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Q: What is 56 as a product for its prime factors in index form?

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648 expressed as a product of its prime factors in index form is 2^3 times 3^4

56

21

72 *23

As a product of its prime factors: 5^3 times 13 = 1625

2*7*11

It is: 22*52 = 100

24 as a product of its prime factors in index form: 2| 24 === 2| 12 === 2| 6 === .....3 Prime factorization of 24= 2 x 2 x 2 x 3

No indices are needed because as a product of its prime factors: 3*5*7 = 105

It is form in which a number is expressed as a product of its prime factors. Conventionally, the factors are written in increasing order of magnitude and repeated factors may be represented in index or exponential form.

It is: 2^3*7 = 56

As a product of its prime factors: 2^3 times 3 times 5^2 = 600

23 x 112 = 968

24 x 5 x 72 = 3920

It is: 3*5*7^2 = 735

2^4 x 3 x 5

175 = 5 x 5 x 7 = 52 x 7

9x4 = 32*x4 has (2+1)*(4+1) = 3*5 = 15 different factors. When an expression is written out as the product of its prime factors in index form, the number of factors can be calculated as the product of each index increased by one.

120 = 23 x 3 x 5

The prime factors of 45 are 3 and 5.

20 = 2 x 2 x 5 = 22 x 5

2^3 x 3 x 11

In index form, 378 = 2 x 3 x 3 x 3 x 7 = 2 x 33 x 7

Prime factors of 1080 are 23 33 5.

56 = 2 x 2 x 2 x 7 = 23 x 7