class 6 Maths Solutions Chapter 12 Percentage Practice Set 30 5
∴ A = 96%
∴ The percentage of literacy in the village is 96%.

Question 6.
In the elections, 1080 of the 1200 women in Jambhulgaon cast their vote, while 1360 of the 1700 in Wadgaon cast theirs. In which village did a greater proportion of women cast their votes?
Solution:
Total number of women in Jambhulgaon = 1200
Number of women in Jambhulgaon who voted = 1080
Suppose A% women cast their vote in Jambhulgaon village.
Maharashtra Board Class 6 Maths Solutions Chapter 12 Percentage Practice Set 30 6
Maharashtra Board Class 6 Maths Solutions Chapter 12 Percentage Practice Set 30 7
∴ A = 90%
In Jambhulgaon, the percentage of women who voted in the elections was 90%.
Total number of women in Wadgaon = 1700 Number of women in Wadgaon who voted = 1360
Suppose B% women cast their vote in Wadgaon.
Maharashtra Board Class 6 Maths Solutions Chapter 12 Percentage Practice Set 30 8
∴ B = 80%
∴ In Wadgaon, the percentage of women who voted in the elections was 80%.
∴ A greater proportion of women cast their votes in Jambhulgaon.

Maharashtra Board Class 6 Maths Chapter 12 Percentage Practice Set 30 Intext Questions and Activities

Question 1.
There are 9 squares in the figure alongside. The letters ABCDEFGHI are written in squares. Give each of the letters a unique number from 1 to 9 so that every letter has a different number.
Besides, A + B + C = C + D + E = E + F + G = G + H + I should also be true. (Textbook pg. no. 64)
Maharashtra Board Class 6 Maths Solutions Chapter 12 Percentage Practice Set 30 9
Solution:
Maharashtra Board Class 6 Maths Solutions Chapter 12 Percentage Practice Set 30 10
(This is one of the possible solutions of the above riddle. There are more solutions possible.)

Maharashtra Board Practice Set 8 Class 6 Maths Solutions Chapter 3 Integers

Balbharti Maharashtra State Board Class 6 Maths Solutions covers the Std 6 Maths Chapter 3 Integers Class 6 Practice Set 8 Answers Solutions.

6th Standard Maths Practice Set 8 Answers Chapter 3 Integers

Question 1.
Subtract the numbers in the top row from the numbers in the first column and write the proper number in each empty box:

6 9 -4 -5 0 +7 -8 -3
3 3 – 6 = -3
8 8 – (-5) = 13
-3
-2

Solution:

6 9 -4 -5
3 (+3) + (-6) = -3 (+3) + (-9) = -6 (+3) + (+4) = 7 (+3) + (+5) = 8
8 (+8) + (-6) = +2 (+8) + (-9) = -1 (+8) + (+4) = 12 (+8) + (+5) = 13
-3 (-3) + (-6) = -9 (-3) + (-9) = -12 (-3) + (+4) = 1 (-3) + (+5) = 2
-2 (-2) + (-6) = -8 (-2) + (-9) = -11 (-2) + (+4) = 2 (-2) + (+5) = 3
0 +7 -8 -3
3 (+3) – 0 = 3 (+3) + (-7) = -4 (+3) + (+8) = 11 (+3) + (+3) = 6
8 (+8) – 0 = 8 (+8) + (-7) = 1 (+8) + (+8) = 16 (+8) + (+3) = 11
-3 (-3) – 0 = -3 (-3) + (-7) = -10 (-3) + (+8) = 5 (-3) + (+3) = 0
-2 (-2) – 0 = -2 (-2) + (-7) = -9 (-2) + (+8) = 6 (-2) + (+3) = 1

Maharashtra Board Class 6 Maths Chapter 3 Integers Practice Set 8 Intext Questions and Activities

Question 1.
A Game of Integers. (Textbook pg. no. 20)
The board for playing this game is given in the back cover of the textbook. Place your counters before the number 1. Throw the dice. Look at the number you get. It is a positive number. Count that many boxes and move your counter forward. If a problem is given in that box, solve it. If the answer is a positive number, move your counter that many boxes further. It it is negative, move back by that same number of boxes.

Suppose we have reached the 18th box. Then the answer to the problem in it is -4 + 2 = -2. Now move your counter back by 2 boxes to 16. The one who reaches 100 first, is the winner.
Maharashtra Board Class 6 Maths Solutions Chapter 3 Integers Practice Set 8 1
Solution:
(Students should attempt this activity on their own)

Maharashtra Board Practice Set 30 Class 7 Maths Solutions Chapter 6 Indices

Balbharti Maharashtra State Board Class 7 Maths Solutions covers the 7th Std Maths Practice Set 30 Answers Solutions Chapter 6 Indices.

Indices Class 7 Practice Set 30 Answers Solutions Chapter 6

Question 1.
Find the square root:
i. 625
ii. 1225
iii. 289
iv. 4096
v. 1089
Solution:
i. 625
Maharashtra Board Class 7 Maths Solutions Chapter 6 Indices Practice Set 30 1
∴ 625 = 5 x 5 x 5 x 5
∴ √625 = 5 x 5 = 25

ii. 1225
Maharashtra Board Class 7 Maths Solutions Chapter 6 Indices Practice Set 30 2
∴ 1225 = 5 x 5 x 7 x 7
∴ √1225 = 5 x 7 = 35

iii. 289
Maharashtra Board Class 7 Maths Solutions Chapter 6 Indices Practice Set 30 3
∴ 289 = 17 x 17
∴ √289 = 17

iv. 4096
Maharashtra Board Class 7 Maths Solutions Chapter 6 Indices Practice Set 30 4
∴ 4096 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2
∴ √4096 = 2 x 2 x 2 x 2 x 2 x 2
= 64

v. 1089
Maharashtra Board Class 7 Maths Solutions Chapter 6 Indices Practice Set 30 5
∴ 1089 = 3 x 3 x 11 x 11
∴ √1089 = 3 x 11
= 33

Maharashtra Board Class 7 Maths Chapter 6 Indices Practice Set 30 Intext Questions and Activities

Question 1.
Try to write the following numbers in the standard form. (Textbook pg. no. 48)
i. The diameter of Sun is 1400000000 m.
ii. The velocity of light is 300000000 m/sec.
Solution:
i. 1400000000 m = 1.4 x 109 m
ii. 300000000 m/s = 3.0 x 108 m/sec.

Question 2.
The box alongside shows the number called Googol. Try to write it as a power of 10. (Textbook pg. no. 48)
Maharashtra Board Class 7 Maths Solutions Chapter 6 Indices Practice Set 30 6
Solution:
1 x 10100

Maharashtra Board Practice Set 20 Class 6 Maths Solutions Chapter 7 Symmetry

Balbharti Maharashtra State Board Class 6 Maths Solutions covers the Std 6 Maths Chapter 7 Symmetry Class 6 Practice Set 20 Answers Solutions.

6th Standard Maths Practice Set 20 Answers Chapter 7 Symmetry

Question 1.
Draw the axes of symmetry of each of the figures below. Which of them has more than one axis of symmetry?
Maharashtra Board Class 6 Maths Solutions Chapter 7 Symmetry Practice Set 20 1
Solution:
Maharashtra Board Class 6 Maths Solutions Chapter 7 Symmetry Practice Set 20 2
Figures (i), (ii) and (iv) have more than one axis of symmetry.

Question 2.
Write the capital letters of the English alphabet in your notebook. Try to draw their axes of symmetry. Which ones have an axis of symmetry? Which ones have more than one axis of symmetry?
Solution:
Alphabets having axis of symmetry:
Maharashtra Board Class 6 Maths Solutions Chapter 7 Symmetry Practice Set 20 3
Alphabets having more than one axis of symmetry:
Maharashtra Board Class 6 Maths Solutions Chapter 7 Symmetry Practice Set 20 4

Question 3.
Use color, a thread and a folded paper to draw symmetrical shapes.
Solution:
Take any color, a thread and a folded square paper.
Step 1:
Take a folded square paper which is folded along one of its axis of symmetry.
Maharashtra Board Class 6 Maths Solutions Chapter 7 Symmetry Practice Set 20 5

Step 2:
Open the paper. Draw a square in one comer. Place the thread in the square drawn and apply colour on it as shown in the figure.
Maharashtra Board Class 6 Maths Solutions Chapter 7 Symmetry Practice Set 20 6

Step 3:
Remove the thread. You will see a white patch where the thread was.
Maharashtra Board Class 6 Maths Solutions Chapter 7 Symmetry Practice Set 20 7

Step 4:
Fold the paper and press it along the axis of symmetry. When you unfold the paper, you will see an imprint on the other side of the fold which is identical to the color patch you had made earlier.
Maharashtra Board Class 6 Maths Solutions Chapter 7 Symmetry Practice Set 20 8

Question 4.
Observe various commonly seen objects such as tree leaves, birds in flight, pictures of historical buildings, etc. Find symmetrical shapes among them and make a collection of them.
Solution:
Some of the symmetrical objects seen in daily life are shown below:
Maharashtra Board Class 6 Maths Solutions Chapter 7 Symmetry Practice Set 20 9

Maharashtra Board Class 6 Maths Chapter 7 Symmetry Practice Set 20 Intext Questions and Activities

Question 1.
Do you recognize this picture?
Why do you think the letters written on the front of the vehicle are written the way they are? Copy them on a paper. Hold the paper in front of a mirror and read it.
Do you see letters written like this anywhere else?
(Textbook pg. no. 40)
Maharashtra Board Class 6 Maths Solutions Chapter 7 Symmetry Practice Set 20 10
Solution:

  1. The name written in reverse alphabets on the vehicle reads
    as ‘AMBULANCE’ when viewed in the mirror.
    In the case of an emergency, it helps a driver to quickly notice an ambulance by looking into his rear view mirror and read the reverse alphabets which appear perfectly normal in a mirror
  2. Other than ambulance, we see letters written in reverse on school bus.

Maharashtra Board Practice Set 29 Class 7 Maths Solutions Chapter 6 Indices

Balbharti Maharashtra State Board Class 7 Maths Solutions covers the 7th Std Maths Practice Set 29 Answers Solutions Chapter 6 Indices.

Indices Class 7 Practice Set 29 Answers Solutions Chapter 6

Question 1.
Simplify:
i. \(\left[\left(\frac{15}{12}\right)^{3}\right]^{4}\)
ii. (34)-2
iii. \(\left[\left(\frac{1}{7}\right)^{-3}\right]^{4}\)
iv. \(\left[\left(\frac{2}{5}\right)^{-2}\right]^{-3}\)
v. (65)4
vi. \(\left[\left(\frac{6}{7}\right)^{5}\right]^{2}\)
vii. \(\left[\left(\frac{2}{3}\right)^{-4}\right]^{5}\)
viii. \(\left[\left(\frac{5}{8}\right)^{3}\right]^{-2}\)
ix. \(\left[\left(\frac{3}{4}\right)^{6}\right]^{7}\)
x. \(\left[\left(\frac{2}{5}\right)^{-3}\right]^{2}\)
Solution:
i. \(\left[\left(\frac{15}{12}\right)^{3}\right]^{4}\)
\(=\left(\frac{15}{12}\right)^{3 \times 4}=\left(\frac{15}{12}\right)^{12}\)

ii. (34)-2
= 34×(-2)
= 3-8

iii. \(\left[\left(\frac{1}{7}\right)^{-3}\right]^{4}\)
\(=\left(\frac{1}{7}\right)^{(-3) \times 4}=\left(\frac{1}{7}\right)^{-12}\)

iv. \(\left[\left(\frac{2}{5}\right)^{-2}\right]^{-3}\)
\(=\left(\frac{2}{5}\right)^{(-2) \times(-3)}=\left(\frac{2}{5}\right)^{6}\)

v. (65)4
= 65×4
= 620

vi. \(\left[\left(\frac{6}{7}\right)^{5}\right]^{2}\)
\(=\left(\frac{6}{7}\right)^{5 \times 2}=\left(\frac{6}{7}\right)^{10}\)

vii. \(\left[\left(\frac{2}{3}\right)^{-4}\right]^{5}\)
\(=\left(\frac{2}{3}\right)^{(-4) \times 5}=\left(\frac{2}{3}\right)^{-20}\)

viii. \(\left[\left(\frac{5}{8}\right)^{3}\right]^{-2}\)
\(=\left(\frac{5}{8}\right)^{3 \times(-2)}=\left(\frac{5}{8}\right)^{-6}\)

ix. \(\left[\left(\frac{3}{4}\right)^{6}\right]^{7}\)
\(=\left(\frac{3}{4}\right)^{6 \times 1}=\left(\frac{3}{4}\right)^{6}\)

x. \(\left[\left(\frac{2}{5}\right)^{-3}\right]^{2}\)
\(=\left(\frac{2}{5}\right)^{(-3) \times 2}=\left(\frac{2}{5}\right)^{-6}\)

Question 2.
Write the following numbers using positive indices:
i. \(\left(\frac{2}{7}\right)^{-2}\)
ii. \(\left(\frac{11}{3}\right)^{-5}\)
iii. \(\left(\frac{1}{6}\right)^{-3}\)
iv. \((y)^{-4}\)
Solution:
i. \(\left(\frac{7}{2}\right)^{2}\)
ii. \(\left(\frac{3}{11}\right)^{5}\)
iii. \(6^{3}\)
iv. \(\frac{1}{y^{4}}\)

Maharashtra Board Practice Set 28 Class 7 Maths Solutions Chapter 6 Indices

Balbharti Maharashtra State Board Class 7 Maths Solutions covers the 7th Std Maths Practice Set 28 Answers Solutions Chapter 6 Indices.

Indices Class 7 Practice Set 28 Answers Solutions Chapter 6

Question 1.
Simplify:
i. a6 ÷ a4
ii. m5 ÷ m8
iii. p3 ÷ p13
iv. x10 ÷ x10
Solution:
i. a6 ÷ a4
= a6-4
= a2

ii. m5 ÷ m8
= m5-8
= m-3

iii. p3 ÷ p13
= p3-13
= p-10

iv. x10 ÷ x10
= x10-10
= x0
= 1

Question 2.
Find the value of:
i. (-7)12 ÷ (-7)12
ii. 75 ÷ 73
iii. \(\left(\frac{4}{5}\right)^{3} \div\left(\frac{4}{5}\right)^{2}\)
iv. 47 ÷ 45
Solution:
i. (-7)12 ÷ (-7)12
= (-7)12-12
= (-7)0
= 1

ii. 75 ÷ 73
= 75-3
= 72
= 49

iii. \(\left(\frac{4}{5}\right)^{3} \div\left(\frac{4}{5}\right)^{2}\)
\(=\left(\frac{4}{5}\right)^{3-2}=\frac{4}{5}\)

iv. 4 ÷ 4
= 47-5
= 42
= 16