Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Balbharti Maharashtra State Board Class 9 Science Solutions Chapter 16 Heredity and Variation Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Class 9 Science Chapter 16 Heredity and Variation Textbook Questions and Answers

1. Complete the following sentences by choosing the appropriate words from the brackets.
(Inheritance, sexual reproduction, asexual reproduction, chromosomes, DNA, RNA, gene)

a. Hereditary characters are transferred from parents to offsprings by …………………………….., hence they are said to be structural and functional units of heredity.
b. Organisms produced by …………………………….. show minor variations.
c. The component which is in the nuclei of cells and carries the hereditary characteristics is called ……………………………..
d. Chromosomes are mainly made up of ……………………………..
e. Organisms produced through …………………………….. show major variations.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

2. Explain the following.

a. Explain Mendel’s monohybrid progeny with the help of any one cross.
Answer:

  • Mendel brought about a cross between two pea plants with only pair of contrasting characters. This type of cross is called a monohybrid cross.
  • Tall pea plants and dwarf pea plants were used in this cross. Hence this is parent generation (P1).
    Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 3
  • All the plants produced in F1 genration are tall, having genotype Tt. This indicates that the gene responsible for tallness in pea plants is dominant over the gene responsible for dwarfness.
  • When F1 plants are self pollinated they produce second filial generation (F2).
  • In F2 generation both tall and dwarf plants appeared in the ratio 3:1.
  • Thus, the genotypic ratio of F2 generation is 3 (Tall) : 1 (Dwarf) and the genotypic ratio is 1 TT : 2 Tt: 1 tt.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

b. Explain Mendel’s dihybrid ratio with the help of any one cross.
Answer:

  • In dihybrid cross, Mendel considered two pairs of contrasting characters.
  • He made a cross between a pea plant producing rounded and yellow couloured seeds and a pea plant with wrinkled and green coloured seeds.
    Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 4
  • All the plants produced in F1 generation had rounded yellow seeds. This is because in pea plants, round shape of seed is dominant over wrinkled shape and yellow colour of seed is dominant over green colour.
  • When F1 plants are self pollinated, they produce four types of gamates – RY, Ry, rY, ry.
  • F2 plants formed by the fusion of four types of male gametes and four types of female gametes, had phenotypes such as round yellow, wrinkled yellow, round green and wrinkled green.
  • Also, F2 generation showed nine different types of genotypes such as RRYY, RRYy, RRyy, RrYY, RrYy, Rryy, rrYY, rrYy, rryy.
  • Phenotypic ratio of dihybrid cross is
    Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 5
  • The genotypic ratio of dihybrid cross is
    Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 6

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

c. Distinguish between monohybrid and dihybrid cross.
Answer:

Monohybrid cross Dihybrid cross
(i) Cross involving a single pair of contrasting characters is called monohybrid cross. (i) Cross involving two pairs of contrasting characters is called a dihybrid cross.
(ii) F1 plants of monohybrid cross produce two types of gametes. (ii) F1 plants of dihybrid cross produce four types of gametes.
(iii) Monohybrid cross has a phenotypic ratio of 3 : 1 in F2 generation. (iii) Dihybrid cross has a phenotypic ratio of 9 : 3 : 3 : 1 in F2 generation.

d. Is it right to avoid living with a person suffering from a genetic disorder?
Answer:

  • No, it is not right to avoid living with a person suffering from a genetic disorder.
  • Genetic disorders are transmitted from parents to offsprings only and they are non-contagious, i.e., they do not spread from one person to another through contact.

3. Answers the following questions in your own words.

a. What is meant by ‘chromosome’. Explain its types.
Answer:

  • The structure in the nucleus of cells that carries the hereditary characteristics is called the chromosome.
  • It is made up mainly of nucleic acids and proteins.
  • Depending upon the position of the centromere, there are four types of chromosomes.
    Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 7

(a) Metacentric: The centromere is exactly at the mid-point in this chromosome, and therefore, it looks like the English letter ‘V’. The arms of this chromosome are equal in length.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

(b) Sub-metacentric: The centromere is somewhere near the mid-point in this chromosome which, therefore, looks like the English letter ‘U. One arm is slightly shorter than the other.

(c) Acrocentric: The centromere is near one end of this chromosome which therefore looks like the English letter One arm is much smaller than the other.

(d) Telocentric: The centromere is right at the end of this chromosome making the chromosome look like the English letter ‘i’. This chromosome consists of only one arm.

b. Describe the structure of the DNA molecule.
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 8

  • In 1953, Watson and Crick proposed a model of the DNA molecule.
  • As per their model, two parallel threads (strands) of nucleotides are coiled around each other to form a double helix structure. This structure can be compared with a coiled and a flexible ladder.
  • Each strand of DNA is made up of many small molecules known as nucleotides.
  • Each nucleotide is made up of a molecule of nitrogen base and phosphoric acid joined to a molecule of sugar.
  • There are four types of nitrogen bases-adenine, guanine, cytosine and thymine. Adenine and guanine are called as purines while cytosine and thymine are called as pyrimidines.
  • Nucleotides are arranged like a chain in the DNA.
  • The two threads (strands) of the DNA are comparable to the two rails of the ladder and each rail is made up of alternately joined molecules of sugar and phosphoric acid.
  • Each rung of the ladder is a pair of nitrogenous bases joined by hydrogen bonds. Adenine always pairs with thymine and cytosine always pairs with guanine.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

c. Express your opinion about the use of DNA fingerprinting.
Answer:

  • DNA fingerprinting is the technique in which the sequence of the genes in the DNA of a person, i.e., the genome of the person is identified.
  • This technique is useful to identify the lineage and to identify criminals because it is unique to every person.
  • It is also useful to identify paternity and maternity disputes etc.
  • This technique was developed by Professor of genetics Sir Alec Jeffreys.
  • A common method of collecting a reference sample, is in the use of a buccal swab. If this is not available, blood or saliva or hair sample may be used.
  • Just like your actual fingerprint, your DNA fingerprint is something that you are born with. It is unique to you.
  • DNA fingerprint is very useful in forensic science.

d. Explain the structure, function and types of RNA.
Answer:

  • Ribonucleic acid (RNA) is an important nucleic acid of the cell.
  • RNA is made up of ribose sugar, phosphate molecules and four types of nitrogenous bases adenine, guanine, cytosine and uracil.
  • The nucleotide i.e., smallest unit of the chain of the RNA molecule is formed by the combination of a ribose sugar, phosphate molecule and one of the nitrogen bases.
  • Large numbers of nucleotides are bonded together to form the macromolecule of RNA.
  • RNA performs the function of protein synthesis.
  • According to function, there are three types of RNA:
    (a) Ribosomal RNA (rRNA): It is the component of cellular organelle ribosome. Ribosomes perform the function of protein synthesis.(b) Messenger RNA (mRNA): It carries the information for protein synthesis from genes (i.e. DNA segment in the cell nucleus) to ribosomes (in the cytoplasm) which produce the proteins.(c) Transfer RNA (tRNA): It carries the amino acid up to the ribosomes as per the message of the mRNA.

e. Why is it necessary for people to have their blood examined before marriage?
Answer:

  • If people have their blood examined before marriage, the partners will know about the possible genetic diseases that their children might inherit. So they may decide not to have children or not to get married.
  • Blood tests before marriage are also done to check for any contagious disease in the partners. This will help to protect the partners from contagious diseases like STDs.

4. Write a brief note on each.

a. Down syndrome
Answer:

  • Down syndrome is the disorder arising due to chromosomal abnormality.
  • This is the first discovered and described the chromosomal disorder in human beings.
  • This disorder is characterized by the presence of 47 chromosomes. It is described as the trisomy of the 21st pair.
  • Infants with this disorder have one extra chromosome with the 21st pair in every cell of the body. Therefore, they have 47 chromosomes instead of 46. Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation
  • Children suffering from Down syndrome are usually mentally retarded and have a short lifespan. Mental retardation is the most prominent characteristic.
  • Other symptoms include short height, short wide neck, flat nose, short fingers, scanty hair, single horizontal crease on palm and a life expectancy of about 16-20 years.

b. Monogenic disorders
Answer:

  • Disorders occurring due to mutation in any single gene into a defective one are called monogenic disorders.
  • Approximately 4000 disorders of this type are now known.
  • Due to abnormal genes, their products are either produced in insufficient quantity or not produced at all.
  • It causes abnormal metabolism and may lead to death at a tender age.
  • Examples of monogenic disorders are Hutchinson’s disease, Tay-Sachs disease, galactosaemia, phenylketonuria, sickle cell anaemia, cyctic fibrosis, albinism, haemophilia, night blindness etc.

c. Sickle cell anaemia: symptoms and treatment.
Answer:

  • Sickle-cell anaemia is a hereditary disease caused due to mutation in a single gene. It is a monogenic disorder.
  • Normal haemoglobin has glutamic acid as the 6th amino acid in its molecular structure. However, if it is replaced by valine, the shape/structure of the haemoglobin molecule, changes.
  • Due to this, the erythrocytes (RBCs) which are normally biconcave become sickle-shaped. This condition is called sickle-cell anaemia. The oxygen-carrying capacity of haemoglobin in such individuals is very low.
  • In this condition, clumping and thereby, destruction of erythrocytes occurs most often. As a result, blood vessels are obstructed and the circulatory system, brain, lungs, kidneys, etc. are damaged.
  • Symptoms of sickle-cell anaemia are swelling of legs and hands, pain in joints, severe general body aches, frequent cold and cough, constant low-grade fever, exhaustion, pale face, low haemoglobin count.
  • A person suffering from sickle-cell anaemia should take a tablet of folic acid daily.

5. How are the items in groups A, B and C inter-releated?

6. Filling the blanks based on the given relationship.
a. 44 + X : Turner syndrome : : 44 + XXY: – ……………………………..
b. 3:1 Monohybrid : : 9:3:3:1 : ……………………………..
c. Women : Turner syndrome : : Men : ……………………………..
Answer:
a. Klinefelter syndrome
b. Dihybrid
c. Klinefelter syndrome

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

7. Complete the tree diagram below based on types of hereditary disorders.
Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 1
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 2

Class 9 Science Chapter 12 Study of Sound Intext Questions and Answers

Question 1.
How do specific traits or characteristics appear in organisms? (Can you tell; Textbook Page No. 180)
Answer:

  • Information necessary for synthesis of a particular protein is stored in the DNA.
  • The segment of DNA which contains all the information for synthesis of a particular protein is called a gene for that protein.
  • To understand how a specific trait is expressed, let us consider plant height as an example.
  • We know that there are growth hormones in plants. Increase in the height of plants depends upon the quantity of growth hormones.
  • The quantity of growth hormone produced by a plant depends upon the efficiency of the concerned enzyme.
  • Efficient enzymes produce a greater quantity of the hormone due to which the height of the plant increases.
  • However, if the enzymes are less efficient, a smaller quantity of hormone is produced leading to the stunting of the plant.
  • Thus, the expression of traits is controlled by the genes.

Question 2.
Show the monohybrid cross between (RR) and (rr) and write the phenotypic and genotypic ratio of F2 generation. (Use your brain power; Textbook Page No. 187)
Answer:
Parental Generation (P1)
Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 9
Phenotypic ratio : 3 Round : 1 Wrinkled
Genotypic ratio : 1 RR : 2 Rr : 1 rr

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 3.
Why did the characteristic of the Rounded- Yellow seeds alone appear in the Fj generation but not the characteristic of the wrinkled- green seeds? (Use your brain power; Textbook Page No. 187)
Answer:

  • Rounded-Yellow seeds is a dominant characteristic whereas wrinkled-green seeds is a recessive characteristic.
  • Therefore only the characteristic of Rounded- Yellow seeds appeared in the F1 generation.

Question 4.
Do all boys and girls of your class look alike? (Think about it; Textbook Page No. 179)
Answer:

  • No, all the boys and girls of my class do not look alike.
  • There is a lot of variation among them.

Question 5.
Carefully observe your classmate’s earlobes. (Observe; Textbook Page No. 179)
Answer:

  • Most of the classmates have free earlobes while very few have attached ear lobes.
  • This shows that in humans free earlobes is a dominant characteristic whereas attached earlobe is a recessive characteristic.

Question 6.
Irrespective of all of us being humans, what difference do you notice in our skin colour? (Observe; Textbook Page No. 179)
Answer:

  • Irrespective of all of us being humans, there is a lot of variation in our skin colour. Some people are light-skinned while some are dark-skinned.
  • The difference in skin colour is due to the gene responsible for the production of the pigment melanin.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 7.
All of you are in std. IX. Why then are some students tall and some short? (Observe; Textbook Page No. 179)
Answer:
Our height is decided by gene. People who are tall have genes for tallness whereas people who are short have genes for shortness and hence the variation.

Class 9 Science Chapter 12 Study of Sound Additional Important Questions and Answers

Choose and write the correct option:

Question 1.
The similarities and differences are all the effect of
(a) Heredity
(b) Fertilization
(c) Evolution
(d) Natural selection
Answer:
(a) Heredity

Question 2.
Each chromosome appears midway during cell division.
(a) Circular
(b) Rod-shaped
(c) Dumbbell-shaped
(d) Bottle-shaped
Answer:
(c) dumbbell-shaped

Question 3.
The chromosome in which the centromere is exactly at the mid-point is called chromosome.
(a) sub-metacentric
(b) metacentric
(c) acrocentric
(d) telocentric
Answer:
(b) metacentric

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 4.
The chromosome in which the centromere is somewhere near the mid-point is called chromosome.
(a) metacentric
(b) acrocentric
(c) sub-metacentric
(d) telocentric
Answer:
(c) sub-metacentric

Question 5.
The chromosome in which the centromere is near one end of the chromosome is called chromosome.
(a) metacentric
(b) acrocentric
(c) sub-metacentric
(d) telocentric
Answer:
(d) telocentric

Question 6.
Sex chromosomes are called
(a) homologous chromosomes
(b) autosomes
(c) allosomes
(d) metacentric chromosomes
Answer:
(c) allosomes

Question 7.
Which of the following is absent in RNA?
(a) Adenine
(b) Uracil
(c) Cytosine
(d) Thymine
Answer:
(d) Thymine

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 8.
DNA was discovered by
(a) Watson and Crick
(b) Frederick Miescher
(c) Gregor Johann Mendel
(d) Robert Brown
Answer:
(b) Frederick Miescher

Question 9.
The double helix model of DNA was produced by
(a) Watson and Crick
(b) Frederick Miescher
(c) Gregor Johann Mendel
(d) Robert Hooke
Answer:
(a) Watson and Crick

Question 10.
The molecule of RNA which is a component of the ribosome organelle is called a
(a) mRNA
(b) tRNA
(c) rRNA
(d) DNA
Answer:
(c) rRNA

Question 11.
In a monohybrid cross, the phenotypic ratio of F, generation is
(a) 1 tall: 3 dwarf
(b) 2 tall: 2 dwarf
(c) 3 tall: 1 dwarf
(d) 3 tall: 2 dwarf
Answer:
(c) 3 talhl dwarf

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 12.
arises due to either inheritance of only X chromosome from parents or due to inactivation of the gender-related part of X-chromosomes.
(a) Down syndrome
(b) Turner syndrome
(c) Klinefelter syndrome
(d) Albinism
Answer:
(b) Turner syndrome

Question 13.
Progenies of normal man and sufferer woman for sickle-cell anaemia will be
(a) all normal
(b) 25% normal and 75% sufferer
(c) all carrier
(d) all sufferer
Answer:
(c) all carrier

Question 14.
is a mitochondrial disorder.
(a) Down syndrome
(b) Cleft palate
(c) Spina bifida
(d) Leber hereditary optic neuropathy
Answer:
(d) Leber hereditary optic neuropathy

Question 15.
is a monogenic disorder.
(a) Haemophilia
(b) Cleft palate
(c) Diabetes
(d) Spina bifida
Answer:
(a) Haemophilia

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 16.
is a recessive character of pea plant.
(a) Round shape of seeds
(b) White colour of flowers
(c) Green colour of pods
(d) Inflated shape of pods
Answer:
(b) White colour of flowers

Question 17.
is a dominant character of pea plant.
(a) Dwarf height
(b) Yellow colour of pod
(c) Yellow colour of seeds
(d) Terminal position of flower
Answer:
(c) Yellow colour of seeds

Question 18.
is a dominant character in human beings.
(a) Non-rolling tongue
(b) Attached ear lobe
(c) Absence of hair on arms
(d) Free ear lobe
Answer:
(d) Free ear lobe

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 19.
is a recessive character in human beings.
(a) Absence of hair on arms
(b) Black and curly hair
(c) Free earlobe
(d) Presence of hair on arms
Answer:
(a) Absence of hair on arms

Question 20.
If one parent is normal and one parent is carrier of sickle-cell anaemia, then the progenies will be
(a) all normal
(b) 50% normal and 50% carrier
(c) 50% carrier and 50% sufferer
(d) all carrier
Answer:
(b) 50% normal and 50% carrier

Question 21.
If one parent is carrier and one parent is a sufferer of sickle-cell anaemia, then the progenies will be
(a) 50% normal and 50% carrier
(b) all sufferers
(c) 50% carrier and 50% sufferer
(d) all carrier
Answer:
(c) 50% carrier and 50% sufferer

Find the odd man out:

Question 1.
Adenine, thymine, cytosine, uracil
Answer:
Adenine. It is a purine whereas the others are pyrimidines.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 2.
Axillary flower, green pod, green seed, inflated pod
Answer:
Green seed. It is a recessive character of pea plant whereas the others are dominant characters.

Question 3.
Constricted pod, purple flower, axillary flower, yellow seeds.
Answer:
Constricted pod. It is a recessive character of pea plant whereas the others are dominant characters.

Question 4.
Green seeds, wrinkled seeds, terminal flower, green pod.
Answer:
Green pod. It is a dominant character of pea plant whereas the others are recessive characters.

Question 5.
Attached ear lobes, brown and straight hair, non-rolling tongue, presence of hair on arms.
Answer:
Presence of hair on arms. It is a dominant characteristic of human beings whereas the others are recessive characters.

Question 6.
Cystic fibrosis, albinism, spina bifida, sicklecell anaemia.
Answer:
Spina bifida. It is a polygenic disorder whereas the others are monogenic disorders.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 7.
Fiutchinson’s disease, phenylketonuria, nightblindness, leber hereditary optic neuropathy.
Answer:
Leber hereditary optic neuropathy. It is a mitochondrial disorder whereas the others are monogenic disorders.

Complete the analogy:

a. Tall plant: Phenotype :: Tt:
b. Dominant trait : Axial position of flower :: Recessive trait:
c. Women : 44 + XX :: Men :
d. Adenine and Guanine : Purine :: Cytosine and Thymine :
Answer:
a. Genotype
b. Terminal position of flower
c. 44 + XY
d. Pyrimidine

Match the columns

Question 1.

Column 1 Column 2 Column 3
(1) Leber hereditary optic neuropathy (a) 44 + XXY (i) Pale skin, white hairs.
(2) Diabetes (b) 45 + X (ii) Men are sterile.
(3) Albinism (c) Mitochondrial disorder (iii) Women are sterile.
(4) Turner syndrome (d) Polygenic disorder (iv) This disorder arises during development of zygote.
(5) Klinefelter Syndrome (e) Monogenic disorder (v) Effect on blood- glucose level.

Answer:
(1 – c – iv),
(2 – d – v),
(3 – e – i),
(4-b- Hi),
(5 – a – ii)

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 2.

Column ‘A’ Column ‘B’
(1) Yellow and rinkled (a) yyrr
(2) Green and round (b) YyRr
(3) Yellow and round (c) YYrr
(4) Green and wrinkled (d) yyRr

Answer:
(1 – c),
(2 – d),
(3 – b),
(4 – a)

Question 3.

Column ‘A’ Column ‘B’
(1) Tay-Sachs disease (a) Multifactorial disorder
(2) Diabetes (b) Destruction of erythrocytes
(3) Sickle-cell anaemia (c) Absence of melanin
(4) Albinism (d) Monogenic disorder

Answer:
(1 – d),
(2 – a),
(3 – b),
(4 – c)

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

State whether the following statements are true or false. Correct the false statement:

Question 1.
Offsprings produced through asexual reproduction show greater variations as compared to those produced through sexual reproduction.
Answer:
False. Offsprings produced through asexual reproduction show minor variations as compared to those produced through sexual reproduction.

Question 2.
Information necessary for protein synthesis is stored in the RNA.
Answer:
False. Information necessary for protein synthesis is stored in the DNA.

Question 3.
The quantity of growth hormone produced by a plant depends upon the efficiency of the concerned enzyme.
Answer:
True

Question 4.
The chromosome in which the centromere is exactly at the mid-point is called telocentric chromosome.
Answer:
False. The chromosome in which the centromere is exactly at the mid-point is called metacentric chromosome.

Question 5.
RNA molecules are called master molecules.
Answer:
False. DNA molecules are called master molecules.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 6.
The pair of sex chromosomes are called autosomes.
Answer:
False. The pair of sex chromosomes is called allosomes.

Question 7.
In DNA, Adenine always pairs with thymine and cytosine always pairs with guanine.
Answer:
True

Question 8.
In humans there are 23 pairs of autosomes and one pair of allosomes.
Answer:
False. In humans, there are 22 pairs of autosomes and one pair of allosomes.

Question 9.
The phenotypic and genotypic ratios are not same.
Answer:
True

Question 10.
Phenotype means the pairs of genes responsible for the visible characteristics of organisms.
Answer:
False. Phentotype means external appearance of visible characteristics of organisms.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 11.
During gamete formation, in Pj generation the pair of gametes separate independently.
Answer:
True

Question 12.
Down syndrome is caused due to monosomy of X chromosome.
Answer:
False. Down syndrome is caused due to trisomy of 21st chromosome.

Question 13.
In Klinefelter syndrome, women are sterile.
Answer:
False. In Klinefelter syndrome, men are sterile as this disorder arises in men due to abnormality in sex chromosome.

Question 14.
If the father and mother are both sufferers or carriers of sickle-cell anaemia, their offsprings are likely to suffer from this disease.
Answer:
True

Question 15.
During fertilization, mitochondria is contributed by the sperm cell and egg cell(ovum).
Answer:
False. During fertilization, mitochondria is contributed by the egg cell (ovum) alone.

Question 16.
Polygenic disorders strictly follow Mendel’s principles of heredity.
Answer:
False. Polygenic disorders do not strictly follow Mendel’s principles of heredity.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 17.
Genetic material is transferred in equal quantity from parents to progeny.
Answer:
True

Give scientific reasons:

Question 1.
DNA molecules are called as ‘Master molecules’.
Answer:

  • Molecules of DNA are present in all organisms from viruses and bacteria to human beings.
  • These molecules control the functioning, growth and division (reproduction) of the cell.
  • Genes present in the DNA are also responsible for transfer of hereditary characteristics from parents to offsprings.
  • Therefore, DNA molecules are called as ‘Master molecules’.

Question 2.
Phenotypic and genotypic ratios are different.
Answer:

  • Phenotype means external appearance or visible characteristics of organisms whereas the genotype is the pairs of genes responsible for the visible characteristics.
  • The genes responsible for any particular character are present in pairs.
  • Though, there are two genes, the phenotype
    depends on the presence of the dominant gene, e.g. Genotype for tall height of the plant is TT or Tt.
  • Therefore, phenotypic and genotypic ratios are different.

Question 3.
A carrier or sufferer of sickle-cell anaemia should avoid marriage with another carrier or sufferer.
Answer:

  • Sickle-cell anaemia is a hereditary disease caused due to mutation of a single gene.
  • It is a monogenic disorder that occurs due to changes in a gene during conception.
  • If father and mother both are sufferers or carriers of sickle-cell anaemia, their offsprings are likely to suffer from the disease.
  • Therefore, a carrier or sufferer of sickle-cell anaemia should avoid marriage with another carrier or sufferer.

Question 3.
Mitochondrial disorders are inherited from the mother only.
Answer:

  • Mitochondrial DNA becomes defective due to mutation.
  • During fertilization, mitochondria are contributed by the egg cell (ovum) alone.
  • Hence, mitochondrial disorders are inherited from the mother only.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 4.
Tobacco smoking causes cancer.
Answer:

  • Tobacco smoke contains harmful chemicals like pyridine, ammonia, aldehyde furfural, carbon monoxide, nicotine, sulphur dioxide etc.
  • They cause uncontrolled cell division.
  • Tobacco smoke is full of minute carbon particles which cause normal tissue lining of the lung to transform into thickened black tissue. This leads to cancer.
  • Therefore, tobacco smoking causes cancer.

Define the following terms:

Question 1.
Gene
Answer:
The segment of DNA which contains all the information for synthesis of a particular protein is called a ‘gene’.

Question 2.
Chromosome
Answer:
The structure in the nucleus of the cells that carries the hereditary characteristics is called chromosome.

Question 3.
Genetics
Answer:
The branch of biology which studies the transfer of characteristics of organism from one generation to the next and genes in particular, is called genetics.

Question 4.
Heredity
Answer:
Transfer of characteristics from parents to offsprings is called heredity.

Question 5.
Homologous chromosomes
Answer:
If the pair consists of chromosomes are similar in shape and organization, they are called homologous chromosomes.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 6.
Heterologous chromosomes
Answer:
If the pair which consists of chromosomes are not similar in shape and organization, they are called heterologous chromosomes.

Question 7.
Genetic disorders
Answer:
Diseases or disorders occuring due to abnormalities in chromosomes and mutations in genes are called genetic disorders.

Distinguish between:

Question 1.
DNA and RNA
Answer:

DNA RNA
(i) In DNA, the sugar present is deoxyribose. (i) In RNA, the sugar present is ribose.
(ii) In DNA, the nitrogen bases are adenine, guanine, cytosine and thymine. (ii) In RNA, the nitrogen base thymine is replaced by uracil.
(iii) DNA is double stranded. (iii) RNA is single-stranded.
(iv) DNA carries hereditary information (iv) RNA helps in protein synthesis.

Question 2.
Turner syndrome and Klinefelter syndrome.
Answer:

Turner syndrome Kline fater syndrome
(i) It is due to monosomy of sex chromosome. (i) It is due to felter of sex chromosome.
(ii) Disorder in sex chromosome results in 44 + X condition. (ii) Disorder in sex chromosome results is 44 + XY condition.
(iii) Seen in women. (iii) Seen in men
(iv) Women suffering from this syndrome are sexually sterile. (iv) Men suffering from this syndrome are sexually sterile.
(v) There is presence of total 45 chromosomes instead of 46. (v) There is presence of total 47 chromosomes instead of 46.

Write short notes on:

Question 1.
Albinism
Answer:

  • Albinism is a monogenic disorder.
  • Our eyes, skin and hair have colour due to the brown pigment melanin. In this disease, the body cannot produce melanin. Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation
  • The skin becomes pale, hair are white and eyes are usually pink due to absence of melanin pigment in the retina and sclera.

Question 2.
Polygenic disorders.
Answer:

  • Polygenic disorders are caused due to mutations in more than one gene.
  • In most such cases, their severity increases due to effects of environmental factors on the foetus.’
  • Common examples of such disorders are cleft lip, cleft palate, constricted stomach, spina bifida (a defect of the spinal cord), etc. Besides diabetes, blood pressure, heart disorders, asthma and obesity are also polygenic disorders.
  • Polygenic disorders do not strictly follow Mendel’s principles of heredity.
  • These disorders arise from a complex interaction between environment, life style and defects in several genes.

Question 3.
Turner syndrome.
Answer:

  • Turner syndrome is a disorder arising in women due to abnormality in sex chromosomes.
  • Turner syndrome arises due to either inheritance of only one X chromosome from parents or due to inactivation of the gender- related part of X-chromosomes.
  • Instead of the normal 44 + XX condition, women suffering from Turner syndrome show a 44 + X condition.
  • Such women are sterile i.e. unable to have children due to improper growth of the reproductive organ.

Answer the following questions:

Question 1.
What are the main objectives of National Health Mission?
Answer:
The main objectives of National Health Mission are:

  • Strengthening of the rural and urban health facilities.
  • Controlling various diseases and illnesses.
  • Increasing public awareness about health.
  • Offering financial assistance to patients through various schemes.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 2.
Which were the seven pairs of contrasting characteristics studied by Mendel in pea plant?
Answer:
The seven pairs of contrasting characters studied by Mendel in pea plant were as follows:

Characters Dominant Recessive
Shape of the seed Round(R) Wrinkled (r)
Colour of the seed Yellow (Y) Green (y)
Colour of the flower Purple (C) White (c)
Shape of pod Inflated (I) Constricted (i)
Colour of pod Green (G) Yellow (g)
Position of flower Axillary (A) Terminal (a)
Height of the plant Tall (T) Dwarf (t)

Question 3.
Name some dominant and recessive characteristics seen in human beings.
Answer:
Some dominant and recessive characteristics of human beings.

Dominant Recessive
Rolling tongue Non-rolling tongue
Presence of hair on arms Absence of hair on arms
Black and curly hair Brown and straight hair
Free earlobe Attached earlobe

Question 4.
What is Klinefelter syndrome?
Answer:

  • Klinefelter syndrome is a disorder arising in men due to abnormalities in sex chromosomes.
  • In this disorder, men have one extra X chromosome, hence their chromosomal condition becomes 44 + XXY.
  • Such men are usually sterile because their reproductive organs are not well developed.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 5.
How is the diagnosis for sickle-cell anaemia made?
Answer:

  • Under the National Health Mission scheme, the ‘Solubility Test’ for diagnosis of sickle-cell anaemia is available at all district hospitals.
  • Similarly, the confirmatory diagnostic test – ‘Electrophoresis’ is performed at rural and subdistrict hospitals.

Question 6.
Find out the Phenotypic ratio of the following:
(a) Round-Yellow
(b) Wrinkled-Yellow
(c) Round-Green
(d) Wrinkled-Green
Answer:
(a) Round-Yellow: 9
(b) Wrinkled-Yellow: 3
(c) Round-Green: 3
(d) Wrinkled-Green: 1
Phenotypic ratio: 9:3:3:1

Question 7.
Find out the Genotypic ratio of the following:
(a) RRYY
(b) RRYy
(c) RRyy
(d) RrYY
(e) RrYy
(f) Rryy
(g) rrYY
(h) rrYy
(i) rryy
Answer:
(a) RRYY -1
(b) RRYy-2
(c) RRyy-1
(d) RrYY-2
(e) RrYy-4
(f) Rryy-2
(g) rrYY – 1
(h) rrYy – 2
(i) rryy – 1
Genotypic ratio: 1:2:1:2:4:2:1:2:1

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Draw neat and labelled diagrams of the following:

Question 1.
Structure of chromosome
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 10

Question 2.
Types of RNA
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 11

Answer the following questions:

Question 1.
What are the effects of tobacco consumption?
Answer:

  • Smoking of cigarettes and bidis adversely affects the process of digestion.
  • It causes a burning sensation in the throat and cough.
  • Excessive smoking causes instability and trembling of fingers.
  • It causes dry cough which leads to sleeplessness.
  • Tobacco consumption can lead to shortening of life span, chronic bronchitis, pericarditis, cancer of the lungs, mouth, larynx (voice box), pharynx, urinary bladder, lips or tongue.
  • The nicotine present in tobacco affects the central and peripheral nervous system. Arteries become hard i.e. it causes arteriosclerosis and hypertension.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 2.
Complete the table for number of chromosomes in different organisms.
Answer:

Organism No. of Chromosomes
Crab 200
Maize 20
Frog 26
Roundworm 04
Potato 48
Human 46
Dog 78
Elephant 56
Fruit fly 08
Mango 40

Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space: Telescopes

Balbharti Maharashtra State Board Class 9 Science Solutions Chapter 18 Observing Space: Telescopes Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 9 Science Solutions Chapter 18 Observing Space: Telescopes

Class 9 Science Chapter 18 Observing Space: Telescopes Textbook Questions and Answers

1. Fill in the blanks with the proper words.

a. The wavelength of visible light is between …………………..….. and …………………..…. .
b. GMRT is used for …………………..….. waves.
c. A certain X-ray telescope is named after scientist …………………..…. .
d. The first scientist to use a telescope for space observations …………………..…. .
e. The biggest optical telescope in India is situated at …………………..…. .

Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space: Telescopes

2. Form pairs

Column ‘A’ Column ‘B’
(1) X-rays (a) GMRT
(2) Optical telescope (b) ISRO
(3) Indian radio telescope (c) Hubble
(4) Launching artificial-satellite (d) Chandra

Answer:
(1 – d),
(2 – c),
(3 – a),
(4 – b),

3. What are the difficulties in using ground-based optical telescopes? How are they overcome?
Answer:
Difficulties:

  • The intensity of visible light coming from a heavenly body decreases due to absorption as it passes through the Earth’s atmosphere. Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space: Telescopes
  • Due to changes in atmospheric temperature and pressure light rays change their path.
  • Because of sunlight, we cannot use optical telescopes during the day.
  • During the night, city lights and cloudy weather cause difficulties.

Solution:

  • To reduce these problems, optical telescopes are situated on top of mountains, in uninhabited places.
  • To get rid of all the above problems completely, the telescope is placed above the earth’s atmosphere, in space.

4. Which type of telescopes can be made using a concave mirror, convex mirror, plane mirror, and a lens? Draw diagrams of these telescopes.
Answer:

  • A Newtonian telescope can be made using a concave mirror, plane mirror and a lens.
    Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space Telescopes 4
  • A Cassegrain telescope can be made using a convex mirror, concave mirror and a lens.
    Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space Telescopes 5
  • A refracting telescope can be made using two or more lenses.
    Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space Telescopes 6

Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space: Telescopes

5. Study the figure and answer the following questions:
Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space Telescopes 3

a. What type of telescope is shown in the figure?
b. Label the main parts of the telescope.
c. Which type of mirror does the telescope use?
d. What other type of telescope uses a curved mirror?
e. Explain the working of the above telescope.
Answer:
(a) The Newtonian telescope (Reflecting telescope)
(b)
Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space: Telescopes 1
(c) Concave mirror
(d) The Cassegrain telescope
(e) Working.

  • Light rays coming from space are reflected by the concave mirror.
  • Before these reflected rays converge at the focus, they are deflected again by a small plane mirror.
  • As a result, they get focused at a point lying on the perpendicular to the axis of the telescope’s cylinder.
  • They pass through the eyepiece and we get a magnified image of the source.

Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space: Telescopes

6. Answer the following questions.

a. Explain the construction of Galileo’s telescope.
Answer:

  • The Galileo’s telescope is made up of two or more convex lenses.
  • The lens facing the object is called the objective lens which is made as large as possible to collect the maximum amount of light coming from a heavenly object.
  • The lens closer to the eye is called the eyepiece which uses the light collected by the objective lens and produces a large image of the source.
  • Such a telescope is also called a refracting telescope.

b. Explain the construction of a radio telescope.
Answer:

  • The radio telescope is made from one or more dishes of a particular parabolic shape.
  • As in optical telescope, the incident radio waves are reflected by these dishes and converge at the focus.
    Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space Telescopes 2
  • A radio receiver is placed at the focal point.
  • The information gathered by this receiver is passed on to a computer which analyses it and constructs an image of the source.

Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space: Telescopes

c. Why are optical telescopes located in uninhabited places on mountains?
Answer:

  • The visible light coming from a heavenly body has to pass through the earth’s atmosphere to reach the earth’s surface.
  • During this journey, some of the light is absorbed by the atmosphere and the intensity of the light reaching the earth’s surface decreases.
  • A second problem is caused by the changes in atmospheric pressure and temperature.
  • These changes cause turbulence in the atmosphere which in turn cause the light rays to change their path slightly and thereby shake the position of the image.
  • We cannot use optical telescope during the day. because of sunlight also.
  • During the night too, city lights and cloudy weather can cause difficulties in observing the heavenly bodies.
  • Hence, optical telescopes are located in uninhabited places on mountains.

d. Why can an X-ray telescope not be based on the earth?
Answer:

  • X-rays are emitted from distant heavenly bodies.
  • The rays coming towards the earth will be absorbed by the earth’s atmosphere and will go undetected.
  • Hence, X-ray telescopes are placed in an orbit outside the earth’s atmosphere and not on the earth.

Class 9 Science Chapter 18 Observing Space: Telescopes Intext Questions and Answers

Question 1.
What is meant by space observation? Why is it important?
Answer:
The observation of distant planets, galaxies and other astronomical objects is called as space observation.

  • Various space based satellites support our telecommunication networks by providing us television broadcasting.
  • Meteorology services such as weather forecasting help in disaster management.
  • Observation of positions of stars and other heavenly bodies has helped in the study of solar system, solar winds, pulsars, supernova, etc.

Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space: Telescopes

Question 2.
What is the difference between sky and space?
Answer:
Sky: It is a layer of gas that surrounds the earth in which sunlight is scattered making it visible from the surface of the earth.
Space: The vast emptiness beyond the sky is called as space.

Class 9 Science Chapter 18 Observing Space: Telescopes Additional Important Questions and Answers

Choose and write the correct options:

Question 1.
The first telescope was invented by
(a) Einstein
(b) Galileo
(c) Newton
(d) Mendel
Answer:
(b) Galileo

Question 2.
Eight is an wave.
(a) electric
(b) magnetic
(c) electromagnetic
(d) mechanical
Answer:
(c) electromagnetic

Question 3.
Visible radiation telescopes are also called as
(a) Gamma Ray telescopes
(b) Optical telescopes
(c) X-ray telescopes
(d) Radio telescopes
Answer:
(b) Optical telescope

Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space: Telescopes

Question 4.
Reflecting telescopes are mainly of two types : ……………….. and ………………. .
(a) Newtonian and Galileoan
(b) Optical and Cassegrain
(c) Newtonian and Cassegrain
(d) Optical and Refracting
Answer:
(c) Newtonian and cassegrain

Question 5.
Giant Meterwave Radio Telescope (GMRT) has been erected at near Pune.
(a) Asangaon
(b) Talegaon
(c) Narayangaon
(d) Bhategaon
Answer:
(c) Narayangaon

Question 6.
Visible light coming from heavenly bodies have to pass through the to reach the earth surface.
(a) stratosphere
(b) troposphere
(c) atmosphere
(d) biosphere
Answer:
(c) atmosphere

Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space: Telescopes

Question 7.
To collect the maximum amount of light coming from an object, the objective lens should be made as as possible.
(a) large
(b) small
(c) circular
(d) flat
Answer:
(a) large

Question 8.
The images formed by lenses have errors of colours. This is called
(a) chromatic disruption
(b) chromatic aberration
(c) chromatic reflection
(d) chromatic reaction
Answer:
(b) chromatic aberration

Question 9.
Radio telescope is made up of one or more dishes of shape.
(a) spherical
(b) hyperbolic
(c) parabolic
(d) hexagonal
Answer:
(c) parabolic

Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space: Telescopes

Match the columns:

Question 1.

Column ‘A’ Column ‘B’
(1) X-rays (a) GMRT
(2) Optical telescope (b) ISRO
(3) Indian radio telescope (c) Hubble
(4) Launching artificial satellite (d) Chandra
(5) Radio waves (e) telecommunication
(6) INSAT and GSAT (f) longer than 20cm

Answer:
(1 – d),
(2 – c),
(3 – a),
(4 – b),
(5 – f),
(6- e)

Question 2.

Column ‘A’ Column ‘B’
(1) Micro waves
(2) Infrared waves
(3) Visible light rays
(4) Ultraviolet rays
(5) X-rays
(a) 800 nm – 0.3mm
(b) 360 pm – 400 nm
(c) 3 pm – 300 pm
(d) 400 nm – 800nm
(e) 0.3 mm -20cm

Answer:
(1 – e),
(2 – a),
(3 – d),
(4 – b),
(5 – c)

Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space: Telescopes

Define the following:

Question 1.
Visible radiation
Answer:
Light is an electromagnetic wave. Every wave has a characteristic wavelength. Our eyes can see only that light which has wavelengths between 400 nm to 800 nm. Such light is called visible radiation.

Question 2.
Reflecting Telescope
Answer:
When light falls on the mirror, it gets reflected. Telescopes that use concave mirrors are called reflecting telescope.

Question 3.
Optical telescopes
Answer:
Telescopes which are made from regular lenses and mirrors and used to see visible radiations coming from space are called optical telescopes.

Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space: Telescopes

Question 4.
Refracting Telescopes
Answer:
Light rays change their direction as they enter a lens from the atmosphere and again when they enter the atmosphere after passing through the lens. This is called refraction. The telescopes that use such lenses are called refracting telescopes.

Question 5.
Radio telescopes
Answer:
Many heavenly bodies emit radio waves in addition to visible radiation. A special type of telescope which is used to receive these rays are known as radio telescope.

Answer the following:

Question 1.
How do refracting telescopes work?
Answer:

  • Most refracting telescopes are made with two or more lenses.
  • The two lenses are called objective lens and an eyepiece lens.
  • The objective lens should be large so that maximum light can be collected from the source.
  • Using the light collected, the eyepiece lens which is small in size, produces a large image of the source.

Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space: Telescopes

Question 2.
What are the difficulties in using refracting telescopes?
Answer:

  • We require a large objective lens which is very difficult to make. Also large lenses are heavy and tend to get distorted.
  • As the objective and eyepiece lens are placed on the opposite sides of the telescope, the length of the telescope also increases with increase in the size of the lenses. This makes it difficult to manage a large telescope.
  • The images formed by lenses have errors of colours. This is called chromatic aberration.

Question 3.
How does a radio telescope work?
Answer:

  • A radio telescope is made from one or more dishes of a particular parabolic shape.
  • The incident radio waves are reflected by these dishes and converge at a focus.
  • A radio receiver is placed at focal point.
  • The information gathered by this receiver is then passed onto a computer which analyses and constructs the image of the source.

Question 4.
What are the two types of reflecting telescopes?
Answer:

  • The reflecting telescopes are mainly of two types: Newtonian and Cassegrain.
  • The newtonian telescope uses a plane mirror and a concave mirror.
  • The Cassegrain telescope uses a convex and a concave mirror.

Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space: Telescopes

Question 5.
What is the purpose of launching X-Ray telescope Chandra?
Answer:
Chandra was launched to study X-rays coming from heavenly objects. Special mirrors which . can reflect X-rays were used in this telescope.

Answer the following:

Question 1.
State some of the satellites and their uses.
Answer:

  • The INSAT and GSAT series of satellites support our telecommunication network, television broadcasting and meteorological services.
  • It is because of them that telephone, television and internet services are available everywhere in the country.
  • The EDUSAT satellite is used exclusively for education.
  • The IRS satellite series is used for the monitoring and management of natural resources as well as disaster management. Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space: Telescopes
  • Astrosat: It has ultraviolet and X-ray telescopes and detectors. It is a unique system having different kinds of telescopes on a single satellite.

Question 2.
What is the specialty of the artificial satellite Astrosat?
Answer:

  • This satellite was launched by Indian Space Research Organization (ISRO).
  • It has ultraviolet and X-ray telescopes and detectors. Most of the parts used in this satellite are made in India.
  • It is an unique system having different kinds of telescopes on a single satellite. Indian scientists are studying various aspects of the Universe using the data obtained with these telescopes.

Answer in detail:

Question 1.
Explain any two space observation telescope.
Answer:
Hubble Telescope:

  • In 1990, the National Aeronautics and Space Administration launched into space an optical telescope called the Hubble telescope.
  • It has a mirror of diameter 94 inches and is orbiting the earth at a height of 589 km from it.
  • This telescope is still working and has helped to make important discoveries.

Chandra Telescope:

  • In 1999, the National Aeronautics and Space Administration launched an X-ray telescope named Chandra, in space, to study X-rays coming from heavenly objects.
  • Special mirrors which can reflect X-rays were used in this telescope.
  • Chandra has given us very useful information about stars and galaxies.
  • The telescope is named after the famous Indian scientist Subramanian Chandrashekhar.

Question 2.
Write short note : GMRT
Answer:

  • Giant Meterwave Radio Telescope (GMRT) is a large radio telescope erected at Narayangaon near Pune.
  • It uses radio waves having wavelengths of about a metre, coming from heavenly bodies to study those bodies. This telescope is actually a collection of 30 dishes, each having a diameter of 45 m.
  • It is called a giant telescope as the arrangement of the 30 dishes over an area which measures up to 25 km across. It works as a single dish having a diameter of 25 km. Maharashtra Board Class 9 Science Solutions Chapter 18 Observing Space: Telescopes
  • GMRT gives the same data that we would have got from a telescope having a single dish of 25 km diameter.
  • Scientists study the solar system, solar winds, pulsars, supernova, interstellar hydrogen clouds, etc. with the help of the GMRT.

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Balbharti Maharashtra State Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Class 9 Science Chapter 17 Introduction to Biotechnology Textbook Questions and Answers

1. Each of the following statements is wrong. Rewrite them correctly by changing either one or two words.

a. Simple squamous epithelium is present in the respiratory tract.
b. Glandular epithelium is present in kidneys.
c. Chlorenchyma helps the plant to float in water.
d. Striated muscles are also called involuntary muscles.
e. Chloroplast is present in permanent tissue.
Answer:
a. False. Ciliated columnar epithelium is present in respiratory tract.
b. False. Cuboidal epithelium is present in kidneys.
c. False. Aerenchyma helps the plant to float in water.
d. False. Striated muscles are also called voluntary muscles.
e. False. Chlorenchyma is present in permanent tissue.

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

2. Identify the odd word and explain why it is odd.

a. Xylem, phloem, permanent tissue, meristematic tissue.
Answer:
Meristematic tissue. It has the ability to divide whereas the others have lost the ability to divide.

b. Epithelium, Muscle fibre, nerve fibre, the epidermis.
Answer:
Epidermis. It is a plant tissue whereas the others are animal tissues.

c. Cartilage, bone, tendon, cardiac muscle.
Answer:
Cardiac muscle. It is a muscular tissue whereas the others are connective tissues.

3. Write the names of the following tissues.

a. Tissue lining inner surface of mouth.
Answer:
Squamous epithelium.

b. Tissue joining muscles and bones.
Answer:
Tendon

c. Tissue responsible for increasing height of plants.
Answer:
Apical meristem.

d. Tissue responsible for increasing girth of stem.
Answer:
Lateral meristem.

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

4. Write the differences.
Simple tissue and complex tissues in plants.
Answer:

Simple Tissue in plants Complex Tissues in plants
(i) They are made up of only one type of cells. (i) They are made up of more than one type of cells.
(ii) They are found in all parts of the plant. (ii) They are found in the vascular regions of the plant.
(iii) They perform different functions like storage (iii) They mainly perform the function of
of food, support, giving strength etc. conduction of water and food.
(iv) Examples – Parenchyma, Collenchyma, Sclerenchyma. (iv) Example – Xylem and phloem.

5. Write short notes.

a. Meristematic tissue.
Answer:

  • Meristematic tissue is present in specific parts of a plant where growth takes place.
  • Cells of meristematic tissue contain thick cytoplasm, a conspicuous nucleus and a thin cell wall and are compactly packed together.
  • Vacuoles are usually absent in these cells and they are highly active.
  • The main function of meristematic tissue is to bring about plant growth.
  • According to the location, meristematic tissues are of three types: Apical meristem, intercalary meristem and lateral meristem.

b. Xylem
Answer:

  • Xylem is a complex permanent tissue in plants.
  • It consists of thick-walled dead cells.
  • The type of cells in xylem are trachieds, vessels, xylem fibres (dead cells) and xylem parenchyma (living cells).
  • Its structure is like interconnected tubes conduct water and minerals only in upward direction.

c. Striated muscles.
Answer:

  • The cells of striated muscles are long, cylindrical, multinucleate and have no branches.
  • These are alternate dark and light bands on these muscles.
  • As they are attached to bones, they are also called skeletal muscles.
  • They move as per our will, hence they are called voluntary muscles.
  • Striated muscles bring about movements of arms and legs, running, speaking etc.

d. Agro-complementary business.
Answer:
(i) The business that are complementary to agriculture and generate supplementary income for the farmers are called agro complementary business.

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

(ii) These include:

  • Animal Husbandry: It is practiced for milk production and for using the cattle as help in farming operations, e.g. cows and buffaloes are raised for milk whereas bulls and male buffaloes for pulling heavy loads.
  • Poultry farming: It is the rearing of egg and meat yielding chickens. Chickens raised for eggs are called layers while those raised for meat are called broilers.
  • Sericulture: It is the rearing of silkworms (moths) for silk production. The silk fibres obtained are processed, reeled and then woven into fabric.

e. Genetic engineering
Answer:

  • Genetic engineering is the deliberate modification of the characteristics of an organism by manipulating its genetic material.
  • An organism that is generated through genetic engineering is called a genetically modified organism (GMO).
  • Genetic engineering is applied in many fields like research, agriculture, industrial biotechnology and medicine.
  • In agriculture, genetic engineering is used in the production of cash crops, improvement in varieties of cash crops, increase in ability of plants to withstand environmental stresses.
  • In medicine, genetic engineering is used for vaccine production, early diagnosis of congenital disease, organ transplant, cancer research, production of artificial skin, cartilage etc. in laboratories.

f. Sericulture
Answer:

  • Sericulture is the rearing of silkworms (moths) for production of silk.
  • Bombyx mori is the most commonly used variety of silkworm for this purpose.
  • The life cycle of silkworm consist of four stages namely egg, larva, pupa and adult.
  • Thousands of eggs deposited by female moths are incubated artificially to shorten the incubation period.
  • Larvae hatching out of eggs are released on mulberry plants.
  • Larvae are nourished by feeding on mulberry leaves.
  • After feeding for 3-4 days, larvae move to branches of mulberry plant.
  • The silk thread is formed from the secretion of their salivary glands.
  • Larvae spin this thread around themselves to form a cocoon. The cocoon may be spherical in nature.
  • Ten days before the pupa turns into an adult, all the cocoons are transferred into boiling water.
  • Due to the boiling water, the pupa dies in the cocoon and silk fibres become loose.
  • These fibres are unwound, processed and reeled. Various kinds of fabric is woven from silk threads.

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

6. Explain the meaning of biotechnology and its impact on agricultural management with suitable examples.
Answer:
The techniques of bringing about improvements in living organisms by artificial genetic changes and by hybridization for the welfare of human beings, are together called biotechnology. Impact of biotechnology on agricultural management:

  • Genetically modified crops (GM crops) are being produced by introducing changes in DNA of natural crops.
  • Normally such varieties are not found in nature.
  • Thus, new varieties are produced artificially Different useful characters are introduced in such varieties.
  • Some naturally occurring varieties cannot withstand environmental stress like frequently changing temperature.
  • Wet and dry famines, changing climates etc. However, GM crops can grow in any of such adverse conditions.
  • As GM crops are resistant to insect pests, pathogens, chemical weedicides, etc. the use of harmful chemicals like pesticides can be avoided.
  • Due to use of seeds of GM crops, there is improvement in nutritive value and decrease in loss of crops.

Draw neat and labelled diagrams of the following:
Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology 2
Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology 3

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

7. Which two main techniques are used in biotechnology? Why?
Answer:

  • The two main techniques used in biotechnology are – Genetic engineering and tissue culture.
  • These techniques are used to bring about improvements in living organisms by artificial genetic changes and by hybridization for the welfare of human beings.
  • Its uses are in the production of cash crops, improvement in varieties of cash crops, early diagnosis of congenital diseases, organ transplant, cancer research, production of artificial skin, cartilage etc. in laboratories.

8. Discuss ‘Agritourism’ in the class and write a project on an agrotourism centre nearby. Present it in the class in groups.
Answer:

  • In agritourism, plantlets of flowering, medicinal, ornamental, vegetable plants and fruit trees are produced on a large scale by tissue culture technique.
  • By growing some of the plants fully, an agritourism centre can be developed.
  • If sufficient land is available, the emerging field of agritoursim would be a good business.
  • An agritourism centre consists of following:
    (a) Mango, chikoo (sapota), guava, coconut, custard apple and some other regional fruit trees.
    (b) Shade giving local or exotic attractive plants.
    (c) Ornamental and flowering plants.
    (d) Butterfly garden.
    (e) Medicinal plant garden.
    (f) Organic vegetables and fruits.
  • People visit places with such attraction in large numbers.
  • Selling plantlets/seedlings, fruits, vegetables at such places can be quite profitable.

9. Define the term tissue and explain the concept of tissue culture.
Answer:
A group of cells having the same origin, same structure and same function is called tissue. Concept of tissue culture:

  • Ex vivo growth of cells or tissues in an aseptic and nutrient-rich medium is called tissue culture.
  • Nowadays, a complete organism can be developed from a single cell or from tissue with the help of the tissue culture technique. Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology
  • A liquid, solid or gel-like medium prepared from agar, which supplies nutrients and energy necessary for tissue culture is used in this technique.
  • Tissue culture can be used to grow plants on a large scale, which bear flowers, fruits of excellent quality, in shorter durations and are disease free.
  • The various processes involved in tissue culture are:

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology 7

10. ‘Rearing of sheep is a livestock’. Justify this statement.
Answer:

  • The term livestock refers to animals reared for profit or for use.
  • Sheep provides us with wool, skin, meat and milk.
  • Therefore, rearing of sheep is a livestock.

Class 9 Science Chapter 17 Introduction to Biotechnology Intext Questions and Answers

Question 1.
Which components bring about important processes in the living organisms?
Answer:
Cells, tissues, organs, organ systems bring out important processes in living organisms.

Question 2.
Which is the smallest structural and functional unit of the body of living organisms?
Answer:
Cell is the smallest structural and functional unit of the body of living organisms.

Question 3.
Which type of muscle is the diaphragm of the respiratory system?
Answer:
Diaphragm is a skeletal muscle. It is an involuntary muscle that regulates breathing, although some voluntary control can be achieved.

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 4.
What is the main difference between the growth of animals and plants?
Answer:

  • Growth in animals is uniform whereas the growth in plants occurs in specific parts of the body.
  • Growth in animals occurs for a certain period of life whereas the growth in plants occur throughout their life.

Question 5.
Why does the growth of a plant occur only at specific parts of the plant body?
Answer:
Growth of a plant occurs only at specific parts of the body due to the presence of meristematic tissues which contain dividing cells.

Question 6.
Suppose you want to grow a garden like the one shown in the picture, around your home or school. What would you do to achieve that? By which methods will you cultivate the seedlings?
Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology 4
Answer:

  • To grow a garden around the school or home, one must cultivate seedlings of different plants and those seedlings must be watered regularly and nurtured properly.
  • Seedlings can be cultivated by the following methods:
    (a) Seed sowing: Seeds are sown, watered and allowed to germinate.
    (b) Transplantation: Seeds are sown somewhere else and then the seedlings are transplanted in the garden.

Question 7.
You must have seen flowers of same variety but of 2 or 3 different colours borne by same plant. How is this possible?
Answer:

  1. The different coloured flowers borne by the same plant are due to the pigments like anthocyanins, carotenoids etc. according to the genetic makeup of the plant.
  2. Also, by using the latest techniques of biotechnology and tissue culture, it is possible to manipulate the genes for flower colour and get the desired flower colour.

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 8.
What keeps the various organs and organ systems separate from each other? Why?
Answer:
The epithelial tissue keeps the various organs and organ systems separate from each other by forming a layer on the organs.

Question 9.
Why are epithelial tissues said to be simple tissues?
Answer:
Epithelial tissues are said to be simple tissues as they are made up of only one type of cells.

Question 10.
Why do slim persons feel more cold in winter than those who are obese?
Answer:

  • Below the skin, there is a tissue called adipose tissue.
  • The cells of these tissue are filled with fat droplets.
  • Due to storage of fat, it acts as an insulator and helps to retain heat in the body.
  • Obese people have more fat deposited in the adipose tissue as compared to slim persons. Therefore, slim persons feel more cold in winter than those who are obese.

Question 11.
Why can bones not be folded?
Answer:

  • Bone cells called osteocytes are embedded in solid ground substance made up of calcium phosphate.
  • This makes the bone hard, rigid and non- flexible. Therefore, bones cannot be folded.

Question 12.
Which other industries can be started as an extension of the plant nursery business?
Answer:
Businesses like Agritourism, Ecotourism, forest resorts and organic fruit gardens, yoga and meditation centres can be started as an extension of the plant nursery business.

Question 13.
To which places do people choose to go on vacation in order to relax when they are tired of crowds and stressful life?
Answer:
People choose to go to hill stations, beaches, forest resorts and places where there is lot of greenery to relax when they are tired of crowds and stressful life.

Question 14.
What is the inter-relationship between the two questions (7 and 8) above?
Answer:
The inter-relationship between the above two questions is that businesses like agritourism, ecotourism, forest resorts etc. can fetch a huge profit as people look for these kind of places to relax, to be away from the hustle and bustle of city life and feel close to nature.

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 15.
Why are the cocoons transferred to boiling water before the pupa develops into an adult?
Answer:

  • Once the pupa develops into an adult, it will secrete a fluid to dissolve the silk and emerge out.
  • Hence the cocoons are transferred to boiling water before the pupa develops in to an adult to kill the silkworms before transformation is complete.

Question 16.
Why we cannot see our organs like the heart, blood vessels and intestines?
Answer:
We cannot see our organs like the heart, blood vessels and intestines as they are located inside the body.

Question 17.
What is meant by white revolution? Who was its pioneer? What benefits did it bring?
Answer:

  • White revolution was the programme launched by the National Dairy Development Board to increase the milk production in India.
  • Dr. Verghese Kurien was the pioneer of white revolution.
  • It transformed India from a milk-deficient nation to the largest producer of milk. It also helped the dairy farmers in directing their own development and empowering them.

It also helped to reduce the malpractices carried out by milk traders and merchants.

Answer the following questions:

Question 1.
Collect information about GM varieties of crops in your area and make a note of them. Also find out if there are adverse effects of GM crops on human beings and environment.
Answer:

  • Some of the GM crops are:
    (a) Maize: MON 810, MON 863
    (b) Rice: Golden rice
    (c) Brinjal: BT brinjal
    (d) Cotton: BT cotton
  • Effects of GM Crops on human beings: GM crops may cause toxicity and allergic reactions in humAnswer:
  • Effects of GM Crops on environment:
    (a) GM crops may be toxic to pollinators and non-target species like butterflies.
    (b) Many GM crops may be a threat to soil ecosystem as they secrete their toxins into the soil.

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 2.
As shown in the figure, place an onion on each gas jar in such a way that its base (roots) will remain dipped in water. Measure and record the length of the roots of both onions on the first, second and third day. On the fourth day, cut off 1 cm of the roots of the onion in flask B Measure the length of the roots of both onions for the next five days and record your observations in the following table.
Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology 6

Length (cm) Day 1 Day 2 Day 3 Day 4 Day 5
Flask A
Flask B

Answer:
(Students are expected to record their observation in the given table).

(a) Which onion has longer roots? Why?
Answer:
The onion in jar Ahas longer roots as it continues to grow due to the presence of meristematic tissue at root tip which had dividing cells.

(b) Why did the roots of the onion in jar B stop growing?
Answer:
The roots of onion in jar B stopped growing as the meristematic tissue present in the root tips were cut off.

Question 3.
Take a fresh and fleshy leaf of Rhoeo, lily or any other plant. Pull and press it, tearing it obliquely in such a way that its transparent epidermis will be visible at the cut margins. Take the transparent epidermis with the forceps and keep it in dilute safranin solution for 1 minute. Spread it on a slide, cover it with a cover-slip and observe it under a compound microscope.
Answer:

  • The cells of the epidermis are flat and polygonal and there are no intercellular spaces between them.
  • A single continuous layer is formed.
  • The epidermis is covered by a waxy cuticle.

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 4.
Establish your own plant nursery near your school or home. Prepare the seedlings of flowering plants, fruit plants, and ornamental plants being grown in your area. Can you start a business in the future with the help of this activity? Think it over.
Answer:
(Students are expected to do this activity on their own.)

Yes, we can start a business of plant nursey in future. If sufficient land is available, the emerging field of agritourism would be a good business.

Question 5.
Observe the skin of the back of your hand with the help of a magnifying lens. Do you see the closely attached squarish and pentagonal shapes?
Answer:
Yes, we can see the squarish and pentagonal shapes. This is the stratified squamous epithelium present on the outer layer of skin.

Question 6.
Observe a permanent slide of blood smear under a compound microscope. What did you see?
Answer:

  • A permanent slide of blood smear under a compound microscope shows different types of cells like RBCs, WBCs and platelets.
  • The different types of WBCs that can be seen are eosin mphocytes.

Question 7.
Visit a modern cowshed nearby and record the following points – The number of cattle, their variety, total milk production, cleanliness in cattle-shed, arrangements for health care of cattle.
Answer:
Students are expected to do this activity on their own.

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 8.
Collect more information about animal husbandry.
Answer:

  • The branch of agriculture which deals with the feeding, shelter, health and breeding of domestic animals is called animal husbandry.
  • It is a scientific and systematic management of livestock.
  • Animal husbandry practices include:
    (a) Proper food and clean drinking water.
    (b) Proper shelter
    (c) Proper methods of breeding
    (d) Prevention and cure of disease.
  • Animal husbandary practices serve as an alternative income for the farmers and help to satisfy the need of food for man.

Question 9.
Find out from the internet the average daily milk yield from local and exotic varieties of cow.
Answer:

  • Milk yield from local cow : 12-15 litres/day.
  • Milk yield from exotic cow: 15-30 litres/day.

Question 10.
Are the structure and functions of the bodies of plants and animals the same?
No. The structure and functions of the bodies of plants and animals are not the same. Some differences between plants and animals:
Answer:

Plants Animals
Plants continue to grow throughout their life. Animals grow only for a specific period of life.
Growth in plants in not uniform. Growth in animals is uniform.
Plants have dividing and non-dividing tissues. Animals do not have different dividing and non­dividing tissues.
Plants are sedentary. Animals generally move from place to place in search of food, shelter and partners.
Energy needs of plants are less. Energy needs of animals are greater.
Plants can prepare their own food by photosynthesis. Animals cannot prepare their own food. They depend on plants and other animals for their food.

Class 9 Science Chapter 17 Introduction to Biotechnology Additional Important Questions and Answers

Choose and write the correct option:

Question 1.
Protective coverings in the animal body are called tissues.
(a) meristematic
(b) muscular
(c) epithelial
(d) bone
Answer:
(c) epithelial

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 2.
Epithelial tissue is present in
(a) skin
(b) inner surface of blood vessels
(c) walls of the alveoli
(d) all of these
Answer:
(d) all of these

Question 3.
helps in selective transport of substances.
(a) Squamous epithelium
(b) Stratified epithelium
(c) Cuboidal epithelium
(d) Columnar epithelium
Answer:
(a) Squamous epithelium

Question 4.
helps in secretion of digestive juice, absorption of nutrients.
(a) Glandular epithelium
(b) Columnar epithelium
(c) Cuboidal epithelium
(d) Ciliated epithelium
Answer:
(b) Columnar epithelium

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 5.
supports internal organs
(a) Areolar tissue
(b) Adipose tissue
(c) Lymph
(d) Tendon
Answer:
(a) Areolar tissue

Question 6.
tissue helps in insulation, supply of
Answer:
(b) Adipose tissue

Question 7.
connect muscles to bones.
(a) Ligaments
(b) Tendons
(c) Cartilages
(d) Nerves
Answer:
(b) Tendons

Question 8.
join two bones to each other.
(a) Cartilages
(b) Tendons
(c) Ligaments
(d) Muscles
Answer:
(c) Ligaments

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 9.
meristem increases the length of root and stem.
(a) Intercalary
(b) Apical
(c) Lateral
(d) Permanent
Answer:
(b) Apical

Question 10.
showed that cells and tissues can be grown ex vivo.
(a) Frederick Campion Steward
(b) Gregor Johann Mendel
(c) Frederick Miescher
(d) Robert Brown
Answer:
(a) Frederick Campion Steward

Question 11.
is an example of genetically modified maize.
(a) Vaishali
(b) Vistive Gold
(c) MON 810
(d) Amflora
Answer:
(c) MON 810

Question 12.
is an exotic variety of cow.
(a) Holstein
(b) Gir
(c) Sahiwal
(d) Dangi
Answer:
(a) Holstein

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 13.
is a layer chicken.
(a) Brahma
(b) Leghorn
(c) Cochin
(d) Aseel
Answer:
(b) Leghorn

Question 14.
is a broiler chicken.
(a) Leghorn
(b) Lehman
(c) Aseel
(d) Minorca
Answer:
(c) Aseel

Question 15.
is a broiler chicken.
(a) Minroca
(b) Ancona
(c) Leghorn
(d) Cochin
Answer:
(d) Cochin

Question 16.
Cartilage is found
(a) all around the cells in body
(b) in nose, ear, larynx, trachea
(c) between the muscles and skin
(d) around the blood vessels
Answer:
(b) in nose, ear, larynx, trachea

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 17.
Which of the following is an exotic variety of COW?
(a) Plymouth Rock
(b) New Hampshire
(c) Black Rock
(d) Brown Swiss
Answer:
(d) Brown Swiss

Question 18.
epithelium is present in the inner surface of respiratory tract.
(a) Stratified
(b) Columnar
(c) Ciliated
(d) Cuboidal
Answer:
(c) Ciliated

Question 19.
Bones consist of osteocytes embedded in solid ground substance made up of
(a) calcium bicarbonate
(b) calcium carbonate
(c) calcium phosphate
(d) calcium sulphate
Answer:
(c) calcium phosphate

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 20.
helps in growth of branches, formation of leaves and flowers.
(a) Lateral meristem
(b) Apical meristem
(c) Intercalary meristem
(d) Xylem
Answer:
(c) Intercalary meristem

Question 21.
tissue is present in the hard coat of seeds, outer covering of coconut.
(a) Parenchyma
(b) Xylem
(c) Collenchyma
(d) Sclerenchyma
Answer:
(d) Sclerenchyma

Question 22.
The cells of tissue are dead.
(a) Parenchyma
(b) Collenchyma
(c) Sclerenchyma
(d) All of these
Answer:
(c) Sclerenchyma

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 23.
Cuboidal epithelium is found in
(a) inner surface of mouth, blood vessels
(b) inner layer of skin
(c) tubules of kidney, salivary gland
(d) inner surface of respiratory tract
Answer:
(c) tubules of kidney, salivary gland

Find the odd man out:

Question 1.
Cell body, muscle fibre, axon, dendrites.
Answer:
Muscle fibre. It is a muscle cell whereas the others are parts of nerve cell.

Question 2.
Tracheids, vessels, companion cells, xylem fibres.
Answer:
Companion cells. It is an element of phloem whereas the others are elements of xylem.

Question 3.
Sieve tubes, tracheids, phloem parenchyma, phloem fibres.
Answer:
Tracheids. It is an element of xylem whereas the others are elements of phloem.

Question 4.
Holstein, Brown swiss, Bombyx mori, Jersey.
Answer:
Bombyx mori. It is a variety of silkworm whereas the others are varieties of cows.

Complete the analogy:

(1) Inner surface of mouth : Squamous epithelium :: Inner surface of intestine :
(2) Glandular epithelium : Secretion of sweat, oil :: Cuboidal epithelium:
(3) Respiratory tract: Ciliated columnar epithelium :: Kidney tubules:
(4) Outer layer of skin : Stratified epithelium :: Inner layer of skin :
(5) Muscular tissue : Movement :: Nervous tissue :
(6) Tendons : Join muscles to bones :: Ligaments :
Answer:
(1) Columnar epithelium
(2) Secretion of saliva
(3) Cuboidal epithelium
(4) Glandular epithelium
(5) Conduction of excitation
(6) Join two bones to each other

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Match the columns:

Question 1.

Column ‘A’ Column ‘B’
(1) Squamous epithelium (a) Secretion of digestive juice
(2) Cuboidal epithelium (b) Selective transport of substances
(3) Columnar epithelium (c) Protection of organs
(4) Stratified epithelium (d) Secretion of saliva

Answer:
(1 – b),
(2 – d),
(3 – a),
(4 – c)

Question 2.

Column ‘A’ Column ‘B’
(1) Brahma (a) Local variety of cow
(2) Jersey (b) Layer chicken
(3) Devin (c) Exotic variety of cow
(4) Lehman (d) Broiler chicken

Answer:
(1 – d),
(2 – C),
(3 – a),
(4 – h)

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 3.

Column ‘A’ Column ‘B’
(1) Potato (a) Vistive Gold
(2) Maize (b) Amflora
(3) Soybean (c) Vaishali
(4) Tomato (d) MON 863

Answer:
(1-b),
(2-d),
(3-a),
(4-c)

Answer the following:

Question 1.
Explain the different types of muscular tissues.
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology 5

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 2.
Explain the types of complex permanent tissues.
Answer:

Name of tissue Xylem Phloem
Characteristics Consists of thick-walled dead cells Consists of cytoplasm containing living cells.
Types of cells Tracheids, vessels and xylem fibres – dead cells. Xylem parenchyma – living cells. Sieve tubes, companion cells, phloem parenchyma – living cells. Phloem fibres – dead cells.
Function A structure like interconnected tubes, conduct water and minerals only in upward direction. Tubes joined to each other, conduct sugar and amino acids from leaves to various parts in upward and downward direction

State whether the following statements are true or false. Correct the false statement:

Question 1.
Lateral meristem increase girth(diameter) of the root and stem.
Answer:
True

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 2.
Due to use of seeds of GM crops, there is decrease in nutritive value and increase in loss of crops.
Answer:
False. Due to use of seeds of GM crops there is improvement in nutritive value and decrease in loss of crops.

Question 3.
In a bioreactor, cells can be grown in a more nutritive medium and protected from pathogens.
Answer:
True

Question 4.
Rare and endangered plants can be grown by tissue culture and can be protected from extinction.
Answer:
True

Question 5.
The silk thread is formed from the secretion of the sweat glands of silkworm.
Answer:
False. The silk thread is formed from the secretion of the salivary glands of silkworm.

Question 6.
Rhode Island Red, New Hampshire, Plymouth Rock, Black Rock are varieties of chicken reared for both eggs as well as meat.
Answer:
True

Question 7.
Phloem consists of thick-walled dead cells.
Answer:
False. Phloem consists of living cells containing cytoplasm.

Question 8.
Stratified squamous epithelium is present in inner surface of mouth, oesophagus, blood vessels and alveoli.
Answer:
False. Stratified squamous epithelium is present in the outer layer of skin.

Question 9.
Broiler chickens are raised for eggs.
Answer:
False. Broiler chickens are raised for meat.

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 10.
Non-striated muscles bring about contraction and relaxation of heart.
Answer:
False. Cardiac muscles bring about contraction and relaxation of heart.

Name the following:

Question 1.
Tissue responsible for growth of branches, formation of leaves and flowers.
Answer:
Intercalary meristem.

Question 2.
Tissue that helps in insulation, supply of energy, storage of fats.
Answer:
Adipose tissue.

Question 3.
Tissue present in outer layer of skin.
Answer:
Glandular epithelium.

Question 4.
Tissue present in nose, ear, larynx, trachea.
Answer:
Cartilage.

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 5.
Dead cells in xylem.
Answer:
Tracheids, vessels and xylem fibres.

Question 6.
Living cells in xylem.
Answer:
Xylem parenchyma.

Question 7.
Living cells in phloem.
Answer:
Sieve tubes, companion cells, phloem parenchyma.

Question 8.
Dead cells in phloem.
Answer:
Phloem fibres.

Question 9.
GM crops.
Answer:
BT cotton, Amflora, Golden Rice.

Question 10.
Local Indian varieties of cow.
Answer:
Sahiwal, Sindhi, Lai kandhari, Devni, Khillari, Dangi.

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 11.
Exotic varieties of cow.
Answer:
Jersey, Brown swiss, Holstein.

Question 12.
Layers.
Answer:
Leghorn, Minorca, Ancona, Lehman.

Question 13.
Broilers.
Answer:
Brahma, Long, Cochin, Aseel.

Question 14.
Chickens reared for both eggs and meat.
Answer:
Rhode Island Red, New Hampshire, Plymouth Rock, Black Rock.

Give scientific reason.

Question 1.
Blood is a complex tissue.
Answer:

  • A complex tissue is made up of more than one type of cells.
  • In blood, cells of different types, colour and shapes are mixed together.
  • Blood contains erythrocytes (RBCs), leucocytes (WBCs) and platelets in a liquid plasma.
  • Therefore, blood is a complex tissue.

Define the following:

Question 1.
Tissue
Answer:
A group of cells having the same origin, same structure and same function is called tissue.

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 2.
Differentiation
Answer:
When cells acquire a specific structure, shape and location and perform a specific function, it is called differentiation.

Question 3.
Biotechnology
Answer:
The techniques of bringing about improvements in living organisms by artificial genetic changes and by hybridization for the welfare of human beings, are together called ‘Biotechnology’.

Question 4.
Tissue culture
Answer:
Ex vivo growth of cells or tissues in an aseptic and nutrient-rich medium’ is called tissue culture.

Write short notes

Question 1.
Animal husbandry
Answer:

  • In India, animal husbandry is practised for milk production and for using the cattle as help in farming operations.
  • Example – Cows and buffaloes are raised for milk and bulls and male buffaloes for pulling the heavy loads.
  • Local Indian varieties of cows like Sahiwal, Sindhi, Gir, Lai kandhari, Devni, Khillari, Dangi, etc. and exotic varieties like Jersey, Brown swiss, Holstein, etc. are kept for their milk.
  • Proper care of cattle is necessary for a clean and high yield of milk which includes:
    (a) A balanced diet, i.e. all constituents of food should be given to cattle. It must include fibre- rich coarse food, fodder, and sufficient water.
    (b) The cattle-shed should be clean and dry with proper ventilation and a roof.
    (c) Cattle should be regularly vaccinated.

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 2.
Poultry farming.
Answer:

  • Rearing of egg and meat yielding chickens is called poultry farming.
  • Chickens raised for laying eggs are called layers . e.g. Leghorn, Minorca, Ancona, Lehman.
  • Chickens raised for meat are called broilers, e.g. Brahma, Long, Cochin, Aseel.
  • Rhode Island Red, New Hampshire, Plymouth Rock, Black Rock are varieties of chicken reared for both eggs as well as meat.
  • The objectives behind development of new hybrid varieties from a cross between Indian varieties like Aseel and exotic varieties like Leghorn are to produce good quality chickens in large numbers.
  • To develop the ability to withstand high temperature, to use by-products of agriculture as poultry feed, etc.

Distinguish between:

Question 1.
Xylem and Phloem
Answer:

Xylem Phloem
(i) Consists of mostly thick-walled dead cells. (i) Consists of mostly living cells containing cytoplasm.
(ii) The types of cells include dead cells- tracheids, vessels and xylem fibres and living cells-Xylem parenchyma. (ii) The types of cells include living cells – Sieve tubes, companion cells, phloem parenchyma and dead cells – phloem fibres.
(iii) Structure like interconnected tubes, conduct water and minerals only in upward direction. (iii) Tubes joined to each other, conduct sugar and amino acids from leaves to various parts in both upward and downward direction.

Question 2.
Striated muscles and Non-striated muscles.
Answer:

Striated muscles Non-striated muscles
(i) Muscle cells are long, cylindrical, multinucleate and have no branches. (i) Muscle cells are short, spindle-shaped, uninucleate and have no branches.
(ii) There are alternate dark and light bands on these muscles and they are attached to bones. (ii) Dark and light bands are absent. Not attached to bones.
(iii) They move as per our will, hence they are called voluntary muscles. (iii) They are not under the control of our will, hence they are called involuntary muscles.
(iv) These muscles bring about movements of arms and legs, running, speaking etc. (iv) These muscles bring about movement of eyelids, passage of food through alimentary canal, contraction and relaxation of blood vessels etc.

Question 3.
Cartilage and Bone
Answer:

Cartilage Bone
(i) They are present in nose, ear, larynx, trachea. (i) They form the skeleton of the body.
(ii) They contain cells supported by fibrous, flexible, jelly-like ground substance. (ii) They contain osteocytes embedded in solid ground substance made up of calcium phosphate.
(iii) Lubricates the surface of bones, gives support and shape to organs. (iii) Supports and protects different organs, helps in movement.

Answer the following questions:

Question 1.
Close your eyes and try to identify different objects by feeling them with your hand. Why is it possible for you to identify things like a note-book, text-book, bench, compass-box, etc. only by touching them?
Answer:

  • We can identify objects just by touching them because of the memory that we retain in our brain.
  • The nervous tissue enables us to respond to the stimuli of touch.

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Answer in detail:

Question 1.
Write the location, structure and function of following epithelial tissues:
(a) Squamous epithelium
(b) Stratified epithelium
(c) Glandular epithelium
(d) Columnar epithelium
(e) Ciliated epithelium
(f) Cuboidal epithelium
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology 8

Question 2.
Write the structure and function of the following connective tissues:
(a) Blood
(b) Lymph
(c) Areolar tissue
(d) Adipose tissue
(e) Cartilage
(f) Bones
(g) Tendons and ligaments
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology 9

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 2.
Describe the structure of nervous tissue with the help of a neat labelled diagram.
Answer:

  • Nervous tissue enables us to respond to stimuli like touch, sound, odour, colour, etc.
  • Cells of the nervous tissue are specifically made to become excited and conduct the excitation from one part of the body to another.
  • The main part of the nerve cell is the cell body which contains the cytoplasm and the nucleus.
  • Numerous, small, branched fibres called dendrites arise from the cell body.
  • One of the fibres, is extremely long and is called
    the axon.
  • The length of the nerve cell may be up to one metre.
  • Many nerve cells are bound together with the help of connective tissue to form a nerve.
  • Nervous tissue is present in the brain, spinal cord and the network of nerves spread all throughout the body.
  • In most animals, action in response to a stimulus occurs due to the integrated functioning of the nervous tissue and muscular tissue.
    Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology 1

Question 3.
Explain the types of simple permanent tissues in plants.
Answer:
Types of simple permanent tissues.

Question 4.
Explain types, location and function of Meristematic tissue in tabular form:
Answer:

Types Apical Intercalary Lateral
Location At tip of the root and stem At the base of the petiole of leaves and branches At sides of root and stem
Function Increase the length of the root and stem Growth of branches, the formation of leaves and flowers Increases diameter of the root and stem

Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology

Question 5.
Explain the types of simple permanent tissues in plants.
Answer:
Types of simple permanent tissues.

Name of Tissue Parenchyma Collenchyma Sclerenchyma
Struc­ture of cells Living cells with thin cell wall and intercellular spaces. Elongated living cells with thickened cell wall at corners due to cellulose and pectin. Dead and fibrous cells with tapering ends, cell wall contains lignin.
Loca­tion All parts like roots, stem, leaves, flowers and seeds. At the base of leaf petiole, branches and stem Stem, veins of leaves, hard coats of seeds, outer covering of coconut.
Func­tions Support, storage of food and filling vacant spaces. Support and flexibility to various parts. Give strength and rigidity to parts of the plants.
Sub­ types Chlorenchyma: Leaves, perform photosynthesis. Aerenchyma: Helps aquatic plants, leaves and stem to float.

Question 6.
Write down the applications of biotechnology (tissue culture) in floriculture, nurseries and forestry.
Answer:
Applications of biotechnology (tissue culture) in floriculture, nurseries and foresty:

  • Tissue culture can be used to grow those plants on a large scale which bear flowers, fruits of excellent quality.
  • Fully grown plants can be produced in shorter durations.
  • Plants can be grown on a large scale even if means of pollination or germinating seeds are not available.
  • For example, orchids or pitcher plants do not germinate but these plants can easily be produced by means of tissue culture.
  • In a bioreactor, cells can be grown in a more nutritive medium and protected from pathogens.
  • Bioreactors are useful for producing plantlets on a very large scale.
  • A large number of seedlings/plantlets can be produced in a short time using minimum resources and materials.
  • Usually, plants produced by tissue culture and genetic modification techniques are disease-free.
  • Plantlets produced by tissue culture technique of the meristem are virus-free.
  • Embryos produced using conventional hybridization technique between two or more varieties may not grow fully for some reasons. Maharashtra Board Class 9 Science Solutions Chapter 17 Introduction to Biotechnology
  • However, embryos produced by tissue culture technique always complete their growth.
  • Rare and endangered plants can be grown using tissue culture technique and can thus be protected from extinction.
  • Similarly, various parts and seeds of such plants can be preserved by tissue culture and those varieties can be protected.

Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use

Balbharti Maharashtra State Board Class 9 Science Solutions Chapter 14 Substances in Common Use Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 9 Science Solutions Chapter 14 Substances in Common Use

Class 9 Science Chapter 14 Substances in Common Use Textbook Questions and Answers

1. Fill in the blanks.

a. The number of molecules of water of crystallization in washing soda is …………….…. .
b. The chemical name of baking soda is …………….…. .
c. …………….…. is used in treatment of hyperthyroidism.
d. The chemical name of Teflon is …………….…. .
Answer:
a. 10
b. Sodium bicarbonate
c. Iodine -123
d. Polytetra fluoroethylene (C2F4)n

Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use

2. Match the pairs

Group A  Group B
1. Saturated brine  a. sodium metal freed
2. Fused salt  b. basic salt
3. CaOCl2  c. crystallization of salt
4. NaHCO3  d. oxidation of colour

Answer:
(1 – c),
(2 – a),
(3 – d),
(4 – b)

3. Write answers to the following

a. What is meant by radioactivity?
Answer:

  • Elements with a high atomic number such as uranium, thorium, radium have a property of spontaneously emitting invisible, highly penetrating and high energy radiation.
  • This property is called radioactivity.
  • A substance having this property is called a radioactive substance.

b. When is said to be the nucleus unstable?
Answer:

  • It is the balance of protons and neutrons in a nucleus which determines whether a nucleus will be stable or unstable.
  • Too many neutrons or protons upset this balance disrupting the binding energy from the strong nuclear forces making the nucleus unstable.

c. Which diseases are caused by artificial food colours?
Answer:
Diseases like ADHD (Attention Deficit Hyperactivity Disorder) can affect children due to excessive consumption of foods with added food colours.

d. Where in the industrial field is radioactivity used?
Answer:
Industrial field Radiography

  • Internal cracks and voids in cast iron articles and iron solder can be detected with the help of gamma rays.
  • For this purpose, isotopes like cobalt-60, iridium-192 are used in the radiography camera.
  • This technique is used for detecting flaws in metal work.

Measurement of thickness, density and level

  • It is necessary to maintain the required thickness in the manufacture of aluminium, plastic, iron sheets of differing thickness.
  • In the manufacturing process, a radioactive substance is placed on one side and an instrument to measure radiation on the other.
  • The radiation read by the measuring instrument varies with the thickness of the sheet.
  • Material inside a packing can also be examined by the same technique.

Luminescent paint and radio luminescence:

  • The radioactive substances radium, promethium, tritium with some phosphor are used to make certain objects visible in the dark, for example, the hands of a clock, and certain other objects.
  • Krypton-85 is used in HID (High-Intensity Discharge) lamps while promethium – 147 is used in portable X-ray units as the source of beta rays.

Use in Ceramic articles:

  • Luminous colours are used to decorate ceramic tiles, utensils, plates, etc.
  • Earlier uranium oxide was used in these paints.

e. Write down properties of teflon.
Answer:
Properties of teflon :

  • The atmosphere and chemical substances have no effect on Teflon.
  • Neither water nor oil will stick to Teflon coated articles.
  • High temperatures do not affect Teflon as its melting point is 327 °C.
  • Teflon coated articles are easy to clean.

f. What type of colours will you use to celebrate ecofriendly Rang Panchami? Why?
Answer:

  • We regularly use artificial colours on Rang Panchami.
  • The red colour used on Rang Panchami is very dangerous. It contains a high proportion of mercury in it.
  • This poses risks like blindness, skin cancer, asthma, itching of the skin, permanent blocking of sweat pores, etc.
  • Therefore, it is necessary to use eco-friendly colours.
  • We will prepare colours for Rang Panchami from natural resources such as beet root, flowers of flame of forest, spinach, flame tree (gulmohar) and protect your health by using these.

g. Why has the use of methods like Teflon coating become more common?
Answer:
The use of methods like Teflon coating became more common because of following properties of teflon:

  • The atmosphere, rain water and chemical substances have no effect on Teflon.
  • Neither water nor oil will stick to Teflon coated articles.
  • High temperatures do not affect Teflon as its melting point is 327 °C.
  • Teflon coated articles are easy to clean.
  • Teflon is a poor conductor of electricity.

4. Give a scientific explanation

a. Bleaching powder has the odour of chlorine.
Answer:

  • Bleaching powder undergoes slow decomposition due to the carbon dioxide in air and chlorine gas is released.
  • Bleaching powder gets its property because of this release of chorine gas.
    Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 7

b. The hard water of a well becomes soft on adding washing soda to it.
Answer:

  • The hard water from a well or a bore-well becomes soft on adding washing soda and we come to know this from the lather formed on it.
  • The hardness of water is due to the presence of chlorides and sulphates of calcium and magnesium in it.
  • Na2CO3 is added to it to soften such water and make it suitable for use.
  • The reaction with Na2CO3 causes the formation of insoluble carbonate salts of magnesium and calcium.
    MgCl2(aq) + Na2CO3(s) → MgCO3(s) + 2 NaCl(s)

c. Soap forms a precipitate in hard water.
Answer:

  • When soap is mixed with hard water, calcium and magnesium salts of fatty acids are formed.
  • These being water insoluble, they form a precipitate and that is why lather is not formed.

d. The particles of powder are given an electric charge while spraying them to form the powder coating.
Answer:

  • Powder coating is a method of applying a layer harder than paint on the surface of an iron object to prevent rusting.
  • In this method, a polymer resin, a pigment and some other ingredients are melt, mixed, cooled and ground into a uniform powder.
  • This powder is sprayed on the polished metal surface by electrostatic spray deposition (ESD).
  • In this method, the particles of the powder are given an electrostatic charge due to which a uniform layer of the powder sticks to the metal surface.
  • Then the object is heated in the oven along with the coating.
  • A chemical reaction occurs in the layer, resulting in the formation of long cross-linked polymeric chains.

e. The aluminium article is used as an anode in the anodising process.
Answer:

  • A protective layer is formed naturally on the surface of aluminium metal by reaction with oxygen in air.
  • In the anodizing process, this layer is made of the desired thickness. Anodizing is done by electrolysis.
  • Dilute Sulphuric acid is taken in the electrolytic cell and the aluminium article is dipped in it as the anode.
  • When an electric current is passed, hydrogen gas is released at the cathode and oxygen gas at the anode.
  • A reaction with oxygen occurs and a layer of hydrated aluminium oxide is formed on the anode. Therefore, aluminium article is used as an anode in the anodizing process.

f. When the radiation coming out from certain radioactive substance is passed through an electric field, marks are found at three places on the photographic plate placed in its path.
Answer:
(i) When the radiation coming out from certain radioactive substance is passed through an electric field, marks are found at three places on the photographic plate placed in its path. This is because the radiation coming out from radioactive substance are of three types Alpha rays, Beta rays and Gamma rays.

(ii) The rays which get deviated slightly towards negatively charged plate are called alpha rays. They get deviated towards negatively charged plate because they are made of positively charged particles, called as alpha particles (He++).

(iii) The rays which get deviated substantially towards the positively charged plate are called beta rays. They get deviated towards a positively charged plate because they are made of negatively charged particles called as beta particles (e-).

(iv) The rays which do not deviate at all are called gamma rays. They are uncharged electromagnetic radiation. Hence, marks are found at three places on the photographic plate. (For diagram refer Fig. 14 .2 from Q. 4(3))

g. A certain type of ceramic tiles are fixed on the outer layer of a space shuttle.
Answer:
(i) Each shuttle is covered by more than 24,000 of the six- by six-inch advance ceramic tiles. This tiles withstand high temperatures without decomposing. They are brittle, water-resistant and electrical insulator. Most of the tiles are made of silica fibres, which are produced from high-grade sand (SiO2).

(ii) Silica is an excellent insulator because it transports heat slowly. When the outer portion of a tile gets hot, the heat takes a long time to work its way down through the rest of the tile to the shuttle’s skin. The tiles keep the orbiter’s aluminium skin at 350 degrees or less.

(iii) The silica fibers are mixed with water and chemicals, and the mixture is poured into molds, which are zapped in microwave ovens at 2,350°C to fuse the silica fibres. Tiles are too brittle to attach to the orbiter directly.

(iv) The shuttle’s skin contracts slightly while in orbit, then expands during re-entry.

(v) In addition, the stresses of launch and re-entry cause the skin to flex and bend. Such motions could easily crack the tiles or shake them off. To keep them in place, workers glue the tiles to flexible felt-like pads, then glue the pads to the orbiter.

5. Write answers to the following

a. Write about artificial food colours, the substances used in them and their harmful effects.
Answer:
(a) Artificial food colour and substances in them.

  • Food colours are mixed in most soft drinks and foodstuffs available in the market.
  • These food colours are in the form of powders, gels and pastes.
  • Food colours are used in domestic as well as commercial products.
  • Certain colours and essences are added to ice cream, ice candies, sauce, fruit juices, cold drinks, pickles, jams and jelly.
  • Food colours are often found to be added to packaged meat (chicken, mutton), chilli powder, turmeric, sweets and other similar substances so as to give them a good colour.
  • Tetrazene, sunset yellow are artificial food colours used extensively.

(b) Harmful effects of artificial food colours

  1. Food colours added to pickles, jam and sauce contain small quantities of lead and mercury. These can be harmful for those who consume these products on a regular basis.
  2. Diseases like ADHD (Attention Deficit Hyperactivity Disorder) can affect children due to excessive consumption of foods with added food colours.

b. What is meant by water of crystallization? Give examples of salts with water of crystallization, and their uses.
Answer:
The exact number of water molecules which are chemically bonded to a molecule of a salt within a hydrated crystalline compound is called as water of crystallization are:

Some substances in our daily use which contain water of crystallization are:

  • Alum (Potash alum – K2SO4.Al2(SO4)3.24H2O)
  • Borax (Na2B4O7.10H2O)
  • Epsom salt (Magnesium sulphate MgSO4.7H2O)
  • Barium chloride (BaCl2.2H2O)
  • Sodium sulphate (Glauber’s salt Na2SO4.10 H2O)
  • Blue vitriol (Copper Sulphate – CuSO4.5H2O)

Uses of these salts are as given below:
(i) Alum (Potash alum – K2SO4.Al2(SO4)3.24H2O)

  • Alum is used in the process of water purification.
  • Because of the property of coagulation, the solid impurities in water come together, become heavy and settle to the bottom. As a result, the impure water or muddy above becomes clear.
  • Alum powder, found in the spice section of many grocery stores, may be used in pickling recipes as a preservative to maintain fruit and vegetable crispness.
  • Alum is used as the acidic component of some commercial baking powders.
  • Alum has been used as an after shave treatment.

(ii) Borax (Na2B4O7.10H2O)

  • Borax today is used for many cleaning purposes.
  • It is used to make homemade laundry detergent.
  • It is added as a cleaning boost to any other detergent.
  • It even keeps ants and other pests away.

(iii) Epsom salt (Magnesium sulphate MgSO4.7H2O)

  • Epsom salt is used as a relaxing magnesium bath soak.
  • To grow better vegetables – Add a tablespoon of Epsom salt to the soil below a vegetable plant to boost growth.

(iv) Barium chloride (BaCl2.2H2O)

  • In industry, Barium chloride is mainly used in the purification of brine solution in caustic chlorine plants.
  • It is also used in the manufacture of heat treatment salts.
  • It is used in hardening of steel.
  • It is used in the manufacture of pigments.

(v) Sodium sulphate (Glauber’s salt Na2SO4.10H2O)

  • In the laboratory, anhydrous Sodium sulphate is widely used as an inert drying agent, for removing traces of water from organic solutions.
  • Glauber’s salt, the decahydrate, is used as a laxative.

(vi) Blue vitriol (Copper sulphate CuSO4.5H2O)

  • Blue vitriol is used in the blood test for diagnosing anaemia.
  • Slaked Time is used with blue vitriol in the Bordeaux mixture which is used as a fungicide on fruits like grapes and musk melon.

c. Write briefly about the three methods of electrolysis of sodium chloride.
Answer:

  • When an electric current is passed through a saturated solution of sodium chloride (brine) it is electrolysed and hydrogen gas is released at the cathode while chlorine gas is released at the anode.
  • This method is used for production of chlorine gas. In this method an important basic compound NaOH is formed in the cell.
  • Chemical reaction
    2NaCl + 2H2O → 2NaOH + Cl2 ↑ + H2
  • When salt is heated to a high temperature (about 800 °C), it melts. This is called the fused state of the salt.

6. Write the uses.

a. Anodizing
b. Powder coating
c. Radioactive substances
d. Ceramic
Answer:
(a) Anodizing : Anodizing is done on aluminum cooking utensils like griddles and cookers.

(b) Powder coating : Powder coating is done on iron objects to prevent rusting. Also, on Plastic and Medium density fibre (MDF) board, to make them highly durable, hard and attractive.

(c) Radioactive substances:
(I) Industrial field:
(i) Industrial Radiography : Internal cracks and voids in cast iron articles and iron solder can be. detected with the help of gamma rays. For this purpose, isotopes like cobalt-60, iridium-192 are used in the radiography camera. This technique is used for detecting flaws in metal work.

(ii) Measurement of thickness, density and level: It is necessary to maintain the required thickness in the manufacture of aluminium, plastic, iron sheets of differing thickness. In the manufacturing process, a radioactive substance is placed on one side and an instrument to measure radiation on the other. The radiation read by the measuring instrument varies with the thickness of the sheet. Material inside a packing can also be examined by the same technique.

(iii) Luminescent paint and radioluminescence:
The radioactive substances radium, promethium, tritium with some phosphor are used to make certain objects visible in the dark, for example, the hands of a clock, and certain other objects. Krypton-85 is used in HID (High Intensity Discharge) lamps while promethium-147 is used in portable X-ray units as the source of beta rays.

Use in Ceramic articles – Luminous colours are used to decorate ceramic tiles, utensils, plates, etc. Earlier uranium oxide was used in these paints.

(II) Field of agriculture :

  • The genes and chromosomes that give seeds properties like fast growth, higher productivity, etc. can be modified by means of radiation.
  • The radioactive isotope cobalt-60 is used for food preservation.
  • Onions, potatoes are irradiated with gamma rays from cobalt-60 to prevent their sprouting.
  • Strontium-90 is used as a tracer in the research on various crops.

(III) Medical science:

  • Polycythemia : The red blood cell count increases in the disease polycythemia. Phosphorus- 32 is used in its treatment.
  • Bone cancer : Strontium-89, strontium-90, samarium-153 and radium-223 are used in the treatment of bone cancer.
  • Hyperthyroidism : Enlargement of thyroid gland, weight loss in spite of appetite, insomnia are the symptoms of hyperthyroidism.
  • It occurs due to overproduction of hormones by the thyroid gland. Iodine-123 is used in the treatment of hyperthyroidism.
  • Tumour detection : Boron-10, iodine-131, cobalt-60 are used in treatment of brain tumour, while arsenic-74 is used in detection of small tumours in the body.

(d) Ceramic : Pots made by a potter, Mangalore roofing tiles, construction bricks, pottery, terracotta articles are some examples of common ceramic articles that we see around.

7. Write the harmful effects

a. Artificial dye
b. Artificial food colour
c. Radioactive substances
d. Deodorant
Answer:
(a) Artificial dye:

  • Dyeing hair can have adverse effects like hair fall, damage to hair texture, burning of skin, adverse effect on eyes, etc.
  • Lipstick contains a dye named carmine. It does not affect lips but causes stomach disorders.
  • Excessive use of plants for making natural dyes results in deterioration of the environment.

(b) Artificial food colour:

  • Food colours added to pickles, jams and sauces contain small quantities of lead and mercury. These can be harmful for those who consume these products on a regular basis.
  • Diseases like ADHD (Attention Deficit Hyperactivity Disorder) can affect children due to excessive consumption of foods with added food colours.

(c) Radioactive substances :

  • The central nervous system is affected by radioactive radiations.
  • Hereditary defects are generated by bombardment of radiation on D.N.A in the body.
  • Radioactive radiation can penetrate the skin, and causes diseases like skin cancer, leukemia.
  • The radioactive pollutants created due to explosions enter the body through air and it is difficult to control them.
  • The radioactive pollutants released in the sea enter the bodies of fishes and through them enter the human body.
  • The radioactive paint on the watch can cause cancer.
  • The radioactive isotopes strontium-90 can enter the body through plants, fruits, flowers, cereals, milk, etc. and cause diseases like bone cancer, leukemia.

(d) Deodorant:

  • Aluminium – Zirconium compounds are the most harmful chemicals in the deodorant. Disorders like headache, asthma, respiratory disorders, heart disease are likely to occur without our knowledge.
  • There is a possibility of various skin disorders and also skin cancer due to the aluminium chlorohydrates.

8. Write the chemical formula Bleaching powder, common salt, baking soda, washing soda
Answer:

Common name Chemical name
Bleaching powder CaOCl2
Common salt NaCl
Baking soda NaHCOs
Washing soda Na2CO3.10 H2O

9. Explain what you see in the following picture
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 19
Powder coating
Answer:

  1. This picture shows powder coating of the given object. Powder coating is a method of applying a layer harder than paint on the surface of an iron object to prevent rusting.
  2. In this method, a polymer resin, a pigment and some other ingredients are melt mixed, cooled and ground into a uniform powder.
  3. This powder is sprayed on the polished metal surface by electrostatic spray deposition (ESD).
  4. In this method, the particles of the powder are given an electrostatic charge due to which a uniform layer of the powder sticks to the metal surface.
  5. Then the object is heated in the oven along with the coating.
  6. A chemical reaction occurs in the layer, resulting in the formation of long cross-linked polymeric chains.
  7. This powder coating is highly durable, hard and attractive. Powder coating can be done on plastic and medium density fibre (MDF) board in day to day use as well.

Class 9 Science Chapter 14 Substances in Common Use Intext Questions and Answers

Can you recall?

Question 1.
What are detergents?
Answer:

  • Detergent is a water-soluble cleansing agent which combines with impurities and dirt to make them more soluble, and differs from soap in not forming a scum with the salts in hard water.
  • Today, detergents are more likely to be a mixture of synthetic chemicals and additives cooked up in a huge chemical plant and, unlike traditional soap, they’re generally liquids rather than solids.
  • Detergents are used in everything from hair shampoo and clothes, washing powder to shaving foam and stain removers.
  • The most important ingredients in detergents are chemicals called surfactants – a word made from bits of the words surface-active agents.

Question 2.
What are the important substances that we use in day to day life? For what purposes do we use them?
Answer:
Some of the substances we use in our day to day life and the purpose of using them are as follows:

Toothpaste: for cleaning teeth and maintaining hygienic conditions of mouth.

Soap : for bathing and maintaining hygienic conditions of body.

Natural and artificial fibers : we wear them as clothes to protect our body and many other purposes.

Washing powder: for cleaning clothes. Vegetables, fruits and food grains : they provide us with necessary vitamins, minerals and carbohydrates required for proper functioning of body.

Water : very important for our survival and many other functions of day to day life.

Metals : for making buildings, bridges, roads, vehicles, trains, ships, airplanes, utensils etc.

Acids, bases and salts : used for various purposes, for example, Sodium chloride which is used as common salt, a very necessary ingredient of our daily food without which our food is tasteless.

Question 3.
How are the various substances in day to day use classified from the scientific point of view?
Answer:
The various substances in day to day use are classified from the scientific point of view as elements, compounds, mixtures, metals, non-metals, acids, bases and salts.

Question 4.
Which chemicals and apparatus will you use in the laboratory for making soap?
Answer:
For making soap in laboratory following chemicals and apparatus are used :
Chemicals : Vegetable oil (coconut oil, castor oil, soya bean oil etc.)
Sodium hydroxide (NaOH)
Salt (Sodium chloride NaCl)

Apparatus :
500 ml glass beaker
Burner
Flat glass tray
Knife

Soaps are essential to personal and public health. They safely remove germs, soils and other contaminants and help us to stay healthy and make our surroundings more pleasant. Soaps are made from fats and oils or their fatty acids.

Take about 20 ml of any vegetable oil (coconut oil, castor oil, soybean oil etc.) in a beaker. Put about 30 – 35 ml of NaOH in it and heat and stir the mixture till a paste is formed. Now add a little salt. Stir again and allow the mixture to cool in a flat glass tray, on cooling it solidifies. Take a knife and cut it in soap bars as per the size required.

Question 5.
What are salts?
Answer:

  • Inorganic substances occur naturally in the form of salts rather than acids or bases.
  • The ionic compounds which do not contain H+ and OH ions and contain only one kind of cation and anion are called simple salts.
  • For example, Na2SO4, K3PO4, CaCl2.
  • The sea is said to be a rich source of salts. In fact, the sea is a rich source of several salts of various elements such as chlorine, sodium, magnesium, potassium, calcium, bromine.
  • The important salts found in sea water are sodium chloride, magnesium chloride, magnesium sulphate, potassium chloride, calcium carbonate and magnesium bromide.

Answer the following questions:

Question 1.
How is it determined whether a substance is acidic, basic or neutral?
Answer:

  • In the pH scale, the pH of solutions varies from 0 to 14 in accordance with the strength of the acids or base.
  • The pH scale shows different colours at different values of pH. Colour from dark red to yellow or from pH value 0 to 6 indicates the substances are acidic.
  • Colour from light blue to violet or from pH value 8 to 14 indicates the substances are basic.
  • Green colour or pH value 7 indicates the substances are neutral.

Question 2.
A sweets shop looks attractive because of the colourful sweets displayed there. Which colours are used in these substances?
Answer:

  • Food colours and essences are used in sweets to make them colourful and tasty.
  • These food colour are in the form of powders, gels and pastes.
  • Food colours are natural as well as artificial.
  • The food colours prepared from seeds, beetroot, flowers and fruit concentrate are natural.
  • Tetrazene, sunset yellow are artificial food colours used extensively.

Question 3.
Make a list of substances in day to day use in accordance with their pH value (O to 14).
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 18

Question 4.
A doctor gives you medicines when you fall ill. What are the medicines made from?
Answer:

  • Long before pure chemicals were manufactured in labs, people used plants for medicine.
  • There are over a hundred active ingredients derived from plants for use as drugs and medicines.
  • The emergence of synthetic chemistry in the 1800s opened up new avenues for scientific research into drugs.
  • Many chemists tried to locate medically active ingredients in plants (for instance the important malaria remedy quinine), and subsequently tried to make those substances in the laboratory in order to become independent of plant supplies.
  • At the same time, a new industry developed as scientists developed processes to synthesise new chemicals on a large scale.
  • New production methods developed in the late 1800s and early 1900s made it easier to standardise, package and transport medicines.

Question 5.
What problems do you get after playing colours on Rang Panchami? Why?
Answer:

  • After playing colours on Rang Panchami we may get problems such as risks of blindness, skin cancer, asthma, itching of the skin, permanent blocking of sweat pores etc.
  • This is because the colours used in rang panchami specially the red colour is very dangerous.
  • It contains a high proportion of mercury in it.

Question 6.
Which colours will you use to prevent the occurrence of these problems?
Answer:

  • To prevent the occurrence of these problem, instead of using artificial colours, natural colours should be used.
  • Natural colours are prepared from natural resouroes such as beet root, flowers of flame of forest, spinach, flame tree (gulmohar).

Question 7.
What problem do you have on painting the house and furniture?
Answer:

  • On painting the house and furniture with artificial colours which are dangerous, we may get problems such as risks of blindness, skin cancer, asthma, itching of the skin, permanent blocking of sweat pores, etc.
  • This is because the colours contain a high proportion of mercury in it.

Question 8.
What is the property of Teflon because of which it is used in non-stickware?
Answer:
Following are the properties of teflon because of which it is used in nonstick cookware.

  • The atmosphere and chemical substances have no effect on Teflon.
  • Neither water nor oil will stick to Teflon coated non-stickware.
  • High temperatures do not affect Teflon as its melting point is 327 °C.
  • Teflon coated non-stickware are easy to clean.

Answer the following questions:

Question 1.
What is the strip shown below? What is it used for?
Answer:
The strip shown is pH metre scale. It is used to determined pH of solutions.

Question 2.
Prepare saturated solutions of given salts and put 2-3 drops of the universal indicator in them and note your observations in the table below:
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 1

Class 9 Science Chapter 14 Substances in Common Use Additional Important Questions and Answers

Select the correct option:

Question 1.
Baking soda is ………………………… .
(a) non-metallic
(b) metallic
(c) acidic
(d) basic
Answer:
(d) basic

Question 2.
During electrolysis of NaCl in the fused state ………………………… is formed at cathode.
(a) sodium
(b) oxygen
(c) oxalic acid
(d) butyric acid
Answer:
(a) sodium

Question 3.
………………………… is known as chloride of lime.
(a) Calcium carbonate
(b) Sodium bicarbonate
(c) Sodium chloride
(d) Bleaching powder
Answer:
(d) Bleaching powder

Question 4.
Salt obtained from certain type of rock is called ………………………… .
(a) hard salt
(b) rock salt
(c) stone salt
(d) pure salt
Answer:
(b) rock salt

Question 5.
The ………………………… % aqueous solution of salt is called brine.
(a) 25
(b) 60
(c) 30
(d) 50
Answer:
(a) 25

Question 6.
The molecular formula for baking soda is ………………………… .
(a) Na2CO3
(b) NaHCO3
(c) Na2SO4
(d) NaNO3
Answer:
(b) NaHCO3

Question 7.
Bleaching powder is also called ………………………… .
(a) Calcium oxygen chlorine
(b) Calcium oxychloride
(c) Calcium hydroxide
(d) Calcium oxalate
Answer:
(b) Calcium oxychloride

Question 8.
NaHCO3 is also called as ………………………… .
(a) Sodium carbonate
(b) Sodium bicarbonate
(c) Sodium carbon oxide
(d) Sodium chloride
Answer:
(b) sodium bicarbonate

Question 9.
Molecular formula for Magnesium bromide is ………………………… .
(a) MgBr
(b) Mg2Br
(c) Mg2Br2
(d) MgBr2
Answer:
(d) MgBr2

Question 10.
The molten state of NaCl is also called as ………………………… .
(a) solid state
(b) semi-solid
(c) gaseous state
(d) fused state
Answer:
(d) fused state

Question 11.
Substance used to make hard water soft is ………………………… .
(a) Na2CO3.10H2O
(b) Na2CO3.H2O
(c) NaCO3.10H2O
(d) NaCO3.H2O
Answer:
(a) Na2CO3.10H2O

Question 12.
The fixed number of molecules of water in alum is ………………………… .
(a) 24
(b) 10
(c) 7
(d) 2
Answer:
(a) 24

Question 13.
Chlorine gas is a strong ………………………… agent.
(a) reducing
(b) oxidising
(c) neutral
(d) acidic
Answer:
(b) oxidising

Question 14.
Bleaching powder is ………………………… in colour.
(a) brownish red
(b) yellowish-white
(c) pinkish brown
(d) greenish blue
Answer:
(b) yellowish-white

Question 15.
Soap is ………………………… in nature.
(a) acidic
(b) basic
(c) neutral
(d) fuming
Answer:
(b) basic

Question 16.
Melting point of NaCl is ………………………… .
(a) 400°C
(b) 100°C
(c) 800°C
(d) 600°C
Answer:
(c) 800°C

Question 17.
Rock salt is ………………………… in colour.
(a) black
(b) white
(c) brown
(d) blue
Answer:
(c) brown

Question 18.
Strong odour in swimming pool is due to ………………………… .
(a) chlorine gas
(b) impurities
(c) calcium carbonate
(d) calcium hydroxide
Answer:
(a) chlorine gas

Question 19.
Molecular formula of sodium bicarbonate is ………………………… .
(a) NaHCO3
(b) Na2HCO3
(c) Na2HCO2
(d) NaHCO2
Answer:
(a) NaHCO3

Question 20.
Soap is ………………………… in nature.
(a) radioactive
(b) natural
(c) acidic
(d) basic
Answer:
(d) basic

Question 21.
The molecular formula for Magnesium bromide is ………………………… .
(а) MgBr
(b) MgBr2
(c) Mg2Br2
(d) Mg2Br
Answer:
(b) MgBr2

Fill in the blanks and rewrite the complete statements:

(1) 25% of NaCl is known as
(2) gas is released when bleaching powder is added to water.
(3) Washing soda is as it absorbs moisture if left exposed to air.
(4) is used to make hard water soft.
(5) Molecular formula for Alum is
(6) is used in blood test for diagnosing anaemia.
(7) High grade of and are used as raw material to manufacture bathing soap.
(8) Pickles, jams and sauce contain small quantities of and
(9) Excessive consumption of foods with added food colours leads to diseases like
(10) Melting point of Teflon is
(11) Anodizing is done by
(12) The red blood cell count increases in the disease
(13) Magnesium sulphate (MgS04.7H20) is also called
Answer:
(1) Brine
(2) Chlorine
(3) hygroscopic
(4) Na2CO3 (Washing soda)
(5) K2SO4.Al2(SO)3.24H2O
(6) Blue Vitriol
(7) fats, oils
(8) lead, mercury
(9) ADHD (Attention Deficit Hyperactivity Disorder)
(10) 327°C
(11) Electrolysis
(12) Polycythemia
(13) Epsom salt
(14) Soap

State whether the following statements are true or false. Correct the false statements.
(1) Bleaching powder is used in preparation of chloroform which is used as an anaesthetic.
(2) On addition of universal indicator the colour of table salt changes to pink.
(3) Borax is Na2B4O7.9H2O.
(4) Boron -10 is used to cure bone cancer.
(5) Clinical deo contains 20 to 25% of aluminium.
(6) NaHCO3 is sodium carbonate.
(7) Soap is acidic in nature.
(8) Baking powder is neutral in nature.
(9) POP is crystalline in nature.
(10) pH value of universal indicator is 0 – 7.
(11) Sodium chloride is formed by neutralization reaction between sodium hydroxide and calcium carbonate.
(12) Boiling point of NaCl is 800 °C.
(13) Molten state of NaCl is also called as solid state.
(14) Mineral halite is an example of Rock Salt.
(15) Sodium bicarbonate is used to reduce acidity.
(16) Bleaching powder is also called as chloride of lime.
(17) Bleaching powder is obtained by reaction of chlorine gas with slaked lime.
(18) Bleaching powder available in market is classified on the basis of colour.
(19) The hard water becomes soft on adding baking soda (NaHCO3)
Answer:
(1) True
(2) False. On addition of universal indicator the colour of table salt changes to green.
(3) False. Borax is Na2B4O7.9H2O
(4) False. Boron – 10 is used in treatment of brain tumour.
(5) True
(6) False. NaHCO3 is sodium bicarbonate.
(7) False. Soap is basic in nature.
(8) False. Baking powder is basic in nature.
(9) False. POP is amorphous in nature.
(10) False. pH value of universal indicator is 0 -14.
(11) False. Sodium chloride is formed by a neutralization reaction between sodium hydroxide and hydrochloric acid.
(12) False. Melting point of NaCl is 800°C.
(13) False. Molten state of NaCl is also called as fused state.
(14) True
(15) True
(16) True
(17) True
(18) False. Bleaching powder available in market is classified on the basis of percentage of chlorine present in it.
(19) False. Hard water becomes soft on adding washing soda (Na2CO3.10H2O)

Name the following:

Question 1.
Important salts found in sea water.
Answer:
Magnesium chloride, Potassium chloride

Question 2.
Chemical used in preparation of breads and cakes to make them soft.
Answer:
Sodium bicarbonate

Question 3.
Gas liberated when bleaching powder is added to CO2 gas.
Answer:
Chlorine (Cl2) gas.

Question 4.
Salt used in refining petroleum
Answer:
Sodium carbonate (Na2CO3)

Question 5.
Chemical formula of bleaching powder
Answer:
CaOCl2

Question 6.
The chemical formula of Sodium hydrogen carbonate.
Answer:
NaHCO3

Question 7.
Nature of soap.
Answer:
Basic

Question 8.
Molecular formula for Magnesium bromide
Answer:
MgBr2

Question 9.
Melting point of NaCl
Answer:
800 °C

Question 10.
Two examples of Rock Salt
Answer:
Mineral halite and Himalayan rock salt.

Question 11.
Uses of sodium bicarbonate
Answer:
To prepare breads, cakes and dhokla

Question 12.
Constituents of baking powder.
Answer:
Baking soda and mild acid (tartaric acid)

Question 13.
Substance used to make hard water soft.
Answer:
Washing soda i.e. Na2CO3.10H2O.

Question 14.
Radioactive isotopes used in treatment of bone cancer.
Answer:
Strontium – 89, Strontium – 90, Samarium -153, Radium – 223

Question 15.
Use of Strontium 89 and strontium 90.
Answer:
Treatment of bone cancer.

Select the odd man out:

Question 1.
Sodium sulphate, Barium chloride, Magnesium sulphate, Bleaching powder.
Answer:
Bleaching powder, all others are crystalline salt with water of crystallization while bleaching powder is not.

Question 2.
Strontium – 89, Strontium – 90, Radium – 223, Iodine -123.
Answer:
Iodine -123, it is used to cure hyperthyroidism while others are used to cure bone cancer.

Question 3.
Soap, Toothpaste, Baking soda, Curd.
Answer:
Curd, it is acidic in nature while others are basic in nature.

Question 4.
Na2CO3.10H2O, Na2SO4.10H2O, BaCl2.2H2O, CaOCl2
Answer:
CaOCl2, it is amorphous in nature while rest are crystalline in nature.

Question 5.
Boron-10, Iodine – 131, Cobalt – 60, Iodine – 123.
Answer:
Iodine -123, it is used in hyperthyroidism while rest are used in treatment of brain tumour.

Question 6.
Na2SO4, K3PO4, MgBr2, HCl.
Answer:
HCl, rest all are salts but HCl is an acid.

Write the correlated terms:

(1) Washing Powder : Basic :: Milk : ……………………………
(2) Na2SO4: Sodium sulphate :: K3PO4 : ……………………………
(3) CaOCl2: Calcium Oxychloride : : NaHCO3 : ……………………………
(4) Borax : 10H2O : : Alum : ……………………………
(5) Sodium Sulphate : Na2SO4.10H2O : : Magnesium Sulphate : ……………………………
(6) Bathing soap : High grades fats and oils :: Washing soap : ……………………………
(7) Radium – 23 : Bone cancer :: Phosphorus – 32 : ……………………………
(8) Iodine -123 : Hyperthyroidism :: Iodine -131 : ……………………………
(9) Clinical deo : 20-25% of aluminium : : Antiperspirant deo : of aluminium chlorohydrate : ……………………………
(10) Sodium carbonate : Na2CO3 : : Sodium bicarbonate : ……………………………
(11) Curd : Acidic : : Soap : ……………………………
(12) Calcium Carbonate : CaCO3 : : Magnesium bromide : ……………………………
(13) Baking Soda : NaHCO3 : : Washing Soda : ……………………………
(14) Baking Soda : Breads and Cakes : : Washing Soda : ……………………………
(15) Borax : Na2B4O7.10H2O : : Alum : ……………………………
Answer:
(1) Acidic
(2) Potassium phosphate
(3) Sodium hydrogen carbonate
(4) 24H2O
(5) MgSO4.7H2O
(6) Low-grade fats and oils
(7) Polycythemia
(8) Tumour detection
(9) 15%
(10) NaHCO.
(11) Basic
(12) MgBr2
(13) Na2CO3.10H2O
(14) Hard water soft
(15) K2SO4.Al2(SO4)3.24H2O

Match the columns:

Question 1.

Column ‘A’ Column ‘B’
(1) Barium chloride (a) 24H2O
(2) Sodium sulphate (b) 7H2O
(3) Magnesium sulphate (c) 2H2O
(4) Alum (d) 10H2O

Answer:
(1 – c),
(2 – d),
(3 – b),
(4 – a)

Question 2.

Column ‘A’ Column ‘B’
(1) Strontium – 90 (a) Brain tumour
(2) Cobalt – 60 (b) Hyperthyroidism
(3) Iodine – 131 (c) Polycythemia
(4) Phosphorus – 32 (d) Bone cancer

Answer:
(1 – d),
(2 – a),
(3 – b),
(4 -c)

Give scientific reasons:

Question 1.
Baking soda is used while making cakes.
Answer:

  • Baking soda is chemically known as sodium bicarbonate.
  • On heating, sodium bicarbonate decomposes to form sodium carbonate, water and carbon dioxide (CO,).
  • The carbon dioxide produced is released due to which the cake becomes soft and spongy.
  • Hence, baking soda is used to make cake spongy and soft.

Question 2.
Baking soda is used to reduce acidity in the stomach.
Answer:

  • Baking soda is used as a medicine (antacid). When it is taken, it undergoes hydrolysis to give sodium hydroxide in the stomach. Thus, sodium hydroxide neutralizes the hydrochloric acid produced by gastric juice and gives relief to the patient from acidity.
    Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 4

Question 3.
Tap water and water in swimming pool has a typical strong odour in the rainy season.
Answer:

  • Tap water and water in swimming pool has a typical strong odour in the rainy season, it is the odour of the chlorine gas that is used to destroy the microbes in the water.
  • Chlorine gas is a strong oxidizing agent and therefore, it has a strong disinfecting as well as bleaching action.
  • Chlorine is inconvenient to handle because of its gaseous state. Instead, the solid bleaching powder which has the same effect is more convenient to use.
  • Bleaching powder undergoes slow decomposition due to the carbon dioxide in air and chlorine gas is released. Bleaching powder gets its property because of this release of chlorine gas.
    Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 5

Question 4.
Sodium carbonate is added to hard water to make it soft.
Answer:

  • The hardness of water is due to the presence of chlorides and sulphates of calcium and magnesium in it.
  • Na2CO3 is added to it to soften such water and make it suitable for use.
  • The reaction with Na2CO3 causes the formation of insoluble carbonate salts of magnesium and calcium thus making the water soft.
    Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 6

Question 5.
Alum is used in the process of water purification.
Answer:

  • Alum is used in the process of water purification because of property of coagulation.
  • The solid impurities in water come together, become heavy and settle to the bottom.
  • As a result, the water above becomes clear.

Question 6.
Overconsumption of artificial food colours should be avoided?
Answer:

  • The overconsumption of artificial food colours should be avoided because they can be detrimental to health.
  • Food colours added to pickles, jam and sauce contain small quantities of lead and mercury. These can be harmful for those who consume these products on a regular basis.
  • Diseases like ADHD (Attention Deficit Hyperactivity Disorder) can affect children due to excessive consumption of foods with added food colours.

Question 7.
Artificial colours in Rang Panchami should be used cautiously.
Answer:

  • We regularly use artificial colours on Rang Panchami.
  • The red colour used on Rang Panchami is very dangerous. It contains a high proportion of mercury in it.
  • This poses risks like blindness, skin cancer, asthma, itching of the skin, permanent blocking of sweat pores etc.
  • Therefore, it is necessary that artificial colours are used cautiously.

Question 8.
There are various brands of bleaching powder in the market.
Answer:

  • When bleaching powder comes in contact with air, it reacts with carbon dioxide to form calcium carbonate and releases chlorine gas. CaOCl2 + CO2 → CaCO3 + Cl2 ↑ (from air)
  • This generated chlorine is known as “available chlorine.”
  • On the basis of the percentage of “available chlorine” various brands of bleaching powder are available in the market.

Question 9.
We use anodized cooking utensils like griddles and cookers.
Answer:

  • Anodizing is process of forming a protective rayer of hydrated aluminium oxide on utensils.
  • Due to anodizing, the surface of the cooking utensils become non-standing, non-toxic and non-reactive with the ingredients of the foot.
  • These utensils get heated faster and withstand high heat.
  • Also the amount of butter, ghee or oil used to cook food in these type of utensils is neglible.
  • These utensils are tough, durable and resistant to corrosion.
  • Hence, we use anodized cooking utensils like gridders and cookers.

Explain the following chemical reactions with the help of balanced equations :

Question 1.
Sodium hydroxide reacts with dilute Hydrochloric acid.
Answer:
When Sodium hydroxide reacts with dilute Hydrochloric acid, it forms sodium chloride and water.
This is a neutralization reaction.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 8

Question 2.
When an electric current is passed through a saturated solution of sodium chloride (brine)
Answer:
When an electric current is passed through a saturated solution of sodium chloride (brine) it is electrolysed and hydrogen gas is released at the cathode while chlorine gas is released at the anode. Also, an important basic compound NaOH is formed in the cell.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 9

Question 3.
Baking soda (Sodium hydrogen carbonate) reacts with dilute hydrochloric acid.
Answer:
When Sodium bicarbonate (Sodium hydrogen carbonate) reacts with dilute hydrochloric acid, it gives sodium chloride, water and carbon dioxide gas is liberated.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 10

Question 4.
Bleaching powder is exposed to air.
Answer:
When bleaching powder is exposed to air, it undergoes slow decomposition due to the carbon dioxide in air and chlorine gas is released.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 11

Question 5.
When dry slaked lime reacts with chlorine gas.
Answer:
When dry slaked lime reacts with chlorine gas, it gives bleaching powder.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 12

Question 6.
Bleaching powder reacts with dilute sulphuric acid.
Answer:
Dilute sulphuric acid reacts rapidly with bleaching powder to form calcium sulphate and release chlorine gas completely.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 13

Question 7.
Bleaching powder reacts with dilute hydrochloric acid.
Answer:
Dilute hydrochloric acid reacts rapidly with bleaching powder to form Calcium chloride and release chlorine gas completely.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 16

Question 8.
Sodium carbonate reacts with magnesium chloride.
Answer:
When Sodium carbonate reacts with magnesium chloride, it forms insoluble magnesium carbonate and sodium chloride. This reaction is used to make hard water soft.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 15

Question 9.
Crystalline sodium carbonate is exposed to air.
Answer:
When crystalline sodium carbonate is exposed to air it loses its water of crystallization readily and a white powder is obtained. This powder is called washing soda.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 14

Question 10.
Sodium carbonate reacts with sulphuric acid.
Answer:
When sodium carbonate reacts with sulphuric acid it forms sodium sulphate, water and carbon dioxide gas is liberated.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 17

Distinguish between;

Question 1.
Washing soda and Baking soda
Answer:

Washing soda Baking soda
(i) Chemical name is sodium carbonate. (i)    Chemical name is sodium bicarbonate or sodium hydrogen carbonate.
(ii) Its molecular formula is Na2CO3.10H2O (ii) Its molecular formula is NaHCO3
(iii) It is a crystalline substance. (iii) It is an amorphous powder.
(iv) It is used in manufacturing soaps and detergents. (iv) It is used in bakery for making cakes and bread lighter and spongy.

Question 2.
Bathing soap and Washing soap
Answer:

Bathing soap Washing soap
(i) High-grade fats and oils are used as the raw material. (i) Low-grade fats and oils are used as the raw material.
(ii) Expensive perfumes added. (ii) Cheaper perfumes added.
(iii) No free alkali content present to prevent injuries to skin. (iii) Free alkali present for cleaning action.

Answer the following:

Question 1.
Give the properties and uses of Sodium bicarbonate.
Answer:
Properties and uses of sodium bicarbonate

  • (i) NaHCO2 reacts with moist litmus paper and red litmus turns blue which means that it is basic in nature.
  • (ii) It is used to make bread, cake, dhokla.
  • (iii) Being basic in nature it is used to reduce acidity in the stomach.
  • (iv) NaHCO3 is used to make the active substance CO2 in the fire extinguisher.
  • (v) Baking soda is used to clean an oven.

Question 2.
Give the properties and uses of washing soda.
Answer:
Properties and uses of washing soda :

  • Washing soda is a whitish and odourless powder at room temperature.
  • Litmus has a blue colour in its aqueous solution.
  • It is hygroscopic, that is, it absorbs moisture if left exposed to air.
  • It is used mainly for washing clothes.
  • Sodium carbonate is used in the glass and paper industry and also in refining of petrol.

Question 3.
Name some substances in our daily use which contain water of crystallization.
Answer:

  • Alum (Potash alum – K2SO4.Al2(SO4)3.24H2O)
  • Borax (Na2B4O7.10H2O)
  • Epsom salt (Magnesium sulphate MgSO4.7H2O)
  • Barium chloride (BaCl2.2H2O)
  • Sodium sulphate (Glauber’s salt Na2SO4.10H2O)

Question 4.
Give the uses of radioactive isotopes in the measurement of thickness, density and level.
Answer:
Measurement of thickness, density and level:

  • It is necessary to maintain the required thickness in the manufacture of aluminium, plastic, iron sheets of differing thickness.
  • In the manufacturing process, a radioactive substance is placed on one side and an instrument to measure radiation on the other.
  • The radiation read by the measuring instrument varies with the thickness of the sheet.
  • Material inside a packing can also be examined by the same technique.

Question 5.
Give the uses of radioactive isotopes in Luminescent paint and radioluminescence.
Answer:
Luminescent paint and radioluminescence:

  • The radioactive substances radium, promethium, tritium with some phosphour are used to make certain objects visible in the dark, for example, the hands of a clock, and certain other objects.
  • Krypton-85 is used in HID (High Intensity Discharge) lamps while promethium-147 is used in portable X-ray units as the source of beta rays.

Question 6.
Give the uses of radioactive isotopes in Field of agriculture.
Answer:
Field of agriculture:

  • The genes and chromosomes that give seeds properties like fast growth, higher productivity, etc. can be modified by means of radiation.
  • The radioactive isotope cobalt-60 is used for food preservation.
  • Onions, potatoes are irradiated with gamma rays from cobalt-60 to prevent their sprouting.
  • Strontium-90 is used as a tracer in the research on various crops.

Question 7.
Give the uses of dyes.
Answer:
Uses of dyes :

  • They are used for colouring cloth and hair.
  • Fluorescent colours are used to make street boards that are visible at night.
  • Dyes are used to polish leather shoes, purses and chappals.

Question 8.
What are the adverse effects of dyes?
Answer:
Adverse effects dyes :

  • Dyeing hair can have adverse effects like hair fall, damage to hair texture, burning of skin, adverse effect on eyes, etc.
  • Lipstick contains a dye named carmine. It does not affect lips but causes stomach disorders.
  • Excessive use of plants for making natural dyes results in deterioration of the environment.

Question 9.
Give the uses of teflon.
Answer:
Uses of teflon :

  • Teflon is a poor conductor of electricity. Therefore, Teflon clad wires and parts are used in high technology electronic instruments.
  • It is used for making non-stick kitchenware.
  • The coloured metal sheets of two-wheelers and four-wheelers are given a Teflon coating to protect them from damage due to high temperature and rain.

Question 10.
What is ceramic? Give examples.
Answer:

  • Ceramic is a heat resistant substance formed by kneading an inorganic substance in water and then shaping it and hardening it by heating.
  • Pots made by a potter, Mangalore roofing tiles, construction bricks, pottery, terracotta articles are some examples of common ceramic articles that we see around.

Question 11.
Give the uses of ceramics.
Answer:

  • Ceramics can withstand high temperatures without decomposing. Ceramic is brittle, water-resistant and an electrical insulator.
  • Therefore, it is used in electrical instruments, for coating the interior of a kiln, the outer surfaces of ships and blades of jet engines.
  • A certain type of ceramic tiles are fixed on the outer layer of a space shuttle. Some types of ceramics are used as superconductors.

Question 12.
What is brine? What happens when ^th of this solution is evaporated?
Answer:

  • The 25% aqueous solution of salt is called saturated brine.
  • When th of this solution is evaporated the dissolved salt gets crystallized and salt gets separated from the solution.

Question 13.
What is baking soda? Give its chemical name and molecular formula.
Answer:

  • Baking soda is a white non-crystalline powder.
  • Its chemical name is sodium hydrogen carbonate or sodium bicarbonate and its molecular formula is NaHC03.

Question 14.
Give two uses of Blue vitriol.
Answer:

  • Blue vitriol is used in the blood test for diagnosing anaemia.
  • Bordeaux mixture which is a mixture of slaked lime and blue vitriol is used as a fungicide on fruits like grapes and musk melon.

Question 15.
What is radioactivity and what are radioactive substances?
Answer:

  • Elements with a high atomic number such as uranium, thorium, radium have a property of spontaneously emitting invisible, highly penetrating and high energy radiation. This property is called radioactivity.
  • A substance having this property is called a radioactive substance.

Question 16.
What can you say about the uses of radioactive isotopes?
Answer:

  • It is a misconception that radioactive elements are used only for making an atom bomb.
  • Radioactive isotopes are used in various fields such as scientific research, agriculture, industry, medicine, etc.
  • Radioactive substances are used in two ways.
  • By using the radiation alone.
  • By using the radioactive element itself.

Question 17.
Give the uses of radioactive isotopes in Radiography.
Answer:

  • Internal cracks and voids in cast iron articles and iron solder can be detected with the help of gamma rays.
  • For this purpose, isotopes like cobalt-60, iridium-192 are used in the radiography camera.
  • This technique is used for detecting flaws in metalwork.

Question 18.
Give the uses of radioactive isotopes in ceramic articles.
Answer:

  • Luminous colours are used to decorate ceramic tiles, utensils, plates, etc.
  • Earlier uranium oxide was used in these paints.

Question 19.
What is a dye?
Answer:
The coloured substance which on applying to an article, imparts that colour to the article, is called a dye

Question 20.
What is done to fix a dye on the cloth ?
Answer:

  • A mordant is to be used to fix the colour after dyeing a cloth.
  • A mordant is a chemical binding agent that adheres well to both the fibers and the dye.

Question 21.
What is Teflon? Give its chemical name.
Answer:

  • Teflon is the polymer of tetrafluoroethylene.
  • Its chemical name is polytetrafluoroethylene (C2F4)n

Question 22.
What is powder coating? Why is it done?
Answer:

  • Powder coating is a method of applying a layer harder than paint on the surface of plastic, medium density fibre (MDF).
  • Board and iron object to make them attractive, durable and to prevent rustihg respectively.

Question 23.
Give the properties of ceramics.
Answer:

  • Ceramics can withstand high temperatures without decomposing.
  • Ceramic is brittle, water resistant and an electrical insulator.

Question 24.
How is bone china made? How is it different from porcelain?
Answer:

  • Bone china is made by adding some ash of animal bones in the mixture of china clay, feldspar and fine silica while making porcelain.
  • This ceramic is harder than porcelain.

Question 25.
What compounds are used instead of clay for making advanced ceramic?
Answer:
Oxides like Alumina (Al2O3), Zirconia (ZrO2) Silica (SiO2) and some other compounds like silicon carbide (SiC), boron carbide (B4C) are used instead of clay for making advanced ceramic.

Question 26.

What is sintering?
Answer:

  • Advanced ceramics requires a temperature of 1600 to 1800 °C and an oxygen-free atmosphere for firing.
  • This process is called sintering.

Write short notes on :

Question 1.
Chernobyl disaster.
Answer:

  • On 26th April 1986, the graphite reactor in the Chernobyl atomic power plant exploded, and suddenly the radioactive isotopes and radiation came out.
  • Due to this episode, radioactive isotopes entered the human body through water and land and caused genetic disorders.
  • These got carried further into the next generation.
  • Thyroid disorders increased in children as well as adults.
  • As a result, the incidence of throat diseases is greater there than in other places.

Question 2.
Food colours.
Answer:

  • Food colours are mixed in most soft drinks and foodstuffs available in the market.
  • These food colours are in the form of powders, gels and pastes.
  • Food colours are used in domestic as well as commercial products.
  • Certain colours and essences are added to ice cream, ice candies, sauces, fruit juices, cold drinks, pickles, jams and jellies.
  • Food colours are often found to be added to packaged meat (chicken, mutton), chilli powder, turmeric, sweets and other similar substances so as to give them a good colour.
  • Food colours are natural as well as artificial.
  • The food colours prepared from seeds, beetroot, flowers and fruit concentrate are natural.
  • Tetrazene, sunset yellow are artificial food colours used extensively.
  • However, over-consumption of artificial food colours can be detrimental to health. Therefore, usage of natural food colours is always good.

Question 3.
Anodizing.
Answer:

  • A protective layer is formed naturally on the surface of aluminium metal by reaction with oxygen in air.
  • In the anodizing process, this layer can be made of the desired thickness.
  • Anodizing is done by electrolysis.
  • Dilute sulphuric acid is taken in the electrolytic cell and the aluminium article is dipped in it as the anode.
  • When an electric current is passed, hydrogen gas is released at the cathode and oxygen gas at the anode.
  • A reaction with oxygen occurs and a layer of hydrated aluminium oxide is formed on the anode, i.e. the aluminium article.
  • This layer can be made attractive by adding colour in the cell during electrolysis.

Answer the following questions:

Question 1.
What are salts? Give their source.
Answer:

  • The ionic compounds which do not contain H+ and OH ions and contain only one kind of cation and anion are called simple salts.
  • For example, Na2SO4, K3PO4, CaCl2.
  • The sea is said to be a rich source of salts of various elements such as chlorine, sodium, magnesium, potassium, calcium, bromine.
  • The important salts found in sea water are:
    (a) Sodium chloride
    (b) Magnesium chloride
    (c) Magnesium sulphate
    (d) Potassium chloride
    (e) Calcium carbonate
    (f) Magnesium bromide

Question 2.
Which are the three kinds of salts depending on their pH value? How are they formed?
Answer:
The three kinds of salts depending on their pH value are:

Neutral salts:
Salt is neutral when its pH value is 7. Such a salt is made from a strong acid and a strong base.

Acidic salts:
The pH value of a salt made from a strong acid and a weak base is less than 7 and it is acidic.

Basic salts:
The pH value of a salt made from a weak acid and strong base is more than 7 and it is basic.

Question 3.
Which is the most used salt? What is its chemical name? How is it formed?
Answer:

  • Table salt, or common salt, which gives a salty taste to food, is the most used of all salts.
  • Its chemical name is Sodium chloride.
  • Sodium chloride is formed by a neutralization reaction between sodium hydroxide and hydrochloric acid.
  • Chemical reaction
  • This is a neutral salt and the pH value of its aqueous solution is 7.

Question 4.
How is bleaching powder obtained?
Answer:

  • Bleaching powder is obtained by the reaction of chlorine gas with slaked lime.
  • Chemical reaction

Question 5.
How is hard water from well converted to soft water?
Answer:

  • The hard water from a well or a bore-well becomes soft on adding washing soda and we come to know this from the lather formed on it.
  • The hardness of water is due to the presence of chlorides and sulphates of calcium and magnesium in it.
  • Na2CO3 is added to it to soften such water and make it suitable for use.
  • The reaction with Na2CO3 causes the formation of insoluble carbonate salts of magnesium and calcium.
  • Chemical reaction
    MgCl2(aq) + Na2CO3(s) → MgCO3(s) + 2NaCl(s) Magnesium Sodium Magnesium Sodium chloride carbonate carbonate chloride

Question 6.
How is washing soda obtained from sodium carbonate?
Answer:

  • Sodium carbonate is a water soluble salt of sodium.
  • Crystalline sodium carbonate, on keeping, loses its water of crystallization readily and a white powder is obtained.
  • This powder is called washing soda.
  • Chemical reaction

Question 7.
How is soap prepared? Why it does not form lather with hard water?
Answer:

  • When oil or animal fat is boiled with an aqueous solution of sodium or potassium hydroxide, sodium or potassium salts of carboxylic acids (fatty acids) are formed.
  • These salts are called soap.
  • When soap is mixed with hard water, calcium and magnesium salts of fatty acids are formed.
  • These being water insoluble, they form a precipitate and that is why lather is not formed.

Question 8.
What are the harmful effects of artificial food colours?
Answer:

  • Food colours added to pickles, jams and sauces contain small quantities of lead and mercury. These can be harmful for those who consume these products on a regular basis.
  • Diseases like ADHD (Attention Deficit Hyperactivity Disorder) can affect children due to excessive consumption of foods with added food colours.

Question 9.
Which is the main source of colour for preparing a natural dye?
Answer:

  • Plants are the main source of colour for preparing a natural dye.
  • Roots, leaves, flowers, bark, fruits, seeds, fungus and pistils are used for making dyes.
  • In Kashmir a very good dye is made from saffron, which is used to dye fibers from which saris, shawls and dresses are made.
  • These are very costly. The use of henna leaves to colour hair is safe for health.

Question 10.
How are artificial colours harmful to us?
Answer:

  • We regularly use artificial colours on Rang Panchami.
  • The red colour used on Rang Panchami is very dangerous.
  • It contains a high proportion of mercury in it.
  • This poses risks like blindness, skin cancer, asthma, itching of the skin, permanent blocking of sweat pores, etc.
  • Therefore, it is necessary that artificial colours are used cautiously.

Question 11.
What are the harmful effects of deodorants?
Answer:

  • Aluminium – Zirconium compounds are the most harmful chemicals in deodorants. Disorders like headache, asthma, respiratory disorders, heart disease are likely to occur without our knowledge.
  • There is a possibility of various skin disorders and also skin cancer due to the aluminium chlorohydrates.

Question 12.
How is a ceramic article made?
Answer:

  • When clay is kneaded in water, shaped and then fired in a kiln at a temperature of 1000 to 1150 °C, a porous ceramic is formed.
  • To overcome the porosity, the fired object is covered with finely ground glass powder suspended in water (glaze) and is then fired again. As a result, the surface of the ceramic becomes shiny and its porosity disappears.

Question 13.
What is porcelain? How is it made?
Answer:

  1. Porcelain is a hard, translucent and white coloured ceramic. It is made by using the white clay called kaolin, found in China. Glass, granite and the mineral feldspar is mixed with kaolin and kneaded with water.
  2. The resulting mixture is shaped and fired in a kiln at a temperature of 1200 to 1450 °C. On firing again after glazing, beautiful articles of porcelain are obtained.

Answer the following questions:

Question 1.
What are the constituents of baking powder? Where is the baking powder used?
Answer:

  • Baking powder consist of 30% sodium bicarbonate, 5-12% monocalcium phosphate and 21-26% sodium aluminium sulphate.
  • Baking powder is a leavening agent and is used for increasing the volume and lightening the texture of baked goods.

Question 2.
Take a piece of coloured cloth. Put some saturated solution of bleaching powder on a small part and observe what changes take place in the colour of the cloth.
Answer:
When bleaching powder is added to a piece of coloured cloth, the fabric looses its colour due to the oxidising reaction of the chlorine present in the bleaching powder.

Answer in detail:

Question 1.
Give the properties and uses of Sodium chloride.
Answer:
Properties and uses of sodium chloride:

  • Common salt is a colourless and crystalline ionic compound. There is no water of crystallization in its crystalline structure.
  • It is a neutral salt, salty in taste.
  • This compound is used for the production of salts like Na2CO3, NaHCO3.
  • When an electric current is passed through a saturated solution of sodium chloride (brine), it is electrolysed and hydrogen gas is released at the cathode while chlorine gas is released at the anode.
  • This method is used for production of chlorine gas. In this method an important basic compound NaOH is formed in the cell.
    2NaCl + 2H2O → 2NaOH + Cl2↑ + H2
  • When salt is heated to a high temperature (about 800 °C), it melts. This is called the fused state of the salt.
  • When fused salt is electrolysed, chlorine gas is released at the anode and liquid sodium metal, at the cathode.

Question 2.
Give the properties and uses of Bleaching Powder.
Answer:
Properties and uses bleaching powder:

  • Bleaching powder is a yellowish-white coloured solid substance.
  • Its chemical name is Calcium oxychloride.
  • It has a strong odour of chlorine gas.
  • It is used for disinfection of drinking water at the water works and the water in the swimming pool.
  • It is used for bleaching of cloth.
  • It is used for disinfection by the road side and garbage sites.
  • Dilute sulphuric acid and dilute hydrochloric acid react rapidly with bleaching powder to release chlorine gas completely.
    CaOCl2 + H2SO4 → CaSO4 + Cl2 ↑ + H2O CaOCl2 + 2HCl → CaCl2 + Cl2 ↑ + H2O
  • Calcium oxychloride reacts slowly with carbon dioxide to form calcium carbonate and chlorine.
    CaOCl2 + CO2 → CaCOs + Cl2

Question 3.
Explain with neat labelled diagram the nature of radioactive radiation.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 2
Answer:

  • When radioactive radiations are allowed to pass through two oppositely charged plates they get separated. This method was introduced by Rutherford in 1902.
  • Rutherford and Willard studied the radiation emitted by radioactive substances.
  • For this purpose, the rays were allowed to pass through an electrical field and a photographic plate was held in their path.
  • It was found that the radiation was divided into three types.
  • One type of radiation deviated slightly towards the negatively charged plate, while the second type of radiation deviated substantially towards the positively charged plate.
  • However, the third type of radiation did not deviate at all in the electrical field.
  • The rays which deviated slightly toward negatively charged plate are called alpha rays.
  • Those which deviate substantially towards the positively charged plate are called beta rays and those which did not deviate at all are called gamma rays.

Question 4.
Give the characteristics of alpha, beta and gamma rays.
Answer:
Characteristics of alpha, beta and gamma rays are as given in the table.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 3

Question 5.
Give the uses of radioactive isotopes in Medical science.
Answer:
Medical science:

  • Polycythemia: The red blood cell count increases in the disease polycythemia. Phosphorus- 32 is used in its treatment.
  • Bone cancer: Strontium-89, strontium-90, samarium-153 and radium-223 are used in the treatment of bone cancer.
  • Hyperthyroidism: Enlargement of thyroid gland, weight loss in spite of appetite, insomnia are the symptoms of hyperthyroidism.
  • It occurs due to overproduction of hormones by the thyroid gland. Iodine-123 is used in the treatment of hyperthyroidism.
  • Tumour detection: Boron-10, iodine-131, cobalt-60 are used in the treatment of brain tumour, while arsenic-74 is used in detection of small tumours in the body.

Question 6.
What are the hazards of radioactive substances and radiation?
Answer:

  • The central nervous system is affected by radioactive radiations.
  • Hereditary defects are generated by bombardment of radiation on D.N.A in the body.
  • Radioactive radiation can penetrate the skin, and causes diseases like skin cancer, leukemia.
  • The radiative pollutants created due to explosions enter the body through air and it is difficult to control them.
  • The radioactive pollutants released in the sea enter the bodies of fishes and through them enter the human body.
  • The radioactive paint on the watch can cause cancer.
  • The radioactive isotopes strontium-90 can enter the body through plants, fruits, flowers, cereals, milk, etc. and cause diseases like bone cancer, leukemia.

Question 7.
Why are deodorant used? Give their types and content.
Answer:

  • Body odour is caused by the bacterial decomposition of the sweat. A deodorant is used to prevent this odour.
  • Deodorants contain parabens (methyl, ethyl, propyl, benzyl and butyl) and also alcohol in large proportions. Aluminium compounds and silica are also used.
  • Types of deodorants are :
    (a) Ordinary deo: It contains a smaller proportion of aluminium. It decreases the odour of the sweat.
    (b) Antiperspirant deo : This decreases the extent of sweating. It contains about 15% of aluminium chlorohydrate. It clogs the sweat pores on the skin.
    (c) Clinical deo : Some people sweat heavily and it has harmful effects on the skin. Clinical deo is meant for such people. It contains 20 to 25% aluminium. It is used during the night.

Question 8.
Explain how powder coating is done.
Answer:

  • Powder coating is a method of applying a layer harder than paint on the surface of an iron object to prevent rusting.
  • In this method, a polymer resin, a pigment and some other ingredients are melt, mixed, cooled and ground into a uniform powder.
  • This powder is sprayed on the polished metal surface by electrostatic spray deposition (ESD).
  • In this method, the particles of the powder are given an electrostatic charge due to which a uniform layer of the powder sticks to the metal surface.
  • Then the object is heated in the oven along with the coating.
  • A chemical reaction occurs in the layer, resulting in the formation of long cross-linked polymeric chains.
  • This powder coating is highly durable, hard and attractive.
  • Powder coating can be done on plastic and medium density fibre (MDF) board in day to day use as well.

 

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Balbharti Maharashtra State Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Class 9 Science Chapter 13 Carbon: An Important Element Textbook Questions and Answers

1. Select the proper option and complete the statements
(single, all, double, ionic, carbon, give and take, hydrogen, multiple, share, most, covalent)

a. A carbon atom forms a ….……………. bond with other atoms. In this bond the two atoms ….electrons.
Answer:
covalent, share

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

b. All the carbon bonds in a saturated hydrocarbon ….……………. electrons.
Answer:
share

c. At least one carbon bond in an unsaturated hydrocarbon is ….…………… .
Answer:
multiple

d. ….……………. is the essential element in all the organic compounds.
Answer:
Carbon

e. The element hydrogen is present in ….. organic compound.
Answer:
all

2. Answer the following questions

a. Why are carbon and its compounds used as fuels?

Answer:
(i) The name ‘carbon’ is derived from Latin word ‘carbo’meaning coal. In the earth’s crust, carbon is present to an extent of approximately 0.27% in the form of carbonate, coal and petroleum. One of the non-crystalline and amorphous form of carbon is coal. Coal is a fossil fuel.

(ii) Peat, lignite, bituminous and anthracite are the four types of coal in the increasing order of their carbon content and heat produced respectively. Charcoal and coke are the other amorphous forms of carbon used as fuel.

(iii) Compounds of carbon such as hydrocarbons consist of carbon and hydrogen and they are easily combustible. For example, methane (CH4) which occurs in natural gas is highly inflammable. It bums by reacting with oxygen to give a bluish flame. In this reaction, 213 Kcal/mol of heat is given out. Methane bums completely.

Chemical reaction:
CH4 + 2O2 → CO2 + 2H2O + Heat

(iv) Thus when hydrocarbons are burnt in air, large amount of heat is evolved with formation of carbon dioxide (CO2) and water (H2O). Due to evolution of heat on combustion, carbon and its compounds are used as fuels.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

b. In which compound forms does carbon occur?
Answer:
Carbon in its combined state exists as various compounds such as:

  • Carbon dioxide and in the form of carbonates such as calcium carbonate, marble, calamine (ZnCO3).
  • Fossil fuel – coal, petroleum, natural gas.
  • Carbonaceous nutrients – carbohydrates, proteins, fats.
  • Natural fibres – cotton, wool, silk.
  • Hydrocarbons – compound of carbon and hydrogen.

c. Write the uses of the diamond.
Answer:
Uses of diamonds are:

  • Diamonds are used in glass cutting and rock drilling machines.
  • Diamonds are used in ornaments.
  • Diamond knives are used in the eye surgery.
  • Diamond dust is used for polishing other diamonds.
  • Diamond is used to make windows giving protection from radiation in space and in artificial satellites.

3. Explain the difference:

a. Diamond and graphite.

Answer:

Diamond  Graphite
(i) Diamond is a brilliant, hard and crystalline allotrope of carbon. (i) Graphite is a black, soft, brittle and slippery crystalline allotrope of carbon.
(ii) In diamonds, every carbon atom is bonded to four neighbouring atoms by covalent bonds forming tetragonal three dimensional structure which makes it very hard. (ii) In graphite, every carbon atom is bonded to three other carbon atoms by covalent bonds in such a way that a hexagonal layered structure is formed. A graphite crystal is made of many such layers of carbon atoms. These layers slip over each other on applying pressure.
(iii) Density of diamond is 3.5 g/cm3. (iii) Density of graphite is 1.9 to 2.3 g/cm3.
(iv) Diamond is a bad conductor of electricity as it does not have free electrons. (iv) Inside each layer of graphite, free electrons move continuously within the entire layer. Hence, graphite is a good conductor of electricity.

b. Crystalline and non-crystalline forms of carbon.
Answer:

Crystalline forms of carbon Non-crystalline forms of carbon
(i) A crystalline form has a regular and definite arrangement of atoms.
(ii) They have high melting points and boiling points.
(iii) A crystalline form has a definite geometrical shape, sharp edges and plane surfaces.
(iv) Diamond, graphite and fullerene are different crystalline forms of carbon.
(i) A non-crystalline form does not have a regular and definite arrangement of atoms.
(ii) They have low melting points and boiling points.
(iii) They are amorphous, hence, they do not have definite geometrical shape.
(iv) Coal, charcoal and coke are different non­crystalline/amorphous forms of carbon.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

4. Write scientific reasons

a. Graphite is a conductor of electricity.
Answer:

  • In graphite, each carbon is bonded to three other carbon atoms in such a way that a hexagonal layered structure is formed.
  • Due to this structure, graphite has free electrons available.
  • These free electrons move continuously within the entire layer.
  • Hence, graphite is a good conductor of electricity.

b. Graphite is not used in ornaments.
Answer:

  • Graphite is a black, soft, brittle and dull form of carbon.
  • It is neither malleable nor ductile.
  • These properties of graphite make it unsuitable for making of ornaments.
  • Hence, graphite is not used for making ornaments.

c. Limewater turns milky when CO2 is passed through it.
Answer:

  • Limewater traditionally means a weak solution of the alkali calcium hydroxide Ca(OH)2.
  • When CO2 is passed through limewater, it reacts with calcium hydroxide to form insoluble particulates (precipitate) of Calcium carbonate (CaCO3).
  • Calcium carbonate is weak basic salt and this gives a milky white precipitate.
  • Hence, lime water turns milky when CO2 gas is passed through it.

d. Biogas is an eco-friendly fuel.
Answer:

  • Biogas is formed by the decomposition of animal dung, dry leaves, wet garbage in a biogas plant.
  • This produces methane gas also called biogas.
  • Biogas is a very cheap fuel option which meets the demand for cooking gas.
  • Biogas is eco-friendly as it contains about 55% to 60% of methane and rest is carbon dioxide, hence, on combustion it does not produce harmful gases which cause pollution.
  • Biogas is a fuel which is convenient to use and in addition to this it produces a very good manure as a side product of the process.
  • Hence, biogas is an eco-friendly fuel.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

5. Explain the following.

a. Diamond, graphite and fullerenes are crystalline forms of carbon.
Answer:

  • Carbon exhibits a property of allotropy in which an element exists in more than one form in nature.
  • The chemical properties of these different forms are the same but their physical properties are different.
  • Carbon exists in crystalline as well as non-crystalline (amorphous form).
  • Crystalline form has a regular and definite arrangement of atoms. They have high melting points and boiling points.
  • A crystalline form has a definite geometrical shape, sharp edges and plane surfaces.
  • Carbon has three crystalline allotropes such as diamond, graphite and fullerene.
  • In the structure of diamond, every carbon atom is bonded to four neighbouring atoms by covalent bonds.
  • Therefore, diamond has a tetragonal three dimensional structure which makes it very hard.
  • Brilliant and pure diamond is the hardest natural substance.
  •  In the structure of graphite, every carbon atom in graphite is bonded to three other carbon atoms in such a way that a hexagonal layered structure is formed.
  • A graphite crystal is made of many sheets or layers of carbon atoms.
  • These layers slip over each other on applying pressure. One layer of graphite is called graphene.
  • Fullerene is rarely found in nature. It is found in soot and in interstellar space.
  • The first example of fullerene is Buckminster fullerene (C60).
  • This allotrope of carbon is named fullerene after the architect.
  • Richard Buckminster Fuller because the structure of C60 resembles the structure of the geodesic dome he designed.
  • (xi) Molecules of fullerenes are found in the form of buckyballs and buckytubes.
  • (xii) There are 30 to 900 carbon atoms in one molecule of a fullerene. , C60, C70, C76, C82 and C86 are other examples of fullerene. Their molecules occur in small numbers in soot.

b. Methane is called marsh gas.
Answer:

  • Methane is formed by the decomposition of plant and animal matter in swamps or marshy areas.
  • As methane gas bubbles out from marshy area, it is called as marsh gas.

c. Petrol, diesel, coal are fossil fuels.
Answer:
(i) A fossil fuel is a fuel formed by natural processes, such as anaerobic decomposition of buried dead organisms. Fossil fuels contain high percentage of carbon. The word carbon is derived from the Latin word ‘Carbo’ meaning coal.

(ii) Coal is formed from the remains of trees and other vegetation. Approximately 350 million years ago, these remains were trapped on the bottom of swamps, accumulating layer after layer and creating a dense material called peat. As this peat was buried under more and more ground, the high temperature and pressure transformed it into coal.

(iii) Petrol and diesel are obtained from mineral oil. Mineral oil also called as crude oil or petroleum oil is formed from the remains of plants and animals that lived in the seas millions of years ago. This plant and animal matter has been drawn down and subjected to extremes of temperature and pressure over millions of years ago.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

(iv) Mineral oil is commonly formed in rocks under the sea bed. The word petroleum is derived from Latin word ‘Rock oil’. Petrol and Diesel are obtained from mineral oil by the process called as fractional distillation.
Thus petrol, diesel and coal are fossil fuels.

d. Uses of various allotropes of carbon.

e. Use of CO2 in fire extinguisher.
Answer:

  • CO2 based fire extinguishers do not cause corrosion and are non-conductors of electricity.
  • It is beyond their capacity to extinguish a big fire.
  • Therefore these fire extinguishers are used to extinguish small scale fire of electrical and electronic equipments.

f. Practical uses of CO2.
Answer:
Practical uses of CO2 are:

  • CO2 is used to make aerated drinks.
  • CO2 obtained by chemical reaction or kept under pressure is used in fire extinguishers. Liquified CO2 is used to remove caffeine from coffee.
  • Liquid CO2 is used as solvent in modem eco-friendly dry cleaning.
  • Solid carbon dioxide is used in cold storage and to keep milk and milk products and frozen substances cool during transport. It is also used for getting special effects of a mist in dramas and movies.

6. Write two physical properties each.

a. Diamond
Answer:
Properties of diamond are:

  • Brilliant and pure diamond is the hardest natural substance.
  • The density of diamond is 3.5 g/cm3.
  • The melting point of diamond is 3500 °C.
  • When a diamond is heated at 800 °C in the presence of oxygen, CO2 is given away. In this process no other product besides CO2 is formed.
  • Diamond does not dissolve in any solvent.
  • Acids/bases have no effect on diamond.
  • Diamond is a bad conductor of electricity as it does not have free electrons.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

b. Charcoal
Answer:

  • The charcoal that is made from animals is made from their bones, horns, etc.
  • On the other hand, the charcoal made from plants is formed by combustion of wood in an insufficient supply of air.

c. Fullerene
Answer:
Properties of fullerenes are:

  • Molecules of fullerenes are found in the form of buckyballs and buckytubes.
  • There are 30 to 900 carbon atoms in one molecule of a fullerene.
  • Fullerenes are soluble in organic solvents such as carbon disulphide, chlorobenzene.

7. Complete the following Chemical reactions.

1. ………………..+………………..→ CO + 2H2O + Heat
2. ………………..+………………..→ HCl + Cl + HCl
3. 2 NaOH + CO2 →………………..+………………..
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 1

8. Write answers to the following in detail.

a. What are the different types of coal? What are their uses?
Answer:
Coal is a fossil fuel. It contains carbon, hydrogen and oxygen. It also contains nitrogen, phosphorus and sulphur. It occurs in the solid state. It is of four types.

  • Peat: Formation of peat is the first step in the formation of coal. It contains a high proportion
    of water and less than 60% of carbon. Therefore, not much heat can be obtained from peat.
  • Lignite: Peat was transformed into Lignite due to increased pressure and temperature inside the earth. It contains 60 to 70% of carbon.- Lignite is the second step of the formation of coal.
  • Bituminous coal: Bituminous coal was formed as the third step of formation of coal. It contains 70 to 90% of carbon.
  • Anthracite: Anthracite is known as the pure form of coal. This coal is hard and contains about 95% of carbon.

Uses of coal:

  • Coal is used as fuel in factories and homes.
  • Coal is used to obtain coke, coal gas and coal tar.
  • Coal is used in thermal power plants for generation of electricity.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

b. How will you prove experimentally that graphite is good conductor of electricity?
Answer:
Apparatus required: Lead pendi, electrical wires, battery/cell, small bulb, etc.

Step-I: Remove the lead from a pencil and assemble the apparatus as shown in the diagram.
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 28

Step-II:

  • Start the electric current in the circuit, the moment the electric current is passed through the circuit, the bulb glows.
  • This experiment proves that graphite is a good conductor of electricity as graphite has free electrons moving continuously within the entire layer and these free electrons conduct electricity in the lead of the pencil.

c. Explain the properties of carbon.
Answer:
Allotropic nature of Carbon: Some elements occur in nature in more than one form. The chemical properties of these different forms are the same but their physical properties are different. This property of elements is called allotropy. Carbon shows the property of allotropy.

Carbon allotropes are of two types:
(A) Crystalline forms:
Carbon has three crystalline allotropes: Diamond, Graphite and Fullerene. Properties of crystalline forms of carbon are as follows:

  • A crystalline form has a regular and definite arrangement of atoms.
  • They are made up of only carbon atoms.
  • They have high melting points and boiling points.
  • A crystalline form has a definite geometrical shape, sharp edges and plane surfaces.

(B) Amorphous forms or non-crystalline forms: Coal, charcoal, coke are the non-crystalline forms of carbon.
Properties of non-crystalline forms of carbon are as follows:

  • The arrangement of carbon atoms in this form is not regular.
  • Apart from carbon atoms, they also contain hydrogen, oxygen, nitrogen, phosphorus and sulfur atoms.
  • Compared to a crystalline form, they have low melting and boiling points.
  • Most of them are used as fuels.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

d. Classify carbon.
Answer:
Carbon is classified as follows:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 2

9. How will you verify the properties of carbon dioxide?
Answer:
Properties of carbon dioxide can be verified in the following ways:

  • When a burning candle is placed in a gas jar of carbon dioxide, it extinguishes indicating that carbon dioxide is a non-combustible gas and does not support combustion.
  • When carbon dioxide gas is passed through lime water, it turns lime water milky due to the formation of insoluble calcium carbonate.
  • Moist blue litmus turns red in a gas jar of carbon dioxide indicating, it is acidic in nature.
  • Carbon dioxide is fairly soluble in water, it dissolves in water forming carbonic acid.

Class 9 Science Chapter 13 Carbon: An Important Element Intext Questions and Answers

Can you recall?

Question 1.
Whatremains behind on complete combustion of any organic compound?
Answer:
A black colour substance ‘Carbon’ remains behind on complete combustion of any organic compound.

Question 2.
What type of element is carbon? Give some information about it.
Answer:

  • Carbon is a non-metallic element. It is available ‘ abundantly in the nature and occurs in free as well as combined state.
  • Carbon in free state is found as diamond and graphite and in combined state it is present to the extent of approximately 0.27% in the form of carbonate, coal, petroleum.
  • In atmosphere, the proportion of carbon in the form of carbon dioxide is approximately 0.03%.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 3.
What is an element? What are the different types of elements.
Answer:

  • A substance which cannot be decomposed into simple substances by any physical or simple chemical method is called as an Element.
  • An element is composed of atoms of only one kind.
  • The different types of elements are:
    (a) Metals – Examples: Gold, Silver, etc.
    (b) Non-metals – Examples: Carbon, Sulphur, etc.
    (c) Metalloids – Examples: Silicon, Antimony, etc.

Answer the following questions:

Question 1.
Does an electric charge form on atoms when a covalent bond is formed between them? Why is a single bond between two carbon atoms strong and stable?
Answer:

  • No, electric charge is not formed on atoms when a covalent bond is formed between them. This is because covalent bond is formed by sharing of electrons.
  • Therefore, there is no change in number of electrons and protons in these atoms and they remain electrically neutral.
  • Covalent bonds occur when electrons are shared between two atoms. A single covalent bond is formed when only one pair of electrons is shared between atoms.
  • In this sharing, the atomic orbitals directly overlap between the nuclei of two atoms forming the strongest type of covalent bond called as sigma bond.
  • Hence, a single covalent bond between two carbon atoms is strong and stable.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 2.
In which of the solvents – water, kerosene and cooking oil does the coal powder dissolve?
Answer:
Solvents such as water, kerosene and cooking oil do not dissolve coal powder in them.

Question 3.
What inference will you draw about the solubility of carbon?
Answer:
Carbon is insoluble in water, kerosene and cooking oil.

Question 4.
Is the density of CO2 more or less than that of air?
Answer:

  1. Density is defined as mass per unit volume of a substance, expressed as kilograms per cubic meter.
  2. At standard temperature and pressure, the density of air is 1.29 kg/m3. While that of carbon dioxide (CO2) is 1.79 kg/m3. Hence, density of CO2 is more than that of air.

Question 5.
What is a compound? How are compounds formed?
Answer:

  • A compound is a substance formed when two or more elements are chemically bonded with each other in definite proportion by weight.
  • When atoms or two or more different elements chemically react with each other in a definite proportion by weight, a compound is formed. Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element
  • The properties of a compound are altogether different from its constituent elements.
  • Example: Pure water is a compound made up of two elements Hydrogen and Oxygen. Hydrogen (H) atoms and oxygen (O) atoms have chemically reacted with each other in definite proportion to form a compound-water (H2O). The proportion of hydrogen and oxygen in water by volume is 2 : 1 and by weight is 1 :8 respectively.
  • The properties of water are altogether different from the properties of its constituent elements, hydrogen and oxygen.

Class 9 Science Chapter 13 Carbon: An Important Element Additional Important Questions and Answers

Choose and write the correct option:

Question 1.
The organic compound having double or triple bond in them is termed as
(a) unsaturated
(b) inorganic
(c) saturated
(d) complete
Answer:
(a) Unsaturated hydrocarbon

Question 2.
Covalent compounds are generally soluble in solvents.
(a) inorganic
(b) organic
(c) mixed
(d) mineral
Answer:
(b) organic

Question 3.
Methane is also called as
(a) maha gas
(b) mar’s gas
(c) Anthracite
(d) marsh gas
Answer:
(d) Marsh gas

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 4.
is an alio trope of carbon used to make ornaments.
Answer:
Diamond

Question 5.
The number of valence electrons in carbon is
(a) 4
(b) 5
(c) 6
(d) 3
Answer:
(a) 4

Question 6.
In saturated hydrocarbons, two carbon atoms are linked by
(a) double bond
(b) triple bond
(c) multiple bond
(d) single bond
Answer:
(d) single bond

Question 7.
Carbon has 4 valence electrons in its outermost shell, hence, it is
(a) divalent
(b) tetravalent
(c) trivalent
(d) pentavalent
Answer:
(b) tetravalent

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 8.
Methanogenic bacteria act on the organic acids to produce
(a) oxygen gas
(b) nitrogen gas
(c) methane gas
(d) carbon dioxide gas
Answer:
(c) Methane gas

Question 9.
is used to remove caffeine from coffee.
(a) liquefied O2
(b) liquefied N2
(c) liquefied CO2
(d) liquefied CH4
Answer:
(c) Liquified CO2

Question 10.
Exhaled air contains about CO2.
(a) 4%
(b) 3%
(c) 5%
(d) 6%
Answer:
(a) 4%

Question 11.
Electronic configuration of carbon is
(a) (2, 2)
(b) (2,4)
(c) (2, 5,4)
(d) (2, 6)
Answer:
(b) 2, 4

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 12.
Molecular formula of ethane is
(a) C3H4
(b) C2H4
(c) C2H6
(d) C2H2
Answer:
(c) C2H6

Question 13.
Molecular mass of carbon dioxide is
(a) 28
(b) 22
(c) 56
(d) 44
Answer:
(d) 44

Question 14.
On heating a mixture of hydrogen and carbon monoxide gases at 300°C in the presence of nickel (catalyst) is formed.
(a) carbon dioxide gas
(b) oxygen gas
(c) methane gas
(d) ethylene gas
Answer:
(c) methane gas

Question 15.
Ethane with molecular formula C2H6 has covalent bonds.
(a) six
(b) seven
(c) eight
(d) nine
Answer:
(b) seven

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 15.
Weight of Kohinoor Diamond was
(a) 186 carats
(b) 27 carats
(c) 252 carats
(d) 23 carats
Answer:
(a) 186 carats

Question 16.
Covalent compounds have
(a) high melting point
(b) low melting point
(c) moderate melting point
(d) very high melting point
Answer:
(b) low melting point

Question 17.
Methane is
(a) C2H6
(b) C3H8
(C) CH2
(d) CH4
Answer:
(d) CH4

Question 18.
Wohler, a German scientist synthesized the compound from an inorganic compound ammonium cyanate.
(a) methane
(b) ethylene
(c) urea
(d) acetic acid
Answer:
(c) urea

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 19.
Molecular mass of methane is
(a) 19
(b) 16
(c) 17
(d) 18
Answer:
(b) 16

Question 20.
coal contains highest percentage of carbon.
(a) Bituminous
(b) Peat
(c) Anthracite
(d) Lignite
Answer:
(c) Anthracite

Question 21.
H2C = CH2 is ……………………… .
(a) Propane
(b) Ethyne
(c) Ethane
(d) Ethene
Answer:
(d) Ethene

Question 22.
CH3 – C = CH is ……………………… .
(a) Propene
(b) Propyne
(c) Ethyne
(d) Ethene
Answer:
(b) Propyne

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 23.
Carbon dioxide gas is not used in
(a) photosynthesis
(b) aerated drinks
(c) glass cutting
(d) fire extinguishers
Answer:
(c) glass cutting

Question 24.
Melting point of diamond is
(a) 3700 °C
(b) 3500 °C
(c) 4000 °C
(d) 2500 °C
Answer:
(b) 3500 °C

Question 25.
Melting point of C02 is
(a) 26 °C
(b) 56 °C
(c)-56.6°C
(d)-98°C
Answer:
(c) -56.6 °C

Question 26.
Melting point o* methane is
(a) -182.5 °C
(b) -161.5 °C
(c) 182.5 °C
(d) 161.5 °C
Answer:
(a) -182.5 °C

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 27.
Biogas contains about methane.
(a) 55% to 60%
(b) 20% to 25%
(c) 90% to 95%
(d) 40% to 45%
Answer:
(a) 55% to 60%

Question 28.
is not a property of carbon dioxide gas.
(a) Supporting combustion
(b) Odourless
(c) Colourless
(d) Turns blue litmus red
Answer:
(a) Supporting combustion

Name the following:

Question 1.
Industries that use methane in the form of natural gas.
Answer:
Fabric mills, paper mills, food processing industry, petrol purification.

Question 2.
Organic compounds prepared from methane.
Answer:
Ethanol, methyl chloride, methylene chloride, acetylene.

Question 3.
Chemicals used in regular fire extinguisher.
Answer:
Sodium bicarbonate and dilute sulphuric acid.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 4.
Components of biogas
Answer:
Methane, carbon dioxide

Question 5.
Organic solvents is which fullerenes are soluble.
Answer:
Carbon disulfide, chlorobenzene.

Question 6.
Use of carbon dioxide is dramas and movies
Answer:
The special effect of mist.

Match the columns:

Question 1.

Column ‘A’ Column ‘B’
(1) Diamond
(2) Fullerenes
(3) Graphite
(a) Hexagonal layered structure
(b) Tetragonal three-dimensional structure
(c) Geodesic dome

Answer:
(1-b),
(2- c),
(3 – a)

Question 2.

Column ‘A’ Column ‘B’
(1) Peat
(2) Lignite
(3) Bituminous
(4) Anthracite
(a) 60-70% of Carbon
(b) 95% of Carbon
(c) less than 60% of Carbon
(d) 70 – 90% of Carbon

Answer:
(1 – c),
(2 – a),
(3 – d),
(4 – b)

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 3.

Column ‘A’ Column ‘B’
(1) Propyne
(2) Propene
(3) Propane
(a) CH3 – CH2 – CH3
(b) CH3 – C = CH
(c) CH3 – CH = CH2

Answer:
(1 – b),
(2 – c),
(3 – a)

Question 4.

Column ‘A’ Column ‘B’
(1) Fullerene
(2) Diamond
(3) Graphite
(a) Lubricants
(b) Insulator
(c) Ornaments

Answer:
(1 – b),
(2 – c),
(3 – a)

Question 5.

Column ‘A Column ‘B’
(1) Water gas
(2) Methane gas
(3) Producer gas
(4) Carbon dioxide gas
(a) CH4
(b) CO + H2
(c) CO2
(d) CO + H2 + CO2 + N2

Answer:
(1 – b),
(2 – a),
(3 – d),
(4 – c)

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

State whether the following statements are true or false. Correct the false statement.

(1) Study of organic compounds is called as organic chemistry.
(2) Hydrocarbons with double bonds are called as saturated hydrocarbons.
(3) Ethene is saturated hydrocarbon.
(4) Covalent compounds are good conductor of electricity.
(5) Methane is a covalent compound.
(6) Covalent compounds are soluble in organic solvents.
(7) Graphite is used in making lubricants and lead pencils.
(8) The density of diamond is 9.8 g/cm3.
(9) Diamond knives are used in eye surgery.
(10) Fullerenes are used as insulators.
(11) Coke is used in production of water gas i.e. (CO2 + H2O).
(12) Structural formula of propyne is CH3 – C = CH.
(13) COz is used to make aerated drinks.
(14) Methane gas is black in colour.
(15) Production of biogas is aerobic process.
Answer:
(1) True
(2) False. Hydrocarbons with double bonds are called as Unsaturated hydrocarbons.
(3) False. Ethene is Unsaturated hydrocarbon.
(4) False. Covalent compounds are bad conductor of electricity.
(5) True
(6) True
(7) True
(8) False: The density of diamond is 3.5 g/cm3.
(9) True
(10) True
(11) False. Coke is used in production of water gas i.e. (CO + H2).
(12) False. Structural formula of propyne is CH3 – C = CH.
(13) True
(14) False. Methane gas is colourless.
(15) False. Production of biogas is anaerobic process.

Find the odd man out:

Question 1.
Propane, Methane, Ethene, Pentane.
Answer:
Ethene. It is an unsaturated hydrocarbon with double bond between two carbon atoms while rest are saturated hydrocarbons with single bond between two carbon atoms.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 2.
CH4, C2H6, C3H8, CaCO3.
Answer:
CaCO3. It is a salt which is an inorganic’ compound, while rest are hydrocarbon compounds, i.e. organic compounds.

Question 3.
C2H2, C3H8, C2H6, CH4.
Answer:
C2H2. It is an unsaturated hydrocarbon with triple bonds while rest are saturated hydrocarbons with single bonds between two carbon atoms.

Question 4.
Diamond, Fullerene, Graphite, Methane.
Answer:
Methane. It is a marsh gas while rest are allotropes of carbon.

Question 5.
Coal, Petroleum, Natural gas, Cotton
Answer:
Cotton. Cotton is a natural fibre while rest all are fossil fuels.

Question 6.
Cotton, Silk, Proteins, Wool
Answer:
Proteins. Proteins are carbonaceous nutrients while rest all are natural fibres.

Question 7.
Carbohydrates, Coal, Proteins, Fats
Answer:
Coal. Coal is a fossil fuel while rest all are carbonaceous nutrients.

Question 8.
Peat, Charcoal, Lignite, Bituminous
Answer:
Charcoal. Charcoal is a non-crystalline form of carbon while rest all are types of coal.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 9.
Lubricants, Electrodes, Ornaments, Arc Lamps
Answer:
Ornaments. Ornaments are made from diamonds while rest all are made from graphite.

Write the correlated terms:

(1) Propene : Double bond :: Propyne : ……………………. .
(2) Ethane : CH3 – CH3 :: Ethene : ……………………. .
(3) Hydrogen : Monovalent :: Carbon : ……………………. .
(4) Methane : Low melting point i.e. -182.5°C Diamond : ……………………. .
(5) Graphite : Hexagonal structure :: Diamond : ……………………. .
(6) Density of Diamond : 3.5 g/cm3 :: Density of Graphite : ……………………. .
(7) Peat: 60% of carbon :: Anthracite : ……………………. .
(8) Melting point of CO2: -56.6°C :: Melting point of CH4: ……………………. .
Answer:
(1) Triple Bond
(2) CH2 = CH2
(3) Tetravalent
(4) High melting point i.e. 3500°C
(5) Tetragonal structure
(6) 1.9 to 2.3 g/cm3
(7) 95% of carbon
(8) -182.5 °C

Give scientific reasons:

Question 1.
Covalent compounds have low melting and boiling points.
Answer:

  • When substances melt or boil, bonds between the molecules are broken due to heat supplied.
  • On covalent compounds, the intermolecular forces of attraction are weak.
  • Hence, intermolecular forces in covalent compounds are broken easily due to which they have low melting and boiling points.

Question 2.
Graphite is a good conductor of electricity whereas diamond is a non-conductor of electricity.
Answer:

  • In diamond, each carbon atom uses all its four electronic to get bonded to another carbon atom, whereas in graphite each carbon uses there out of four electrons during bonding.
  • Hence in diamond no free electrons are left whereas in graphite free electrons are available.
  • Due to the presence of electron which are free to flow graphite is a good conductor of electricity, whereas due to the absence of free electrons diamond is a non-conductor of electricity.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 3.
Graphite is used as a lubricant.
Answer:

  • Lubricants are used to reduce friction and wear and tear of mechanical parts.
  • Graphite is smooth and slippery and hence is useful in reducing friction. Hence, graphite is used as a lubricant.

Question 4.
Methane is used as a domestic fuel.
Answer:

  • Methane is highly inflammable.
  • It burns by reacting with oxygen to give a bluish flame.
  • It burns completely and producers 213 Kcal/ mol of heat.
  • Being the smallest hydrocarbon, the proportion of CO2 released in the combustion of methane is small.
  • Therefore methane is used as a domestic fuel.

Answer in short:

Question 1.
What was the contribution of chemist Wohier in organic chemistry?
Answer:

  • The German chemist Wohier synthesized an organic compound urca from an inorganic compound ammonium cyanate,
  • Ever since then, many organic compounds have been made from inorganic compounds.
  • Carbon was found to he the main element in all these compounds.
  • Hence, organic chemistry is also referred to as chem is try of carbon corn pounds.

Question 2.
With neat diagram explain the structure of diamond.
Ans.

  • In diamond, every carbon atom is bonded to four neighbouring atoms by covalent bonds.
  • Therefore, diamond has a tetragonal three dimensional structure which makes it very hard.
    Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 29

Question 3.
With neat diagram explain the structure of graphite?
Answer:

  • Every carbon atom in graphite is bonded to three other carbon atoms in such a way that a hexagonal layered structure is formed.
  • A graphite crystal is made of many sheets or layers of carbon atoms.
  • These layers slip over each other on applying pressure.
  • One layer of graphite is called graphene.
    Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 30

Question 4.
Give the properties of graphite.
Answer:
Properties of graphite are:

  • Graphite found in nature is black, soft, brittle and slippery.
  • Inside each layer of graphite, free electrons move continuously within the entire layer. That is why graphite is a good conductor of electricity. Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element
  • Due to the layered structure graphite can be used for writing on paper.
  • The density of graphite is 1.9 to 2.3 g/cm3.
  • Graphite does not dissolve in most solvents.

Question 5.
Give the uses of graphite.
Answer:
Uses of graphite are:

  • Graphite is used for making lubricants.
  • Graphite is used for making carbon electrodes.
  • Graphite is used in pencils for writing.
  • Graphite is used in paints and polish.
  • Graphite is used in arc lamps which gives a very bright light.

Question 6.
Give the uses of fullerenes.
Answer:
Uses of Fullerenes are:

  • Fullerenes are used as insulators.
  • Fullerenes are used as a catalyst in water purification.
  • At a certain temperature, fullerene exhibits superconductivity.

Question 7.
What is Coal?
Answer:

  • Coal is a fossil fuel. It contains carbon, hydrogen and oxygen.
  • It also contains nitrogen, phosphorus and sulphur.
  • It occurs in the solid state. It is of four types – peat, lignite, bituminous and anthracite.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 8.
What is Coke?
Answer:
The pure coal that remains when coal gas has been taken away from coal, is called coke.

Question 9.
Give the uses of Coal.
Answer:
Uses of Coal are:

  • Coal is used as fuel in factories and homes.
  • Coal is used to obtain coke, coal gas and coal tar.
  • Coal is used in thermal power plants for generation of electricity.

Question 10.
Give the uses of Coke.
Answer:
Uses of Coke are:

  • Used as domestic fuel.
  • Coke is used as a reducing agent.
  • Coke is used in production of water gas (CO + H2) and producer gas (CO + H2 + CO2 + N2)

Question 11.
Name the types of coal and give the differences in them.
Answer:
The four types of coal are Peat, Lignite, Bituminous and Anthracite.
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 3

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 12.
Give the properties of covalent compounds.
Answer:
Properties of covalent compounds:

  • Covalent compounds have low melting points and boiling points.
  • Generally they are insoluble in water and soluble in organic solvents.
  • They are poor conductors of heat and electricity.

Question 13.
What are saturated hydrocarbons? Give examples.
Answer:

  • The hydrocarbons having only single bonds between carbon atoms are called saturated hydrocarbons.
  • For example, ethane (C2H6) which is (CH3 – CH3), propane (C3H8) which is (CH3 – CH2 – CH3).

Question 14.
What are unsaturated hydrocarbons? Give examples.
Answer:

  • Some hydrocarbons have a multiple bond between two carbon atoms.
  • A multiple bond can be a double bond or a triple bond.
  • Hydrocarbons having at least one multiple bond are called unsaturated hydrocarbons.
  • For example, ethene (H2C = CH2), ethyne (HC = CH), propene (CH3 – CH = CH2), propyne (CH3 – C = CH).

Question 15.
Give the following information of carbon dioxide: Molecular formula, Molecular mass, Melting point, Percentage occurrence in air.
Answer:
Molecular formula – CO2, Molecular mass – 44, Melting point -56.6 °C Percentage occurrence in air – 0.03%.

Question 16.
Give the physical and chemical properties of carbon dioxide.
Answer:
Physical properties of carbon dioxide are:

  • It is an odourless gas.
  • It is a colourless gas.

Chemical properties of carbon dioxide are:

  • It is non-combustible and does not support combustion.
  • It turns lime water milky.
  • It is fairly soluble in water and dissolves in water forming carbonic acid.
  • It turns blue litmus red indicating it is acidic in nature.
  • The colour of universal indicator turns orange/ yellow in C02 indicating its pH value between 4 and 6, i.e. acidic in nature.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 17.
Give the uses of Carbon dioxide.
Answer:
Uses of Carbon dioxide are:

  • CO2 is used to make aerated drinks
  • Solid carbon dioxide is used in cold storage and also to keep milk and milk products and frozen substances cool during transport. It is also used for getting special effects of a mist in dramas and movies.
  • CO2 obtained by chemical reaction or kept under pressure is used in fire extinguishers.
  • Liquified CO2 is used to remove caffeine from coffee.
  • Liquid CO2 is used as solvent in modern eco-friendly dry cleaning.
  • Plants use CO2 in air for photosynthesis.

Question 18.
Give the occurrence of methane.
Answer:
The occurrence of methane is as follows:

  • Methane occurs in natural gas to the extent of 87%.
  • Decomposition of organic matter in the absence of air (anaerobic) produces methane.
  • Methane is present in biogas.
  • Methane is found in coal mines.
  • Methane is found at the surface of marshy places which is why it is also called marsh gas.
  • On heating a mixture of hydrogen and carbon monoxide gases at 300 °C in the presence of nickel (catalyst), methane gas is formed.
  • Fractional distillation of natural gas gives methane in pure form.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 19.
Give the physical properties of methane.
Answer:
Physical properties of methane are:

  • Melting point of methane is (-182.5 °C).
  • Boiling point of methane is (-161.5 °C).
  • It is a colourless gas.
  • The density of liquid methane is less than that of water.
  • Methane is sparingly soluble in water. It is highly soluble in organic solvents like gasoline, ether and alcohol.
  • Methane is in gaseous state at room temperature.

Question 20.
Give the uses of methane.
Answer:
Uses of methane are:

  • Methane in the form of natural gas is used in industries such as fabric mills, paper mills, food processing industry, petrol purification.
  • Being the smallest hydrocarbon, the proportion of CO2 released in the combustion of methane is small and, therefore, it is used as a domestic fuel.
  • Methane is used for production of organic compounds such as ethanol, methyl chloride, methylene chloride and acetylene.

Question 21.
How is methane formed? Give structural formula and electron dot model of methane.
Answer:

  • Atomic number of carbon is 6. The electronic configuration of carbon is (2, 4). The valency of carbon is 4.
  • Carbon atom can form four covalent bonds with other carbon atoms or atoms of different elements.
  • When a carbon atom shares one electron each with four hydrogen atoms and forms four C-H bonds, a methane (CH4) molecule is formed.
    Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 4

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 22.
What are organic and inorganic compounds?
Answer:
Compounds obtained directly or indirectly from plants and animals are called organic compounds and compounds obtained from minerals are called inorganic compounds.

Question 23.
What is allotropy?
Answer:

  • Allotropy – Some elements occur in nature in more than one form.
  • The chemical properties of these different forms are the same but their physical properties are different.
  • This property of elements is called allotropy.

Question 24.
What are basic organic compounds? What are they also called as?
Answer:

  • The compounds formed from only carbon and hydrogen are called basic organic compounds.
  • These are also called hydrocarbons.

Write a balanced chemical equation and explain the following chemical reactions.

Question 1.
Preparation of urea from Ammonium cyanate:
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 5
Organic compound Urea can be synthesized from an inorganic compound Ammonium cyanate.

Question 2.
Coal when burnt in air
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 6
When coal is burnt in air, the carbon present in coal combines with oxygen present in air to form carbon dioxide gas.

Question 3.
Calcium carbonate reacts with dilute hydrochloric acid:
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 7
When Calcium carbonate reacts with dilute hydrochloric add it forms Caldum chloride, water and Carbon dioxide gas is evolved.

Question 4.
Carbon dioxide is passed through an aqueous solution of Sodium hydroxide:
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 8
When Carbon dioxide gas is passed through an aqueous solution of Sodium hydroxide it forms Sodium carbonate and Water.

Question 5.
Carbon dioxide is passed through an aqueous solution of Sodium carbonate:
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 9
When carbon dioxide is passed through an aqueous solution of Sodium carbonate, it forms Sodium bicarbonate.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 6.
Carbon dioxide is passed through freshly prepared lime water for a short duration and then for longer duration:
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 10
When Carbon dioxide is passed through freshly prepared lime water, it forms water and white precipitate of Calcium carbonate because of which lime water turns milky.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 11
When Carbon dioxide is continuously passed through milky lime water, it forms Calcium bicarbonate which is soluble in water and therefore, water once again turns colourless.

Question 7.
Carbon dioxide gas is dissolved in water.
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 12
Carboh dioxide gas is fairly soluble in water, it dissolves in water under pressure to form Carbonic acid.

Question 8.
Sodium bicarbonate reacts with dilute Sulphuric acid, (reaction in fire extinguisher):
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 13
When Sodium bicarbonate reacts with dilute Sulphuric acid it forms Sodium sulphate, water and Carbon dioxide gas.

Question 9.
Methane gas is burnt in air:
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 14
Methane is highly inflammable, it burns in air with a bluish flame and combines with oxygen present in air to form Carbon dioxide and water. In these reaction 213 kcal/mol of heat is given out.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 10.
Methane and Chlorine gases react with each other.
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 15
Methane and chlorine gases react with each other at the temperature of 250 °C to 400 °C in presence of ultra voilet light and form mainly Methyl chloride (Chloromethane and ‘ Hydrogen chloride)
This reaction is called Chlorination of methane.

Question 11.
Production of methane gas in biogas plant.
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 16
In biogas plant, microbes act on the bio-degradable complex organic compounds and produce organic acids.

The methanogenic bacteria act on the organic acids to produce Methane gas and Carbon dioxide gas.

Question 12.
Production of water gas:
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 17
When super heated steam is passed over red hot coke at high temperature, it forms carbon monoxide gas and hydrogen gas.

This gaseous product of carbon monoxide gas and hydrogen gas together is called as water gas.

With the help of ne abelled diagram explain the following:

Question 1.
Regular fire extinguisher.
Answer:

  • A fire extinguisher contains Sodium bicarbonate powder. There is also dilute sulphuric acid placed in a glass capsule.
  • On pressing the knob, the capsule breaks and sulphuric acid comes in contact with the sodium bicarbonate. These two react chemically to release CO2 which comes out.
  • CO2 based fire extinguishers do not cause corrosion and are non-conductors of electricity. Therefore, they are used when electrical or electronic equipment catches fire. Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element
  • CO2 based fire extinguishers are used to extinguish small scale fire. It is beyond their capacity to extinguish a big fire.
  • In modern fire extinguishers liquid and solid CO2 is filled under pressure. On reducing the pressure, it becomes gaseous and comes out forcefully through the horn-like hose pipe.
  • Chemical reaction:
    Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 18

Question 2.
Biogas plant.
Answer:

  • Animal dung, dry leaves, wet garbage get decomposed by anaerobic microbes in a biogas plant.
  • This produces methane gas, also called biogas.
  • Biogas is a very cheap fuel option which meets the demand for cooking gas. It is also used for the production of electricity.
  • Biogas contains about 55% to 60% methane and the rest is carbon dioxide.
  • Biogas is a fuel which is convenient to use and, in addition to this, a very good manure is also produced as a side product of the process.
  • Biogas production process – Production of biogas is an anaerobic process. It takes place in two stages.
    (a) Production of acids – The microbes act on the biodegradable complex organic compound and produce organic acids.
    (b) Methane gas production – The methanogenic bacteria act on the organic acids to produce methane gas.

Chemical reaction:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 19

Answer the following

Question 1.
What happens when substances like milk, sugar, wool, dry leaves, hair and seeds are heated strongly in hard glass test tube?
Answer:
When milk, sugar, wool, dry leaves, hair and seeds are heated strongly in hard glass test tube, they get charred and a black substance is left behind. This black substance is carbon.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Answer the following questions:

Question 1.
Take some milk in an evaporating dish. Heat the evaporating dish on a bunsen burner. What remains behind at the bottom of an evaporating dish on complete evaporation of the milk?
Answer:

  • On complete evaporation of milk, a black residue is left behind.
  • This residue is of carbon.

Question 2.
Take small samples of sugar, wool, dry leaves, hair, seeds, split pulses and plastic in separate test tubes. Heat each test tube and observe the changes taking place in the substances. What does the black substance in each test tube indicate?
Answer:

  • On heating the above samples, they get charred and a black substance is left behind.
  • The black substance is carbon.

Question 3.
Apparatus : Coal, match box, moist litmus paper, etc.

Procedure : Ignite the coal. Hold the moist blue litmus paper over the gas released on igniting the coal. Note the observation.
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 20

(a) With which gas in the air does the coal react on igniting?
Answer:
Coal reacts with oxygen gas present in the air, on igniting.

(b) What is the substance formed?
Answer:
The substance formed is carbon dioxide.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

(c) What change takes place in the litmus paper?
Answer:
The moist blue litmus paper turns red.

(d) Write down the chemical reaction taking place in the above procedure.
Answer:
(i) Carbon combines with oxygen to form Carbon dioxide gas.
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 21
(ii) This C02 combines with water present on moist blue litmus paper to form Carbonic acid which turns blue litmus to red.
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 22

Question 4.
Apparatus : Pencil, electrical wires, battery/ cell, small bulb, water, kerosene, test tube, lead pencils, etc.

Procedure : Remove the lead from a pencil and arrange the apparatus as shown in the above diagram. Note your observations for the following.
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 23

(a) What is the colour of lead in the pencil? .
Answer:
The colour of the lead in the pencil is black as it is made from graphite which is an allotrophic form of carbon.

(b) Try to break lead with your hand.
Answer:
The lead breaks easily as it is made up of graphite which is brittle in nature.

(c) Start the electric current in the circuit and observe. What did you find?
Answer:
When we start the electric current in the circuit, the bulb in the circuit glows, indicating that the lead in the pencil is a good conductor of electricity.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

(d) Take some water in a test tube. Take some kerosene in another test tube. Put lead dust in both the test tube. What did you observe?
Answer:
(i) Lead dust does not dissolve in water nor in kerosene.
(ii) It remains insoluble in both the test tubes.

Question 5.
Apparatus : Test tube, straw, lime water, etc.

Procedure: Take freshly prepared lime water in a test tube. Blow air in it for some time through the straw and observe the lime water. Note the observation.
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 24

(a) What did you see?
Answer:
When we blow air through the straw in freshly prepared lime water, it turns milky.

(b) What might be the reason behind the change?
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 25
Freshly prepared lime water is obtained by dissolving lime (CaO) in water (H2O).

When we blow air through the straw in lime water, carbon dioxide (CO2) present in the air reacts with lime water to form white precipitate (insoluble substance) of Calcium Carbonate (CaCO3) due to which lime water turns milky.
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 26

Question 6.
With the help of a neat labelled diagram explain the laboratory preparation of Carbon dioxide gas.
Answer:
The laboratory preparation of Carbon dioxide gas is as follows:

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Apparatus : Retort stand, round bottom flask, thistle funnel, gas delivery tube, gas jars.
Chemicals : Calcium carbonate (Pieces of Shahabad tiles/marble pieces/limestone), dilute hydrochloric acid.

Procedure:

  • Assemble the apparatus as shown in the figure. While assembling, place CaCO3 in the round bottom flask.
  • Add dilute HCl in the flask through thistle funnel. See to it that the end of the funnel dips in the acid.
  • CO2 is formed as a result of the reaction between CaCO3 and HCl. Collect this gas in four to five gas jars. The chemical equation of the above reaction is as follows. CaCO3 + 2HCl → CaCl2 + H2O + CO2
    Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 27

 

Maharashtra Board Class 10 Hindi Lokbharti Solutions Chapter 2 लक्ष्मी

Balbharti Maharashtra State Board Class 10 Hindi Solutions Lokbharti Chapter 2 लक्ष्मी Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 10 Hindi Lokbharti Chapter 2 लक्ष्मी

Hindi Lokbharti 10th Std Digest Chapter 2 लक्ष्मी Textbook Questions and Answers

सूचना के अनयुार कृहत्‍ँ कीहजए:

प्रश्न 1.
संजाल पूण् कीहजए:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 1
उत्तर:

प्रश्न 2.
उचित घटनाक्रम लगाकर वाक्य फिर से लिखिए:
१. उसके गले में रस्सी थी।
२. रहमान बड़ा मूर्ख है।
३. वह लक्ष्मी को सड़क पर ले आया।
४. उसने तुम्हें बड़ी बेदर्दी से पीटा है।
उत्तर:
(i) उसने तुम्हें बेदर्दी से पीटा है।
(ii) रहमान बड़ा मूर्ख है।
(iii) उसके गले में रस्सी थी।
(iv) वह लक्ष्मी को सड़क पर ले आया।

प्रश्न 3.
उततर हलखखए:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 2

उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 21

Maharashtra Board Solutions

प्रश्न 4.
गलत वाक्य, सही करके लिखिए:
१. करामत अली पिछले चार सालों से गाय की सेवा करता चला आ रहा था।
२. करामत अली को लक्ष्मी की पीठ पर रोगन लगाने के बाद इत्मीनान हुआ।
उत्तर:
(i) करामत अली पिछले एक साल से गाय की सेवा करता चला आ रहा था।
(ii) करामत अली को लक्ष्मी की पीठ पर रोगन लगाने के बाद भी इत्मीनान नहीं हुआ।

प्रश्न 5.
हनम्हलखखत मयु्दो के आधार पर वर्णन कीहजए:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 3
उत्तर:

प्रश्न 6.
कारण हलखखए:
a. करामत अली लक्ष्मी के हलए सानी तैयार करने लगा।
b. रमजानी ने करामत अली को रोगन हदया।
c. रिमान ने लक् को इलाके से भहर तोडा हदया।
d. करामत अली ने लक् को गऊशाला मे भरती हकया।
उत्तर:
a. सुबह से रमजानी या रहमान किसी ने भी लक्ष्मी को चारा, दर्रा कुछ भी नहीं दिया था। लक्ष्मी बहुत भूखी थी।
b. रहमान के मारने के कारण लक्ष्मी की पीठ पर चोट आई थी।
c. रहमान ने सोचा कि लक्ष्मी नाले के पास उगी दूब खाकर पेट भर लेगी।
d. पैसे की तंगी के कारण करामत अली लक्ष्मी के दाने-चारे का प्रबंध नहीं कर पा रहा था। वह लक्ष्मी को भूखों मरता नहीं देख सकता था।

प्रश्न 7.
हिंदी-मराठी मे समोच्ररत शब् के हभन नर् हलखखए:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 4
उत्तर:

 हिंदी मराठी
(1) खत  पत्र  खाद
(2) पीठ  पीठ (शरीर का अंग)  आटा
(3) खाना  भोजन  दराज
(4) चारा  उपाय  जानवरों को खिलाने की सामग्री
(5) कल  बीता हुआ अथवा आने वाला समय (कल)  रुझान, प्रवृत्ति

Maharashtra Board Solutions

प्रश्न.
यदि आप करामत अली की जगि पर होते तो’ इस संदभ् मे अपने हिचार लिखिए।
उत्तर:
करामत अली दोस्त को दिए गए वचन को निभाने वाला और पशु की पीड़ा समझने वाला इन्सान है। यदि करामत अली की जगह मैं होती/होता तो मैं भी वही करती/करता, जो करामत अली ने किया। जब हम किसी पशु को पालते हैं, तो उसकी सुख-सुविधा और खाने-पीने की उचित व्यवस्था करना हमारी जिम्मेदारी होती है। यदि मेरे समक्ष करामत अली जैसी स्थिति (आर्थिक संकट) उत्पन्न होती, तो मैं भी अपने पालतू पशु को भूखा मरते देखने या उसे कसाई के हाथों बेचने के स्थान पर किसी अच्छे पशुघर (गऊशाला) में ही दाखिल कराती/कराता। पशुघर में अपने जैसे अन्य पशुओं के साथ मेरा प्रिय पशु भी सुखपूर्वक अपना शेष जीवन बिता सकता। इससे मुझे बहुत संतोष होता।

भाषा बिंदु
प्रश्न 1.
निम्नलिखित वाक्यों में उचित विरामचिह्नों का प्रयोग कर वाक्य पुनः लिखिए:

१. ओह कंबख्त ने कितनी बेदर्दी से पीटा है
२. मैंने कराहते हुए पूछा मैं कहाँ हूँ
३. मँझली भाभी मुट्ठी भर बँदियाँ सूप में फेंककर चली गई
४. बड़ी बेटी ने ससुराल से संवाद भेजा है उसकी ननद रूठी हुई है मोथी की शीतलपाटी के लिए
५. केवल टीका नथुनी और बिछिया रख लिए थे
६. ठहरो मैं माँ से जाकर कहती हूँ इतनी बड़ी बात
७. टाँग का टूटना यानी सार्वजनिक अस्पताल में कुछ दिन रहना
८. जल्दी-जल्दी पैर बढ़ा
९. लक्ष्मी चल अरे गऊशाला यहाँ से दो किलोमीटर दर है
१०. मानो उनकी एक आँख पूछ रही हो कहो कविता कैसी रही

प्रश्न 2.
निम्नलिखित विरामचिह्नों का उपयोग करते हुए बारह-पंद्रह वाक्यों का परिच्छेद लिखिए:

विरामचिह्न वाक्य
?
;
,
!
‘ ’
‘‘ ’’
x x x
— 0 —
……………
( )
[ ]
^
:
-/ Maharashtra Board Solutions

उत्तर:

विरामचिह्न वाक्य
लक्ष्मी बड़ी भयभीत और घबराई हुई थी।
मालिक आज दर्रा-खली कुछ नहीं।
? कौन खरीदेगा इस बूढ़ी गाय को?
; हिंदी साहित्य के विकास; उन्नति में डायरी का भी योगदान है।
, देखो, मुझे गाय बेचनी ही नहीं है।
! ये देखो चाचाजी!
‘ ’ गोआ में ‘सी-फूड’ की अधिकता है।
‘‘ ’’ “ऐसी कोई विशेष बात नहीं है।”
x x x हे ग्रामदेवता नमस्कार xxx
– ० – इस तरह राजा – ० – रानी सुख से रहने लगे।
…………… तुम इस गाय को लेकर क्या करोगे…..?
( ) रवींद्रनाथ ठाकुर का [(बंगला भाषा) अनुवादित (अनूदित)] साहित्य सभी पढ़ते हैं।
[ ] रवींद्रनाथ ठाकुर का [(बंगला भाषा) अनुवादित (अनूदित)] साहित्य सभी पढ़ते हैं।
^ मामा जी आगरा से आएँगे।
: मनु (हँसते हुए): मैंने तो लड्डू का डिब्बा देखा भी नहीं।
-/ परीक्षार्थी उत्तीर्ण/अनुत्तीर्ण में से एक तो अवश्य होगा।

प्रश्न.
हकसी पालतूप्री की आतमकरा हलखखए।
उत्तर:
ऐसे अनेक जानवर हैं, जो या तो संख्या में कम हैं या बदलते पर्यावरण और परभक्षण मानकों के कारण लुप्तप्राय हो रहे हैं। साथ ही वनों की कटाई के कारण भोजन और पानी की कमी हो जाना भी इनकी आबादी कम होने का कारण है। भारतीय वन्थ जीवों में अनूप मृग, चौसिंगा, कस्तूरी मृग, नीलगाय, चीतल, कृष्णमृग, एक सींग वाला गैंडा, सांभर, गोर, जंगली सूअर आदि दुर्लभ प्रजातियाँ हैं।

पर्यावरण संतुलन में इन जीवों की भूमिका अत्यंत महत्त्वपूर्ण है। इन प्रजातियों में बड़ी तेजी से गिरावट आ रही है। भारत में स्तनपायी वन्य जीवों की 81 प्रजातियाँ संकटग्रस्त हैं। इनमें से कुछ हैं-शेर, चीता, बाघ, सफेद तेंदुआ, गैंडा, जंगली भैंसा, जंगली सूअर, लाल पांडा, चिम्पैंजी, नीलगिरि लंगूर, बारहसिंगा, कस्तूरी मृग, नीलगिरि हिरन, चौसिंगा हिरन, कश्मीरी हिरन आदि।

कुत्ते की आत्मकथा
मैं गलियों में मारा-मारा फिरने वाला एक कुत्ता हूँ। मैंने अपने जीवन में बहुत सुख-दुख सहे हैं। मैं आपको अपनी व्यथा-कथा सुनाता हूँ।

मेरी माँ एक किसान-परिवार की पालतू कुतिया थी। उसी के घर में मेरा जन्म हुआ था। मेरा रंग दूध की तरह सफेद था। बच्चे-बूढ़े सभी मुझे प्यार से उठा लेते थे। वे मुझे गोद में लेकर सहलाते। लोग मुझे तरह-तरह की चीजें खाने के लिए देते थे। मैं बहुत खुश था।

एक दिन उस किसान ने मुझे एक अमीर आदमी के हाथों सौंप दिया। मेरा मालिक मुझे पाकर बहुत खुश हुआ। वह मेरा बहुत ख्याल रखता था। वह मुझे ‘टॉमी’ कहकर बुलाता था। जहाँ भी जाता, वह अपने साथ मुझे ले जाता था।

मैं भी अपने मालिक की बहुत सेवा करता था। रात के समय में उसके बँगले की रखवाली करता था। मालिक के बच्चे मुझे बहुत प्यार करते थे। लेकिन सब दिन एक समान नहीं होते। धीरे-धीरे मेरा स्वास्थ्य गिरने लगा। मैं कमजोर होता चला गया। न मैं अब पहले जैसा ताकतवर रहा और न ही सुंदर। इसलिए मेरे प्रति मालिक और उसके परिवार का रुख बदल गया।

मेरे बुढ़ापे ने मुझे कहीं का नहीं रखा। मुझे अब अपना जीवन बोझ-सा लगने लगा है। मैं पेट भरने के लिए मारा-मारा फिरता हूँ। जिसके दरवाजे पर पहुँचता हूँ, वही दो डंडे जमा देता है। (यहाँ पर ‘कुत्ते की आत्मकथा’ नमूने के रूप में दी गई है। विद्यार्थी अपनी पसंद के पालतू प्राणी की आत्मकथा लिखें।)

Maharashtra Board Solutions

Hindi Lokbharti 10th Textbook Solutions Chapter 2 लक्ष्मी Additional Important Questions and Answers

गद्यांश क्र. 1
प्रश्न.
निम्नलिखित पठित गद्यांश पढ़कर दी गई सूचनाओं के अनुसार कृतियाँ कीजिए:

कृति 1: (आकलन)
(1) कारण लिखिए:
(i) रहमान ने लक्ष्मी की पीठ पर डंडे बरसा दिए।
उत्तर:
(i) लक्ष्मी ने दूध नहीं दिया था।

(2) संजाल पूर्ण कीजिए:

उत्तर:

कृति 2: (आकलन)
• संजाल पूर्ण कीजिए:

उत्तर:

कृति 3: (शब्द संपदा)
(1) गद्यांश में प्रयुक्त शब्द-युग्म ढूँढकर लिखिए।
(i) …………………
(ii) …………………
(iii) …………………
(iv) …………………
उत्तर:
(i) उछलती-कूदती
(ii) दो – चार
(iii) धीरे-धीरे
(iv) इधर-उधर।

Maharashtra Board Solutions

(2) निम्नलिखित शब्दों के लिंग बदलकर लिखिए:
(i) गाय
(ii) बेटी
(iii) रस्सी
(iv) खूटा।
उत्तर:
(i) गाय – बैल
(ii) बेटी – बेटा
(iii) रस्सी – रस्सा
(iv) खूटा – खूटी।

कृति 4: (स्वमत अभिव्यक्ति)

प्रश्न.
पालतू जानवरों के साथ किए जाने वाले सौहार्दपूर्ण व्यवहारों के बारे में अपने विचार 25 से 30 शब्दों में लिखिए।
उत्तर:
जानवरों का मनुष्य के जीवन में बहुत महत्त्व है। इसलिए प्राचीन काल से पशु मनुष्य के साथी रहे हैं। गाय, बैल, भैंस, कुत्ता, घोड़ा आदि जानवर हमारे लिए बहुत उपयोगी हैं। पालतू पशु मनुष्य के परिवार के सदस्य जैसे होते हैं। हमें उन्हें प्रेम से पालना चाहिए। हमें उनके प्रति सौहार्दपूर्ण व्यवहार रखना चाहिए। उन्हें उचित समय पर अच्छी खुराक देनी चाहिए।

उनकी साफ-सफाई का ध्यान रखना चाहिए। पशु मूक प्राणी होते हैं। वे अपना दुख-दर्द बता नहीं सकते। इसलिए मनुष्य को उनके भोजन के साथ-साथ उनकी भावनाओं को भी समझना जरूरी है। ये जानवर हमारे प्रति भी सद्व्यवहार और स्नेह रखते हैं। उनकी अच्छी देखभाल करना हमारा कर्तव्य है।

गद्यांश क्र. 2
प्रश्न.
निम्नलिखित पठित गद्यांश पढ़कर दी गई सूचनाओं के अनुसार कृतियाँ कीजिए:

कृति 1: (आकलन)
(1) संजाल पूर्ण कीजिए:
(i)
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 11
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 14

(ii)

उत्तर:

(iii)
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 13
उत्तर:

Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 16

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(2) आकृति पूर्ण कीजिए:
(i) लक्ष्मी शांत खड़ी जख्मों पर यह लगवाती – [ ]
(ii) लक्ष्मी की पीठ पर रोगन लगाने के बाद भी करामत अली को यह नहीं हुआ – [ ]
उत्तर:
(i) लक्ष्मी शांत खड़ी जख्मों पर यह लगवाती रही – [तेल]
(ii) लक्ष्मी की पीठ पर रोगन लगाने के बाद भी करामत अली को यह नहीं हुआ – [इत्मीनान]

कृति 2: (आकलन)
(1) उत्तर लिखिए:
(i)

उत्तर:

(ii)

उत्तर:

कृति 3: (शब्द संपदा)
(1) निम्नलिखित शब्दों के समानार्थी शब्द लिखिए:
(i) बरस
(ii) गाय
(iii) दूध
(iv) जरूरत।
उत्तर:
(i) बरस – साल
(ii) गाय – धेनु
(iii) दूध – दुग्ध
(iv) जरूरत – आवश्यकता।

(2) निम्नलिखित शब्दों का वचन बदलकर लिखिए:
(i) निशानी
(ii) समस्या
(iii) बेटी
(iv) जरूरत।
उत्तर:
(i) निशानी – निशानियाँ
(ii) समस्या – समस्याएँ
(iii) बेटी – बेटियाँ
(iv) जरूरत – जरूरतें।

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(3) गद्यांश में प्रयुक्त उर्दू शब्द ढूँढकर लिखिए।
(i) ……………….
(ii) ……………….
(iii) ……………….
(iv) ……………….
उत्तर:
(i) मवेशी
(ii) शौक
(iii) जरूरत
(iv) खुशनसीबी।

(4)
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 25
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 26

कृति 4: (स्वमत अभिव्यक्ति)

प्रश्न.
पशुपालन के विषय पर 25 से 30 शब्दों में अपने विचार लिखिए।
उत्तर:
आदि मानव जब से एक स्थान पर समूह बनाकर रहने और खेती करने लगा, तभी से मनुष्यों और पशुओं का साथ रहा है। कृषि कार्य में उसे कई पशुओं को पालतू बनाना पड़ा था। भारतीय समाज में पशुपालन की परंपरा तभी से चली आ रही है। देश के प्रत्येक कृषक की यह इच्छा रहती है कि उसके पास बैलों की एक जोड़ी और एक गाय अवश्य हो।

ये जानवर उसके लिए मात्र खेती में काम आने वाले, दूध देने वाले, सवारी तथा रखवाली के काम आने वाले ही नहीं होते, वरन ये कृषक परिवार का अभिन्न अंग होते हैं। घर के सभी सदस्यों को इनसे अत्यंत प्रेम होता है। ये अपने बच्चों के समान इन पशुओं के खान-पान और इनकी सुख-सुविधा का ध्यान रखते हैं।

गद्यांश क्र. 3

प्रश्न.
निम्नलिखित पठित गद्यांश पढ़कर दी गई सूचनाओं के अनुसार कृतियाँ कीजिए:

कृति 1: (आकलन)
कारण लिखिए:
(a) करामत अली लक्ष्मी को बेचना नहीं चाहता था।
उत्तर:
(a) करामत अली जानता था कि बूढ़ी लक्ष्मी को अगर कोई खरीदेगा तो वह उसे काट-काटकर बेचने के लिए ही खरीदेगा।

Maharashtra Board Solutions

कृति 2: (आकलन)
(1) आकृति पूर्ण कीजिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 27
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 29

(2) उत्तर लिखिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 28
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 30

(ii) रमजानी ने संदूकची से यह निकाला – [ ]
उत्तर:
(ii) रमजानी ने संदूकची से यह निकाला – [बीस का एक नोट]

कृति 3: (शब्द संपदा)
(1) निम्नलिखित शब्दों के विरुद्धार्थी शब्द लिखिए:
(i) विशेष
(ii) बूढ़ी
(iii) आसान
(iv) बेचना।
उत्तर:
(i) विशेष x सामान्य
(ii) बूढ़ी x युवा
(iii) आसान x कठिन
(iv) बेचना x खरीदना।

(2) निम्नलिखित शब्दों के लिंग पहचानकर लिखिए:
(i) दूध
(ii) परेशानी
(iii) जमाना
(iv) सानी।
उत्तर:
(i) दूध – पुल्लिंग
(ii) परेशानी – स्त्रीलिंग
(iii) जमाना – पुल्लिग
(iv) सानी – स्त्रीलिंग।

Maharashtra Board Solutions

कृति 4: (स्वमत अभिव्यक्ति)

प्रश्न.
मानव और पशु के संबंध के विषय में 25 से 30 शब्दों में अपने विचार लिखिए।
उत्तर:
आदि-मानव पशुओं का शिकार पेट भरने के लिए करता था। कालांतर में उसने पशुओं का शिकार छोड़कर कृषि करना सीखा, साथ ही पशुओं को पालकर उनसे काम लेना प्रारंभ किया। गाय, बैल, घोड़ा और कुत्ता आदि हमारे बहुत अच्छे मित्र हैं। उनसे हमारे अनेक कार्य सिद्ध होते हैं। पशु अपनी मित्रता में सदा खरे उतरे हैं। उन्होंने मानव की हर तरह से सेवा की है। कुत्ता एक स्वामिभक्त जानवर है। अपने मालिक के लिए यह अपने प्राण भी न्योछावर कर देता है। सुरक्षा करने, मार्ग दिखाने आदि में कुत्ता अतुलनीय भूमिका निभाता है। संकट में फंसे लोगों को बचाने में भी कुत्ते बहुत कुशल होते हैं। कुत्तों में सूंघने की अद्भुत शक्ति होती है। कुत्ते पुलिस के काम में बहुत सहायता करते हैं।

गद्यांश क्र.4
प्रश्न.
निम्नलिखित पठित गद्यांश पढ़कर दी गई सूचनाओं के अनुसार कृतियाँ कीजिए:

कृति 1: (आकलन)
(1) (i) आकृति पूर्ण कीजिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 31
उत्तर:

Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 34

(ii)
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 32
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 35

(2) संजाल पूर्ण कीजिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 33
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 36

Maharashtra Board Solutions

कृति 2: (आकलन)
(1) कारण लिखिए:
(i) लक्ष्मी को कांजी हाउस में पहुँचाने की धमकी देना
(ii) माँ-बेटे को आश्चर्य होना
(iii) रहमान ने लक्ष्मी को इलाके से बाहर छोड़ दिया।
उत्तर:
(i) क्योंकि लक्ष्मी दूसरे व्यक्ति की गाय का सब चारा खा गई है।
(ii) क्योंकि लक्ष्मी एक-डेढ घंटे बाद ही घर के सामने खड़ी थी।

(2) केवल एक/दो शब्दों में उत्तर लिखिए:
(i) करामत अली इस समय ड्यूटी से लौटा – ……………………….
(ii) दूसरों की गाय का चारा खाने वाली – ……………………….
(ii) रमजानी इसकी बातें सुनती रही – ……………………….
(iv) लक्ष्मी को देखकर आश्चर्यचकित होने वाले – ……………………….
उत्तर:
(i) दोपहर बाद।
(ii) लक्ष्मी
(iii) आगंतुक की।
(iv) माँ – बेटे।

(3) आकृति पूर्ण कीजिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 37
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 38

कृति 3: (शब्द संपदा)
(1) निम्नलिखित शब्दों के समानार्थी शब्द लिखिए: –
(i) दिन
(ii) घर
(iii) माँ
(iv) आश्चर्य।
उत्तर:
(i) दिन = दिवस
(ii) घर = सदन
(iii) माँ = जननी
(iv) आश्चर्य = अचरज।

(2) निम्नलिखित शब्दों का वचन बदलकर लिखिए:
(i) इलाका
(ii) आँखें
(iii) गली
(iv) नाला।
उत्तर:
(i) इलाका – इलाके
(ii) आँखें – आँख
(iii) गली – गलियाँ
(iv) नाला – नाले।

(3) लिंग पहचानकर लिखिए:
(i) रस्सी – ……………………….
(ii) झाड़-झंखाड़ – ……………………….
उत्तर:
(i) रस्सी-स्त्रीलिंग
(ii) झाड़-झंखाड़-पुल्लिग।

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(4) गद्यांश में प्रयुक्त निम्नलिखित शब्द के भिन्न-भिन्न अर्थ लिखिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 39
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 40

कृति 4: (स्वमत अभिव्यक्ति)

प्रश्न.
‘कांजी हाउस में पशुओं के रखरखाव’ विषय पर 25 से 30 शब्दों में अपने विचार लिखिए।
उत्तर:
कांजी हाउस सरकार द्वारा संचालित एक केंद्र (पशुधर) होता है। यहाँ उन पशुओं को रखा जाता है, जो लावारिस इधर-उधर घूमते रहते हैं और खेतों में घुसकर लोगों की फसल को नुकसान पहुँचाते हैं। शिकायतकर्ता इन पशुओं को कांजी हाउस में भेज देते हैं। इन पशुओं का नियमपूर्वक रिकॉर्ड रखा जाता है। इनके मालिक जब इन्हें लेने आते हैं तो उनसे जुर्माना वसूल कर पशु उनके हवाले कर दिए जाते हैं। यदि लंबे समय तक किसी पशु की खोज-खबर लेने कोई नहीं आता, तो उसे नीलाम कर दिया जाता है। कांजी हाउस में इन पशुओं के खान-पान का कोई ध्यान नहीं रखा जाता।

गद्यांश क्र. 5
कृति 1: (आकलन)
(1) दो ऐसे प्रश्न बनाकर लिखिए जिनके उत्तर निम्नलिखित शब्द हों:
(i) लक्ष्मी
(ii) गऊशाला में।
उत्तर:
(i) टुकड़े-टुकड़े होकर कौन बिक जाएगी?
(ii) करामत अली लक्ष्मी को कहाँ भरती करा देगा?

(2) संजाल पूर्ण कीजिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 41
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 42

कृति 2: (आकलन)
(1) संजाल पूर्ण कीजिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 43
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 2 लक्ष्मी 44

(2) कारण लिखिए:
(a) लक्ष्मी बिना किसी रुकावट के करामत अली के पीछे-पीछे चली आ रही थी।
उत्तर:
(a) लक्ष्मी करामत अली के प्रेम को पहचानती थी। वह जानती थी कि करामत अली उसे किसी भी प्रकार का नुकसान नहीं पहुंचाएगा।

Maharashtra Board Solutions

(3) एक-दो शब्दों में उत्तर लिखिए:
(i) रमजानी ने किसके चेहरे के भाव भाँप लिए?
(ii) रमजानी कहाँ खड़ी लक्ष्मी को बाहर ले जाते देखती रही?
उत्तर:
(i) करामत अली
(ii) दरवाजे पर।

कृति 3: (शब्द संपदा)
(1) निम्नलिखित शब्दों के विरुद्धार्थी शब्द लिखिए:
(i) दोस्त
(ii) रात
(iii) सवेरा
(iv) बाहर।
उत्तर:
(i) दोस्त x दुश्मन
(ii) रात x दिन
(iii) सवेरा x साँझ
(iv) बाहर x भीतर।

(2) गद्यांश में प्रयुक्त उर्दू के शब्द ढूँढकर लिखिए।
(i) ………………..
(ii) ………………..
(ii) ………………..
(iv) ………………..
उत्तर:
(i) किस्मत
(ii) खुद
(iii) हुज्जत
(iv) इत्मीनान।

(3) गद्यांश में प्रयुक्त शब्द-युग्म ढूँढकर लिखिए।
(i) ………………..
(ii) ………………..
(ii) ………………..
(iv) ………………..
उत्तर:
(i) मुँह-हाथ
(ii) पीछे-पीछे
(iii) थके-माँदे
(iv) खाए-पिए।

भाषा अध्ययन (व्याकरण)
प्रश्न, सूचनाओं के अनुसार कृतियाँ कीजिए:
1. शब्द भेद:
• अधोरेखांकित शब्दों का शब्दभेद पहचानकर लिखिए:
(i) वह लक्ष्मी को किसी भी हालत में बेचना नहीं चाहता था।
(ii) रामू ने देखा कि दूध नदारद!
(iii) राशन के लिए कुछ रुपए रखे थे।
उत्तर:
(i) वह – पुरुषवाचक सर्वनाम ।
(ii) दूध – द्रव्यवाचक संज्ञा।
(iii) कुछ – संख्यावाचक विशेषण।

2. अव्यय:
निम्नलिखित अव्ययों का अपने वाक्यों में प्रयोग कीजिए:
(i) और
(ii) जहाँ
(iii) अरे!
(iv) अरे रे!
उत्तर:
(i) लक्ष्मी ने चारे को सूंघा और फिर उसकी ओर निराशा से देखने लगी।
(ii) जहाँ इसकी किस्मत में होगा, वहीं छोड़ आऊँगा।
(iii) अरे। लक्ष्मी जल्दी चल।
(iv) अरे रे! साँप ने उसे काट लिया।

Maharashtra Board Solutions

3. संधि:
कृति पूर्ण कीजिए:

संधि शब्द  संधि विच्छेद  संधि भेद
निराशा  …………………… ……………………
अथवा
…………………..  अति + अंत ……………………

उत्तर:

संधि शब्द  संधि विच्छेद  संधि भेद
निराशा निः + आशा विसर्ग संधि
अथवा
अत्यंत  अति + अंत स्वर संधि

4. सहायक क्रिया:
निम्नलिखित वाक्यों में से सहायक क्रियाएँ पहचानकर उनका मूल रूप लिखिए:
(i) रमजानी काम में जुट गई।
(ii) रहमान ने लक्ष्मी को घर से निकालने के लिए कमर कस ली।
(iii) लक्ष्मी ने घास छोड़ दिया।

सहायक क्रिया  मूल रूप
(i) गई  जाना
(ii) ली  लेना
(iii) दिया  देना

5. प्रेरणार्थक क्रिया:
निम्नलिखित क्रियाओं के प्रथम प्रेरणार्थक और द्वितीय प्रेरणार्थक रूप लिखिए:
(i) मिलना
(ii) पीना
(iii) बनना।
उत्तर:

क्रिया  प्रथम प्रेरणार्थक रूप  द्वितीय प्रेरणार्थक रूप
(i) मिलना  मिलाना  मिलवाना
(ii) पीना  पिलाना  पिलवाना
(i) बनना  बनाना  बनवाना

6. मुहावरे:
(1) मुहावरों का अर्थ लिखकर वाक्य में प्रयोग कीजिए:
(i) चंपत होना
(ii) कमर कसना
(iii) ताँता लगना
उत्तर:
(i) चंपत होना।
अर्थ: गायब होना।
वाक्य: पुलिस को देखकर चोर चंपत हो गया

(ii) कमर कसना।
अर्थ: तैयार होना।
वाक्य: अकाल का मुकाबला करने के लिए लोगों ने कमर कस ली

(iii) ताँता लगना।
अर्थ: कतार लग जाना, भीड़ लगना।
वाक्य: गांधी जी के दर्शनों के लिए आश्रम में हमेशा लोगों का तांता लगा रहता।

Maharashtra Board Solutions

(2) अधोरेखांकित वाक्यांश के लिए कोष्ठक में दिए गए उचित मुहावरे का चयन करके वाक्य फिर से लिखिए: (पैर पकड़ना, जान में जान आना, ताँता बंध जाना)
(i) वर्षा होने पर किसानों को धीरज प्राप्त हुआ
(ii) रमण ने पिता जी से क्षमा याचना की
उत्तर:
(i) वर्षा होने पर किसानों की जान में जान आई
(ii) रमण ने पिता जी के पैर पकड़े

7. कारक:
निम्नलिखित वाक्यों में प्रयुक्त कारक पहचानकर उनका भेद लिखिए:
(i) कंबख्त ने कितनी बेरहमी से पीटा है।
(ii) लक्ष्मी ने आज भी दूध नहीं दिया।
(iii) उसने लक्ष्मी के माथे पर हाथ फेरा।
उत्तर:
(i) बेरहमी से-करण कारक
(ii) लक्ष्मी ने-कर्ता कारक
(iii) माथे पर-अधिकरण कारक।

8. काल परिवर्तन:
निम्नलिखित वाक्यों का सूचना के अनुसार काल परिवर्तन कीजिए:
(i) लक्ष्मी उसकी ओर देखती है। (अपूर्ण भूतकाल)
(ii) रहमान लक्ष्मी को मारता है। (पूर्ण वर्तमानकाल)
(iii) लक्ष्मी बड़ी घबराई हुई है। (पूर्ण भूतकाल)
उत्तर:
(i) लक्ष्मी उसकी ओर देख रही थी।
(ii) रहमान ने लक्ष्मी को मारा है।
(iii) लक्ष्मी बड़ी घबराई हुई थी।

9. वाक्य भेद:
(1) निम्नलिखित वाक्यों का रचना के आधार पर भेद पहचानकर लिखिए:
(i) रमजानी खड़ी थी और आगंतुक की बातें सुन रही थी।
(ii) जो भी गाय के पास जाता, वह उसे सिर मारने की कोशिश करती।
उत्तर:
(i) संयुक्त वाक्य
(ii) मिश्र वाक्य।

(2) निम्नलिखित वाक्यों का अर्थ के आधार पर दी गई सूचना के अनुसार वाक्य परिवर्तन कीजिए:
(i) करामत अली ने लक्ष्मी की पीठ सहलाई। (निषेधवाचक वाक्य)
(ii) यह तुम्हारा पुराना धंधा है। (प्रश्नवाचक वाक्य)
उत्तर:
(i) करामत अली ने लक्ष्मी की पीठ नहीं सहलाई।
(i) क्या यह तुम्हारा पुराना धंधा है?

Maharashtra Board Solutions

10. वाक्य शुद्धिकरण:
निम्नलिखित वाक्य शुद्ध करके लिखिए:
(i) लक्ष्मी की आँख में आँसू आई।
(ii) नईम का आवाज करामत के कान में पहुंचा।
(iii) मामला लक्ष्मी को गऊशाला ले जाने पर ठिक हो गई।
उत्तर:
(i) लक्ष्मी की आँखों में आँसू आए
(ii) नईम की आवाज करामत के कान में पहुंची
(iii) मामला लक्ष्मी को गऊशाला ले जाने पर ठीक हो गया

लक्ष्मी Summary in Hindi

लक्ष्मी विषय – प्रवेश :

लक्ष्मी मवेशियों के शौकीन ज्ञान सिंह की अधेड़ उम्र की प्रिय गाय थी। नौकरी से अवकाश के बाद ज्ञान सिंह को मकान खाली करने की नौबत आई तो लक्ष्मी को रखने की समस्या आई। उसका हल उन्होंने निकाला अपने पड़ोसी और दोस्त करामत अली को लक्ष्मी को सौंप देने से। करामत अली जी – जान से लक्ष्मी की सेवा करते थे, पर जब लक्ष्मी ने दूध देना बंद कर दिया, तो वह उनके परिवार के लिए समस्या बन गई।

प्रस्तुत कहानी में कहानीकार गुरुबचन सिंह ने एक ओर मित्र को दिए गए वचन के पालन पर बल दिया है, तो दूसरी ओर प्राणिमात्र के प्रति दया – भावना को प्रतिपादित किया है। कहानी में दर्शाया गया है कि अनुपयोगी हो जाने के बाद भी पालतू प्राणियों की उचित देखभाल करना आवश्यक है।

लक्ष्मी मुहावरे – अर्थ

  • मुँह मारना – जल्दी – जल्दी खाना।
  • गला भर आना – भाव विह्वल होना, आवाज भर आना।
  • हाथ थामना – सहारा देना।
  • कोरा जवाब देना – साफ मना करना।
  • तैश में आना – आवेश (जोश) में आना।

Maharashtra Board Class 10 Hindi Lokbharti Solutions Chapter 5 गोवा जैसा मैंने देखा

Balbharti Maharashtra State Board Class 10 Hindi Solutions Lokbharti Chapter 5 गोवा जैसा मैंने देखा Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 10 Hindi Lokbharti Chapter 5 गोवा : जैसा मैंने देखा

Hindi Lokbharti 10th Std Digest Chapter 5 गोवा जैसा मैंने देखा Textbook Questions and Answers

कृति

सूचना के अनुसार कृतियाँ कीजिए:

प्रश्न 1.
प्रवाह तालिका पूर्ण कीजिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 29
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 26

प्रश्न 2.
कृति पूर्ण कीजिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 30
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 9

प्रश्न 3.
लिखिए
a. नीले पानीवाला पथरीला –
b. रेतीला तथा उथला –
c. सबसे लंबा –
d. मछुआरों की पहली पसंद –
उत्तर:
(i) नीले पानीवाला पथरीला – अंजुना बीच
(ii) रेतीला तथा उथला – बेनालियम बीच
(iii) सबसे लंबा – कलिंगवुड बीच
(iv) मछुआरों की पहली पसंद – बेनालियम बीच।

प्रश्न 4.
सूची बनाइए:

गोवा का प्राकृतिक सौंदर्य दर्शाने वाले वाक्य
१.
२.
३.
४. Maharashtra Board Solutions

उत्तर:

गोवा का प्राकृतिक सौंदर्य दर्शाने वाले वाक्य
(i) हरीतिमा से भरपूर
(ii)  खूबसूरत सफेद रेतीले समुद्र तट
(iii) चंद्रमा की चाँदनी में नहाया समुद्र
(iv) गहरा नीला पानी।

प्रश्न 5.
कृति पूर्ण कीजिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 32

उत्तर:
(1) नवरात्रि की परंपराएँ –
(i) घरों में, गली-मोहल्लों में माँ दुर्गा की घटस्थापना।
(ii) लड़कियों द्वारा गरबा का पर्व मनाना।

(ii) दशहरा की परंपराएँ –
(1) सुबह लोग अपने वाहनों की सफाई करके उनकी पूजा करते हैं।
(2) शाम को भगवान की एक पालकी मंदिर ले जाई जाती है और लोग एक विशेष पेड़ की पत्तियाँ तोड़कर एक-दूसरे को देकर बधाई देते हैं।

प्रश्न 6.
‘बेनालिया’, ‘अंजुना’ तथा ‘कलिंगवुड’ बीच की विशेषताएँ:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 33
उत्तर:
बेनालियम –
(1) यह बीच उथला और रेतीला है।
(2) यहाँ सुबह-सुबह बड़ी मात्रा में मछलियाँ पकड़ी जाती हैं।
(3) यह बीच मछुआरों की पहली पसंद है।

अंजुना –
(1) यह गहरा और नीले पानीवाला खूबसूरत बीच है।
(2) इस पथरीले बीच के एक ओर लंबी-सी पहाड़ी है।
(3) यह बीच बॉलीवुड की पहली पसंद है। यहाँ कई हिट फिल्मों की शूटिंग हुई है।

कलिंगवुड –
(1) यह काफी रेतीला बीच है।
(2) यह बीच 3 से 4 किमी. तक फैला हुआ है।
(3) यह गोवा का सबसे लंबा बीच है।

Maharashtra Board Solutions

प्रश्न 7.
सोचिए और लिखिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 34
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 28

अभिव्यक्ति-

प्रकृति को सुंदर बनाए रखने में मेरा योगदान’ विषय पर अपने विचार लिखिए।
उत्तर:
हम इस ब्रह्मांड के सबसे सुंदर, हरियाली से युक्त और बेहद आकर्षक ग्रह धरती पर निवास करते हैं। प्रकृति हम इन्सानों को ईश्वर द्वारा दिया गया सबसे खूबसूरत उपहार है। सुंदर पुष्प, आकर्षक पक्षी, वनस्पति, नीला आकाश, भूमि, समुद्र, जंगल, पर्वत, पठार, सूरज, चाँद इस सुंदर प्रकृति का हिस्सा हैं। स्वस्थ जीवन के लिए प्रकृति बहुत आवश्यक है। मैं इस बात का सदा ध्यान रखता हूँ कि यथासंभव प्रकृति की रक्षा कर सकूँ। मैं जब भी बाहर पार्क या बगीचे में जाता है, अनावश्यक रूप से किसी भी फूल-पत्ते को नहीं तोड़ता।

वहाँ खेलते हुए बच्चों को भी फूल-पत्ते तोड़ने से मना करता हूँ, उन्हें समझाता हूँ। मैं एक स्काउट लीडर हूँ। प्रकृति को बचाने के लिए लोगों में जागरूकता फैलाने का प्रयास करता हूँ। अन्य स्काउट्स के साथ मिलकर रैली निकलवाता हूँ कि घर के बाहर कचरा न फैलाएँ, प्लास्टिक की थैलियों के स्थान पर कपड़े के थैलों का प्रयोग करें।

भाषा बिंद

प्रश्न 1.
कोष्ठक में दी गई संज्ञाओं से विशेषण संलग्न हैं। नीचे दी गई सारिणी में संज्ञा तथा विशेषणों को भेदों सहित लिखिए: [भयभीत गाय, नीला पानी, दस लीटर दूध, चालीस छात्र, कुछ लोग, दो गज जमीन, वही पानी, यह लड़का]

संज्ञा  भेद  विशेषण  भेद
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उत्तर:

संज्ञा  भेद  विशेषण  भेद
(1) गाय  जातिवाचक  भयभीत  गुणवाचक
(2) पानी  द्रव्यवाचक  नीला  गणवाचक
(3) दूध  द्रव्यवाचक  दस लीटर  परिमाणवाचक
(4) छात्र  जातिवाचक  चालीस  संख्यावाचक
(5) लोग  समूहवाचक  कुछ सार्वनामिक
(6) जमीन  जातिवाचक  दो गज  परिमाणवाचक
(7) पानी  द्रव्यवाचक  वही  सार्वनामिक
(8) लड़का  जातिवाचक  यह  सार्वनामिक

Maharashtra Board Solutions

प्रश्न 2.
उपर्युक्त संज्ञा-विशेषणों की जोड़ियों का स्वतंत्र वाक्यों में प्रयोग कीजिए।
उत्तर:
(i) भयभीत गाय – लाठियों के डर से भयभीत गाय इधर-उधर दौड़ रही थी।
(ii) नीला पानी – झील का नीला पानी चाँद की रोशनी में चमक रहा था।
(iii) दस लीटर दूध – हमारी गाय दोनों समय दस लीटर दूध देती है।
(iv) चालीस छात्र – स्वाति की कक्षा में चालीस छात्र हैं।
(v) कुछ लोग – छत पर कुछ लोग चहलकदमी कर रहे हैं।
(vi) दो गज जमीन – औरंगजेब सारी उम्र युद्ध करता रहा। अंत में उसे अपनी दिल्ली में दो गज जमीन भी नहीं मिली।
(vii) वही पानी – यह वही पानी है, जो कल भरा था।
(viii) यह लड़का – यह लड़का चोर नहीं है।

प्रश्न 3.
पाठ में प्रयुक्त विशेषणों को ढूँढ़कर उनकी सूची बनाइए।
उत्तर:

  • समुद्री
  • खूबसूरत
  • सफेद
  • सांस्कृतिक
  • शांत
  • शीतल
  • स्थानीय
  • रोमांचक
  • सुस्वादु
  • शाकाहारी।।

प्रश्न 4.
निम्नलिखित वाक्यों में आई हुईं सहायक क्रियाओं को अधोरेखांकित कीजिए तथा उनका अर्थपूर्ण वाक्यों में प्रयोग कीजिए:
(i). टैक्सी एक पतली-सी सड़क पर दौड़ पड़ी।
वाक्य = ……………………………..

(ii). शरीर को कुछ समय के लिए विश्राम मिल जाता है।
वाक्य = ……………………………..

(iii). हम आराम करने के इरादे से अपने-अपने स्यूट चले गए।
वाक्य = ……………………………..

(iv). फिर भी धूप तीखी ही होती जाती है।
वाक्य = ……………………………..

(v). सबके बावजूद यह अपने में एक सांस्कृतिक विरासत भी समेटे हुए हैं।
वाक्य = ……………………………..

(vi). इधर बच्चे रेत का घर बनाने लगे।
वाक्य = ……………………………..

(vii). अब समुद्र स्याह और भयावह दिखने लगा।
वाक्य = ……………………………..

(viii). यहाँ सुबह-सुबह बड़ी मात्रा में मछलियाँ पकड़ी जाती हैं।
वाक्य = ……………………………..
उत्तर:
(i) टैक्सी एक पतली-सी सड़क पर दौड़ पड़ी।
वाक्य – गोली की आवाज सुनकर उड़ती हुई चिड़िया नीचे गिर पड़ी।

(ii) शरीर को कुछ समय के लिए विश्राम मिल जाता है।
वाक्य – सरदियों में सूरज जल्दी छिप जाता है।

(iii) हम आराम करने के इरादे से अपने-अपने स्यूट में चले गए।
वाक्य – बिटिया के विदा होते ही सारे मेहमान चले गए।

(iv) फिर भी धूप तीखी ही होती है।
वाक्य – प्रातःकाल आकाश की आभा मनोरम होती है।

(v) सबके बावजूद यह अपने में एक सांस्कृतिक विरासत भी समेटे हुए है।
वाक्य – जल्दी कक्षा में पहुँचो, विद्यार्थी खाली बैठे हुए हैं।

(vi) इधर बच्चे रेत का घर बनाने लगे।
वाक्य – पिता जी तेजी से दौड़ने लगे।

(vii) अब समुद्र स्याह और भयावह दिखने लगा।
वाक्य – बेटा, अब उठो। सूरज दिखने लगा।

(viii) यहाँ सुबह-सुबह बड़ी मात्रा में मछलियाँ पकड़ी जाती हैं।
वाक्य – गुजरात में मकर संक्रांति के दिन सुबह से रात तक पतंग उड़ाई जाती हैं।

Maharashtra Board Solutions

प्रश्न 5.
पाठ में प्रयुक्त दस सहायक क्रियाएँ छाँटकर लिखिए।
उत्तर:

  • हो उठता है।
  • चले आते हैं।
  • देते हैं।
  • जा पहुँचा।
  • हो गए।
  • रुक गई।
  • पकड़े हुए है।
  • भाग रहे थे।
  • दौड़ पड़ी।
  • बटौं हुआ है।

उपयोजित लेखन-

विजय/विजया मोहिते, वरदा सोसाइटी, विजयनगर, कोल्हापुर से व्यवस्थापक, औषधि भंडार, नागपुर को पत्र लिखकर आयुर्वेदिक औषधियों की माँग करता/करती है।
उत्तर:
5/7/2020
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औषधि भंडार,
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Hindi Lokbharti 10th Textbook Solutions Chapter 5 गोवा जैसा मैंने देखा Additional Important Questions and Answers

कृतिपत्रिका के प्रश्न 1 (अ) तथा प्रश्न 1 (आ) के लिए)

गद्यांश क्र. 1

प्रश्न.
निम्नलिखित पठित गद्यांश पढ़कर दी गई सूचनाओं के अनुसार कृतियाँ कीजिए:

Maharashtra Board Solutions

कृति 1: (आकलन)

प्रश्न 1.
आकृति पूर्ण कीजिए:
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 1
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 2

प्रश्न 2.
गलत वाक्यों को सही करके लिखिए:
(i) देश के मध्य में स्थित होने के कारण यह छोटा-सा राज्य प्रत्येक पर्यटक के दिल की धड़कन है।
(ii) शीतल हवा के झोंकों से मन प्रसन्न हो गया और यात्रा की चिंता मिट गई।
उत्तर:
(i) देश के एक कोने में स्थित होने के कारण यह छोटा-सा राज्य प्रत्येक पर्यटक के दिल की धड़कन है।
(ii) शीतल हवा के झोंकों से मन प्रसन्न हो गया और यात्रा की सारी थकान मिट गई।

प्रश्न 3.
संजाल पूर्ण कीजिए: (बोर्ड की नमूना कृतिपत्रिका)
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 3
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 4

प्रश्न 4.
एक-दो शब्दों में उत्तर: लिखिए: (बोर्ड की नमूना कृतिपत्रिका)
(i) लेखक का ध्यान अपनी ओर खींचने वाला – [ ]
(ii) समस्याओं से निजात पाने का सबसे अच्छा तरीका – [ ]
(iii) लेखक के सफर का साधन – [ ]
(iv) लेखक के मड़गाँव में पहुँचने का दिन – [ ]
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 5

कृति 2: (आकलन)

प्रश्न 1.
आकृति पूर्ण कीजिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 6
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 7

प्रश्न 2.
उत्तर: लिखिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 10
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 11

Maharashtra Board Solutions

कृति 3: (शब्द संपदा)

प्रश्न 1.
गद्यांश में प्रयुक्त २ प्रत्यययुक्त शब्द ढूँढकर लिखिए। – (बोर्ड की नमूना कृतिपत्रिका)
(i) _____________
(ii) _____________
उत्तर:
(i) तरंगायित
(ii) प्रत्येक

प्रश्न 2.
निम्नलिखित शब्दों को वर्तनी के नियमानुसार लिखिए:
(i) त्रंगाइत
(ii) आर्कषन
(iii) ओप्चारिक
(iv) खानपुर्ती।
उत्तर:
(i) गाइत -तरंगायित
(ii) आर्कषन -आकर्षण
(iii) ओप्चारिक -औपचारिक
(iv) खानपुर्ती -खानापूर्ति।

प्रश्न 3.
निम्नलिखित शब्दों के विलोम शब्द गद्यांश से ढूँढ़कर लिखिए: (बोर्ड की नमूना कृतिपत्रिका)
(i) अप्रसन्न x _____________
(ii) बुरा x _____________
उत्तर:
(i) अप्रसन्न x प्रसन्न
(ii) बुरा x अच्छा।

कृति 4: (स्वमत अभिव्यक्ति)

प्रश्न.
‘आनंद प्राप्ति का साधन: पर्यटन’ विषय पर अपने विचार 25 से 30 शब्दों में लिखिए। (बोर्ड की नमूना कृतिपत्रिका)
उत्तर:
पर्यटन से हमारे ज्ञान में वृद्धि होती है। किसी स्थान के बारे में पढ़कर जानकारियाँ प्राप्त करने और उसे प्रत्यक्ष देखने में अंतर होता है। यह सुख हमें पर्यटन से प्राप्त होता है। पर्यटन से हमें भिन्नभिन्न प्रदेशों और देशों के प्रसिद्ध स्थलों एवं धरोहरों को देखने का अवसर मिलता है। उनकी संस्कृतियों, उनके रहन-सहन और रीतिरिवाजों को प्रत्यक्ष देखने का मौका मिलता है। इससे हम एक-दूसरे के करीब आते हैं। वहाँ हुए विकास कार्यों से प्रेरणा लेते हैं। इसके अतिरिक्त पर्यटन से अपने रोजमर्रा के कार्यों से कुछ दिन दूर रहने और निश्चित होकर देश-दुनिया को देखने, उससे कुछ सीखने और अपने आप में सुधार करने तथा तनावों से मुक्त रहने का अवसर मिलता है। इस तरह पर्यटन निश्चित रूप से आनंद प्राप्ति का एक सुंदर और मनोरंजक साधन है।

गद्यांश क्र. 2

प्रश्न.
निम्नलिखित पठित गद्यांश पढ़कर दी गई सूचनाओं के अनुसार कृतियाँ कीजिए:

ति 1: (आकलन)

प्रश्न 1.
सही विकल्प चुनकर वाक्य फिर से लिखिए:

(i) गोवा की __________________ बड़ी अच्छी होती है। (सुबह/शाम/रात)
(ii) __________________ सागर देखने का उत्साह बढ़ता जा रहा था। (अरब/हिंद/बंगाल)
(iii) यही __________________ का सत्य भी है। (लोगों/दुनिया/जीवन)
(iv) __________________ सुस्ताने के लिए किनारे पर बैठ जाते हैं। (कुत्ते/पक्षी/लोग)
उत्तर:
(i) गोवा की शाम बड़ी अच्छी होती है।
(ii) अरब सागर देखने का उत्साह बढ़ता जा रहा था।
(iii) यही जीवन का सत्य भी है।
(iv) पक्षी सुस्ताने के लिए किनारे पर बैठ जाते हैं।

प्रश्न 2.
वाक्य पूर्ण कीजिए:

(i) फिर भी धंसे हुए पैरों को __________________
(ii) मानो, लहर कह रही हो कि __________________
उत्तर:
(i) फिर भी धंसे हुए पैरों को पूरी ताकत से उठा-उठाकर भाग रहे थे।
(ii) मानो, लहर कह रही हो कि बनने के बाद मिटना ही नियति है।

Maharashtra Board Solutions

प्रश्न 3.
आकृति पूर्ण कीजिए:

(i) (1) लहरों की आवाज – [ ]
(2) बच्चों से मिली सीख – [ ]
(ii)
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 13
उत्तर:
(i) (1) लहरों की आवाज – रणभेरी जैसी।
(2) बच्चों से मिली सीख – जीवन में आशावाद हो, तो कोई काम असंभव नहीं

(ii)
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 14

ति 2: (आकलन)

प्रश्न 1.
आकृति पूर्ण कीजिए:

(i) खूबसूरत यह देखते ही मैं उससे जाकर लिपट गया
(ii) बहुत ही खूबसूरत और शांत जगह है यह –
(ii) तभी अचानक इनकी आवाज सुनाई दी
(iv) जल्दी-जल्दी चलने के बाद भी यह तय नहीं हो पा रही थी
उत्तर:
(i) खूबसूरत यह देखते ही मैं उससे जाकर लिपट गया – [समुंदर]
(ii) बहुत ही खूबसूरत और शांत जगह है यह – [बेनालियम]
(iii) तभी अचानक इनकी आवाज सुनाई दी – [लहरों की]
(iv) जल्दी-जल्दी चलने के बाद भी यह तय नहीं हो पा रही थी – [दूरी]

प्रश्न 2.
उत्तर: लिखिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 15
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 17

कृति 3: (शब्द संपदा)

प्रश्न 1.
निम्नलिखित शब्दों का वचन बदलकर लिखिए:
(i) हवा
(ii) मछली
(ii) लहर
(iv) बच्चे।
उत्तर:
(i) हवा – हवाएँ
(ii) मछली – मछलियाँ
(iii) लहर – लहरें
(iv) बच्चे – बच्चा

प्रश्न 2.
निम्नलिखित शब्दों के लिंग पहचानकर लिखिए:
(i) जगह
(ii) रेत
(iii) जीवन
(iv) सड़क।
उत्तर:
(i) जगह – स्त्रीलिंग
(ii) रेत – पुल्लिग
(iii) जीवन – पुल्लिंग
(iv) सड़क – स्त्रीलिंग।

Maharashtra Board Solutions

प्रश्न 3.
निम्नलिखित शब्दों के विरुद्धार्थी शब्द लिखिए:
(i) शांत
(ii) मुश्किल
(iii) शाम
(iv) खूबसूरत।
उत्तर:
(i) शांत x अशांत
(ii) मुश्किल x आसान
(iii) शाम x सुबह
(iv) खूबसूरत X बदसूरत।

कृति 4: (स्वमत अभिव्यक्ति)

प्रश्न.
‘गोवा की शाम’ के विषय में अपने विचार लिखिए।
उत्तर:
भारत के पश्चिमी समुद्र तट पर बसे गोवा की खूबसूरती के समान यहाँ की शामें भी अद्भुत होती हैं। जैसे-जैसे शाम होती है, गोवा मस्ती में डूबने लगता है। सागर के तट पर चाँदी जैसी रेत, नीलम जैसा पानी, चर्च, नारियल के पेड़ों का सौंदर्य मन को मोह लेता है। दूर-दूर तक विदेशी सैलानियों की भीड़ दिखाई देती है, कोई उछल रहा है, कोई कूद रहा है, कोई नाच रहा है। बीच पर तरह-तरह के वॉटर स्पोर्ट्स चल रहे हैं।

कहीं मोटरबोट राइडिंग हो रही है, तो कहीं पैराशूट राइडिंग। सैलानियों के लिए क्रूज एक अलग ही आकर्षण होता है। क्रूज अर्थात एक छोटे से स्टीमर में सौ-डेढ़ सौ लोग संगीत की तेज धुन पर थिरकते हुए। यह स्टीमर करीब एक घंटे की घुमावदार परिक्रमा कराता है।

गद्यांश क्र. 3

प्रश्न.
निम्नलिखित पठित गद्यांश पढ़कर दी गई सूचनाओं के अनुसार कृतियाँ कीजिए:

कृति 1: (आकलन)

प्रश्न 1.
जोड़ियाँ मिलाइए:

‘अ’  ‘आ’
(i) मनोरम  फिल्में
(ii) युवा  बाजार
(iii) हिट दृश्य
(iv) स्थानीय  मस्ती

उत्तर:

‘अ’  ‘आ
(i) मनोरम  दृश्य
(ii) युवा  मस्ती
(iii) हिट  फिल्में
(iv) स्थानीय  बाजार

प्रश्न 2.
आकृति पूर्ण कीजिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 17
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 19

Maharashtra Board Solutions

प्रश्न 3.
संजाल पूर्ण कीजिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 18

उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 20

कृति 2: (आकलन)

प्रश्न 1.
विधानों के सामने सत्य/असत्य लिखिए:
(i) पानी नीले पत्थरों पर पछाड़ खाता रहता है।
(ii) पानी ने काट-काटकर पत्थरों में छेद कर दिए हैं।
(iii) गोवा की सारी मछलियाँ निर्यात कर दी जाती हैं।
(iv) हम लोग दिन भर पणजी शहर देखते रहे।
उत्तर:
(i) असत्य
(ii) सत्य
(iii) असत्य
(iv) सत्य।

कृति 3: (शब्द संपदा)

प्रश्न 1.
निम्नलिखित शब्दों के समानार्थी शब्द लिखिए:
(i) समुद्र
(ii) पानी
(iii) पत्थर
(iv) किनारा।
उत्तर:
(i) समुद्र – जलधि
(ii) पानी – सलिल
(iii) पत्थर – पाषाण
(iv) किनारा – तट।

प्रश्न 2.
गद्यांश में प्रयुक्त अंग्रेजी शब्द ढूँढकर लिखिए।
(i) ____________
(ii) ____________
(iii) ____________
(iv) ____________
उत्तर:
(i) शूटिंग
(ii) फिल्म
(iii) बॉलीवुड
(iv) बीच।

Maharashtra Board Solutions

प्रश्न 3.
गद्यांश में प्रयुक्त प्रत्यययुक्त शब्द ढूँढ़कर उनके मूल शब्द और प्रत्यय अलग करके लिखिए।
(i) ____________
(ii) ____________
(iii) ____________
(iv) ____________
उत्तर:
शब्द – मूल शब्द – प्रत्यय
(i) पथरीला – पत्थर – ईला
(ii) पहाड़ी – पहाड़ – ई
(iii) स्थानीय – स्थान – ईय
(iv) व्यावसायिक – व्यवसाय – ई

गद्यांश क्र. 4

प्रश्न.
निम्नलिखित पठित गद्यांश पढ़कर दी गई सूचनाओं के अनुसार कृतियाँ कीजिए:

कृति 1: (आकलन)

प्रश्न 1.
सही विकल्प चुनकर वाक्य फिर से लिखिए:

(i) आप भी अपनी ______________ के अनुसार हाथ आजमा सकते हैं। (इच्छा/जेब/रुचि)
(ii) हम यानी मैं और मेरी ______________ दोनों डर भी रहे थे। (पत्नी/बिटिया/माँ)
(iii) कोलबा बीच पर हमने ______________ मछलियाँ देखीं। (व्हेल/डॉल्फिन/शार्क)
(iv) शाम को भगवान की एक ______________ मंदिर ले जाई जाती है। (मूर्ति/फोटो/पालकी)
उत्तर:
(i) आप भी अपनी रुचि के अनुसार हाथ आजमा सकते हैं।
(ii) हम यानी मैं और मेरी पत्नी दोनों डर भी रहे थे।
(iii) कोलबा बीच पर हमने डॉल्फिन मछलियाँ देखीं।
(iv) शाम को भगवान की एक पालकी मंदिर ले जाई जाती है।

प्रश्न 2.
कारण लिखिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 21
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 22

कृति 2: (आकलन)

प्रश्न 1.
संजाल पूर्ण कीजिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 23
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 25

Maharashtra Board Solutions

कृति 3: (शब्द संपदा)

प्रश्न 1.
सोचिए और लिखिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 5 गोवा जैसा मैंने देखा 27

प्रश्न 2.
गद्यांश में प्रयुक्त अंग्रेजी शब्द ढूंढकर लिखिए।

(i) _____________
(ii) _____________
(iii) _____________
(iv) _____________
उत्तर:
(i) बोटिंग
(ii) वॉटर
(iii) स्पोर्ट्स
(iv) पैराग्लाइडिंग।

प्रश्न 3.
गद्यांश में प्रयुक्त शब्द-युग्म ढूँढ़कर लिखिए।
(i) _____________
(ii) _____________
(iii) _____________
(iv) _____________
उत्तर:
(i) रचा-बसा
(ii) अपनी-अपनी
(iii) एक-दूसरे
(iv) घूमना-फिरना।

कृति 4: (स्वमत अभिव्यक्ति)

प्रश्न.
‘गोवा की संस्कृति’ के विषय में 25 से 30 शब्दों में अपने विचार लिखिए।
उत्तर:
सुरम्य सागरतट पर बसा गोवा प्रांत अपनी प्राकृतिक सुंदरता और अनूठी संस्कृति के लिए प्रसिद्ध है। यहाँ की संस्कृति काफी प्राचीन है। आजादी से पहले गोवा पुर्तगाल और फ्रांस का उपनिवेश था। इस वजह से आज भी यहाँ के रहन-सहन, खान-पान पर पश्चिमी संस्कृति का पूरा प्रभाव दिखाई देता है। यहाँ लगभग 80 प्रतिशत लोग ईसाई हैं।

गोवा की एक खास बात यह है कि यहाँ के ईसाई समाज में भी हिंदुओं जैसी जाति व्यवस्था पाई जाती है। दक्षिण गोवा में ईसाई समाज का प्रभाव अधिक है, लेकिन वहाँ के वास्तुशास्त्र में हिंदू प्रभाव दिखाई देता है। गोवा में अत्यंत प्राचीन मंदिर पाए जाते हैं, जबकि उत्तर: गोवा में पुर्तगाली वास्तुकला के नमूने ज्यादा दृष्टिगोचर होते हैं।

Maharashtra Board Solutions

भाषा अध्ययन (व्याकरण)

प्रश्न.
सूचनाओं के अनुसार कृतियाँ कीजिए:

1. शब्द भेद:
अधोरेखांकित शब्दों का शब्दभेद पहचानकर लिखिए:
(i) मैं उनसे पूछने लगा।
(ii) हम मड़गाँव 23 नवंबर को पहुंचे।
उत्तर:
(i) उनसे – पुरुषवाचक सर्वनाम।
(ii) मड़गाँव – व्यक्तिवाचक संज्ञा।

2. अव्यय:
निम्नलिखित अव्ययों का अपने वाक्यों में प्रयोग कीजिए:
(i) वहाँ
(ii) कभी-कभी।
उत्तर:
(i) वहाँ! एक मजेदार दृश्य देखने को मिला।
(ii) कभी-कभी कोई जल-पक्षी कुत्तों का शिकार बन जाता है।

3. संधि:
कृति पूर्ण किजिए:

संधि शब्द  संधि विच्छेद  संधि भेद
स्वच्छ  ___________ ___________
अथवा
 सत् + आचार  ___________ ___________

उत्तर:

संधि शब्द  संधि विच्छेद  संधि भेद
स्वच्छ सु + अच्छ स्वर संधि
अथवा
सदाचार सत् + आचार व्यंजन संधि

4. सहायक क्रिया:
निम्नलिखित वाक्यों में से सहायक क्रियाएँ पहचानकर उनका मूल रूप लिखिए:
(i) हम सभी समुद्र की ओर दौड़ पड़े।
(ii) हम दिन भर पणजी शहर देखते रहे।
उत्तर:
सहायक क्रिया – मूल रूप
(i) पड़े – पड़ना
(i) रहे – रहना

Maharashtra Board Solutions

5. प्रेरणार्थक क्रिया:
निम्नलिखित क्रियाओं के प्रथम प्रेरणार्थक और द्वितीय प्रेरणार्थक रूप लिखिए:
(i) सुनना
(ii) बनना
(iii) झुकना।
उत्तर:

क्रिया  प्रथम प्रेरणार्थक रूप  द्वितीय प्रेरणार्थक रूप
(i) सुनना  सुनाना  सुनवाना
(ii) बनना  बनाना  बनवाना
(iii) झुकना  झुकाना  झुकवाना

6. मुहावरे:
(1) निम्नलिखित मुहावरों का अर्थ लिखकर वाक्य में प्रयोग कीजिए:
(i) शिकार होना
(ii) दीवार टूट जाना।
उत्तर:
(i) शिकार होना।
अर्थ: पीड़ित होना।
वाक्य: पुराने जमाने में न जाने कितने गरीब जींदारों के अत्याचारों के शिकार हो जाते थे।

(ii) दीवार टूट जाना।
अर्थ: अड़चन समाप्त हो जाना।
वाक्य: स्त्रियों को समानता का अधिकार मिल जाने से सभी स्त्री-पुरुष के बीच असमानता की दीवार टूट गई।

(2) अधोरेखांकित वाक्यांश के लिए कोष्ठक में दिए गए उचित मुहावरे का चयन करके वाक्य फिर से लिखिए: (कान पक जाना, भनक पड़ना, कान पकड़ना) थानेदार ने उड़ती हुई बात सुनी कि गाँव में डाकू आने वाले हैं।
उत्तर:
भनक पड़ना। वाक्य: थानेदार के कान में भनक पड़ी कि गाँव में डाकू आने वाले हैं।

7. कारक:
निम्नलिखित वाक्यों में प्रयुक्त कारक पहचानकर उनका भेद ‘लिखिए:
(i) गोवा की मांडवी नदी वर्ष भर पानी से भरी रहती है।
(ii) गोवा राज्य दो भागों में बँटा हुआ है।
उत्तर:
(i) पानी से-करण कारक।
(ii) भागों में-अधिकरण कारक।

8. विरामचिह्न:
निम्नलिखित वाक्यों में यथास्थान उचित विरामचिह्नों का प्रयोग करके वाक्य फिर से लिखिए:
(i) दूर दूर तक पानी ही पानी तेज हवा और रस्सियों से हवा में लटके हम
(ii) गोवा यह नाम सुनते ही सभी का मन तरंगायित हो उठता है और हो भी क्यों न यहाँ की प्रकृति आबोहवा जीवनशैली ही ऐसी है
उत्तर:
(i) दूर-दूर तक पानी-ही-पानी, तेज हवा और रस्सियों से हवा में लटके हम।
(ii) गोवा ! यह नाम सुनते ही सभी का मन तरंगायित हो उठता है और हो भी क्यों न, यहाँ की प्रकृति, आबोहवा जीवनशैली ही ऐसी है।

Maharashtra Board Solutions

9. काल परिवर्तन:
निम्नलिखित वाक्यों का सूचना के अनुसार काल परिवर्तन कीजिए:
(i) मंत्री जी ने लोगों को एक मशवरा दिया। (पूर्ण वर्तमानकाल)
(ii) गोवा में मुझे मेरे पुराने अध्यापक मिले थे। (सामान्य भूतकाल)
उत्तर:
(i) मंत्री जी ने लोगों को एक मशवरा दिया है।
(ii) गोवा में मुझे मेरे पुराने अध्यापक मिले।

10. वाक्य भेद:
(1) रचना के आधार पर निम्नलिखित वाक्यों का भेद पहचानकर लिखिए:
(i) सबकी अपनी-अपनी सांस्कृतिक परंपरा है।
(ii) डॉल्फिन मछलियाँ छोटी थीं पर बच्चों को आनंद आया।
उत्तर:
(i) सरल वाक्य
(ii) संयुक्त वाक्य।

(2) निम्नलिखित वाक्यों का अर्थ के आधार पर दी गई सूचना के अनुसार परिवर्तन कीजिए:
(i) पर्यटन का अपना ही आनंद है। (विस्मयवाचक)
(ii) आशावाद हो तो हर काम संभव है। (निषेधवाचक)
उत्तर:
(i) वाह! पर्यटन का अपना ही आनंद है।
(ii) आशावाद हो तो कोई काम असंभव नहीं है।

11. वाक्य शुद्धिकरण:
निम्नलिखित वाक्य शुद्ध करके लिखिए:
(i) भाषा ईश्वर का बड़ा देन है।
(ii) पैसेवाली व्यक्ति कटु बोलती है।
उत्तर:
(i) भाषा ईश्वर की बड़ी देन है।
(ii) पैसेवाला व्यक्ति कटु बोलता है।

उपक्रम/कृति/परियोजना

प्रश्न.
गोवा की ऐतिहासिक पृष्ठभूमि की जानकारी पदिए और कालानुक्रम के अनुसार प्रमुख घटनाओं की तालिका बनाइए।
उत्तर:
गोवा की ऐतिहासिक पृष्ठभूमि:

मौर्य वंश  तीसरी सदी ईसा पूर्व से पहली सदी तक
कोल्हापुर के सातवाहन  पहली सदी से 580 ईसवी तक
बादामी के चालुक्य  580 ईसवी से 750 ईसवी तक
विजयनगर  1312 ईसवी सें1468 तक
दिल्ली सल्तनत  1469 ईसवी से 1510 ईसवी तक
पुर्तगाली शासन  1510 ईसवी से 1960 ईसवी तक

Maharashtra Board Solutions

प्रश्न.
गोवा की प्राकृतिक सुंदरता पर संवाद प्रस्तुत कीजिए।
उत्तर:
गोवा की प्राकृतिक सुंदरता पर दो सहेलियों के बीच संवाद:
रुचि: नीनू, बहुत दिनों बाद दिखी। कैसी हो? कहीं बाहर गई थी क्या?

नीनू: हाँ रुचि, हम लोग एक सप्ताह के लिए गोवा गए थे।

रुचि: गोवा! नीनू मैंने सुना है कि गोवा बहुत सुंदर है।

नीनू: सच सुना है रुचि। गोवा इतना सुंदर है कि मेरा तो मन करता था कि वहाँ से वापस ही नहीं आऊँ।

रुचि: मुझे भी तो कुछ बताओ।

नीनू: रुचि, गोवा अपने समुद्र तटों के लिए बहुत प्रसिद्ध है। साफ नीला पानी, लंबे समुद्र तट, चमचमाती रेत और नारियल के वृक्ष यहाँ की विशेषता है। गोवा में इतनी अधिक हरियाली है कि ऐसा लगता है मानो घरती ने हरी चादर ओढ़ रखी है।

रुचि: ओह! सुनकर ही कितना अच्छा लग रहा है।

नीनू: गोवा के लोग प्रकृति से बहुत प्रेम करते हैं। छोटे-से छोटे घर के आगे भी सुंदर-सुंदर फूल-पौधे जरूर होते हैं। वहाँ बड़ा शांत और मनोरंजक वातावरण है।

रुचि: गोवा के समुद्र तट के बारे में कुछ और बताओ न।

नीनू: वहाँ सागर से आसमान देखकर लगता है मानो नीला आसमान पानी से मिल रहा है। प्रातःकाल में उगता हुआ सूरज ऐसा लगता है, मानो समुद्र में से ही उग रहा हो। इसी तरह सूर्यास्त के समय सूरज का लाल गोला धीरे-धीरे नीचे जाता हुआ अचानक समुद्र में डूबता-सा लगता है। जैसे-जैसे शाम होती है, समुद्र की लहरों का ऊँचा उठन्य शुरू हो जाता है।

गोवा जैसा मैंने देखा Summary in Hindi

गोवा जैसा मैंने देखा विषय–प्रवेश :

प्रस्तुत यात्रा निबंध में विनय शर्मा ने भारत के पश्चिमी तट पर बसे गोवा की प्राकृतिक सुंदरता, वहाँ के लोगों की जीवन शैली, त्योहारों तथा समुद्र तटों का मनोरम, मनोहारी चित्रण किया है। यहाँ के समुद्र तट पर्यटकों के आकर्षण के केंद्र बिंदु हैं। पश्चिमी फैशन के साथ अपने आप को ढालते हुए भी गोवा अपनी भारतीय परंपरा और सभ्यता को नहीं भूला है।

गोवा जैसा मैंने देखा मुहावरे – अर्थ

  • मन तरंगायित होना – मन उमंग से भरना।
  • निजात पाना – मुक्ति पाना।
  • दो – चार होना – जूझना।
  • जेब ढीली होना – जेब खाली होना, बहुत खर्च होना।

Maharashtra Board Class 10 Hindi Lokbharti Solutions Chapter 8 गजल

Balbharti Maharashtra State Board Class 10 Hindi Solutions Lokbharti Chapter 8 गजल Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 10 Hindi Lokbharti Chapter 8 गजल

Hindi Lokbharti 10th Std Digest Chapter 8 गजल Textbook Questions and Answers

सूचना के अनयुार कृहत्‍ँ कीहजए:

(1) गजल की पंक्तियों का तातप्‍:
a. नीं के अंदर हदिाे ————
b. आईना बनकर हदिो ————
उत्तर:
(i) हमें प्रशंसा और वाहवाही का लोभ त्यागकर नींव की ईंटों के समान कुछ अच्छा और सुदृढ़ काम करना चाहिए।
(ii) हमें ऐसी शख्सियत बनना चाहिए कि कैसी भी प्रतिकूल परिस्थिति क्यों न हो, हम विचलित न हों। बिना टूटे, बिना बिखरे हर परिस्थिति का डटकर सामना करें। अपने लक्ष्य को प्राप्त करें।

(2) कृति पूण् कीहजए:
Maharashtra Board Class 10 Hindi Solutions Chapter 8 गजल 7
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 8 गजल 5

(3) हजनके उततर हनम् शब् हों ऐसे प्र तै्‍र कीहजए:
1. भीड़
2. जुगनू
3. हततली
4. आसमान
उत्तर:
1. कवि अक्सर किसी शक्ल को कहाँ देखना चाहता है?
2. वक्त की धुंध में साथ रहने को किसने कहा?
3. कवि खिलते फूल के स्थान पर कहाँ दिखने को कहता है?
4. गर्द बनकर कहाँ लिखना चाहिए?

(4) हनम्हलखखत पंक्तियों से प्र तीिनमूल् हलखखए:
१. आपको मिसूस ……………………………………….. भीतर हदिो।
२. कोई ऐसी श्‍ ……………………………………….. मुझे अ्‍र हदिो।.
उत्तर:
(ii) हे ईश्वर, मैं चाहता हूँ कि मैं जिसे भी देखू, मुझे उसी में तुम नजर आओ। अर्थात मानव मात्र ईश्वर का अंश है।

(5) कृहत पूण् कीहजए:
गजल मे प्रयुक्त प्कृहतक घ‍ट
Maharashtra Board Class 10 Hindi Solutions Chapter 8 गजल 8
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 8 गजल 6

(6) कहि के अनयुार ऐसे हदखो:

यदि मेरा घर अंतररक में होता,’ हिष् पर अससी से सौ शब्दों मे हनबंध लेखन कीहजए।
उत्तर:
पिछले कई वर्षों में अंतरिक्ष विज्ञान में जो प्रगति हुई है, वह सराहनीय है। पहले अंतरिक्ष यात्रा कल्पना से अधिक कुछ नहीं थी लेकिन आज अंतरिक्ष यात्रा के सपने सच हो गए हैं। रूस ने अंतरिक्ष यान के द्वारा अपने अंतरिक्ष यात्री यूरी गागरिन को पहली बार अंतरिक्ष में भेजा था। फिर तो अमेरिकी अंतरिक्ष यात्री नील आर्मस्ट्रांग और एडविन एल्ड्रिन सबसे पहले चंद्रमा पर पहुचनेवाले अंतरिक्ष यात्री हो गए।

Maharashtra Board Solutions

अब तो ऐसा लगता है कि कभी-न-कभी हम को भी अंतरिक्ष में जाने का मौका मिल सकता है। लेकिन यह कब संभव होगा, कहा नहीं जा सकता। काश, मेरा घर अंतरिक्ष में होता…. यदि सच में मेरा घर अंतरिक्ष में होता तो कितना अच्छा होता। जिस आसमान को दूर से देखा करते हैं, हम उसकी खूब सैर करते। चाँद, सितारों को नजदीक से देखते। बादलों के बीच लुका-छिपी खेलते। परियों के देश में जाते।

वे किस तरह रहती हैं, जानने-देखने का अवसर पाते। हम अंतरिक्ष से अपनी सुंदर धरती को देखते। अपने प्यारे भारत को देखते। आकाशगंगा के विभिन्न ग्रहों-उपग्रहों को देखते। सौरमंडल के सबसे सुंदर ग्रह शनि और उसके वलयों को देखते। उनके जितना निकट जा सकते, अवश्य जाते। स्पेस वॉक करते। वहाँ फैली शांति का अनुभव करते। वहाँ के प्रदूषणरहित वातावरण में रहने का मौका मिलता, जिससे हमारा स्वास्थ्य बहुत बढ़िया हो जाता। काश ऐसा हो पाता…

प्रयु गजल की अपनी पसंदीदा हकनिी चार पंक्तियों का केंद्रीय भाव सपष् कीहजए।

Hindi Lokbharti 10th Textbook Solutions Chapter 8 गजल Additional Important Questions and Answers

पद्यांश क्र.1

प्रश्न.
निम्नलिखित पठित पद्यांश पढ़कर दी गई सूचनाओं के अनुसार कृतियाँ कीजिए:

कृति 1: (आकलन)
(1) आकृति पूर्ण कीजिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 8 गजल 1
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 8 गजल 2

(2) विधानों के सामने सत्य / असत्य लिखिए:
(i) स्वर्णिम शिखर बनकर जीना ही जीना है।
(ii) मील का पत्थर बनकर जीना अच्छा नहीं है।
(iii) मोमबत्ती के धागे जैसा जीवन जियो।
(iv) जिंदगी टूटकर नहीं बिखरनी चाहिए।
उत्तर:
(i) असत्य
(ii) असत्य
(iii) सत्य
(iv) सत्य।

Maharashtra Board Solutions

(3) उचित जोड़ियाँ मिलाइए:

 आ
(i) शिखर  गर्द
(ii) आस्मान  जिंदगी
(iii) पत्थर  स्वर्णिम
(iv) शक्ल  मील
 नींव

उत्तर:

 आ
(i) शिखर  स्वर्णिम
(ii) आस्मान  गर्द
(iii) पत्थर  मील
(iv) शक्ल  जिंदगी

(4) दो ऐसे प्रश्न तैयार कीजिए, जिनके उत्तर निम्नलिखित शब्द हों:
(i) आईना
उत्तर:
(i) पत्थरों के शहर में क्या बनकर दिखना चाहिए?

(5) एक शब्द में उत्तर लिखिए:
(i) पत्थर के शहर में यह बनकर दिखना है –
(ii) दिखने का शौक है तो यह बनो –
उत्तर:
(i) आईना।
(ii) नींव।

कृति 2: (शब्द संपदा)

(1) निम्नलिखित शब्दों के समानार्थी शब्द लिखिए:
(i) शक्ल = ……………………
(ii) शिखर = ……………………
(iii) गर्द = ……………………
(iv) पत्थर = ……………………
उत्तर:
(i) शक्ल = चेहरा
(ii) शिखर = शीर्ष
(ii) गर्द = धूल
(iv) पत्थर = पाषाण।

(2) निम्नलिखित शब्दों के विरुद्धार्थी शब्द लिखिए:
(i) आदमी x
(ii) शहर x
(ii) आसमान x
(iv) टूटना x
उत्तर:
(i) आदमी x जानवर
(ii) शहर x गाँव
(iii) आसमान x जमीन
(iv) टूटना x जुड़ना।

Maharashtra Board Solutions

कृति 3: (सरल अर्थ)

प्रश्न.
उपयुक्त पदयांश की आरंभ की चार पंक्तियों का सरल अर्थ 25 से 30 शब्दों में लिखिए।
उत्तर:
किसी भी अट्टालिका के चमचमाते शिखरों को सभी देखते हैं। उनकी शान की प्रशंसा भी करते हैं। लोग समाज में इन शिखरों के समान ही सम्मान पाना चाहते हैं। परंतु वास्तव में देखा जाए तो इन शिखरों से अधिक महत्व है उन ईंटों और पत्थरों का, जिनके कारण ये शिखर बन सके। यदि नींव की ईंटों ने गुमनामी के अंधेरे में रहना स्वीकार न किया होता, तो इन शिखरों का अस्तित्व ही न होता। यदि हम समाज के लिए कुछ करना चाहते हैं, तो हमें प्रशंसा और जैं सुदृढ़ काम करना चाहिए।

पद्यांश क्र. 2
प्रश्न.
निम्नलिखित पठित पद्यांश पढ़कर दी गई सूचनाओं के अनुसार कृतियाँ कीजिए:

कृति 1: (आकलन):

(1) सही विकल्प चुनकर वाक्य फिर से लिखिए:
(i) वक्त की इस धुंध में तुम …………………………….. बनकर दिखो। (सितारा/चिराग/रोशनी)
(ii) हम सभी के लिए एक …………………………….. है। (दुनिया/मर्यादा/मंच)
(iii) कोई …………………………….. कली फूल बनने से डर जाए। (छोटी/सुंदर/नाजुक)
(iv) कोई ऐसी शक्ल तो मुझको दिखे इस …………………………….. में। (भीड़/संसार/घर)
उत्तर:
(i) वक्त की इस धुंध में तुम रोशनी बनकर दिखो।
(ii) हम सभी के लिए एक मर्यादा है।
(iii) कोई नाजुक कली फूल बनने से डर जाए।
(iv) कोई ऐसी शक्ल तो मुझको दिखे इस भीड़ में।

(2) निम्नलिखित पंक्तियों से प्राप्त जीवनमूल्य लिखिए:
(i) एक जुगनू ने …………………………….. रोशनी बनकर दिखो।
उत्तर:
(i) जब वक्त साथ न दे रहा हो। हर तरफ असफलता और निराशा का साम्राज्य हो। ऐसे समय में एक छोटी-सी आशा की किरण भी बहुत बड़ा सहारा बन सकती है। हमें निराश, हताश लोगों के मन में आशा की किरण जगाना चाहिए।

(3) ऐसे प्रश्न तैयार कीजिए, जिनके उत्तर निम्नलिखित शब्द हों:
(iv) मोती।
उत्तर:
(iv) मोती को किसके अंदर दिखना चाहिए?

(4) जोड़ियाँ मिलाइए:

‘अ’  ‘आ’
(i) धुंध  सीप
(ii) मर्यादा  तितली
(iii) मोती  रोशनी
(iv) फूल  मनुष्य

उत्तर:

‘अ’  ‘आ’
(i) धुंध  रोशनी
(ii) मर्यादा  मनुष्य
(iii) मोती  सीप
(iv) फूल  तितली

कृति 2: (शब्द संपदा)

निम्नलिखित शब्दों के लिंग पहचानकर लिखिए:
(i) जुगनू – ……………………….
(ii) रोशनी – ……………………….
(iii) मोती – ……………………….
(iv) सीप – ……………………….
उत्तर
(i) जुगनू – पुल्लिंग
(ii) रोशनी – स्त्रीलिंग
(iii) मोती – पुल्लिंग
(iv) सीप – स्त्रीलिंग

Maharashtra Board Solutions

कृति 3: (सरल अर्थ):

प्रश्न.
उपर्युक्त पद्यांश की प्रथम चार पंक्तियों का सरल अर्थ 25 से 30 शब्दों में लिखिए।
उत्तर:
जब वक्त हमारा साथ न दे रहा हो। हर तरफ असफलताएँ धुंध के समान छाई हों। निराशा रूपी अंधकार का साम्राज्य हो। ऐसे: समय में एक छोटी-सी आशा की किरण भी बहुत बड़ा सहारा बन सकती है। ठीक उसी प्रकार, जैसे घने अंधकार में चमकता हुआ जुगनू । तुम्हें भी निराश, हताश लोगों के मन में आशा की किरण जगाना चाहिए।

सभी मनुष्यों के लिए समाज में रहने के लिए कुछ सीमाएँ हैं, जिनका हमें पालन करना होता है। तभी समाज हमें और हमारे व्यवहार को स्वीकार करता है। अगर तुम चाहते हो कि लोगों में तुम्हारी कोई पहचान बने तो जिस प्रकार सीप के अंदर मूल्यवान मोती छिपा होता है, उसी प्रकार तुम्हें समाज के कल्याण के लिए श्रेष्ठ कर्म करने चाहिए।

भाषा अध्ययन (व्याकरण)

प्रश्न.
सूचनाओं के अनुसार कृतियाँ कीजिए:

1. शब्द भेद:
अधोरेखांकित शब्दों के शब्दभेद पहचानिए:
(i) मैं दिल्ली में अच्छा घर ढूँढ़ रहा हूँ।
(ii) वे तेजी के साथ बगीचे की ओर चल पड़े।
(iii) तुम अब पढ़ने बैठ जाओ।
उत्तर:
(i) अच्छा – गुणवाचक विशेषण।
(ii) बगीचे – जातिवाचक संज्ञा।
(iii) तुम – पुरुषवाचक सर्वनाम।

2. अव्यय:
निम्नलिखित अव्ययों का अपने वाक्यों में प्रयोग कीजिए:
(i) के मारे.
(ii) या
(iii) पर।
उत्तर:
(i) के मारे – लड़का डर के मारे काँप रहा था।
(ii) या – वे खेलने या घूमने गए होंगे।
(iii) पर – गाड़ी थी, पर पर्याप्त पेट्रोल नहीं था।

3. संधि:
कृति पूर्ण कीजिए:

संधि शब्द संधि विच्छेद संधि भेद
नरेश ………………… …………………
अथवा
………………… दिक् + अंबर …………………

उत्तर:

संधि शब्द संधि विच्छेद संधि भेद
नरेश नर + ईश स्वर संधि
अथवा Maharashtra Board Solutions
दिगंबर दिक् + अंबर व्यंजन संधि

4. सहायक क्रिया:
निम्नलिखित वाक्यों में से सहायक क्रियाएँ पहचानकर उनका मूल रूप लिखिए:
(i) वे गरीबों को फल बाँटते रहे।
(ii) देरी करने को मेरा मन गवारा नहीं कर पाया।
(iii) उनके शब्द मेरे कानों में गूंजने लगे।
उत्तर:
सहायक क्रिया – मूल रूप
(i) रहे – रहना
(ii) पाया – पाना
(iii) लगे – लगना

5. प्रेरणार्थक क्रिया:
निम्नलिखित क्रियाओं के प्रथम प्रेरणार्थक और द्वितीय प्रेरणार्थक रूप लिखिए:
(i) छोड़ना –
(ii) डूबना –
(iii) सूखना। –
उत्तर:

क्रिया  प्रथम प्रेरणार्थक रूप  द्वितीय प्रेरणार्थक रूप
(i) छोड़ना  छुड़ाना  छुड़वाना
(ii) डूबना  डुबाना  डुबवाना
(iii) सूखना  सुखाना  सुखवाना

6. मुहावरे:
(1) निम्नलिखित मुहावरों का अर्थ लिखकर वाक्य में प्रयोग किजिए:
(i) नाम-निशान न रहना
(ii) रटता जाना।
उत्तर:
(i) नाम-निशान न रहना।
अर्थ: अस्तित्व मिट जाना।
वाक्य: भूकंप के कारण पुराने कार्यालय का नाम-निशान नहीं रहा

(ii) रटते जाना।
अर्थ: बार-बार कहते जाना।
वाक्य: विजय गाँव जाने की बात रटता जा रहा है

Maharashtra Board Solutions

(2) अधोरेखांकित वाक्यांशों के लिए कोष्ठक में दिए गए उचित मुहावरे का चयन करके वाक्य फिर से लिखिए: (तोलकर बोलना, तीर की तरह निकल जाना, कानों में गूंजना, ठहाका लगाना)
(i) पाकिटमार महिला का बटुआ छीनकर बहुत तेजी से निकल गया
(ii) माता-पिता द्वारा दी गई सीख जीवनभर ध्वनित होती रहती है
(iii) सज्जन हमेशा सोच-समझकर बोलता है
उत्तर:
(i) पाकिटमार महिला का बटुआ छीनकर तीर की तरह निकल गया
(ii) माता-पिता द्वारा दी गई सीख जीवनभर कानों में गूंजती रहती है
(iii) सज्जन हमेशा तौलकर बोलते हैं

7. कारक:
निम्नलिखित वाक्यों में प्रयुक्त कारक पहचानकर उनका भेद लिखिए:
(i) ईश्वर की प्राप्ति आसानी से नहीं होती।
(ii) एक बच्चा कुर्सी पर चढ़ा तो दूसरा नाचने लगा।
(iii) मैंने तय किया कि आज किसी से नहीं मिलूँगा।
उत्तर:
(i) की – संबंध कारक।
(ii) पर – अधिकरण कारक।
(iii) से – करण कारक।

8. विरामचिह्न:
निम्नलिखित वाक्यों में यथास्थान उचित विरामचिह्नों का प्रयोग करके वाक्य फिर से लिखिए:
(i) “गरम गरम भूनकर मसाला लगाकर दूंगा’
(ii) आदमी ने आकर पूछा-अभी भोजन तैयार होने में कितना विलंब है
(iii) हाँ, सूर ने एक जगह लिखा है-मैं दसों दिशाओं में देख लेता हूँ
उत्तर:
(i) “गरम-गरम भूनकर मसाला लगाकर दूंगा।”
(ii) आदमी ने आकर पूछा – “अभी भोजन तैयार होने में कितना विलंब है?”
(iii) हाँ, सूर ने एक जगह लिखा है- ‘मैं दसों दिशाओं में देख लेता हूँ।’

9. काल परिवर्तन:
निम्नलिखित वाक्यों का सूचना के अनुसार काल परिवर्तन कीजिए:
(i) ठीक ग्यारह बजे प्रधानमंत्री बाहर आते हैं। (सामान्य भूतकाल)
(ii) मुझे भाई का जला हुआ चेहरा याद आता है। (सामान्य भविष्यकाल)
(iii) गुरुदेव अपने समय पर स्नान करते हैं। (पूर्ण भूतकाल)
उत्तर:
(i) ठीक ग्यारह बजे प्रधानमंत्री बाहर आए।
(ii) मुझे भाई का जला हुआ चेहरा याद आएगा।
(iii) गुरुदेव ने अपने समय पर स्नान किया था।

10. वाक्य भेद:
(1) निम्नलिखित वाक्यों का रचना के आधार पर भेद पहचानकर लिखिए:
(i) ईश्वर ने हमें मनुष्य जीवन दिया है।
(ii) हमारा उद्देश्य, सजना, सँवरना ही नहीं है, बल्कि हमारे द्वारा किए गए कार्य सुंदर होने चाहिए।
उत्तर:
(i) सरल वाक्य
(ii) संयुक्त वाक्य।

Maharashtra Board Solutions

(2) निम्नलिखित वाक्यों को अर्थ के आधार दी गई सूचना के अनुसार वाक्य परिवर्तन कीजिए:
(i) चाची जली-भुनी रहती थी। (संदेहवाचक वाक्य)
(ii) मन अब सुकून अनुभव कर रहा था। (निषेधवाचक वाक्य)
उत्तर:
(i) शायद चाची जली-भुनी रहती थी।
(ii) मन अब सुकून अनुभव नहीं कर रहा था।

11. वाक्य शुद्धिकरण:
निम्नलिखित वाक्य शुद्ध करके लिखिए:
(i) इस मंदिर में अनेकों बूध की मूर्तियाँ हैं।
(ii) माँ को यहाँ से गए बस एक मिनेट हुई है।
(iii) मेरा घर तुमसे अच्छा है।
उत्तर:
(i) इस मंदिर में बुद्ध की अनेक मूर्तियाँ हैं।
(ii) माँ को यहाँ से गए बस एक मिनट हुआ है।
(iii) मेरा घर तुम्हारे घर से अच्छा है।

गजल Summary in Hindi

गजल विषय-प्रवेश :
प्रस्तुत गजल में माणिक वर्मा ने हमें निरंतर आगे बढ़ते रहने की प्रेरणा दी है। कवि का मानना है कि बाहरी रंग-रूप तो। अस्थायी होता है। सुंदरता हमारे विचारों में, हमारे कामों में होनी चाहिए।

गजल कविता का सरल अर्थ

1. आपसे किसने ………………………… भीतर देखो।

किसी भी अट्टालिका के चमचमाते शिखरों को सभी देखते हैं। उनकी शान की प्रशंसा भी करते हैं। लोग समाज में इन शिखरों के समान ही सम्मान पाना चाहते हैं। परंतु वास्तव में देखा जाए तो इन शिखरों से अधिक महत्व है उन ईंटों और पत्थरों का, जिनके कारण ये शिखर बन सके। यदि नींव की ईंटों ने गुमनामी के अंधेरे में रहना स्वीकार न किया होता, तो इन शिखरों का अस्तित्व ही न होता। यदि हम समाज के लिए कुछ करना चाहते हैं, तो हमें प्रशंसा और वाहवाही का लोभ त्यागकर नींव की ईंटों के समान कुछ अच्छा और सुदृढ़ काम करना चाहिए।

यदि आप मंजिल की ओर अग्रसर हैं तो अपने अच्छे कर्मों के कारण उसी प्रकार आसमानों तक छा जाइए, जैसे आँधी आने पर पृथ्वी से आकाश तक धूल-ही-धूल दृष्टिगोचर होती है। अर्थात आपके द्वारा किए गए अच्छे कामों का प्रभाव और चर्चा हर तरफ हो। और यदि आप मंजिल की ओर बढ़ते हुए मार्ग में कहीं बैठ जाते हो तो मील के पत्थर के समान बनो। मील का पत्थर जिस प्रकार एक पथिक को अपनी मंजिल की ओर बढ़ते समय सहायता करता है, उसी प्रकार क्रियाशील न होते हुए भी आप दूसरों की मदद करें।

ईश्वर ने हमें मनुष्य जीवन दिया है। हमारा उद्देश्य केवल सजना, सँवरना और सुंदर दिखना ही नहीं होना चाहिए। हमारे द्वारा किए गए काम सुंदर होने चाहिए। ईश्वर द्वारा प्रदत्त इस श्रेष्ठ मानव जीवन में हमें मानवीय गुणों को अपनाना चाहिए। हमारा कोई भी काम ऐसा न हो, जो मानवता के दायरे से बाहर हो। समाज में सभी के प्रति हमारा व्यवहार ऐसा हो कि सारा संसार हमें एक अच्छे मनुष्य के रूप में जाने। हमें ऐसी शख्सियत बनना चाहिए कि कैसी भी प्रतिकूल परिस्थिति क्यों न हों, हम विचलित न हों। बिना टूटे, बिना बिखरे हर परिस्थिति का डटकर सामना करें। अपने लक्ष्य को प्राप्त करें।

हमें प्रत्येक मानव से सहानुभूति रखनी चाहिए। यह तभी संभव हो सकेगा, जब हम उनके हर दुख-तकलीफ को समझें। जैसे मोमबत्ती का धागा सदा उसके साथ रहता है। उसके साथ जलता है। उसी प्रकार जब हम दीन-दुखियों की पीड़ा को समझेंगे, तो उसे दूर करने का यथासंभव प्रयास करेंगे। इस प्रकार हम अपना मानव-धर्म निभा पाएँगे।

2. एक जुगनू ………………………… अक्सर देखो।

जब वक्त हमारा साथ न दे रहा हो; हर तरफ असफलताएँ धुंध के समान छाई हों; निराशा रूपी अंधकार का साम्राज्य हो; ऐसे समय में एक छोटी-सी आशा की किरण भी बहुत बड़ा सहारा बन सकती है। ठीक उसी प्रकार, जैसे घने अंधकार में चमकता हुआ जुगनू। तुम्हें भी निराश, हताश लोगों के मन में आशा की किरण जगाना चाहिए।

सभी मनुष्यों के लिए समाज में रहने के लिए कुछ सीमाएँ हैं, जिनका हमें पालन करना होता है। तभी समाज हमें और हमारे व्यवहार को स्वीकार करता है। अगर तुम चाहते हो कि लोगों में तुम्हारी कोई पहचान बने तो जिस प्रकार सीप के अंदर मूल्यवान मोती छिपा होता है, उसी प्रकार तुम्हें समाज के कल्याण के लिए श्रेष्ठ कर्म करने चाहिए। तुम्हारी यह कल्याण-भावना तुम्हें एक पहचान देगी, सम्मान देगी।

यदि कोई कोमल कली फूल बनने से डर रही हो। कली जानती है कि उसके खिलते ही तितली उसका रस चूसने के लिए आएगी और फूल बनी कली को परेशान करेगी। तुम फूल को तितली से बचाने का प्रयास करो। अर्थात उसके डर को दूर करने में उसकी मदद करो।

यह संसार मनुष्यों का एक सागर है। भीड़ में जाने-अनजाने अनगिनत चेहरे हर तरफ दिखाई देते हैं। हे ईश्वर, मैं चाहता हूँ कि मैं जिसे भी देखू, मुझे उसी में तुम नजर आओ। तुम तो सर्वव्यापक हो।

Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)

Balbharti Maharashtra State Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT) Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)

Class 9 Science Chapter 10 Information Communication Technology (ICT) Textbook Questions and Answers

1. Fill in the blanks to complete the statements. Justify the statements.

a. While working with a computer we can read the information stored in its memory and perform other actions in ………………………. memory.
b. While presenting pictures and videos about the works of scientists, we can use ……………………… .
c. To draw graphs based on the quantitative information obtained in an experiment, one uses ……………………… .
d. The first generation computers used to shut down because of ……………………… .
e. A computer will not work unless ………………………. is supplied to it.

Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)

2. Answer the following questions.

a. Explain the role and importance of information communication in science and technology.
Answer:

  • ICT plays a key role in creating, displaying, collecting, processing and communicating information in the field of science and technology.
  • Following is the importance of ICT in science and technology:
    (a) Access to wide range of information
    (b) Storing of Data
    (c) Processing of Data
    (d) Securing work files
    (e) Proper representation of data

b. Which application software in the computer system did you find useful while studying science, and how?
Answer:

  • Microsoft word: To write down the information collected and making a document for further evaluation.
  • Microsoft excel : To draw graph based on the obtained numerical information from the experiment.
  • Internet explorer: To search for information in finding out the solution or solving the queries by reading the available information.

c. How does a computer work?
Answer:

Input unit Processor Output Unit
All types of information/ data is entered into the computer through this unit. Generally, a keyboard is used to enter data or information Processing Unit
(1) Memory unit
(2) Control unit
(3) ALU unit
The result/solution/ answer is eventually sent to the output unit. Generally, a screen/monitor or printer is used as an output unit.

d. What precautions should be taken while using various types of software on the computer?
Answer:

  • Antivirus must be installed.
  • Software should be legal and from a trusted place.
  • Application should be scanned before using.
  • Pirated Software should not be used Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)
  • Provide all necessary data to obtain the best possible results.

e. Which are the various devices used in information communication? How are they used in the context of science?
Answer:

  • Various devices used in information communication are: Computers, Laptops, Mobiles, Radios, Television, etc.
  • Computers, Laptops and Mobiles: Help in accessing, collecting, processing, communicating, sharing and storing of information. It helps in determining the appropriate conclusions in all fields, including the field of science.
  • Television: Help in getting information about the new and innovative technology.

3. Using a spreadsheet, draw graphs between distance and time, using the information about the movements of Amar, Akbar and Anthony given in the table on page 4, in the lesson on Laws of Motion. What precautions will you take while drawing the graph?
Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT) 3
Answer:
Precautions to be taken while drawing a graph:

  • The data should be kept in tabular form.
  • Whenever there is ‘drag and fill’ option used, ‘smart tag’ option should be used after ‘drag data’ to fill data as required. Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)
  • Entered data should be formatted in the manner required.
  • Various types of graphs can be created by using the same data, so appropriate graph should be selected.
  • Chart titles and axes titles should be updated as per the data.

4. Explain the differences between the different generations of computers. How did science contribute to these developments?
Answer:
Generation: 1st
Time Period: 1946 – 1956
Development: Vacuum Tubes Characteristics:

  • Huge in size
  • Expensive
  • Lot of electricity consumption
  • Heat generation

Generation: 2nd
Time Period: 1956 – 1963
Development: Transistors
Characteristics:

  • Frequent shutdowns
  • Superior to 1st Generation
  • Small in size and fast
  • Cheaper as compared to 1st Generation
  • Less consumption of electricity

Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)

Generation: 3rd
Time Period: 1963 -1971
Development: IC
Characteristics:

  • Keyboards and monitors
  • OS
  • Smaller and still cheaper

Generation: 4th
Time Period: 1971 – 2010
Development: Microprocessor Characteristics:

  • Use of Internet
  • GUI
  • Introduction of portable devices like mobiles, laptops, etc.

Generation: 5th
Time Period: 2010 – Till Date
Development: Artificial Intelligence (AI) Characteristics:

  • Voice recognition
  • Sensors
  • Nano technology

1st Generation computers occupied the entire room, but due to advancement in science and technology, today’s computer fits into our pockets.

Initially computers needed a specific language to interact but today we use voice recognition for the same.

In these ways, science has contributed in making the computers faster, smaller, cheaper and much more useful.

5. What devices will you use to share with others the knowledge that you have?
Answer:
Devices like radios, televisions, pendrives, computers, laptops, mobiles, landlines, hard drives, CDs, memory cards help us in sharing our knowledge with others.

Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)

6. Using information communication technology, prepare powerpoint presentations on at least three topics in your textbook. Make a flowchart of the steps you used while making these presentations.
Answer:
Steps for preparation of PowerPoint presentations:
Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT) 1

7. Which technical difficulties did you face while using the computer? What did you do to overcome them?
Answer:

  • Lagging: Due to lot of applications running at the same time, the computer starts lagging and becomes slow. Closing a few applications helped solve the problem of lagging.
  • Viruses and Bugs: Cybercrimes are rising daily, even from single mail the computer can be attacked by viruses. Installing a valid antivirus helps solve the problem of viruses and bugs.
  • Breach of Privacy: Confidential information being accessed by anyone is the breach of privacy. Putting privacy setting in place helps solve the problem. Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)
  • Physical Damage: Hardware over a period of time might get physically damaged. Taking precautions while using will help to solve the problem.

Class 9 Science Chapter 10 Information Communication Technology (ICT) Intext Questions and Answers

Question 1.
Make a list of various hardware and software items of a computer,
Answer:
Hardware: Mouse, Keyboard, Pendrive, Monitor and other parts of computer.
Software: Operating Systems, Application Programs, Antivirus, etc.

Answer the following questions:

Question 2.
Which devices do we directly or indirectly use for collecting, sharing, processing and communicating information?
Answer:

  • Computers
  • Laptops
  • Mobiles
  • Memory Cards
  • Pendrives
  • Landlines
  • Hard disks etc.

Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)

Question 3.
How is information communication technology important for dealing with explosion of information?
Answer:

  • Information explosion means a situation whère information is available in abundance, in other words, too much information.
  • Devices like computers, laptops help us in easier accessment of information that we need from all the data.

Class 9 Science Chapter 10 Information Communication Technology (ICT) Additional Important Questions and Answers

Choose and write the correct option:

Question 1.
…………………….. includes communication devices and the use of those devices as well as the services provided with their help.
(a) Operating System
(b) Office
(c) Computers
(d) Information Communication Technology
Answer:
(d) Information Communication Technology

Question 2.
Computers have gone through …………………….. generations.
(a) 5
(b) 7
(c) 10
(d) 8
Answer:
(a) 5

Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)

Question 3.
First generation of Computers were considered to be present in the period of ……………………. .
(a) 2000 – 2001
(b) 1901 – 2001
(c) 1946 -1959,
(d) 1996 – 2001
Answer:
(c) 1946-1959

Question 4.
Full form of RAM is ……………………. .
(a) Roaming Application Memory
(b) Random Accessible Media
(c) Random Access Memory
(d) None of the above
Answer:
(c) Random Access Memory

Question 5.
Full form of ROM is ……………………. .
(a) Roaming Only Memory
(b) Random Output Media
(c) Read Only Memory
(d) None of the above
Answer:
(c) Read Only Memory

Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)

Question 6.
…………………….. is raw information.
(a) Program
(b) Memory
(c) Data
(d) Operating System
Answer:
(c) Data

Question 7.
…………………….. are used for sharing information.
(a) Telephones
(b) Hard disks
(c) RAM
(d) ROM
Answer:
(a) Telephones

Question 8.
Hard disks are used for …………………….. information.
(a) storing
(b) communicating
(c) sharing
(d) all of the above
Answer:
(a) storing

Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)

Question 9.
Computers are used for …………………….. information.
(a) storing
(b) managing
(c) sharing
(d) all of the above
Answer:
(d) All of the above

Question 10.
RAM and ROM are 2 types of …………………….. memory.
(a) external
(b) internal
(c) physical
(d) garbage
Answer:
(b) internal

Question 11.
The information stored in ROM is only …………………….., changes cannot be made.
(a) external memory
(b) readable
(c) accessible
(d) physical
Answer:
(b) readable

Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)

Question 12.
…………………….. is a group of commands to be given to the computer.
(a) Program
(b) Memory
(c) Data
(d) Operating System
Answer:
(a) Program

Question 13.
…………………….. communicates between the computer and the person working on it.
(a) Program
(b) Memory
(c) Data
(d) Operating System
Answer:
(d) Operating System

Match the columns:

Column ‘A’ Column ‘B’
(1) Antivirus
(2) OS
(3) CPU
(4) Printer
(5) Mouse
a) Output Device
b) Software
c) Input Device
(d) Operating System
(e) Brain of the computer

Answer:
(1 – b),
(2 – d),
(3 – e),
(4 – a),
(5 – c)

Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)

State whether the following statements are true or false and if false, correct the false statements:

(1) RAM and ROM are the types of external memory.
(2) ICT includes communication devices and the use of those devices as well as services provided with their help.
(3) A computer cannot be used without its operating system.
(4) Microsoft Excel is used to make PowerPoint.
(5) Software refers to the set of commands given to the computer.
Answer:
(1) False. RAM and ROM are the types of internal memory.
(2) True
(3) True
(4) False. Microsoft Excel is used to make spreadsheets.
(5) True

Answer the following in one sentence:

Question 1.
Name the computer which was made between 1946 -1959.
Answer:
The ENIAC computer was made in the period of 1946-1959.

Question 2.
Give one example of Input Unit.
Answer:
Keyboard.

Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)

Question 3.
Name the 3 major parts of the processing units.
Answer:

  • Memory unit
  • Control unit
  • ALU unit

Question 4.
What precautions need to the taken care while entering formula into the excel?
Answer:
While using a formula, the ‘=’ sign should be typed first. Similarly, no space should be inserted while typing any formula.

Question 5.
What is Internet Explorer?
Answer:
This is a kind of Search Engine. It helps to find the information we want from all the information available on the internet.

Question 6.
What is a PDF?
Answer:
A PDF or Portable Document Format file can be used to view the file to print it or to handle files.

Question 7.
What is C-DAC?
Answer:
C-D AC, is a well-known Centre for Development of Advanced Computing, situated in Pune.

Write the Full forms of the following abbreviation:

Question 1.
ICT
Answer:
Information Communication Technology

Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)

Question 2.
OS
Answer:
Operating System

Question 3.
RAM
Answer:
Random Access Memory

Question 4.
ROM
Answer:
Read Only Memory

Question 5.
CPU
Answer:
Central Processing Unit

Question 6.
DOS
Answer:
Disk Operating System

Question 7.
PDF
Answer:
Portable Document Format

Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)

Question 8.
ALU
Answer:
Arithmetic Logical Unit

Question 9.
GUI
Answer:
Graphical User Interface

Question 10.
C-DAC
Answer:
Centre for Development of Advanced Computing

Question 11.
ISCII
Answer:
Indian Script Code for Information Interchange

Define the following:

Question 1.
Memory
Answer:
Memory is the place for storing data obtained from the input and also the generated solution or answer by the computer.

Question 2.
RAM
Answer:
RAM is created from electronic components and can function only as long as it is supplied with electricity.

Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)

Question 3.
ROM
Answer:
Information stored in ROM can only be read and changes cannot be made to the information originally stored here.

Question 4.
Operating System
Answer:
It is a program which provides a means of communication between the computer and the person working on it. It is called the DOS (Disk Operating System).

Question 5.
Program
Answer:
A program is a group of commands to be given to a computer.

Question 6.
Data and Information
Answer:
Data is information in its raw (unprocessed) form.

Question 7.
Hardware
Answer:
Hardware consists of all the electronic and mechanical parts used in computers.

Question 8.
Software:
Answer:
Software refers to the commands given to the computer, information supplied to it (input) and the results obtained from the computer after analysis (output).

Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)

Give scientific reasons:

Question 1.
Computer cannot function without its operating system.
Answer:

  • Operating system is like a link between the computer and the person working on it.
  • Operating system manages all the activities performed by the computer.
  • Without the operating system, the user won’t be able to input any data or run any program. Thus, a computer cannot run without an operating system.

Question 2.
ROM is a Read Only Memory.
Answer:

  • ROM also known as Read Only Memory is a part of internal memory of a computer where the information stored can only be read.
  • ROM helps store data permanently for a long period of time and the information stored cannot be deleted.
  • Thus, data in a ROM can only be read and cannot be altered or modified and hence, it is called as Read Only Memory.

Complete the table:
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT) 2

Answer the following questions:

Question 1.
What precautions will you take when entering data?
Answer:

  1. As far as possible, the data should be kept in tabular form. Different types of data should be entered in different cells. Data should be entered neatly and in one ‘flow’. Unnecessary space and special characters should not be used.
  2. Many times we ‘drag and fill’ data. At such times, the ‘smart tag’ can be used after ‘drag data’ to fill any data in any manner as required. Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)
  3. Once the data has been entered, it can be formatted in different ways. Similarly, we can perform different types of calculations, using different formulae.
  4. While using a formula, the ‘=’ sign should be typed first. Similarly, no space should be inserted while typing any formula.

Answer in detail:

Question 1.
Write in short about the opportunities in the field of ICT.
Answer:
(i) Software Field: This is an important field. Having accepted the challenge of creating software, many companies have entered this field. The opportunities in the software field can be classified as follows – application program development, software package development, operating systems and utility development, special purpose scientific applications.

(ii) Hardware Field: Today, there are several companies in our country too, which make computers. They sell computers that they have themselves made. Others sell computers brought from outside as well as repair them and take maintenance contracts to keep computers in big companies working efficiently without a break. Plenty of jobs are available here. There are job opportunities in hardware designing, hardware production, hardware assembly and testing, hardware maintenance, servicing and repairs, etc.

(iii) Marketing: There are many establishments which make and sell computers and related accessories. They need good sales personnel who are experienced in the working of computers as well as skilled in marketing.

(iv) Training: The training of new entrants for various jobs is a vast field. It is very important to have dedicated teachers who are competent in the field of computers.

Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)

Question 2.
Write in short about the industries conducting research in the field of computers.
Answer:

  • C-DAC, the well-known Centre for Development of Advanced Computing, situated in Pune, is the leading institute in India that conducts research in the field of computers.
  • The first Indian supercomputer was made with help from this institute. Valuable guidance for making this computer (the Param computer) was received from the senior scientist Vijay Bhatkar. Param means the supreme.
  • This computer can perform one billion calculations per second. It is used in many fields like space research, movements in the interior of the earth, research in oil deposits, medicine, meteorology, engineering, military etc.
  • C-DAC has also participated in developing the ISCII code for writing different language scripts. (Indian Script Code for Information Interchange).

Question 3.
Use Microsoft Word to create a document and write equations.
Answer:

  • Click on the Microsoft word 2010 icon on the desktop.
  • Select the ‘New option in the ‘File’ tab, and then select the ‘Blank document’ option.
  • Type your material on the blank page on the screen using the keyboard. Use the language, font size, bold, etc. options in the Home tab to make the typed material attractive.
  • To type equations in the text, select the ‘Equation’ option in the ‘Insert’ tab. Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT)
    Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT) 4 Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT) 5
  • Select the proper equation and type it using mathematical symbols.
    Maharashtra Board Class 9 Science Solutions Chapter 10 Information Communication Technology (ICT) 5

 

Maharashtra Board Class 10 Hindi Lokbharti Solutions Chapter 11 कृषक गान

Balbharti Maharashtra State Board Class 10 Hindi Solutions Lokbharti Chapter 11 कृषक गान Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 10 Hindi Lokbharti Chapter 11 कृषक गान

Hindi Lokbharti 10th Std Digest Chapter 11 कृषक गान Textbook Questions and Answers

कृति

कृतिपत्रिका के प्रश्न 2 (अ) तथा प्रश्न 2 (आ) के लिए
सूचना के अनुसार कृतियाँ कीजिए:

प्रश्न 1.
संजाल पूर्ण कीजिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 11 कृषक गान 1
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 11 कृषक गान 8

प्रश्न 2.
कृतियाँ पूर्ण कीजिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 11 कृषक गान 2
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 11 कृषक गान 6
Maharashtra Board Class 10 Hindi Solutions Chapter 11 कृषक गान 7

प्रश्न 3.
वाक्य पूर्ण कीजिए:
a. कृषक कमजोर शरीर को ____________
b. कृषक बंजर जमीन को ____________
उत्तर:
(i) कृषक कमजोर शरीर को पत्तियों से पालता है।
(ii) कृषक बंजर जमीन को अपने खून से सींचकर उर्वरा बना देता है।

Maharashtra Board Solutions

प्रश्न 4.
निम्नलिखित पंक्तियों में कवि के मन में कृषक के प्रति जागृत होने वाले भाव लिखिए:

पंक्ति  भाव
१. आज उसपर मान कर लूँ
२. आह्वान उसका आज कर लूँ
३. नव सृष्टि का निर्माण कर लूँ
४. आज उसका ध्यान कर लूँ।

उत्तर:

पंक्ति  भाव
१. आज उसपर मान कर लूँ अभिमान
२. आह्वान उसका आज कर लूँ मानवता
३. नव सृष्टि का निर्माण कर लूँ सृजनशीलता
४. आज उसका ध्यान कर लूँ। आदर

प्रश्न 5.
कविता में आए इन शब्दों के लिए प्रयुक्त शब्द हैं:
१. निर्माता – ____________
२. शरीर – ____________
३. राक्षस – ____________
४. मानव – ____________
उत्तर:
१. निर्माता – सृजक
२. शरीर – तन
३. राक्षस – असुर।
४. मानवता – मनुजता।

प्रश्न 6.
कविता की प्रथम चार पंक्तियों का भावार्थ लिखिए।
उत्तर:
कृषक के अभावों की कोई सीमा नहीं है। परंतु वह संतोष रूपी धन के सहारे अपना जीवन व्यतीत कर रहा है। पूरे संसार में कैसा भी वसंत आए, कृषक के जीवन में सदैव पतझड़ ही बना रहता है। अर्थात ऋतुएँ बदलती हैं, लोगों की परिस्थितियाँ बदलती हैं, परंतु कृषक के भाग्य में अभाव ही अभाव हैं। ऐसी दयनीय स्थिति के बावजूद उसे किसी से कुछ माँगना अच्छा नहीं लगता। वह हाथ फैलाना नहीं जानता। कृषक को अपनी दीन-हीन दशा पर भी नाज है। मैं ऐसे व्यक्ति पर अभिमान करना चाहता हूँ। कृषक के गीत गाना चाहता हूँ।

प्रश्न 7.
निम्न मुद्दों के आधार पर पद्य विश्लेषण कीजिए:
1. रचनाकार कवि का नाम:
2. रचना का प्रकार:
3. पसंदीदा पंक्ति:
4. पसंदीदा होने का कारण:
5. रचना से प्राप्त प्रेरणा:
उत्तर:
(1) रचनाकार का नाम → दिनेश भारद्वाज।
(2) कविता की विधा → गान।
(3) पसंदीदा पंक्ति → हाथ में संतोष की तलवार ले जो उड़ रहा है।
(4) पसंदीदा होने का कारण → अनगिनत अभावों के होते हुए भी कृषक के पास संतोष रूपी धन है।
(5) रचना से प्राप्त संदेश/प्रेरणा → कृषक दिन-रात परिश्रम करके संपूर्ण सृष्टि का पालन करता है। हमें उसके परिश्रम के महत्त्व को समझना चाहिए। उसका सम्मान करना चाहिए।

Maharashtra Board Solutions

Hindi Lokbharti 10th Textbook Solutions Chapter 11 कृषक गान Additional Important Questions and Answers

पद्यांश क्र. 1

प्रश्न.
निम्नलिखित पठित पट्यांश पढ़कर दी गई सूचनाओं के अनुसार कृतियाँ कीजिए:

→ कृति 1: (आकलन)

(1) कविता में आए इन शब्दों के लिए प्रयुक्त शब्द हैं:
(i) वसंत
(ii) पाला हुआ
उत्तर:
(i) वसंत – मधुमास
(ii) पाला हुआ – पालित

(2) सही विकल्प चुनकर वाक्य फिर से लिखिए:
(i) कृषक हाथ में _____________ की तलवार लेकर चल रहा है। (श्रम/संतोष/धन)
(ii) सारे संसार में _____________ और उस पर सदा पतझड़ रहता है। (वसंत/वर्षा/फूल)
(iii) कृषक को अपनी _____________ पर अभिमान है। (मेहनत/गरीबी/दीनता)
(iv) उसके लिए _____________ और छाया एक जैसी है। (धूप/रोशनी/कालिमा)
उत्तर:
(i) कृषक हाथ में संतोष की तलवार लेकर चल रहा है।
(ii) सारे संसार में वसंत और उस पर सदा पतझड़ रहता है।
(iii) कृषक को अपनी दीनता पर अभिमान है।
(iv) उसके लिए धूप और छाया एक जैसी है।

→ कृति 2: (शब्दल)

(1) पद्यांश से प्रत्यय जुड़े हुए दो शब्द ढूँढकर लिखिए:
(i) ______________
(ii) ______________
उत्तर:
(i) दीनता (ii) मनुजता।

(2) निम्नलिखित शब्दों के अर्थ लिखिए:
(i) मधुमास – ______________
(ii) आह्वान – ______________
उत्तर:
(i) मधुमास – वसंत ऋतु
(ii) आह्वान – पुकार।

पद्यांश क्र. 2

प्रश्न.
निम्नलिखित पठित पद्यांश पढ़कर दी गई सूचनाओं के अनुसार कृतियाँ कीजिए:

→ कृति 1: (आकलन)

(1) संजाल पूर्ण कीजिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 11 कृषक गान 9
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 11 कृषक गान 12

Maharashtra Board Solutions

(2) उत्तर लिखिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 11 कृषक गान 10
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 11 कृषक गान 13

(3) आकृति पूर्ण कीजिए:
(i) कृषक विश्व का यह है
(ii) वह अपने क्षीण तन को इनसे पालता है
(iii) कृषक अपने खून से सींचकर ऊसरों को यह बना देता है
(iv) आज यह पीड़ित होकर रो रही है
उत्तर:
(i) कृषक विश्व का यह है – पालक
(ii) वह अपने क्षीण तन को इनसे पालता है – पत्तियों से
(iii) कृषक अपने खून से सींचकर ऊसरों को यह बना देता है – उर्वर
(iv) आज यह पीड़ित होकर रो रही है – मनुजता

(4) कविता की पंक्तियों को उचित क्रमानुसार लिखकर प्रवाह तख्ता पूर्ण कीजिए:
(i) आज उससे कर मिला, नव सृष्टि का निर्माण कर लूँ।
(ii) छोड़ सारे सुर-असुर, मैं आज उसका ध्यान कर लूँ।
(iii) जोड़कर कण-कण उसी के, नीड़ का निर्माण कर लूँ।
(iv) किंतु अपने पालितों के, पद दलित हो मर रहा है।
उत्तर:
(i) किंतु अपने पालितों के, पद दलित हो मर रहा है।
(ii) आज उससे कर मिला, नव सृष्टि का निर्माण कर लूँ।
(iii) छोड़ सारे सुर-असुर, मैं आज उसका ध्यान कर लूँ।
(iv) जोड़कर कण-कण उसी के, नीड़ का निर्माण कर लूँ।

(5) आकृति पूर्ण कीजिए:
Maharashtra Board Class 10 Hindi Solutions Chapter 11 कृषक गान 11
उत्तर:
Maharashtra Board Class 10 Hindi Solutions Chapter 11 कृषक गान 14

Maharashtra Board Solutions

→ कृति 2: (शब्द संपदा)

(1) पद्यांश में प्रयुक्त शब्द-युग्म ढूँढ़कर लिखिए:
(i) …………………
(ii) …………………
उत्तर:
(i) सुर-असुर
(ii) कण-कण।

(2) निम्नलिखित शब्दों में से प्रत्यय अलग करके लिखिए:
(i) पालक = _____________
(ii) मनुजता = _____________
(iii) पीड़ित = _____________
(iv) जोड़कर = _____________
उत्तर:
(i) पालक = पाल + क
(ii) मनुजता = मनुज + ता”
(iii) पीड़ित = पीड़ा + इत
(iv) जोड़कर = जोड़ + कर।

(3) पद्यांश में आए इन शब्दों के लिए प्रयुक्त शब्द हैं:
(i) उपजाऊ
(ii) किसान
उत्तर:
(i) उपजाऊ – उर्वरा
(ii) किसान – कृषक

→ कृति 3: (सरल अर्थ)

प्रश्न.
पद्यांश की अंतिम चार पंक्तियों का सरल अर्थ लिखिए।
उत्तर:
देखिए कविता का सरल अर्थ [5]।

पद्य विश्लेषण

सूचना: यह प्रश्नप्रकार कृतिपत्रिका के प्रारूप से हटा दिया गया है। लेकिन यह प्रश्न पाठ्यपुस्तक में होने के कारण विद्यार्थियों के अधिक अभ्यास के लिए इसे उत्तर-सहित यहाँ समाविष्ट किया गया है।

भाषा अध्ययन (व्याकरण)

1. शब्द भेद:
अधोरेखांकित शब्दों के शब्दभेद पहचानकर लिखिए:
(i) हमें अपने देश पर अभिमान है।
(ii) भूकंप में घंटों मलबे के नीचे दबे रहकर भी बच्चा जीवित रहा।
उत्तर:
(i) अभिमान – भाववाचक संज्ञा।
(ii) जीवित – गुणवाचक विशेषण।

Maharashtra Board Solutions

2. अव्यय:
निम्नलिखित अव्ययों का अपने वाक्यों में प्रयोग कीजिए:
(i) बल्कि
(ii) तो।
उत्तर:
(i) सिरचन को लोग पूछते ही नहीं थे, बल्कि उसकी खुशामद भी करते थे।
(ii) लहरें बच्चों का रेत का घर गिरा देती तो वे नया घर बनाने लगते।

3. संधि:
कृति पूर्ण कीजिए

संधि शब्द  संधि विच्छेद  संधि भेद
…………..  सम् + सार  …………..
अथवा
निश्चय  ………….. …………..

उत्तर:

संधि शब्द  संधि विच्छेद  संधि भेद
संसार  सम् + सार  व्यंजन संधि
अथवा
 निश्चय  निः + चय विसर्ग संधि

4. सहायक क्रिया:
निम्नलिखित वाक्यों में से सहायक क्रियाएँ पहचानकर उनका मूल रूप लिखिए:
(i) सामने शेर को देखते ही सभी यात्री काँपने लगे।
(ii) तुम्हारी भाभी ने कहाँ से सीखी हैं?
उत्तर:
सहायक क्रिया – मूल रूप
(i) लगे – लगना
(ii) हैं – होना

5. प्रेरणार्थक क्रिया:
निम्नलिखित क्रियाओं के प्रथम प्रेरणार्थक और द्वितीय प्रेरणार्थक रूप लिखिए:
(i) चलना
(ii) चमकना
(iii) लिखना।
उत्तर:
क्रिया – प्रथम प्रेरणार्थक रूप – द्वितीय प्रेरणार्थक रूप
(i) चलना – चलाना – चलवाना
(ii) चमकना – चमकाना – चमकवाना
(iii) लिखना – लिखाना – लिखवाना

Maharashtra Board Solutions

6. मुहावरे:
(1) निम्नलिखित मुहावरों के अर्थ लिखकर वाक्यों में प्रयोग कीजिए:
(i) चंपत होना
(ii) मन न लगना।
उत्तर:
(i) चंपत होना।
अर्थ: गायब हो जाना।
वाक्य: पुलिस के आते ही चोर चंपत हो गया।

(ii) मन न लगना।
अर्थ: इच्छा न होना।
वाक्य: सिरचन का किसी काम में मन नहीं लग रहा था।

(2) अधोरेखांकित वाक्यांशों के लिए उचित मुहावरे का चयन कर वाक्य फिर से लिखिए: (खून का चूंट पीकर रह जाना, पानी फेरना, पिंड छुडाना)
(i) लालची और निर्लज्ज लोगों से छुटकारा पाना आसान नहीं होता।
(ii) शिवाजी आगरे से भाग निकले, इसलिए औरंगजेब को अपना मन मारकर रह जाना पड़ा।
उत्तर:
(i) लालची और निर्लज्ज लोगों से पिंड छुड़ाना आसान नहीं होता।
(ii) शिवाजी आगरे से भाग निकले, इसलिए औरंगजेब को अपना खून का चूंट पीकर रह जाना पड़ा।

7. कारक:
निम्नलिखित वाक्यों में प्रयुक्त कास्क पहचानकर उनका भेद लिखिए:
(i) मानू फूट-फूटकर रो रही थी।
(ii) सिरचन ने जीभ को दाँत से काटकर दोनों हाथ जोड़ दिए।
उत्तर:
(i) मानू-कर्ता कारक
(ii) दाँत से-करण कारक।

8. विरामचिह्न:
निम्नलिखित वाक्यों में यथास्थान उचित विरामचिह्नों का प्रयोग करके वाक्य फिर से लिखिए:
(i) माँ हँसकर कहती जा जा बेचारा मेरे काम में पूजा भोग की बात ही नहीं उठाता कभी
(ii) मानू कुछ नहीं बोली बेचारी किंतु मैं चुप नहीं रह सका चाची और मँझली भाभी की नजर न लग जाए इसमें भी
उत्तर:
(i) माँ हँसकर कहती,“जा-जा बेचारा मेरे काम में पूजा भोग की बात ही नहीं उठाता कभी।”
(ii) मानू कुछ नहीं बोली।…बेचारी! किंतु मैं चुप नहीं रह सका-“चाची और मँझली भाभी की नजर न लग जाए इसमें भी!”

Maharashtra Board Solutions

9. काल परिवर्तन:
निम्नलिखित वाक्यों का सूचना के अनुसार काल परिवर्तन कीजिए:
(i) सिरचन को एक सप्ताह पहले ही काम पर लगा दिया। (पूर्ण भूतकाल)
(ii) मानू ससुराल जाती है। (सामान्य भविष्यकाल)
(iii) उनके आशीर्वाद आज भी हमें मिले। (सामान्य वर्तमानकाल)
उत्तर:
(i) सिरचन को एक सप्ताह पहले ही काम पर लगा दिया था।
(ii) मानू ससुराल जाएगी।
(iii) उनके आशीर्वाद आज भी हमें मिलते हैं।

10. वाक्य भेद:
(1) निम्नलिखित वाक्यों का रचना के आधार पर भेद लिखिए:
(i) यह वही लड़का है, जिसे पुरस्कार मिला था।
(ii) मजदूर गड़ढ़ा खोदे और घर चले गए।
उत्तर:
(i) मिश्र वाक्य
(ii) संयुक्त वाक्य।

(2) निम्नलिखित वाक्यों का अर्थ के आधार पर दी गई सूचना के अनुसार परिवर्तन कीजिए:
(i) गाँव के किसान सिरचन को मजदूरी के लिए नहीं बुलाते। (इच्छावाचक वाक्य)
(ii) तुम्हें समय पर स्कूल जाना चाहिए। (आज्ञावाचक वाक्य)
उत्तर:
(i) काश! गाँव के किसान सिरचन को मजदूरी के लिए नहीं बुलाते।
(ii) तुम समय पर स्कूल जाओ।

11. वाक्य शुद्धिकरण:
निम्नलिखित वाक्य शुद्ध करके लिखिए:
(i) लोग गंगा नदी को पवीत्र मानते हैं।
(ii) किसी झमाने में यह शहर बहुत आबाद हैं।
उत्तर:
(i) लोग गंगा नदी को पवित्र मानते हैं।
(ii) किसी जमाने में यह शहर बहुत समृद्ध था।

कृषक गान Summary in Hindi

विषय-प्रवेश : प्रस्तुत गीत में गीतकार दिनेश भारद्वाज एक कृषक का महत्त्व प्रतिपादित कर रहे हैं। कृषक, जो कि संपूर्ण संसार का अन्नदाता है, स्वयं अभावों में जीता है। पर किसी के समक्ष हाथ नहीं फैलाता। कवि समाज में उसका सम्मान पूर्ववत स्थापित करना चाहते हैं।

कविता का सरल अर्थ

1. हाथ में संतोष ………………………… का गान कर लूँ।।

कृषक के अभावों की कोई सीमा नहीं है। परंतु उसके पास संतोष रूपी धन है। वह उसी संतोष के सहारे अपना जीवन व्यतीत कर रहा है। पूरे संसार में कैसा भी वसंत आए, कृषक के जीवन में सदैव पतझड़ ही रहता है। अर्थात ऋतुएँ बदलती हैं, लोगों की परिस्थितियाँ बदलती हैं, परंतु कृषक के भाग्य में अभाव ही अभाव हैं। ऐसी दयनीय स्थिति के बावजूद उसे किसी से कुछ माँगना अच्छा नहीं लगता। कृषक को अपनी दीन-हीन दशा पर भी नाज है। कवि कहते हैं कि में ऐसे व्यक्ति पर अभिमान करना चाहता हूँ। मैं कृषक के गीत गाना चाहता हूँ।

2. चूसकर श्रम रक्त ………………………… का गान कर लूँ।।

कृषक दिन-रात खेतों में काम करता है। अपने रक्त को पसीने के रूप में बहाता है और संपूर्ण जगत को जीवन-रस प्रदान करता है। ईश्वर की बनाई इस सृष्टि में उसके लिए धूप-छाया दोनों एक-सी हैं। मौसम में कैसा भी बदलाव आए, कृषक की स्थिति नहीं बदलती। मैं मानवता के साथ उसका आह्वान करना चाहता हूँ। मैं कृषक के गीत गाना चाहता हूँ।

3. विश्व का पालक  ………………………… का गान कर लूँ।।

कृषक संपूर्ण संसार का अन्नदाता है। वह अन्न उगाकर पूरे विश्व का पालन करता है। लोगों को जीवन देता है। किंतु अफसोस की बात है कि जिन लोगों को वह पालता है, उन्हीं के द्वारा उसे पददलित

किया जाता है। अपमानित किया जाता है। मैं चाहता हूँ कि मैं कृषक का हाथ पकड़कर एक नवीन सृष्टि का निर्माण करूँ, जहाँ लोग उसके महत्त्व को समझें। उसका सम्मान करें। मैं कृषक के गीत गाना चाहता हूँ।

4. क्षीण निज बलहीन ………………………… का गान कर लूँ।।

कृषक को जीवन में पर्याप्त सुविधाएँ नहीं मिल पाती। उसे अपने दुर्बल, क्षीण शरीर को ढकने के लिए कपड़े तक नहीं प्राप्त होते। वह पत्तों से अपना तन ढकने को मजबूर होता है। कृषक ऊसर धरती में जी-तोड़ मेहनत करके, पसीने के रूप में अपने खून को बहाकर उसे उपजाऊ बनाता है। मेरे लिए वह सभी देवी-देवताओं से ऊपर है। मैं चाहता हूँ कि देव-दानवों के स्थान पर कृषक का ही ध्यान करूं, उसी के जीवन को बेहतर बनाने का प्रयास करूं। मैं कृषक के गीत गाना चाहता हूँ।

5. यंत्रवत जीवित बना ………………………… का गान कर लूँ।

कृषक एक जीवित मशीन के समान है। वह बिना अपने अधिकार माँगे मशीन की तरह पूरा जीवन काम करता रहता है। उस अन्नदाता, सृष्टि के पालक की दुर्दशा देखकर आज मानवता रो रही है। मैं कण-कण जोड़कर कृषक के लिए एक ऐसे नीड़ का, ऐसे घर का निर्माण करना चाहता हूँ, जहाँ उसे एक अच्छा जीवन जीने के लिए सभी आवश्यक सुविधाएँ प्राप्त हों। मैं कृषक के गीत गाना चाहता हूँ।