Balbharti Maharashtra State Board Class 7 Maths Solutions covers the 7th Std Maths Practice Set 25 Answers Solutions Chapter 5 Operations on Rational Numbers.

## Operations on Rational Numbers Class 7 Practice Set 25 Answers Solutions Chapter 5

Question 1.

Simplify the following expressions.

i. 50 x 5 ÷ 2 + 24

ii. (13 x 4) ÷ 2 – 26

iii. 140 ÷ [(-11) x (-3) – (-42) ÷ 14 – 1)]

iv. {(220 – 140) + [10 x 9 + (-2 x 5) ]} – 100

v. \(\frac{3}{5}+\frac{3}{8} \div \frac{6}{4}\)

Solution:

i. 50 x 5 ÷ 2 + 24 = 250 ÷ 2 + 24

= 125 + 24

= 149

ii. (13 x 4) = 2 – 26

= 52 ÷ 2 – 26

= 26 – 26

= 0

iii. 140 ÷ [(-11) x (-3) – (-42) ÷ 14 – 1)]

= 140 ÷ [33 + 42 ÷ 14 – 1]

= 140 ÷ [33 + 3 – 1]

= 140 ÷ 35

= 4

iv. {(220 – 140) + [10 x 9 + (-2 x 5) ]} – 100

= {80 + [90 – 10]} – 100

= {80 + 80} – 100

= 160 – 100

= 60

v. \(\frac{3}{5}+\frac{3}{8} \div \frac{6}{4}\)

\(=\frac{3}{5}+\frac{3}{8} \times \frac{4}{6}\)

\(=\frac{3}{5}+\frac{1}{4}\)

\(=\frac{12}{20}+\frac{5}{20}=\frac{12+5}{20}=\frac{17}{20}\)

**Maharashtra Board Class 7 Maths Chapter 5 Operations on Rational Numbers Practice Set 25 Intext Questions and Activities**

Question 1.

Use the signs and numbers in the boxes and form an expression such that its value will be 112. (Textbook pg. no. 42)

[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

[+ x ÷ -]

Solution:

{3 + (6 x 7) + (9 ÷ 3)} + {- 8 + 8 x 9}

Note: The above problem has many solutions. Students may write solution other than the one given.