Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Balbharti Maharashtra State Board 11th Biology Important Questions Chapter 7 Cell Division Important Questions and Answers.

Maharashtra State Board 11th Biology Important Questions Chapter 7 Cell Division

Question 1.
Why interphase is known as preparatory phase.
Answer:
1. During interphase, the cell is metabolically very active.
2. In this phase, a cell grows to its maximum size, chromosomal material (DNA and histone proteins) duplicates and the cell prepares itself for next mitotic division. Hence, inteiphase is known as preparatory phase.

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 2.
Name the following.
1. In which phase the amount of DNA per cell doubles?
2. Which types of RNA are synthesized during first growth phase?
Answer:
1. S-phase.
2. m-RNA, t-RNA and r-RNA

Question 3.
Match the Column I (Phases of Cell cycle) with Column II (Approximate time for completion).

Column I Column II
1. G: Phase (a) 1-3 Hours
2. Gi Phase (b) 2-5 Hours
3. M Phase (c) 6-8 Hours
4. S Phase (d) 8 Hours

Answer:

Column I Column II
1. G: Phase (b) 2-5 Hours
2. Gi Phase (d) 8 Hours
3. M Phase (a) 1-3 Hours
4. S Phase (c) 6-8 Hours

Question 4.
What is cell division? Mention the types of cell division.
Answer:
The division of cells into two (or more) daughter cells with same (or different) genetic material is called cell division. There are three types of cell divisions:
1. Amitosis:
a. It is the simplest form of cell division. The nucleus elongates and a constriction appears along its length.
b. This constriction deepens and divides nucleus into two daughter nuclei followed by division of cytoplasm resulting in formation of two daughter cells.
c. This type of division is observed in unicellular organisms, abnormal cells, old cells and in foetal membrane cells.

2. Mitosis:
a. In this type of cell division, the cell divides and forms two similar daughter cells which are identical to the parent cell.
b. It is completed in two steps as karyokinesis and cytokinesis.

3. Meiosis:
a. In this type of cell division, the number of chromosomes is reduced to half. Hence, this type of cell division is also called reductional division.
b. Meiosis produces four haploid daughter cells from a diploid parent cell.

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 5.
With the help of suitable diagrams, explain karyokinesis in brief.
Answer:
Karyokinesis is the nuclear division which is divided into prophase, metaphase, anaphase and telophase.
1. Prophase:
a. In this phase, condensation of chromatin material, migration of centrioles, appearance of mitotic apparatus and disappearance of nuclear membrane takes place.
b. Due to condensation, each chromosome with its sister chromatids connected by centromere is clearly visible under light microscope.
c. The nucleolus starts to disappear.
d. Centrosome start moving towards the opposite poles of the cell.
e. Mitotic apparatus is almost completely formed.

2. Metaphase:
a. Chromosomes are completely condensed and appear short.
b. Centromere and sister chromatids become very prominent.
c. All the chromosomes are arranged at equatorial plane of cell. This is called metaphase plate.
d. Mitotic spindle is fully formed in this phase.
e. Centromere of each chromosome divides horizontally into two, each being associated with a chromatid. [Note: The centromeres divide at the beginning of anaphase so that the two chromatids of each chromosome become separated from each other.
Source: Cell Division, Donald B. McMillan, Richard J. Harris, in An Atlas of Comparative Vertebrate Histology, 2018.]

3. Anaphase:
a. In this phase, chromatids of each chromosome separate and form two chromosomes called daughter chromosomes.
b. The chromosomes which are formed are pulled away in opposite direction by spindle apparatus.
c. Anaphase ends when each set of chromosomes reach at opposite poles of the cell.

4. Telophase:
a. This is the final stage of karyokinesis.
b. The chromosomes with their centromeres begin to uncoil at the poles.
c. The chromosomes lengthen and lose their individuality.
d. The nucleolus reappears and the nuclear membrane appear around the chromosomes.
e. Spindle fibres breakdown and get absorbed in the cytoplasm. Thus, two daughter nuclei are formed.

These are small disc-shaped structures at the surface of the centromeres which serve as the sites of attachment of spindle fibres to the chromosomes.

Question 6.
Draw neat and labelled diagram of Anaphase.
Answer:
Anaphase:
a. In this phase, chromatids of each chromosome separate and form two chromosomes called daughter chromosomes.
b. The chromosomes which are formed are pulled away in opposite direction by spindle apparatus.
c. Anaphase ends when each set of chromosomes reach at opposite poles of the cell.

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 7.
Match the following.

Column I Column II
1. Prophase (a) Chromatids moving to opposite poles.
2. Metaphase (b) Nuclear membrane starts disappearing.
3. Anaphase (c) Chromosomes at equatorial plane of the cell.
4. Telophase (d) Nuclear membrane reappears

Answer:

Column I Column II
1. Prophase (b) Nuclear membrane starts disappearing.
2. Metaphase (c) Chromosomes at equatorial plane of the cell.
3. Anaphase (a) Chromatids moving to opposite poles.
4. Telophase (d) Nuclear membrane reappears

Question 8.
Observe the given diagram and explain the depicted process in your own words.
Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division 1
Answer:

  1. The process depicted in the given diagram is cytokinesis in animal cell.
  2. This step takes place at the end of karyokinesis (nuclear division) of mitosis.
  3. It depicts the division of the cytoplasmic material in order to form two daughter cells that resemble each other.
  4. The division starts with a constriction generally at the equator. This constriction gradually deepens and ultimately joins in the centre dividing into two cells.
  5. At the time of cytoplasmic division, organelles like mitochondria and plastids get distributed between the two daughter cells.

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 9.
Diagrammatically differentiate between cytokinesis in animal cell and plant cell.
Answer:
Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division 2

Question 10.
How cell wall is formed in plant cell?
Answer:
The formation of the new cell wall begins with the formation of a simple precursor, called the ‘cell-plate’ that represents the middle lamella between the walls of two adjacent cells.

Question 11.
What is necrosis?
Answer:
Necrosis is a form of cell injury which leads to the premature death of cells. For example: due to scrape or a harmful chemical.

Question 12.
What is apoptosis? Write its significance.
Answer:

  1. Apoptosis also known as programmed cell death or cellular suicide. In apoptosis cells die in controlled way.
  2. For example: during embryonic development the cells between the embryonic fingers die in a normal process called apoptosis to give a definite shape to the fingers.
  3. Apoptosis also helps in eliminating potential cancer cells.

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 13.
Which type of cell division is known as reductional division? Why?
Answer:
1. Meiosis is known as reductional division.
2. The number of chromosome is reduced to half, hence, meiosis is known as reductional division.

Question 14.
Describe the various phases of heterotypic division.
Answer:
Heterotypic division is first meiotic division, during which a diploid cell is divided into two haploid cells. The daughter cells resulting from this division are different from the parent cell in chromosome number. Hence the division is called heterotypic division.
It consists of following phases:
1. Prophase -I:
It is the most complicated and longest phase of meiotic division.
It is further divided into five sub-phases viz. leptotene, zygotene, pachytene, diplotene and diakinesis.

a. Leptotene:

  1. The volume of the nucleus increases.
  2. The chromosomes become long distinct and coiled.
  3. They orient themselves in a specific fonn known as bouquet stage. This is characterized with the ends of chromosomes converged towards the side of nucleus where the centrosome lies.
  4. The centriole duplicates into two and migrates to opposite poles. [Note: Centrioles divide during Gj phase of interphase.]

b. Zygotene:

  1. Pairing of non-sister chromatids of homologous chromosomes takes place by formation of synaptonemal complex. This pairing is called synapsis.
  2. Each pair consists of a maternal chromosome and a paternal chromosome. Chromosomal pairs are called bivalents or tetrads.

c. Pachytene:

  1. Each individual chromosome begins to split longitudinally into two similar chromatids. Therefore, each bivalent now appears as a tetrad consisting of four chromatids.
  2. The homologous chromosomes begin to separate but they do not separate completely and remain attached to one or more points. These points are called chiasmata (Appear like a cross-X).
  3. Chromatids break at these points and broken segments are exchanged between non-sister chromatids of homologous chromosomes resulting in recombination.

d. Diplotene:
The chiasma becomes clearly visible in diplotene due to beginning of repulsion between synapsed homologous chromosomes. This is known as desynapsis. Synaptonemal complex also starts to disappear.

e. Diakinesis:

  1. The chiasmata begin to move along the length of chromosomes from the centromere towards the ends of chromosomes. The displacement of chiasmata is termed as terminalization.
  2. The terminal chiasmata exist till the metaphase.
  3. The nucleolus and nuclear membrane completely disappear and spindle fibres begin to appear.

2. Metaphase -1:
a. The spindle fibres are well developed.
b. The tetrads orient themselves on equator in such a way that centromeres of homologous tetrads lie towards the poles and arms towards the equator.
c. They are ready to separate as repulsive force increases.
a. Homologous chromosomes are carried towards the opposite poles by spindle apparatus. This is known as disjunction.
b. The two sister chromatids of each chromosome do not separate in meiosis -I. This is reductional division.
c. The sister chromatids of each chromosome are connected by a common centromere.
d. Both sister chromatids of each chromosome are now different in genetic content as one of them has undergone recombination.
Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division 3

3. Anaphase – I:
1. Homologous chromosomes are carried towards the opposite poles by spindle apparatus. This is known as disjunction.
2. The two sister chromatids of each chromosome do not separate in meiosis -I. This is reductional division.
3. The sister chromatids of each chromosome are connected by a common centromere.
4. Both sister chromatids of each chromosome are now different in genetic content as one of them has undergone recombination.
Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division 4

4. Telophase-I:
a. The haploid number of chromosomes becomes uncoiled and elongated after reaching their respective poles.
b. The nuclear membrane and nucleolus reappear and thus two daughter nuclei are formed.
Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division 5

Cytokinesis -1:
Cytokinesis occurs after karyokinesis and two haploid cells are formed. In many cases, these daughter cells pass through interkinesis.
Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division 6
[Note: The association between the homologous chromosomes i.e. chiasmata remain till metaphase I. During metaphase /, the paired homologous chromosomes move to the metaphase plate. In anaphase [ the spindle fibers begin to shorten. As these spindle fibres shorten, the association between homologous chromosomes (chiasmata) are broken, allowing homologous chromosomes to be pulled to opposite poles.]

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 15.
What is Homotypic Division? Explain its phases.
Answer:
Two haploid cells formed during first meiotic division divide further into four haploid cells this division is called homotypic division. It consists of five phases: prophase – II, metaphase – II, anaphase – II, telophase – II, and Cytokinesis – II.
Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division 7

1. Prophase-II:
a. The chromosomes are distinct with two chromatids.
b. Each centriole divides into two resulting in formation of two centrioles which migrate to opposite poles and form asters.
c. Spindle fibres are formed between the centrioles.
d. The nuclear membrane and nucleolus disappears in this phase.

2. Metaphase -II:
a. Chromosomes are arranged at the equator.
b. The two chromatids of each chromosome are separated by division of the centromere.
c. Some of the spindle fibres are attached to the centromeres and some are arranged end to end between two opposite centrioles.

3. Anaphase – II:
In this phase, the separated chromatids become daughter chromosomes and move to opposite poles due to the contraction of the spindle fibres attached to centromeres.

4. Telophase – II:
a. In this stage daughter chromosomes starts to uncoil.
b. The nuclear membrane surrounds each group of chromosomes.
c. Nucleolus reappears in this phase.

5. Cytokinesis – II
a. Cytokinesis takes place after the nuclear division.
b. Two haploid cells are formed from each haploid cell.
c. Thus, four haploid daughter cells are formed.
d. These cells then undergo changes to form gametes.

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 16.
Why meiosis is important?
Answer:

  1. Meiotic division produces gametes or spores.
  2. If it is absent, the number of chromosomes would double or quadruple resulting in the formation of monstrosities (abnormal gametes).
  3. The constant number of chromosomes in a given species across generations is maintained by meiosis and fertilization.
  4. Because of crossing over, exchange of genetic material takes place leading to genetic variations, which are the raw materials for evolution.

Question 17.
Observe the diagram and answer the questions given below it.
Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division 8
1. Identify the type of cell division shown in the diagram.
2. Write its significance of meiosis.
Answer:
1. The type of cell division shown in diagram is meiosis II.
2. Meiotic division produces gametes or spores.

  1. If it is absent, the number of chromosomes would double or quadruple resulting in the formation of monstrosities (abnormal gametes).
  2. The constant number of chromosomes in a given species across generations is maintained by meiosis and fertilization.
  3. Because of crossing over, exchange of genetic material takes place leading to genetic variations, which are the raw materials for evolution.

Question 18.
Explain Anaphase-I with a neat labelled diagram.
Answer:
Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division 9
Anaphase:
a. In this phase, chromatids of each chromosome separate and form two chromosomes called daughter chromosomes.
b. The chromosomes which are formed are pulled away in opposite direction by spindle apparatus.
c. Anaphase ends when each set of chromosomes reach at opposite poles of the cell.

Question 19.
What is crossing over? Give its significance.
Answer:
Crossing over:
The process of exchange of genetic material between non-sister chromatids of homologous chromosomes is known as crossing over.
Significance of crossing over:
Crossing over results in genetic recombination of parental characters that leads to variations.

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 20.
What happens during diakinesis?
Answer:

  1. In diakinesis, the chiasmata begin to move along the length of chromosomes from the centromere towards the ends of chromosomes.
  2. The displacement of chiasmata is termed as terminalization. The terminal chiasmata exist till the metaphase.
  3. The nucleolus disappears and the nuclear membrane also begins to disappear.
  4. Spindle fibres starts to appear in the cytoplasm.

Question 21.
Differentiate between anaphase of mitosis and anaphase – I of meiosis.
Answer:

Anaphase of mitosis Anaphase – I of meiosis
1. Centromere divides into two, resulting in the separation of chromatids. Centromere does not divide.
2. Homologous chromosomes are not involved. Homologous chromosomes are involved.
3. Disjunction does not occur. Disjunction occurs.
4. Same number of chromosomes gather at each pole. Half the chromosome number gather at respective pole.

Question 22.
Give reasons: Meiosis is known as reductional division.
Answer:
Meiosis is known as reductional division because the parent cell produces four daughter cells each having half the number of chromosomes present in the parent cell.

Question 23.
Fill in the blanks:

  1. The process of mitosis maintains the _______.
  2. ________ involves the cell death, but it benefits the organism as a whole.
  3. Crossing over takes place in _______ phase of Prophase-I.

Answer:

  1. The process of mitosis maintains the nucleo-cytoplasmic ratio.
  2. Apoptosis involves the cell death, but it benefits the organism as a whole.
  3. Crossing over takes place in pachytene phase of Prophase-I.

Question 24.
1. Complete the following flowchart.
2. Explain the type of cell division in which chromosome number remain the same as that of the parent cell.
Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division 10
Answer:
Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division 11Karyokinesis is the nuclear division which is divided into prophase, metaphase, anaphase and telophase.
1. Prophase:
a. In this phase, condensation of chromatin material, migration of centrioles, appearance of mitotic apparatus and disappearance of nuclear membrane takes place.
b. Due to condensation, each chromosome with its sister chromatids connected by centromere is clearly visible under light microscope.
c. The nucleolus starts to disappear.
d. Centrosome start moving towards the opposite poles of the cell.
e. Mitotic apparatus is almost completely formed.

2. Metaphase:
a. Chromosomes are completely condensed and appear short.
b. Centromere and sister chromatids become very prominent.
c. All the chromosomes are arranged at equatorial plane of cell. This is called metaphase plate.
d. Mitotic spindle is fully formed in this phase.
e. Centromere of each chromosome divides horizontally into two, each being associated with a chromatid. [Note: The centromeres divide at the beginning of anaphase so that the two chromatids of each chromosome become separated from each other.
Source: Cell Division, Donald B. McMillan, Richard J. Harris, in An Atlas of Comparative Vertebrate Histology, 2018.]

3. Anaphase:
a. In this phase, chromatids of each chromosome separate and form two chromosomes called daughter chromosomes.
b. The chromosomes which are formed are pulled away in opposite direction by spindle apparatus.
c. Anaphase ends when each set of chromosomes reach at opposite poles of the cell.

4. Telophase:
a. This is the final stage of karyokinesis.
b. The chromosomes with their centromeres begin to uncoil at the poles.
c. The chromosomes lengthen and lose their individuality.
d. The nucleolus reappears and the nuclear membrane appear around the chromosomes.
e. Spindle fibres breakdown and get absorbed in the cytoplasm. Thus, two daughter nuclei are formed.

These are small disc-shaped structures at the surface of the centromeres which serve as the sites of attachment of spindle fibres to the chromosomes.

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 25.
While studying mitosis, different teams of students made following observations in the cells focused under microscope.
1. In certain cells chromosomes were arranged at equatorial plane with fibres originating from cylindrical structures at both the poles.
2. Few cells showed chromatids moving towards opposite poles.
a. In first observation which stage of mitosis is seen by students and what is the scientific term used to represent cylindrical structures?
b. Which stage is seen in the second observation?
Answer:
a. The stage observed in the first case is metaphase. The scientific term used to represent the cylindrical structures are centrioles.
b. The other stage seen in second observation is anaphase.

Question 26.
During biology practical students were asked to see the slide mounted under microscope and note down their observations. Few students noted that the stage observed is anaphase of mitosis and others said that it is anaphase I of meiosis. Later while explaining about experiments teacher said that it is anaphase I of meiosis. On what basis teacher confirmed that it is anaphase I of meiosis?
Answer:
Chromosomes moving towards opposite poles during anaphase I do not separate at the centromeres.

Question 27.
Colchicine is an alkaloid extracted from plants. It prevents the formation of spindle fibres. In the presence colchicine, if a cell enters mitosis what would be the outcome?
Answer:
The spindle fibres are necessary for segregating the sister chromatids to opposite poles of the cell during anaphase. In the presence of colchicine, no spindle fibres will form to attach to the kinetochores (small disc¬like structures present on chromosomes). Therefore, the cell will be stuck in mitosis with the condensed pairs of sister chromatids in an unorganized array.

Question 28.
Read the following statements and mention whether they are TRUE or FALSE in respective boxes.
1. Life of all multicellular organisms starts from single cell which is known as zygote.
2. Spindle fibres present between centriole and centromere are known as polar fibres which can contract.
3. Growth of every living organism depends on cell division.
4. Spindle fibres present between opposite centrioles are called as kinetochore fibres which can elongate.

(i) (ii) (iii) (iv)
(A) T T F T
(B) F F T F
(C) T F T F
(D) 1 T F F ‘

Answer:
(C)

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 29.
Quick Review

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division 12

Question 30.
Exercise:

Question 1.
Define cell cycle.
Answer:

  1. Sequential events occurring in the life of a cell is called cell cycle.
  2. Interphase and M – phase are the two phases of cell cycle.
  3. Cell undergoes growth or rest during interphase and divides during M – phase.

Question 2.
Observe the following diagram and the questions based on it.
Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division 13
1. If the initial amount of DNA in a cell is 2C then in which phase of cell cycle the amount of this DNA would become 4C? Also name the process.
2. Which sub-phase of the interphase is of short duration?
3. Enlist the phases of karyokinesis in proper order.
Answer:
S – phase (Synthesis phase):
In this phase DNA is synthesized (replicated), so that amount of DNA per cell doubles.
Synthesis of histone proteins takes place in this phase.
Karyokinesis is the nuclear division which is divided into prophase, metaphase, anaphase and telophase.
1. Prophase:
a. In this phase, condensation of chromatin material, migration of centrioles, appearance of mitotic apparatus and disappearance of nuclear membrane takes place.
b. Due to condensation, each chromosome with its sister chromatids connected by centromere is clearly visible under light microscope.
c. The nucleolus starts to disappear.
d. Centrosome start moving towards the opposite poles of the cell.
e. Mitotic apparatus is almost completely formed.

2. Metaphase:
a. Chromosomes are completely condensed and appear short.
b. Centromere and sister chromatids become very prominent.
c. All the chromosomes are arranged at equatorial plane of cell. This is called metaphase plate.
d. Mitotic spindle is fully formed in this phase.
e. Centromere of each chromosome divides horizontally into two, each being associated with a chromatid. [Note: The centromeres divide at the beginning of anaphase so that the two chromatids of each chromosome become separated from each other.
Source: Cell Division, Donald B. McMillan, Richard J. Harris, in An Atlas of Comparative Vertebrate Histology, 2018.]

3. Anaphase:
a. In this phase, chromatids of each chromosome separate and form two chromosomes called daughter chromosomes.
b. The chromosomes which are formed are pulled away in opposite direction by spindle apparatus.
c. Anaphase ends when each set of chromosomes reach at opposite poles of the cell.

4. Telophase:
a. This is the final stage of karyokinesis.
b. The chromosomes with their centromeres begin to uncoil at the poles.
c. The chromosomes lengthen and lose their individuality.
d. The nucleolus reappears and the nuclear membrane appear around the chromosomes.
e. Spindle fibres breakdown and get absorbed in the cytoplasm. Thus, two daughter nuclei are formed.

These are small disc-shaped structures at the surface of the centromeres which serve as the sites of attachment of spindle fibres to the chromosomes.

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 3.
During which stage of Prophase-I synapsis occurs?
Answer:
b. Zygotene:
Pairing of non-sister chromatids of homologous chromosomes takes place by formation of synaptonemal complex. This pairing is called synapsis.
Each pair consists of a maternal chromosome and a paternal chromosome. Chromosomal pairs are called bivalents or tetrads.

Question 4.
During which stage disjunction takes place?
Answer:
Telophase-I:
a. The haploid number of chromosomes becomes uncoiled and elongated after reaching their respective poles.
b. The nuclear membrane and nucleolus reappear and thus two daughter nuclei are formed.

Question 5.
What is disjunction?
Answer:
Telophase-I:
a. The haploid number of chromosomes becomes uncoiled and elongated after reaching their respective poles.
b. The nuclear membrane and nucleolus reappear and thus two daughter nuclei are formed.

Question 6.
Why meiosis is known as reductional division?
Answer:
In this type of cell division, the number of chromosomes is reduced to half. Hence, this type of cell division is also called reductional division.

Question 7.
Sketch and label the phase of cell division in which synaptonemal complex is formed?
Answer:
Zygotene:
Pairing of non-sister chromatids of homologous chromosomes takes place by formation of synaptonemal complex. This pairing is called synapsis.
Each pair consists of a maternal chromosome and a paternal chromosome. Chromosomal pairs are called bivalents or tetrads.

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 8.
Make a schematic representation of a type of cell division in which chromosome number is reduced to half.
Answer:
Karyokinesis is the nuclear division which is divided into prophase, metaphase, anaphase and telophase.
1. Prophase:
a. In this phase, condensation of chromatin material, migration of centrioles, appearance of mitotic apparatus and disappearance of nuclear membrane takes place.
b. Due to condensation, each chromosome with its sister chromatids connected by centromere is clearly visible under light microscope.
c. The nucleolus starts to disappear.
d. Centrosome start moving towards the opposite poles of the cell.
e. Mitotic apparatus is almost completely formed.

2. Metaphase:
a. Chromosomes are completely condensed and appear short.
b. Centromere and sister chromatids become very prominent.
c. All the chromosomes are arranged at equatorial plane of cell. This is called metaphase plate.
d. Mitotic spindle is fully formed in this phase.
e. Centromere of each chromosome divides horizontally into two, each being associated with a chromatid. [Note: The centromeres divide at the beginning of anaphase so that the two chromatids of each chromosome become separated from each other.
Source: Cell Division, Donald B. McMillan, Richard J. Harris, in An Atlas of Comparative Vertebrate Histology, 2018.]

3. Anaphase:
a. In this phase, chromatids of each chromosome separate and form two chromosomes called daughter chromosomes.
b. The chromosomes which are formed are pulled away in opposite direction by spindle apparatus.
c. Anaphase ends when each set of chromosomes reach at opposite poles of the cell.

4. Telophase:
a. This is the final stage of karyokinesis.
b. The chromosomes with their centromeres begin to uncoil at the poles.
c. The chromosomes lengthen and lose their individuality.
d. The nucleolus reappears and the nuclear membrane appear around the chromosomes.
e. Spindle fibres breakdown and get absorbed in the cytoplasm. Thus, two daughter nuclei are formed.

These are small disc-shaped structures at the surface of the centromeres which serve as the sites of attachment of spindle fibres to the chromosomes.

Question 9.
Describe mitosis and its stages in brief.
Answer:
Karyokinesis is the nuclear division which is divided into prophase, metaphase, anaphase and telophase.
1. Prophase:
a. In this phase, condensation of chromatin material, migration of centrioles, appearance of mitotic apparatus and disappearance of nuclear membrane takes place.
b. Due to condensation, each chromosome with its sister chromatids connected by centromere is clearly visible under light microscope.
c. The nucleolus starts to disappear.
d. Centrosome start moving towards the opposite poles of the cell.
e. Mitotic apparatus is almost completely formed.

2. Metaphase:
a. Chromosomes are completely condensed and appear short.
b. Centromere and sister chromatids become very prominent.
c. All the chromosomes are arranged at equatorial plane of cell. This is called metaphase plate.
d. Mitotic spindle is fully formed in this phase.
e. Centromere of each chromosome divides horizontally into two, each being associated with a chromatid. [Note: The centromeres divide at the beginning of anaphase so that the two chromatids of each chromosome become separated from each other.
Source: Cell Division, Donald B. McMillan, Richard J. Harris, in An Atlas of Comparative Vertebrate Histology, 2018.]

3. Anaphase:
a. In this phase, chromatids of each chromosome separate and form two chromosomes called daughter chromosomes.
b. The chromosomes which are formed are pulled away in opposite direction by spindle apparatus.
c. Anaphase ends when each set of chromosomes reach at opposite poles of the cell.

4. Telophase:
a. This is the final stage of karyokinesis.
b. The chromosomes with their centromeres begin to uncoil at the poles.
c. The chromosomes lengthen and lose their individuality.
d. The nucleolus reappears and the nuclear membrane appear around the chromosomes.
e. Spindle fibres breakdown and get absorbed in the cytoplasm. Thus, two daughter nuclei are formed.

These are small disc-shaped structures at the surface of the centromeres which serve as the sites of attachment of spindle fibres to the chromosomes.

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 10.
Describe chiasmata. Draw diagram to illustrate your answer.
Answer:
Pachytene:
Each individual chromosome begins to split longitudinally into two similar chromatids. Therefore, each bivalent now appears as a tetrad consisting of four chromatids.
The homologous chromosomes begin to separate but they do not separate completely and remain attached to one or more points. These points are called chiasmata (Appear like a cross-X).
Chromatids break at these points and broken segments are exchanged between non-sister chromatids of homologous chromosomes resulting in recombination.

Diplotene:
The chiasma becomes clearly visible in diplotene due to beginning of repulsion between synapsed homologous chromosomes. This is known as desynapsis. Synaptonemal complex also starts to disappear.

Question 11.
Correct the following diagram and write a short note on it.
Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division 14
Answer:
b. Zygotene:
Pairing of non-sister chromatids of homologous chromosomes takes place by formation of synaptonemal complex. This pairing is called synapsis.
Each pair consists of a maternal chromosome and a paternal chromosome. Chromosomal pairs are called bivalents or tetrads.

Question 12.
Explain prophase I in your own words.
Answer:
Prophase -I:
It is the most complicated and longest phase of meiotic division.
It is further divided into five sub-phases viz. leptotene, zygotene, pachytene, diplotene and diakinesis.

Question 13.
Explain homotypic division.
Answer:
Two haploid cells formed during first meiotic division divide further into four haploid cells this division is called homotypic division. It consists of five phases: prophase – II, metaphase – II, anaphase – II, telophase – II, and Cytokinesis – II.

1. Prophase-II:
a. The chromosomes are distinct with two chromatids.
b. Each centriole divides into two resulting in formation of two centrioles which migrate to opposite poles and form asters.
c. Spindle fibres are formed between the centrioles.
d. The nuclear membrane and nucleolus disappears in this phase.

2. Metaphase -II:
a. Chromosomes are arranged at the equator.
b. The two chromatids of each chromosome are separated by division of the centromere.
c. Some of the spindle fibres are attached to the centromeres and some are arranged end to end between two opposite centrioles.

3. Anaphase – II:
In this phase, the separated chromatids become daughter chromosomes and move to opposite poles due to the contraction of the spindle fibres attached to centromeres.

4. Telophase – II:
a. In this stage daughter chromosomes starts to uncoil.
b. The nuclear membrane surrounds each group of chromosomes.
c. Nucleolus reappears in this phase.

5. Cytokinesis – II
a. Cytokinesis takes place after the nuclear division.
b. Two haploid cells are formed from each haploid cell.
c. Thus, four haploid daughter cells are formed.
d. These cells then undergo changes to form gametes.

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 14.
How does cytokinesis in plant cells differ from animal cells?
Answer:
The formation of the new cell wall begins with the formation of a simple precursor, called the ‘cell-plate’ that represents the middle lamella between the walls of two adjacent cells.

Question 15.
What is the significance of meiosis in sexually reproducing animals?
Answer:

  1. Meiotic division produces gametes or spores.
  2. If it is absent, the number of chromosomes would double or quadruple resulting in the formation of monstrosities (abnormal gametes).
  3. The constant number of chromosomes in a given species across generations is maintained by meiosis and fertilization.
  4. Because of crossing over, exchange of genetic material takes place leading to genetic variations, which are the raw materials for evolution.
  5. Gametes are produced by the process of meiosis which are essential for sexual reproduction.
  6. Diploid organisms have two set of chromosomes (one paternal and one maternal).
  7. For a diploid organism to undergo sexual reproduction it needs to create gametes that contain only one set of chromosomes so the number of chromosomes remains same in the next generation.
  8. In absence of meiosis, the chromosome number of parents and their offsprings will differ in every generation; hence no species will hold its characters.
  9. Also, there will be no crossing over of homologous chromosomes. Thus, there will be no variations with respect to the changing environment in progeny to maintain their existence, which may lead to extinction of species.

Question 16.
Explain the first three stages of Meiosis II.
Answer:
Two haploid cells formed during first meiotic division divide further into four haploid cells this division is called homotypic division. It consists of five phases: prophase – II, metaphase – II, anaphase – II, telophase – II, and Cytokinesis – II.

1. Prophase-II:
a. The chromosomes are distinct with two chromatids.
b. Each centriole divides into two resulting in formation of two centrioles which migrate to opposite poles and form asters.
c. Spindle fibres are formed between the centrioles.
d. The nuclear membrane and nucleolus disappears in this phase.

2. Metaphase -II:
a. Chromosomes are arranged at the equator.
b. The two chromatids of each chromosome are separated by division of the centromere.
c. Some of the spindle fibres are attached to the centromeres and some are arranged end to end between two opposite centrioles.

3. Anaphase – II:
In this phase, the separated chromatids become daughter chromosomes and move to opposite poles due to the contraction of the spindle fibres attached to centromeres.

4. Telophase – II:
a. In this stage daughter chromosomes starts to uncoil.
b. The nuclear membrane surrounds each group of chromosomes.
c. Nucleolus reappears in this phase.

5. Cytokinesis – II
a. Cytokinesis takes place after the nuclear division.
b. Two haploid cells are formed from each haploid cell.
c. Thus, four haploid daughter cells are formed.
d. These cells then undergo changes to form gametes.

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 17.
Sketch, label and describe telophase in mitosis.
Answer:
Telophase:
a. This is the final stage of karyokinesis.
b. The chromosomes with their centromeres begin to uncoil at the poles.
c. The chromosomes lengthen and lose their individuality.
d. The nucleolus reappears and the nuclear membrane appear around the chromosomes.
e. Spindle fibres breakdown and get absorbed in the cytoplasm. Thus, two daughter nuclei are formed.

These are small disc-shaped structures at the surface of the centromeres which serve as the sites of attachment of spindle fibres to the chromosomes.

Question 18.
Explain the process recombination.
Answer:
a. Recombination is exchange of genetic material between paternal and maternal chromosomes during gamete formation.
b. The points where crossing over takes place is known as chiasmata.
c. Chromatids acquire new combinations of alleles by physically exchanging segments in crossing-over.
d. The exchange of genetic material between homologous chromosomes involves accurate breakage and joining of DNA molecules through a complex mechanism.
e. It is catalyzed by enzymes.

Question 19.
1. What is necrosis?
2. What is apoptosis? Mention its significance.
Answer:
1. Necrosis is a form of cell injury which leads to the premature death of cells. For example: due to scrape or a harmful chemical.
(2) 1. Apoptosis also known as programmed cell death or cellular suicide. In apoptosis cells die in controlled way.
2. For example: during embryonic development the cells between the embryonic fingers die in a normal process called apoptosis to give a definite shape to the fingers.
3. Apoptosis also helps in eliminating potential cancer cells.

Question 20.
Multiple Choice Questions:

Question 1.
Replication of DNA takes place during
(A) prophase
(B) S-phase
(C) G2 phase
(D) Interkinesis
Answer:
(B) S-phase

Question 2.
During cell division, spindle fibers are attached to
(A) telomere
(B) centromere
(C) chromomeres
(D) chromosome
Answer:
(B) centromere

Question 3.
Which of the following is the shortest phase?
(A) metaphase
(B) anaphase
(C) interphase
(D) S-phase
Answer:
(B) anaphase

Question 4.
Reappearance of nucleolus is during
(A) telophase
(B) prophase
(C) cytokinesis
(D) inter-kinesis
Answer:
(A) telophase

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 5.
During telophase,
(A) nuclear membrane is formed.
(B) nucleolus appears.
(C) astral rays disappear.
(D) all the above
Answer:
(D) all the above

Question 6.
Cytokinesis in plant cell takes place by
(A) furrowing
(B) cell plate formation
(C) any one of (A) or (B)
(D) none of these
Answer:
(B) cell plate formation

Question 7.
Meiosis is a
(A) homotypic division
(B) equatorial division
(C) reductional division
(D) none of the above
Answer:
(C) reductional division

Question 8.
Formation of Synaptonemal complex during meiosis occurs at
(A) Leptotene
(B) Zygotene
(C) Diplotene
(D) Pachytene
Answer:
(B) Zygotene

Question 9.
Crossing over takes place in the ________ stage.
(A) leptotene
(B) zygotene
(C) pachytene
(D) diplotene
Answer:
(C) pachytene

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 10.
Crossing over takes place between
(A) sister chromatids
(B) non-homologous chromosomes
(C) non-sister chromatids of homologues
(D) any two chromatids
Answer:
(C) non-sister chromatids of homologues

Question 11.
Crossing over of chromosomes during meiosis leads to
(A) mutation
(B) sex determination
(C) new gene combination
(D) loss of chromosomes
Answer:
(C) new gene combination

Question 12.
Points at which crossing over has taken place between homologous chromosomes are called
(A) chiasmata
(B) synaptonemal complexes
(C) centromeres
(D) telomere
Answer:
(A) chiasmata

Question 13.
Which of the following events take place during diplotene stage of prophase I of meiosis?
(A) Compaction of chromosomes
(B) Formation of synapsis
(C) Process of crossing over
(D) Repulsion of homologues
Answer:
(D) Repulsion of homologues

Question 14.
The correct sequence of stages in prophase I of meiosis is
(A) Leptotene, Pachytene, Zygotene, Diakinesis, Diplotene
(B) Zygotene, Leptotene, Pachytene, Diakinesis, Diplotene
(C) Leptotene, Zygotene, Pachytene, Diplotene, Diakinesis
(D) Diplotene, Diakinesis, Pachytene, Zygotene, Leptotene
Answer:
(C) Leptotene, Zygotene, Pachytene, Diplotene, Diakinesis

Question 15.
In which phase of meiosis are homologous chromosomes separated?
(A) Anaphase I
(B) Prophase II
(C) Anaphase II
(D) Prophase I
Answer:
(A) Anaphase I

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 16.
Mitosis differs from meiosis in not having
(A) Long prophase
(B) duplication of DNA
(C) Synapsis and crossing over
(D) interphase
Answer:
(C) Synapsis and crossing over

Question 17.
How many divisions are required to produce 128 gametes?
(A) 64
(B) 16
(C) 32
(D) 12
Answer:
(C) 32

Question 18.
Number of cells undergoing meiotic divisions to produce 124 microspores in angiosperm is
(A) 62
(B) 31
(C) 124
(D) 8
Answer:
(B) 31

Question 19.
How many haploid daughter cells are produced at the end of meiosis-II?
(A) 2
(B) 4
(C) 6
(D) 8
Answer:
(B) 4

Question 21.
Competitive Corner:

Question 1.
Crossing over takes place between which chromatids and in which stage of the cell cycle?
(A) Non-sister chromatids of nonhomologous chromosomes at Pachytene stage of prophase I
(B) Non-sister chromatids of nonhomologous chromosomes at Zygotene stage of prophase I
(C) Non-sister chromatids of homologous chromosomes at Pachytene stage of prophase I
(D) Non-sister chromatids of homologous chromosomes at Zygotene stage of prophase I
Answer:
(C) Non-sister chromatids of homologous chromosomes at Pachytene stage of prophase I

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 2.
After meiosis I, the resultant daughter cells have
(A) four times the amount of DNA in comparison to haploid gamete.
(B) same amount of DNA as in the parent cell in S phase.
(C) twice the amount of DNA in comparison to haploid gamete.
(D) same amount of DNA in comparison to haploid gamete.
Answer:
(C) twice the amount of DNA in comparison to haploid gamete.

Question 3.
Cells in G0 phase
(A) suspend the cell cycle
(B) terminate the cell cycle
(C) exit the cell cycle
(D) enter the cell cycle
Answer:
(C) exit the cell cycle

Question 4.
The CORRECT sequence of phases of cell cycle is: [NEET (UG) 2019]
(A) S → G1 → G2 → M
(B) G1 → S → G2 → M
(C) M → G1 → G2 → S
(D) G1 → G2 → S → M
Answer:
(B) G1 → S → G2 → M

Question 5.
The stage during which separation of the paired homologous chromosomes begins is
(A) Diakinesis
(B) Diplotene
(C) Pachytene
(D) Zygotene
Answer:
(B) Diplotene

Question 6.
Which of the following options gives the correct sequence of events during mitosis?
(A) Condensation → nuclear membrane disassembly → crossing over – segregation → telophase
(B) Condensation → nuclear membrane disassembly → arrangement at equator → centromere division → segregation → telophase
(C) Condensation → crossing over → nuclear membrane disassembly → segregation → telophase
(D) Condensation → arrangement at equator → centromere division → segregation → telophase
Answer:
(B) Condensation → nuclear membrane disassembly → arrangement at equator → centromere division → segregation → telophase

Question 7.
Which of the following is not a characteristic feature during mitosis in somatic cells?
(A) Chromosome movement
(B) Synapsis
(C) Spindle fibres
(D) Disappearance of nucleolus
Answer:
(B) Synapsis

Maharashtra Board Class 11 Biology Important Questions Chapter 7 Cell Division

Question 8.
Arrange the following events of meiosis in correct sequence. [AIPMT Retest 2015]
(a) Crossing over
(b) Synapsis
(c) Terminalisation of chiasmata
(d) Disappearance of nucleolus
(A) (b), (c), (d), (a)
(B) (b), (a), (d), (c)
(C) (b),(a), (c), (d)
(D) (a), (b), (c), (d)
Answer:
(C) (b),(a), (c), (d)

Maharashtra Board 11th BK Important Questions Chapter 4 Ledger

Balbharti Maharashtra State Board 11th Commerce Book Keeping & Accountancy Important Questions Chapter 4 Ledger Important Questions and Answers.

Maharashtra State Board 11th Commerce BK Important Questions Chapter 4 Ledger

1. Answer in one sentence only.

Question 1.
State the meaning of ‘Debit Balance’.
Answer:
Excess of the debit total of an account over its credit total is called debit balance.

Question 2.
What do you mean by Credit Balance?
Answer:
Excess of credit total of an account over its debit total is called credit balance.

Maharashtra Board 11th BK Important Questions Chapter 4 Ledger

Question 3.
What is the balance of Outstanding Salary A/c?
Answer:
The balance of Outstanding Salary A/c is a credit balance.

Question 4.
What is the balance of Cash A/c?
Answer:
The balance of Cash A/c is always a debit balance.

Question 5.
Where is the balance of Salaries A/c transferred at the end of the year?
Answer:
At the end of the year, the balance of Salaries A/c is transferred to Profit and Loss A/c.

Question 6.
From which books of accounts posting is made in the Ledger?
Answer:
From Journal and Subsidiary books posting is made in the ledger.

Maharashtra Board 11th BK Important Questions Chapter 4 Ledger

Question 7.
What do you mean by the head of an Account?
Answer:
The name of the account which is written on the top of the ledger account in the middle is called “Head of an account”.

2. Write the word, term, phrase, which can substitute each of the statements.

Question 1.
A bound book of Account.
Answer:
Ledger

Question 2.
The credit balance of the Bank Account.
Answer:
Bank Overdraft

Question 3.
Recording of transactions from Journal to Ledger.
Answer:
Ledger Posting

Maharashtra Board 11th BK Important Questions Chapter 4 Ledger

Question 4.
Page number of Ledger.
Answer:
L.F. No.

Question 5.
The right-hand side of an account.
Answer:
Credit Side

Question 6.
The left-hand side of an account.
Answer:
Debit Side

Question 7.
Excess of a debit total of an account over its credit total.
Answer:
Debit Balance

Question 8.
Excess of credit total of an account over its debit total.
Answer:
Credit Balance

Maharashtra Board 11th BK Important Questions Chapter 4 Ledger

Question 9.
A secondary book of account in which entries are recorded from Journal or Subsidiary books.
Answer:
Ledger

Question 10.
Page of the account book.
Answer:
Folio

Question 11.
A book of accounts in which all ledger accounts are maintained.
Answer:
Ledger

Question 12.
Type of accounts that are not balanced but transferred to Trading Account or P/L A/c.
Answer:
Nominal Accounts

Question 13.
An account where the total purchase book is posted.
Answer:
Purchases Account

Maharashtra Board 11th BK Important Questions Chapter 4 Ledger

Question 14.
A statement of accounts’s prepared from the balances of the ledger account.
Answer:
Trial Balance

3. Select appropriate alternatives from those given below and rewrite the sentences.

Question 1.
_______________ is the act of transferring an entry from journal to ledger.
(a) Journalising
(b) Casting
(c) Balancing
(d) Posting
Answer:
(d) Posting

Question 2.
Cash account always shows _______________ balance.
(a) Credit
(b) Negative
(c) Minus
(d) Debit
Answer:
(d) Debit

Question 3.
Bank overdraft means _______________ balance of Bank A/c.
(a) Debit
(b) Credit
(c) Positive
(d) Nil
Answer:
(b) Credit

Maharashtra Board 11th BK Important Questions Chapter 4 Ledger

Question 4.
Real accounts generally shows _______________ balance.
(a) Debit
(b) Credit
(c) Negative
(d) Nil
Answer:
(a) Debit

Question 5.
Excess of debit total of an account over it’s credit total indicates _______________ balance.
(a) Negative
(b) Positive
(c) Debit
(d) Credit
Answer:
(c) Debit

Question 6.
When goods are sold on credit _______________ account is credited.
(a) Buyer’s A/c
(b) Cash A/c
(c) Sales A/c
(d) Seller’s A/c
Answer:
(c) Sales A/c

Question 7.
When the total of debit side of an account exceeds credit side, it is called _______________ balance.
(a) Debit
(b) Credit
(c) Nil
(d) Real
Answer:
(a) Debit

Question 8.
Machinery A/c shows _______________ balance.
(a) Credit
(b) Debit
(c) Positive
(d) Negative
Answer:
(b) Debit

Maharashtra Board 11th BK Important Questions Chapter 4 Ledger

Question 9.
Left hand side of an account is called _______________
(a) Credit
(b) Debit
(c) Middle
(d) Centre
Answer:
(b) Debit

Question 10.
_______________ is prepared from the balances in the ledger accounts.
(a) List
(b) Journal
(c) Book
(d) Trial Balance
Answer:
(d) Trial Balance

Question 11.
Total of Sales book is _______________ to sales account.
(a) entered
(b) moved
(c) posted
(d) given
Answer:
(c) posted

Question 12.
Wages A/c is transferred to _______________ A/c.
(a) Trading A/c
(b) Profit & Loss A/c
(c) Trial Balance
(d) Any
Answer:
(a) Trading A/c

Question 13.
All entries are posted from Journal to _______________
(a) Ledger
(b) Balance Sheet
(c) Trial Balance
(d) Cash A/c
Answer:
(a) Ledger

4. State whether the following statements are ‘True or False’ with reasons.

Question 1.
Ledger accounts are balanced every day.
Answer:
This statement is False.
Ledger accounts are balanced on a particular period of time or on the accounting year of the firm. They are not balanced every day.

Maharashtra Board 11th BK Important Questions Chapter 4 Ledger

Question 2.
Every account is divided into two sides.
Answer:
This statement is True.
Every account is divided into two sides i.e. Debit and Credit to do ledger pasting from a journal which follows the rules of double-entry book-keeping.

Question 3.
The discount allowed is a real account.
Answer:
This statement is False.
Discount allowed is an expense for the business. All expenses come under the Nominal account. So the discount allowed is a Nominal account.

Question 4.
The bank is a Nominal A/c.
Answer:
This statement is False.
A bank is an Artificial person created by law. The bank is personal accounts.

Question 5.
Accounts of expenses may show a credit balance.
Answer:
This statement is False.
Accounts of expenses always show debit balance. They fall under the nominal account and its Golden rule is to Debit all Expenses.

Question 6.
A Debtors A/c always show a credit balance.
Answer:
This statement is False.
A Debtor A/c always shows a Debit balance. The debtor is a personal account and as per the rule of personal account Debit the receiver.

Maharashtra Board 11th BK Important Questions Chapter 4 Ledger

Question 7.
When goods are sold for cash, the personal a/c of the buyer is debited.
Answer:
This statement is False.
In a cash transaction, there is no Personal A/c. The personal account comes in a credit transaction. So when goods are sold for cash, the cash account is debited. A cash account is a real account and as per rule debit what comes in.

Question 8.
Capital a/c is a nominal a/c.
Answer:
This statement is False.
Capital is a Personal account. Capital is the amount invested by the proprietor in his business. A proprietor is a person. Capital is also personal A/c.

Question 9.
Drawing a/c is a personal a/c.
Answer:
This statement is True.
Drawings mean cash or goods withdrawn by the proprietor for his personal or family use he is a person. So drawing is personal A/c.

Question 10.
Narration is not necessary for a ledger.
Answer:
This statement is False.
Narration is necessary for a Journal book and not in Ledger. Ledgers are self-narrative as every ledger has headed.

Question 11.
All a/c’s are closed down at the end of the accounting year.
Answer:
This statement is True.
All ledger accounts are closed an accounting year or Financial year to prepare the Trial balance and Financial statements of the year.

Question 12.
Recording of a transaction in the journal is called posting.
Answer:
This statement is False.
The process of recording a transaction in the Journal is called Journalising. Posting means transferring journal entries to respective ledger accounts.

Maharashtra Board 11th BK Important Questions Chapter 4 Ledger

Question 13.
Balance of personal a/c is brought down for the next year.
Answer:
This statement is True.
Personal accounts are the account of Debtors or Creditors. The business has to collect or pay amounts on personal accounts. Current year collections or payments are done in the following year. So balances of personal accounts are brought for the next year.

Question 14.
All transactions are recorded directly in the ledger.
Answer:
This statement is False.
First, every transaction is recorded in a Journal book or Subsidiary book and from there they are posted to respective ledger accounts. No transaction can be recorded directly in the ledger.

Question 15.
Ledger Folio and index are necessary for the ledger.
Answer:
This statement is True.
The index is necessary to final particular account on its page number and ledger folio number is also necessary for cross-checking with the journal book. This makes handling convenient and easier.

Question 16.
Ledger posting is not necessary for journal proper.
Answer:
This statement is False.
Ledger posting is necessary for journal proper. From Ledger trial balance and financial statements are prepared for the accounting year. Without posting of journal proper Trial balance and financial statements will not be tally and can’t give true and fair accounting.

Question 17.
Ledger Folio is recorded in the journal.
Answer:
This statement is True.
Ledger folio is a page of the ledger, where posting is made from a journal book. For cross-reference, the ledger folio is recorded in the journal.

Maharashtra Board 11th BK Important Questions Chapter 4 Ledger

Question 18.
Ledger posting is made before journal entry.
Answer:
This statement is False.
Ledger posting is made after journal entry. First, all transactions are recorded to Journal and from the journal, posting is made to Ledger.

5. Fill in the blanks.

Question 1.
Debtors A/c shows _______________ balance.
Answer:
Debit

Question 2.
Left hand side of an account is called _______________ side.
Answer:
Debit

Question 3.
_______________ is prepared from the balances in the Ledger A/c.
Answer:
Trial Balance

Question 4.
Total of salary A/c is transfered to _______________ A/c.
Answer:
Profit and loss A/c

Maharashtra Board 11th BK Important Questions Chapter 4 Ledger

Question 5.
b/d (brought down) balance indicates _______________ balance.
Answer:
Opening

Question 6.
_______________ Balance on Nominal Account shows Inconies or gains.
Answer:
Credit

Question 7.
Debtors A/c shows _______________ balance.
Answer:
Debit

Question 8.
Drawing A/c shows _______________ balance.
Answer:
Debit

Question 9.
Wages A/c balance transferred to _______________ A/c.
Answer:
Profit and Loss

Question 10.
Discount allowed shows _______________ Balance.
Answer:
Debit

Maharashtra Board 11th BK Important Questions Chapter 4 Ledger

Question 11.
Dividend received shows _______________ Balance.
Answer:
Credit

Question 12.
Ledger is the _______________ book of Accounts.
Answer:
Principal

6. Complete the following table.

Question 1.
Maharashtra Board 11th BK Important Questions Chapter 4 Ledger 6 Q1
Answer:
Credit balance

Question 2.
Maharashtra Board 11th BK Important Questions Chapter 4 Ledger 6 Q2
Answer:
Ledger

Question 3.
Maharashtra Board 11th BK Important Questions Chapter 4 Ledger 6 Q3
Answer:
Credit Balance

Maharashtra Board 11th BK Important Questions Chapter 4 Ledger

Question 4.
Maharashtra Board 11th BK Important Questions Chapter 4 Ledger 6 Q4
Answer:
Livestock A/c

Question 5.
Maharashtra Board 11th BK Important Questions Chapter 4 Ledger 6 Q5
Answer:
Output GST

7. Put ‘✓’ mark for the nature of balance for the following.

Question 1.

Account Dr. Balance Cr. Balance
1. Salary A/c
2. Purchase A/c
3. Sales Return A/c
4. Machinery A/c
5. Bank Balance A/c
6. Cash Balance A/c
7. Sale A/c
8. Purchase Return A/c
9. Bills Payable A/c
10. Debtors A/c
11. Creditors A/c
12. Stationery A/c
13. Furniture A/c
14. Amit’s Loan A/c

Answer:

Account Dr. Balance Cr. Balance
1. Salary A/c
2. Purchase A/c
3. Sales Return A/c
4. Machinery A/c
5. Bank Balance A/c
6. Cash Balance A/c
7. Sale A/c
8. Purchase Return A/c
9. Bills Payable A/c
10. Debtors A/c
11. Creditors A/c
12. Stationery A/c
13. Furniture A/c
14. Amit’s Loan A/c

Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger

Balbharti Maharashtra State Board Bookkeeping and Accountancy 11th Solutions Chapter 4 Ledger Textbook Exercise Questions and Answers.

Maharashtra State Board Bookkeeping and Accountancy 11th Solutions Chapter 4 Ledger

1. Answer in one sentence only.

Question 1.
What is Ledger?
Answer:
Ledger is an important book of account in which individual records business transactions with respect to persons, properties, expenses, or losses are maintained.

Question 2.
What is ledger posting?
Answer:
Transferring the entry passed in the journal to the ledger for the individual record is called ledger posting.

Question 3.
When does an account show a nil balance?
Answer:
When the total credit side of an account equals the total of the debit side, such an account shows a nil balance.

Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger

Question 4.
What is Folio?
Answer:
Page number of the account opened in the ledger is called Ledger folio.

Question 5.
Where is the statement form of ledger A/c is used in actual practice?
Answer:
The statement form of ledger A/c is used in the banks and financial institutions to prepare the client’s account showing balances of accounts after each transaction is complete.

Question 6.
Why Proprietor’s Capital account is a liability for the business?
Answer:
Capital invested in the business by the proprietor is an asset for the proprietor and liability for the business.

Question 7.
Why does a cash account never shows a credit balance?
Answer:
Available cash with the business is an asset of the business and the account of every asset shows debit, cash account always shows debit balance.

Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger

Question 8.
What is ‘Trial Balance’?
Answer:
Trial Balance is an abstract or list of all the ledger accounts as on a specified date showing debit total and the credit total of all the accounts or their net balance.

2. Write the word, term, phrase, which can substitute each of the statements.

Question 1.
Principal Book of accounts.
Answer:
Ledger

Question 2.
Transferring a journal entry to the appropriate accounts in the Ledger.
Answer:
Posting

Question 3.
Page number of Ledger to which an entry is posted.
Answer:
Ledger folio

Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger

Question 4.
The process of extracting the balance and inserting it on the lesser side of an account.
Answer:
Balancing

Question 5.
A debit balance to Personal Accounts.
Answer:
Debtor

Question 6.
A credit balance to Bank Account.
Answer:
Bank overdraft

Question 7.
An account to be debited for goods damaged by fire.
Answer:
Loss by fire

Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger

Question 8.
A Trial Balance in which only net balances of all ledger accounts are transferred.
Answer:
Net Trial Balance

3. Select appropriate alternatives from those given below and rewrite the sentences.

Question 1.
In case of a credit transaction one of the account must be a ______________ account.
(a) Cash
(b) Credit
(c) Personal
(d) Debit
Answer:
(c) Personal

Question 2.
‘c/d’ indicates ______________ balance.
(a) Opening
(b) Closing
(c) Positive
(d) Negative
Answer:
(b) Closing

Question 3.
______________ Column of ledger is used for writing page number of Journal.
(a) J.F.
(b) L.F.
(c) Date
(d) Particulars
Answer:
(a) J.F.

Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger

Question 4.
Debtors Account shows ______________ balance.
(a) Real
(b) Negative
(c) Credit
(d) Debit
Answer:
(d) Debit

Question 5.
______________ is the process of deriving the difference between totals of the debit and credit side of each ledger a/c.
(a) Totalling
(b) Journalizing
(c) Balancing
(d) Posting
Answer:
(c) Balancing

Question 6.
Total of Purchase book is ______________ to Purchase Account.
(a) posted
(b) moved
(c) given
(d) entered
Answer:
(a) posted

Question 7.
Real account always shows ______________ balance.
(a) minimum
(b) maximum
(c) debit
(d) credit
Answer:
(c) debit

Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger

Question 8.
______________ is prepared to test arithmetical accuracy of Books of Accounts.
(a) Trial Balance
(b) Ledger
(c) Journal
(d) List
Answer:
(a) Trial Balance

4. State whether the following statements are ‘True or False’ with reasons.

Question 1.
Ledger is a book of Original Entry.
Answer:
This statement is False.
Ledger is a book of Secondary Entry.
Journal is a book of Original Entry: First, all transactions are recorded to journal or subsidiary books, and then they are pasted to the respective ledger accounts.

Question 2.
The process of recording a transaction in the Journal is called Posting.
Answer:
This statement is False.
The process of recording a transaction in the Journal is called Journalising. Posting means transferring journal entries to respective ledger accounts.

Question 3.
A cash withdrawal from business by the trader should be credited to Drawings A/c.
Answer:
This statement is False.
Cash withdrawn from the business by the trader should be debited to Drawing A/c. It is a personal account and as per the golden rules of a personal account Debit the receiver.

Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger

Question 4.
Balances of Nominal Accounts are carried forward to the next year.
Answer:
This statement is False.
Balances of Nominal Accounts are transferral to Trading and Profit and loss accounts of the year to find Gross Profit and Net Profit.

Question 5.
When the debit side of an account is greater than the credit side, the account shows a debit balance.
Answer:
This statement is True.
While balancing the ledger account the side which is greater is the balance of that account so when the debit side of an account is greater the account shows debit balances.

Question 6.
The name of an account written on top of each account is called ‘Head of Account’.
Answer:
This statement is True.
There are many ledger accounts in the ledger book. To identity, the name of the account, every account on the Top Head of Account is written.

Question 7.
Agreement of Trial Balance always proves accounting accuracy.
Answer:
This statement is False.
Even though the Trial balance is tally there may be some mistake like the complete omission of transaction or compensatory error so Agreement of Trial Balance does not always prove accounting accuracy.

Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger

Question 8.
The trial balance is based on the double-entry principle that for every debit there is an equal amount of corresponding credit.
Answer:
This statement is True.
Trial balance is an extract of ledger balances. Ledger is prepared of journal book which follows the Double Entry System of book-keeping. When both the effects of debit and credit with equal amount is given. The trial balance will be tally.

5. Fill in the blanks.

Question 1.
______________ Balance on Nominal Account shows expenses or loss.
Answer:
debit

Question 2.
Cash account always shows ______________ balance.
Answer:
debit

Question 3.
The right hand side of an account is called ______________ side.
Answer:
credit

Question 4.
Creditors shows ______________ balance.
Answer:
credit

Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger

Question 5.
______________ accounts are closed by transferring its balances to Profit and Loss Account.
Answer:
Nominal

Question 6.
‘b/d’ means ______________
Answer:
brought down

Question 7.
Rent paid for the residential quarter will be debited to ______________ account.
Answer:
Drawings

Question 8.
Sold goods of ₹ 24,000 at 20% Profit on cost, the purchase price of the goods is ______________
Answer:
₹ 20,000

6. Complete the following table.

Question 1.
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger 6 Q1
Answer:
Ledger

Question 2.
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger 6 Q2
Answer:
Return outward

Question 3.
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger 6 Q3
Answer:
J.F.

Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger

Question 4.
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger 6 Q4
Answer:
Credit balance

Question 5.
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger 6 Q5
Answer:
Nominal A/c

7. Put ‘4’ mark for the nature of balance for the following.

Question 1.
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger 7 Q1
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger 7 Q1.1
Answer:

Account Dr. Balance Cr. Balance
1. Capital A/c 4
2. Goodwill 4
3. Bank Overdraft 4
4. Bills Receivable 4
5. Creditors 4
6. Drawings 4
7. Advertisement 4
8. Prepaid Rent 4
9. Outstanding Salary 4
10. Bad debts 4

Practical Problems

Question 1.
Give Journal entries of the following posting from the ledger account.
In the books of Sopan
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q1
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q1.1
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q1.2
Solution:
Journal of Sopan
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q1.3
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q1.4

Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger

Question 2.
Prepare necessary Ledger Accounts from the following Subsidiary Books.
Purchase Book
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q2
Purchase Return Book
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q2.1
Solution:
In the Ledger of ______________
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q2.2
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q2.3

Question 3.
From the following transactions prepare necessary Ledger Accounts in the Books of Vinay and balance the same.
2019 Jan.
1 Started business with Cash ₹ 10,000
6 Bought goods from Vikas ₹ 3,000
9 Sold goods to Bhushan ₹ 2,400
12 Paid to Vikas on account ₹ 1,600
19 Received on account from Bhushan ₹ 1,000
25 Cash Purchases ₹ 3,600
30 Cash Sales ₹ 5,000
31 Paid Wages ₹ 400
Solution:
In the Ledger of Vinay
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q3
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q3.1
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q3.2
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q3.3
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q3.4

Question 4.
Journalise the following transactions and prepare Cash A/c only.
2019 July
1 Hardik started the business with Cash ₹ 15,000 and Machinery ₹ 20,000.
4 Purchased goods for ₹ 9,000 less 10% Cash Discount.
9 Sold goods to Amar ₹ 3,000.
12 Distributed goods worth ₹ 700 as free samples.
14 Bought Stationery for ₹ 550 for office use.
18 Received ₹ 950 from Dhanashree, a customer, whose account was earlier written off as a bad debt.
21 Abhiram invoiced us goods worth ₹ 3,000.
24 Settled Abhiram’s account, he allowed 5% cash discount.
27 Exchanged goods worth ₹ 2,500 against Furniture of the same amount.
29 Withdrawn cash from ATM ₹ 5,000 for office use and ₹ 3,000 for personal use.
Solution:
Journal of Hardik ______________
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q4
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q4.1
Ledger of Hardik
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q4.2

Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger

Question 5.
Prepare Aparna’s account in the books of Suparna.
2019 Jan.
1 Balance due from Aparna ₹ 60,000
4 Sold goods to Aparna ₹ 15,000 at 10% Trade Discount.
7 Goods returned by Aparna ₹ 1,500 (Gross)
11 Received crossed cheque from Aparna ₹ 50,000
17 Invoiced goods to Aparna ₹ 12,000
25 Sold goods to Aparna in cash ₹ 6,000
30 Received cash from Aparna ₹ 33,000 in full settlement of her account.
Solution:
Ledger of Suparna
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q5

Working Notes:
Jan. 4:
Trade discount = 10% on ₹ 15,000
= \(\frac {10}{100}\) × ₹ 15,000
= ₹ 1,500
Net Selling Price = Catalogue price – Trade discount
= 15,000 – 1,500
= ₹ 13,500

Question 6.
Prepare Cash A/c, Bank A/c, Purchases A/c, Sales A/c, and Capital A/c and balance the same in the books of Madanlal.
2019 Aug.
1 Started business with a bank balance of ₹ 40,000.
2 Purchased goods from Aseem worth ₹ 15,000 less 10% Trade Discount.
3 Sold goods to Arun for ₹ 8,000 in cash.
4 Paid Rent ₹ 3,000 and Electricity bill ₹ 500.
5 Purchased 100 Shares of Perfect Technologies for ₹ 55 per share and paid Brokerage ₹ 250 by transfer through net banking.
6 Withdrawal of goods for personal use ₹ 500.
7 Sold goods for cash ₹ 5,000 less 10% Cash Discount.
8 Deposited cash into Bank ₹ 2,000.
9 Paid ₹ 3,000 for daughter’s tuition fees by Debit Card.
10 Purchased a Table for ₹ 2,000.
19 Received ₹ 1,500 by selling the scrap.
27 Paid cash into a bank in excess of ₹ 2,000
Solution:
In the Ledger of Madanlal
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q6
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q6.1

Question 7.
Journalise the following transactions; post them into Ledger for February 2019
1 Sunil Started business with a stock of goods ₹ 20,000 and Cash ₹ 1,70,000 out of which ₹ 50,000 borrowed from his friend Kedar @ 10 p.a.
5 Placed an order for goods worth ₹ 7,000 with Mohan for which an advance of ₹ 5,500 was paid.
9 Purchased Stationery for office use ₹ 4,500
12 Goods distributed as free samples ₹ 2,000
17 Paid Freight ₹ 400 on behalf of Mr. Dev.
24 Received Goods from Mohan as per our order dated 5th Feb and settled his account.
27 Bought goods from Shekhar on two months credit for ₹ 7,000 at 20% Trade Discount with instructions to send them to Sagar.
28 Sent to Sagar Outward Invoice for goods supplied by Shekhar, at list price less 10% Trade Discount.
Solution:
Journal of Sunil
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q7
Ledger of Sunil
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q7.1
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q7.2
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q7.3
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q7.4
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q7.5
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q7.6

Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger

Question 8.
Journalise the following transactions and Prepare ledger accounts in the books of Sanjeev.
2019 June
1 Cash Received from Raju ₹ 10,000 for commission.
3 Intra-state sale to Rakesh ₹ 3,000 and SGST @ 2.5% and CGST @ 2.5% applicable.
5 Received full amount from Rakesh.
8 Intra-state purchases from Mangesh ₹ 2,000 and SGST @ 2.5% and CGST @ 2.5% applicable.
11 Paid the necessary amount to Mangesh.
18 Paid Rent ₹ 2,500
24 Paid mobile bill ₹ 1,000 out of which ₹ 700 for office use and for ₹ 300 for personal use.
Solution:
Journal of Sanjeev
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q8
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q8.1
In the Ledger of Sanjeev
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q8.2
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q8.3
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q8.4
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q8.5
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q8.6

Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger

Question 9.
The following ledger balances were extracted from the books of Pawan Pawar, Pune as of 1st July 2019.
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q9
The following transactions took place during July 2019. Post them into Ledger and prepare Trial Balance as of 31st July 2019.
1 Introduced additional Capital ₹ 40,000
4 Bought goods from Rakesh ₹ 80,000 @ 10% Trade Discount
7 Sold goods to Rashmi ₹ 30,000
9 Returned goods to Rakesh ₹ 20,000 (Gross)
11 Rashmi returned goods to us ₹ 400
14 Paid to Rakesh ₹ 40,000 @ 2% Cash Discount
22 Made purchases ₹ 17,000 and amount paid by cheque
24 Cash Sales ₹ 8,000
27 Bought Stationery ₹ 3,000
28 Received from Rashmi ₹ 39,000 by RTGS and discount allowed ₹ 1000
29 Paid Salary ₹ 10,000
29 Sold goods to Rashmi ₹ 20,000
31 Bought goods from Rakesh ₹ 36,000 and paid by cheque.
Solution:
Ledger of Pawan Pawar, Pune
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q9.1
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q9.2
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q9.3
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q9.4
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q9.5
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q9.6

Trial Balance as of 31st July 2019
Maharashtra Board 11th BK Textbook Solutions Chapter 4 Ledger Practical Problems Q9.7

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Balbharti Maharashtra State Board 11th Biology Important Questions Chapter 6 Biomolecules Important Questions and Answers.

Maharashtra State Board 11th Biology Important Questions Chapter 6 Biomolecules

Question 1.
How are living organisms classified? Give examples of each.
Answer:
1. Living organisms are classified as unicellular (consisting of single cell) and multicellular (having many cells).
2. Example of unicellular organisms: bacteria, yeast.
Example of multicellular organisms: plants, animals.

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 2.
What is biochemistry?
Answer:
1. Biochemistry is biological chemistry that provides us the idea of the chemistry of living organisms and molecular basis for changes taking place in plants, animals and microbial cells.
2. It develops the foundation for understanding all biological processes and communication within and between cells as well as chemical basis of inheritance and diseases in animals and plants.

Question 3.
What does chemical analysis of living organisms indicate?
Answer:
Chemical analysis of all living organisms indicates the presence of the most common elements like carbon, hydrogen, nitrogen, oxygen, sulphur, calcium, phosphorus, magnesium and others with their respective content per unit mass of a living tissue.

Question 4.
Name the basic macromolecules present in the living organisms.
Answer:
Polysaccharides (carbohydrate) polymer of monosaccharide, polypeptides (proteins) polymer of amino acids and polynucleotides (nucleic acids) polymer of nucleotides are the three basic macromolecule present in the living organisms.

Question 5.
Draw a flowchart showing classification of carbohydrates.
Answer:
Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules 1

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 6.
Write a short note on
1. Glucose
2. Galactose and
3. Fructose.
Answer:
1. Glucose:
a. It is the most important fuel in living cells.
b. Its concentration in the human blood is about 90mg per 100ml of blood.
c. The small size and solubility in water of glucose molecules allows them to pass through the cell membrane into the cell.
d. Energy is released when the molecules are metabolized by cellular respiration.

2. Galactose:
a. It looks very similar to glucose molecules.
b. They can also exist in a and p forms.
c. Galactose react with glucose to form the disaccharide lactose.
d. However, glucose and galactose cannot be easily converted into one another.
e. Galactose cannot play the same role in respiration as glucose.

3. Fructose:
a. It is the fruit sugar and chemically it is ketohexose but it has a five-atom ring rather than a six-atom ring.
b. Fructose reacts with glucose to form the sucrose, a disaccharide.

Question 7.
How are disaccharides absorbed through the cell membrane?
Answer:
1. Disaccharides are soluble in water but they are too big to pass through the cell membrane by diffusion.
2. They are broken down in the small intestine during digestion.
3. Thus, formed monosaccharides then pas into the blood and through cell membranes into the cells.
Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules 2

Question 8.
Identify the X and Y in the following structure of a disaccharide.
Answer:
Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules 3
X: Glycosidic bond Y: Glucose

Question 9.
Distinguish between monosaccharides and disaccharides.
Answer:

Monosaccharides Disaccharides
1. They are composed of 3-6 carbon atoms. They are composed of two monosaccharide units covalently linked to each other.
2. They cannot be hydrolyzed into smaller units. They can be hydrolysed into monosaccharides.
3. Glucose, Fructose Sucrose and Lactose

Question 10.
Which macromolecules are too big to escape from the cell?
Answer:
Polysaccharides are too big to escape from the cell.

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 11.
Write a short note on
1. Starch
2. Glycogen
3. Cellulose.
Answer:
1. Starch:
a. Starch is a stored food in the plants.
b. Starch contains two types of glucose polymer: amylose and amylopectin.
c. Both are made from a-glucose.
d. Amylose is an unbranched polymer of a-glucose.
e. The molecules coil into a helical structure.
f. It foims a colloidal suspension in hot water.
g. Amylopectin is a branched polymer of a-glucose.
h. It is completely insoluble in water.
Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules 4

2. Glycogen:
a. It is amylopectin with very short distances between the branching side-chains.
b. Glycogen is stored in animal body particularly in liver and muscles from where it is hydrolyzed as per need to produce glucose.

3. Cellulose:
a. It is a polymer made from P-glucosc molecules and the polymer molecules are ‘straight’.
b. Cellulose serves to form the cell walls in plant cells.
c. These are much tougher than cell membranes.
d. This toughness is due to the arrangement of glucose units in the polymer chain and the hydrogen-bonding between neighbouring chains.

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 12.
Why plant fats are liquid at room temperature while animal fats are solid?
Answer:

  1. Plant fats are unsaturated fatty acids, whereas animal fats are saturated fatty acids.
  2. Fats having unsaturated fatty acids are liquid at room temperature.
  3. Saturated fatty acids are solid at room temperature. Hence, plant fats are liquid at room temperature, while animal fats are solid.

Question 13.
Draw the structure of triglyceride.
Answer:
Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules 5

Question 14.
Observe the following diagram and answer the questions based on it.
1. Identify the part ‘X’ in the given diagram.
2. What is the chemical property of the part ‘X’.
Answer:
1. The part labelled as ‘X’ is non-polar tail.
2. Non-polar tails are hydrophobic in nature.

Question 15.
Give two examples of unsaturated fatty acids.
Answer:
Oleic acid and linoleic acid are the examples of unsaturated fatty acids.

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 16.
Explain primary structure of protein.
Answer:
The linear sequence of amino acids in polypeptide chain of a protein forms the primary structure of a protein.

Question 17.
Explain the secondary structure of protein with examples.
Answer:

  1. There are two types of secondary structure of protein: a-helix and P-pleated sheets.
  2. The polypeptide chain is arranged in a spiral helix. These spiral helices are of two types: a-helix (right handed) and P-helix (left handed).
  3. This spiral configuration is held together by hydrogen bonds.
  4. The sequence of amino acids in the polypeptide chain determines the location of its bend or fold and the position of formation of hydrogen bonds between different portions of the chain or between different chains. Thus, peptide chains form an a-helix structure.
  5. Example of a-helix structure is keratin.
  6. In some proteins two or more peptide chains are linked together by intermolecular hydrogen bonds. Such structures are called P-pleated sheets.
  7. Example of P-pleated sheet is silk fibres.
  8. Due to formation of hydrogen bonds peptide chains assume a secondary structure.

Question 18.
Explain the tertiary and quaternary structure of protein with example.
Answer:
Tertiary structure:

  1. In tertiary structure the peptide chains are much looped, twisted and folded back on themselves due to formation of disulphide bonds.
  2. Such loops and bends give the protein a tertiary structure.
  3. E.g. Myoglobin, enzymes.

Quaternary structure:
1. When a protein has more than two polypeptide subunits their arrangement in space is called quaternary structure.
2. E.g. Haemoglobin.

Question 19.
Write a note on properties of protein.
Answer:
Properties of proteins are as follows:

  1. Proteins are extremely reactive and highly specific in behaviour.
  2. Proteins are amphoteric in nature i.e. they act as both acids and bases.
  3. The behaviour of proteins is strongly influenced by pH.
  4. Like amino acids, proteins are dipolar ions at the isoelectric point i.e. the sum of the positive charges is equal to the sum of the negative charges and the net charge is zero.
  5. The ionic groups of a protein are contributed by the side chains of the polyfunctional amino acids.
  6. A protein consists of more basic amino acids such as lysine and arginine exist as a cation at the physiological pH of 7.4. Such proteins are called basic proteins.
  7. Histones of nucleoproteins are basic proteins.
  8. A protein rich in acidic amino acids exists as an anion at the physiological pH. Such proteins are called acidic proteins.
  9. Most of the blood proteins are acidic proteins.

Question 20.
Mention the findings of Feulgen.
Answer:
1. In 1924, Feulgen showed that chromosomes contain DNA.
2. He found that nucleic acids contain two pyrimidine (cytosine and thymine) and two purine (adenine and guanine) bases.

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 21.
What were the findings of Wilkins and coworkers?
Answer:
The findings of Wilkins and coworkers were as follows:

  1. Purine and pyrimidine bases are placed regularly along the DNA molecules at a distance of 3.4 A.
  2. DNA (Deoxyribonucleotide) is composed of sugar molecule (a pentose sugar of deoxyribose type), phosphoric acid (phosphates when in chemical combination), nitrogen containing bases (nitrogen containing organic ring compounds).
  3. Bases are of two types: Pyrimidine bases and purine bases.
  4. Pyrimidine bases are single ring (monocyclic) nitrogenous bases. Cytosine, Thymine and uracil are pyrimidines.
  5. Purine are double ring (dicyclic) nitrogenous bases. Adenine and guanine are purines.

Question 22.
Chargaff analyzed the composition of DNA from various sources. Mention what were his implications from all his experiments.
Answer:
Implications proposed by Erwin Chargaff:
1. Purine and pyrimidine always occur in equal amount in DNA.
2. The base ratio i.e. A+T/G+C may vary in the DNA of different groups of animals and plants but the ratio remains constant for particular species.

Question 23.
Describe the structure of DNA.
Answer:
Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules 6

  1. DNA is a long chain made up of alternate sugar and phosphate groups. The sugar present in DNA is always a deoxyribose attached to a phosphate group. So, it forms a regular, repeating phosphate sugar sequence.
  2. A base is attached to sugar -phosphate chain. Together this unit which consist of sugar, phosphate and a base is called nucleotide.
  3. The nitrogenous base and a sugar of a nucleotide form a molecule called nucleoside. It lacks phosphate group. Four types of nucleoside are found in DNA molecule.
  4. In a nucleoside, nitrogenous base is attached to the first carbon atom (C-1) of the sugar and when a phosphate group gets attached with that of the carbon (C-5) atom of the sugar molecule a nucleotide molecule is formed.
  5. A single strand of DNA consists of several thousands of nucleotides one above the other.
  6. The phosphate group of the lower nucleotide attached with the 5th carbon atom of the deoxyribose sugar forms phospho-di-ester bond with that of the 3rd carbon atom of the deoxyribose sugar of the nucleotide placed just above it.
  7. Single long chain of polynucleotides of DNA consists of one end with sugar molecules not connected with another nucleotide having C-3 carbon which is not connected with phosphate group, similarly the other end having C-5 of the sugar is not connected with any phosphate group. These two ends of the polynucleotide chain are called as 3′ and 5′ ends respectively.
  8. The single polynucleotide strand of DNA is not straight but helical in shape.
  9. The DNA molecule consists of such two helical polynucleotide chains which are complementary to each other.
  10. The two complementary polynucleotide chains of DNA are held together by the weak hydrogen bonds.
  11. Adenine always pairs with thymine, and guanine with cytosine (a pyrimidine with a purine).
  12. Adenine-thymine pair consists of two hydrogen bonds and guanine-cytosine pair consists of three hydrogen bonds (Thus, if the sequence of bases of a polynucleotide chain is known, that of the other can be determined).

Question 24.
Draw the structures of nitrogen bases in nucleic acid.
Answer:
Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules 7

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 25.
Describe the structure of RNA.
Answer:
Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules 8

  1. The other nucleic acid found in living organisms is Ribose nucleic acid.
  2. In most of the organisms it is not found to be hereditary material but in certain organisms like tobacco mosaic virus, it is the hereditary material.
  3. Like DNA, ribose nucleic acid also consists of polynucleotide chain with the difference that it consists of single strand. Exceptions are Reovirus and wound tumor virus where RNA is double stranded.
  4. The nucleotides of RNA have ribose sugar instead of the deoxyribose sugar as in the case of DNA.
  5. In case of RNA, Uracil substitutes thymine of DNA.
  6. Purine, pyrimidine equality is not found in RNA molecule because of its single stranded structure.
  7. RNA strand is usually found folded upon itself in certain regions or entirely. These folding helps in stability of the RNA molecule.
  8. Most of the RNA polynucleotide chains start either with adenine or guanine.
  9. Three types of cellular RNAs have been distinguished:
    1. messenger RNA (mRNA) or template RNA,
    2. ribosomal RNA (rRNA),
    3. transfer RNA (tRNA) or soluble RNA.

Question 26.
Observe the following figure and name the type of bond shown by arrow in the structure.
Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules 9
Answer:
The type of bond shown in the diagram is hydrogen bond.

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 27.
What would have happened if there were no enzymes in the body?
Answer:
If enzymes were absent in the body, either the reactions would not occur or if they occur they would occur at a very slow rate.

Question 28.
How many reactions are catalyzed by an enzyme?
Answer:
Each enzyme catalyzes only one reaction.

Question 29.
What is a substrate?
Answer:
The substance upon which an enzyme acts is termed as the substrate.

Question 30.
What is endo-enzyines? Give examples.
Answer:
The enzymes which act within the cell in which they are synthesized are known as endo-enzymes E.g., enzymes produced in the chloroplast and mitochondria.

Question 31.
What are exo-enzymes?
Answer:
1. The enzymes which act outside the cell of which they are synthesized are known as exo-enzymes. E.g. enzymes released by many fungi.
2. These enzymes, synthesized by living cell, retain their catalytic property even when extracted from cells.

Question 32.
How are enzymes categorised?
Answer:
On basis of chemical composition enzymes are categorised:
1. Purely proteinaceous enzymes: e.g. Proteases that spilt protein
2. Conjugated enzymes: enzymes are made up of a protein to which a non-protein prosthetic group is attached.

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 33.
What is a prosthetic group ? What w ill happen if it is removed?
Answer:
1. Prosthetic group is non-protein in nature and is attached to the protein component of enzyme by chemical bonds.
2. It is not removed by hydrolysis.
3. If the prosthetic group is removed the protein part of the enzyme becomes inactive.

Question 34.
What are coenzymes?
Answer:
1. Enzymes require certain organic compounds for their activity.
2. The organic compounds that are tightly attached to the protein part are called coenzymes.
3. E.g. Nicotinamaide adenine dinucleotide (NAD), Flavin mononucleotide (FMN).

Question 35.
What are co-factors?
Answer:
1. Enzymes require certain inorganic ions for their activity.
2. The inorganic ions which are loosely attached to the protein part are called co-factors.
E.g. Magnesium, copper, zinc, iron, manganese etc.
[Note: Apoenzyme (protein part) and co-factor together form a complete catalytically active enzyme which is known as holoenzyme. The co-factors are of two types; metal ions and coenzymes. A coenzyme or metal ion that is very tightly or even covalently bound to the enzyme protein is known as a prosthetic group.]

Question 36.
Complete the analogy.
Iron (Fe): Catalase: Manganese (Mn):
Answer:
Peptidase

Question 37.
Give examples of coenzymes and cofactors.
Answer:
1. Nicotinamaide adenine dinucleotide (NAD), Flavin mononucleotide (FMN).
2. Magnesium, copper, zinc, iron, manganese etc.

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 38.
How are enzymes named?
Answer:

  1. Enzymes are named by adding the suffix- ‘ase’ to the name of the substrate on which they act e.g. protease, sucrase, nuclease etc. which break up proteins, sucrose and nucleic acids respectively.
  2. The enzymes can be named according to the type of function they perform.
    For e.g., dehydrogenase remove hydrogen, carboxylase add CO; decarboxylases remove C02, oxidases helping in oxidation.
  3. Some enzymes are named according to the source from which they are obtained.
    For e.g., papain from papaya, bromelain from the member of Bromeliaceae family, pineapple.
  4. According to international code of enzyme nomenclature, the name of each enzyme ends with an -ase and consists of double name!
  5. The first name indicates the nature of substrate upon which the enzyme acts and the second name indicates the reaction catalyzed.

For e.g., pyruvic decarboxylase catalyses the removal of C02 from the substrate pyruvic acid.
Similarly, the enzyme glutamate pyruvate transaminase catalyses the transfer of an amino group from the substrate glutamate to another substrate pyruvate.

Question 39.
Explain in detail the mechanism of enzyme action. Write a note on model proposed by Emil Fischer for mechanism of enzyme action.
Answer:
1. The basic mechanism by which enzymes catalyze chemical reactions begins with the binding of the substrate (or substrates) to the active site on the enzyme.
2. The active site is the specific region of the enzyme which combines with the substrate.
3. The binding of the substrate to the enzyme causes changes in the distribution of electrons in the chemical bonds of the substrate and ultimately causes the reactions that lead to the formation of products.
4. The products are released from the enzyme surface to regenerate the enzyme for another reaction cycle.
Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules 10
5. Lock and Key model proposed by Emil Fischer: i. Proteinaceous Nature:
All enzymes are basically made up of protein.

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 40.
Describe the concept of metabolism.
Answer:

  1. Metabolism is the sum of the chemical reactions that take place within each cell of a living organism and provide energy for vital processes and for synthesizing new organic material.
  2. It involves continuous process of breakdown and synthesis of biomolecules through chemical reactions.
  3. Each of the metabolic reaction results in a transformation of biomolecules.
  4. Most of these metabolic reactions do not occur in isolation but are always linked with some other reactions.
  5. In cells, metabolism involves two following types of pathways:

a. Catabolic pathways
This involves formation of simpler structure from a complex biomolecule.
For e.g. when we eat wheat, bread or chapati, our gastrointestinal tract digests (hydrolyses) the starch to glucose units with help of enzymes and releases energy in form of ATP (Adenosine triphosphate).

b. Anabolic pathway
It is also called as biosynthetic pathway that involves formation of a more complex biomolecules from a simpler structure
Fone.g., synthesis of glycogen from glucose and protein from amino acids. These pathways consume energy.

Question 41.
Draw a flowchart showing catabolic and anabolic reactions.
Answer:
Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules 11

Question 42.
Write a short note on secondary metabolites.
Answer:

  1. Secondary metabolites are small organic molecules produced by organisms that are not essential for their growth, development and reproduction.
  2. Several types of bacteria, fungi and plants produce secondary metabolites.
  3. Secondary metabolites can be classified on the basis of chemical structure (e.g. SMs containing rings, sugar), composition (with or without nitrogen), their solubility in various solvents, or the pathway by which they are synthesized (e.g. phenylpropanoid produces tannins).
  4. A simple way of classifying secondary metabolites includes three main groups such as:
    • Terpenes: Made from mevalonic acid that is composed mainly of carbon and hydrogen
    • Phenolics: Made from simple sugars containing benzene rings, hydrogen and oxygen.
    • Nitrogen-containing compounds: Extremely diverse class may also contain sulphur.

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 43.
Fill in the blanks.

  1. Living organism have _________ as the basic structural and functional unit.
  2. The cells have _______ containing numerous chemical molecules, the biomolecules.
  3. ________ are used very quickly by cells but if a cell is not in need of all the energy released immediately then it may get stored.
  4. By ________ reaction monosaccharide is converted to disaccharide.
  5. The balance between catabolism and anabolism maintain _______ in the cell as well as in the whole body.

Answer:

  1. Cell
  2. Protoplasm
  3. monosaccharides
  4. Condensation reaction
  5. Homeostasis

Question 44.
Apply Your Knowledge:

Question 1.
While performing an experiment, to understand effect of pH on enzyme activity, a student prepared
solution of varied pH. He observed that enzyme activity is maximum at a particular range of pH.
What is the reason for its maximum activity at a particular range of pH? What would be the effect on enzyme activity if strong acid or strong base is added?
Answer:
The enzymes are highly specific to pH and remain active within particular range of pH only. Hence, exhibit maximum activity only at particular range of pH. When strong acid or strong base is added in the reaction the enzyme activity is inhibited as most of the enzymes are denatured.

Question 2.
When a compound ‘x’ is added to a chemical solution containing enzyme and substrate, the enzymatic activity stops. What could be the nature of compound ‘x’?
Answer:
Compound ‘x’ could be either competitive or non-competitive inhibitor.

Question 45.
Quick Review

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules 12
Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules 13

Question 46.
Exercise:

Question 1.
Draw a flow chart of biomolecules in living system.
Answer:
Refer Quick Review

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 2.
Explain what is biochemistry?
Answer:
1. Biochemistry is biological chemistry that provides us the idea of the chemistry of living organisms and molecular basis for changes taking place in plants, animals and microbial cells.
2. It develops the foundation for understanding all biological processes and communication within and between cells as well as chemical basis of inheritance and diseases in animals and plants.

Question 3.
Mention the basic macromolecules present in the living organism.
Answer:
Polysaccharides (carbohydrate) polymer of monosaccharide, polypeptides (proteins) polymer of amino acids and polynucleotides (nucleic acids) polymer of nucleotides are the three basic macromolecule present in the living organisms.

Question 4.
Write a note on monosaccharides.
Answer:
Monosaccharides:
a. Monosaccharides are the simplest sugars having crystalline structure, sweet taste and soluble in water.
b. They cannot be further hydrolyzed into smaller molecules.
c. They are the building blocks or monomers of complex carbohydrates.
d. They have the general molecular formula (CH20)n, where n can be 3, 4, 5, 6 and 7.
e. They can be classified as triose, tetrose, pentose, etc.
f. Monosaccharides containing the aldehyde (-CHO) group are classified as aldoses e.g. glucose, xylose, and those with a ketone(-C=0) group are classified as ketoses. E.g. ribulose, fructose.

Question 5.
Explain the absorption of disaccharides through the cell membrane.
Answer:
1. Disaccharides are soluble in water but they are too big to pass through the cell membrane by diffusion.
2. They are broken down in the small intestine during digestion.
3. Thus, formed monosaccharides then pass into the blood and through cell membranes into the cells.

Question 6.
Draw the structure of amylose.
Answer:
Starch:
a. Starch is a stored food in the plants.
b. Starch contains two types of glucose polymer: amylose and amylopectin.
c. Both are made from a-glucose.
d. Amylose is an unbranched polymer of a-glucose.
e. The molecules coil into a helical structure.
f. It foims a colloidal suspension in hot water.
g. Amylopectin is a branched polymer of a-glucose.
h. It is completely insoluble in water.

Question 7.
Write the significance of carbohydrates.
Answer:
Significances of carbohydrates are as follows:

  1. Carbohydrates provide energy for metabolism.
  2. Glucose is the main substrate for ATP synthesis.
  3. Lactose, a disaccharide present in the milk provides energy to babies.
  4. Polysaccharide serves as a structural component of cell membrane, cell wall and reserved food as starch and glycogen.

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 8.
What is glycosidic bond?
Answer:
Oligosaccharides:
a. A carbohydrate polymer comprising of two to six monosaccharide molecules is called oligosaccharide.
b. They are linked together by glycosidic bond.
c. They are classified on the basis of monosaccharide units:
Disaccharides: These are the sugars containing two monosaccharide units and can be further hydrolysed into smaller components. E.g.: Sucrose, maltose, lactose, etc.
Trisaccharides: These contain three monomers. E.g. Raffmose.
Tetrasaccharides: These contain four monomers. E.g.: Stachyose.

Glycosidic bond:
a. Glycosidic bond is a covalent bond that forms a linkage between two monosaccharides by a dehydration reaction.
b. It is formed when a hydroxyl group of one sugar reacts with the anomeric carbon of the other.
c. Glycosidic bonds are readily hydrolyzed by acid but resist cleavage by base.
d. There are two types of glycosidic bonds: a-glycosidic bond and P-glycosidic bond.

Question 9.
What are saturated fatty acids?
Answer:
1. Saturated fatty acids: They contain single chain of carbon atoms with single bonds.
E.g. Palmitic acid, stearic acid
2. Unsaturated fatty acids: They contain one or more double bonds between the carbon atoms of the hydrocarbon chain.
a. Simple lipids: These are esters of fatty acids with various alcohols.
E.g. Fats, wax.
b. Compound lipids: These are ester of fatty acids containing other groups like phosphate (Phospholipids), sugar (glycolipids), etc.
E.g. Lecithin
c. Sterols: They are derived lipids. They are composed of fused hydrocarbon rings (steroid nucleus) and a long hydrocarbon side chain.
E.g. Cholesterol, phytosterols.

Question 10.
Write a note on simple lipids.
Answer:
Lipids are classified into three main types:
Simple lipids:
a. These are esters of fatty acids with various alcohols. Fats and waxes are simple lipids.
b. Fats are esters of fatty acids with glycerol (CH2OH-CHOH-CH2OH).
c. Triglycerides are three molecules of fatty acids and one molecule of glycerol.
d. Unsaturated fats are liquid at room temperature and are called oils. Unsaturated fatty acids are hydrogenated to produce fats e.g. Vanaspati ghee.

Question 11.
Write a note on derived lipids.
Answer:
Derived Lipids:
a. They are composed of fused hydrocarbon rings (steroid nucleus) and a long hydrocarbon side chain.
b. One of the most common sterols is cholesterol.
Biological significance:
a. It is widely distributed in all cells of the animal body, but particularly in nervous tissue.
b. Cholesterol exists either free or as cholesterol ester.
c. Adrenocorticoids, sex hormones (progesterone, testosterone) and vitamin D are synthesized from cholesterol.
d. Cholesterol is not found in plants.
e. Sterols exist as phytosterols in plants.
f. Yam Plant (Dioscorea) produces a steroid compound called diosgenin. It is used in the manufacture of antifertility pills, i.e. birth control pills.

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 12.
What are compound lipids? Mention their biological significance.
Answer:
Compound lipids:
a. These are ester of fatty acids containing other groups like phosphate (Phospholipids), sugar (glycolipids), etc.
b. They contain a molecule of glycerol, two molecules of fatty acids and a phosphate group or simple sugar.
c. Some phospholipids such as lecithin also have a nitrogenous compound attached to the phosphate group.
d. Phospholipids have both hydrophilic polar groups (phosphate and nitrogenous group) and hydrophobic non-polar groups (hydrocarbon chains of fatty acids).
e. Glycolipids contain glycerol, fatty acids, simple sugars such as galactose. They are also called cerebrosides.
Biological significance:
a. Phospholipids contribute in the formation of cell membrane.
b. Large amounts of glycolipids are found in the brain white matter and myelin sheath.

Question 13.
Explain the classification of proteins based on their chemical composition.
Answer:
On the basis of structure, proteins are classified into three categories:
1. Simple proteins:
a. Simple proteins on hydrolysis yield only amino acids.
b. These are soluble in one or more solvents.
c. Simple proteins may be soluble in water.
d. Histones of nucleoproteins are soluble in water.
e. Globular molecules of histones are not coagulated by heat.
f. Albumins are also soluble in water but they get coagulated on heating.
g. Albumins are widely distributed e.g. egg albumin, serum albumin and legumelin of pulses are albumins.
Importance: They are involved in structural components; they also act as a storage kind of protein.
Some are associated with nucleic acids in nucleoproteins of cell.

2. Conjugated proteins:
a. Conjugated proteins consist of a simple protein united with some non-protein substance.
b. The non-protein group is called prosthetic group e.g. haemoglobin.
c. Globin is the protein and the iron containing pigment haem is the prosthetic group.
d. Similarly, nucleoproteins have nucleic acids.
e. Proteins are classified as glycoproteins and mucoproteins.
f. Mucoproteins are carbohydrate-protein complexes e.g. mucin of saliva and heparin of blood.
g. Lipoproteins are lipid-protein complexes e.g. conjugate protein found in brain, plasma membrane, milk etc. Importance: They are involved in structural components of cell membranes and organelles.
They also act as a transporter.
Some conjugated proteins are important in electron transport chain in respiration.

3. Derived proteins:
a. These proteins are not found in nature as such.
b. These proteins are derived from native protein molecules on hydrolysis.
c. Metaproteins, peptones are derived proteins.
Importance: They act as a precursor for many molecules which are essential for life.

Question 14.
What is peptide bond? Explain its formation.
Answer:
1. The covalent bond that links the two amino acids is called a peptide bond.
2. Peptide bond is formed by condensation reaction.

Question 15.
Mention the examples of simple proteins and write their significance.
Answer:
Examples of simple proteins are: E.g.: Albumins and histones.
Significance:
1. Albumin:
a. % It is the main protein in the blood.
b. It maintains the pressure in the blood vessels.
c. It helps in transportation of substances like hormone and drugs in the body.
2. Histones:
a. It is the chief protein of chromatin.
b. They are involved in packaging of DNA into structural units called nucleosomes.

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 16.
What is nucleotide?
Answer:
Nucleotide is a unit which consists of a sugar, phosphate and a base. Nucleotides are basic units of nucleic acids.

Question 17.
Write a note on structure of DNA molecule proposed by Watson and Crick.
Answer:
1. DNA is a long chain made up of alternate sugar and phosphate groups. The sugar present in DNA is always a deoxyribose attached to a phosphate group. So, it forms a regular, repeating phosphate sugar sequence.
2. A base is attached to sugar -phosphate chain. Together this unit which consist of sugar, phosphate and a base is called nucleotide.
3. The nitrogenous base and a sugar of a nucleotide form a molecule called nucleoside. It lacks phosphate group. Four types of nucleoside are found in DNA molecule.
4. In a nucleoside, nitrogenous base is attached to the first carbon atom (C-1) of the sugar and when a phosphate group gets attached with that of the carbon (C-5) atom of the sugar molecule a nucleotide molecule is formed.
5. A single strand of DNA consists of several thousands of nucleotides one above the other.
6. The phosphate group of the lower nucleotide attached with the 5th carbon atom of the deoxyribose sugar forms phospho-di-ester bond with that of the 3rd carbon atom of the deoxyribose sugar of the nucleotide placed just above it.
7. Single long chain of polynucleotides of DNA consists of one end with sugar molecules not connected with another nucleotide having C-3 carbon which is not connected with phosphate group, similarly the other end having C-5 of the sugar is not connected with any phosphate group. These two ends of the polynucleotide chain are called as 3′ and 5′ ends respectively.
8. The single polynucleotide strand of DNA is not straight but helical in shape.
9. The DNA molecule consists of such two helical polynucleotide chains which are complementary to each other.
10. The two complementary polynucleotide chains of DNA are held together by the weak hydrogen bonds.
11. Adenine always pairs with thymine, and guanine with cytosine (a pyrimidine with a purine).
12. Adenine-thymine pair consists of two hydrogen bonds and guanine-cytosine pair consists of three hydrogen bonds (Thus, if the sequence of bases of a polynucleotide chain is known, that of the other can be determined).

  1. According to Watson and Crick, DNA molecule consists of two strands twisted around each other in the form of a double helix.
  2. The two strands i.e. polynucleotide chains are supposed to be in opposite direction so end of one chain having 3′ lies beside the 5′ end of the other.
  3. One turn of the double helix of the DNA measures about 34A.
  4. It consists paired nucleotides and the distance between two neighboring pair nucleotides is 3.4A.
  5. The diameter of the DNA molecule has been found be 20A.

Question 18.
What is the function of ribosomal RNA?
Answer:
Ribosomal RNA (rRNA):
a. rRNA was discovered by Kurland in 1960.
b. It forms 50-60% part of ribosomes.
c. It accounts 80-90% of the cellular RNA.
d. It is synthesized in nucleus.
e. It gets coiled at various places due to intrachain complementary base pairing.
Role of ribosomal RNA: It provides proper binding site for m-RNA during protein synthesis.

Question 19.
Write a short note on m-RNA.
Answer:
Messenger RNA (mRNA):
a. It is a linear polynucleotide.
b. It accounts 3% of cellular RNA.
c. Its molecular weight is several million. , d. mRNA molecule carrying information to form a complete polypeptide chain is called cistron.
e. Size of mRNA is related to the size of message it contains.
f. Synthesis of mRNA begins at 5’ end of DNA strand and terminates at 3’ end.

Role of messenger RNA:
It carries genetic information from DNA to ribosomes, which are the sites of protein synthesis.
Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules 14

Question 20.
Write a note on types of non-genetic RNA.
Answer:
There are three types of cellular RNAs:
1. messenger RNA (mRNA),
2. ribosomal RNA (rRNA),
3. transfer RNA (tRNA). ‘

1. Messenger RNA (mRNA):
a. It is a linear polynucleotide.
b. It accounts 3% of cellular RNA.
c. Its molecular weight is several million. , d. mRNA molecule carrying information to form a complete polypeptide chain is called cistron.
e. Size of mRNA is related to the size of message it contains.
f. Synthesis of mRNA begins at 5’ end of DNA strand and terminates at 3’ end.

Role of messenger RNA:
It carries genetic information from DNA to ribosomes, which are the sites of protein synthesis.

2. Ribosomal RNA (rRNA):
a. rRNA was discovered by Kurland in 1960.
b. It forms 50-60% part of ribosomes.
c. It accounts 80-90% of the cellular RNA.
d. It is synthesized in nucleus.
e. It gets coiled at various places due to intrachain complementary base pairing.
Role of ribosomal RNA: It provides proper binding site for m-RNA during protein synthesis.

3. Transfer RNA (tRNA):
a. These molecules are much smaller consisting of 70-80 nucleotides.
b. Due to presence of complementary base pairing at various places, it is shaped like clover-leaf.
c. Each tRNA can pick up particular amino acid.
d. Following four parts can be recognized on tRNA
1. DHU arm (Dihydroxyuracil loop/ amino acid recognition site
2. Amino acid binding site
3. Anticodon loop / codon recognition site
4. Ribosome recognition site.
e. In the anticodon loop of tRNA, three unpaired nucleotides are present called as anticodon which pair with codon present on mRNA.
f. The specific amino acids are attached at the 3’ end in acceptor stem of clover leaf of tRNA.
Role of transfer RNA: It helps in elongation of polypeptide chain during the process called translation.

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 21.
What are co-factors? Give examples.
Answer:

  1. Enzymes require certain inorganic ions for their activity.
  2. The inorganic ions which are loosely attached to the protein part are called co-factors.
  3. E.g. Magnesium, copper, zinc, iron, manganese etc.

[Note: Apoenzyme (protein part) and co-factor together form a complete catalytically active enzyme which is known as holoenzyme. The co-factors are of two types; metal ions and coenzymes. A coenzyme or metal ion that is very tightly or even covalently bound to the enzyme protein is known as a prosthetic group.]

Question 22.
Describe the important properties of enzymes.
Answer:
1. Proteinaceous Nature:
All enzymes are basically made up of protein.

2. Three-Dimensional conformation:
a. All enzymes have specific 3-dimensional conformation.
b. They have one or more active sites to which substrate (reactant) combines.
c. The points of active site where the substrate joins with the enzyme is called substrate binding site.

3. Catalytic property:
a. Enzymes are like inorganic catalysts and influence the speed of biochemical reactions but themselves remain unchanged.
b. After completion of the reaction and release of the product they remain active to catalyze again.
c. A small quantity of enzymes can catalyze the transformation of a very large quantity of the substrate
into an end product.
d. For example, sucrase can hydrolyze 100000 times of sucrose as compared with its own weight.

4. Specificity of action:
a. The ability of an enzyme to catalyze one specific reaction and essentially no other is perhaps its most significant property. Each enzyme acts upon a specific substrate or a specific group of substrates.
b. Enzymes are very sensitive to temperature and pH.
c. Each enzyme exhibits its highest activity at a specific pH i.e. optimum pH.
d. Any increase or decrease in pH causes decline in enzyme activity e.g. enzyme pepsin (secreted in stomach)shows highest activity at an optimum pH of 2 (acidic)

5. Temperature:
a. Enzymes are destroyed at higher temperature of 60-70°C or below, they are not destroyed but become inactive.
b. This inactive state is temporary and the enzyme can become active at suitable temperature.
c. Most of the enzymes work at an optimum temperature between 20°C and 35°C.

There are two types of models:
1. Lock and Key model:
a. Lock and Key model was first postulated in 1894 by Emil Fischer.
b. This model explains the specific action of an enzyme with a single substrate.
c. In this model, lock is the enzyme and key is the substrate.
d. The correctly sized key (substrate) fits into the key hole (active site) of the lock (enzyme).

2. Induced Fit model (Flexible Model):
a. Induced Fit model was first proposed in 1959 by Koshland.
b. This model states that approach of a substrate induces a conformational change in the enzyme.
c. It is the more accepted model to understand mode of action of enzyme.
d. The induced fit model shows that enzymes are rather flexible structures in which the active site continually reshapes by its interactions with the substrate until the time the substrate is completely bound to it.
e. It is also the point at which the final form and shape of the enzyme is determined.
[Note: Temperature is a factor affecting enzyme activity and not a property of enzyme.]

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 23.
Explain the classification enzymes and mention the example of each class.
Answer:
1. Enzymes are biological macromolecules which act as a catalyst and accelerates the reaction in the body.
2. Enzymes are classified into six classes:
a. Oxidoreductases: These enzymes catalyze oxidation and reduction reactions by the transfer of hydrogen and/or oxygen, e.g. alcohol dehydrogenase
b. Transferases: These enzymes catalyse the transfer of certain groups between two molecules, e.g. glucokinase
c. Hydrolases: These enzymes catalyse hydrolytic reactions. This class includes amylases, proteases, lipases etc. e.g. Sucrase
d. Lyases: These enzymes are involved in elimination reactions resulting in the removal of a group of atoms from substrate molecule to leave a double bond. It includes aldolases, decarboxylases, and dehydratases, e.g. fumarate hydratase.
e. Isomerases: These enzymes catalyze structural rearrangements within a molecule. Their nomenclature is based on the type of isomerism. Thus, these enzymes are identified as racemases, epimerases, isomerases, mutases, e.g. xylose isomerase.
f. Ligases or Synthetases: These are the enzymes which catalyze the covalent linkage of the molecules utilizing the energy obtained from hydrolysis of an energy-rich compound like ATP, GTP e.g. glutathione synthetase, Pyruvate carboxylase.

Question 24.
Enlist the factors affecting the activity of enzymes.
Answer:
The factors affecting the enzyme activity are as follows:
1. Concentration of substrate:
a. Increase in the substrate concentration gradually increases the velocity of enzyme activity within the limited range of substrate levels.
b. A rectangular hyperbola is obtained when velocity is plotted against the substrate concentration.
c. Three distinct phases (A, B and C) of the reaction are observed in the graph.
Where V = Measured velocity, Vmax = Maximum velocity, S = Substrate concentration,
Km = Michaelis-Menten constant.
d. Km or the Michaelis-Menten constant is defined as the substrate concentration (expressed in moles/lit) to produce half of maximum velocity in an enzyme catalyzed reaction.
e. It indicates that half of the enzyme molecules (i.e. 50%) are bound with the substrate molecules when the substrate concentration equals the Km value.
f. Km value is a constant and a characteristic feature of a given enzyme.
g. It is a representative for measuring the strength of ES complex.
h. A low Km value indicates a strong affinity between enzyme and substrate, whereas a high Km value reflects a weak affinity between them.
i. For majority of enzymes, the Km values are in the range of 10-5 to 10-2 moles.

2. Enzyme Concentration:
a. The rate of an enzymatic reaction is directly proportional to the concentration of the substrate.
b. The rate of reaction is also directly proportional to the square root of the concentration of enzymes.
c. It means that the rate of reaction also increases with the increasing concentration of enzyme and the rate of reaction can also decrease by decreasing the concentration of enzyme.

3. Temperature:
a. The temperature at which the enzymes show maximum activity is called Optimum temperature.
b. The rate of chemical reaction is increased by a rise in temperature but this is true only over a limited range of temperature.
c. Enzymes rapidly denature at temperature above 40°C.
d. The activity of enzymes is reduced at low temperature.
e. The enzymatic reaction occurs best at or around 37°C which is the average normal body temperature in homeotherms.

4. Effect of pH:
a. The pH at which an enzyme catalyzes the reaction at the maximum rate is known as optimum pH.
b. The enzyme cannot perform its function beyond the range of its pH value.

5. Other substances:
a. The enzyme action is also increased or decreased in the presence of some other substances such as co-enzymes, activators and inhibitors.
b. Most of the enzymes are combination of a co-enzyme and an apo-enzyme.
c. Activators are the inorganic substances which increase the enzyme activity.
d. Inhibitor is the substance which reduces the enzyme activity.

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 25.
With the help of lock and key theory explain the mechanism of enzyme action.
Answer:
1. Proteinaceous Nature:
All enzymes are basically made up of protein.

2. Three-Dimensional conformation:
a. All enzymes have specific 3-dimensional conformation.
b. They have one or more active sites to which substrate (reactant) combines.
c. The points of active site where the substrate joins with the enzyme is called substrate binding site.

3. Catalytic property:
a. Enzymes are like inorganic catalysts and influence the speed of biochemical reactions but themselves remain unchanged.
b. After completion of the reaction and release of the product they remain active to catalyze again.
c. A small quantity of enzymes can catalyze the transformation of a very large quantity of the substrate
into an end product.
d. For example, sucrase can hydrolyze 100000 times of sucrose as compared with its own weight.

4. Specificity of action:
a. The ability of an enzyme to catalyze one specific reaction and essentially no other is perhaps its most significant property. Each enzyme acts upon a specific substrate or a specific group of substrates.
b. Enzymes are very sensitive to temperature and pH.
c. Each enzyme exhibits its highest activity at a specific pH i.e. optimum pH.
d. Any increase or decrease in pH causes decline in enzyme activity e.g. enzyme pepsin (secreted in stomach)shows highest activity at an optimum pH of 2 (acidic)

5. Temperature:
a. Enzymes are destroyed at higher temperature of 60-70°C or below, they are not destroyed but become inactive.
b. This inactive state is temporary and the enzyme can become active at suitable temperature.
c. Most of the enzymes work at an optimum temperature between 20°C and 35°C.

There are two types of models:
1. Lock and Key model:
a. Lock and Key model was first postulated in 1894 by Emil Fischer.
b. This model explains the specific action of an enzyme with a single substrate.
c. In this model, lock is the enzyme and key is the substrate.
d. The correctly sized key (substrate) fits into the key hole (active site) of the lock (enzyme).

Question 26.
With the help of suitable examples give any three classes of enzymes.
Answer:
a. Oxidoreductases: These enzymes catalyze oxidation and reduction reactions by the transfer of hydrogen and/or oxygen, e.g. alcohol dehydrogenase
b. Transferases: These enzymes catalyse the transfer of certain groups between two molecules, e.g. glucokinase
c. Hydrolases: These enzymes catalyse hydrolytic reactions. This class includes amylases, proteases, lipases etc. e.g. Sucrase

Question 27.
Following graph represents the effect of substrate concentration on enzyme activity. Identify ‘X’ and ‘Y’ Write proper explanation of the process.
Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules 17
Answer:
The factors affecting the enzyme activity are as follows:
1. Concentration of substrate:
a. Increase in the substrate concentration gradually increases the velocity of enzyme activity within the limited range of substrate levels.
b. A rectangular hyperbola is obtained when velocity is plotted against the substrate concentration.
c. Three distinct phases (A, B and C) of the reaction are observed in the graph.
Where V = Measured velocity, Vmax = Maximum velocity, S = Substrate concentration,
Km = Michaelis-Menten constant.
d. Km or the Michaelis-Menten constant is defined as the substrate concentration (expressed in moles/lit) to produce half of maximum velocity in an enzyme catalyzed reaction.
e. It indicates that half of the enzyme molecules (i.e. 50%) are bound with the substrate molecules when the substrate concentration equals the Km value.
f. Km value is a constant and a characteristic feature of a given enzyme.
g. It is a representative for measuring the strength of ES complex.
h. A low Km value indicates a strong affinity between enzyme and substrate, whereas a high Km value reflects a weak affinity between them.
i. For majority of enzymes, the Km values are in the range of 10-5 to 10-2 moles.

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 28.
Explain the concept of metabolism.
Answer:

  1. Metabolism is the sum of the chemical reactions that take place within each cell of a living organism and provide energy for vital processes and for synthesizing new organic material.
  2. It involves continuous process of breakdown and synthesis of biomolecules through chemical reactions.
  3. Each of the metabolic reaction results in a transformation of biomolecules.
  4. Most of these metabolic reactions do not occur in isolation but are always linked with some other reactions.
  5. In cells, metabolism involves two following types of pathways:

a. Catabolic pathways
This involves formation of simpler structure from a complex biomolecule.
For e.g. when we eat wheat, bread or chapati, our gastrointestinal tract digests (hydrolyses) the starch to glucose units with help of enzymes and releases energy in form of ATP (Adenosine triphosphate).

b. Anabolic pathway
It is also called as biosynthetic pathway that involves formation of a more complex biomolecules from a simpler structure
Fone.g., synthesis of glycogen from glucose and protein from amino acids. These pathways consume energy.

Question 29.
Distinguish between Catabolic pathways and anabolic pathways.
Answer:
In cells, metabolism involves two following types of pathways:

a. Catabolic pathways
This involves formation of simpler structure from a complex biomolecule.
For e.g. when we eat wheat, bread or chapati, our gastrointestinal tract digests (hydrolyses) the starch to glucose units with help of enzymes and releases energy in form of ATP (Adenosine triphosphate).

b. Anabolic pathway
It is also called as biosynthetic pathway that involves formation of a more complex biomolecules from a simpler structure
Fone.g., synthesis of glycogen from glucose and protein from amino acids. These pathways consume energy.

Question 30.
Write the application of secondary metabolites.
Answer:

  1. Drugs developed from secondary metabolites have been used to treat infectious diseases, cancer, hypertension and inflammation.
  2. Morphine, the first alkaloid isolated from Papaver somniferum is used as pain reliver and cough suppressant.
  3. Secondary metabolites like alkaloids, nicotine, cocaine and the terpenes, cannabinol are widely used for recreation and stimulation.
  4. Flavours of secondary metabolites improve our food preferences.
  5. Tannins are added to wines and chocolate for improving astringency.
  6. Since most secondary metabolites have antibiotic property, they are also used as food preservatives.
  7. Glucosinolates is a secondary metabolite which is naturally present in cabbage imparts a characteristic flavour and aroma because of nitrogen and sulphur-containing chemicals. It also offers protection to these plants from many pests.

Question 31.
Explain the formation of metabolic pool.
Answer:

  1. Metabolism is the sum of the chemical reactions that take place within each cell of a living organism and provide energy for vital processes and for synthesizing new’ organic material.
  2. Metabolic pool in the cell is formed due to glycolysis and Krebs cycle.
  3. The catabolic chemical reaction of glycolysis and Krebs cycle provides ATP and biomolecules. These biomolecules form the metabolic pool of the cell.
  4. These biomolecules can be utilized for synthesis of many important cellular components.
  5. The metabolites can be added or withdrawn from the pool according to the need of the cell.

Question 32.
Explain the concept of metabolic pool.
Answer:
1. Metabolic pool is the reservoir of biomolecules in the cell on which enzymes can act to produce useful products as per the need of the cell.
2. The concept of metabolic pool is significant in cell biology because it allows one type of molecule to change into another type E.g. Carbohydrates can be converted to fats and vice-versa.

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 33.
Multiple Choice Questions:

Question 1.
Most common constituents of organic compounds found in organims are
(A) C, H, O, P
(B) C, H, O
(C) C, H, N, P
(D) C, H, O, N, P
Answer:
(B) C, H, O

Question 2.
Carbohydrates are composed of
(A) carbon
(B) hydrogen
(C) oxygen
(D) all of these
Answer:
(D) all of these

Question 3.
In which of the following, the ratio of hydrogen and oxygen atoms is 2:1?
(A) proteins
(B) fats
(C) oil
(D) carbohydrates
Answer:
(D) carbohydrates

Question 4.
Which of the following do not give smaller sugar units on hydrolysis?
(A) Monosaccharides
(B) Disaccharides
(C) Polysaccharides
(D) Glycogen
Answer:
(A) Monosaccharides

Question 5.
The simplest monosaccharide made up of three carbons amongst the following is
(A) erythrose
(B) glucose
(C) glyceraldehyde
(D) ribose
Answer:
(C) glyceraldehyde

Question 6.
Deoxyribose sugar is an example of
(A) monosaccharide
(B) disaccharide
(C) polysaccharide
(D) simple protein
Answer:
(A) monosaccharide

Question 7.
Common examples of hexose sugar is/are
(A) glucose
(B) fructose
(C) erythrose
(D) both (A) and (B)
Answer:
(D) both (A) and (B)

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 8.
If a compound contains 2 monosaccharides, then it is described as
(A) derived monosaccharide
(B) disaccharide
(C) polysaccharide
(D) pentose sugar
Answer:
(B) disaccharide

Question 9.
In a disaccharide, monomers are linked with each other through ________ bonds.
(A) peptide
(B) hydrogen
(C) glycosidic
(D) ester
Answer:
(C) glycosidic

Question 10.
A disaccharide that gives two molecules of glucose on hydrolysis is
(A) sucrose
(B) maltose
(C) lactose
(D) none of these
Answer:
(B) maltose

Question 11.
Sugar present in milk is
(A) fructose
(B) lactose
(C) galactose
(D) sucrose
Answer:
(B) lactose

Question 12.
Polysaccharides consist of
(A) two monosaccharide units
(B) eight monosaccharide units
(C) many monosaccharide units
(D) amino acids
Answer:
(C) many monosaccharide units

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 13.
________ are water insoluble and small molecular weight compounds as compared to macromolecules.
(A) Lipids
(B) proteins
(C) carbohydrates
(D) nucleic acids.
Answer:
(A) Lipids

Question 14.
Simple lipids are esters of
(A) amino acids
(B) proteins
(C) phosphorus
(D) fatty acids with glycerol
Answer:
(D) fatty acids with glycerol

Question 15.
Fatty acids which do not contain double bond between carbon atoms are
(A) saturated fatty acids
(B) unsaturated fatty acids
(C) oleic and linoleic acids
(D) linoleic and linolenic acids
Answer:
(A) saturated fatty acids

Question 16.
Proteins are linear polymers of
(A) amino acids
(B) fatty acids
(C) monosaccharides
(D) nucleic acids
Answer:
(A) amino acids

Question 17.
Proteins are formed by the condensation of
(A) nucleic acids
(B) amino acids
(C) fatty acids
(D) carbohydrates
Answer:
(B) amino acids

Question 18.
Protein is
(A) micromolecule
(B) macromolecule
(C) soluble
(D) specific
Answer:
(B) macromolecule

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 19.
Keratin is a ________ protein.
(A) transport
(B) protective
(C) structural
(D) storage
Answer:
(C) structural

Question 20.
A nucleotide contains
(A) sugar + phosphate
(B) N-base + phosphate
(C) sugar + nitrogenous base
(D) sugar + N-base + phosphate
Answer:
(D) sugar + N-base + phosphate

Question 21.
Nucleotides, the polymers of nucleic acid are joined together by __________ bond.
(A) Peptide
(B) Ester
(C) Phosphodiester
(D) Glycosidic
Answer:
(C) Phosphodiester

Question 22.
Find the odd one.
(A) Adenine
(B) Cytosine
(C) Thymine
(D) Uracil
Answer:
(D) Uracil

Question 23.
The two strands of DNA are
(A) similar in nature and complementary
(B) anti-parallel and complementary
(C) parallel and complementary
(D) basically, different in nature
Answer:
(B) anti-parallel and complementary

Question 24.
RNA is genetic material in
(A) bacteria
(B) cyanobacteria
(C) bacteriophages
(D) plant viruses
Answer:
(D) plant viruses

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 25.
Which RNA is present in more amount in the cell?
(A) m-RNA
(B) t-RNA
(C) r-RNA
(D) not certain
Answer:
(C) r-RNA

Question 26.
Smallest RNA is
(A) t-RNA
(B) m-RNA
(C) r-RNA
(D) not specific
Answer:
(A) t-RNA

Question 27.
________ catalyze hydrolysis of ester, ether etc.
(A) Lyases
(B) Ligases
(C) Hydrolases
(D) Transferases
Answer:
(C) Hydrolases

Question 28.
_______ catalyze interconversions of geometric, optical and positional isomers.
(A) Transferases
(B) Ligases
(C) Oxidoreductase
(D) Isomerases
Answer:
(D) Isomerases

Question 29.
Metal cofactors are also known as?
(A) prosthetic group
(B) coenzyme
(C) activators
(D) inhibitors
Answer:
(C) activators

Question 30.
________ are also known as dehydrogenases.
(A) Oxidoreductases
(B) Ligases
(C) Lyases
(D) Transferases
Answer:
(A) Oxidoreductases

Question 31.
The enzyme functions best at temperature
(A) 30°C to 50°C
(B) 15°C to 25°C
(C) 20°C to 35°C
(D) 40°C to 50°C
Answer:
(C) 20°C to 35°C

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 32.
As temperature changes from 30° to 45° C, the rate of enzyme activity will
(A) decrease
(B) increase
(C) first increase and then decrease
(D) first decrease and then increase
Answer:
(C) first increase and then decrease

Question 33.
Out of the following, which is not a property of enzymes?
(A) Specific in nature
(B) Proteinaceous
(C) Used up in reaction
(D) Increased rate of biochemical reaction
Answer:
(C) Used up in reaction

Question 34.
Majority of cellular enzymes function best at _______ PH.
(A) acidic
(B) basic
(C) neutral
(D) strong base
Answer:
(B) basic

Question 35.
The _______ action of enzyme with a substrate is explained by lock and key theory.
(A) relative
(B) specific
(C) random
(D) abstract
Answer:
(B) specific

Question 36.
Morphine, the first alkaloid isolated from ________
(A) Pisum sativum
(B) Hibiscus rosa sinensis
(C) Papaver somniferum
(D) Azadirachta indica
Answer:
(C) Papaver somniferum

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 34.
Competitive Corner:

Question 1.
Prosthetic groups differ from co-enzymes in that –
(A) They can serve as co-factors in a number of enzyme – catalyzed reactions
(B) They require metal ions for their activity
(C) They (prosthetic groups) are tightly bound to apoenzymes
(D) Their association with apoenzymes is transient
Hint: Apoenzyme (protein part) and co-factor together form a complete catalytically active enzyme which is known as holoenzyme. The co-factors are of two types; metal ions and coenzymes. A coenzyme or metal ion that is very tightly or even covalently bound to the enzyme protein is known as a prosthetic group.
Answer:
(C) They (prosthetic groups) are tightly bound to apoenzymes

Question 2.
Consider the following statements:
1. Coenzyme or metal ion that is tightly bound to enzyme protein is called prosthetic group.
2. A complete catalytic active enzyme with its bound prosthetic group is called apoenzyme. Select the correct option.
(A) Both (i) and (ii) are false.
(B) (i) is false but (ii) is true.
(C) Both (i) and (ii) are true.
(D) (i) is true but (ii) is false.
Answer:
(D) (i) is true but (ii) is false.

Question 3.
Concanavalin A is:
(A) a lectin
(B) a pigment
(C) an alkaloid
(D) an essential oil
Answer:
(A) a lectin

Question 4.
Which one of the following carbohydrates is a heteropolysaccharide?
(A) Cellulose
(B) Starch
(C) Glycogen
(D) Hyaluronic acid
Answer:
(D) Hyaluronic acid

Question 5.
The two functional groups characteristic of sugars are
(A) Carbonyl and phosphate
(B) Carbonyl and methyl
(C) Hydroxyl and methyl
(D) Carbonyl and hydroxyl
Answer:
(D) Carbonyl and hydroxyl

Maharashtra Board Class 11 Biology Important Questions Chapter 6 Biomolecules

Question 6.
Which one of the following statements is correct with reference to enzymes?
(A) Apoenzyme = Holoenzyme + coenzyme
(B) Holoenzyme = Apoenzyme + Coenzyme
(C) Coenzyme = Apoenzyme + Holoenzyme
(D) Holoenzyme = Coenzyme + Co-factor
Answer:
(B) Holoenzyme = Apoenzyme + Coenzyme

Question 7.
Which of the following are NOT polymeric?
(A) Nucleic acids
(B) Proteins
(C) Polysaccharides
(D) Lipids
Answer:
(D) Lipids

Maharashtra Board 11th BK Important Questions Chapter 3 Journal

Balbharti Maharashtra State Board 11th Commerce Book Keeping & Accountancy Important Questions Chapter 3 Journal Important Questions and Answers.

Maharashtra State Board 11th Commerce BK Important Questions Chapter 3 Journal

1A. Answer in One Sentence:

Question 1.
What do you mean by Journalising?
Answer:
Journalisation means a process of recording two-fold effects of business transactions in the summarized form of debit and credit in the journal.

Question 2.
Which column in a journal is not filled in at the time of journalising?
Answer:
Ledger Folio column in a journal is not filled in at the time of journalising.

Maharashtra Board 11th BK Important Questions Chapter 3 Journal

Question 3.
Which account is credited when Salary is paid by cheque?
Answer:
Bank Account is credited when salary is paid by cheque.

Question 4.
Why is a journal called the book of prime entry?
Answer:
Journal is called a book of prime entry because all the business transactions are recorded first in the journal in a chronological order i.e. in the order of their occurrence.

Question 5.
In which order the transactions are recorded in a journal.
Answer:
The transactions are recorded in a journal in chronological order i.e. in the order of their occurrence or taking place.

Maharashtra Board 11th BK Important Questions Chapter 3 Journal

Question 6.
Which account is debited, when goods are destroyed by fire?
Answer:
When goods are destroyed by fire, the Loss by Fire Account is debited.

2. Correct the following statements and rewrite the statements.

Question 1.
Transactions can be recorded in any order in the Journal.
Answer:
Transactions must be recorded in chronological order in the Journal.

Question 2.
Trade discount is recorded in the books of accounts.
Answer:
A cash discount is recorded in the books of accounts.

Question 3.
Trade discount is calculated after cash discount while calculating discount on purchase or sales.
Answer:
Trade discount is calculated before cash discount while calculating discount on purchase or sales.

Maharashtra Board 11th BK Important Questions Chapter 3 Journal

Question 4.
Trade discount is allowed for prompt payments.
Answer:
A cash discount is allowed for prompt payments.

Question 5.
The process of entering or recording the transactions in the Journal is called posting.
Answer:
The process of entering or recording the transaction in a Journal is called Journalising.

3. Do you agree or disagree with the following statements

Question 1.
Purchase of Assets should be debited to purchase A/c.
Answer:
Disagree

Question 2.
A cash discount is recorded in the books of Accounts.
Answer:
Agree

Question 3.
GST is imposed by the local body.
Answer:
Disagree

Maharashtra Board 11th BK Important Questions Chapter 3 Journal

Question 4.
Capital is an asset for business organisations.
Answer:
Disagree

Question 5.
With NEFT, RTGS Transaction Cash A/c is affected.
Answer:
Disagree

Question 6.
On purchase of goods or assets output, GST A/c is credited.
Answer:
Disagree

Question 7.
5% GST Charge on luxury cars.
Answer:
Disagree

Maharashtra Board 11th BK Important Questions Chapter 3 Journal

Question 8.
GST Generates income to Central Government only.
Answer:
Disagree

Question 9.
Ledger Folio column in Journal filled while passing Journal entry only.
Answer:
Disagree

Question 10.
Purchase of shares of TATA Ltd should be debited to TATA Ltd’s A/c.
Answer:
Disagree

Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal

Balbharti Maharashtra State Board Bookkeeping and Accountancy 11th Solutions Chapter 3 Journal Textbook Exercise Questions and Answers.

Maharashtra State Board Bookkeeping and Accountancy 11th Solutions Chapter 3 Journal

1A. Answer in One Sentence:

Question 1.
What is Journal?
Answer:
Journal is a book of account in which all types of day-to-day business transactions are recorded in chronological
order.

Question 2.
What is Narration?
Answer:
Explanation of transaction which is written just below the accounting entry in the particular column is called narration.

Question 3.
What is GST?
Answer:
GST is an abbreviated form of Goods and Service Tax that is levied by the Government on specific goods and services in the place of different taxes levied earlier.

Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal

Question 4.
In which year GST was imposed by the Central Government of India?
Answer:
In the year 2017 GST was imposed by the Central Government of India.

Question 5.
What is meant by simple entry?
Answer:
An entry in which only two accounts are affected viz. one account is debited and the other account is credited is called simple entry.

Question 6.
What is the meaning of combined entry?
Answer:
A journal entry that combines more than one debit or more than one credit or both is called a combined/compound entry.

Question 7.
Which account is debited, when rent is paid by Debit card?
Answer:
The rent account is debited when rent is paid by debit card.

Question 8.
Which discount is not recorded in the books of account?
Answer:
Trade discount is not recorded in the books of the account.

Question 9.
In which order monthly transactions are recorded in a Journal?
Answer:
In chronological (date wise) order monthly transactions are recorded in the journal.

Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal

Question 10.
Which account is credited, when goods are sold on credit?
Answer:
Sales account is credited, when goods are sold on credit.

2. Give one word/term or phrase for each of the following statements:

Question 1.
A book of prime entry.
Answer:
Journal

Question 2.
The tax imposed by Central Government on Goods and Services.
Answer:
GST

Question 3.
A brief explanation of an entry.
Answer:
Narration

Question 4.
The process of recording transactions in the Journal.
Answer:
Journalising

Question 5.
The French word from which the word Journal is derived.
Answer:
Jour

Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal

Question 6.
Concession is given for immediate payment.
Answer:
Cash discount

Question 7.
Entry in which more than one accounts are be debited or credited.
Answer:
Combined Entry

Question 8.
Anything took by the proprietor from the business for his private use.
Answer:
Drawings

Question 9.
Tax payable to the Government on purchase of goods.
Answer:
Input Tax

Question 10.
Page number of the ledger.
Answer:
Ledger Folio

3. Select the most appropriate alternative from the alternatives given below and rewrite the statements.

Question 1.
___________ means explanation of the transactions recorded in the Journal.
(a) Narration
(b) Journalising
(c) Posting
(d) Casting
Answer:
(a) Narration

Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal

Question 2.
___________ discount is not recorded in the books of accounts.
(a) Trade
(b) Cash
(c) GST
(d) VAT
Answer:
(a) Trade

Question 3.
Recording of transaction in Journal is called ___________
(a) posting
(b) journalising
(c) narration
(d) prime entry
Answer:
(b) journalising

Question 4.
Every Journal entry require ___________
(a) casting
(b) posting
(c) narration
(d) journalising
Answer:
(c) narration

Question 5.
The ___________ column of the Journal is not recorded at the time of journalising.
(a) date
(b) particulars
(c) ledger folio
(d) amount
Answer:
(c) ledger folio

Question 6.
Goods sold on credit should be debited to ___________
(a) Purchase A/c
(b) Customer A/c
(c) Sales A/c
(d) Cash A/c
Answer:
(b) Customer A/c

Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal

Question 7.
Wages paid for installation of Machinery should be debited to ___________
(a) Wages A/c
(b) Machinery A/c
(c) Cash A/c
(d) Installation A/c
Answer:
(b) Machinery A/c

Question 8.
The commission paid to the agent should be debited to ___________
(a) Drawing A/c
(b) Cash A/c
(c) Commission A/c
(d) Agent A/c
Answer:
(c) Commission A/c

Question 9.
Loan taken from Dena Bank should be credited to ___________
(a) Capital A/c
(b) Dena Bank A/c
(c) Cash A/c
(d) Dena Bank Loan A/c
Answer:
(d) Dena Bank Loan A/c

Question 10.
Purchase of animals for cash should be debited to ___________
(a) Livestock A/c
(b) Goods A/c
(c) Cash A/c
(d) Bank A/c
Answer:
(a) Livestock A/c

4. State whether the following statements are True or False with reasons.

Question 1.
Narration is not required for each and every entry.
Answer:
This statement is False.
Correct statement: Narration is required for each and every entry.
Reasons: Narration is a brief explanation of the Journal Entry. It is written in the bracket just below the accounting entry. By reading the narration, the reader understands the meaning and significance of accounting entry and the nature and type of business transactions. Narration should be as short as possible and it should be simple and easy to understand.

Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal

Question 2.
A journal voucher is a must for all transactions recorded in the Journal.
Answer:
This statement is True.
Reasons: A voucher is a document that supports a payment made by the businessmen. It is legal evidence that a certain sum of money has been paid to a specific person or party. A Journal voucher is an original or basic voucher on the basis of which business transactions are journalized in the journal. Journal voucher provides legal proof for the business transactions. Therefore a journal voucher is necessary for all transactions recorded in the journal.

Question 3.
Cash discount allowed should be debited to discount A/c.
Answer:
This statement is True.
Reasons: Any allowance or reduction in payment allowed by the seller to the buyer or creditor to the debtor on payment of cash is called cash discount. It is the concession given to encourage prompt payment. The gash discount allowed is an expense or a loss to the receiver. Expenses or Losses are always to be debited. Cash discount allowed is an expense or loss and therefore it is debited to Discount A/c.

Question 4.
Journal is a book of prime entry.
Answer:
This statement is True.
Reasons: Journal is the most important book of accounts. It is a book of daily records. It is the main book of accounts in which transactions are recorded for the first time from source documents. Therefore this book is known as the book of original entry or first entry or prime entry. Business transactions are first entered in the journal and then they are recorded in other accounts book. For these reasons, the journal is called a book of prime entry.

Question 5.
Trade discount is recorded in the books of accounts.
Answer:
This statement is False.
Correct statement: Trade discount is never recorded in the books of accounts.
Reasons: The discount which is allowed or given by the manufacturer to wholesalers and by wholesalers to retailers and retailers to customers on the bulk purchases is called trade discount. By custom or by law trade discount is calculated on the catalog or printed price of the goods. Trade discount is directly deducted from the printed price and net prices of the goods or services are recorded in the books of accounts. A trade discount is given to encourage the buyers to increase their purchases. It is given to traders to enable them to earn a sizeable profit on the printed prices.

Question 6.
Goods lost by theft are debited to the goods account.
Answer:
This statement is False.
Correct statement: Goods lost by theft is credited to the goods account.
Reasons: Goods account is a real account because unsold goods are the property of the business. If goods are purchased or acquired, the Goods account is debited and if goods are sold or lost from the business, they are credited. As per the traditional approach, goods lost means go away from the business, and whatever goes out an account of it is credited. As per the modern approach if loss of business increases account of such loss is credited in the hooks of account.

Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal

Question 7.
If rent is paid to the landlord, the landlord’s A/c should be debited.
Answer:
This statement is False.
Correct Statement: If rent is paid to the landlord, the Rent account should be debited.
Reasons: Rent paid is an expense and hence it is a nominal account. When rent is paid to the landlord, the rent account is affected and not the landlord’s account. Rent is an expense to a tenant who pays it and it is an income for the landlord. Such payment is not personally due to the landlord as there is no lending and borrowing of money between landlord and rent payer. As per the rule of nominal account, the rent account is debited because it is an expense. As cash goes out cash account is credited.

Question 8.
Book Keeping records monetary and non-monetary transactions.
Answer:
This statement is False.
Correct Statement: Book Keeping records only monetary transactions.
Reasons: According to the money measurement concept, in the books of accounts accountant records only those business transactions which are monetary or financial in nature and capable to be expressed in monetary terms. It means the qualitative and quantitative aspects which cannot be measured in terms of money are not recorded in the books of account personal or non-monetary transactions are not recorded, in the books of accounts e.g. giving lift from car to neighbour, drinking tea along with friends in the restaurant, etc. are not recorded in the books of account as these transactions are not monetary in nature.

Question 9.
Drawings made by the proprietor increase his capital.
Answer:
This statement is False.
Correct statement: Drawings made by the proprietor decreases his capital.
Reasons: Total amount of goods and services withdrawn by the proprietor from the business from time to time for personal use or family use is called drawings. Withdrawals made by a businessman for business purpose is not treated as drawings. Drawings are always adjusted or deducted from capital. Heavy withdrawals made by a businessman for self-use reduces capital in the business. If the businessman controls the drawings more funds are made available for the development of the business. Drawing made by the proprietor reduces his capital investment.

Question 10.
GST paid on the purchase of goods Input tax A/c should be debited.
Answer:
This statement is True.
Reasons: GST is abbreviated from Goods and Service Tax. GST is levied by the government on the purchases of Goods and Services at a specified rate. Since it is imposed on purchases of goods and services, it increases its cost. GST is added to the purchase price. Purchases are always debited and hence GST i.e. Input tax account is also debited along with purchases. In the case of sales of goods and services, the output tax account is credited.

5. Fill in the blanks.

Question 1.
The first book of original entry is the ___________
Answer:
Journal

Question 2.
The process of recording transaction into journal is called ___________
Answer:
Journalising

Question 3.
An explanation of the transaction recorded in the journal ___________
Answer:
Narration

Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal

Question 4.
___________ discount is not recorded in the books of accounts.
Answer:
Trade

Question 5.
___________ is concession allowed for bulk purchase of goods or for immediate payment.
Answer:
Discount

Question 6.
Every Journal Entry requires ___________
Answer:
Narration

Question 7.
___________ discount is always recorded in the books of accounts.
Answer:
Cash

Question 8.
___________ is the document on the basis of which the entry is recorded in the journal.
Answer:
Voucher

Question 9.
There are ___________ parties to a cheque.
Answer:
Three

Question 10.
The ___________ cheque is safer than other cheques as it cannot be encashed on the counter of the bank.
Answer:
Crossed.

6. Specimen and Proforma.

Question 1.
Prepare specimen of Tax Invoice.
Answer:
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal 6 Q1

Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal

Question 2.
Prepare specimen of Receipt.
Answer:
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal 6 Q2

Question 3.
Prepare specimen of the Crossed cheque.
Answer:
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal 6 Q3

Question 4.
Prepare specimen of Cash voucher.
Answer:
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal 6 Q4

7. Correct the following statements and rewrite the statements.

Question 1.
All business transactions are recorded in the Journal.
Answer:
Only monetary transactions are recorded in the Journal.

Question 2.
A cash discount is not recorded in the books of accounts.
Answer:
A cash discount is recorded in the books of accounts.

Question 3.
Journal is a book of Secondary entry.
Answer:
Journal is a book of Prime entry.

Question 4.
GST is imposed by the Government of India from 1st July 2018.
Answer:
GST is imposed by the Government of India from 1st July 2017.

Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal

Question 5.
The machinery purchased by the Proprietor decreases his capital.
Answer:
Machinery purchased by the proprietor increases his Capital.

8. Do you agree or disagree with the following statements.

Question 1.
Narration is required for every entry.
Answer:
Agree

Question 2.
GST stands for Goods and Sales Tax.
Answer:
Disagree

Question 3.
Trade discount is not recorded in the books of accounts.
Answer:
Agree

Question 4.
Wages paid for the installation of Machinery is debited to Wages Account.
Answer:
Disagree

Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal

Question 5.
The process of entering or recording the transactions in a Journal is called Journalising.
Answer:
Agree

9. Calculate the following:

Question 1.
Purchased Motor Car from Tata & Company worth ₹ 2,00,000 at 18% GST. Find out GST amount.
Solution:
Cost of the Motor Car = ₹ 2,00,000
GST @ 18% = 2,00,000 × \(\frac{18}{100}\) = ₹ 36,000
Net value of the Motor Car = ₹ 2,00,000 + ₹ 36,000 = ₹ 2,36,000

Question 2.
Paid Transport charges ₹ 10,000 @ 5% GST. Calculate CGST & SGST.
Solution:
Transport charges = ₹ 10,000 @ 5% GST.
CGST = Transport charges × 2.5%.
= 10,000 × \(\frac{2.5}{100}\)
= 10,000 × \(\frac{25}{1000}\)
= ₹ 250
SGST = Transport charges × 2.5%.
= 10,000 × \(\frac{2.5}{100}\)
= 10,000 × \(\frac{25}{1000}\)
= ₹ 250
Net value = 10,000 + 250 + 250 = ₹ 10,500.

Question 3.
Bought goods from Ranjan ₹ 10,000 @ 5% GST and 10% cash discount. Calculate cash discount.
Solution:
Cost of the goods bought = ₹ 10,000 @ 5% GST and 10% cash discount.
GST on Goods Purchased = Cost of goods × 5%.
= 10,000 × \(\frac{5}{100}\)
= ₹ 500.
Net value of Goods Purchased = 10,000 + 500 = ₹ 10,500
Cash discount = Net value × 10%.
= 10,500 × \(\frac{10}{100}\)
= ₹ 1,050.

Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal

Question 4.
Received cheque of ₹ 90,000 from Kiran in full settlement of his account ₹ 1,00,000/-. Calculate discount rate.
Solution:
Discount allowed to Kiran = Amount due – Amount received
= 1,00,000 – 90,000
= ₹ 10,000.
Rate of discount allowed to Kiran = \(\frac{100 \times \text { Total Discount allowed }}{\text { Amount on which discount allowed }}\)
= \(\frac{100 \times 10,000}{1,00,000}\)
= 10%

Question 5.
Sold goods of ₹ 1,00,000 at 10% Trade Discount and 10% cash discount to Ram and received 50% amount by cheque. Calculate the amount of cheque received.
Solution:
Trade Discount = Catalogue price × Rate of trade discount
= 1,00,000 × \(\frac{10}{100}\)
= ₹ 10,000
Net amount receivable = Catalogue price – Trade Discount
= 1,00,000 – 10,000
= ₹ 90,000
50% of net amount received.
∴ Amount receivable = 50% of 90,000
= \(\frac{50}{100}\) × 90,000
= ₹ 45,000
Cash discount allowed = 10% on ₹ 45,000
= \(\frac{10}{100}\) × 45,000
= ₹ 4,500
Amount of cheque received = 50% of total amount – Cash discount
= 45,000 – 4,500
= ₹ 40, 500
Amount received by cheque = ₹ 40,500.

10. Complete the following table.

Question 1.
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal 10 Q1
Answer:
1. Drawings A/c
2. Sonali’s A/c
3. Bad debts A/c
4. Livestock A/c
5. Capital A/c

Practical Problems

Question 1.
Journalise the following transactions in the books of Anand General Merchants.
2019 April
1 Mr. Anand started the business with cash of ₹ 60,000.
5 Purchased goods for cash ₹ 30,000.
7 Sold goods of ₹ 10,000 to Suresh.
10 Purchased Furniture from Mr. Govind on credit ₹ 30,000.
15 Paid for Rent ₹ 3000 and paid by debit card.
21 Purchased goods from Urmila on credit ₹ 70,000.
27 Paid for Transport ₹ 1,000 to United Transport.
30 Paid to Urmila ₹ 20,000 on behalf of Sharmila.
Solution:
In the Journal of Anand General Merchants
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal Practical Problems Q1

Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal

Question 2.
Journalise the following transactions in the books of Gajanan.
2019 May
3 Purchased goods for ₹ 90,000 and amounts paid by Bank directly.
7 Sold goods to Satish on credit ₹ 30,000.
9 Paid for Postage ₹ 10,000.
12 Paid for Wages ₹ 15,000.
15 Received cheque of ₹ 30,000 from Satish.
21 Received Dividend ₹ 5000.
25 Purchased Laptop of ₹ 40,000 and paid by cheque.
28 Deposited cash ₹ 10,000 into State Bank of India.
31 Purchased goods for ₹ 40,000 and paid by RTGS.
Solution:
Journal of Gajanan
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal Practical Problems Q2
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal Practical Problems Q2.1

Question 3.
Journalise the following transactions in the books of Ashok General Stores.
2019 May
1 Received ₹ 5,000 from Ram on behalf of Bharat.
4 Purchased Goods for cash ₹ 55,000.
8 Paid for Salary ₹ 8,000.
12 Purchased goods from Ganesh ₹ 30,000 on credit.
17 Sold goods to Mrs. Neha ₹ 60,000 on credit.
20 Purchased Machinery of ₹ 80,000 @ 12% GST and amount paid by cheque.
25 Paid to SG & Sons by cheque ₹ 30,000.
28 Received Commission ₹ 10,000 from Ganesh.
30 Paid Rent ₹ 5000.
31 Purchased Shares of Atul Company Ltd. for ₹ 10,000 through Demat account.
Solution:
Journal of Ashok General Stores
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal Practical Problems Q3
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal Practical Problems Q3.1
Working Note:
Dated 20th May 2019:
Calculation of CGST and SGST on Machinery
Catalogue price of ₹ 80,000 @ 12%.
CGST i.e. Central Goods and Services Tax = 12% × \(\frac{1}{2}\) = 6%.
CGST = Price of Machinery × 6%.
= 80,000 × \(\frac{6}{100}\)
= ₹ 4,800.
SGST i.e. State Goods and Service Tax = 12% × \(\frac{1}{2}\) = 6%.
SGST = 80,000 × \(\frac{6}{100}\) = ₹ 4,800.

Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal

Question 4.
Journalise the following transactions in the books of Sanjay General Stores.
2019 June
1 Started business with cash ₹ 50,000, Bank ₹ 1,00,000, Goods worth ₹ 50,000.
5 Purchased goods from Mohan on credit ₹ 80,000 at 10% Trade Discount.
9 Sold goods to Urmila ₹ 30,000 at 5% Trade Discount.
12 Paid into Dena Bank ₹ 40,000.
15 Goods worth ₹ 5000 were distributed as a free samples.
22 Paid for Commission ₹ 5,000 to Anand.
24 Received ₹ 28,000 from Urmila in full settlement of her account by Debit Card.
29 Paid for Advertisement ₹ 9,000.
30 Purchased Laptop for ₹ 20,000 @ 28% GST and amount paid by NEFT.
Solution:
Journal of Sanjay General Stores
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal Practical Problems Q4
Working Note:
5th June 2019:
Calculation of Trade discount
Purchased goods for ₹ 80,000 @ 10% Trade discount
Trade discount = 80,000 × \(\frac{10}{100}\) = ₹ 8,000
Net Purchase Price = 80,000 – 8,000 = ₹ 72,000

24th June 2019:
Discount allowed to Urmila = Amount due – Amount received
= 28,500 – 28,000
= ₹ 500

30th June 2019:
Calculation of CGST and SGST
Price of Laptop = ₹ 20,000 @ 28% GST.
CGST = (Price of Laptop) × Rate of CGST
= 20,000 × \(\frac{14}{100}\)
= ₹ 2,800
SGST = (Price of Laptop) × Rate of SGST
= 20,000 × \(\frac{14}{100}\)
= ₹ 2,800

Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal

Question 5.
Journalise the following transactions in the books of Kunal Stores.
2018 August
1 Purchased goods of ₹ 90,000 at 10% Trade Discount and 10% Cash Discount from Rakesh and 1/3rd amount paid by cheque.
5 Opened current account in State Bank of India by depositing ₹ 60,000.
8 Cash purchases ₹ 85,000.
10 Goods sold on credit to Tushar ₹ 20,000 @ 10% Trade Discount.
12 Paid Salary ₹ 4,000.
16 Tushar returned goods of ₹ 250.
17 Goods taken by Kunal for his private use ₹ 2,000.
20 Purchased Laptop of ₹ 40,000 from Joshi Electronics @ 18% GST and paid by cheque.
22 Rent paid by cheque ₹ 15,000.
25 Purchased Motor car worth ₹ 2,00,000 for cash @ 18% GST and paid by Bank.
26 Goods distributed as free sample ₹ 4,000.
28 Purchased goods from Amit of ₹ 60,000 on credit.
30 Paid by ECS cash to Amit ₹ 58,500, who allowed us a discount of ₹ 1,500.
30 Sold goods ₹ 5,000 at a loss of ₹ 1,000
31 Sold goods for ₹ 20,000.
Solution:
Journal of Kunal Stores
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal Practical Problems Q5
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal Practical Problems Q5.1
Working Notes:
1. 2018 Aug. 1st:
Trade discount = 10% on Purchase catalogue price
= \(\frac{10}{100}\) × 90,000
= ₹ 9,000
Net Purchase price = 90,000 – 90,00 = ₹ 81,000
Amount paid = \(\frac{1}{3}\) × 81,000 = ₹ 27,000
Cash discount = 10% on 27,000
= \(\frac{10}{100}\) × 27,000
= ₹ 2700
Amount paid by cheque = 27,000 – 2700 = ₹ 24,300

2. Aug. 10th:
Net price of Goods sold to Tushar = 20,000 – 10% Trade discount
= 20,000 – \(\frac{10}{100}\) × 20,000
= 20,000 – 2,000
= ₹ 18,000

3. 20th Aug. 2018:
Calculation of GST
CGST = 9% on ₹ 40,000
= \(\frac{9}{100}\) × 40,000
= ₹ 3,600
SGST = 9% on ₹ 40,000
= \(\frac{9}{100}\) × 40,000
= ₹ 3,600

4. 25th Aug. 2018:
Calculation of GST
CGST = 9% on ₹ 2,00,000
= \(\frac{9}{100}\) × 2,00,000
= ₹ 18,000
SGST = 9% on ₹ 2,00,000
= \(\frac{9}{100}\) × 2,00,000
= ₹ 18,000

Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal

Question 6.
Journalise the following transactions in the books of Nina General Stores.
2018 Sept
1 Sold goods of ₹ 50,000 at 10% Trade Discount and 10% Cash Discount to Raj and received 50% by cheque and 20% by cash.
3 Bought goods worth ₹ 60,000 from Prashant at 7.5% Trade Discount and half amount paid by cash.
5 Returned goods worth ₹ 550 to Prashant.
7 Sold goods worth ₹ 90,000 to Ranvir on credit at 10% Trade Discount.
12 Received Commission ₹ 4,500.
15 Received cheque of ₹ 80,000 from Ranvir in full settlement of his account.
18 Purchased Computer worth ₹ 80,000 from Reliance Company by cheque at 28% GST.
22 Wages paid ₹ 13,000.
23 Paid for Life Insurance premium ₹ 17,000.
27 Sold goods worth ₹ 28,000 to Tushar who paid us ₹ 18,000 immediately
Solution:
Journal of Nina General Stores
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal Practical Problems Q6
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal Practical Problems Q6.1
Working Notes:
1. 1st Sept. 2018:
Selling (invoice) price = ₹ 50,000
Trade Discount = 10% on ₹ 50,000
= \(\frac{10}{100}\) × 50,000
= ₹ 5,000
Net selling price = 50,000 – 5,000 = ₹ 45,000
50% of the Net selling price received by cheque
Amount of cheque received = 50% of Net selling price – Cash discount
= \(\frac{50}{100}\) × 45,000 – 10% on ₹ 22,500
= 22,500 – 2,250
= ₹ 20,250
20% of Net selling price received by cash.
Net amount of cash received = 20% of Net selling price – Cash discount
= \(\frac{20}{100}\) × 45,000 – Cash discount
= 9,000 – \(\frac{10}{100}\) × 9000
= 9,000 – 900
= ₹ 8,100
30% of Net Selling price is not received
∴ Amount not received = \(\frac{30}{100}\) × 45,000 = ₹ 13,500
Total of cash discount = 2,250 + 900 = ₹ 3,150

2. 3rd Sept. 18:
Trade discount = 7.5% on 60,000
= \(\frac{7.5}{100}\) × 60,000
= ₹ 4,500
Net Purchase price = 60,000 – 4,500 = ₹ 55,500

3. 18th Sept. 18:
Calculation of GST
CGST = (Purchase Price of Computer) × 14%
= 80,000 × \(\frac{14}{100}\)
= ₹ 11,200
SGST = 80,000 × \(\frac{14}{100}\) = ₹ 11,200
Net Purchase price of Computer = 80,000 + 11,200 + 11,200 = ₹ 1,02,400

Question 7.
Journalise the following transactions in the books of Varun
2018 Oct.
1 Purchased Machinery of ₹ 95,000 and paid ₹ 5,000 for freight.
3 Purchased goods for ₹ 1,50,000 and amount paid by Bank.
6 Purchased Laptop from Nagesh & Co. worth ₹ 1,80,000 @ 18% GST.
10 Paid into Bank of Baroda ₹ 70,000.
12 Paid for Rent ₹ 4,000 and Commission ₹ 3,000.
15 Bought goods from Tushar Company Ltd. ₹ 1,20,000 at 12% GST and paid 1/2 amount by RTGS.
16 Cash purchases ₹ 50,000 amount paid by cheque.
20 Invoiced goods to Satish ₹ 80,000 at 12% GST and the amount received by cheque.
25 Paid for Telephone charges ₹ 90,000
27 Mrs. Varsha bought goods from us ₹ 90,000 at a 12% Trade Discount.
28 Purchased goods from Abhijeet & Sons ₹ 1,50,000 at 18% GST.
30 Paid to Abhijeet & Sons and received 10% Cash Discount by cheque.
31 Paid for Advertisement ₹ 8,000 and Brokerage ₹ 12,000.
Solution:
Journal of Varun
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal Practical Problems Q7
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal Practical Problems Q7.1

Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal

Question 8.
Journalise the following transactions in the books of Dhoni Auto Car Centre
2018 Nov
1 Sold 1,000 shares for ₹ 100 each and paid brokerage @ 1% and the amount credited to our account.
4 Purchased goods from Ashish & Co. of ₹ 2,00,000.
6 Sold goods to Virat & Co. ₹ 1,50,000.
8 Paid for Advertisement ₹ 30,000 to Times of India.
10 Paid for Printing and Stationery ₹ 7,000.
12 Purchased goods from Prakash & Co. ₹ 1,50,000 @ 18% GST.
15 Paid for Transport charges ₹ 10,000 @12% GST.
20 Purchased goods from Vikram & Sons ₹ 1,20,000 @ 18% GST and paid half the amount immediately.
25 Paid to Prakash & Co. less 10% discount.
30 Invoiced Goods to Sanjay ₹ 60,000.
31 Sanjay returned goods of ₹ 10,000.
31 Sanjay became insolvent and recovered only 50 paise in a rupee as a final settlement from him.
Solution:
Journal of Dhoni Auto Car Centre
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal Practical Problems Q8
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal Practical Problems Q8.1
Working Notes:
1. 2018, Nov. 1:
Amount credited to Bank A/c = Sales proceed – Brokerage @ 1%
= 1,000 × 100 – \(\frac{1}{100}\) × 1,000 × 100
= 1,00,00 – 1,000
= ₹ 99,000

2. Nov. 12:
Net Purchase price = Purchase price + 9% CGST + 9% SGST
= 1,50,000 + \(\frac{9}{100}\) × 1,50,000 + \(\frac{9}{100}\) × 1,50,000
= 1,50,000 + 13,500 + 13,500
= ₹ 1,77,000

3. Nov. 20:
Net Purchase price = Purchase price + 9% CGST + 9% SGST
= 1,20,000 + \(\frac{9}{100}\) × 1,20,000 + \(\frac{9}{100}\) × 1,20,000
= 1,20,000 + 10,800 + 10,800
= ₹ 1,41,600
Amount paid = \(\frac{1}{2}\) of 1,41,600 = ₹ 70,800 and credit purchased = ₹ 70,800.

4. Nov. 25:
Cash discount = Amount due to Prakash & Co × 10%
= 1,77,000 × \(\frac{10}{100}\)
= ₹ 17,700

5. Bad debts = Amount due from Sanjay – Amount recovered
= 50,000 – 50% of 50,000
= 50,000 – 25,000
= ₹ 25,000

Question 9.
Journalise the following transactions in the books of Hero Enterprises.
Balance on 1st April 2019
Cash at Bank ₹ 80,000, Sundry Debtors Ram ₹ 20,000, Rahim ₹ 30,000, Stock ₹ 55,000, Building ₹ 1,50,000.
Credit Balances on 1st April 2019
Sundry Creditors Swapna ₹ 20,000, Rohit ₹ 30,000, Bank Loan ₹ 50,000.
2019 April
1 Purchased goods worth ₹ 1,50,000 from Prashant & Co., less 10% Trade Discount.
4 Sold goods to Mr. Amit Sharma ₹ 70,000 at 10% Trade Discount on credit.
9 Purchased goods for cash ₹ 2,00,000 @ 28% GST amount paid by NEFT.
12 Sold Goods to Aditya Ray of ₹ 90,000 @ 28% GST.
15 Paid for Rent ₹ 5000 and Salary ₹ 18,000.
17 Paid for Proprietor’s house Rent ₹ 12,000.
20 Sold half of the goods purchased on 9th April at 20% Profit and 28% GST.
25 Paid for Wages ₹ 1,500.
25 Purchased Furniture ₹ 1,80,000 @ 12% GST and amount paid by RTGS.
28 Sold an old Furniture of ₹ 20,000 for ₹ 12,000.
30 Sold shares of ₹ 10,000 for ₹ 15,000 and the amount received by cheque.
Solution:
Journal of Hero Enterprises
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal Practical Problems Q9
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal Practical Problems Q9.1
Working Notes:
1. 2019 April, 20:
Cost of Goods sold = \(\frac{1}{2}\) of purchases on 9th April, 2019
= \(\frac{1}{2}\) × 2,00,000
= ₹ 1,00,000
Selling price of Goods sold = \(\frac{120}{100}\) × ₹ 1,00,000 = ₹ 1,20,000

2. April, 28:
Loss on sale of furniture = Cost of furniture – Selling price
= 20,000 -12,000
= ₹ 8,000

3. April, 30:
Profit on sale of shares = Selling price – Cost of shares
= 15,000 – 10,000
= ₹ 5,000

Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal

Question 10.
Journalise the following transactions in the books of Harbhajan & Co. for the month of 1st April 2019.
Balance on 1st April 2019
Cash in hand ₹ 35,000, Cash at Bank ₹ 25,000, Furniture ₹ 1,50,000, Laptop ₹ 1,00,000
Debtors: Sangita ₹ 40,000, Viru ₹ 30,000
Creditors: Ganesh ₹ 10,000, Garima ₹ 40,000, Bank loan ₹ 50,000.
2019 April
1 Purchased goods from Ajay Kumar worth ₹ 2,50,000 at 10% Trade discount @ 18% GST and paid 1/4 amount in Cash.
5 Purchased shares of Infosys Company ₹ 50,000 and ₹ 500 paid as a brokerage for Demat A/c.
8 Sold goods to Raj worth ₹ 90,000 at 10% Trade discount and 1/3 amount received by cash and 5% cash discount is allowed.
12 Paid house rent of proprietor ₹ 9,000 and office rent ₹ 5,000.
15 Purchased Laptop of ₹ 60,000 @ 18% GST and paid amount by cheque.
20 Paid transport charges on the above Laptop ₹ 1,000 @ 18% GST.
25 Paid Commission ₹ 20,000 to Ram.
26 Paid Telephone Charges ₹ 1,000.
28 Transferred from private Bank A/c of proprietor to business Bank A/c ₹ 40,000.
30 Bought goods for ₹ 1,50,000 @ 12% as GST by cheque.
30 Exchanged our Furniture of ₹ 30,000 against a Motor car of the same value for business.
Solution:
Journal of Harbhajan & Co.
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal Practical Problems Q10
Maharashtra Board 11th BK Textbook Solutions Chapter 3 Journal Practical Problems Q10.1
Working Notes:
1. 8 April 2019:
Net selling price = Selling price – 10% Trade discount
= 90,000 – 10% on 90,000
= 90,000 – 9,000
= ₹ 81,000
Cash received = \(\frac{1}{3}\) of 81,000
= \(\frac{1}{3}\) × 81,000
= ₹ 27,000
Net cash received = 27,000 – Cash discount @ 5%
= 27,000 – \(\frac{5}{100}\) × 27,000
= 27,000 – 1,350
= ₹ 25, 650
Credit sale = \(\frac{2}{3}\) of 81,000
= \(\frac{2}{3}\) × 81,000
= ₹ 54,000

Maharashtra Board 11th BK Important Questions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Balbharti Maharashtra State Board 11th Commerce Book Keeping & Accountancy Important Questions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping Important Questions and Answers.

Maharashtra State Board 11th Commerce BK Important Questions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

1. Answer in one sentence only.

Question 1.
State the meaning of the accounting equation.
Answer:
An equation that indicates or shows that the total assets of a business are always equal to the total liabilities of a business plus capital is called the accounting equation.

Question 2.
What do you mean by debt?
Answer:
To debit an account means to enter the entry or write on the left-hand side of an account.

Maharashtra Board 11th BK Important Questions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 3.
Give two examples of personal accounts.
Answer:
Two examples of personal accounts are stated below:

  1. Mr. Raghuvir Sharma’s Account
  2. The Bank of India’s Account.

Question 4.
What is a Nominal Account?
Answer:
The account relating to business expenses, incomes, and gains is called a nominal account.
e.g. Rent A/c.

Question 5.
Give two examples of real accounts.
Answer:
Two examples of real accounts are:

  1. Cash A/c
  2. Goodwill A/c

Question 6.
State whether drawings increase or decrease owner’s equity.
Answer:
Drawings made by the owner of the business decrease its equity.

Question 7.
What is a conventional cash book?
Answer:
A cash book that is prepared to record not only cash transactions but all types of transactions such as credit purchase or sale, banking transactions, opening, and closing entries, adjustments entries is called a conventional cash book.

Maharashtra Board 11th BK Important Questions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 8.
Explain the term dual aspect.
Answer:
Every transaction has two aspects i.e. for every debit there is corresponding and equal credit.

Question 9.
State the meaning of impersonal account.
Answer:
The account which is not of a person is called an impersonal account.

Question 10.
Write the rule of Real account.
Answer:
The rule of real account states that Debit what comes in and Credit what goes out.

Question 11.
Which account will be debited when goods are sold to Ram on credit?
Answer:
When goods are sold to Ram, Ram’s A/c will be debited.

Question 12.
Which account will be debited when Mr. Shyam has paid cash to you?
Answer:
Cash A/c will be debited when Mr. Shyam has paid cash to us.

2. Write one word/term or phrase which can substitute each of the following statements.

Question 1.
Expenses are paid before it is due.
Answer:
Prepaid Expenses

Question 2.
Income due but not yet received.
Answer:
Accrued Income

Maharashtra Board 11th BK Important Questions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 3.
Carriage paid on the sale of goods.
Answer:
Carriage Outward

Question 4.
Statement of Assets & Liabilities.
Answer:
Balance Sheet

Question 5.
Account prepared to know Net Profit or Net Loss.
Answer:
Profit & Loss Account

Question 6.
Value of goods remaining unsold at the end of the year.
Answer:
Closing Stock

Question 7.
The provision was made to compensate the loss on account of likely debts.
Answer:
Provision for Bad & Doubtful Debts

Question 8.
The accounts are prepared at the end of the accounting year to know the profit or loss and financial position of the business.
Answer:
Final Accounts

Maharashtra Board 11th BK Important Questions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 9.
An amount spent on promoting the sale of goods.
Answer:
Selling Expenses

Question 10.
Additional information is provided below the Trial Balance.
Answer:
Adjustments

3. Select the most appropriate alternatives from those given below and rewrite the statements.

Question 1.
___________ is excess of assets over liabilities.
(a) Goodwill
(b) Capital
(c) Investments
(d) Drawings
Answer:
(b) Capital

Question 2.
Discount earned is transferred to credit side of ___________ account.
(a) Current A/c
(b) Profit & Loss Account
(c) Trading
(d) Capital
Answer:
(b) Profit & Loss Account

Question 3.
___________ is a statement that shows the financial position of a business on a specific date.
(a) Trading account
(b) Trial Balance
(c) Profit & Loss A/c
(d) Balance Sheet
Answer:
(d) Balance Sheet

Maharashtra Board 11th BK Important Questions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 4.
Outstanding expenses are shown on the ___________ side of Balance Sheet.
(a) Assets
(b) Liability
(c) Both
(d) None of these
Answer:
(b) Liability

Question 5.
Interest on Drawing is credited to ___________ Account.
(a) Trading
(b) Profit & Loss Account
(c) Capital
(d) All
Answer:
(b) Profit & Loss Account

Question 6.
Debit balance of Trading Account means ___________
(a) Gross Loss
(b) Net Loss
(c) Net Profit
(d) Gross Profit
Answer:
(a) Gross Loss

Question 7.
Carriage Inward is debited to ___________ Account.
(a) Trading A/c
(b) Profit & Loss
(c) Capital
(d) Bank
Answer:
(a) Trading A/c

Question 8.
Excess of credit over to debit in Profit & Loss Account indicates ___________
(a) Net Profit
(b) Gross Profit
(c) Gross Loss
(d) Net Loss
Answer:
(a) Net Profit

Maharashtra Board 11th BK Important Questions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 9.
Closing stock is always valued at cost or market price which is ___________
(a) more
(b) less
(c) zero
(d) equal
Answer:
(b) less

Question 10.
When a specific date is not given, in that case, interest on the drawing is charged for ___________ month.
(a) Four
(b) Six
(c) Eight
(d) Nine
Answer:
(b) Six

4. Fill in the blanks.

Question 1.
Gross Profit is transferred to ___________ account.
Answer:
Profit & Loss Account

Question 2.
Debit Balance of Trading Account indicates ___________
Answer:
Gross Loss

Question 3.
Income Receivable appears on ___________ side of Balance Sheet.
Answer:
Asset

Question 4.
Interest on Bank Loan is debited to ___________ A/c.
Answer:
Profit & Loss Account

Maharashtra Board 11th BK Important Questions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 5.
Profit and Loss Account is prepared to find out ___________ results of the business.
Answer:
Networking

Question 6.
All indirect/operating expenses are transferred to ___________ account.
Answer:
Profit and Loss Account

Question 7.
Interest of proprietor’s drawing is credited to ___________ account.
Answer:
Profit & Loss Account

Question 8.
An excess of debit over credit in the Profit & Loss A/c represents the ___________
Answer:
Net Loss

Question 9.
All direct expenses are transferred to ___________ account.
Answer:
Trading A/c

Maharashtra Board 11th BK Important Questions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 10.
Balance Sheet is ___________ of assets & liabilities.
Answer:
Statement

5. Classify the following accounts under the types of Personal, Real, and Nominal accounts.

Question 1.
Investments A/c
Answer:
Real Account

Question 2.
Creditors A/c
Answer:
Personal Account

Question 3.
Land A/c
Answer:
Real Account

Question 4.
Purchase Returns A/c
Answer:
Personal Account

Question 5.
Cash A/c
Answer:
Real Account

Question 6.
Building A/c
Answer:
Real Account

Maharashtra Board 11th BK Important Questions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 7.
Capital A/c
Answer:
Personal Account

Question 8.
Goodwill A/c
Answer:
Real Account

Question 9.
Interest received A/c
Answer:
Nominal Account

Question 10.
Depreciation A/c
Answer:
Nominal Account

Question 11.
Stationery A/c
Answer:
Nominal Account

Question 12.
Salary A/c
Answer:
Nominal Account

Maharashtra Board 11th BK Important Questions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 13.
Excise duty A/c
Answer:
Nominal Account

Question 14.
Bank Loan A/c
Answer:
Personal Account

Question 15.
Bank Overdraft A/c
Answer:
Personal Account

Question 16.
Sales A/c
Answer:
Nominal Account

Question 17.
Return Inwards A/c
Answer:
Personal Account

Question 18.
Rent received A/c
Answer:
Nominal Account

Maharashtra Board 11th BK Important Questions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 19.
Wages A/c
Answer:
Nominal Account

Question 20.
Discount received A/c
Answer:
Nominal Account

Question 21.
Debtors A/c
Answer:
Personal Account

Question 22.
Furniture & Fixtures A/c
Answer:
Nominal Account

Question 23.
Purchases A/c
Answer:
Nominal Account

Maharashtra Board 11th BK Important Questions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 24.
Bad Debts A/c
Answer:
Nominal Account

Question 25.
Dadar Library A/c
Answer:
Personal Account

Question 26.
Rent paid A/c
Answer:
Nominal Account

Question 27.
Prepaid Insurance A/c
Answer:
Personal Account

Question 28.
Carriage Outwards A/c
Answer:
Nominal Account

Question 29.
Rent Receivable A/c
Answer:
Personal Account

Maharashtra Board 11th BK Important Questions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 30.
Profit on sale of machinery A/c
Answer:
Nominal Account

Question 31.
Bills Payable A/c
Answer:
Personal Account

Question 32.
Bank of India A/c
Answer:
Personal Account

Question 33.
Carriage Inwards A/c
Answer:
Nominal Account

Question 34.
Stock A/c
Answer:
Real Account

Question 35.
Accrued Interest A/c
Answer:
Personal Account

Maharashtra Board 11th BK Important Questions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 36.
Bank A/c
Answer:
Personal Account

Question 37.
12% Government Bonds A/c
Answer:
Real Account

Question 38.
Carriage A/c
Answer:
Nominal Account

Question 39.
Advertisement A/c
Answer:
Nominal Account

Question 40.
Conveyance A/c
Answer:
Nominal Account

Maharashtra Board 11th BK Important Questions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 41.
Premises A/c
Answer:
Real Account

Question 42.
Octroi A/c
Answer:
Nominal Account

Question 43.
Postage A/c
Answer:
Nominal Account

Question 44.
Electricity Charges A/c
Answer:
Nominal Account

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Balbharti Maharashtra State Board Bookkeeping and Accountancy 11th Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping Textbook Exercise Questions and Answers.

Maharashtra State Board Bookkeeping and Accountancy 11th Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

1. Answer in one sentence only.

Question 1.
What is a Double Entry System?
Answer:
A system of accounting is which double or two-fold effects of every business transaction are recorded systematically in the books of accounts is called a double-entry book-keeping system.

Question 2.
What is an Account?
Answer:
The summarised record of all transactions related to a person, an institution, an income, and expenditure, an asset, a liability, a profit, gain as per the accounting principles is called an account.

Question 3.
State the meaning of the Single Entry System.
Answer:
A book-keeping system in which only one aspect of every business transaction is considered and systematically recorded in the books of accounts and other aspects are completely ignored is called Single Entry System.

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 4.
What is Personal Account?
Answer:
Account of person or account relating to a person with whom a business keeps dealings is called Personal Account.
e.g. Kishor’s A/c, Bank of India’s A/c.

Question 5.
State the rules of Nominal Account.
Answer:
The rules of Nominal Account state that Debit all expenses or loses and Credit all incomes and gains.

Question 6.
Give two examples of intangible assets.
Answer:
Goodwill and Patents or Trademark are two examples of intangible assets.

Question 7.
State the meaning of Real Account.
Answer:
Account of tangible as well as intangible property or anything owned and possessed by the business is called real account, e.g. Cash A/c.

Question 8.
Give two examples of income and gains.
Answer:
Interest received, Discount earned, sales, etc. are examples of income and gains.

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 9.
State the rule for Personal Account.
Answer:
The rule of personal account states that Debit the receiver and Credit the giver.

Question 10.
How many methods of recording accounting information are there?
Answer:
The methods of recording accounting information are broadly classified as (i) Indian System and (ii) English System. It is sub-classified as (a) a Single Entry System and (b) a Double Entry System.

2. Write one word/term or phrase which can substitute each of the following statements.

Question 1.
Method of Accounting which records both aspects of the transaction.
Answer:
Double Entry System

Question 2.
The right-hand side of an account.
Answer:
Credit side

Question 3.
Name of the account which is debited when proprietor uses business money for personal use.
Answer:
Drawings A/c

Question 4.
Accounts of Assets and Properties.
Answer:
Real A/c

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 5.
Accounts of Expenses and Losses and Incomes and Gains.
Answer:
Nominal A/c

Question 6.
The left-hand side of an account.
Answer:
Debit side

Question 7.
The Assets which cannot be seen, touched or felt.
Answer:
Intangible Asset

Question 8.
A person who invented the Double Entry System.
Answer:
Luca D. Bargo Pacioli

Question 9.
Incomplete system of recording business transactions.
Answer:
Single Entry System

Question 10.
A scientific system of recording business transactions.
Answer:
Double Entry system

3. Select the most appropriate alternatives from those given below and rewrite the statements.

Question 1.
International Accounting day is observed on _______________
(a) 10th November
(b) 12th November
(c) 10th December
(d) 15th December
Answer:
(a) 10th November

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 2.
Conventional system of accounting is _______________
(a) English entry system
(b) Double entry system
(c) Indian System
(d) None of these
Answer:
(c) Indian System

Question 3.
Every debit has corresponding _______________
(a) Debit
(b) Credit
(c) Right hand side
(d) None of these
Answer:
(b) Credit

Question 4.
Radha’s Account is a type of _______________ account.
(a) Nominal
(b) Personal
(c) Real
(d) Expenses
Answer:
(b) Personal

Question 5.
Machinery Account is _______________ account.
(a) Nominal
(b) Income
(c) Personal
(d) Real
Answer:
(d) Real

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 6.
Goodwill is _______________ asset.
(a) Tangible
(b) Current
(c) an intangible
(d) None of these
Answer:
(c) an intangible

Question 7.
Prepaid expenses is _______________ account.
(a) Real
(b) Personal
(c) Nominal
(d) Income
Answer:
(b) Personal

Question 8.
Debit the receiver, Credit the _______________
(a) Goes out
(b) Giver
(c) Income and gains
(d) Comes in
Answer:
(b) Giver

Question 9.
Debit what comes in, Credit what _______________
(a) Giver
(b) Expenses and losses
(c) Goes out
(d) Income and gains
Answer:
(c) Goes out

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 10.
Debit all _______________ and Credit all income and gains.
(a) Giver
(b) Expenses and losses
(c) Goes out
(d) None of these
Answer:
(b) Expenses and Losses

4. State whether the following statements are True or False with reasons.

Question 1.
Outstanding expense is a nominal account.
Answer:
This statement is False.
Outstanding expenses are personal accounts. It is a representative personal account. Expenses are payable to some person.

Question 2.
A capital account is a real account.
Answer:
This statement is False.
Capital is a personal account. Amount invested in the business by the proprietor is capital. A proprietor is a natural person.

Question 3.
Every debit has equal and corresponding credit.
Answer:
This statement is True.
Under the Double Entry System, the two-fold effects of each transaction are recorded. Under this system one account is to be debited and another is to be credited with an equal amount.

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 4.
The discount received is a nominal account.
Answer:
This statement is True.
Discount received in an income for the business. All expenses and income come under the Nominal account.

Question 5.
The drawings account is a nominal account.
Answer:
This statement is False.
The drawing is a Personal account. Drawing means cash on goods withdrawn by the proprietor for personal use. As the proprietor is a Personal account his drawings are also a Personal account.

Question 6.
Outstanding salary is a nominal account.
Answer:
This statement is False.
Outstanding salary is Personal account. Salary is the amount payable to staff. As he is a person, the amount payable to him is a personal account. It is a Representative Personal account.

Question 7.
A loan account is a personal account.
Answer:
This statement is True.
The loan is taken from a person or bank and they are persons either natural or person or artificial persons.

Question 8.
A goodwill account is a real account.
Answer:
This statement is True.
All properties/assets come under real accounts. Goodwill is an intangible asset so goodwill is a Real account.

Question 9.
A discount account is a nominal account.
Answer:
This statement is False.
Trade discount is a noncash transaction it is not recorded in the books of account so it doesn’t fall under any account.

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 10.
Personal transactions of proprietors are recorded in the books of account of business.
Answer:
This statement is False.
Personal transactions of proprietors are not recorded in the books of account of business. Only business transactions are recorded in the books of account of business as businesses have a separate entity.

Question 11.
A motor car account is a Real Account.
Answer:
This statement is True.
All properties and assets fall under real accounts. Motor car is property so it is a real account.

Question 12.
The rule of a Nominal Account is to Debit the receiver and Credit the giver.
Answer:
This statement is False.
The rule of the Nominal account is to debit all expenses and losses Credit all incomes and gains.

Question 13.
A bank loan account is a Nominal account.
Answer:
This statement is False.
The bank account is a Personal account. It is a representative person.

Question 14.
Assets = Capital + Liabilities
Answer:
This statement is True.
Total assets are always equal to total liabilities. Total liabilities include capital also.
So Assets = Capital + Liabilities.

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 15.
A Trademark account is a personal account.
Answer:
This statement is False.
Trademark is a real account. All tangible and intangible assets are properties and they fall under real account.

5. Fill in the blanks.

Question 1.
Increase in asset is debited and decrease in asset is _______________
Answer:
Credited

Question 2.
Assets = Liabilities + _______________
Answer:
Capital

Question 3.
Increase in capital is credited and decrease in capital is _______________
Answer:
Debited

Question 4.
Scientific and complete system of recording is known as _______________
Answer:
Double Entry System

Question 5.
Debit all expenses and losses, Credit all _______________
Answer:
Income and Gains

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 6.
Land and Building account is _______________ account.
Answer:
Real

Question 7.
Cash Book and Personal Accounts are only maintained under _______________ system.
Answer:
Single Entry

Question 8.
Debit what comes in and credit what goes out is the rule of _______________ account.
Answer:
Real

Question 9.
Travelling expenses account is _______________ type of Account.
Answer:
Nominal

Question 10.
Every transaction has _______________ effect.
Answer:
Two Fold

Question 11.
_______________ accounts are accounts of properties and assets.
Answer:
Real

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 12.
Laptop account is a _______________ account.
Answer:
Real

6. Classify the following accounts under the types of Personal, Real, and Nominal accounts.

Question 1.
Mr. Rohit’s capital A/c
Answer:
Personal Account

Question 2.
Loose Tools A/c
Answer:
Real Account

Question 3.
Drawing A/c
Answer:
Personal Account

Question 4.
Cartage A/c
Answer:
Nominal Account

Question 5.
Prepaid Rent A/c
Answer:
Personal Account

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 6.
Copyright A/c
Answer:
Real Account

Question 7.
Patent A/c
Answer:
Real Account

Question 8.
Outstanding Income A/c
Answer:
Personal Account

Question 9.
Prepaid Expenses A/c
Answer:
Personal Account

Question 10.
Commission Received A/c
Answer:
Nominal Account

Question 11.
Freight A/c
Answer:
Nominal Account

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 12.
Plant and Machinery A/c
Answer:
Real Account

Question 13.
Sundry Income A/c
Answer:
Nominal Account

Question 14.
Live Stock A/c
Answer:
Real Account

Question 15.
Goods distributed as free sample A/c
Answer:
Nominal Account

Question 16.
Radhika’s A/c
Answer:
Personal Account

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 17.
Outstanding Wages A/c
Answer:
Personal Account

Question 18.
Loss on Sale of Furniture A/c
Answer:
Nominal Account

Question 19.
Bank of Maharashtra A/c
Answer:
Personal Account

Question 20.
Loan A/c
Answer:
Personal Account

Question 21.
Computer A/c
Answer:
Real Account

Question 22.
Legal Expenses A/c
Answer:
Nominal Account

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 23.
Fixed Deposit A/c
Answer:
Real Account

Question 24.
Income Receivable A/c
Answer:
Personal Account

Question 25.
Audit Fees A/c
Answer:
Nominal Account

Question 26.
Trademark A/c
Answer:
Real Account

Question 27.
Loss by fire A/c
Answer:
Nominal Account

Question 28.
Motor Car A/c
Answer:
Real Account

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 29.
Income tax A/c
Answer:
Personal Account

Question 30.
GST A/c (Goods and Service Tax)
Answer:
Nominal Account

Question 31.
Siddhivinayak Trust A/c
Answer:
Personal Account

Question 32.
Office Equipment A/c
Answer:
Real Account

Question 33.
The stock of Stationery A/c
Answer:
Real Account

Question 34.
Indian Railways A/c
Answer:
Personal Account

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 35.
Income Received in Advance A/c
Answer:
Personal Account

Question 36.
Dividend on Investment Advance A/c
Answer:
Nominal Account

Question 37.
Discount A/c
Answer:
Nominal Account

Question 38.
Raj & company A/c
Answer:
Personal Account

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 39.
Repairs A/c
Answer:
Nominal Account

Question 40.
Royalty A/c
Answer:
Nominal Account

7. Complete the following Accounting equation table.

Question 1.
Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping 7 Q1
Answer:

Transactions Assets (₹) = Liabilities (₹) + Capital (₹)
1. Started business with Cash ₹ 50,000 50,000 = 00 + 50,000
2. Purchased goods of ₹ 10,000 50,000
(+) 10,000
(-) 10,000
= 00 + 50,000
3. Goods stolen ₹ 1,000 50,000
(-) 1,000
= 00 + 50,000
(-) 1,000
4. Sold goods for Cash ₹ 5,000 49,000
(+) 5,000
(-) 5,000
= 00 + 49,000
5. Loan taken from Bank ₹ 7,000 49,000
(+) 7,000
= 00
7,000
+ 49,000
Total 56,000 = 7,000 + 49,000

8. Give necessary transactions for the following effect of increase and decrease in Assets, Capital, and Liabilities.

Question 1.
Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping 8 Q1
Answer:

1. Sold goods for Cash ₹ 10,000 Increase in Assets
Decrease in Assets
2. Goods costing ₹ 12,000 Sold for ₹ 15,000 Increase in Capital
Decrease in Assets
3. Paid cash ₹ 8,500 to our creditor Mr. Kishor Decrease in Liabilities
Decrease in Assets
4. Goods worth ₹ 7,000 stolen from Godown Decrease in Assets
Decrease in Capital

Practical Problems

Question 1.
Prepare a chart showing Analysis of the following transactions in a Tabular form according to the Traditional Approach:
1. Rajasaheb started the business with cash of ₹ 85,000.
2. Goods Purchased for cash ₹ 5,000.
3. Sold goods on credit worth ₹ 6,000 to Ramesh.
4. Cash deposited into Bank of Maharashtra ₹ 12,000.
5. Interest received ₹ 700 from Radhika.
6. Paid Rent ₹ 2,000 to the landlord.
7. Bought goods on credit from Birajmohan ₹ 7,000.
8. Withdrew cash from bank ₹ 1,000 for office use.
9. Purchased computer ₹ 9,000 for cash.
10. Paid Mobile bill (office) ₹ 500.
11. Sold old Mobile ₹ 2,000.
12. Received Rent ₹ 1,000 from the tenant.
Solution:
Table showing analysis of the transactions is given below (Traditional Approach)
Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping Practical Problems Q1

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 2.
Prepare Chart showing Analysis of the following transaction in a Tabular form according to Modern Approach.
1. Mr. Meghraj started the business with cash of ₹ 30,000.
2. Deposited cash into Bank of India ₹ 2,000.
3. Withdrew cash ₹ 1,000 for personal use.
4. Purchased goods on credit from Nilesh ₹ 2,000.
5. Cash purchases ₹ 3,000.
6. Paid Wages ₹ 400.
7. Purchased a chair for office use ₹ 3,200.
8. Sold goods to Mohan worth ₹ 1,200.
9. Withdrew Cash for Office use ₹ 3,000.
10. Sold old furniture ₹ 9,000.
11. Received Dividend of ₹ 1,000.
12. Paid for Printing bill book ₹ 200.
Solution:
Analysis of transactions by applying rules of Debit and Credit (Modern Approach)
Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping Practical Problems Q2
Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping Practical Problems Q2.1

Question 3.
Give the accounting equation for the following transactions:
1. Mr. Vaibhav started the business with Cash of ₹ 1,00,000.
2. Purchased goods on credit from Rita Stores ₹ 9,000.
3. Purchased Laptop for office use ₹ 10,000.
4. Sold goods to Rina on credit ₹ 12,000.
5. Received Interest ₹ 2,500.
6. Paid Telephone bill ₹ 1,300.
Solution:
Table showing Accounting equations for the transactions.
Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping Practical Problems Q3

Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping

Question 4.
Give the accounting equation for the following transactions.
1. Mr. Swaraj commenced business with a Bank balance of ₹ 1,10,000.
2. Purchased Furniture on credit from S.M Furniture Mart ₹ 25,000.
3. Bought goods on credit from Yuvraj ₹ 15,000.
4. Purchased Machinery ₹ 10,000.
5. Paid Electricity bill ₹ 3,500.
6. Goods destroyed by fire ₹ 1,500.
Solution:
Table showing equation for the transactions.
Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping Practical Problems Q4

Question 5.
Show accounting equation for the following transactions:
1. Rohit started the business with cash of ₹ 50,000.
2. Bought goods on credit from Manoj ₹ 6,000.
3. Cash purchases ₹ 5,000.
4. Paid wages ₹ 3,000 to Casual labour.
5. Sold goods to Santosh ₹ 7,000 on credit.
6. Received Commission ₹ 1,000 from Vaishali.
Solution:
Maharashtra Board 11th BK Textbook Solutions Chapter 2 Meaning and Fundamentals of Double Entry Book-Keeping Practical Problems Q5

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Balbharti Maharashtra State Board 11th Commerce Book Keeping & Accountancy Important Questions Chapter 1 Introduction to Book Keeping and Accountancy Important Questions and Answers.

Maharashtra State Board 11th Commerce BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

1. Answer in One Sentence:

Question 1.
What is Transaction?
Answer:
The exchange of goods or services for money or money’s worth is called a transaction.

Question 2.
What is Cash Discount?
Answer:
The amount which is deducted by the seller from the amount due at the time of the receipt is called cash discount.

Question 3.
What is the entity concept?
Answer:
The business entity concept states that a business has a separate entity and has an independent legal existence distinct from the person who owns it.

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 4.
What is the money measurement concept?
Answer:
The money measurement concept implies that every business transaction must be recorded in a common unit of measurement i.e. in terms of money only.

Question 5.
What is the consistency concept?
Answer:
The consistency concept implies that any policy adopted for accounting should be continuous or consistent throughout the business and it need not be changed generally unless and until circumstances demand.

Question 6.
What is conservatism?
Answer:
The concept of conservatism states that while deciding the policy of the enterprise the businessman has to anticipate no profit but provide for all possible losses.

Question 7.
What is accounting?
Answer:
Accounting is a process of recording, classifying, summarising, analyzing, and interpreting financial transactions and communicating the result thereof to the users of such information.

Question 8.
Name the financial statements prepared by a business.
Answer:
A businessman prepares the financial statements such as income statements i.e. Trading Account and Profit and Loss Account and Position Statement i.e. Balance Sheet.

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 9.
Explain the term ‘Profit’.
Answer:
Excess of revenue income over revenue expenditure is termed as profit.

Question 10.
Explain the term ‘Cost Concept’.
Answer:
The concept according to which assets are recorded in the books of accounts at the price at which they are acquired or purchased is called the cost concept.

2. Give the word term or phrase which can substitute each of the following statements:

Question 1.
Dealings between two persons.
Answer:
Transaction

Question 2.
Business transaction in which cash is not paid or received immediately.
Answer:
Credit Transaction

Question 3.
An allowance is given by the receiver of the cash to the giver of cash at the time of payment.
Answer:
Cash Discount

Question 4.
Liability depends on the happening or not happening a certain event.
Answer:
Contingent Liability

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 5.
Expenditure on fixed assets increases the earning capacity of the business.
Answer:
Capital Expenditure

Question 6.
System in which entry is recorded for cash as well as credit transactions.
Answer:
Accrual System

Question 7.
The concept under which comparison of one accounting period with the other period is possible.
Answer:
Consistency Concept

Question 8.
A science and art of correctly recording in the books of accounts, all those business transactions that result in the transfer of money or money’s worth.
Answer:
Bookkeeping

Question 9.
Exchange of goods and services either for cash or any other goods or services.
Answer:
Transaction

Question 10.
Sale or purchase of goods or services for immediate cash payment.
Answer:
Cash Transaction

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 11.
Sale or purchase of goods or services for a certain value to be receivable or payable in the future.
Answer:
Credit Transaction

Question 12.
Commodity purchased or produced for sale.
Answer:
Goods

Question 13.
Excess of assets over liabilities.
Answer:
Capital

Question 14.
Excess of profit over normal profit.
Answer:
Super Profit

Question 15.
The total amount of goods and services are withdrawn by the proprietor for self-use.
Answer:
Drawings

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 16.
Amount of discount deducted from the invoice price.
Answer:
Trade discount

Question 17.
The reputation of a business is expressed in terms of money.
Answer:
Goodwill

Question 18.
The concept states that assets when purchased should be recorded at cost price.
Answer:
Cost concept

Question 19.
The concept states that business operations will continue forever.
Answer:
Concept of Going Concern

Question 20.
A concept on which a double-entry bookkeeping system is based.
Answer:
Dual Aspect Concept

Question 21.
Rules of conduct are accepted universally to record business transactions.
Answer:
Accounting Principles

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 22.
General ideas which convey certain meanings.
Answer:
Concepts

Question 23.
The general notion or abstract ideas on which accounting is based.
Answer:
Accounting Concept

Question 24.
The accounting concept suggests that a business has a separate identity from its owner.
Answer:
Business Entity Concept

Question 25.
The accounting concept states that monetary transactions are only recorded in the books of accounts.
Answer:
Money Measurement Concept

Question 26.
The money value for which assets are acquired or manufactured.
Answer:
Cost

Question 27.
Proprietor’s contribution to the business.
Answer:
Capital

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 28.
Valuable things are owned by the business.
Answer:
Assets

Question 29.
Period of time for which accounts of the business are prepared.
Answer:
Financial year/Accounting year

Question 30.
Amount received after selling of goods or services.
Answer:
Revenue

Question 31.
Excess of revenue over its cost.
Answer:
Profit

Question 32.
Name the accounting concept on the basis of which the income statement is prepared.
Answer:
Accrual Accounting Concept

3. Select the most appropriate alternatives from those given below and rewrite the statements.

Question 1.
Money value of the reputation of business is known as ____________
(a) Copyright
(b) Goodwill
(c) Patents
(d) Trademark
Answer:
(b) Goodwill

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 2.
Heavy advertising expenditure for launching a new product is called as ____________
(a) Capital expenditure
(b) Revenue Expenditure
(c) Deferred Revenue Expenditure
(d) None of these
Answer:
(c) Deferred Revenue Expenditure

Question 3.
Expenditure incurred on purchase of fixed asset is ____________
(a) Revenue Expenditure
(b) Capital Expenditure
(c) Deferred Revenue Expenditure
(d) None of these
Answer:
(b) Capital Expenditure

Question 4.
Concept which provides a line between present and future is known as ____________
(a) Going Concern Concept
(b) Cost Concept
(c) Accrual Concept
(d) Entity Concept
Answer:
(a) Going Concern Concept

Question 5.
Totalling of Journal or Ledger is called as ____________
(a) Posting
(b) Folio
(c) Casting
(d) Journalising
Answer:
(c) Casting

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 6.
In cash transaction, goods or services are exchanged for ____________
(a) other goods
(b) other services
(c) immediate cash
(d) grains
Answer:
(c) immediate cash

Question 7.
The work of book-keeping is of ____________ nature.
(a) competitive
(b) primary/basic
(c) secondary
(d) none of these
Answer:
(b) primary/basic

Question 8.
Capital is ____________ of the business.
(a) asset
(b) liability
(c) property
(d) goodwill
Answer:
(b) liability

Question 9.
The work of accounting depends upon ____________
(a) book-keeping
(b) cash book
(c) subsidiary books
(d) ledger
Answer:
(a) book-keeping

Question 10.
____________ is the amount invested by the owner of a business.
(a) Cash
(b) Money
(c) Asset
(d) Capital
Answer:
(d) Capital

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 11.
Revenue expenditure is ____________ in nature.
(a) capital
(b) outstanding
(c) recurring
(d) contingent
Answer:
(c) recurring

Question 12.
Amount withdrawn by the owner for his personal expenses is called ____________
(a) Drawings
(b) Personal expenses
(c) Cash
(d) Assets
Answer:
(a) Drawings

Question 13.
Financial statements are a part of ____________
(a) Book keeping
(b) Planning
(c) Accounting
(d) None of these
Answer:
(c) Accounting

Question 14.
A ____________ liability is an uncertain liability.
(a) Long term
(b) Contingent
(c) Current
(d) Fixed
Answer:
(b) Contingent

Question 15.
A Derson who is unable to nay his debts, is called ____________
(a) insolvent
(b) solvent
(c) well to do
(d) poor
Answer:
(a) insolvent

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 16.
According to ____________ concept business shall go on for a long time.
(a) going concerned
(b) consistency
(c) materiality
(d) dual aspects
Answer:
(a) going concerned

Question 17.
According to ____________ concept, every business transaction has two aspects.
(a) going concerned
(b) materiality
(c) business entity
(d) dual aspects
Answer:
(d) dual aspects

Question 18.
According to ____________ concept revenue is recognised when it is earned.
(a) Realisation
(b) Accounting period
(c) Accrual
(d) Matching cost
Answer:
(c) Accrual

Question 19.
According to ____________ convention, while preparing planning anticipate losses.
(a) Materiality
(b) Consistency
(c) Conservatism
(d) disclosure
Answer:
(c) Conservatism

Question 20.
Customs and traditions which guide the accountants to prepare accounting statements are called ____________
(a) Conventions
(b) Principles
(c) Concepts
(d) Procedure
Answer:
(a) Conventions

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 21.
According to ____________ concept, assets are recorded at a price paid to acquire them.
(a) Cost
(b) Money measurement
(c) Entity
(d) Dual aspect
Answer:
(a) Cost

4. State whether the following statements are true or false with reasons:

Question 1.
The trading concern is established for rendering services to society.
Answer:
This statement is False.
The main objective of trading concern is to earn profit. It is for traders’ livelihood, so the trading concern is not established for rendering services to the society.

Question 2.
Book-keeping is an art as well as a science.
Answer:
This statement is True.
Book-keeping is also considered as an art of recording business transactions because the writing of accounts in a specific style and format requires education, knowledge, training, skill, and experience. From another point of view, Book-keeping is a continuous process of collecting, analyzing, classifying, summarising, and recording the different types of business transactions. In brief, bookkeeping may be defined as “A science as well as an art of collecting, analyzing, classifying, summarising and recording all types of business transactions in a significant manner and in terms of money in a separate set of books.”

Question 3.
In Book-keeping & Accountancy non-monetary transactions are also recorded.
Answer:
This statement is False.
Only monetary transactions are recorded in Book-keeping & Accountancy. It is done to find financial results for the purpose of analyzing and interpreting.

Question 4.
Perpetual succession is explained by the concept of the entity.
Answer:
This statement is False.
The concept of entity is different from the perpetual succession. Entity means separate existence of business from the owner whereas perpetual succession means long life and continuation.

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 5.
Accounting is useful only to the owner.
Answer:
This statement is False.
Accounting is not only useful for the owner but also to the suppliers, government, customers, lenders, etc.

Question 6.
Writing of account does not require specific skill and knowledge.
Answer:
This statement is False.
Writing of account requires specific skill and knowledge as book-keeping is an art and science of correctly recording business transactions.

Question 7.
The main objective of Bookkeeping is to keep permanent records of business transactions.
Answer:
This statement is True.
The record of business transactions is prepared for a specific period of time i.e. one year and it is preserved for a long period of time.

Question 8.
In credit transactions, goods or services are purchased for cash only.
Answer:
This statement is False.
In credit transactions, goods and services are purchased and sold for credit only. Credit means post-pone payments for a future date.

Question 9.
In barter transactions, goods or services are purchased for other goods or services.
Answer:
This statement is True.
Barter means exchange of goods or services for goods or services. No money is involved in barter transactions.

Question 10.
In cash transactions, goods or services are purchased for a certain value to be paid in the future.
Answer:
This statement is False.
In a cash transaction, goods or services are purchase or sold for spot payments or receipts. No credit is allowed.

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 11.
Good is a commodity that is purchased for self-use.
Answer:
This statement is False.
Good is a commodity that is purchased for resale purposes. It is an article or a commodity in which businessman deals.

Question 12.
Amount due from other person is known as debt.
Answer:
This statement is True.
Debt is a total sum of money due from a person with whom the business has dealings. Accordingly, a person from whom such debt is due to a business is called the debtor.

Question 13.
Liabilities represent the debts or obligations that a business must receive in terms of money.
Answer:
This statement is False.
Liabilities refer to the total amount of obligations that a business has to pay in the future. Liability means the total amount owed by the business to other persons.

Question 14.
Capital = Liabilities – Assets.
Answer:
This statement is False.
Excess of business assets over business liabilities is called capital.
Capital = Assets – liabilities.

Question 15.
Drawings made by the businessman increase his capital.
Answer:
This statement is False.
Drawing means cash or goods withdrawn by the proprietor for his personal or family use. Drawings made by the businessman decreases his capital.

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 16.
A person whose assets are equal to or greater than liabilities is known as insolvent.
Answer:
This statement is False.
Insolvent means a person whose liabilities are greater than assets is known as ‘Insolvent’.

Question 17.
A person whose assets are less than business liabilities is known as insolvent.
Answer:
This statement is True.
When a person is not able to pay liabilities is called insolvent. Liabilities are greater than assets.

Question 18.
The cost or sacrifice which is incurred to run the business is known as an income.
Answer:
This statement is False.
The cost or sacrifice which is incurred to run the business is known as an expenditure.

Question 19.
Benefits which are given by giver to the receiver is known as discount.
Answer:
This statement is False.
Discount is a concession given by the seller to the buyer. There are two types of discount,

  • Cash discount
  • Trade discount

Question 20.
Posting implies recording a transaction in a journal.
Answer:
This statement is False.
Posting means transferring or recording journal entries from the journal to the respective ledger accounts. Ledger is the main book of accounting.

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 21.
Contingent liabilities can also be called doubtful liabilities.
Answer:
This statement is True.
The contingent liabilities are the liabilities whose occurrence depends upon the happening of a certain event that may or may not take place. So a contingent liabilities can also be called doubtful liabilities.

Question 22.
A sports club is a trading concern.
Answer:
This statement is False.
The sports club is a nontrading concern as they do not work for profit-making. They work for the promotion of sports.

Question 23.
A cash discount is an incentive allowed for the speedy recovery of income.
Answer:
This statement is True.
A cash discount is given by the creditor or seller to the debtor or buyer to induce him to make prompt payment. It is given at the time of cash payment.

Question 24.
Excess of revenue over expenses is called loss.
Answer:
This statement is False.
Excess of revenue over expenses is called profit. Your income is less and expenditures are less so you get profit.
Income ₹ 50,000 – Expenses ₹ 35,000 = Profit is ₹ 15,000.

Question 25.
Excess of liabilities over assets represents the solvency of a business.
Answer:
This statement is False.
Excess of liabilities over assets represents insolvency of business. A trader cannot pay his debts as liabilities are greater than his assets.
Liabilities ₹ 1,50,000 Assets ₹ 80,000.
₹ 1,50,000 – ₹ 80,000 = ₹ 70,000 deficiency.

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 26.
A business can not run without bookkeeping.
Answer:
This statement is False.
Book-keeping is a recording of business financial transactions which is useful to prepare ledger, trial balance, financial statements. All the above are useful to take decisions, planning, liabilities, and assets so a businessman cannot run his business without book-keeping.

Question 27.
Bookkeeping is necessary only for organizing with profit objectives.
Answer:
This statement is False.
Books of accounts are maintained by trading and non-trading concerns. Non-trading concerns do not earn any profits so book-keeping is not necessary only with the objective of profit.

Question 28.
The figures of profit and net worth are disclosed by books of accounts.
Answer:
This statement is True.
The purpose of preparing books of accounts is to know financial details of organization from journal ledger, trial balance, final accounts proprietor to get an idea of his financial status. The purpose of financial books of accounts is to get profit and net worth etc.

Question 29.
Financial statements are an effective weapon in the hands of management.
Answer:
This statement is True.
With help of financial statements, management does planning, decision-making for the future. The past record gives ideas to the management to improve financial decisions like more profit better financial conditions etc. so financial statements are effective weapons in the hands of management.

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 30.
Irregularities, frauds, and misappropriations can be detected only because of books accounts.
Answer:
This statement is False.
Irregularities frauds and misappropriations can be detected by auditing. Continuous and periodical auditing will detect the irregularities frauds and misappropriations which is done by a chartered accountant.

5. Do you agree or disagree with the following statements:

Question 1.
Goodwill is a tangible asset.
Answer:
Disagree

Question 2.
For income tax purposes an accounting year starts on 1st January and ends on 31st March.
Answer:
Disagree

Question 3.
Earning profits is an aim of Not for Profit Concern.
Answer:
Disagree

Question 4.
Trade discount is recorded in the books of accounts.
Answer:
Disagree

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 5.
Wages paid on installation of machinery are revenue expenditures.
Answer:
Disagree

Question 6.
An amount that is not recoverable from debtors is called bad debt.
Answer:
Agree

Question 7.
The double-entry book-keeping system is invented in India.
Answer:
Disagree

Question 8.
Book-keeping does not have any rules and regulations for recording business transactions.
Answer:
Disagree

Question 9.
The owner of the business does not have any utility of book-keeping.
Answer:
Disagree

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 10.
Bookkeeping cannot be used as financial evidence in a court of law.
Answer:
Disagree

Question 11.
It is not possible for management to plan and take decisions in business with help of book-keeping and accountancy.
Answer:
Disagree

Question 12.
Cash-withdrawn by the proprietor from his business for personal use is called capital.
Answer:
Disagree

Question 13.
A person who has to pay the business for getting goods and services on credit is known as the debtor.
Answer:
Agree

Question 14.
Trade discount is not recorded in the books of accounts.
Answer:
Agree

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 15.
Purchase of goods is revenue expenditure.
Answer:
Agree

Question 16.
Heavy expenditure on advertising is deferred revenue expenditure.
Answer:
Agree

Question 17.
A solvent person’s assets are more than his liabilities.
Answer:
Agree

Question 18.
Net Worth = Total Assets – Outsiders Liabilities
Answer:
Agree

Question 19.
Conservatism’s concept means to play safe.
Answer:
Agree

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 20.
The dual aspect means every transaction has two effects i.e. debit and credit.
Answer:
Agree

6. Complete the following sentences:

Question 1.
In barter transaction goods are exchange for ____________
Answer:
Goods

Question 2.
Asset is ____________ of the business.
Answer:
property

Question 3.
Capital expenditures are ____________ in nature.
Answer:
Non Recurring

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 4.
A ____________ liability is an uncertain liability.
Answer:
Contingent

Question 5.
A person whose liabilities are more than his assets is known as ____________
Answer:
Insolvent

Question 6.
An article or a commodity which is purchase for resale in business is called ____________
Answer:
Goods

Question 7.
Customs and traditions which guide the accountants to prepare accounting systems are called ____________
Answer:
Conventions

Question 8.
Discount given by the creditor to the debtor on payment of cash is called ____________
Answer:
Cash discount

Question 9.
For tax purpose an year starts on 1st April and ends on 31st March is called ____________
Answer:
Accounting year

Question 10.
An institution which provides standard of accounting in India called ____________
Answer:
Institute of Chartered Accountants of India

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 11.
Which accounting standard is followed for depreciation on fixed assets ____________
Answer:
AS-6

Question 12.
Brief explanation of an entry is called as ____________
Answer:
Narration

Question 13.
Businessman open ____________ type of bank account.
Answer:
Current

Question 14.
The main objective of business concern ____________
Answer:
making profits

Question 15.
Assets which are held in the business for a period of less than one year ____________
Answer:
Current Assets

Question 16.
10 years loan taken from bank by organisation is ____________ term loan.
Answer:
long

Question 17.
Heavy expenses paid on formation of an organisation is known as ____________ expenditure.
Answer:
Deferred Revenue

Maharashtra Board 11th BK Important Questions Chapter 1 Introduction to Book Keeping and Accountancy

Question 18.
Dividend received on shares is ____________ income.
Answer:
Revenue

Question 19.
Loss on sale of old machine is ____________ loss.
Answer:
Capital

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

Balbharti Maharashtra State Board 12th Chemistry Important Questions Chapter 13 Amines Important Questions and Answers.

Maharashtra State Board 12th Chemistry Important Questions Chapter 13 Amines

Question 1.
What are amines?
Answer:
Amines : The alkyl or aryl derivatives of ammonia in which one, two or all the three hydrogen atoms attached to nitrogen are replaced by same or different alkyl or aryl groups are called amines. OR Amines are nitrogen-containing organic compounds having basic character.

Example : methyl amine : CH3 – NH2
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 1

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

Question 2.
Classify the following amines as primary, secondary and tertiary.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 7

Question 3.
Mention the functional group in :
(1) Primary amine
(2) Secondary amine
(3) Tertiary amine.
Answer:
(1) A primary amine has a functional group – NH2 (amino group).
Example : ethylamine, C2H5 – NH2
(2) A secondary amine has a functional group – NH – (imino group).
Example : Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 8
(3) A tertiary amine has a functional group Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 9 (tertiary nitrogen atom)

Example :
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 10

Question 4.
Write common and IUPAC names of following compounds :
Answer:
(A) Primary amines :
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 14
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 15
(B) Secondary amine :
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 16
(C) Tertiary Aimines :
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 17.

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

Question 5.
Give the structures of the following :
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 22

Question 6.
Give the IUPAC names of the following amines :
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 23

Question 7.
Write the IUPAC names of the following amines :
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 24

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

Question 8.
Give the structures and IUPAC names of the following amines :
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 25

Question 9.
Classify the following amines as primary, secondary and tertiary and write the IUPAC names.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 26

Question 10.
Write the structures and classify the following amines as primary, secondary, tertiary amines.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 27

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

Question 11.
Write the common and IUPAC name of a tertiary amine in which one methyl, one ethyl and one w-propyl group is attached to nitrogen.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 28

Question 12.
How will you prepare ethanamine from ethyl iodide?
Answer:
When ethyl iodide is heated with excess of alcoholic ammonia, under pressure at 373 K ethanamine is obtained as a major product.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 29

Question 13.
How is a nitroalkane converted to a primary amine?
OR
What is the action of LiAlH4/ether on (i) 1-Nitropropane (ii) 2-MethyI-l-nitropropane?
Answer:
When a nitroalkane is refluxed with tin (or iron) and concentrated HCl it gives corresponding primary amine.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 33
For example, (1) nitromethane on reduction by refluxing with Sn and concentrated HCl gives methylamine.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 34

(2) 1-Nitropropane on reduction with Sn and concentrated HCl gives propan-1-amine.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 35

(3) Niirobenzcnc on reducion with tin and concentrated HCI or by using H2/Pd in ethanol gives anilinc.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 36

(4) When nitropropane is reduced in the presence of LiAlH4 in ether, n-propyl amine is obtained.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 37

(5) When 2-methyl-1-nitropropane is reduced in the presence of LiAlH4 in ether, 2-methyl propan-1-amine is obtained.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 38

Question 14.
How will you prepare aniline from nitrobenzene?
OR
How is aniline prepared from nitro compounds?
Answer:
Nitrobenzene is reduced to aniline by passing hydrogen gas in the presence of finely divided nickel, palladium or platinum.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 39

Question 15.
Identify the compounds A and B in the following reactions
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 40
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 41

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

Question 16.
How will you obtain a primary amine from an alkyl cyanide (nitrile)?
OR
Write a short note on Mendius reduction.
Answer:
Alkyl cyanides (nitriles) on reduction by sodium and ethyl alcohol form corresponding primary amines. This reaction is called Mendius reduction.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 42
For example; propionitrile on reduction by sodium and ethanol gives n-propyl amine (Propan-1-amine).
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 43
Methyl cyanide or acetonitrile on reduction by sodium and ethanol gives ethanaminc.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 44

Question 17.
How will you prepare ethylamine from acetonitrile?
OR
How is ethanamine prepared from methyl cyanide?
OR
What is the action of a mixture of sodium and alcohol on acetonitrile?
Answer:
Methyl cyanide or acetonitrile on reduction by sodium and ethyl alcohol forms ethanamine. The reaction is called Mendius reduction.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 45

Question 18.
How will convert phenyl acetonitrile to β-phenylethylamine?
Answer:
When phenyl acetonitrile is reduced in the presence of sodium and ethanol, β-phenyl ethylamine is obtained.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 46

Question 19.
How will you obtain primary amine from an acid amide?
Answer:
Acid amides on reduction with lithium aluminium hydride or sodium, ethanol form corresponding primary amines.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 50
For example : Acetamide on reduction with lithium aluminium hydride or sodium, ethanol gives ethylamines.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 51

Question 20.
Explain Hoffmann degradation of amides.
Write a note on Hoffmann bromamide degradation.
Answer:
The conversion of amides into amines in the presence of bromine and alkali is known as Hoffmann degradation of amides. An important characteristic of this reaction is that an amine with one carbon less than those in the amide is formed. Thus, decreasing the length of carbon chain. This reaction is an example of molecular rearrangement and involves the migration of an alkyl or aryl group from the carbonyl carbon to the adjacent nitrogen atom. For example,

(1) When propanamide is treated with bromine and aqueous or alcoholic sodium hydroxide, ethanamine is obtained which has one carbon atom less.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 53
(2) When benzamide is treated with bromine and aqueous or alcoholic sodium hydroxide, aniline is obtained.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 54

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

Question 21.
How will you obtain methyl amine from acetamide?
Answer:
When acetamide is treated with bromine and aq or alcoholic solution of KOH, methyl amine is obtained, which has one cabon atom less.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 55

Question 22.
How will you convert the following?

(1) Ethyl bromide to ethylamine.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 60

(2) Propionitrile to n-propyl amine.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 61

(3) Acetonitrile to ethylamine.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 62

(4) Phenyl acetonitrile to β-phenylethyl amine.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 63

(5) Acetamide to ethylamine.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 64

(6) Nitropropane to propan-l-amine.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 65

(7) Nitrobenzene to Aniline.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 66

(8) Benzamide to aniline.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 67

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

Question 23.
How will you prepare propan-l-amine from (1) butane nitrile (2) 1-nitropropane (3) propanamide (4) butanamide?
Answer:
(1) From butane nitrile :
When butane nitrile is reduced by sodium and ethanol, it gives propan-l-amine.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 68

(2) From 1-nitropropane :
When 1-nitropropane is reduced in the presence of tin and cone, hydrochloric acid, propan-l-amine is obtained.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 69

(3) From propanamide :
When propanamide is reduced in the presence of lithium aluminium hydride, propan-l-amine is obtained.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 70

(4) From butanamide :
When butanamide is treated with bromine and aq. KOH, propan-l-amine is obtained.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 71

Question 24.
Write a reaction to, convert acetic acid into methyl amine.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 78

Question 25.
Primary and secondary amines have boiling points higher than the tertiary amines. Explain why?
Answer:
(1) The N – H bond in amines is polar in nature because of electronegativities of nitrogen (3.0) and hydrogen (2.1) are different.
(2) Due to the polar nature of N – H bond, primary and secondary have strong intermolecular hydrogen bonding. Tertiary amines do not have intermolecular hydrogen bonding as there is no hydrogen atom on nitrogen of tertiary amine. Thus, intermolecular forces of attraction are strongest in primary and secondary amines and weakest in to tertiary amines. Hence, primary and secondary amines have boiling points higher than the tertiary amines.

Question 26.
Amines have boiling points higher than the hydrocarbon but lower than the alcohols of comparable masses. Explain, why?
Answer:
Amines are polar than alkanes but less polar than alcohols. Primary and secondary amines form intermolecular hydrogen bonds. This hydrogen bonding leads to an associated structure. The association is more in primary amines than that in secondary amines as there are two hydrogen atoms attached to the nitrogen atom. However, tertiary amines do not form intermolecular hydrogen bonds because they do not contain any hydrogen atoms attached to the nitrogen atom. Hence, amines have higher boiling points than the hydrocarbons but lower boiling points than the alcohols of comparable masses.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 79

Compound Molar mass Boiling points (K)
nC2H5CH(CH3)2 72 300
nC4H9NH2 73 350.8
nC4H9OH 74 391

Question 27.
Arrange the following compounds in the decreasing order of their solubility in water.
(a) Ethyl amine, diethyl amine and triethyl amine.
Answer:
Diethyl amine > triethyl amine > ethyl amine
(The reason that ethyl group has greater +1 effect than methyl group)

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

(b) Ethyl amine, n-propyl amine and n-butyl amine.
Answer: n-butyl amine < n-propyl amine < ethyl amine

(c) n-Butane, n -butyl alcohol and n-butyl amine
Answer:
n-butyl alcohol < n-butyl amine < n-butane

Question 28.
Arrange the following compounds in the decreasing order of their boiling points.
(a) Ethane, ethyl amine and ethyl alcohol.
Answer:
Ethyl alcohol < ethyl amine < ethane

(b) Ethyl amine, n-propyl amine and n-butyl amine.
Answer:
n-butyl amine < n-propyl amine < ethyl amine

(c) n-propyl amine, ethyl methyl amine and trimethyl amine.
Answer:
n-propyl amine < ethyl methyl amine < trimethyl amine.

(d) Ethyl alcohol, dimethyl amine and ethyl amine.
Answer:
Ethyl alcohol < ethyl amine < dimethyl amine.

Question 29.
Explain the basic nature of amines with a suitable examples.
OR
Explain why amines are basic.

Question 38.
Tertiary amine (R3N) or 3° amine is weaker base than secondary amine R2NH or 2° amine. Explain.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 81
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 82
The increase in basic strength from 1° amine to 2° amine is explained on the basis of increased stabilization of conjugate acids by +1 effect of the increased number of the alkyl group. However, decreased basic strength of 3° implies that the conjugate acid of 3° amine is less stabilized and is weak base though the +1 effect of three alkyl groups in R3NH is large.

R2NH is best stabilized by solvation while the stabilization by solvation is very poor in R3NH. Hence (R3N) or tertiary amine or 3° amine is weaker base than secondary amine (R2NH) or 2° amine.

Question 30.
Primary or aliphatic amine is a stronger base than ammonia. Explain.
Answer:
(1) The alkyl group in primary amines has +I effect i.e. (electron releasing).
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 83
The alkyl group tends to increase the electron density on the nitrogen atom. As a result, amines can donate the lone pair of electrons on nitrogen more easily than ammonia.

(2) The amine being a base, can donate a pair of electrons to an acid. The alkyl group with +I effect will disperse the positive charge on the cation more than ammonia.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 84

Due to +I effect of alkyl group cation formed by primary amine is more stable compared to cation formed from ammonia. Also it is seen that observed increasing basic strength from ammonia to primary amine is explained on the basis of increased stabilization of conjugate acids by +I effect for the presence of alkyl (R) groups. Hence, primary or aliphatic amine is a stronger base than ammonia.

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

Question 31.
Aniline is less basic than ammonia. Explain.
Answer:
The less basic character of aniline can be explained on the basis of resonance shown by aniline.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 85

Due to resonance, the nitrogen atom of amino group in aniline acquires a positive charge, hence, lone pair of electrons is less available for protonation as compared to that of ammonia. Aniline is resonance stabilized by five resonance structures. On the other hand, aniline in aqueous medium, accepts a proton does not have lone pair of electrons on nitrogen to produce a very low concentration of anilium ion and anilium ion shows only two resonance structures and therefore less stabilized than anline.

Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 86

Thus, aniline is more stable than anilium ion. Hence aniline accepts proton less readily or less basic in nature than ammonia.

Question 32.
Explain the order of basicity in ammonia and aliphatic amines.
Answer:
Since nitrogen atom in ammonia molecule has a lone pair of electrons, it is a Lewis base.
Greater the availability of an electron pair, more is the basic character.

Since alkyl group (R -) is an electron releasing group with (+I) inductive effect, alkyl amines act as a stronger base than ammonia.

The decreasing order of basicity is –
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 87

The availability of a lone pair of electrons on a nitrogen atom in amines is influenced by steric factor due to crowding of alkyl groups which affects solvation along with inductive effect of alkyl groups.

Due to high energy of solvation of \(\mathrm{NH}_{4}^{+}\) ions, they acquire higher stability in aqueous solutions.

The presence of alkyl groups in secondary and tertiary amines, due to steric hindrance decrease the solvation energy.

This effect is more in tertiary amines making the tertiary ammonium ions (R3NH+) unstable as compared to secondary ammonium ion (R2N+H2).
Hence the cumulative effect on the order of basicity of amines is, secondary amine > primary amine > tertiary amine > ammonia (NH3).

Question 33.
Arrange the following amines in the decreasing order of their basic nature.
(a) Aniline, propan-l-amine and N-methylethanamine.
Answer:
N-methylethanamine < propan-l-amine < aniline

(b) Benzene-1, 4-diamine, ammonia and 4-aminobenzoic acid.
Answer:
Ammonia < benzene-1, 4-diamine < 4-aminobenzoic acid

(c) N-Methylaniline, phenylmethylamine and N-phenylaniline.
Answer:
N-Methylaniline < N-phenylaniline < phenylmethylamine

Question 34.
Arrange the following amines in the increasing order of their pKb values.
(a) Aniline, N-methylaniline and cyclohexalamine.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 88

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

(b) Phenylmethylamine, 2-aminotoluene and 2-fluoroaniline.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 89

(c) Aniline, 4-methoxyaniline and 4-nitroaniline.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 90

Question 35.
Arrange the following compounds in the decreasing order of their basic nature in the gaseous phase.
Ammonia, N-methylhexanamine, propan-1-amine and N, N-dimethylethanolamine.
Answer:
Propan-1-amine < N-methylethanamine < N,N-dimethylmethanamine < ammonia

Question 36.
Explain laboratory test for amines.
Answer:
(1) All amines are basic compounds. Aqueous solution of water soluble amines turns red litmus blue.

(2) When water insoluble amine is dissolved in aqueous HCl, forms water soluble substituted ammonium chloride, further a substituted ammonium chloride on reaction with excess aqueous NaOH regenerates the original insoluble amine.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 91

(3) Diazotization reaction/ Orange dye test: In a sample of aromatic primary amine, 1-2 mL of cone. HCl is added. The aqueous solution of NaNO2 is added with cooling. This solution is transfered to a test tube containing solution of β naphthol in NaOH. Formation of orange dye indicates presence of aromatic primary amino group. (It may be noted that temperature of all the solutions and reaction mixtures is maintained near 0 °C throughout the reaction).

Question 37.
Explain Hofmann’s exhaustive alkylation.
OR
Explain Hofmann’s exhaustive methylation of amines.
Answer:
Hofmann’s Exhaustive alkylation : When a primary amine is heated with excess of primary alkyl halide it gives a mixture of secondary amine, tertiary amine along with tetraalkylammonium halide
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 92

If excess of alkyl halide is used, tetraalkyl ammonium halide is obtained as major product. The reaction is known as exhaustive alkylation of amines.

Hofmann’s Exhaustive Methylation : The process of converting a primary, secondary or tertiary amine into quaternary ammonium halide by heating them with excess of methyl iodide, is called exhaustive methylation or Hoffmann’s exhaustive methylation.

Thus when methyl amine is heated with excess of methyl iodide it forms dimethylamine (secondary amine), then trimethylamine (a tertiary amine) and finally of quaternary ammonium iodide. The reaction is carried out in the presence of mild base NaHCO3, to neutralize the large quantity of HI formed.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 93

Question 38.
Predict the products of exhaustive methylation of following compounds.
(1) Ethylamine.
Answer:
A primary amine, ethylamine (CH3 – CH2 – NH2) on exhaustive methylation, i.e., on heating with excess methyl iodide, forms secondary amine, tertiary amine and finally a quaternary ammonium salt, ethyl-trimethyl ammonium iodide.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 97

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

(2) Benzylamine.
Answer:
Benzylamine C6H5CH2NH2 on exhaustive methylation i.e., on heating with excess methyl iodide forms benzylmethyl amine, benzyldimethyl ammonium chloride and finally benzyltrimethyl ammonium iodide.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 98

Question 39.
Explain Hofmann elimination.
OR
Write a note on Hoffmann elimination.
Answer:
When tetra alkyl ammonium halide is heated with moist silver hydroxide, a quaternary ammonium hydroxide is obtained. Quaternary ammonium hydroxides are deliquescent crystalline solids and are basic in nature. Quaternary ammonium hydroxides on strong heating undergo ^-elimination to give tertiaryamine, alkenes and water, the reaction is called Hofmann elimination. The major product is least substituted alkene.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 99

Question 40.
Write the bond line formula of the alkene which is obtained as major product from the following amines, on heating with excess of methyl iodide followed by strong heating with moist silver oxide.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 102
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 103

Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 104
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 105

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 106
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 107

Question 41.
Compound X with a molecular formula C5H13N did not react with nitrous acid, but reacted with one mole of CH3I to form a salt. What is the structure of X?
Answer:
The structure of compound X is Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 108 ethyl-N-methylethanamine since compound X is tertiary amine. It reacts with one mole of CH3I to give a quaternary ammonium salt.

Question 42.
What is the action of acetyl chloride on :
(1) ethyl amine (ethanamine)
(2) diethyl amine (N-Ethylethanamine)
(3) triethyl amine?
OR
Write a short note on acylation of amines.
Answer:
The reaction of amines with acetyl chloride is called acetylation of amines.

(1) Acetyl chloride on reaction with ethylamine forms monoacetyl derivative, N-ethylacetamide (or N-acetyl ethylamine).
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 109
(2) Diethyl amine on reaction with acetyl chloride forms N-acetyl dimethylamine.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 110
(3) Triethyl amine, being a tertiary amine does not have H atom attached to nitrogen of amine, hence it does not react with acetyl chloride.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 111

Question 43.
What is the action of acetic anhydride on aniline?
Answer:
Aniline on reaction with acetic anhydride forms N-phenyl acetamide.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 116

Question 44.
What is the action of benzoyl chloride on ethanamine?
Answer:
When benzoyl chloride is treated with ethanamine, N-ethyl benzamide is obtained.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 117

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

Question 45.
What is the action of nitrous acid on ethylamine?
Answer:
Ethyl amine on reaction with nitrous acid in cold forms aliphatic diazonium salt, (unstable intermediate), which decomposes immediately by reaction with solvent water to produce ethyl alcohol and nitrogen gas.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 123

Question 46.
What is the action of nitrous acid on aniline?
Answer:
Aniline reacts with nitrous acid in cold to form diazonium salt which has reasonable solubility at 273 K
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 124

Question 47.
How is benzenediazon|um chloride prepared?
Answer:
Benzenediazonium chloride is prepared by the action of nitrous acid on aniline at 273-278 K. Nitrous acid being unstable, is prepared in situ by the reaction between sodium nitrite and dilute hydrochloric acid.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 125

Question 48.
Write resonance stabilized structures of aryl diazonium salt.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 126

Question 49.
Write a note on Sandmeyer’s reaction.
OR
How is aryl chloride or aryl bromide or aryl cyanide prepared from diazonium salt?
Answer:
[Replacement by Cl, Br and -CN : Sandmeyer reaction.] Freshly prepared aromatic diazonium salt on reaction with cuprous chloride gives aryl chloride, on reaction with cuprous bromide gives aryl bromide and on reaction with cuprous cyanide give aryl cyanide. The reaction in which copper (I) salts are used to replace nitrogen in diazonium salt is called Sandmeyer reaction.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 128

Question 50.
How is aryl chloride or aryl bromide prepared by Gattermann reactions?
Answer:
The aryl chloride or bromides can also be prepared by Gattermann reactions in which diazonium salt reacts with
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 129

Question 51.
How is aryl iodide obtained from diazonium salt?
Answer:
When diazonium salt is warmed with potassium iodide, aryl iodide is obtained.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 130

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

Question 52.
Explain the reduction of arene diazonium salt?
OR
How is arene obtained from arene diazonium salt?
OR
What is the action of benzene diazonium chloride on ethanol?
Answer:
Arene diazonium salt on treatment with mild reducing agents like phosphinic acid (hypophosphoric acid) or ethanol, arene is obtained.

Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 131Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 132

Question 53.
How is phenol obtained from arene diazonium salt?
Answer:
When arene diazonium salt is slowly added to a large volume of boiling dilute sulphuric acid, phenol is obtained,
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 133

Question 54.
How is aryl fluoride obtained from diazonium salt?
Answer:
When fluoroboric acid is treated with the solution of diazonium salt, a precipitate of diazonium fluoroborate is obtained, which is filtered and dried. When dry diazonium fluoroborate is heated, it decomposes to give aryl fluoride. This reaction is called Balz-Schiemann reaction.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 134

Question 55.
How is nitrobenzene obtained from benzene diazonium fluoroborate?
Answer:
When benzene diazonium fluoroborate is heated with aqueous solution of sodium nitrite in the presence of copper powder, nitrobenzene is obtained.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 135
Benzene diazonium fluorobate can be obtained by reaction of benzene diazonium chloride with HBF4.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 136

Question 56.
What is meant by a coupling reaction? Explain with suitable examples.
OR
What is the action of benzene diazonium chloride on (a) phenol in alkaline medium (b) aniline?
OR
Write a note on the coupling reaction.
Answer:
Diazonium salts react with certain aromatic compounds having an electron-rich group (e.g.-OH, – NH2, etc.) to form azo compounds. This reaction is an electrophilic substitution and is called coupling reaction. Azo compounds are brightly coloured and are used as dyes and indicators. Coupling reaction is an electrophilic substitution reaction. Benzene diazonium chloride reacts with alkaline solution of phenol to give p-hydroxy azo benzene (orange dye).
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 139
Benzene diazonium chloride reacts with aniline in mild alkaline medium to give p-aminobenzene (yellow dye).
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 140

Question 57.
What is the action of p-toluene sulphonyl chloride on ethyl amine and diethyl amine?
Answer:
(1) When ethyl amine is treated with p-toluene sulphonyl chloride, N-ethyl p-toluene sulphonamide is obtained.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 144
(2) When diethyl amine is treated with p-toluene suiphonyl chloride. N.N-dicthyl p-toluene suiphonyl amide is formed.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 145

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

Question 58.
How will you distinguish between :
(1) Ethylamine, diethyl amine and triethyl amine by using (i) nitrous acid (ii) Hinsberg’s reagent.
(2) Diethyl amine and triethyl amine by using acetic anhydride.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 150
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 151

Question 59.
Give a chemical test to distinguish between following pairs of compounds.
(i) Ethylamine and diethyl amine :
Answer:
Ethylamine (C2H5NH2) is a primary amine while diethyl amine ( (C2H5)2NH) is a secondary amine. So the two can be distinguished by the following test.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 152

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

(ii) Ethyl amine and aniline :
Answer:
Ethylamine is an aliphatic amine, while aniline is an aromatic amine. So the two can be distinguished by the following test :
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 153

(iii) Aniline and benzyl amine :
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 154

(iv) Aniline and N-ethylaniline :
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 155

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

Question 60.
Compound ‘X’ with a molecular formula C4H11N did not react with Hinsberg’s reagent, but reacted with one mole of CH3I to form a salt. What is the structure of ‘X’?
Answer:
The structure of compound ‘X’ is :
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 156
Since the compound ‘X’ does not react with NaN02 and HC1 i.e. nitrous acid (HO – N = O), it must be a tertiary amine.

The tertiary amine reacts with one mole of CH3I to give a quaternary ammonium salt.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 157

Question 74.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 158
p-(dimethylamino) azobenzene is yellow dye which was formerly used as a colouring agent in margarine. Write the structures of the reactants used in the preparation of this dye.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 159

Question 61.
Convert 3-Methyl aniline into 3-nitrotoluene.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 160

Question 62.
How will you bring about following conversions?
(1) N.Methyl aniline into N-methyl benzanilide.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 161

(2) 1.4-Dichlorobutane Into hexane-1,6-diamlne.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 162

(3) Benzene into 3-bromo aniline.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 163

(4) Chlorobenzene into 4-chioroanilinc.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 164

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

(5) 11enaniide into toluene.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 165

Question 63.
What is the action of aqueous bromine on aniline?
Answer:
Action of aqueous bromine on aniline : When aniline is treated with bromine water at room temperature, a white precipitate of 2, 4, 6-tri bromoaniline is obtained.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 166

Question 64.
Explain the action of cone, nitric acid (nitrating mixture) on aniline.
Answer:
When aniline is warmed with a mixture of cone, nitric acid and cone, sulphuric acid (a nitrating mixture), a mixture of ortho, meta and para nitroaniline is obtained.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 169

Question 65.
What is the action of acetic anhydride on aniline?
Answer:
When aniline is heated with acetic anhydride, an acetanilide is obtained.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 170

Question 66.
How will you convert aniline to p-nltroanhline? (major product)
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 171

Question 67.
What is the action of cone, sulphuric acid on aniline?
Answer:
Aniline on treatment with cold sulphuric acid forms anilium hydrogen sulphate which on heating with sulphuric acid at 453 K-475 K gives sulphanilic acid, (p-aminobenzene sulphonic acid) as major product.Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 172
Sulphanilic acid exists as a salt; called dipolar ion or zwitter ion. It is produced by the reaction between an acidic group and a basic group present in the same molecule.

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

Question 68.
How will you convert the following?
(1) Ethylamine to ethyl alcohol.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 173

(2) N-Methyl aniline to N-Nitroso-N-methyl aniline.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 174

(3) Diethylamine to N-nitrosodiethylamine
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 175

(4) Triethylamine to triethyl ammonium nitrite.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 176

(5) Ethyl amine to N-ethylacetamide.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 177

(6) Diethyl amine to N-acetyl diethylamine.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 178

(7) Aniline to acetanilide.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 179

(8) Aniline to N-ethyl henzamide.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 180

(9) Ethylamine to ethyl isocyanide.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 181

(10) Aniline to phenyl isocyanide.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 182

(11) Aniline to 2,4,6-tribromoaniline.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 183

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

Question 69.
Give a plausible explanation for each of the following statements :
(1) Ethylamine is soluble in water whereas aniline is not.
Answer:
Ethylamine is soluble in water due to intermolecular hydrogen bonding resulting in the formation of C2H5NH3 ion. Whereas in anline the hydrogen bonding with water is negligible due to the phenyl group (C6H5) is bulky and has -I effect. Therefore, aniline is nearly insoluble in water.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 184

(2) Butan-1-ol is more soluble in water than butani-amine.
Answer:
Rutan- l-al is more soluble in watcr duc to intermoiccular hydrogen bonding. In alcohols, hydrogen bonding is through oxygen atoms. WIereas hutani-amine is less soluble in water due to the larger hydrocarbon part is hydrophobic in nature. Hence, butan-l-ol is more soluble in water than butani-amine.

(3) Butan-1-amlne has higher boiling point than N-ethylethanamine.
Answer:
Due to the presence of two H-atoms on N-atom in butait- I -amine, they undergo extensive intermolecular H-bonding while in N-cthylethanamine due to the presence of one-H atom on the N-atom, they undergo least intermolecular H-bonding. Hence, butan- l-amine has higher boiling point than-N-ethyl ethanamine.

(4) AnIline Is less basic than ethyl afine.
Answer:
Aniline (Kb4-2 x 10-10) is less basic than ethyl amine (Kb5.1 x 10-4). This is because -I effect of phenyl group in aniline as compared to + 1 effect of ethyl group in ethyl amine.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 185
Due to resonance, the lone pair of electrons on the nitrogen atom gets delocalized over the benzene ring and thus less available for protonation. On the other hand, in ethyl anine, delocalization of the lone pair of electrons on the nitrogen atom by resonance is not possible. Further more, the electron density on the nitrogen atom is increased by +1 effect of the ethyl group. Hence, aniline is less basic than ethyl amine.

(5) pKb value of diethyl amine is less than that of ethyl amine.
Answer:
The basic strength of amines is expressed in terms of pKb values. Smaller is the value of pKb more basic is the amine. The pKb value of ethyl amine is 3.29 and that of diethyl amine is 3.00. Therefore, diethyl amine is more basic than ethyl amine.

(6) Aniline cannot be prepared by Gabriel phthalimide synthesis.
Answer:
In Gabriel-phthalimide synthesis of aniline, potassium phthalimide requires the treatment with chlorobenzene or bromobenzene. Since aryl halides do not undergo nucleophilic substitution reaction. Therefore, chlorobenzene or bromobenzene does not react with potassium phthalimide to give N-phenylphthalimide and hence aniline cannot be prepared by Gabriel phthalimide synthesis.

(7) Gabriel phthalimide synthesis is preferred for the preparation of aliphatic primary amines.
Answer:
In aromatic amines, the lone pair of electrons on the N-atom is delocalized over the benzene ring. As a result electron density on the nitrogen atom decreases. Whereas in aliphatic primary amines, due to +1 effect of alkyl group, electron density on nitrogen atom increases. As the pKh value of aliphatic amines is more than that of aromatic amines, aromatic amines are less basic than primary aliphatic amines. Hence, Gabriel phthalimide synthesis is preferred for the preparation of aliphatic amines.

(8) Arere diazonium salts are relatively more stable than alkyl diazonium salts.
Answer:
Arene diazonium salts are stable due to the dispersal of the positive charge over the benzene ring as shown below :
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 186
Alkane diazonium salts are unstable due to their tendency to eliminate a stable molecule of nitrogen to form carbocation. Aromatic diazonium salts have much lower tendency to remove nitrogen than aliphatic diazonium salts. Hence, arene diazonium salts are relatively more stable than alkyl diazonium salts.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 187

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

(9) Tertiary amines cannot be acylated.
Answer:
Tertiary amines do not react with acetic anhydride or acetyl chloride i.e. they can be acylated because they do not contain a H-atom on the N-atom.

(10) Besides the ortho and para derivatives, considerable amount of meta derivatives is also formed during nitration of aniline.
OR
Although amino group is o- and p-directing in electrophilic substitution reactions, aniline on nitration gives substantial amount of m-nitroaniline.
Answer:
In aromatic amines, -NH2 is an electron releasing or activating group. It activates the ortho and para positions in the benzene ring towards electrophilic substitution. When aniline is treated with nitrating mixture (cone. HNO3+ cone. H2SO4), a mixture of ortho and para nitroaniline is obtained. However, a substantial amount of m-nitroaniline is also formed. Aniline being a base gets protonated in acidic medium to form anilium cation, which deactivates the ring and the substitution takes place at the meta position.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 188

Question 70.
How will you convert :
(1) Aniline into benzyl alcohol.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 191

(2) Aniline into 4-bromoaniline.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 192

(3) Aniline into 1,3,5-tribromo benzene.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 193

(4) Aniline into 2,4,6-tribromo fluoro benzene.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 194

Question 71.
How will you convert :
(1) Propanoic acid into ethanoic acid.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 197

(2) Propanoic acid into ethanol
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 198

(3) Ethanamine into propan-l-amine.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 199

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

(4) Propan-l-amine into ethanamine.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 200

(5) Propanoic acid into ethanamine.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 201

(6) Ethanamine into propanoic acid.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 202

(7) Benzene to aniline.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 203

(8) Aniline to Benzene.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 204

(9) Aniline into benzoic acid.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 205

(10) Benzoic acid into aniline.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 206

(11) Aniline into benzamide.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 207

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

(12) 3-Nitrotoluene into 3-methyl aniline.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 208

(13) 3-Methyl aniline into 3-Nitrotoluene.
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 209

Question 72.
An organic compound ‘A’ having molecular formula C2H6O evolves hydrogen gas on treatment with sodium metal and on treatment with red phosphorous and iodine gives compound ‘B’. The compound ‘B’ on treatment with alcoholic KCN and on subsequent reduction gives compound ‘C’. The compound ‘C’ on treatment with nitrous acid evolves nitrogen gas. Write the balanced chemical equations for all the reactions involved and identify the compounds ‘A’, ‘B’ and ‘C;.
Answer:
A = C2H5OH ethanol
B = C2H5I ethyl iodide
C = C2H5CH2NH2 n-propyl amine
Compound C2H6O = C2H5OH
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 215

Question 73
Identify B, C and D write complete reactions :
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 216
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 217
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 218

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

Question 74.
Identify the compounds B, C and D in the following series of reactions and rewrite the complete equations :
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 219
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 220

Question 75.
Identify the compounds ‘A’ and ‘B’ in the following equation :
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 221
Answer:
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 222

Question 76.
Answer in one sentence :

(1) Arrange the following compounds in decreasing order of basic strength in their aqueous solutions. NH3, C2H5NH2, (CH3)2NH, (CH3)3N
Answer:
The decreasing order of basic strength is – (C2H5)2NH > (C2H5)3N > (C2H5)2NH > NH3
(The reason that ethyl group has greater +1 effect than methyl group).

(2) Arrange the following compounds in an increasing order of their solubility in water.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 226
Answer:
The solubility increases in order in which molecular mass decreases.
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 227

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

(3) What is Hinsberg’s reagent?
Answer:
Benzenesulphonyl chloride (C6H5SO2Cl) is known as Hinsberg’s reagent.

(4) Name the reaction in which a primary amine is formed from amide.
Answer:
Hoffmann bromamide degradation.

(5) NH3 is a Lewis base.
Answer:
Since nitrogen in ammonia molecule has a lone pair of electrons, it is a Lewis base.

(6) How many primary amines are possible for the compound C3H9N?
Answer:
For the compound C3H9N, two primary amines are possible.

(7) State the hybridization of the nitrogen atom in amines.
Answer:
The hybridization of nitrogen atom in amines is sp3.

(8) Arrange the following compounds in an increasing order of basic strength. Aniline, p-nitroaniline, p-toluidine.
Answer:
p-nitroaniline < aniline < p-toluidine.

(9) Which of the two is more basic and why? CH3NH2 or NH3
Answer:
Due to +1 effect of -CH3 group, electron density on N-atom increases, hence methyl amine is a stronger base than ammonia.

(10) Which of the two is more basic and why? p-toluidine or aniline.
Answer:
p-toluidine is more basic due to the presence of -CH3 group at para position. Due to +1 effect of -CH3 group, electron density on nitrogen increases, hence the tendency to donate pair of electrons increases.

Multiple Choice Questions

Question 77.
Select and write the most appropriate answer from the given alternatives for each subquestion :

1. Which of the following is an amine?
(a) C2H5N(COCH3)2
(b) (C2H5)2N – N = 0
(c) (C2H5)3N
(d) All of these
Answer:
(d) All of these

2. N-methyl-N-ethyl-n-propyl amine is
(a) a primary amine
(b) a secondary amine
(c) a tertiary amine
(d) an alkyl nitrile
Answer:
(c) a tertiary amine

3. Which of the following is a tertiary amine?
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 229
Answer:
(d)

4. Tertiary butyl amine is a
(a) primary amine
(b) secondary amine
(c) tertiary amine
(d) quaternary ammonium salt
Answer:
(a) primary amine

5. The IUPAC name of
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 230
(a) ethyl propanamine
(b) ethyl butylamine
(c) 2-pentanamine
(d) 3-hexanamine
Answer:
(d) 3-hexanamine

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

6. The IUPAC name of ethyl dimethyl amine is ……………..
(a) 2-amino propane
(b) N,N-dimethyl ethanolamine
(c) ethyl methanamine
(d) propanamine
Answer:
(b) N,N-dimethyl ethanolamine

7. Isopropyl amine and trimethyl amine are ……………..
(a) acidic in nature
(b) electrophilic compounds
(c) structural isomers
(d) optically active compounds
Answer:
(c) structural isomers

8. N, N-dimethylethanolamine is ……………
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 231
Answer:
(b)

9. IUPAC name of diethylmethyl amine is ………………
(a) methyl amino propane
(b) N-Ethyl-N-methylhexanamine
(c) methyl diethanamine
(d) amino pentane
Answer:
(b) N-Ethyl-N-methylhexanamine

10. Ethyl bromide reacts with excess of alcoholic ammonia, the major product is …………..
(a) ethyl amine
(b) diethylamine
(c) triethylamine
(d) tetraethyl ammonium bromide
Answer:
(a) ethyl amine

11. Isopropylamine is obtained by the reduction of
(a) acetoxime
(b) acetaldoxime
(c) formaldoxime
(d) aldoxime
Answer:
(a) acetoxime

12. Which of the following compounds can be converted into amines in the presence of Na and alcohol?
(a) Alkyl nitriles
(b) Aldoxime
(c) Ketoxime
(d) All of these
Answer:
(d) All of these

13. Chloroethane when boiled with excess of aqueous-alcoholic ammonia gives hydrochloric acid and
(a) triethyl amine
(b) trimethyl amine
(c) diethyl amine
(d) ethyl amine
Answer:
(d) ethyl amine

14. How many hydrogen atoms are required for the reduction of 1-nitropropane to n-propyl amine?
(a) Four
(b) Three
(c) Six
(d) Two
Answer:
(c) Six

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

15. A secondary alkyl halide is heated with excess of ammonia, the major product obtained is
(a) primary amine
(b) secondary amine
(c) tertiary amine
(d) quaternary ammonium salt
Answer:
(a) primary amine

16. The true statement about ethylamine is
(a) it is weaker base than ammonia
(b) it is stronger base than diethyl amine
(c) it is stronger base than triethyl amine
(d) it is stronger base than alkali
Answer:
(c) it is stronger base than triethyl amine

17. The reaction which is given only by primary amines is
(a) acetylation
(b) alkylation
(c) reaction with HNO2
(d) carbyl amine test
Answer:
(d) carbyl amine test

18. The amine which reacts with NaNO2 and dil. HCl to give yellow oily compound is
(a) ethylamine
(b) isopropylamine
(c) sec-butylamine
(d) dimethylamine
Answer:
(d) dimethylamine

19. The name of the compound ‘C’ in the following series of reactions, is Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 232
(a) propan-l-ol
(b) propan-2-ol
(c) butan-l-ol
(d) butan-2-ol
Answer:
(b) propan-2-ol

20. Triethylamine when treated with nitrous acid gives
(a) an alcohol
(b) a nitrosamine
(c) a monoacetyl derivative
(d) a soluble nitrite salt
Answer:
(d) a soluble nitrite salt

21. Ammes are basic in nature because
(a) of the nitrogen atom contain or lone pair of electrons
(b) they give H+ ions in aqueous medium
(c) they form quaternary ammonium salts when heated with acids
(d) both (a) and (c)
Answer:
(a) of the nitrogen atom contain or lone pair of electrons

22. An aqueous solution of primary amine contains
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 233
Answer:
(d)

23. The basic nature of amines in an aqueous solution is in the order of
(a) tert. > sec. > pri.
(b) sec. > pri. > tert.
(b) pri. > sec. > tert.
(d) pri. > tert. > sec.
Answer:
(b) pri. > sec. > tert.

24. In trimethyl ammonium ion, the number of sigma bonds attached to nitrogen are
(a) 2
(b) 3
(c) 4
(d) 5
Answer:
(b) 3

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

25. The number of coordinate bond/bonds in a trialkyl ammonium ion is
(a) one
(b) two
(c) three
(d) four
Answer:
(a) one

26. The number of electrons in the valence shell of nitrogen in methyl amine is
(a) 5
(b) 3
(c) 8
(d) 7
Answer:
(c) 8

27. Ethanamine reacts with excess of acetyl chloride to form
(a) C2H5NHCOCH3
(b) C2H5N(CH3)2
(c) C2H5N(COCH3)2
(d) C2H5N+H3Cl
Answer:
(c) C2H5N(COCH3)2

28. The compound used for acylation of amine is
(a) (CH3CO)2O
(b) CH3COOH
(c) CH3COCl
(d) both (a) and (c)
Answer:
(d) both (a) and (c)

29. Dimethyl amine reacts with acetyl chloride to give
(a) N-acetyl methyl amine
(b) N-acetyl ethyl amine
(c) N-acetyl dimethyl amine
(d) N-acetyl diethyl amine
Answer:
(c) N-acetyl dimethyl amine

30. Identify ‘A’ in the following reaction :
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 234
Answer:
(c)

31. n-propyl alcohol is obtained when HNO2 is treated with
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 235
Answer:
(c)

32. A mixture of CH3NH2, (CH3)2NH, (CH3)3N can be distinguished by using
(a) HCI
(b) HNO2
(c) HNO3
(d) H2SO4
Answer:
(b) HNO2

33. In the acetylation reaction the H-atom of an amine is replaced by
(a) a carbonyl group
(b) an alkyl group
(c) an acetyl group
(d) an imino group
Answer:
(c) an acetyl group

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

34. Amines are basic in nature
(a) as they have a fishy odour
(b) as they form quaternary ammonium salts with alkyl halides
(c) due to the presence of an unshared pair of electrons on the nitrogen atom
(d) all of these
Answer:
(c) due to the presence of an unshared pair of electrons on the nitrogen atom

35. The correct order of increasing basic strength is
(a) NH3 < CH3NH2 < (CH3)2NH
(b) CH3NH2 < (CH3)2NH < NH3
(c) CH3NH2 < NH3 < (CH3)2NH
(d) (CH3)2NH < NH3 < CH3NH2
Answer:
(a) NH3 < CH3NH2 < (CH3)2NH

36. Which of the following is the strongest base?
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 236
Answer:
(d)

37. Identify the weakest base amongst the following :
(a) p-methoxyaniline
(b) o-toluidine
(c) benzene-1, 4-diamine
(d) 4-aminobenzoic acid
Answer:
(d) 4-aminobenzoic acid

38. Amine that cannot be prepared by Gabriel phthalimide synthesis is
(a) aniline
(b) benzyl amine
(c) methyl amine
(d) iso-butyl amine
Answer:
(a) aniline

39. Which of the following exist as Zwitter ion?
(a) Salicylic acid
(b) Suphanilic acid
(c) p-Aminophenol
(d) p-Amino acetophenone
Answer:
(b) Suphanilic acid

40. Reduction of benzene diazonium chloride with Zn/HCl gives
(a) phenyl hydrazine
(b) hydrazine hydrate
(c) aniline
(d) ozo benzene
Answer:
(c) aniline

41. When primary amine reacts with CHCl3 in alcoholic KOH, the product is
(a) aldehyde
(b) alcohol
(c) cyanide
(d) an isocyanide
Answer:
(d) an isocyanide

42. Which of the following amines cannot be prepared by Gabriel phthalimide synthesis?
(a) sec-Propylamine
(b) tert-Butylamine
(c) 2-Phenylethylamine
(d) N-Methyl benzyl amine
Answer:
(d) N-Methyl benzyl amine

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

43. Which of the following compounds has highest boiling point?
(a) Ethane
(b) Ethanoic acid
(c) Ethanol
(d) Ethanamine
Answer:
(b) Ethanoic acid

44. Identify the statement about the basic nature of amines.
(a) Alkylamines are weaker bases than ammonia.
(b) Arylamines are stronger bases than alkylamines.
(c) Secondary aliphatic amines are stronger bases than primary aliphatic amines.
(d) Tertiary aliphatic amines are weaker bases than arylamines.
Answer:
(c) Secondary aliphatic amines are stronger bases than primary aliphatic amines.

45. The compounds ‘A’, ‘B’ and ‘C’ react with methyl iodide to give finally quaternary ammonium iodides. Only ‘C’ gives carbylamines test while only ‘A’ forms yellow oily compound on reaction with nitrous acid. The compounds ‘A’, ‘B’ and ‘C’ are respectively.
(a) butan-1-amine, N-ethylethanamine and
N, N-dimethylethanamine.
(b) N-ethylethanamine, N, N-dimethylethanamine and butan-1 – amine.
(c) N, N-dimethylethanamine, N-ethylethanamine and butan-1-amine.
(d) N-ethylethanamine, butan-1-amine and N-ethylethanamine.
Answer:
(b) N-ethylethanamine, N, N-dimethylethanamine and butan-1 – amine.

46. Which of the following amines is most basic in nature?
(a) 2, 4-Dichloroaniline
(b) 2, 4-Dimethylaniline
(c) 2, 4-Dinitroaniline
(d) 2, 4-Dibromoaniline
Answer:
(b) 2, 4-Dimethylaniline

47. How many moles of methyl iodide are required to convert ethylamine, diethylamine and triethylamine into quaternary ammonium salt, respectively?
(a) 1, 2 and 3
(b) 2, 3 and 1
(c) 3, 2 and 1
(d) 3, 1 and 2
Answer:
(c) 3, 2 and 1

48. Which of the following amines does not undergo acetylation?
(a) t-Butylamine
(b) Ethylamine
(c) Diethylamine
(d) Triethylamine
Answer:
(d) Triethylamine

49. n-Propylamine can be prepared by catalytic reduction of
(a) n-propyl cyanide
(b) propionaldoxime
(c) acetoxime
(d) nitroethane
Answer:
(b) propionaldoxime

50. Identify the compound ‘B’ in the following series of reactions :
Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 237
Answer:
(c)

Maharashtra Board Class 12 Chemistry Important Questions Chapter 13 Amines

51. Chloropicrin is used as
(a) antiseptic
(b) antibiotic
(c) insecticide
(d) anaesthetic
Answer:
(c) insecticide

52. Identify the compound B in the following series of reactions. Maharashtra Board Class 12 Chemistry Solutions Chapter 13 Amines 238
(a) n-propyl chloride
(b) propanamine
(c) n-propyl alcohol
(d) Isopropyl alcohol
Answer:
(c) n-propyl alcohol

53. Which of the following amines yields foul smelling product with haloform and alcoholic KOH?
(a) Ethyl amine
(b) Diethyl amine
(c) Triethyl amine
(d) Ethyl methyl amine
Answer:
(a) Ethyl amine

54. Which of the following compounds is NOT prepared by the action of alcoholic NH3 on alkyl halide?
(a) CH3NH2
(b) CH3-CH2-NH2
(c) CH3 – CH2 – CH2 – NH2
(d) (CH3)3CNH2
Answer:
(d) (CH3)3CNH2