Maharashtra Board 12th Commerce Maths Solutions Chapter 3 Differentiation Ex 3.2

Balbharati Maharashtra State Board 12th Commerce Maths Solution Book Pdf Chapter 3 Differentiation Ex 3.2 Questions and Answers.

Maharashtra State Board 12th Commerce Maths Solutions Chapter 3 Differentiation Ex 3.2

1. Find the rate of change of demand (x) of a commodity with respect to price (y) if:

Question 1.
y = 12 + 10x + 25x2
Solution:
Given y = 12 + 10x + 25x2
Maharashtra Board 12th Commerce Maths Solutions Chapter 3 Differentiation Ex 3.2 I Q1
Hence, the rate of change of demand (x) with respect to price (y) \(=\frac{d x}{d y}=\frac{1}{10+50 x}\)

Question 2.
y = 18x + log(x – 4)
Solution:
Given y = 18x + log (x – 4)
Maharashtra Board 12th Commerce Maths Solutions Chapter 3 Differentiation Ex 3.2 I Q2
Hence, the rate of change of demand (x) with respect to price (y) \(=\frac{d x}{d y}=\frac{x-4}{18 x-71}\)

Maharashtra Board 12th Commerce Maths Solutions Chapter 3 Differentiation Ex 3.2

Question 3.
y = 25x + log(1 + x2)
Solution:
Given y = 25x + log(1 + x2)
Maharashtra Board 12th Commerce Maths Solutions Chapter 3 Differentiation Ex 3.2 I Q3
Hence, the rate of change of demand (x) with respect to price (y) \(\frac{d x}{d y}=\frac{1+x^{2}}{25 x^{2}+2 x+25}\)

2. Find the marginal demand of a commodity where demand is x and price is y.

Question 1.
y = xe-x + 7
Solution:
Maharashtra Board 12th Commerce Maths Solutions Chapter 3 Differentiation Ex 3.2 II Q1
Maharashtra Board 12th Commerce Maths Solutions Chapter 3 Differentiation Ex 3.2 II Q1.1

Question 2.
y = \(\frac{x+2}{x^{2}+1}\)
Solution:
Maharashtra Board 12th Commerce Maths Solutions Chapter 3 Differentiation Ex 3.2 II Q2

Maharashtra Board 12th Commerce Maths Solutions Chapter 3 Differentiation Ex 3.2

Question 3.
y = \(\frac{5 x+9}{2 x-10}\)
Solution:
Maharashtra Board 12th Commerce Maths Solutions Chapter 3 Differentiation Ex 3.2 II Q3